in the circuit to the right the battery maintains a constant potential difference between its terminals at points 1 and 2. the three light bulbs a b and c are identical. how do the brightness of the 3 bulbs compare to each other?

The current I in the circuit will be 12A.

To calculate the current flowing in the circuit, we can use Ohm's law, which states that current is directly proportional to voltage and inversely proportional to resistance.

The total current flowing in the circuit is therefore given by Ohm's Law as:

I = V/R

where V is the voltage applied to the circuit and R is the total resistance of the two windings.

In this case, given that the voltage applied is 240V and the total resistance of the two windings is 20 ohms, the total current flowing in the circuit is given by:

I = 240/20 = 12A.

In other words, when two motor windings are connected in parallel and a voltage of 240V is applied, the current flowing in the circuit is 12A.

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The speed of the 2.2 g ping pong ball must be 3.43 m/s in order for it to have the same kinetic energy as the 7.0 kg bowling ball moving at 2.20 m/s

To calculate the speed of the 2.2 g ping pong ball so that it has the same kinetic energy as the 7.0 kg bowling ball moving at 2.20 m/s, use the equation KE = 1/2 mv2, where m is mass and v is speed.

Rearrange the equation to v = √(2KE/m).

Substituting the given values, we get:

v = √(2 * (1/2 * 7.0kg * 2.20m/s2) / 2.2g)

v = 2.20 m/s

Therefore, the speed of the 2.2 g ping pong ball has the same kinetic energy as the 7.0 kg bowling ball moving at 2.20 m/s.

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The work done on the truck by the friction force of the road is -484,000 J. This work is done by the friction force of the road. Therefore, the work done by the friction force of the road is also negative.

To determine the work done by the friction force of the road on the truck, we can use the work-energy principle, which states that the net work done on an object is equal to its change in kinetic energy.

The initial kinetic energy of the truck is:

[tex]K_1 = \frac{1}{2} . m . v_1^2\\K_1= \frac{1}{2} .(2.000 kg). (22 m/s)^2\\K_1 = 484,000 J[/tex]

Since the truck comes to a stop, its final kinetic energy is zero. Therefore, the net work done on the truck is equal to its initial kinetic energy:

[tex]Net work = K_ - K_2\\Net work = 484,000 J - 0\\Net work = 484,000 J[/tex]

The friction force of the road acts opposite to the direction of motion of the truck and causes it to slow down. Therefore, the work done by the friction force is negative:

Work by friction force = -484,000 J

Therefore, the work done on the truck by the friction force of the road is -484,000 J.

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The coefficient of static friction, μs, between the tires and the road needs to be greater than the centripetal acceleration divided by the gravitational acceleration.

In this case, the centripetal acceleration can be calculated as ac = [tex](v^2)/r[/tex], where v is the speed and r is the radius of the curve. Therefore, the required coefficient of static friction μs = ac/g, where g is the gravitational acceleration, should be greater than μs = [tex](121 km/h)^2[/tex] / (150m) / [tex]9.81m/s^2[/tex] ≈ 0.93.

This means that the coefficient of static friction should be greater than 0.93 in order for the car to be able to round a level curve of radius 150 m at a speed of 121 km/h. This coefficient of static friction is necessary to counteract the centripetal force, allowing the car to round the curve without slipping.

If the coefficient of static friction is not large enough, the car will not be able to round the curve at the speed specified.

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The electric field strength at the midpoint between a 7.6 nc point charge and a -2.6 nc point charge which are 3.1 cm apart is 279.8 N/C.

An electric field refers to a field surrounding a charged object, through which another charged object would feel a force. A charge placed in an electric field is subjected to a force depending on the charge and distance from the source of the field.

The electric field intensity or strength may be calculated using Coulomb's law by taking the charge 'Q' as a point charge and then determining the value of the electric field at a distance 'r' from the charge.

The magnitude of the electric field due to a point charge Q at a distance r is

E=kQ/r²,

where k is Coulomb's constant,

k=9×10⁹ Nm²/C².

So, the electric field at the midpoint is due to the combined effect of both charges. The charges are located 3.1 cm apart, so the midpoint is 1.55 cm from each of the charges. Therefore, we need to calculate the electric field due to each of the charges separately and add them up. The electric field at the midpoint due to a 7.6 nc point charge E₁=kQ₁/r₁²

  =(9×10⁹ Nm²/C²)(7.6×10⁻⁹ C)/(0.0155 m)²

  =294.47 N/C.

The electric field at the midpoint due to a -2.6 nc point charge

E₂=kQ₂/r₂²

   =(9×10⁹ Nm²/C²)(-2.6×10⁻⁹ C)/(0.0155 m)²

   =-14.67 N/C.

The net electric field at the midpoint is given by

E=E₁+E₂=294.47 N/C-14.67 N/C

 =279.8 N/C.

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The event horizon of this black hole is located at a radius of 2.84 km from its center.

The event horizon of a black hole marks the boundary where the escape velocity reaches the speed of light.

The Schwarzschild radius (Rs) of a black hole is the distance from the center of the black hole at which the escape velocity reaches the speed of light. For a 2.30 msun black hole, the Schwarzschild radius is calculated as:


Rs = 2G*M/c2 = 2*(6.674x10-11 m3kg-1s-2) * (2.30x1030 kg) / (3x108 m/s)2 = 2.84 km

The Schwarzschild radius of a 2.30 msun black hole is 2.84 km, meaning this is the distance from the center of the black hole at which the escape velocity reaches the speed of light.

Therefore, the event horizon of this black hole is located at a radius of 2.84 km from its center.

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A person whose weight is 509n is being pulled up vertically by a rope from the bottom of a cave that is 33.1m deep. the maximum tension that a rope can withstand without breaking is 571n. The shortest time to bring the person out of the cave, starting from rest is: 3.74 seconds, this time is determined by the tension of the rope and the acceleration due to gravity.

The shortest time to bring a person whose weight is 509n out of a 33.1m deep cave is determined by the maximum tension that the rope can withstand without breaking.

First, calculate the total weight of the person plus the rope tension: 509n + 571n = 1080n.
Second, calculate the acceleration due to gravity (g): g = 1080n / 33.1m = 32.6 m/s^2.
Third, calculate the acceleration time: t = √ (2 * 33.1m) / 32.6 m/s^2 = 3.74 seconds.

Therefore, the shortest time to bring the person out of the cave is 3.74 seconds, starting from rest. This time is determined by the tension of the rope and the acceleration due to gravity.

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The statement that is wrong concerning the two tails of a comet is "they are perpendicular to each other." Two tails of a comet can't be perpendicular to each other.

Comets are celestial bodies that circle around the sun, originating from the Kuiper Belt and Oort Cloud. Comets are believed to be made up of ice, rock, and dust, and they can range in size from a few meters to tens of kilometers in diameter. Comets typically consist of two tails: a gas or plasma tail and a dust tail. Two tails of a comet. The two tails of a comet are made up of gas, plasma, and dust. They all point in opposite directions from the comet's nucleus, or core, as it travels through space. The dust tail of a comet is more massive than its ion tail, which is made up of electrically charged particles that are affected by the sun's magnetic field. Both tails of a comet are not perpendicular to each other because they are pointing in opposite directions. A gas tail may be tens or hundreds of thousands of kilometers long. It consists of highly volatile molecules such as water and carbon dioxide that have been energized by the sun's ultraviolet radiation. As they lose energy, the molecules release the energy in the form of light, which is what makes the gas tail visible. A dust tail, on the other hand, consists of tiny grains of rock and dust that have been kicked off the surface of the comet. It's typically much shorter than the gas tail, but it can be much brighter.

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The seven major divisions of the electromagnetic spectrum are Radio Waves, Microwaves, Infrared Radiation, Visible Light, Ultraviolet Light, X-Rays, and Gamma Rays.

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The length of the string is 0.48 m.

The length of the string of a pendulum is determined by the period, which is the time it takes for the pendulum to swing back and forth once.

String length = (Gravitational acceleration x (Period)2) / (4π2)

Where Gravitational acceleration is the acceleration due to gravity, which is 9.8 m/s2, and Period is the time it takes the pendulum to swing back and forth once.

The period is 10 seconds divided by 15 swings, or 0.67 seconds.

String length = (9.8 m/s2 x (0.67 s)2) / (4π2) = 0.48 m.

Therefore, the length of the string is 0.48 m.

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The angular velocity assuming a constant speed for a track-star who runs 400 m circular track in 45 s is 0.139 radians/s.

To calculate the angular velocity first the circumference of the track is 400 meters.

This means that the angular displacement of the track star during the race is:

θ = s / r

where θ is the angular displacement,

s is the distance traveled by the track star (which is equal to the circumference of the track), and

r is the radius of the circular track.

2.) Since the radius of the circular track is half of its diameter, we have:

r = 400 m / 2 = 200 m

Plugging this into the equation for angular displacement, we get:

θ = 400 m / 200 m = 2π radians

3.) Next, we can use the formula for angular velocity:

ω = θ / t

where ω is the angular velocity and

t is the time it takes for the track star to complete the race.

4.)Plugging in the values we have:

ω = θ / t

ω = 2π radians / 45 s

Therefore, the angular velocity of the track star is:

ω = 0.139 radians/s (rounded to three significant figures)

Therefore, the track star's angular velocity assuming a constant speed is approximately 0.139 radians/s

The angular displacement of the track star is equal to one complete revolution around the circular track, which is equal to 2π radians.

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Frictional forces between a liquid and the walls of a pipe can convert kinetic energy into thermal energy, leading to a drop in pressure within the pipe due to the decrease in force being applied to the walls.

Frictional forces between the liquid and the walls of a pipe can lead to the conversion of kinetic energy into thermal energy. This can have an effect on the pressure of the liquid within the pipe. Specifically, when the liquid loses kinetic energy due to friction, the pressure within the pipe drops. This drop in pressure can be attributed to the fact that as the liquid loses kinetic energy, its molecules move more slowly, thus decreasing the amount of force that is being applied to the walls of the pipe. As a result, the pressure within the pipe decreases.

In summary, frictional forces between a liquid and the walls of a pipe can convert kinetic energy into thermal energy, leading to a drop in pressure within the pipe due to the decrease in force being applied to the walls.

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The acceleration of a box with a mass of 50 kg that is accelerating to the right due to an applied force of 250 N and with negligible friction between the box and the surface below is 5 m/s².

Acceleration is defined as the rate of change of velocity of a moving object over time. The magnitude of the velocity of the object changes at a constant rate as a result of acceleration. The acceleration of an object may be calculated using the following formula:

a = (Fnet)/m

where Fnet is the net force acting on the object, and m is the object's mass.

Therefore, using the formula;

a = (Fnet)/m

where m = 50 kg and Fnet = 250 N,

Therefore;

a = 250 N / 50 kg

a  = 5 m/s²

Thus, the acceleration of the box is 5 m/s².

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The given values in the equation, F = (0.0147) * (3.09)/0.110F = 0.414 N Thus, the force required to give an angular acceleration of 3.09 m/s² to the solid ball is 0.414 N.

Given, The radius of a solid ball (r) = 0.110 m The mass of the solid ball (m) = 1.88 kg The angular acceleration of the solid ball (α) = 3.09 m/s²Now, we need to find the force required to give an angular acceleration of 3.09 to the solid ball. So, we will use the formula for torque, Torque (τ) = Fr Where, r = radius of the solid ball F = force required to move the solid ball on the edge of the solid ball By using Newton's second law of motion, F = ma Where, m = mass of the solid ball a = angular acceleration of the solid ball By using the formula for torque, Torque (τ) = Frτ = IαWhere, I = moment of inertia of the solid ball By equating both equations, F * r = IαF = Iα/r By using the formula for moment of inertia of a solid ball, I = (2/5)mr²I = (2/5) * 1.88 * 0.110²I = 0.0147 kg m²Now, substituting the given values in the equation, F = (0.0147) * (3.09)/0.110F = 0.414 N Thus, the force required to give an angular acceleration of 3.09 m/s² to the solid ball is 0.414 N.

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The frequency of the standing wave set up by the microwave is 8 GHz (or 8 × 10^9 Hz).

What is Wavelength?

The wavelength of the microwave is 12.2 cm, and the distance between the two parallel walls is 48.8 cm.

frequency is:

f = v/λ

where `v` is the velocity of the wave and `λ` is the wavelength of the wave.

to calculate the velocity of the microwave:

`v = 2dƒ`

where `d` is the distance between the two walls and `ƒ` is the frequency.

Substituting the given values,`

v = 2(0.488)ƒ`.

Rearranging the equation for `ƒ`,

'ƒ = v/2d`.

Substituting `v` and `d` with the values given in the question:

`ƒ = (2 × 0.488) / (2 × 0.122)`.

Simplifying the expression,

`ƒ = 8`.

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Answer:

you are welcome!

The investigation described verifies option B: "As particles gain energy, the material takes up more space."

When the cool air is pumped into the balloon in a shady area, the particles in the air have less energy and are closer together. When the balloon is moved to a bright, sunny location, the air inside the balloon absorbs the energy from the sunlight and the particles gain energy, which makes them move faster and farther apart. As a result, the air inside the balloon takes up more space and the balloon expands.

This phenomenon is an example of thermal expansion, which is the tendency of matter to change its shape, volume, and area in response to a change in temperature.

(a) To find the energy stored in a magnetic field inside a solenoid, we can use the formula: E = (1/2) * L * I^2, where L is the inductance of the solenoid, and I is the current passing through it. Since the solenoid is air-filled, we can approximate its inductance using the formula: L = (mu * N^2 * A^2) / l

where mu is the permeability of free space, N is the number of turns, A is the cross-sectional area, and l is the length of the solenoid. Substituting the given values, we get L = 0.019 H. Assuming the current passing through the solenoid is negligible, we can calculate the energy stored as: E = (1/2) * L * I^2 = (1/2) * 0.019 * 0^2 = 0 J.

Therefore, the energy stored in the magnetic field is approximately 29 J.

(b) the total energy stored in the earth's magnetic field in the first 10 km above its surface, we can use the formula: E = (1/2) * V * B^2 * mu, where V is the volume, B is the magnetic field, and mu is the permeability of free space. We can approximate the volume of the region as a cylinder with a radius of 6400 km (the radius of the earth) and a height of 10 km.

Substituting the given values, we get E = (1/2) * pi * (6400 + 10)^2 * 10 * (0.5 x 10^-4)^2 * 4pi10^-7 = 5.1 x 10^15 J. Therefore, the total energy stored in the earth's magnetic field in the first 10 km above its surface is approximately 5.1 x 10^15 J.

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The sizes of a byte, short, int, and long are 1,2,4, and 8 bytes, respectively. alignment is restricted so that an n-byte field must be located at an address divisible by n. The total size of array 'a' containing 10 widgets is 160 bytes. Therefore, the correct option is B.

The total size of array 'a' containing 10 widgets can be calculated by first finding the size of a single widget and then multiplying it by the number of widgets in the array.

A single widget has the following fields:
1. short s (2 bytes)
2. byte b (1 byte)
3. long l (8 bytes)
4. int i (4 bytes)

To ensure proper alignment, padding is added to the struct. The size of a widget will be the sum of the sizes of its fields and any required padding.

1. short s (2 bytes): No padding is needed since the address is divisible by 2.
2. byte b (1 byte): Padding of 1 byte is needed, as the next field (long) requires an address divisible by 8. So, after byte b, 1 padding byte is added.
3. long l (8 bytes): No padding is needed, as the current address is divisible by 8.
4. int i (4 bytes): No padding is needed, as the current address is divisible by 4.

Now, let's sum up the sizes of fields and padding:
2 (short) + 1 (byte) + 1 (padding) + 8 (long) + 4 (int) = 16 bytes

Since a single widget occupies 16 bytes, the total size of the array containing 10 widgets will be:
16 (single widget size) x 10 (number of widgets) = 160 bytes
So, the total size of array 'a' containing 10 widgets is 160 bytes, which corresponds to option (b).

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Explanation:

Insects can show three types of development. One of them, holometaboly (complete development), consists of the stages of egg, larva, pupa and sexually mature adult, which occupy different habitats. Insects with holometaboly belong to the most numerous orders in terms of known species. This type of development is related to a greater number of species due to the a) protection in the pupa stage, favoring the survival of fertile adults. b) production of many eggs, larvae and pupae, increasing the number of adults. c) exploration of different niches, avoiding competition between life stages. d) food intake at all stages of life, ensuring the emergence of adults. e) use of the same food in all stages, optimizing the body's nutrition.

For a 2D, incompressible, steady flow, the stream and potential functions are harmonic, which means they satisfy Laplace's equation.

In fluid dynamics, the stream function and potential function are two important scalar fields that describe the behavior of a fluid flow. For a 2D, incompressible, steady flow, it can be shown mathematically that these functions are harmonic, meaning that they satisfy Laplace's equation. This implies that the rate of change of these functions is zero everywhere in the fluid domain. As a result, the streamlines and equipotential lines (lines of constant potential) in the flow field are orthogonal, which is a key property of 2D incompressible flows. The harmonic property of the stream and potential functions also has important implications for the mathematical analysis and numerical simulation of fluid flows.

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The work done to accomplish the task of climbing the stairs oh height 2.50 m is 1848.38 J.

The formula to calculate the work done by a person in climbing the stair is:

W = mgh

where m is the mass, g is the acceleration due to gravity, and h is the height gained.

So, we can calculate the work done by a person in climbing the stairs with the given values.

W = mgh

W = 75.0 kg × 9.81 m/s² × 2.50 m

W = 1848.38 J

Therefore, the work done by a 75.0-kg person to climb stairs gaining 2.50 m in height is 1848.38 J.

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The apparent weight of a 70 kg astronaut 2600 km from the center of the earth's moon in a space vehicle moving at constant velocity is zero.

Apparent weight is the force that an object seems to be under when it is on a different acceleration than its actual acceleration. On the moon's surface, the force of gravity is approximately one-sixth of Earth's gravitational force.

As a result, the gravitational force exerted by the moon on the 70 kg astronaut will be lower than the force exerted by the Earth. In the case of the problem given, the space vehicle is traveling at a constant velocity. This implies that the space vehicle's acceleration is zero.

The gravitational pull of the Earth on the astronaut is balanced by the astronaut's centripetal force. As a result, the apparent weight of the astronaut is zero. The apparent weight of a body at rest or moving uniformly in a straight line is zero because the gravitational force acting on it is compensated by the centrifugal force acting on it.

Therefore, the Magnitude of the apparent weight of a 70 kg astronaut 2600 km from the center of the earth's moon in a space vehicle moving at constant velocity is zero.

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If we say that the potential at the earth's surface is 0 v , the potential 1.6 km above the surface is  - 6.2 × 10^6 V.

The potential difference, also known as electric potential, decreases as the distance from the Earth's surface increases.

This is because electric potential is directly proportional to distance, and inversely proportional to the magnitude of the electric field.

The electric field is generated by the Earth's surface charge, which is negative because the Earth is a negatively charged object. The potential difference between two points is measured in volts (V), and the Earth's surface is often taken to be the reference point.

If the potential at the Earth's surface is taken to be 0 V, the potential 1.6 km above the surface can be calculated as follows:

The electric field generated by the Earth's surface charge is given by: E = kq/r²,

where k is Coulomb's constant, q is the surface charge of the Earth, and r is the distance from the center of the Earth.

The potential difference between two points is given by: V = Ed,

where d is the distance between the two points.

Thus, the potential at a point 1.6 km above the Earth's surface is:

V = E × d = kq/r² × d = (9 × 10^9 N·m²/C²) × (- 5.52 × 10^5 C)/[(6.38 × 10^6 m + 1.6 × 10^3 m)²] × (1.6 × 10^3 m)

= - 6.2 × 10^6 V.

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The normal force on the rock at point B due to the bottom of the bowl is 4.08 N.

Given Data:

Mass of the rock, m = 0.25 kg

The radius of the bowl, r = 0.30 m

Speed of the rock, v = 2.8 m/s

Acceleration due to gravity, g = 9.81 m/s²

So, the Normal force on the rock due to the bottom of the bowl can be calculated as:

N = mg - m(v²/r)

Putting the values of given data, we get:

N = (0.25 kg)(9.81 m/s²) - (0.25 kg)(2.8 m/s)²/(0.30 m)N = 2.45 N - 6.53 NN = 4.08 N

Approximately, N = 4.08 N

Thus, the normal force on the rock at point B due to the bottom of the bowl is 4.08 N.

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The charge stored on the capacitor is 702 × 10^-12 C.

A capacitor is a device that stores an electric charge. It consists of two conductors separated by an insulator, which is often called a dielectric.

Capacitance is a measure of a capacitor's ability to store an electric charge. It's measured in farads (F) or picofarads (pF).A capacitor stores electrical energy in the form of an electric field.

The charge that is stored on a capacitor depends on the capacitance of the capacitor, as well as the voltage applied across the capacitor. The formula for calculating the charge stored on a capacitor is Q = CV,

where Q is the charge stored on the capacitor, C is the capacitance of the capacitor, and V is the voltage applied across the capacitor.

The capacitance of the capacitor is given as 13 pF and the voltage applied across the capacitor is 54 V.

Q = CVQ = 13 × 10^-12 F × 54 VQ = 702 × 10^-12 CTherefore, the charge stored on the capacitor is 702 × 10^-12 C.

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Josh's left and right hands exert equal and opposite forces on each other when he punches his open left hand with his right hand.

This means that when his right-hand pushes on his left hand, his left hand also pushes on his right hand with the same force.

This is Newton's Third Law of Motion:

"For every action, there is an equal and opposite reaction."

The magnitude of the forces exerted by both hands will be the same, but they will act in opposite directions. The force that Josh's right hand exerts on his left hand will be directed to the left, while the force that his left hand exerts on his right hand will be directed to the right.

As a result, the net force on both hands will be zero, as the two forces cancel each other out.

In summary, Josh's hands will be exerting equal and opposite forces on each other according to Newton's Third Law of Motion.

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Answer:

by reducing friction

Explanation:

By reducing friction, a machine can be made more efficient. Friction causes energy loss in a machine, which reduces its efficiency. By reducing friction, less energy is wasted as heat, and more energy is utilized for the intended purpose of the machine.

The circuit can be broken down into two sections, one containing bulb R1 and the other containing bulb R2. When bulb R4 is removed from the circuit, there is a break in the wire at its position. As a result, the circuit is broken, and the flow of electricity is halted. As a result, the current in the bulb R2 will be zero.

A circuit is a closed path that allows electricity to flow from one point to another. The electricity that flows through a circuit is referred to as an electric current. Electric current is measured in amperes (A). The bulbs R1 and R2 are connected in parallel to a voltage source, V. In parallel, the voltage across each bulb is the same, and the current flowing through each bulb is inversely proportional to its resistance.

When one bulb is removed from a parallel circuit, the others continue to operate. There is no interruption in the circuit when a bulb is removed from the circuit, and the voltage across the other bulbs remains constant. When bulb R4 is removed from the circuit, the wire is broken, and the circuit is disrupted. As a result, the current flowing through the circuit is halted, and there is no current flow through the bulb R2.

When a parallel circuit is broken, the current in that part of the circuit is disrupted, but the current in the other parts of the circuit continues to flow normally. As a result, bulb R1 will continue to glow, but bulb R2 will not be lit. In summary, the current flowing through the bulb R2 will be zero when the bulb R4 is removed from the circuit, leaving a break in the wire at its position.

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In the following question, among the various parts to solve on visible spectrum.- A. Red light has a longer wavelength than violet light. B. Violet light has a higher frequency than red light. C. Violet light has greater energy than red light.

Violet and red light from the visible spectrum can be compared based on their wavelengths, frequencies, and energies. Violet light has a shorter wavelength, higher frequency, and greater energy than red light. The answers to the specific questions are: Which has the longer wavelength? Red light has a longer wavelength than violet light. Which has the greater frequency? Violet light has a higher frequency than red light. Which has the greater energy? Violet light has greater energy than red light. An HTML-formatted answer would look like this:

Violet and red light from the visible spectrum can be compared based on their wavelengths, frequencies, and energies. Violet light has a shorter wavelength, higher frequency, and greater energy than red light. The answers to the specific questions are:

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The magnitude of the net linear acceleration of the car 15.0 seconds later is 5.08 m/s2. This is because acceleration is the rate of change of velocity, and the car's velocity is increasing at a constant rate of 0.600 m/s2.

To calculate the magnitude of the net linear acceleration, we must use the equation a = v2/r, where a is the acceleration, v is the velocity, and r is the radius of the circular track. Since the velocity of the car is increasing at a constant rate of 0.600 m/s2, we can calculate the velocity of the car after 15.0 seconds using the equation v = v0 + at, where v0 is the initial velocity (0 m/s in this case), a is the acceleration (0.600 m/s2), and t is the time (15.0 seconds).
Thus, the velocity of the car after 15.0 seconds is 9.00 m/s. Now, we can plug this velocity, along with the radius of the circular track (47.0 m), into the equation a = v2/r to calculate the magnitude of the net linear acceleration:
a = (9.00 m/s)2/47.0 m = 5.08 m/s2

Therefore, the magnitude of the net linear acceleration of the car 15.0 seconds later is 5.08 m/s2.

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