If 0.40 mole of H2 and 0.15 mole of O2 were to react as completely as possible to produce H2O, what mass of reactant would remain

Answer:

Water is a compound because it is made up of water molecules. There is no such thing as water atoms. Water molecules are made of hydrogen and oxygen atoms, in the definite proportion of two hydrogens for one oxygen.

Explanation:

The difference between a molecule and a compound is this:

A molecule consists of two or more atoms joined by a chemical bond.

A compound consists of two or more different atoms joined by chemical bonds.

Water (H2O) is both a molecule and a compound.

Hydrogen gas (H2) and oxygen gas (O2) are molecules but because the atoms of which they are made are not different, they do not qualify as compounds.

Both concentration and conductivity increase when larger amounts of sugar in a beaker of water dissolves.

The volume of the resulting solution will be larger than one quart if you dissolve a cup of sugar in a quart of water. In comparison to distilled water, the concentration of solutes inside the cell is higher. Most of the time, a particular amount of solvent can only dissolve a specific maximum amount of solute. This maximum amount is specified as the solubility of the solute. Only solutions with charge carriers will be able to conduct electricity. Simply having polar molecules in the solution is insufficient. It must be able to transfer electrons between points with the least amount of interference.

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Answer:

Reducing agent - S

Explanation:

The equation for the reaction is given as;

K2Cr2O3 + H2O + S --> SO2 + KOH + Cr2O3

The balanced equation is given as:

2K2Cr2O7 + 2H2O + 3S → 3SO2 + 4KOH + 2Cr2O3        

The reducing agent can be obtained by comparing the oxidation number of the elements. Increase in oxidation number signifies a reducing agent

K:

Reactant - 1

Product - 1

Cr

Reactant - +2

Product - +3

O

Reactant -   -2

Product -    -2

H

Reactant - +1

Product - +1

S

Reactant - O

Product - +4

S has an increase in oxidation number hence it is the reducing agent.

Although Cr has an increase in oxidation number, it occurs as a compound.

The answer to the given operations with proper number of significant figures is 5.7 × 10².

Significant figures or numbers can be defined as those particular numbers or digits which are essential in determining the accuracy of a particular value. For example, 4.392 has 4 significant figures.

When we are rounding off a number to write it with the proper number of significant figures, we first need to decide the amount of significant figures that it should have.

On calculating the given operation,

⇒ 108 × 5.3 = 572.4

In significant figures,

= 5.72 × 10²

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Answer:

3. The limiting reactant is the reactant that gives you the smaller amount of product. Therefore HCI is the limiting reactant in this problem. In this reaction 9.4 grams of ZnCl2 will form and there will be leftover zinc that did not react.

Answer:

1935J

Explanation:

Answer:

[tex]\boxed {\boxed {\sf C. \ 1935 \ J}}[/tex]

Explanation:

The equation for this problem is:

[tex]q=mc\Delta T[/tex]

where m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.

The mass is 3 kilograms, but the specific heat capacity includes grams in the units. Convert kilograms to grams. There are 1000 grams in 1 kilogram.

The specific heat capacity for lead is found on the table. It is 0.129 J/g°C.

Let's find the change in temperature. It is raised from 15 °C to 20 °C.

Now we know every value.

Substitute the values into the formula.

[tex]q= (3000 \ g)( 0.129 \ J/g \textdegree C)(5 \textdegree C)[/tex]

Multiply the first 2 numbers together. The units of grams cancel.

[tex]q= (387 \ J/ \textdegree C )(5 \textdegree C)[/tex]

Multiply again. This time the units of degrees Celsius cancel.

[tex]q= 1935 \ J[/tex]

1935 Joules of energy are required and choice C is correct.

Hydroelectric energy is a renewable form of energy used to generate electricity.

This energy is created by harnessing the power of moving water, typically from rivers and streams, to spin turbines and generate electricity.

Hydroelectric power plants are used to generate electricity for homes, businesses, and cities all over the world.

By utilizing the natural power of water, hydroelectric energy is a clean, safe, and reliable source of energy that helps reduce global carbon emissions. It is also a cost-effective energy source, making it a popular choice for many energy providers.

Hydroelectric energy is one of the most widely used sources of electricity in the world, with many countries heavily relying on it for their energy needs.

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Answer:

b. 23.3g

Explanation:

Based on the reaction:

CH₄ + 2O₂ → CO₂ + 2H₂O

To find the mass of CO2 produced we must find, as first, the limiting reactant. With limiting reactant we can find the moles and the mass of CO2 as follows:

Limiting reactant:

For a complete reaction of 0.53 moles of CH4 are necessaries:

0.53 moles CH4 * (2mol O2 / 1mol CH4) = 1.06 moles O2.

As there are 1.5 moles, CH4 is limiting reactant.

Moles CO2:

1 mole of CH4 produce 1 mole of CO2. That means the moles of CO2 formed are 0.53 moles.

Mass CO2 (Molar mass: 44.01g/mol)

0.53 moles CO2 * (44.01g / mol) =

b. 23.3g

Answer:

I believe the answer would be C4H9O2.

Answer: D!! ( difference in the potential energy of the reactants and products )

Explanation:

i have the same test

The correct answer is 7.0 moles of AgNO3 will form 7.0 moles of Zn(NO3)2,

Mole ratio is the ratio between the number of moles of two substances that are involved in a chemical reaction. It is an important concept in stoichiometry, which is the study of the relationship between the amounts of reactants and products in a chemical reaction. Mole ratio is often expressed as a fraction, in which the numerator is the number of moles of one substance, and the denominator is the number of moles of the other substance.

Since the reaction is a 1:1 mole ratio of reactant to product:

AgNO3 → Zn(NO3)2

7.0 mol AgNO3 → 7.0 mol Zn(NO3)2

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4-methyl-2-pentene s the expected major organic product from treatment of 4-methyl-2-pentyne with sodium metal in liquid ammonia.

The process includes hydrogenation of an alkyne to an alkene in liquid ammonia using sodium metal. This is a particular reaction that leads in the creation of trans alkene.  Alkynes are hydrocarbons with triple carbon-carbon bonds. For molecules with a single triple bond, their typical formula is CnH2n-2 (and no rings).

A number of the same reactions occur in alkynes as in alkenes, but they can react twice due to the existence of two p-bonds inside the triple bond. When sodium dissolves into liquid ammonia (boiling point -33 °C), it turns a vivid blue. When there are alkynes present, they have reduced to a trans (i.e. E) alkene.

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The equilibrium concentration of a sulfate ion is 32× 10⁻⁶M can be added in a 1. 0 Dash L solution of strontium sulfate which is 0. 10 mol of Sr(CH3CO₂)₂.

Solubility is defined as the maximum amount of a solute that can be dissolved in a known quantity of the solvent at a certain temperature is its solubility.

The solubility of SrSO₄ is:

SrSO₄(s) → Sr²⁺(aq) + SO₄²⁻(aq)

Where Ksp is defined as:

Ksp = 3.2x10⁻⁷ = [Sr²⁺] [SO₄²⁻]

The concentration of Sr is:

0.10mol / 1L = 0.10M = [Sr²⁺]

Replacing in Ksp:

3.2x10⁻⁷ = [0.10M] [SO₄²⁻]

[SO₄²⁻] = 3.2x10⁻⁶M

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Answer:

[tex]\boxed {\boxed {\sf 20.51 \ g \ NH_3}}[/tex]

Explanation:

If we want to convert from moles to grams, we must use the molar mass. This values tells us the mass of 1 mole of a substance. They can be found on the Periodic Table; they are equivalent to the atomic masses, but the units are grams per mole (g/mol) instead of atomic mass units (amu).

We have the compound ammonia or NH₃. Look up the molar masses for the individual elements.

Check for subscripts. There is a subscript of 3 after hydrogen. This means there are 3 atoms of hydrogen in 1 molecule of ammonia. We should multiply hydrogen's molar mass by 3.

Add nitrogen's molar mass.

Now, use the molar mass as a ratio.

[tex]\frac {17.031 \ g \ NH_3}{1 \ mol \ NH_3}[/tex]

Since we are trying to find the mass of 1.204 moles, we multiply by that value.

[tex]1.204 \ mol \ NH_3 *\frac {17.031 \ g \ NH_3}{1 \ mol \ NH_3}[/tex]

The units of "moles of ammonia" cancel.

[tex]1.204 *\frac {17.031 \ g \ NH_3}{1}[/tex]

The denominator of 1 can be ignored.

[tex]1.204 * 17.031 \ g \ NH_3[/tex]

[tex]20.505324 \ g \ NH_3[/tex]

The original measurement of moles has 4 significant figures, so our answer must have the same. For the number we calculated, that is the hundredth place.

The 5 in the thousandth place tells us to round to 0 to a 1 in the hundredth place.

[tex]20.51 \ g \ NH_3[/tex]

1.204 moles of ammonia is equal to 20.51 grams of ammonia.

Answer:

uhhhhh not sure i cant see it

Explanation:

Irony is a mismatch between what is expected and what actually occurs. These literary methods aid in the creation of dramatic effects in writing.

Irony is a disconnect between what is expected to happen and what actually happens. These types of literary devices help in creating a dramatic effect in literature.

Irony is a literary device which was used extensively in Greek tragedy. It involves expressing the meaning of something by making use of words which technically mean the opposite of the original thing being conveyed.

Irony is used for a dramatic or humorous effect.  There are three types of irony seen in literature as follows:

• Verbal Irony  

• Situational Irony  

• Dramatic Irony  

Verbal irony involves the usage of different words to mean something dissimilar to what they look like they actually mean.  

Situational Irony means that what happens is totally different from what was expected to be happening.

Dramatic Irony occurs in plays, etc. where the audience or the readers are more aware of what is actually going on as compared to the character in the scene.

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According to the question,16.2 kPa is equal to 0.16 atmospheres.

What is the atmospheres?

The atmosphere is the thin layer of gases and particles that surrounds Earth, protecting us from the sun’s harmful radiation and maintaining the planet’s temperature. It is composed of 78% nitrogen, 21% oxygen, 0.9% argon, 0.03% carbon dioxide, and trace amounts of other gases, as well as water vapour, dust, and other particles. The atmosphere works by trapping heat from the sun, allowing temperatures to remain relatively stable throughout the world. It also helps regulate the water cycle, ensuring that water remains available for life on Earth. The atmosphere also helps protect us from environmental hazards like ozone depletion and acid rain. In addition, it is home to many species of birds, insects, and other animals. Without the atmosphere, Earth would be a barren, lifeless planet.

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Taking into account the definition of molarity,  the molarity of a solution made up of 15.5 mol of ammonium sulfate dissolved in enough water to make 45 liters of solution is 0.34 moles/L.

The molar concentration is a measure of the concentration of a solute in a solution, be it some molecular, ionic or atomic species and indicates the number of moles of solute contained in one liter of solution.

The molarity of a solution is calculated by:

molarity= number of moles÷ volume

Molarity is expressed in units moles/L.

In this case, you have:

Replacing in the definition of molarity:

molarity= 15.5 moles÷ 45 L

Solving:

molarity= 0.34 moles/L

Finally, the molarity of the solution is 0.34 moles/L.

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Answer:

They are similar, because one can be obtained by dilating the other about the origin with a scale factor of 1/2.

Explanation:

The image is dilated by 1/2.

Take a look.

The coordinate labels of the preimage include: A, B, C, and D.

The coordinate labels of the image include: A', B', C', and D'.

Coordinates of point A: (2, 8)

Coordinates of point A': (1, 4)

**The preimage's x and y-coordinates multiplied by 1/2 will give you the x and y-coordinates of the image.**

The boiling point of a substance is determined by the strength of the interparticle forces between molecules.

Boiling point is the temperature at which a liquid changes state from liquid to gas, also known as its vaporization point. The boiling point of water at sea level is 100°C (212°F).

In the case of SiH4, the boiling point is higher than that of SiO2 due to the stronger nature of the intermolecular forces. This is because SiH4 is held together by stronger hydrogen bonds, resulting in more energy needed to break apart the molecules. On the other hand, SiO2 is held together by weaker dipole-dipole interactions and London dispersion forces, meaning it requires less energy to break apart the molecules and thus has a lower boiling point.

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When 200 grams of water cools from 50.0°C to 250°C, the total amount of heat energy released by the water is The total amount of energy released is 20, 930 J.

We will apply the formula. q = mCt, where q is the amount of heat energy released. m= mass. C is the specific heat of the water. T= temperature change. Because the specific heat of the water has not been specified, we will use the standard value of 4.186J/g °C. q = mCΔT. q = 200 × 4.186 × (50 -25) (50 -25) q = 200 × 4.186 × 25 q = 5000 × 4.186 q = 20, 930 The total amount of energy released is 20, 930 J.

In physics, energy (from Ancient Greek: v, enérgeia, "activity") is a quantitative property that is transferred to a body or a physical system and is visible in the performance of work as well as in the form of heat and light. Energy is a conserved quantity, which means that it can be converted in form but not created or destroyed. The joule is the SI unit of energy measurement (J).

The kinetic energy of a moving object, the potential energy stored by an object (for example, due to its position in a field), the elastic energy stored in a solid object, and the chemical energy associated with chemical reactions are all common types of energy.

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The volume of the copper is equal to  4cm³.

The density of the substance can be described as the substance's mass per unit of its volume. The symbol commonly used to express density is ρ and the D letter can also be used.

The mathematical formula of the density can be expressed as written below:

Density = Mass/Volume or ρ = m/V

The density of a material varies with temperature and pressure. There is a small variation for solids as well as liquids but much larger for gases. Increasing the pressure of material decreases the volume of material and thus increases its density.

Given the mass of the copper = 35.2 g

The density of the copper at  20°C, d = 8.80 g/cm³

The volume of the copper, V = mass/density = 35.2/8.80 = 4 cm³

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The pressure acting here is 3.32 atm. Then the volume of copper can be determined using ideal gas law. The volume is 3.9 L.

Ideal gas equation is a combination of   Boyle's law, Charle's law and Avogadro's law. The expression relating pressure, volume,   temperature and number of moles of a gas is written as:

PV = nRT.

It can be rearranged as PM = dRT.

where d is the density and M be the mass.

Atomic mass of copper = 63.5 g/mol

density = 8.80 g/cm³

T = 20° C or 293 K.

Then pressure p =  dRT/M

p = 8.80 g/cm³ × 0.082× 293 /63.5 = 3.32 atm

Now the weight of copper = 35.2 g

number of moles of Cu = 35.2/63.5 = 0.5 g.

Then, v = nRT/P

v = 0.5 × 0.082 × 293 /3.32 = 3.9 cm³.

Therefore, the volume of copper is 3.9 L.

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According to the data collected during the experimental reaction in the laboratory, and the balanced equation of the reaction, 5 moles of iron (Fe) and 2.5 moles of aluminum oxide (Fe2O3) were produced.

Fe2O3 + 2Al → 2Fe + Al2O3

If 1 mole of Fe2O3 is combined with 2 moles of Al

So 3 moles of Fe2O3 combine with x moles of Al

X moles of Al = 3 moles Fe2O3 x 2 moles Al / 1 mole Fe2O3 = 6 moles

Limiting reagent: Al, because there are only 5 moles available

If 2 moles of Al produce 2 moles of Fe

So 5 moles of Al produce x moles of Fe

X moles of Fe = 5 moles of Al x 2 moles of Fe / 2 moles of Al = 5 moles

If 2 moles of Al produce 1 mole of Fe2O3

So 5 moles of Al produce x moles of Fe2O3

X moles of Fe = 5 moles of Al x 1 mole of Fe2O3 / 2 moles of Al = 2.5 moles

By establishing the balanced equation of the reaction and the stoichiometric relationships, the amount of limit reagent is first determined and with this data, the moles of products are later determined.

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Answer:

3KClO4 + KCl ➡️ 4KClO3

2AlI3 + 3HgCl2 ➡️ 2AlCl3 + 3HgI2

Answer:

proton 5+

electron 5-

neutron 0, neutral

Explanation:

Boron is the fifth element on the periodic table, meaning it's atomic# is 5. that is the # of protons. Protons have a positive chargé. The # of electrons in a neutrally charged atom is the same as the # of protons, because they're negatively charged. so if there are 5 protons, there are 5 electrons +5 + -5 = 0 chargé. The third subatomic particle is a neutron. It has a charge of 0, neutral, thus its name. You know there are 6 neutrons in a Boron atom because the atomic mass is 11. electrons have basically no weight, so 11 - 5 protons = 6 neutrons.

The subatomic particles in part Z of the boron atom are neutrons and protons. neutrons have a charge of zero while protons have a charge of +1. Note that Z represents the core of the boron atom.

The atom is composed of three fundamental subatomic particles which are;

Protons and neutrons are found at the core of the atom. This core is the center of the atom. The protons and neutrons are found inside the nucleus or core of the atom and are collectively called nucleons. Electrons move round the orbits of the atom.

Protons are positively charged, electrons are negatively charged while neutrons have no charge.

Part Z is the nucleus or core of the atom and contains neutrons and protons.

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ΔHrxn∘ = -144 kj / mol is the Standard Enthalpy of the reaction.  It is the sum of the individual enthalpies of the reactants subtracted from the sum of enthalpies of the products.  

2CuO(s)+NO(g) → Cu2O(s)+NO2(g)

[tex]Cu_{2}O[/tex] → 2[tex]Cu[/tex]  +  1/2 [tex]O_{2}[/tex]                                                        eqn 1

ΔH1 =  [tex]Cu_{2}O[/tex]  -  2 Cu - 1/2 [tex]O_{2}[/tex]

ΔH1 = -168.6 kj / mol  

2[tex]NO[/tex] + [tex]O_{2}[/tex] → [tex]2NO_{2}[/tex]                                                              eqn 2

ΔH2 = 2 [tex]NO[/tex]  +  [tex]O_{2}[/tex]   -  [tex]2NO_{2}[/tex]

ΔH2 = -114.1 kj / mol  

[tex]CuO[/tex] → [tex]Cu[/tex]  +  [tex]1/2 O_{2}[/tex]                                                            eqn 3

ΔH3 = Cuo - Cu -  [tex]1/2 O_{2}[/tex]

ΔH3=  157.3 kj / mol  

1/2 eqn 2    +          2  eqn 3    -  eqn 1

Δ H= -57.05 + 78.65 -168.6

ΔH= -144 kj / mol

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