the snow globe below is formed by an hemisphere and cylinder on a cylinder base.

Answer:

Give options :/

Step-by-step explanation:

Answer:

Odd: f(-x) = -f(x)

Step-by-step explanation:

Odd: f(-x) = -f(x)

f(-1) = 5

-(f(1)) = 5

Answer:

answer recent question of my pr.ofil.e

Answer:

x ≥ -1

Step-by-step explanation:

Hello!

Solve for x by isolating the variable.

The inequality is true for all values of x greater than or equal to -1.

Answer:

56

Step by step explanation:

[tex]62+x-x^2\\\\\text{When x = 3}\\\\62+3 -3^2 = 62+3-9 = 65-9 = 56[/tex]

Answer:

the total mass of the products is equal to the total mass of the reactants

Step-by-step explanation:

The sum of the relative formula masses of the reactants is equal to the sum of the relative formula masses of the products.

Answer:

Slope of the line DV = -1

Step-by-step explanation:

Let point D (-5, 1) be [tex](x_{1}, y_{1})[/tex]

Let point V (-1, -3) be [tex](x_{2}, y_{2})[/tex]

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

Plug in the appropriate values,

[tex]m = \frac{-3-1}{-1-(-5)} = \frac{-4}{4} = -1[/tex]

slope equals -1

Answer:

Can you help me............. In my question

A) The equation for the growth of bacteria over time is : n(t) = 27(   [tex]e^{25t}[/tex])

B) The number of bacteria the would be in 5 minutes 1 hour is :

n(5mins) = 215.055 ,  n(1) = 1944132282109.422

C) The time it will take for the bacteria to reach a population of 10,000 is : t = 0.237 hours

Applying the mathematical growth and decay modelling

a. n(t) = [tex]n_{0}[/tex] [tex]e^{rt}[/tex]

[tex]n_{0}[/tex] = initial amount of bacterial

[tex]e^{rt}[/tex] = exponent

r = rate

t = time

n(t) = 27(   [tex]e^{25t}[/tex])

b. for 5 minutes

converting 5 minutes to hours; we divide by 60 minutes

[tex]\frac{5}{60}[/tex] = 0.083 hour

n(5 mins) = 27(   [tex]e^{25t}[/tex])

n(5 mins) = 27(   [tex]e^{25 * 0.083}[/tex])

n(5 mins) = 27(   [tex]e^{2.075}[/tex])

n(5mins) = 27(   7.965)

n(5mins) = 215.055

For 1 hour we have

n(1) = 27(   [tex]e^{25t}[/tex])

n(1) = 27(   [tex]e^{25 * 1}[/tex])

n(1) = 27(   [tex]e^{25}[/tex])

n(1) = 27 * (72004899337.386)

n(1) = 1944132282109.422

c. How long will it take for the bacteria to reach a population of 10,000?

10000 = 27(   [tex]e^{25t}[/tex])

[tex]\frac{10000}{27}[/tex] = (   [tex]e^{25t}[/tex])

370.370 = (   [tex]e^{25t}[/tex])

㏑ (370.370 ) = ㏑ (   [tex]e^{25t}[/tex])

5.915 = 25t

[tex]\frac{5.915}{25}[/tex] = t

t = 0.237 hours

In conclusion this type of question can be done by mathematical modelling

Learn more about mathematical modelling: https://brainly.com/question/4960142

Step-by-step explanation:

given :

h = 50 ft

the angle if elevation , a = 50°

find :

the distance , d =?

the answer:

tan a = h/d

d = h /tan a

= 50/ tan 50°

= 50 / 1,19

= 42,02 ft

Let's see

PEMDAS

Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS. PEMDAS is the order of operations, and stands for:

Parenthesis, Exponents (& Roots), Multiplication, Division, Addition, Subtraction.

First, divide 3 from both sides of the equation:

[tex]\frac{(3x^2)}{3} = \frac{(48)}{3}[/tex]

[tex]x^{2} = \frac{48}{3}\\ \\x^2 = 16[/tex]

Next, isolate the variable, x, by rooting both sides of the equation:

[tex]\sqrt{x^{2} } = \sqrt{16}\\ x = \sqrt{16} = \sqrt{4 * 4}[/tex]

x = ±4

C) ±4 is your answer.

~

Answer:

a= 28.27

Step-by-step explanation:

[tex]a=\pi r^2[/tex]

[tex]a=\pi 3^2\\a=28.27[/tex]

Answer:

-1

Step-by-step explanation:

g(2) = (2) - 3(2) + 4(2) - 5

g(2) = 2 - 6 + 8 - 5

g(2) = 2 - 6 + 3

g(2) = 2 - 3

g(2) = -1

Answer:

800 bacteria

Step-by-step explanation:

Answer of this question depend upon number of hours at the end of day

Let Take Full Day of 24 hrs

Colby bacteria will doubled 12 times ( doubled once in 2hrs => 24/2 = 12)

Colby bacteria at end of day = 50 * 2¹²

Jaquan bacteria will doubled 8 times ( doubled once in 3hrs => 24/3 = 8)

Let say Jaquan bacteria at start  of Day = J

Jaquan bacteria at end of day = J * 2⁸

Equating Both

J * 2⁸ = 50 * 2¹²

=> J = 50 * 2⁴

=> J = 50 * 16

=> J = 800

Jaquan will start  with 800 Bacteria

Answer:

530 m²

Step-by-step explanation:

First of all we need to label the missing sides ,please check the figure I provided for that :

x = 37 - (10+ 15) = 37 - 25 = 12

z = 10

y = 2 × 10 = 20

The shade does area = area of the whole rectangle − the white area

                                    = 37 × 20 − [ (15×20)÷2 + (10×12)÷2 ]

                                    =  740      − [    150        +      60       ]

                                    = 740.      −               210

                                    = 530

The Quotients of the given expression (2m + 4) / 8 divided by (m + 2)/6 would be 3/2.

Quotients are the number that is obtained by dividing one number by another number.

Dividend ÷ Divisor = Quotients

(2m + 4) / 8 divided by (m + 2)/6

= (2m + 4) / 8 ÷ (m + 2)/6

= (2m + 4)/8 x (6 / (m + 2) )

= (m + 2)/4 x 6/(m + 2)

= 6/4

= 3/2

Thus, the quotients will be 3/2.

Learn more about Quotients;

https://brainly.com/question/730603

Answer:

the product

= (x+4)(x+5)

= x^2 + 5x + 4x +20

= x^2 + 9x + 20
hope this helps!!!

Answer:

Step-by-step explanation:

Applying Distributive Property :

Combining Like-Terms :

Answer:

x=-50

Step-by-step explanation:

I used the method of balancing equations:

Add -40x to both sides

-38x+43 + 40x = -40x-57+40x

Simplify:

2x+43 = -57

Subtract 43 from both sides:

2x+43 -43 = -57 -43

Simplify:

2x =  -100

Solve for x

2x÷2 = -100÷2

x = -50

Hope this helped and brainliest please

Answer:

Step-by-step explanation:

In this question we have given an equation that is -38x + 43 = -40x - 57 . And we have to find the solution of this question that means we have to find the value of x .

So let's start our Solution : -

[tex] \hookrightarrow \: -38x+43=-40x-57 [/tex]

Step 1 : Subtracting 43 on both sides :

[tex] \hookrightarrow \: \: - 38x + \cancel{43} - \cancel{43 }= - 40x - 57 - 43[/tex]

On calculating further , We get :

[tex] \hookrightarrow \: - 38x = - 40x - 100[/tex]

Step 2 : Adding 40x on both sides :

[tex] \hookrightarrow \: - 38x + 40x = - \cancel{40x} - 100 + \cancel{40x}[/tex]

On calculating further , We get :

[tex] \hookrightarrow \:2x = - 100[/tex]

Step 3 : Dividing by 2 on both sides :

[tex] \hookrightarrow \: \frac{ \cancel{2}x}{ \cancel{2} } = \cancel \frac{ - 100}{2} [/tex]

On calculating further , We get :

[tex] \hookrightarrow \: \purple{\boxed{\frak{x = - 50}}}[/tex]

Verifying : -

Now we're verifying our answer by substituting value of x in given equation . So ,

Therefore , our solution is valid .

Answer: Reflection across the y-axis

Step-by-step explanation:

A reflection over a y-axis means that the original point (x, y) becomes (-x, y)

The original point (-2, 1) should become (-(-2), 1) which becomes just (2, 1).

(2, 1) is the reflected point hence it is a reflection across the y-axis

Answer:

d

Step-by-step explanation:

I got it right on the test

Answer:

173 degrees

Step-by-step explanation:

we know AED + AEB + BEC + CED = 360

AEB = 112

to find BEC, we have B + BCE + BEC = 180 because they form a triangle. so BEC = 180 - B - BCE = 180 - 73 - 79 = 28

to find CED, follow the same steps as BEC: 180 - 37 - 96 = 47

now AED = 360 - AEB - BEC - CED = 360 - 112 -  28 - 47 = 173

Answer: No solution

Step-by-step explanation:

       These two equations have parallel slopes and therefore no solution.

-> See attached for graph. Since there is no point of intersection, there is no solution.

Answer: False

Step-by-step explanation:

The lower case letter denotes a relation, not a function

Answer:

39.37 in

Step-by-step explanation:

Model mural::

L*W = 0.3 sq. ft

--------------

Actual mural::

(5L)(5W) = 25*LW = 25*0.3 = 7.5 sq ft.

Answer:

WFF

Step-by-step explanation:

savoy..it's me Wolfie it's been so long, I really hope you remember me...

Step-by-step explanation:

There two solutions. X can be zero cause anything divided by zero is undefined.

When dealing with positive numbers:

[tex]least \: to \: greatest \: for \: \: x \geqslant 1[/tex]

[tex] - \frac{1}{x} < \: \: 1 - x \: < \: \: x - 1 \: \: < x[/tex]

When dealing with negative numbers:

[tex]least \: to \: greatest \: for \: \: x < 0[/tex]

[tex] - x \: < x - 1 \: < - \frac{1}{x} \: < 1 - x[/tex]

I'(-4, -3)     J'(-4, -2)

K'(-2, -2)     L'(0, -4)    

[tex]I(0,-3)\rightarrow I'(0-4,-3)\rightarrow I'(-4,-3)\\ J(0,-2)\rightarrow J'(0-4,-2)\rightarrow J'(-4,-2)\\ k(2,-2)\rightarrow k'(2-4,-2)\rightarrow k'(-2,-2)\\ L(4,-4)\rightarrow L'(4-4,-4)\rightarrow L'(0,-4)\\ \{Conversion\ principle\}[/tex]

I hope this helps you

:)

Step-by-step explanation:

quotient is a result of the number

divided by a number

and if u want to divided with zero so division are not exis

can't divided by 0