Pls help easy math 2 pics

Answer:

-Dilate circle A by scale factor of 2

Got it right on the test (see picture)

Circle A is translated using the rule (x + 1, y - 1). Then the correct option is B.

It is a locus of a point drawn an equidistant from the center. The distance from the center to the circumference is called the radius of the circle.

Circle A has a center of (2,3) and a radius of 5, and circle B has a center of (1,4) and a radius of 10.

Circle B is translated as 1 unit leftward in the x-direction and 1 unit upward in the y-direction.

Then circle B is dilated by a factor of 2.

More about the circle link is given below.

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Answer:

2 is the base, 10 is the base, and x is the base. X is the exponent of 2, x is the exponent of 10, and x is the exponent of x.

Step-by-step explanation:

Step-by-step explanation:

The statements that describe the graph are,

The ball travels 24 cm in 1s.

It takes the ball 2s to complete a cycle

The midline is at f(x)=0

I hope it helped you

Answer:

45.27 miles

Step-by-step explanation:

Pythagorean theorem

23^2 + 39^2 = d ^ 2

d = 45.27 miles

If  a person drives 23 miles south and make a turn to east and drive 39 miles then the distance between starting point and person is 45.27 miles.

Pythagoras theorem applies in a right angled triangle. It says that in a right angled triangle the square of hypotenuse is equal to sum of squares of perpendicular and base of that triangle.

[tex]H^{2} =P^{2} +B^{2}[/tex]

When person drives towards south and then east , it forms a right angled triangle. We have to find the distance of person from the starting point. If we see the figure then we will come to know that we are require to find hypotenuse of triangle.

H=[tex]\sqrt{P^{2} +B^{2} }[/tex]

Distance=[tex]\sqrt{23^{2} +39^{2} }[/tex]

=[tex]\sqrt{1521+529}[/tex]

=[tex]\sqrt{2050}[/tex]

=45.27

Hence the distance of person from starting point is 45.27 miles.

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[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

Let's solve ~

First we have to calculate g (-5) :

[tex]\qquad \tt \dashrightarrow \:x - 8[/tex]

[tex]\qquad \tt \dashrightarrow \: - 5 - 8[/tex]

[tex]\qquad \tt \dashrightarrow \: - 13[/tex]

Now, let's find f (g (-5)) :

[tex]\qquad \tt \dashrightarrow \: {x}^{2} + 6x[/tex]

[tex]\qquad \tt \dashrightarrow \:( - 13) {}^{2} + (6 \times - 13)[/tex]

[tex]\qquad \tt \dashrightarrow \:169 + ( - 78)[/tex]

[tex]\qquad \tt \dashrightarrow \:169 - 78[/tex]

[tex]\qquad \tt \dashrightarrow \:91[/tex]

Answer:

  9.  3x² +x -2y +5 = 0

  10.  4x² +x -y +4 = 0

  11.  9x² -6x -3y -12 = 0

Step-by-step explanation:

"General form" of a polynomial equation is ...

  f(x, y) = 0

where the terms are arranged in lexicographical order and decreasing degree. That is, for terms of the same degree, x-terms are listed before y-terms, and xy terms are listed before y-only terms.

The leading coefficient can be positive or negative, your choice. (Positive is generally preferred.) For linear equations, "standard form" has the coefficients mutually prime. Making that happen for a general form polynomial would be your choice.

__

The highest-degree term is 3x². If we keep the leading coefficient positive, we can get general form by subtracting the expression on the left side of the equal sign.

  3x² +x -2y +5 = 0

__

Subtracting the right side gives ...

  4x² +x -y +4 = 0

__

Subtracting the left side gives ...

  9x² -6x -3y -12 = 0

or

  3x² -2x -y -4 = 0 . . . . . . remove a common factor of 3

Answer:

parallelogram

Step-by-step explanation:

sr/pq=sp/rq

ab/dc=ad/bc

Answer:

Proven.

Step-by-step explanation:

So, fasten your seatbelts, we're about to go on a long ride(◠‿・)—☆

» In a parallelogram, opposite sides are equal in length.

This can be represented (in the vector way) by

'QR = '-SP = 'PS and 'RS = 'QS (let “'” represent a vector)

'QR + 'SP= 0 and 'RS-'QS = 0

Note the signs. The signs are determined by the arrows in the diagram. [A reminder: If you walk from a point A to a point B, your displacement vector is 'AB. If you walk back, that is, from B to A; your displacement vector is 'BA which is also equal to '-AB.]

This means: to prove that PQRS is a parallelogram, we must prove that

'QR + 'SP= 0 and/or 'RS-'QS = 0.

In this solution, we will only work on the first equation.

Permit me to remove this ' sign.

QR = QC+CR ...1

QR= QB+BA+AD+DR...2

ADD 1 TO 2

2QR= QC+CR+QB+BA+AD+DR

[LOOK CLOSELY, QC+QB=0 ; CR+DR=0. This is because BQ+QC = BC

BUT, BQ=QC= (BC)/2

QC-BQ= 0

AND, -BQ= QB

QC+QB= 0 ;)]

2QR= BA+AD...3

★

SP = SA+AP...4

SP= SD+DC+CB+BP...5

ADD 4 TO 5

2SP = SA+AP+SD+DC+CB+BP

[AGAIN, SA+ SD = 0 ; AP+ BP = 0]

2SP= DC+CB...6

3+6

2QR+2SP= BA+AD+DC+CB

[ BA+AD+DC+CB, IN A SIMPLE WAY, MEANS:

you start from B, and move to A (BA); from A to D (AD); from D to C (DC); and from C to B (CB). Therefore, you have gone from B to B (from your starting point and back). Hence, your total DISPLACEMENT is zero (you haven't changed your position).

2(QR+SP) = 0

'QR+'SP= 0

PROVEN

You can work out the other equation, but it is evident that PQRS is a parallelogram.

An additional interest of $ 4.08 is earned in year 5 by using compound interest and in comparison with simple interest method.

Simple interest (C) is the amount of money gained and solely related to the initial capital ([tex]C_{o}[/tex]), in monetary units. The money earned by simple interest is determined by the following formula:

[tex]C = \frac{C_{o}\cdot r\cdot t}{100}[/tex]     (1)

Where:

Compound interest (C) takes into account the capital throughout time and its formula is presented below:

[tex]C = C_{o}\cdot \left[\left(1+\frac{r}{100} \right)^{t}-1\right][/tex]

Now we proceed to determine the simple and compound interest: ([tex]C_{o} = 1000[/tex], r = 2, t = 5)

C = [(1000) · (2) · (5)]/100

C = $ 100

C = (1000) · {[1+(2/100)]⁵-1}

C = $ 104.08

An additional interest of $ 4.08 is earned in year 5 by using compound interest and in comparison with simple interest method. [tex]\blacksquare[/tex]

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our number is x

we add seven (+7) to x

x+7

Answer:

The correct answer is 12/37

Answer:

92

Step-by-step explanation:

Add 95, 90, and 83 all together

add 92 to that total

divide by 4

It will take approximately 169 minutes for a the rocket to travel a distance of  1,260,000,000 feet at 1,540,000 ft/min

Given Data

Applying the relationship between speed, distance and time we have

Speed = Distance/Time

Substituting our given data into the expression we have

1,540,000  = 260,000,000/time

Making time subject of formula

time = 260,000,000/1,540,000

time = 169 miniutes

Learn more about speed, distance and time  here:

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Answer:

6 miles in 66 mins

Step-by-step explanation:

4 miles = 44 mins

simplify to the lowest point

1 mile = 11 mins

? = 66 mins

? = 1 x 6

you can run 6 miles in 66 mins

Answer:

Step-by-step explanation:

4/44= 0.0909090909...*66=6

find the propotunate value by dividing each initial value and multiply it by the listed secondary value

Answer:

Correct ones A and F

------------------------------------------

Correct ones H and K

Answer:

  350 adult tickets

Step-by-step explanation:

If x is the number of adult tickets sold, then x-57 is the number of student tickets sold (57 fewer). The total number sold is ...

  x +(x -57) = 643

  2x = 700 . . . . . . . . collect terms, add 57

  x = 350 . . . . . . . divide by 2

There were 350 adult tickets sold.

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

Let's solve ~

[tex]\qquad \tt \dashrightarrow \:(3 {x}^{5} \times 2xy) - ( {x}^{2} y \times 4 {x}^{4} )[/tex]

[tex]\qquad \tt \dashrightarrow \:6 {x}^{6} y - 4 {x}^{6} y[/tex]

[tex]\qquad \tt \dashrightarrow \:2 {x}^{6} y[/tex]

= (3x^5× 2xy) — (x^2y × 4x^4)

= 6x^6y - 4x^6y

= 2x^6y

Answer:

$121,683.79

Step-by-step explanation:

A= P(1+ r)^t

A= Amount, P = Principal, r = Rate (decimal form), t= time

A = 47000(1+0.0825)^12

A = 47000(1.0825)^12

A = 47000(2.589016751)

A = 121683.7873

Rounded Answer = $121,683.79

(If there is meant to be no cents then $121,684). Good luck :)

Answer:

-6

Step-by-step explanation:

-2x - 9 = 4/3x+11

-

-6x-27=4x+33

-

-6x-27-4x=33

-

=6x-4x=33+27

-

10x=33+27

-

-10x=60

-

x= -6

Answer:

  245 ft

Step-by-step explanation:

The geometry of the problem can be modeled by a right triangle in which Meena's height is the side opposite the angle of depression, and the distance to the boat is the side adjacent to the angle of depression. The mnemonic SOH CAH TOA reminds us of the relation ...

  Tan = Oppsite/Adjacent

__

The more useful trig function for this problem is the inverse of the tangent function, the cotangent. Using that function, we have ...

  cot(angle) = (distance to boat)/(Meena's height)

Then the distance to the boat is ...

  distance to boat = (Meena's height)×cot(angle)

The change in distance from A to B is then ...

  A -B = (120 ft)(cot(18°) -cot(44°))

  = (120 ft)(3.0777 -1.0355) ≈ 245.06 ft

The distance from point A to point B is about 245 feet.

Answer:

$ 200

Step-by-step explanation:

$ per ticket   =   $ 120 / 3 tix

Price for 5     $120 / 3 tix  * 5 tix = $ 200

Answer:

15 years old

Step-by-step explanation:

Start by defining the variables that we are going to use throughout our working:

Let the current age of Wei Ling and Wei Xuan be L and X years old respectively.

Next, form equations using the given information.

5 years ago

Wei Ling: (L -5) years old

Wei Xuan: (X -5) years old

Given that the ratio of Wei Ling's age to that of Wei Xuan's is 2: 5,

[tex] \frac{ L - 5}{X - 5} = \frac{2}{5} [/tex]

Cross multiply:

2(X -5)= 5(L -5)

Expand:

2X -10= 5L -25

2X= 5L -25 +10

2X= 5L -15 -----(1)

9 years time

Wei Ling: (L +9) years old

Wei Xuan: (X +9) years old

Given that the ratio of Wei Ling's age to that of Wei Xuan is 3: 4,

[tex] \frac{L + 9}{X + 9} = \frac{3}{4} [/tex]

Cross multiply:

3(X +9)= 4(L +9)

Expand:

3X +27= 4L +36

3X= 4L +36 -27

3X= 4L +9 -----(2)

Let's solve using the elimination method.

(1) ×3:

6X= 15L -45 -----(3)

(2) ×2:

6X= 8L +18 -----(4)

(3) -(4):

6X -6X= 15L -45 -(8L +18)

0= 15L -45 -8L -18

0= 7L -63

7L= 63

L= 63 ÷7

L= 9

Substitute L= 9 into (1):

2X= 5(9) -15

2X= 45 -15

2X= 30

X= 30 ÷2

X= 15

Thus, Wei Xuan is 15 years old now.

coat cost= $60.

the fraction of amount she needs to save.

saved/ actual cost

= $42/ $60 ÷ 2/2

= 21/30

answer= option a) 21/30

Answer: 10

Step-by-step explanation:

Answer:

(-10,0)

Step-by-step explanation:

2a =[2(-2) , 2(-3)] = (-4 -6) <--- add them

-3b = [-3(1) . -3(-1)] = (-3 +3) <--- add them

2a - 3b =  

[(-4  -6), (-3  +3)] =

(-10,0)

The angle at which the ball takes off, distance the ball in the air, the ball's speed is mathematically given as

Generally, the equation for the verticle component   is mathematically given as

[tex]y=xtan\theta-\frac{16x^2}{v0cos^2\theta}\\\\Therefore\\\\\theta=tan^{-1}(1.8)[/tex]

theta=60

b)

hmax=vo^2sin^2\theta/2g

vo=116.486

Therefore, distance the ball in the air

[tex]d=\frac{2*114.486*0.874*2}{32}[/tex]

d=6.3658

c)

The ball's speed when it hits the ground will be vo

vo=116.486

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Answer:

B

Step-by-step explanation:

It's 18! Obviously it's not 180 because it's too big. It can't be 36 because 36 doesn't go evenly into 90. 6 is too small, so the answer is 18.