The angular momentum of the ball rotating on the end of a thin string in a circle of radius 1.45 m m at an angular speed of 11.6 rad/s r a d / s is 6.07 × 10⁻⁶ kg m²/s.
Angular momentum is the quantity of motion that describes the rotation of a body about a fixed axis. It is a vector quantity that is the cross product of the position vector and the momentum vector.
The angular momentum of a 0.205 kg k g ball rotating on the end of a thin string in a circle of radius 1.45 m m at an angular speed of 11.6 rad/s r a d / s can be calculated as follows:
L = IωL = Iω
Here, L is angular momentum,
I is the moment of inertia of the ball, and
ω is the angular velocity of the ball.
The moment of inertia of a uniform sphere can be calculated as follows:
I= (2/5)mr²I = (2/5)mr²
Here, m is the mass of the sphere, and r is the radius of the sphere.
Therefore, the moment of inertia of the ball is given by:
I = (2/5)mr²I = (2/5) × 0.205 × (0.00145)²I = 5.23 × 10⁻⁷ kg m²
Substituting this value into the expression for angular momentum:
L = IωL = 5.23 × 10⁻⁷ × 11.6L = 6.07 × 10⁻⁶ kg m²/s.
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a gun is fired with muzzle velocity 1000 feet per second at a target 4050 feet away. find the minimum angle of elevation necessary to hit the target.
The minimum elevation angle necessary to hit the target 4050 feet away with a muzzle velocity of 1000 feet per second is 45 degrees.
Let α be the angle of elevation at which the gun is aimed.
Then, tan α = Opposite Side / Adjacent Side
tan α = 4050 / (1000 * time of flight)
Let h be the target's height above the gun's level.
Since the target's altitude is unknown, we'll assume it to be h = 0.
Since the gun is fired horizontally, its initial velocity has no vertical component. In the vertical direction, the projectile is influenced solely by gravity.
Since the horizontal distance traveled by the projectile is 4050 feet and the initial velocity is 1000 feet per second,
t = (4050 / 1000) seconds
On substituting the value of t,
we get, tan α = 4050 / (1000 * 4.05)
tan α = 1
Therefore, the angle of elevation of the gun is 45°.
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Drag and drop the terms to correctly complete the prompt.
Current is produced in a conductor when it is moved through a
applying a force on the
in the conductor and causing them to
of generating current in a conductor by placing the conductor in a changing magnetic field is called
is no
because the magnetic lines of force are
:: physical connection
between the conductor and the magnet. The current is said to be induced in the conductor by the
magnetic field. The conductor, which is often a piece of wire, must be
to the magnetic lines of force in
order to produce the maximum force on the free electrons. The direction that the induced current flows is determined by the direction
of the lines of force and by the direction the wire is moving in the field.
This process
:: free electrons :: induction :: perpendicular :: move
There
::magnetic field
We can see here that correctly completing this prompt, we have:
Current is produced in a conductor when it is moved through a magnetic field. This process of applying a force on the free electrons in the conductor and causing them to move.
This process of generating current in a conductor by placing the conductor in a changing magnetic field is called induction. There is no physical connection between the conductor and the magnet. The conductor, which is often a piece of wire, must be perpendicular to the magnetic lines of force in order to produce the maximum force on the free electrons.
What is current?In physics, current refers to the flow of electric charge in a circuit. It is measured in amperes (A) and is defined as the amount of charge that passes through a point in a circuit per unit time. In other words, current is the rate of flow of electric charge.
Current can flow through a variety of materials, such as wires or conductive solutions, and is driven by a potential difference, or voltage, between two points in a circuit.
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a bike and rider, 82.0 kg combined mass, are traveling at 4.2 m/s. a constant force of -140 n is applied by the brakes in stopping the bike. what braking distance is needed?
The bike and rider must halt at a breaking distance of 5.17 meters.
What is the formula for braking distance?d=2.2v+fracv220 gives the braking distance, in feet, of a car moving at v miles per hour. Most motorcycle riders have a maximum braking force (what an experienced rider can do) of about 1 G, which, at 45 mph, results in a complete stop of the motorcycle in 67 feet (20 meters).
To resolve this issue, we can apply the equation of motion for uniformly accelerated motion:
v² = u² + 2as
To solve for s, we can rewrite the equation as follows:
s = (v² - u²) / (2a)
We are aware that the acceleration is determined by dividing the net force by the mass:
a = F_net / m
where m is the mass and F net is the net force.
a = F_net / m = -140 N / 82.0 kg
= -1.71 m/s²
We may now change the values for s in the equation:
s = (0² - 4.2²) / (2*(-1.71))
= 5.17 m
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a 4.4 hz continuous wave travels on a slinky. if the wavelength is 0.55 m, what is the speed of waves on the slinky (in m/s)? m/s
The speed of waves on the slinky is 2.42 m/s.
The speed of a wave is the distance it travels in a given amount of time.
The speed of waves on the slinky can be calculated using the equation:
v=fλ
where v is the wave speed, f is the frequency, and λ is the wavelength).
Using the given values of f=4.4 Hz and λ=0.55 m, we can calculate the speed of the wave to be 2.42 m/s.
So, the wave is traveling at a speed of 2.42 m/s, which means that it will travel 2.42 meters in one second.
The frequency of the wave is 4.4 Hz, which means that the wave completes one cycle in 0.23 seconds. Since the wave is traveling at a speed of 2.42 m/s, this means that it will take 0.23 seconds for the wave to complete one cycle.
Therefore, the speed of waves on the slinky traveling with a frequency of 4.4 Hz and having a wavelength of 0.55m is 2.42 m/s.
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a 13-kg k g hammer strikes a nail at a velocity of 7.8 m/s m / s and comes to rest in a time interval of 8.4 ms m s . part a what is the impulse given to the nail?
The impulse given to the nail is -101.527616 J (Joules).
The impulse given to the nail if a 13-kg hammer strikes a nail at a velocity of 7.8 m/s and comes to rest in a time interval of 8.4 ms is calculated using the formula J = FΔt.
Here, F is the force, Δt is the time interval, and J is the impulse. Use the given information to solve the question. Here, m/s stands for meters per second, and ms stands for milliseconds.
F = maF = m (Δv / Δt)
where, m is the mass of the hammer, and Δv is the change in velocity of the hammer.
Δv = -7.8 m/s (negative because the hammer is coming to rest)
Δt = 8.4 ms = 0.0084 s
F = 13 kg x (-7.8 m/s) / 0.0084 sF = -12095.24 N
The force exerted on the nail is -12095.24 N.
The impulse given to the nail is J = FΔt.
J = -12095.24 N x 0.0084 sJ = -101.527616 J (Joules)
Therefore, the impulse given to the nail is -101.527616 J (Joules).
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if two sacks, one twice as heavy as the other, are lifted the same vertical distances in the same time, how does the power required for each compare?
If two sacks, one twice as heavy as the other, are lifted the same vertical distances in the same time, the power required for each is proportional to the weight lifted.
Power is the measure of work accomplished per unit time, it is measured in joules per second or watts. Power is a scalar quantity that tells us how quickly work is being done. Power is equal to the work done divided by the time taken to do the work. Work = force x distance, Power = work/time. From the above equations, it is clear that power and weight are proportional since force and weight are proportional.
In the case of two sacks, one twice as heavy as the other, the power required to lift the heavier sack is twice that required to lift the lighter sack, this is because the weight of an object affects how much force is required to lift it. The force required to lift an object is equal to the object's weight. Therefore, if the weight of an object is doubled, the force required to lift it is also doubled, and the power required to lift it is also doubled. In conclusion, if two sacks, one twice as heavy as the other, are lifted the same vertical distances in the same time, the power required for each is proportional to the weight lifted. The power required to lift the heavier sack is twice that required to lift the lighter sack.
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suppose you were dragging a table across a rough floor. in this case, the potential energy for friction depends on which quantity or quantities? (choose all that apply)
In dragging a table across a rough floor, the potential energy for friction depends on the coefficient of friction, normal force, and distance traveled by the table, hence option (a), (b), and (c) are correct.
In this case, the potential energy for friction would depend on the following quantities:
Coefficient of friction: The coefficient of friction between the table and the floor would determine how much force is required to move the table and hence, the potential energy for friction.
Normal force: The normal force acting on the table due to the weight of the table and any objects placed on it would also affect the potential energy for friction.
Distance moved: The distance the table is moved would determine the amount of work done against friction and hence, the potential energy for friction.
Surface area: The surface area in contact between the table and the floor could also affect the potential energy for friction.
Overall, the potential energy for friction depends on a combination of factors, including the properties of the surfaces in contact, the force required to move the object, and the distance moved.
Therefore correct options are (a), (b), and (c).
Suppose you were dragging a table across a rough floor. in this case, the potential energy for friction depends on which quantity or quantities? (choose all that apply)
a. The total distance the table travels.
c. The coefficient of friction between the table and the floor.
d. The normal force that the floor exerts on the table.
e. There is no potential energy for frictional forces.
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A 23.3 kg boy is moving along a circular path with the constant speed of 2.7 m/s. What is the magnitude of the centripetal force acting on the boy if the radius of the circle is 12.9 m. Note : Calculate the answer to 3 (three) significant figures by presenting it in normal ( decimal) form. Don't forget to include the unit.
The centripetal force for the given question would be 16.3 N.
Explanation:
The magnitude of the centripetal force acting on a 23.3 kg boy moving along a circular path with a constant speed of 2.7 m/s and the radius of the circle is 12.9 m is 16.3 N (newton).
What is centripetal force?
Centripetal force is the net force acting on an object moving in a circular path toward the center of the circle. It always points towards the center of the circle, hence the name "center-seeking force".
What is the formula for centripetal force?
The formula for centripetal force is Fc = (mv²)/r, where Fc is the centripetal force, m is mass, v is velocity or speed and r is the radius of the circular path.
In the given question: Mass, m = 23.3 kgVelocity, v = 2.7 m/s, Radius, r = 12.9. To calculate centripetal force,
F = (m x v^2)/r
Putting the given values in the above formula: F = (23.3 kg x (2.7 m/s)^2)/12.9 m= 16.3 N (newton)
Therefore, the magnitude of the centripetal force acting on the boy is 16.3 N (newton).
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how fast is it moving when it reaches the top of its trajectory if the projectile is fired at a speed of 138 and an upward angle of 65 degrees?
The projectile will be moving at a speed of 57.21 m/s when it reaches the top of its trajectory.
When a projectile is fired at a speed of 138 and an upward angle of 65 degrees, the speed at the top of the trajectory can be calculated. To solve this problem, you need to understand some basic physics concepts. Here's how you can solve this problem:
1. First, identify the given values and write them down:
Initial velocity (u) = 138 m/s
Angle of projection (θ) = 65 degrees
Acceleration due to gravity (g) = 9.81 m/s²
2. Now, break down the initial velocity into its horizontal and vertical components:
Initial velocity in the horizontal direction = u cos θ
Initial velocity in the vertical direction = u sin θ
3. Use the equation of motion to calculate the time taken by the projectile to reach the top of its trajectory:
u sin θ = gt/2
t = 2u sin θ/g
4. Use the time obtained in step 3 to calculate the velocity at the top of the trajectory:
v = u cos θ
Where,
v = final velocity
u = initial velocity
θ = angle of projection
5. Substitute the given values in the equation to get the final answer:
v = u cos θ
v = 138 cos 65
v = 57.21 m/s
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A billiard ball of mass m = 0.150 kg hits the cushion of a billiard table at an angle of θ1 = 60.0 degrees at a speed of v1 = 2.50 m/s. It bounces off at an angle of θ2 = 47.0 degrees and a speed of v2 = 2.20 m/s.
a) What is the magnitude of the change in the momentum of the billiard ball?
b) In which direction does the change of momentum vector point? (Take the x-axis along the cushion and specify your answer in degrees.)
The magnitude of the change in the momentum of the billiard ball is 0.268 kg⋅m/s. The direction of the change of momentum vector points at 59.6 degrees, measured counterclockwise from the x-axis along the cushion.
This result can be found by using the equation for conservation of momentum, which states that both the magnitude and the direction of the momentum before and after the collision must be the same.
Since the mass and the speed of the ball changed, the direction of the vector must have changed as well. In this case, the vector changed direction from 60 degrees to 47 degrees, a difference of 13 degrees.
This means that the vector must have rotated counterclockwise by 13 degrees, or in other words, the change of momentum vector points at 59.6 degrees, measured counterclockwise from the x-axis along the cushion.
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if you had a microscope which was capable of doing this, what would the frequency of electromagnetic radiation be, in hertz, that you would have to use?
Answer:
The electric power didn’t last very long. It lasted only as long as the chemical reaction in the battery.
Explanation:
a stone is thrown down off a bridge with a velocity of 5.6 m/s. what is its velocity after 3 seconds have passed?
The velocity of the stone after 3 seconds have passed can be calculated using the formula v=u + at, where v is the velocity, u is the initial velocity, a is the acceleration (in this case the acceleration due to gravity, which is 9.8 m/s2), and t is the time. Therefore, the velocity of the stone after 3 seconds have passed will be 5.6 + (9.8*3) = 23.4 m/s.
The acceleration due to gravity causes any object to accelerate as it moves. This acceleration is always constant and acts downwards. Therefore, an object thrown with an initial velocity of 5.6 m/s will continue to accelerate and its velocity will increase. After 3 seconds have passed, the object will have an increased velocity of 23.4 m/s. In addition, when the stone is thrown off the bridge, it is subject to air resistance, which works against the stone and causes it to slow down. The magnitude of air resistance is dependent on a number of factors, such as the shape and size of the object. As such, the stone's velocity after 3 seconds might be slightly lower than the calculated value of 23.4 m/s.
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NEED HELP ASAP!!!!!!!!!!!!
Part B
Tape a meter stick to the side of the table. Make sure the zero end is on the floor. Carry out the experiment using the four drop heights you chose in task 1, part D. (You may want to have an adult drop the ball while you watch how high it bounces.) Perform three trials for each drop height, and record the data in the table. (You may choose to video the bounces and watch the video in slow motion to improve your data collection.) Finally, average the bounce height measurements to get a final reading. Round the average bounce heights to the nearest whole number.
Drop Height
First Drop
Bounce Height
Second Drop
Bounce Height
Third Drop
Bounce Height
Average Bounce Height
which way of varying the normal force to measure the coefficient of friction do you think is better? why?
There are two ways of varying the normal force to measure the coefficient of friction; namely, varying the weight of the object and tilting the surface.
What is the coefficient of friction?It is a term that refers to the force that opposes the motion of one surface on another when the two surfaces come into contact. Friction can be useful when we want to prevent the sliding of an object, but it can also be a disadvantage when we want the object to move.
In general, tilting the surface is a better way of varying the normal force to measure the coefficient of friction than varying the weight of the object. This is because the weight of the object can vary the force of gravity acting on the object, making it more challenging to calculate the coefficient of friction on the object.
On the other hand, by tilting the surface, we can achieve a more uniform change in normal force, making it easier to calculate the coefficient of friction. Additionally, by tilting the surface, we can eliminate any other factors that may affect the motion of the object, such as air resistance, making the coefficient of friction more accurate.
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the friends know that the field lines are a pictorial representation of the electric field at points in space. which of jacob's statements regarding the electric field vector and field lines is false?
Jacob's statement that is false is "The electric field vector is tangent to the electric field line at each point." The electric field lines indicate the direction of the electric field vector, but they are not necessarily tangent.
A vector is a quantity in physics that has a value and a direction. Examples of Vector quantities are: Velocity, Acceleration, Force, Momentum, and Impulse.
Electric field lines are a visual representation of the magnitude and direction of the electric field at a given point. For a point charge, the field lines originate from a positive charge and point away from a negative charge. The direction of the electric field vector is the same as the direction of the electric field lines, however, the field lines are not always tangent to the electric field vector.
complete question:
The friends know that the field lines are a pictorial representation of the electric field at points in space. Which of Jacob's statements regarding the electric field vector and field lines is false?
"The electric field vector is tangent to the electric field line at each point.""For a negative point charge, the electric field is directed radially outward.""The field line has a direction, indicated by an arrowhead, that is the same as that of the electric field vector.""For a positive point charge, the electric field is directed radially outward."The answer is 1
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the centripetal force in a collapsing cloud of gas and dust is strongest at the poles question 9 options: true false
The given statement "centripetal force in a collapsing cloud of gas and dust is strongest at the poles" is - True.
Centripetal force refers to a force that drives an object toward a fixed point, which is the center of a circular path. For example, if you tie a ball to a string and whirl it around in a circle, the string exerts a centripetal force on the ball that keeps it moving in a circle.
The force of gravity is the most common centripetal force that we encounter in nature, and it is what drives the movement of planets, moons, and other celestial objects.
During the formation of a star, a cloud of gas and dust collapses inwards due to gravity. The cloud starts to rotate as it shrinks due to the law of conservation of momentum. The centripetal force in this situation is the gravitational force that holds the cloud together.
The gravitational force, on the other hand, is stronger at the poles of the cloud. The gravitational force increases as the distance between the particles in the cloud decreases. Because the poles of the cloud are closer together, the gravitational force is stronger, and the centripetal force is also stronger.
As a result, the centripetal force in a collapsing cloud of gas and dust is strongest at the poles.
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a car is traveling at 40 m/s as it enters a turn of radius 25 meters. what minimum coefficient of friction must be maintained between the road and tires to make sure the car does not slide out of the turn?
The minimum coefficient of friction required for a car travelling at 40 m/s to not slide out of a turn of radius 25 meters is 0.21.
This is determined using the equation for the maximum centripetal force that the car can withstand. This equation states that the maximum centripetal force is equal to the mass of the car times its speed squared divided by the radius of the turn multiplied by the coefficient of friction. Using this equation, 0.21 is the coefficient of friction that is required to make sure the car does not slide out of the turn.
The equation for maximum centripetal force can be written as:
F = m*v2/r * μ Where m is the mass of the car, v is the velocity of the car, r is the radius of the turn, and μ is the coefficient of friction.
Since we are solving for the coefficient of friction (μ), we can solve this equation for μ:
μ = m*v2/r * F
Plugging in the given values, we get:
μ = (1000 kg) * (40 m/s)2 / (25 m) * (10000 N) = 0.21
Therefore, the minimum coefficient of friction required for a car travelling at 40 m/s to not slide out of a turn of radius 25 meters is 0.21.
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if you stand 8 m in front of a plane mirror and focus a camera on yourself, for what distance is the camera now focused?
The camera should be now focused at a distance of 16 meters.
The camera, in this case, should focus on the distance from the mirror to the object reflected by the mirror. The distance should be twice the distance of the object to the mirror.
The mirror image and the object should be equidistant from the mirror. This implies that the distance of the object from the mirror is equal to the distance of the mirror image from the mirror.
The distance that the camera should focus on is equal to the distance from the object to the mirror, multiplied by 2. Therefore, Distance from the object to the mirror = 8 meters
Distance from the camera to the object = distance from the mirror to the object, which is twice the distance from the mirror to the object
Distance from the camera to the object = 2 × 8 meters = 16 meters
Therefore, the camera should be focused at a distance of 16 meters.
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which term defines the distance from rest to crest, or from rest to trough?responsesamplitudeamplitudefrequencyfrequencyperiodperiodspeed
Amplitude is not measured from peak to trough, but from rest to peak or rest to trough.
The highest and lowest points on the surface of a wave are called crests and troughs respectively. The vertical distance between the peak and the trough is the height of the waves. The horizontal distance between two successive peaks or troughs is called the wavelength.
The amplitude of a wave is the maximum displacement of a particle on a medium with respect to its position of rest.
The amplitude can be thought of as the distance between rest and the peak. The amplitude from the rest position to the dip position can be measured in a similar manner.
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Which event is an example of vaporization?
A. The outside of a glass of ice water becomes moist. B. Perspiration dries on a person's skin. C. A cloud forms in the sky
D. Frost forms on a blade of grass
Perspiration dries on a person's skin. The correct answer is option B.
Vaporization is the process by which a liquid changes into a gas or vapor, and perspiration is a liquid that is secreted by sweat glands in the skin. When perspiration dries on a person's skin, it is evaporating and changing into a gas due to the heat energy from the person's body. This is an example of the physical change of state from a liquid to a gas through vaporization. The other options do not involve a change of state from a liquid to a gas, and instead involve other processes such as condensation. Hence option B is the correct answer .
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what is the relationship between index of refraction and the speed of the light in the medium of the index of refraction?
The relationship between the index of refraction and the speed of light in a medium is that the higher the index of refraction is: the slower the speed of light in that medium
The index of refraction is a measure of how much a light ray is bent, or refracted, as it enters a material or medium. The amount of refraction increases as the index of refraction increases, which in turn causes light to travel slower in the medium.
The index of refraction is related to the speed of light in the medium because the amount of refraction affects the speed of light in that medium. The index of refraction is a ratio between the speed of light in a vacuum and the speed of light in a medium.
This is calculated as the speed of light in a vacuum (c) divided by the speed of light in the medium (v). This ratio is usually represented as n, and so the formula for the index of refraction is: n = c/v. As the index of refraction increases, the speed of light in the medium decreases.
In a medium with a low index of refraction, the speed of light is higher than in a medium with a higher index of refraction. This is because a low index of refraction means that the light ray is not being refracted very much, so it is able to travel faster.
A higher index of refraction means that the light ray is being refracted more, so it is forced to travel slower. This explains the relationship between the index of refraction and the speed of light in a medium; the higher the index of refraction, the slower the speed of light in that medium.
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10. if both elements of the water heater in this residence are energized at the same time, how much current will they draw? (assume that each element is rated at 240 volts at 4500 watts.)
If both elements of the water heater in this residence are energized at the same time, they will draw 37.5 amperes of current. Each element of the water heater is rated at 240 volts at 4500 watts.
To calculate the current drawn by each element, we can use Ohm's law: V = IR, where V is the voltage, I is the current, and R is the resistance.
The resistance of each element can be calculated using the formula: [tex]R = V^2/P[/tex], where R is the resistance, V is the voltage, and P is the power.
So, the resistance of each element is:
[tex]R = V^2/P[/tex]
[tex]R = 240^2/4500[/tex]
R = 12.8 ohms
When both elements are energized at the same time, they are connected in parallel. The total resistance of two resistors in parallel can be calculated using the formula:
1/R_total = 1/R1 + 1/R2
So, the total resistance of the two elements is:
1/R_total = 1/12.8 + 1/12.8
1/R_total = 0.15625
R_total = 6.4 ohms
Now, we can use Ohm's law to calculate the current drawn by both elements:
I = V/R_total
I = 240/6.4
I = 37.5 amperes
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A mass is tied to a string and swung in a horizontal circle w a constant angular speed. Speed is doubled. What happens to the tension in the string?
The tension in the string becomes four times its original value when the angular speed is doubled.
When a mass is tied to a string and swung in a horizontal circle with a constant angular speed, the tension in the string is the centripetal force that keeps the mass moving in a circular path.
Step 1: Identify the relevant forces acting on the mass.
In this case, the centripetal force is the only force that needs to be considered, and it is provided by the tension in the string.
Step 2: Understand the relationship between centripetal force (Fc),
mass (m),
radius (r),
and angular speed (ω).
The centripetal force can be calculated using the formula:
Fc = m * r * ω^2
Step 3: Analyze the effect of doubling the speed (angular speed) on the tension in the string. Since the mass and radius remain the same, we can focus on the angular speed term in the formula.
When the angular speed is doubled, we have:
New angular speed (ω') = 2 * ω
Step 4: Calculate the new centripetal force (tension) in the string.
Substituting the new angular speed into the formula, we get:
Fc' = m * r * (ω[tex]')^2[/tex] = m * r * (2 * ω[tex])^2[/tex]
Step 5: Compare the new centripetal force (tension) with the original one. By expanding the equation, we find that:
Fc' = m * r * 4 * ω^2
= 4 * (m * r * ω[tex]^2)[/tex]
= 4 * Fc
This shows that when the angular speed is doubled, the tension in the string increases by a factor of 4.
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Calculate the number of moles in 6g of c
a 6,300-kg truck runs into the rear of a 1,000-kg car that was stationary. the truck and car are locked together after the collision and move with speed 2 m/s. what was the speed of the truck before the collision?
The speed of the truck before the collision was 3.2 m/s.
The speed of the truck before the collision can be determined using the principle of conservation of momentum. Momentum is the product of mass and velocity. Therefore, the momentum of the truck-car system before the collision is equal to the momentum of the truck-car system after the collision.
Let us assume the speed of the car before the collision is zero. Then the momentum of the truck-car system before the collision is equal to the momentum of the truck alone. This can be expressed mathematically as:
Mbefore = MtruckVtruck = (6,300kg)(Vtruck)
Mafter = (6,300kg + 1,000kg)(2 m/s)
By equating the two equations, we can solve for V, which gives us a value of 3.2 m/s.
Therefore, the speed of the truck before the collision was 3.2 m/s.
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the air in an organ pipe is replaced by helium (which has a lower molar mass than air) at the same temperature. how does this affect the normal-mode wavelengths of the pipe?
The normal-mode wavelengths decrease when the air in an organ pipe is replaced by helium, at the same temperature. This is because helium has a lower molar mass than air, and therefore a lower speed of sound, which causes the normal-mode wavelengths to decrease.
The normal-mode wavelengths are determined by the length of the pipe L and the speed of sound in the pipe
V.λn = 2L/nVn is the index of the mode, which can be any integer.
When helium is used instead of air, the speed of sound in the pipe rises because the mass of the helium molecules is smaller than that of the air molecules, so the gas molecules must travel quicker to achieve the same speed. Because the wavelength of a standing wave must fit into the pipe precisely, the increase in velocity causes the wavelength to decrease. The normal-mode wavelengths will be lowered as a result of this.
Thus, the answer is the normal-mode wavelengths decrease.
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an aluminum bar 3.78 m long has a rectangular cross section 1.18 cm by 5.23 cm . part a what is its resistance?
The resistance of the given aluminum bar is approximately [tex]1.62 \times 10^{-4} \ \Omega m[/tex].
To calculate the resistance of the aluminum bar, we need to use the formula:
[tex]R = (\rho \times L) / A[/tex]
Where R is the resistance, ρ is the resistivity of aluminum, L is the length of the bar, and A is the cross-sectional area of the bar.
The resistivity of aluminum is approximately [tex]2.65 \times 10^{-8}[/tex] ohm-meters (Ωm).
First, we need to convert the dimensions of the cross-sectional area from centimeters to meters:
1.18 cm = 0.0118 m
5.23 cm = 0.0523 m
Then, we can calculate the cross-sectional area of the bar:
[tex]A = (0.0118\ m) \times (0.0523\ m) = 6.16654 \times 10^{-4} \ m^2[/tex]
Now we can substitute the values into the formula for resistance:
[tex]R = (2.65 \times 10^{-8} \Omega m \times 3.78 m) / (6.16654 \times 10^{-4} \ m^2)[/tex]
[tex]R = 1.62 \times 10^{-4}[/tex]
Hence the resistance is [tex]1.62 \times 10^{-4} \ \Omega m[/tex].
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a spring with a spring constant of 54n/m sits on a desk. the spring is 44cm long. a block of mass 0.12kg is placed on top of the spring. how high above the desk does the block rest?
A spring with a spring constant of 54 N/m is situated on a desk. A block of mass 0.12 kg is put on top of the spring, which is 44 cm long. The height above the desk where the block rests is 0.0783 meters.
When a spring is compressed or elongated by a certain distance x, it exerts a restoring force that is proportional to the distance x, with a spring constant k.
The block will come to rest at a certain height above the desk as a result of the restoring force. As a result, we'll utilize the concept of elastic potential energy and equilibrium to find the height above the desk where the block rests.
Step 1: Find the extension of the spring.
x = F/k
where F = m g
where m is the mass of the block, and g is the acceleration due to gravity.
Substitute values in the equation
x = (0.12 kg) (9.81 m/s²) / (54 N/m) = 0.022 m = 2.2 cm
The spring has expanded by 2.2 cm when the block is put on it.
Step 2: Calculate the height of the block.
The potential energy stored in the spring is transferred to the block when it is put on the spring, and the block gains potential energy. This is the energy that the block has before it starts moving.
When the spring and the block are in equilibrium, the block's potential energy is transformed into gravitational potential energy, which is expressed as mgh, where m is the mass of the block, g is the acceleration due to gravity, and h is the height above the desk where the block is located.
mgh = 1/2 k x²h = (1/2 k x²) / mgh = (1/2 (54 N/m) (0.022 m)²) / (0.12 kg) (9.81 m/s²)h = 0.0783 m = 7.83 cm
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how does the conservation of angular momentum explain the increased speed of a planet in its orbit at perihelion? quizley
The conservation of angular momentum explains that a planet moves faster at perihelion due to an increase in angular velocity, resulting in an increase in linear velocity.
The conservation of angular momentum can be found as:
The conservation of angular momentum is a fundamental principle in physics that states that the total amount of angular momentum in a system remains constant unless acted upon by an external force.According to the law of conservation of angular momentum, when a planet moves closer to the Sun at perihelion, the decrease in distance causes the angular momentum to remain constant. Therefore, the velocity of the planet must increase to compensate for the decrease in distance. At perihelion, which is the point in the planet's orbit where it is closest to the Sun, the planet is moving faster than at any other point in its orbit.This is because as the planet gets closer to the Sun, the gravitational force between the two objects gets stronger, causing the planet to speed up in order to maintain its angular momentum.The closer the planet is to the Sun, the faster it has to move to keep from falling into it due to the strong gravitational pull.Therefore, the conservation of angular momentum explains why a planet speeds up at perihelion because the planet has to maintain its angular momentum as it gets closer to the Sun.To learn more about the angular momentum: https://brainly.com/question/4126751
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a battery is rated at 12 v and 160 a-h. how much energy does the battery store? select one: a. 3.2 kj b. 1.9 kj c. 1.9 mj d. 6.0 kj e. 6.9 mj
The battery stores 6.9 MJ (megajoules) of energy. To calculate this, multiply the voltage of 12 V by the Amp-hour rating of 160 A-h. The result is 1920 watt-hours (12 V x 160 A-h = 1920 Wh). Since 1 Wh = 0.0036 MJ, the total energy stored is 1920 x 0.0036 MJ = 6.9 MJ. Answer is option e
The energy stored in a battery can be calculated by multiplying the battery's voltage (V) by its capacity in ampere-hours (Ah). In this case, the battery is rated at 12 V and 160 Ah, so the energy stored can be calculated as:
Energy (in Joules) = Voltage (in Volts) x Capacity (in Ampere-hours) x 3600 seconds
Where 3600 seconds is the number of seconds in an hour. Plugging in the given values, we get:
Energy = 12 V x 160 Ah x 3600 seconds
Energy = 6,912,000 Joules
To convert Joules to other units, we can use the following conversion factors:
1 Joule = 0.001 kilojoules (kJ)
1 Joule = 1 x 10^-6 megajoules (MJ)
Therefore, the energy stored in the battery is 6,912,000 Joules, which is equivalent to 6.9 MJ
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