Answer:
y = [tex]\frac{1}{2}[/tex] x + 4
Step-by-step explanation:
1). Slopes of ║ lines are equal.
2). Equation of the line passing through the point ( [tex]x_{1}[/tex] , [tex]y_{1}[/tex] ) is
y - [tex]y_{1}[/tex] = m( x - [tex]x_{1}[/tex] )
~~~~~~~~~~~~~~~~~~
y = [tex]\frac{1}{2}[/tex] x - 10 , slope m = [tex]\frac{1}{2}[/tex]
( 2 , 5 )
y - 5 = [tex]\frac{1}{2}[/tex] ( x - 2 )
y = [tex]\frac{1}{2}[/tex] x - 1 + 5
y = [tex]\frac{1}{2}[/tex] x + 4
#1
y=1/2x-10Comapre to slope intercept form
Slope=m=1/2Parallel lines have equal slope
Equation of parallel line in point slope form
y-5=1/2(x-2)2y-10=x-22y=x+8y=1/2x+4What is the equation of the line that passes
through the point (-2,2) and the point (-6,4)?
Answer:
y = -1/2x+1
Step-by-step explanation:
First step is to find the slope
m = (y2-y1)/(x2-x1)
= ( 4-2)/(-6 - -2)
(4-2)/(-6+2)
2/-4
-1/2
Then we can use the slope intercept form of a line
y = mx+b where m is the slope and b is the y intercept
y = -1/2x+b
Substitute a point into the equation to find b
2 = -1/2(-2) +b
2 = 1+b
Subtract 1 from each side
1 =b
y = -1/2x+1
y = mx + b
Where m = slope and b is the y intercept
Let's find the slope = change in y/change in x
m = (4-2)/(-6+2) = 2/-4 = -1/2
Now we have:
y = (-1/2)x + b
Now substitute point (-6,4)
4 = (-1/2)(-6) + b
4 = 3 + b
b = 1
So y = (-1/2)x + 1 is the equation
ANSWER:
[tex]y=(-\frac{1}{2})x[/tex]+1
so letter c
One baseball team won 30 games throughout their entire season. Of all their games, this team won 60% of them. Given this, how many games in total did this team play? Round your answer to the nearest whole number if necessary.
Answer:
18 Games
Step-by-step explanation:
For this problem we will have to use the same percentage Therom again, except this time we are solving for a diffrent variable.
Total Games * Percentage won in fraction form = Games won
Fill the values.
30 * 3/5 = X
Simplify
18=X
Which value of b will cause the quadratic equation x2 bx 5 = 0 to have two real number solutions?
Any value in the interval (-∞,-2√5] ∪[2√5,∞) will cause the quadratic equation x2+bx+5 = 0 to have two real number solutions.
Given quadratic equation is:
[tex]x^{2} +bx+5=0[/tex]
What is a quadratic equation?Any equation of the form [tex]ax^{2} +bx+c=0[/tex] is called a quadratic equation where a≠0.
To have two real number solutions the discriminant of a quadratic equation should be greater than or equal to zero.
[tex]D\geq 0[/tex]
[tex]b^{2} -4(1)(5)\geq 0[/tex]
[tex]b^{2}-20 \geq 0[/tex]
[tex]b^{2} -(2\sqrt{5}) ^{2}\geq 0[/tex]
[tex](b+2\sqrt{5} )(b-2\sqrt{5} )\geq 0[/tex]
b∈[tex](-\infty,-2\sqrt{5}][/tex]∪[tex][2\sqrt{5},\infty)[/tex]
Hence, any value in the interval (-∞,-2√5] ∪[2√5,∞) will cause the quadratic equation x2+bx+5 = 0 to have two real number solutions.
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A tunnel with a parabolic arch is 12 m wide. If the height of the arch 4 m
from the left edge is 6 m, can a truck that is 5 m tall and 3.5 m wide pass
through the tunnel? Justify your decision.
Check the picture below.
45/8 ÷ 11/9 in simplest form
Answer:
high chance tat it is 405/88. mixed farction = 4 53/88
Step-by-step explanation:
Look at this table:
х
ONN
у
10
20
7
4
12
16
Is this relation a function?
Answer:
I think the answer is No
Step-by-step explanation:
It is not a function because there cannot be two points on the same x value. Hope I remembered this correctly.
HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPpppppp
Answer:
∅
Step-by-step explanation:
y = -x - 2
3x + 3y = 6
3x + 3(-x - 2) = 6
3x - 3x - 6 = 6
0x - 6 = 6
0 = 12
SOLUTION DNE (∅)
I hope this helps!
Hamilton path or Circuit? explain answer
Answer:
Hamilton
Hamilton
Hamilton
Circuit
Circuit
Find the formula for an inverse proportion, knoping that its graph goes through th
point:
(2/3,9/5)
The graph of this equation runs through the point (2/3, 9/5), and it illustrates an inverse proportion, where y is inversely proportional to x.
What is an inverse proportion?An inverse proportion in mathematics is a relationship between two variables where a rise in one variable causes a fall in the other and vice versa. The two variables are thus inversely proportional to one another.
Let x be the independent variable and y be the dependent variable in an inverse proportion. Then the general form of an inverse proportion is:
y = k/x
where k is a constant of proportionality.
To find the specific formula for an inverse proportion that goes through the point (2/3, 9/5), we can substitute these values into the equation and solve for k:
y = k/x
9/5 = k/(2/3)
Multiplying both sides by (2/3), we get:
k = (9/5) * (2/3) = 6/5
Therefore, the specific formula for the inverse proportion is:
y = (6/5) / x
y = 6/(5x)
This equation represents an inverse proportion, where y is inversely proportional to x, and the graph of this equation passes through the point (2/3, 9/5).
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For a class project, Mr. Turner has 350 sheets of paper to offer to his students. The paper comes in a variety of. The table shows the number of sh eets of each color. Which equation would I use? Please help fast! I’ll respond
Answer:
B
Step-by-step explanation:
Is the correct answer
If d = the number of dogs, which variable expression represents the phrase
below?
the sum of the number of clogs and the 6 cats
Answer:
=d+6c
Step-by-step explanation:
I hope this is the right answer
The radius of a circle is 2.6 ft. Find the circumference
to
the
nearest
tenth
to the nearest tenth.
Answer:
16.3 ft
Explanation:
circumference of circle = 2πr ( r is the radius )
Here radius = 2.6 ft
Circumference:
2 * π * 2.65.2 π16.3 ftDigram :
[tex] \setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\qbezier(2.3,0)(2.121,2.121)(0,2.3)\qbezier(-2.3,0)(-2.121,2.121)(0,2.3)\qbezier(-2.3,0)(-2.121,-2.121)(0,-2.3)\qbezier(2.3,0)(2.121,-2.121)(-0,-2.3)\put(0,0){\line(1,0){2.3}}\put(0.5,0.3){\bf\large 2.6ft\ cm}\end{picture}[/tex]
[tex] \\ \\ [/tex]
Given :
radius of circle = 2.6 ft[tex] \\ \\ [/tex]
To find :
Circumference = ?[tex] \\ \\ [/tex]
Solution :-
We know :
[tex] \boxed{ \rm Circumference_{(\sf circle)} = 2\pi \: radius}[/tex]
[tex] \\ [/tex]
So:-
[tex] \dashrightarrow\sf Circumference_{(\sf circle)} = 2\pi \: radius \\ [/tex]
[tex] \\ \\ [/tex]
[tex] \dashrightarrow\sf Circumference_{(\sf circle)} = 2 \times \dfrac{22}{7} \times 2.6\\ [/tex]
[tex] \\ \\ [/tex]
[tex] \dashrightarrow\sf Circumference_{(\sf circle)} = 2 \times \dfrac{22}{7} \times \dfrac{26}{10} \\ [/tex]
[tex] \\ \\ [/tex]
[tex] \dashrightarrow\sf Circumference_{(\sf circle)} =\dfrac{44}{7} \times \dfrac{26}{10} \\ [/tex]
[tex] \\ \\ [/tex]
[tex] \dashrightarrow\sf Circumference_{(\sf circle)} =\dfrac{1144}{7 \times 10} \\ [/tex]
[tex] \\ \\ [/tex]
[tex] \dashrightarrow\sf Circumference_{(\sf circle)} =\dfrac{1144}{70} \\ [/tex]
[tex] \\ \\ [/tex]
[tex] \dashrightarrow\bf Circumference_{(\bf circle)} =16.34~ft\{approx\} \\ [/tex]
1 and 1/2 - 1 and 1/4
Step-by-step explanation:
[tex] = 1 \frac{1}{2} - 1 \frac{1}{4} \\ [/tex]
[tex] = \frac{1 \times 2 + 1}{2} - \frac{1 \times 4 + 1}{4} \\ [/tex]
[tex] = \frac{3}{2} - \frac{5}{4} \\ [/tex]
[tex] = \frac{3}{2} \times \frac{2}{2} - \frac{5}{4} \times \frac{1}{1} \\ [/tex]
[tex] = \frac{6 - 5}{4} \\ [/tex]
[tex] = \frac{1}{4} \\ [/tex]
I don't understand what to do or how to solve it
Answer:
120 degrees
Step-by-step explanation:
the angle at the center is called the central angle and you can tell because J is the center of the circle
The minor arc that is between point H and point K (the shorter way) is the same measure as the central angle
if radius equals 3 and the arc that bounds that sector is 40° what is the sector area and arc length equal?
Answer:
Sector area= 3.143 units²
Arc length = 2.095 units
Answer:
arc length = 3 * 40° * (PI / 180)
arc length = 2.0943951024
sector area = (radius * angle (radians))
sector area = (3 * 0.6981317008)
sector area = 3.1415926536
Source: https://www.1728.org/radians.htm
Step-by-step explanation:
1. A cake recipe requires 4 cups of flour to make 12 cupcakes. Using the same cake recipe, what is the amount of flour needed for 1 cupcake?
Answer:
1/3rd a cup
Step-by-step explanation:
make me brainly
Use the box method to distribute and simplify (5x+2)(3x+3)
Answer:
3(5x^2+7x+2)
Step-by-step explanation:
(5x+2)(3x+3)
I use the foil method, but if you need to use a different method you can look online at how it is done, but this should give you the correct answer.
First
Outside
Inside
Last
First you multiply 5x and 3x together (the first values in each bracket), which gives you 15x squared (15x^2)
Then you multiply the 5x and 3 (the values on the "outside" of the equation --> first and last) which gives you 15x
Then you multiply the "inside" values (the ones in the middle of all the terms), which is 2 and 3x, and gives you 6x
Last you multiply the 2 values that are last in each bracket, 2 and 3, which gives you 6
So then you put then in order of the exponent
15x^2+15x+6x+6
Then you collect like terms (which means terms that have the same number of the variable) and you're left with the answer
15x^2+21x+6
Then most likely you need to further simplify and you can common factor a number out (take the highest number that evenly mutiplies into each term and divide it out of each), so that you have,
3(5x^2+7x+2)
GUYS PLS ANSWER ALL OF THESE I WILL GIVE 70 POINTS IF YOU DO PLS PLS PLS
In EFG the measure of G=90 FG=21 and EF=63 feet find the measure of E to the nearest degree.
Answer:
∠ E ≈ 71°
Step-by-step explanation:
using the cosine ratio in the right triangle
cos E = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{EG}{EF}[/tex] = [tex]\frac{21}{63}[/tex] , then
∠ E = [tex]cos^{-1}[/tex] ( [tex]\frac{21}{63}[/tex] ) ≈ 71° ( to the nearest degree )
need this question now I think it's only a good answer
For ellipses:
-First, let's use completing the square method to determine values of a(semi-major axis), b(semi-minor axis), and the coordinates of the center of the ellipse.
[tex]\mathsf{x^2+4y^2-10x-24y+45=0}[/tex][tex]\mathsf{x^2-10x+4y^2-24y=-45}[/tex][tex]\mathsf{(x^2-10x)+4(y^2-6y)=-45}[/tex][tex]\mathsf{(x^2-10x+25)+4(y^2-6y+9)=-45+25+4(9)}[/tex][tex]\mathsf{(x-5)^2+4(y-3)^2=16}[/tex][tex]\mathsf{\dfrac{(x-5)^2}{16}+\dfrac{(y-3)^2}{4}=1}[/tex][tex]\mathsf{\dfrac{(x-5)^2}{(4)^2}+\dfrac{(y-3)^2}{(2)^2}=1}[/tex]-The center of the ellipse is at C(5, 3), semi-major axis, a = 4, and semi-minor axis, b = 2.
-Since the major axis of the ellipse is horizontal, the distance between the center of the ellipse and the co-vertices of the ellipse is ±b.
[tex]\mathsf{CoV_1=(5,3+b)}[/tex][tex]\mathsf{CoV_2=(5,3-b)}[/tex]-The coordinates of the co-vertices of the ellipse are:
[tex]\mathsf{CoV_1=(5,3+2)} \longrightarrow \mathsf{CoV_1=(5,5)}[/tex][tex]\mathsf{CoV_2=(5,3-2)} \longrightarrow \mathsf{CoV_2=(5,1)}[/tex]For the parabola:
-We have the following data:
The parabola is opening to the left and axis symmetry along the major axis of the ellipse (axis of symmetry: y = 3):
[tex]\mathsf{(y-k)^2=-4a(x-h)}[/tex]The focus of the parabola is the center of the ellipses.
F = (5, 3)-The parabola is passing through the co-vertices of the ellipse:
-The parabola is passing through poînts (5, 5) and (5, 1)
-From the first data, we know that the value of k is equal to 3 because the axis of symmetry of the parabola is y = 3.
[tex]\mathsf{(y-3)^2=-4a(x-h)}[/tex]-From the second data, we know that the x-coordinate of the vertex is at h = 5 + a. (Note: the distance of the focus of the parabola and the vertex of the parabola is equal to ±a, since the parabola is opening the the left we use -a)
[tex]\mathsf{F=(5,3)}[/tex]
[tex]\mathsf{F=(h-a,k)}[/tex][tex]\mathsf{5=h-a}[/tex][tex]\mathsf{h=5+a}[/tex][tex]\mathsf{V=(h,k)}[/tex][tex]\mathsf{V=(5+a,3)}[/tex]-Substitute the coordinates of the vertex of the parabola
[tex]\mathsf{(y-3)^2=-4a[x-(5+a)]}[/tex][tex]\mathsf{(y-3)^2=-4a(x-5-a)}[/tex][tex]\mathsf{(y-3)^2=-4ax+20a+4a^2}[/tex]-From the third data, we know that if the poînts lies on the parabola, the coordinates of the poînts must satisfy the equation of the parabola.
Using the point (5, 5), x = 5, y = 5:
[tex]\mathsf{(y-3)^2=-4ax+20a+4a^2}[/tex][tex]\mathsf{(5-3)^2=-4a(5)+20a+4a^2}[/tex][tex]\mathsf{4=-20a+20a+4a^2}[/tex][tex]\mathsf{4a^2=4}[/tex][tex]\mathsf{a^2=1}[/tex][tex]\mathsf{a=1}[/tex]-Another way to solve for the value of a is using the formula for the length of the latus rectum (LR = 4a). Since the length of the latus rectum is equal to the minor axis of the ellipse, we can easily solve for the value of a.
[tex]\mathsf{LR=4a}[/tex][tex]\mathsf{4=4a}[/tex][tex]\mathsf{a=1}[/tex]-Substitute the value of a in the equation:
[tex]\mathsf{(y-3)^2=-4a[x-(5+a)]}[/tex][tex]\mathsf{(y-3)^2-4(1)[x-(5+1)]}[/tex][tex]\mathsf{(y-3)^2=-4(x-6)}[/tex][tex]{\boxed {\red{{\mathsf{(y-3)^2=-4(x-6)}}}}}[/tex](ノ‥)ノ
If the average value of the function f on the interval 2≤x≤6 is 3, what is the value of ∫62(5f(x)+2)dx ?
The value of the definite integral is 68.
We have,
Break down the integral into two parts:
[tex]\int\limits^6_2 (5f(x) + 2)dx = \int\limits^6_2(5f(x)dx + \int\limits^6_2(2)dx[/tex]
Given that the average value of f(x) on this interval is 3, replace 5f(x) with 5 * 3 = 15:
[tex]\int\limits^6_2 (5f(x)dx = \int\limits^6_2(15)dx[/tex]
= 15(6 - 2)
= 15(4)
= 60
And,
[tex]\int\limits^6_2 2 dx = 2 [6 - 2] = 8[/tex]
Adding both parts of the integral:
= 60 + 8
= 68
Therefore,
The value of the definite integral is 68.
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What’s The Answer Of This? Please Help
Answer:
x = 85°
y = 45°
Step-by-step explanation:
For x, a line measures 180°, so subtract 95° from 180° to get 85°.
For y, all the angles in a triangle measure to 180°, and since we know x, add it to 50° and subtract it from 180°. 85° + 50° = 135°, and 180° - 135° = 45°
Answer:
x = 85
y = 45
Step-by-step explanation:
for x, angles on a straight line add up to 180 so 95 + x = 180 then evaluate for x
for y, angle in a triangle add up to 180 so 50+85 (as evaluated for x) +y= 180 and evaluate for y
Solve for x: 5-(x + 5) >-2(x + 4)
x>-8
x<-8
x>-18
x<-18
FOR EDMENTUM/PLATO pls help and if u got the rest pls share:)
Part D
What is the probability that client D, the 39-year-old you’re considering for a 20-year policy, lives to be 59 years old? Client D is an Asian female, but there is no specific life table for Asian females; look in table 3, which is a general table for females.
12pt
Characters used: 0 / 15000
Part E
What is the probability the client E, the 68-year-old you’re considering for a 10-year policy, lives to be 78 years old? Remember that client E is a non-Hispanic black male.
12pt
Characters used: 0 / 15000
Part F
What is the probability that client F, the 53-year-old you’re considering for a 20-year policy, lives to be 73 years old? Remember that client F is a Hispanic female.
The probability that client D will be able to live to be 59 years old is 0.4.
How to calculate probability?Youe information is incomplete. Therefore, an overview of probability will be given.
Let's assume that there is an entire population of 50 people and the number of those that lives to 59 years is 20.
Therefore, the probability that can be deduced of those that live to 59 years will be:
= 20/50 × 100
= 2/5 × 100.
= 40%
= 0.4
In conclusion, the probability is 0.4.
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2x + 8y = 4
x = -3y + 5
Answer:
(
x
,
y
)
=
(
26
5
,
−
6
5
)
Step-by-step explanation:
9) In spite of offering 20 % discount on a watch priced at Rs. 300, a shopkeeper gains 20 %. What is the cost price of the watch ? (A) Rs. 250 (B) Rs. 200 (C) Rs. 260 (D) Rs. 280
Answer:
B) Rs. 200 is C.P. when shopkeeper gains 20% even though he offers 20% discount on a watch having M.P. Rs 300
Teresa deposits $3,500 in an account that earns
2.25% compounded annually. What is the total
balance at the end 14 years? (Round to the
nearest cent) TEKS A2.5(B)(D)
The total amount accrued, principal plus interest, with compound interest on a principal of $3,500.00 at a rate of 2.25% is $4,779.19.
Compound InterestGiven Data
Principal P= $3,500 Rate r = 2.25%Time t = 14 yearsFinal Amount A = ??A = P + I where
P (principal) = $3,500.00
I (interest) = $1,279.19
Calculation Steps:
First, convert R as a percent to r as a decimal
r = R/100
r = 2.25/100
r = 0.0225 rate per year,
Then solve the equation for A
A = P(1 + r/n)^nt
A = 3,500.00(1 + 0.0225/1)^(1)(14)
A = 3,500.00(1 + 0.0225)^(14)
A = $4,779.19
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(30 points) Find the volume of the cylinder.
Either enter an exact answer in terms of
π
πpi or use
3.14
3.143, point, 14 for
π
πpi.
Answer:
I guess both of the answers are correct.Hope the picture will help you.....
Answer: the answer on khan academy is 144 pie units^3
Every third person on a list of soccer players is selected for a survey, What kind of sampling method is used?
The method which is used for every third person on a list of soccer players selected for a survey is known as systematic sampling.
What is a sample method?The sampling method is the method of selecting the subset from the set to make a statical inference.
Because of its simplicity, systematic sampling, also known as the nth name selection approach, is frequently employed instead of random sampling. Following the collection of the sample, every nth person of the population is registered in the sample.
Thus, the systematic sampling method is used.
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What is the equation of the line that is perpendicular to the given line and has an x-intercept of 6? y = –three-fourthsx 8 y = –three-fourthsx 6 y = four-thirdsx – 8 y = four-thirdsx – 6
Answer:
y = –three-fourthsx
Step-by-step explanation: