The magnitude of the constant acceleration of the ball is 9.7 m/s².
What is acceleration?Acceleration is the rate of change of velocity.
To calculate the constant acceleration of the ball, we use the formula below.
Formula:
a = (v-u)/t................. Equation 1From the question,
Given:
a = Acceleration,v = Final velocityu = Initial velocityt = TimeFrom the question,
Given:
v = 33 m/su = 0 m/s t = 3.4 secondsSubstitute these values into equation 1
a = (33-0)/3.4a = 9.7 m/s²Hence, the acceleration is 9.7 m/s².
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if a referee tosses a basketball in the air and hits the floor, at what point will the ball have no mechanical kinetic energy (hint: this occurs at more than one point)
the ball have no mechanical kinetic energy:
Just before the ball is set in motion in the air. Just after it hits the floor.What is mechanical kinetic energy?This refers to the energy that an object possessed due to its motion or due to its position. It is calculated by getting the product of the mass of the object and its velocity and dividing it by two. It is measured in joules, J.
if a referee tosses a basketball in the air, the ball will not have mechanical kinetic energy:
Just before the ball is set in motion in the air. ( Potential energy that is energy due to an object's position).Just after it hits the floor. ( Potential energy that is energy due to an object's position).Learn more about kinetic energy on
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The Earth wire only carries a current if there is a _____ in the
circuit. What one word completes the sentence?
Answer:
Fault
Explanation:
it only carries a current if there is a fault.
A gas is placed in a 5.0-mL syringe. It exerts 141 mm Hg of pressure on the inside walls of the syringe. The syringe's plunger is pressed, reducing the volume of the syringe to 2.9 mL. The cap was not removed from the syringe, so none of the gas escapes. Assuming the temperature of the gas does not change, use Boyle's law (below) to determine the pressure of the compressed gas. P_1V_1 = P_2V_2
Answer: [tex]243.10\ mm\ \text{of}\ Hg[/tex]
Explanation:
Given
The initial volume of gas [tex]V_1=5\ ml[/tex]
Initial pressure is [tex]P_1=141\ mm\ \text{of}\ Hg[/tex]
Final volume is [tex]V_2=2.9\ ml[/tex]
As it is given [tex]P_1V_1=P_2V_2[/tex]
insert the values
[tex]141\times 5=P_2\cdot 2.9\\P_2=243.10\ mm\ \text{of}\ Hg[/tex]
Bonjour ,
je n'arrive pas a comprendre cet exercice de physique niveau 5eme.
Ceci concerne le chapitre sur l'éléctricité .
MERCI
Answer:
Bonjour! Mon francais est assez rouillé, mais faire de mon mieux pour traduire la page; voici les principaux points:
1. (Une) Le rôle de la boule de flotteur dans le circuit électrique est qu'il permet à la pompe d'arrêter lorsque l'eau n'est pas le bon niveau en venant en contact avec deux conducteurs et la fermeture du circuit électrique.
2. (Deux) Je veux dire que le matériau qui constitue la balle en isolant, car il maintient l'eau et hors de blocage force active de la machine.
3. (Trois) Le courant électrique continuera aussi longtemps que la pompe est branchée sur une prise électrique, je crois.
Encore une fois, s'il vous plaît pardonnez-moi, je suis mieux à la lecture de français que de l'écrire! J'espère que cela a pu aider. Si vous avez plus de questions, je vais faire de mon mieux pour y répondre!
Salut!
A force F making an angle with the horizontal is acting on an object resting on the table. Which statement is true for the motion of sliding the object on the table? A. It is independent of all the forces acting on the object. B. It depends only on the forces acting along the x-axis. C. It depends only on the forces acting along the y-axis. D. It depends only on the normal force acting on the object. E. It depends only on the frictional force acting on the object.
Answer:
C
Explanation:
it depends only on the forces acting along the y- axis
Answer:
The statement that is true for the motion of sliding the object on the table is : its independent of all forces acting on the object
Explanation:
The coyote, whose mass is 20kg is chasing the roadrunner when the coyote accidentally runs off the edge of the cliff and plummets to the ground 30m below. What force does the ground exert on the coyote as he makes a coyote-shaped dent 0.420m deep in the ground.
The force is 196 N (20kg x 9.8 m/s2)
What is force ?Force is an action or influence that causes an object to change its state of motion or rest. Force can be exerted by a single object or by two or more objects interacting with each other. Examples of force include friction, gravity, magnetism, electricity, and pressure. The magnitude of a force is usually measured in newtons (N) and is determined by the amount of mass and acceleration of the object it is acting upon.
The force exerted on the coyote by the ground is equal to the mass of the coyote multiplied by the acceleration due to gravity, which is 9.8 m/s2.
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A horizontal spring mass system is to be constructed. A spring which has a spring constant of 3 kg/s2 will be used. The system should be designed so that when it is released and vibrating freely (there is no forcing) the amplitude of its vibrations will decay like ????−0.4t, and it should oscillate with a period of 4 seconds.
(Although the motion is oscillatory it is not strictly periodic because the amplitude decays exponentially. In this context "period" refers to the period of the sine and/or cosine functions that create the oscillations in the motion.)
Based on these constraints determine the mass of the object, ????(kg), to be used, and also determine the value of the friction coefficient, ???? (kg/s).
????: kg
b: kg/s
Answer:
a) 1.1418 kg
b) 0.9135 kg/s
Explanation:
Given data :
spring constant ( k ) = 3 kg/s^2
amplitude of vibrations will decay like :
The mass of the object will be 1.418 kg and the value of the friction coefficient, b is 0.9135 kg/s.
What is Periodic motion?In physics, a periodic motion is a movement that repeats at regular intervals. A swing in motion, a rocking chair, a bouncing ball, a tuning fork vibrating, the Earth orbiting the Sun, and a water wave are all examples of periodic motion. The time interval for repetition, or cycle, of the motion, is referred to in each case as a period, and the frequency is the number of periods per unit of time.
According to the question, the given values are :
Spring constant, k = 3 kg/s²,
Time, T₁ = 4 sec
r = 0.4
The formula for damped oscillation is : [tex]e^-^r^t[/tex]
r = b / 2 m
w₁ = [tex]\sqrt{w_0^2-r^2}[/tex]
T₁ = 2π / w₁
= 2 π / [tex]\sqrt{w_0^2-r^2}[/tex]
w₀ = [tex]\sqrt{4 \pi^2/T_1 +r^2}[/tex]
[tex]\sqrt{k/m}[/tex] = [tex]\sqrt{4 \pi^2/T_1 +r^2}[/tex]
M = k / [tex]{4 \pi^2/T_1 +r^2}[/tex]
M = 3/ (4π/4² +(0.4)²)
M = 1.1418 kg
b = 2 Mr = 2 × 1.1418 × 0.4
b = 0.9135 kg/s
Hence, the mass of the object is 1.1418 kg and the friction coefficient is 0.9135 kg/s.
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A 5,257 kg rocket blasts off to the moon with an acceleration of 76 m/s ^2 what is the net force on the rocket
Newton's subsequent law expresses that power is corresponding to what exactly is needed for an object of consistent mass to change its speed. This is equivalent to that item's mass increased by its speed increase. We use Newtons, kilograms, and meters each second squared as our default units, albeit any proper units for mass (grams, ounces, and so forth) or speed (miles each hour out of every second, millimeters per second2, and so on) could unquestionably be utilized also - the estimation is the equivalent notwithstanding.
Hence, the appropriate answer will be 399,532.
Net Force = 399532
A student decides to give his bicycle a tune up. He flips it upside down (so there's no friction with the ground) and applies a force of 34 N over 0.6 seconds to the pedal, which has a length of 16.5 cm. If the back wheel has a radius of 33.0 cm and moment of inertia of 1200 kg cm^2, what is the tangential velocity of the rim of the back wheel in m/s
Answer:
[tex]V=9.2565m/s[/tex]
Explanation:
From the question we are told that:
Force [tex]F = 34 N[/tex]
Time [tex]t = 0.6 s[/tex]
Length of pedal [tex]l_p=16.5cm \approx0.165m[/tex]
Radius of wheel [tex]r = 33 cm = 0.33 m[/tex]
Moment of inertia, [tex]I = 1200 kgcm2 = 0.12 kg.m2[/tex]
Generally the equation for Torque on pedal [tex]\mu[/tex] is mathematically given by
[tex]\mu=F*L\\\mu=34*0.165[/tex]
[tex]\mu=5.61N.m[/tex]
Generally the equation for angular acceleration [tex]\alpha[/tex] is mathematically given by
[tex]\alpha=\frac{\mu}{l}[/tex]
[tex]\alpha=\frac{5.61}{0.12}[/tex]
[tex]\alpha=46.75[/tex]
Therefore Angular speed is \omega
[tex]\omega=\alpha*t[/tex]
[tex]\omega=(46.75)*(0.6)[/tex]
[tex]\omega=28.05rad/s[/tex]
Generally the equation for Tangential velocity V is mathematically given by
[tex]V=r\omega[/tex]
[tex]V=(0.33)(28.05)[/tex]
[tex]V=9.2565m/s[/tex]
George is studying a mechanical wave. He counts thirty crests of the wave pass through a point in 10 seconds.
If What is the frequency of this wave?
Select one:
2 Hz.
20 Hz.
3 Hz.
30 Hz.
Answer:
Option C
Explanation:
Frequency determines the number of waves that pass through any defined point in a given time period.
Frequency of 1 hertz means that one wave travels through a given point in one second.
By the above definition, we can say
Frequency
[tex]= \frac{30}{10} \\=3[/tex]
Hence, option C is correct
What influences speed of an objects fall? (Choose as many as apply)
1. Sunlight
2. Air
3. Altitude
4. Heat
Altitude and Air
but mainly altitude, Air is just depending on the situation.
Air does not always influence an object's fall, but Altitude always influences it.
You push a cart with mass 30 kg forward, giving it an acceleration of 5 m/s2How much force did you apply? O A. 0.17 N O B. 35 N O C. 75 N O D. 150 N
Answer:
150N
Explanation:
To find the force applied remember that force equals to Mass multiply by the Acceleration.
F=Ma
=30*5
=150N
Answer:
150N
Explanation:
F = m*a = 30 * 5 = 150 N
Two engines create SIL values of 75 dB and 85 dB respectively. What dB reading would you expect when both are run simultaneously?
Answer:
Explanation:
In a quiet forest, you can sometimes hear a single leaf fall to the ground. ... greater its pressure amplitude, the more the air is compressed in the sound it creates. ... Graphs of the gauge pressures in two sound waves of different intensities. ... The sound intensity level β in decibels of a sound having an intensity I in watts per .
A coil of 27 turns is in the shape of an ellipse having a major axis of 12.0 cm and a minor axis of 9.00 cm. The coil rotates at 57rpm in a region in which the Earth's magnetic field is 74.0 microT. What is the maximum voltage induced in the coil if the axis of rotation of the coil is along its major axis and this axis of rotation is aligned perpendicular to the Earth's magnetic field
Answer:
Explanation:
Emf induced e = nBAω sinωt where n is no of turns , B is magnetic field, A is area of the coil ω is angular frequency of rotation .
maximum emf = nBAω
Given n = 27 , B = 74 x 10⁻⁶ T , A = .12 m x .09 m = 108 x 10⁻⁴ m²
ω = 2π x 57/60 = 5.966 rad/s .
Putting the values
maximum emf = 27 x 74 x 10⁻⁶ T x 108 x 10⁻⁴ m² x 5.966 rad/s .
= 1.29 x 10⁻⁴ V .
A lawnmower is pushed with a force of 72 Newtons at an angle of 40 degrees from the horizontal. How much work is done to the mower if it moves 740 meters?
The work done to the mower is the product of the external force applied on the object and the distance covered by the object which is equal to 40,811 Joules.
What is Work done?Work done on an object can be defined as the product of external force applied on the object and the distance over which the force is being applied on the object. Work is done on an object when a force is applied to an object and the object is moved through certain distance.
From this we can see that the horizontal component of the force:
X-Component (horizontal component):
cos(θ) = x/F
Then,
X= F cos(θ).…..(1)
Now putting the values of F and θ in equation (1) we get,
X = 72 N × cos(40)
X = 72 N × 0.766
X= 55.15 N this is the x-component force
The work done to the mower is:
W = F × d
W = 55.15 × 740
W = 40,811 Joules
The work done to the mower is 40811 Joules.
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A wave is traveling at a speed of 12m/s and its wavelength is 3 m calculate the wave frequency
Answer:
f = 4 Hz
Explanation:
Given that,
The speed of a wave, v = 12 m/s
The wavelength of a wave, [tex]\lambda=3\ m[/tex]
We need to find the frequency of the wave. We know that the speed of wave is equal to the product of wavelength and frequency. So,
[tex]v=f\lambda\\\\f=\dfrac{v}{\lambda}\\\\f=\dfrac{12}{3}\\\\f=4\ Hz[/tex]
So, the frequency of the wave is equal to 4 Hz.
a mango fruit drop down from top of its tree which is 5m high. How long does it take to reach the ground
Answer:
What is the mass tho?
You need the mass to answer this question
Answer:
[tex]distance = ut + \frac{1}{2} g {t}^{2} \\since \: the \: fruit \: is \: from \: rest : \: initial \: velocity \: is \: 0 \: (u = 0) \\ 5 = (0 \times t) + ( \frac{1}{2} \times 9.81 \times {t}^{2} ) \\ 5 = 4.905 {t}^{2} \\ t = \sqrt{1.0194} \\ t = 1 \: second[/tex]
¿Con qué cualidad del sonido está relacionada la Amplitud de onda?
Answer:
Amplitud (dinámica)
Explanation:
La amplitud de una onda de sonido determina su volumen relativo. En música, el volumen de una nota se denomina nivel dinámico.
6. An object experiences a force of 4N left and 4N right, what is the net force?
Answer:
The net force is equal to zero.
Explanation:
Two equal forces going in opposite directions will always result in a net force of 0.
Answer:
The net force would be 0.
Explanation:
If you have equal amounts of force on each side it is 0. If you had different amounts of force on each side the side you would subtract the greater one form the smaller one equalling your net force.
what is polarization of light?
Answer:
Polarized light waves are light waves in which the vibrations occur in a single plane. The process of transforming unpolarized light into polarized light is known as polarization. There are a variety of methods of polarizing light.
Explanation:
A 3.89 x 10-8 F capacitor has a
voltage applied, which creates
1.15 x 10-10 C of charge on the
plates. What voltage was applied?
Answer:
0.00296
Explanation: This answer works for Acellus! :)
The voltage applied to the capacitor is approximately 2.964 x 10⁻³ C/F.
Capacitance is a fundamental electrical property that measures the ability of a system to store an electric charge when a potential difference (voltage) is applied across it. It is denoted by the symbol "C" and is measured in farads (F). A capacitor is a device commonly used to create capacitance in an electrical circuit.
In simple terms, capacitance is a measure of how much electric charge can be stored on an object (usually a capacitor) for a given electric potential difference. It is directly proportional to the amount of charge stored and inversely proportional to the applied voltage. Capacitance plays a crucial role in various electronic circuits and systems, including filtering, energy storage, and timing applications.
To calculate the voltage applied to the capacitor, we can use the formula:
Q = C × V
Where:
Q is the charge on the plates of the capacitor
C is the capacitance
V is the voltage applied to the capacitor
Given:
Capacitance (C) = 3.89 x [tex]10^{(-8)[/tex] F
Charge on the plates (Q) = 1.15 x [tex]10^{(-10)[/tex]C
Rearranging the formula, we can solve for V:
V = Q / C
Substituting the given values:
V = (1.15 x [tex]10^{(-10)[/tex] C) / (3.89 x [tex]10^{(-8)[/tex] F)
Dividing the numerator and denominator by [tex]10^{(-8)[/tex]:
V = (1.15 / 3.89) x [tex]10^{(-10 - (-8))[/tex] C/F
V = (1.15 / 3.89) x [tex]10^{(-2)[/tex] C/F
V = 0.2964 x [tex]10^{(-2)[/tex] C/F
Using scientific notation, we can express the voltage as:
V = 2.964 x [tex]10^{(-3)[/tex]C/F
Therefore, the voltage applied to the capacitor is approximately 2.964 x [tex]10^{(-3)[/tex] C/F.
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Net work W would accelerate an object from rest to velocity v. What net work is needed to accelerate the object from rest to velocity 2v?
The net work that is needed to accelerate a 2.0 kg mass from rest to velocity 2v is 4.0 m/s.
What is net work done?When a force acts on a body at rest or at uniform motion in a straight line, then it starts to accelerate.
Given that, the velocity is 5.0
Time is 2 sec
The given mass is 2.0 kg
First, we calculate the acceleration
Acceleration = v / t = 10 / 5.0 = 2
From Newton's second law, we know that
force = mass x acceleration
F = ma
F = 2.0 x 2 = 4.0 m/s
Therefore, the net work that is needed to accelerate a 2.0 kg mass from rest to velocity 2v is 4.0 m/s.
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The question is incomplete. Your most probably complete question is given below:
What net force is needed to accelerate a 2.0 kg mass from rest to a velocity of 10 m/s in 5.0 s?
A particle which is moving in a straight line with a velocity of 15m/s accelerates uniformly for 3.0s, increasing its velocity to 45m/s. What distance does it travel while accelerating
The distance travel while accelerating is 90m
The initial velocity of the particle is 15m/s and the final velocity is 45m/s, so the change in velocity is 45m/s - 15m/s = 30m/s. The particle accelerates uniformly for 3.0s, so the acceleration is 30m/s / 3.0s >>30/3=10 that is 10m/s^2.
The distance traveled during the acceleration is equal to the average velocity times the time elapsed, so the distance traveled is (15m/s + 45m/s)/2 * 3.0s = (15+45)/2*3= 90m .
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(eopt)s. Find the power dissipated in a 25 r heater
connected to a 220V outer.
Answer:
P = 1936 W
Explanation:
Given that,
Voltage, V = 220 V
The resistance of the heater, R = 25 ohms
We need to find the power dissipated in the heater. We know that the power dissipated by the electric appliances is given by :
[tex]P=\dfrac{V^2}{R}\\\\P=\dfrac{(220)^2}{25}\\\\P=1936\ W[/tex]
So, the required power is equal to 1936 W.
1. What does Louis de Broglie's principle propose about electrons?
They have energy and momentum.
They behave as a wave and a particle.
They contain high-energy and low-energy photons.
They interact with other electrons to form new substances.
Louis de Broglie's principle of electrons states that (b) They behave as a wave and a particle.
The de Broglie equation is one of the equations that is commonly used to define the wave properties of matter. It basically describes the wave nature of the electron.Electromagnetic radiation, exhibit dual nature of a particle (having a momentum) and wave (expressed in frequency, wavelength). Microscopic particle-like electrons also proved to possess this dual nature property.Louis de Broglie in his thesis suggested that any moving particle, whether microscopic or macroscopic will be associated with a wave character. It was called ‘Matter Waves’. He further proposed a relation between the velocity and momentum of a particle with the wavelength, if the particle had to behave as a wave.Particle and wave nature of matter, however, looked contradictory as it was not possible to prove the existence of both properties in any single experiment. This is because of the fact that every experiment is normally based on some principle and results related to the principle are only reflected in that experiment and not the other.To know more about electrons visit:
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Question 18 (2 points)
Which statement is TRUE about the relationship between magnetic fields and
electric charges.
A. Moving electric charges (electrons in a circuit) creates a magnetic field and
a magnetic field can cause an electric charge to move (electricity).
B. Moving electric charges (electrons in a circuit) creates an electric field and
a magnetic field can cause static electricity.
C. Static (not moving) electric charges creates a magnetic field and a magnetic field
can cause electricity to stop flowing.
Answer:
A.Moving electric charges (electrons in a circuit) creates a magnetic field and
a magnetic field can cause an electric charge to move (electricity).
Explanation:
A Ferris wheel, rotating initially at an angular speed of 0.16 rad/s, accelerates over a 8.0-s interval at a rate of 0.040 rad/s2. What is its angular speed after this 8.0-s interval?
Answer:
0.48 rad/s
Explanation:
We can use this equation to find the final velocity
[tex]w_f=w_0+at[/tex]
We are given
[tex]w_0=0.16[/tex]
[tex]t=8.0[/tex]
[tex]a=0.04[/tex]
Inserting those numbers into our equation gives us
[tex]w_f=0.16+0.04*8[/tex]
Lets solve for [tex]w_f[/tex].
[tex]w_f=0.16+0.32[/tex]
[tex]w_f=0.48[/tex]
1. Compare and contrast sensation and perception.
2. Describe an example of sensory adaptation that you have experienced.
3. Why would it be difficult to play a sport such as baseball or basketball without the ability
to perceive depth?
4. Do you think that subliminal messages should be banned from advertising? Why or why
not?
5. What is your opinion about extrasensory perception? Do you think it exists? Explain your
answer.
A frog jumps as is moves. what is the relation between its maximum height and maximum range
The relation between a frog's maximum height and maximum range is that when the frog jumps at an angle of 45°, its maximum height is half of the horizontal range.
What are the maximum height and maximum range?The maximum height refers to the maximum vertical distance that an object can travel.
The maximum range is the maximum horizontal distance that an object can travel.
The maximum height, H that the projectile reaches when the range, R, is at its greatest is H = Rmax /4.
R = 4Hcot is the relationship between the horizontal range and maximum height.
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the angel between vector a A = 2.00i + 3.00i and vecto B is 45 degree , the scalar product of vectors A and B is 3.00 if the x component of vector B is positive , what is the vector B
I think the answer is b but im not really sure