Which of the following is NOT one of the four elements of emotion?
Behavioral Expression
Attention
Subjective Experience
Physiological Arousal

If you pound a feather with a hammer, which one feels a greater force always the hammer both feather moves, then it felt the greater force.

What is the force?
Force is an influence that produces a change in the motion of an object. It is measured in units of mass times acceleration, or newtons (N). Force is a vector quantity, meaning it has both magnitude and direction. Force can cause an object to accelerate, decelerate, remain in motion, change direction, or alter shape. Examples of forces include gravity, friction, tension, and magnetism. Forces can also be generated by electrical, thermal, and nuclear energy. All forces are generated by the interaction of two objects and can be balanced or unbalanced. Unbalanced forces will cause an object to move or accelerate and balanced forces will cause an object to remain stationary or in motion at a constant speed.

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Example of erosion: Wind carries small pieces of rock away from the side of a mountain.

Erosion is the procedure by which the surface of the Earth gets worn down. Erosion can be created by natural elements such as erosion as wind and glacial ice. But everyone who has ever seen a picture of the Grand Canyon knows that nothing strikes the erosion slow steady movement of the water when it comes to commuting the Earth

Rain, rivers, floods, lakes, and the ocean convey away bits of soil and sand and slowly wash away the deposit. Rainfall produces four types of soil erosion: splash erosion, sheet erosion, rill erosion, and ravine erosion.

So we can conclude that Erosion is a ruinous force that wears away land features.

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The original speed of the bullet was 300.6 m/s.

A measure of the amount of matter contained in or constituting a physical body. In classical mechanics, the mass of an object is related to the force required to accelerate it and hence is related to its inertia, and is essential to Newton's laws of motion.

Given:

mV bi​ +MV wi​ =mV b​ +M Vwf​

where m= mass of bullet =10 g=10^−2 ∣kg

M= mass of wood block =5 kg

V bI​ = initial mass of bullet

Vwi​ = initial mass of wood block and V bf​ =V wf​  

=0.06 m/s 10 −2 Vbi+0(10 −2 +5)0.6 V

bi​ = 10 −2 5.01×0.6​ V

bi​ =300.6 m/s

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Electrical burns can occur in a variety of ways, including arc burns, low voltage burns, high voltage burns, mouth burns, flash burns, and flame burns.

Electric shock, a serious electrical mishap, or a fatal electrical event are all considered electrical incidents.

For the purposes of reporting and analysis, incident definition types let you attribute the appropriate type to safety events. Having only the two types of incidents—Accident and Near Miss—is one strategy.

An occurrence or scenario that has a number of serious repercussions and necessitates the implementation of special measures by one or more emergency responder agencies is referred to as a big incident.

Any electrical incident that results in or has the potential to result in: death or serious bodily harm to a person; significant property damage; or a serious risk to the public safety must be reported, according to the Electrical Safety (General) Regulations of 2019.

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Force is positive if the mass accelerates downward. Use the formula T = M x A to determine the tension in the rope.

That direction is the pull that is referred to as tension. As a result, the tension will point toward the string or rope and away from the mass.

A mass suspended by a string is pulled upward by the string, exerting an upper force that shifts the tension to the upper side.

For instance, you should know that T = 9g x 2m/s2 = 18gm/s2 or 18N when trying to calculate T in a straightforward pulley system with a linked mass of 9g and an upward acceleration of 2m/s2 (newtons). The direction in which a string expands changes when it passes over an ideal massless pulley, but the string's tension is unaffected.

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It would take 5 pounds of force, that is equal force, to stop the ball from rolling because the same amount of force must be used to stop the object.

According to Newton's third law of motion, every action which is occurring in nature has an equal as well as an opposite reaction. For instance, if a particular object A happens to exert a force on another object B, then  object B will also be exerting an equal as well as an opposite force on  object A.

If a particular ball is rolling with 5 pounds of force then the same amount of reaction will be required to bring it to rest. That is, equal force of 5 pounds will be required to stop the ball.

Hence, option D is the correct option.

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As air is blowing across the top of a soft drink bottle, it reverberates. The frequency grows as the chamber's length lengthens.

The frequency of physics is the number of waves that pass by a specific location in a time period. According to this concept, how several cycles or waves do a body in periodical motion experience in a single unit of time?

The distance between normal incidence (adjacent crests) in adjacent cycles determines how far a waveform signal has traveled in place or over a wire. In wireless systems, this length is often expressed in metres (m), centimeters (cm), or millimeters (mm) (mm).

Therefore, As air is blown, a soda pop bottle reverberates.

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Answer:

Reduce friction

Answer: +/- 71,65 Calorías

Explanation: Se deduce que la fuerza aplica para aumentar o disminuir la energía del generador.

+/- x Calorías

X = Equivalente de 300 Joules en calorías

Para poder pasar Joules a calorías.

Hacemos una regla de 3 simple

1 Calorías = 4,18 Julios

0,2392 calorías = 1 Julio

(  1 / 4,18 = 0,2392 calorías)

300 Julios = 71,65 calorías

(0,2392 calorías x 300 julios = +/- 71,65 calorías)

Answer:343m

Explanation:

Answer:

In my opinion I think the answer is C you don't have to choose C

Answer:

A The additional potential energy the reactants must gain in order toreact

Explanation:

It will take 1.5 seconds for Marissa's car to accelerate from 26. 4 m/s to 28. 6 m/s.

Acceleration can be calculated by looking at the change in velocity over a specific period of time. It is an important concept in physics as it is used to explain the motion of objects in the real world.

Acceleration is a measure of how quickly an object is changing its velocity on average, and it is usually expressed in meters per second squared (m/s2).

This simple calculation of Marissa's car acceleration can be determined by using the formula: Delta speed / Acceleration rate = Time taken.

In this case, that would be 2.2 m/s (28.6-26.4) / 3.6 m/s2

= 0.6 s or 1.5 sec (rounded up).

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Given :

An engine creates a 2230 N force that pushes a car forward 58.3 m in 9.40 s.

To Find :

How much power does the engine produce in Watt.

Solution :

We know, Work done is given by :

[tex]W = F.d\\\\W = 2230 \times 58.3 \ J\\\\W = 130009\ J[/tex]

Now, Power is given by :

[tex]Power = \dfrac{Work \ Done}{Time \ Taken}\\\\P = \dfrac{130009}{9.4}\ W\\\\P = 13830.74\ W[/tex]

Therefore, power produced by engine is 13830.74 W.

The car's acceleration can be calculated as: a = v2/R = (18.0 m/s) 2/(12.0 m) = 27.0 m/s2. The conventional method can be used to determine net force: 13500 N is equal to Fnet = m•a = (500 kg)•(27.0 m/s2).

It may slow down or decelerate when traveling uphill or straight ahead. Roller coasters accelerate as they travel down hills due to the force of gravity dragging them downward.

Calculus and other fundamental mathematical concepts are used to calculate the maximum speed, the angles of ascent and descent, and the height necessary for the automobile to climb the next hill. The roller coaster's safety is further ensured by these calculations.

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The number of electrons that move in a circuit where a current of 2.0 A flows for 2.0 minutes will be [tex]1.5X10^2^2[/tex]. The correct option is C.

Electrical charge carriers, often electrons or atoms deficient in electrons, travel as current. The capital letter I is a typical way to represent current.

A current of 2A passes through a wire for 20 minutes. The number of electrons that crossed the cross-section in this period is

Given that,

Current =2A

Time t= 20min = 20×60s

Let,

n and e be the number and charge of electrons in time t.

So,

The total charge, q(say) in the wire is

q = ne

Hence, the current flowing in time t is

I = q/t

I = ne/t

n = It/e

[tex]n=\frac{2(20X60)}{1.6X10^{-19}} \\\\n=\frac{2400}{1.6X10^{-19}}\\\\n=1.5X10^{22}[/tex]

Thus, the answer is [tex]1.5X10^2^2[/tex], means the correct option is C.

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Your question seems incomplete, the missing options are:

[tex]1.5X10^{21}\\\\1.5X10^{20}\\\\1.5X10^{22}\\\\1.5X10^{21}\\\\1.5X10^{23}[/tex]

The force of gravitational attraction is 489.18N

                                          [tex]F = \frac{Gm_{1} m_{2} }{r^{2} }[/tex]

Where,

F is the gravitational force between two bodies

m1 is the mass of the first body = 50 Kg

m2 is the mass of the second body = [tex]5.97 * 10^{24} Kg[/tex]

r is the distance between the centres of two bodies = [tex]6.38 * 10^{6} m[/tex]

G = gravitational constant = [tex]6.67 * 10^{-11}[/tex]

Putting these values in above equation we get: F = 489.18N

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For the Direct free kick, the game restarted.

There are two different kinds of free kicks used in soccer: direct and indirect.The term "direct free kick" refers to a kick that can be used as a direct strike.Indirect free kicks require a second touch before the ball can be used as a shot at goal.

If a player attacks an opponent in a way that the referee deems to be irresponsible, reckless, or employing excessive force, the referee will award a direct free kick.jumps, kicks, or makes an attempt to kick.

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After that, we will calculate the temperature, total enthalpy, and masses of each water phase using the steam table.

Given the water's initial mass and pressure, we can determine whether it is superheated or saturated by utilizing a steam table. On a variety of scales, including the Fahrenheit and Celsius systems, temperature is a unit that is used to denote hotness or coolness.

Heat energy will logically go from a hotter (body with a higher temperature) to a colder (body with a lower temperature) according to temperature (one at a lower temperature).

A comparison of a substance's temperature to a set of hot and cold reference values can be used to determine its temperature. The letter "T" stands for "temperature," which is denoted by the SI unit of "°C."

The three scales that are most frequently used to measure temperature are the Celsius scale, the Fahrenheit scale, and the Kelvin scale.

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By replacing the force system acting on the post with a resultant force and a couple of moments at point o we get total momentum of 1478.85 ft-lb.

As per the figure we have 3 forces: At the top 300lb left side 150lnb and at the middle 200lb.

first, we have to break down the forces into x and y components.

Now calculating each force separately:

∑Fₓ=300lb+cos 30°-150×4/3+200

=259.81-120+200

∑Fₓ=339.81lb.

Now, calculate the sum of y components.

∑Fy=300 sin 30°+150×3/5

∑Fy=300 sin 30°+90

∑Fy=240lb

Now we have to x and y components by these values we can find the actual force.

|F|=√Fx²+Fy²

|F|=√(339.81)²+(240)²                     α=tan⁻¹(∑Fₓ/∑Fy)

|F|=√115470.83+57600                      α=tan⁻¹(339.81/240)

|F|=√173070                                       α=35.23°

|F|=416.02 and 35.23°

the sum of moments at O

∑Mo=-Fx₃×2+Fx₂×4-Fx₁×6

∑Mo=-200(2)+4/5 150*4-3000cos30°(6)

∑Mo=-400+480-277.65

         =1478.85ftlb

∑Mo=1478.85ftlb

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The frequency of Sound A is 440.3 Hz.

The resultant frequency of the sound A and sound B is calculated as follows;

Mathematically, the relationship between period and frequency of a wave is given as;

F = 1 / T

where;

The resultant frequency from the given graph is calculated as;

The period of the sound in the image = 0.3 s

F = 1 / T

F = 1 / 0.3 s

F = 3.3 Hz

If sound B = 437 Hz, the frequency of sound A which is greater is calculated as;

F ( A ) = 437 Hz  +  3.3 Hz

F ( A ) = 440.3 Hz

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The electric field strength at point (x,y) = ( 25 mm ,0cm) is =16321.0769 N/C

The electric field strength at point (x,y) = (0cm, 25 mm) is =35321.58999 N/

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The electric field strength at point (x,y) = ( 20 mm ,0cm) is =16321.0769 N/C

The electric field strength at point (x,y) = (0cm, 20 mm) is =35321.58999 N/C

A vector is a quantity with both a magnitude and a direction, like the electric field. The vector's magnitude corresponds to the electric field intensity.

Each point in space has an electric field associated with it when there is charge present in any form. E, often known as electric field strength, electric field intensity, or just the electric field, is a mathematical constant that expresses the strength and direction of an electric field.

Given:

Charge = 5.0 nC

x = 25 mm, y = 0 cm

The electric field at any given point of the dipole is given as:

E= (KP) ÷ (r^2 + a^2)^3/2

Where:

K = 9x10^9 Nm^2/c^2 (coloumb constant)

P = (0.003) (5x10^-9c) which is the movement of the dipole

(0.003) is arrived at when mm is converted to m. 3.0 mm space apart was converted to a meter.

r= the point, in the question above is 20mm = 0.02m

Now, the electric field (E),

E = (KP) ÷ (r^2 + a^2)^3/2

= (9x10^9 Nm^2/c^2) (0.003 m) (5x10^-9c) ÷ [ (0.02m)^2 + (0.003)^2]^3/2

= 0.135 ÷ (8.271513x10^-6)

=16321.0769 N/C

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The current through the bottom of the wire is 0.415 A and the negative sign of the current indicates that current flows from left to right from the bottom wire.

The current through various parts of the circuit is as shown in figure.

Here we have to calculate the current I_5.

Applying Kirchoff's loop rule on each of the loops in the circuit, Consider the left triangle, for it, we have

[tex]$$\begin{aligned}& \left(I_1\right) 6 \Omega+\left(I_3\right) 12 \Omega-9 \mathrm{~V}=0 \\& \Rightarrow 6 I_1+12 I_3=9 \\& \Rightarrow I_1=\frac{9}{6}-\frac{12}{6} I_3 \\& \Rightarrow I_1=1.5-2 I_3-----(1)\end{aligned}$$[/tex]

For the centre of the triangle, we have

[tex]$$\begin{aligned}& \left(I_4\right) 24 \Omega-\left(I_3\right) 12 \Omega=0 \\& \Rightarrow I_4=\frac{12}{24} I_3 \\& \Rightarrow I_4=\frac{I_3}{2}-----(2)\end{aligned}$$[/tex]

And for the right triangle, we have

[tex]$$\begin{aligned}& \left(I_2\right) 10 \Omega+\left(I_4\right) 24 \Omega-15 \mathrm{~V}=0 \\& \Rightarrow I_2=\frac{15}{10}-\frac{24}{10} I_4 \\& \Rightarrow I_2=1.5-2.4 I_4------(3)\end{aligned}$$[/tex]

The junction rule applied at the left corner gives

I_1  =I_3+I_5

=I_5  =I_1-I_3

=1.5-2 I_3-(I_3)=1.5-3 I_3--------(4)

And applying the junction rule at the right corner,

I_4 =I_2+I_5

I_5 =I_4-I_2

=I_4-(1.5-2.4 I_4)=3.4 I_4-1.5-------(5)

Using equation (2) [tex]$I_4=\frac{I_3}{2}$[/tex], equation (5) can be written as

[tex]$$\begin{aligned}I_5 & =3.4\left(\frac{I_3}{2}\right)-1.5 \\\end{aligned}$$[/tex]==1.7 I_3-1.5

Solving equations (4) and (6), we have

1.5-3 I_3=1.7 I_3-1.5

(1.5+1.5)=(1.7+3.0) I_3

3.0=4.7 I_3

[tex]\Rightarrow I_3=\frac{3.0}{4.7} \mathrm{~A}[/tex]

Hence the current in the bottom wire is given by

[tex]I_5 & =1.7\left(\frac{3.0}{4.7}\right)-1.5 \\[/tex] =1.085-1.5 =-0.415 A

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Answer:

A gallon of water would be a good household object to use for strength training.

Explanation:

Gallon jugs of water typically weigh around 8.3 lbs, which can provide a good amount of resistance for strength training exercises such as bicep curls, shoulder presses, and tricep dips. Additionally, the handle on the jug of water makes it easy to grip and use for various exercises. Cans of soup and boxes of tissues are generally too light to provide enough resistance for strength training, and a paperback book may not be sturdy enough to use for certain exercises.

The right response is a hockey puck slides along a horizontal icy frictionless surface and as a car is going along a straight road at a constant pace, according to the motion diagram.

The car is shown in the diagram starting at point a. The arrows remain pointing in the same way. This indicates that the thing is travelling directly forward. The arrows stay stationary at A. This indicates that the thing is travelling continuously.

The speed of the puck is not impacted by friction while it is moving on an ice rink surface. So, it is reasonable to suppose that it is moving at a constant speed before to impact.

The work done is zero only if there is no non-conservative force, such as friction, because the kinetic energy does not vary and the car is going along a straight, horizontal road. The work done will be force into displacement if there is friction.

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At kelvin temperature T, cylinder A includes n molecule of a gas, and the force exerted by the gas on the cylinder is NkBT/l.

When two bodies interact, it refers to any form of pushing or pulling that one body exerts on the other. A vector quantity, that is. For instance, a person pushes or pulls on something to provide force, such as opening a door.

Contact forces that act at a remove forces are the two different types of forces. Your daily use of force is evident. Basically, pressure and pull are forces.

Formulas,

-P = F/A

-n = n/Na

-PV = nRT

= NKT (R = KNa)

- Volume of cylinder: A* l

F=PA

P = NKbT / V

P = NKbT / A* l

F = NkBT / A * l (A)

Cross out A,

Final, F = NkBT/l.

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Answer:

1. Water pump

2. Radiator

3. Thermostat

4. AntiFreeze

5. Bypass Valve

6. Thermo switch

7. Radiator hoses

8. Fan

9. Water Pump Impeller

10. Core

Explanation:

Based on Cooling System Fundamentals, we have the following;

1. Coolant is forced through the engine and other system parts by the WATER PUMP.

2. The RADIATOR transfers engine coolant heat to the outside air.

3. Coolant flow and engine operating temperature are controlled by the THERMOSTAT.

4. ANTIFREEZE is mixed with water to produce the engine coolant.

5. A(n) BYPASS VALVE permits coolant circulation through the engine when the thermostat is closed.

6. The fan switch, or THERMO SWTICH is a temperature-sensitive switch that controls fan motor operation.

7. The engine is connected to the radiator by the RADIATOR HOSES.

8. The FAN draws air through the radiator.

9. A disc with fan-like blades that spins and produces pressure and flow is known as a(n) WATER PUMP IMPELLER

10. The center section of the radiator made up of tubes and cooling fins is called the CORE.

Answer:

1.03 * 10^-5

Explanation:

The magnetic flux through the loop is approximately 1.317 × [tex]10^{(-5)[/tex]T·m².

To calculate the magnetic flux through a loop, we use the formula:

Φ = B × A × cos(θ)

Where:

Φ is the magnetic flux

B is the magnetic field strength

A is the area of the loop

θ is the angle between the magnetic field and the normal to the loop

Given:

Magnetic field strength (B) = 3.09 × [tex]10^{(-4)[/tex] T (east direction)

Area of the loop (A) = 0.0471 m²

The loop faces directly northeast

To find the angle θ,  determine the angle between the magnetic field direction (east) and the normal to the loop (northeast).

Since the loop faces northeast, the angle between the normal to the loop and the east direction is 45 degrees (90 degrees divided by 2).

Now calculate the magnetic flux:

Φ = B  × A  × cos(θ)

Φ = (3.09 × [tex]10^{(-4)[/tex] T) × (0.0471 m²) × cos(45°)

Using the value of cos(45°) as 0.7071:

Φ = (3.09 × [tex]10^{(-4)[/tex] T) × (0.0471 m²) ×0.7071

Φ = 1.317 × [tex]10^{(-5)[/tex] T·m²

Therefore, the magnetic flux through the loop is approximately 1.317 × [tex]10^{(-5)[/tex] T·m².

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The kinetic energy would be 96 J, for the car moving at 4m/s and with 3kg mass.

The kinetic energy (Ek) of the toy car is given by Ek = ½ mv2, where m is the mass of the car (3 kg) and v is the velocity (4 m/s). Thus, the kinetic energy of the car is 24 J. If the car were moving twice as fast (8 m/s), the kinetic energy would be 96 J. The units are Joules (J).

Kinetic energy is the energy of a body or system due to its motion. It is the energy that an object has due to its motion. Kinetic energy is equal to one half of the mass of the object multiplied by the square of its velocity.

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