I have a room that is sealed air tight that is sitting at 90 degrees and another room, also sealed air tight, that is sitting at 40 degrees. What happens when I open the door between the rooms? How does the air flow? What does the temperature become when the rooms reach equilibrium?

Answers

Answer 1

Answer: When you open the door between the two rooms, the air will flow from the warmer room to the cooler room until the temperatures in both rooms reach equilibrium. This process is called heat transfer. The final temperature will depend on the size and insulation of the rooms, as well as other factors such as humidity and air pressure.


Related Questions

a particle of mass m is embedded at a distance r/4 from the center of a massless circular disc of radius r which can roll without slipping down a plane inclined at an angle a with the horizontal. Use the Lagrangian method to write the dif- ferential equation of motion for the system

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The differential equation of motion for the system using the Lagrangian method is D²θ/Dt² + (g/[(19/8) r]sin α)θ = 0.

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The differential equation of motion for the system is given by the Lagrangian method when a particle of mass m is embedded at a distance r/4 from the center of a massless circular disc of radius r that can roll without slipping down a plane inclined at an angle a with the horizontal. Using the Lagrangian method, the differential equation of motion for

the system is given as follows:L = T - VL = [1/2 m(r² + (r/4)²)ω² + 1/2 Iω²] - mgrsin(α)r/4Here, I = [1/2 m(r/2)²] + m(r/4)²I = [1/2 m(r²/4 + r²/16)] + m(r²/16)I = m(r²/8)Therefore, I = mr²/4Then, the expression of Lagrangian can be given as:L = [1/2 m(r² + r²/16)ω² + 1/2 (mr²/4)ω²] - mgrsin(α)r/4L = [1/2 m(17r²/16)ω² + (1/8)mω²] - mgrsin(α)r/4L = [1/8 mω²(17r² + 2r²) - mgrsin(α)r/4]L = [1/8 mω²(19r²) - mgrsin(α)r/4]So, the Lagrangian equation of motion for the system is given as:D²θ/Dt² + (g/[(19/8) r]sin α)θ = 0

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when measuring absorbance readings it is important to hold the wavelength constant across all samples. group of answer choices true false

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The given statement "when measuring absorbance readings it is important to hold the wavelength constant across all samples" is true because it is important to hold the wavelength constant across all samples.

Keep the wavelength constant across all samples when taking measurements of absorbance. This is due to the fact that a substance's absorbance changes depending on the wavelength of light used to detect it.

Therefore, the absorbance measurements won't be precise and trustworthy if the wavelength is not maintained constant. A single wavelength of light is usually used for all measurements in a given experiment to guarantee precise and trustworthy results.

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A 0.7 kg mass is attached to an ideal spring with a constant of 86 N/m. The mass is initially held at rest so that the spring is at its unextended length of 0.95 m. The mass is then released. What is the maximum distance the mass will fall?

Answers

Since the mass is attached to an ideal spring, the system will undergo simple harmonic motion. The maximum distance the mass will fall is equal to the amplitude of the oscillation.

The period of oscillation can be calculated as:

T = 2π√(m/k)

where m is the mass and k is the spring constant.

Substituting the given values, we get:

T = 2π√(0.7 kg / 86 N/m) ≈ 0.887 s

The maximum distance the mass will fall is equal to half the amplitude of the oscillation, which can be calculated using the equation:

x = A cos(2πt/T)

where x is the displacement of the mass from its equilibrium position at time t, and A is the amplitude of oscillation.

At the maximum displacement, cos(2πt/T) will be equal to -1. Therefore,

A = -x

The velocity of the mass at the maximum displacement will be zero. Therefore, the total energy of the system will be equal to the potential energy at the maximum displacement:

1/2 k A^2 = m g A

where g is the acceleration due to gravity.

Solving for A, we get:

A = (m g / k) = (0.7 kg x 9.81 m/s^2) / 86 N/m ≈ 0.0807 m

Therefore, the maximum distance the mass will fall is approximately 0.0807 m.

if two objects in space are moved to a distance of 7 times further from each other than they were before, by what factor has the gravitational force changed? (hint: it should be a factor less than 1.

Answers

The gravitational force has changed by a factor less than 1, which is 1/49 or approximately 0.0204.

When two objects in space are moved to a distance of 7 times further from each other than they were before, the gravitational force has changed by a factor less than 1. Gravity is a natural phenomenon that arises due to the attraction between two objects with mass.

Gravity is directly proportional to the mass of the objects and inversely proportional to the square of the distance between them. The formula for the gravitational force is given by:Fg = (G x m1 x m2) / r2where, G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between them.

In the given case, if two objects in space are moved to a distance of 7 times further from each other than they were before, then their distance will become 7r. Hence, the new gravitational force will be given by:F'g = (G x m1 x m2) / (7r)2Simplifying the above expression:F'g = Fg/49.

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the diagram below illustrates the geometry of lunar phases with the moon shown in 8 positions in its orbit. which numbered position with a first quarter moon?

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The diagram you are referring to demonstrates the various Lunar phases as the Moon orbits Earth. To identify the numbered position representing the first quarter moon, let's understand the different lunar phases.



The primary lunar phases are:

1. New Moon
2. First Quarter
3. Full Moon
4. Last Quarter

These phases occur as the Moon orbits Earth, with the illuminated side of the Moon (the side facing the Sun) changing based on its position relative to Earth.

In the case of the first quarter moon, it occurs when the Moon has completed one-quarter of its orbit around Earth since the new moon. During this phase, half of the Moon's illuminated side is visible from Earth, making it appear as a semicircle in the sky.

Now, let's consider the numbered positions in the diagram:

1. New Moon - Moon is between Earth and the Sun, and its illuminated side is facing away from Earth.
2. Waxing Crescent - A small part of the illuminated side is visible, as the Moon moves away from the New Moon position.
3. First Quarter - The Moon has completed one-quarter of its orbit, and half of the illuminated side is visible from Earth.
4-7. Waxing Gibbous, Full Moon, Waning Gibbous, and Last Quarter - Other positions/phases as the Moon continues its orbit.
8. Waning Crescent - The Moon is almost back to its New Moon position.

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why parachutist travel at constant velocity for the last part of his drop​

Answers

Explanation:

Air friction finally builds up and  equals the magnitude of his weight.

The drag force resists the downward movement of gravity.

Eventually, they reach an equilibrium where acceleration = 0 and velocity remains constant.

light of 600.0 nm is incident upon a single slit. the resulting diffraction pattern is observed on a screen that is 0.50 m from the slit. the distance between the first and third minima of the diffraction pattern is 0.80 mm. which range of values listed below contains the width of the slit?

Answers

The width of the slit, which the light of 600.0 nm is incident upon, falls in the range of 2.95 µm to 3.05 µm.


1. Calculate the angular separation between the first and third minima (∆θ) using the given distance (0.80 mm) and screen distance (0.50 m): ∆θ = (0.80 mm) / (0.50 m) = 0.0016 rad.


2. Determine the order difference between the first and third minima (m): m = 3 - 1 = 2.


3. Calculate the angular separation for a single order (∆θ_m): ∆θ_m = ∆θ / m = 0.0016 rad / 2 = 0.0008 rad.


4. Use the single-slit diffraction formula to find the slit width (a): a = (λ / ∆θ_m), where λ is the wavelength (600.0 nm = 6.0 x 10^-7 m).


5. Calculate a: a = (6.0 x 10^-7 m) / 0.0008 rad ≈ 3.0 x 10^-6 m, or 3.0 µm.


6. The range is approximately ±0.05 µm, so the final range is 2.95 µm to 3.05 µm.

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how does the number of lines in the emission spectrum for element compare with the number of lines in the absorption spectrum ?

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The number of lines in the emission spectrum for an element compares with the number of lines in the absorption spectrum in that they are generally equal. When an element is heated, it emits light at specific wavelengths, creating an emission spectrum. Conversely, when light passes through a cool gas of that element, the same wavelengths of light are absorbed, creating an absorption spectrum.

1. An element is heated, and its electrons gain energy and move to higher energy levels.
2. The heated element emits light at specific wavelengths, creating an emission spectrum with distinct lines.
3. When light passes through a cool gas of the same element, electrons absorb the energy from the light and move to higher energy levels.
4. The absorbed wavelengths of light create an absorption spectrum with distinct lines.
5. The emission and absorption spectra for a given element have the same number of lines, as they represent the same energy level transitions within the element's electrons.

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a mass of 0.150 kg is attached to a spring with a force constant of 3.58 n/m and undergoes simple harmonic oscillations with an amplitude of 7.50 cm. what is the total mechanical energy of the system?

Answers

The full Mechanical energy of the machine is 0.01 J.

Mass of the cart, m = 0.15 kg

The force constant of the spring, K = 3.58 N/m

The amplitude of the oscillations, A = 7.5 cm = 0.075 m

[tex]E=\frac{1}{2} KA^2[/tex]

[tex]E= \frac{1}{2} *3.58*(0.075)^2\\E= 0.01J[/tex]

Mechanical energy is a form of energy associated with the motion and position of objects. It is the sum of two components: kinetic energy and potential energy. Kinetic energy is the energy possessed by an object due to its motion and is dependent on the mass of the object and its velocity. Potential energy is the energy an object possesses due to its position or state, and it is dependent on the height of an object above a reference point and its mass.

Mechanical energy is conserved in an isolated system where no external forces act on it. This means that the total mechanical energy of the system remains constant, even if the kinetic and potential energy of individual objects within the system change. Mechanical energy plays a crucial role in many aspects of physics, from the study of mechanics to the understanding of thermodynamics and electromagnetism.

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Question 12 (1 point)
Jared has been running in the park on a hot day when he feels his legs begin
spasming in an unusual way. He feels shaky. He thinks back to what he learned in
fitness class about heat emergencies for what to do. What should Jared do FIRST?
Run home to take a cold shower.
Find a cool place to rest.
Begin stretching carefully.
Buy a sports drink with electrolytes.

Answers

Find a cool place to rest. It is important for Jared to get out of the heat and lower his body temperature as quickly as possible.

What is temperature?

Temperature is a physical property of matter that is a measure of the average kinetic energy of the particles in a substance. It is the measure of hot and cold, and is usually expressed in terms of the Celsius, Fahrenheit, or Kelvin scale. Temperature affects the state of matter, and can be used to determine whether a substance is solid, liquid, or gas. Additionally, temperature affects the rate of chemical reactions, and can be used as a metric in which to measure the amount of energy being released or absorbed. Temperature is very important to all forms of life, as living organisms rely on temperature to survive and thrive.

Taking a cold shower, stretching and replenishing electrolytes can all happen after he finds a cool place to rest.

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you are running a length of fiber optic cable between two wiring closets. what best describes the cable you are running?

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The cable being run between the two wiring closets is most likely a fiber optic cable.

Fiber optic cables are used for high-speed data transmission over long distances. They consist of a core of optically transparent material, such as glass or plastic, surrounded by a cladding material that reflects light back into the core.

The core and cladding are protected by an outer jacket or sheath that provides physical protection and insulation. Fiber optic cables are preferred for long-distance communication because they are less susceptible to interference and signal degradation than copper cables.

They are also able to transmit data at much higher speeds and over longer distances without the need for signal repeaters.

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a basketball has a diameter of about 25 cm (0.25 meters). if i measure the apparent angular diameter of a basketball to be 357 arc seconds, what is its distance from me in meters?

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A basketball has a diameter of about 25 cm (0.25 meters). if i measure the apparent angular diameter of a basketball to be 357 arc seconds: the basketball is about 2.52 meters away from you.

To solve this problem, we can use the small angle formula which relates the angular size of an object, the actual size of the object, and its distance from the observer:

angular size = actual size / distance

First, we need to convert 357 arc seconds to radians:

1 arc second = 1/60 arc minute

1 arc minute = 1/60 degree

1 degree = π/180 radians

Therefore:

357 arc seconds = (357/60) arc minutes = 5.95 arc minutes

5.95 arc minutes = 5.95/60 degrees = 0.0992 radians

Now we can use the small angle formula:

0.0992 radians = 0.25 meters / distance

Solving for distance, we get:

distance = 0.25 meters / 0.0992 radians

distance = 2.52 meters

Therefore, the basketball is about 2.52 meters away from you.

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A 14.0 kg stone slides down a snow-covered hill (the figure (
Figure 1)), leaving point A with a speed of 12.0 m/s. There is
no friction on the hill between points A and B, but there is friction
on the level ground at the bottom of the hill, between B and the
wall. After entering the rough horizontal region, the stone travels
100 m and then runs into a very long, light spring with force
constant 2.10 N/m. The coefficients of kinetic and static friction
between the stone and the horizontal ground are 0.20 and 0.80,
respectively.
how far will the stone compress the spring?

Answers

To find the distance that the stone will compress the spring, we need to use conservation of energy. At point A, the total mechanical energy of the system is:

E = (1/2)mv^2

where m is the mass of the stone and v is its velocity at point A. We can calculate this as:

E = (1/2)(14.0 kg)(12.0 m/s)^2 = 1008 J

As the stone slides down the hill, it loses potential energy but gains kinetic energy. At point B, all of the stone's potential energy has been converted to kinetic energy, so we can write:

E = (1/2)mv^2

where v is the velocity of the stone at point B. We can solve for v as follows:

v = sqrt(2E/m) = sqrt(2(1008 J)/(14.0 kg)) = 12.0 m/s

Next, the stone encounters friction on the level ground between points B and the wall. The work done by friction is equal to the force of friction times the distance traveled:

W_friction = f_friction * d

where f_friction is the force of friction and d is the distance traveled. The force of friction is given by:

f_friction = µ_k * m * g

where µ_k is the coefficient of kinetic friction, m is the mass of the stone, and g is the acceleration due to gravity. Substituting values, we get:

f_friction = 0.20 * 14.0 kg * 9.81 m/s^2 = 27.7 N

The work done by friction is equal to the initial kinetic energy of the stone minus the final kinetic energy:

W_friction = (1/2)mv_B^2 - (1/2)mv_C^2

where v_B is the velocity of the stone at point B and v_C is its velocity just before hitting the spring. Solving for v_C, we get:

v_C = sqrt(v_B^2 - 2W_friction/m) = sqrt((12.0 m/s)^2 - 2(27.7 N * 100 m)/(14.0 kg)) = 9.31 m/s

Finally, we can calculate the distance that the stone compresses the spring using Hooke's law:

F_spring = -kx

where F_spring is the force exerted by the spring, k is the spring constant, and x is the distance that the spring is compressed. The force exerted by the spring is equal to the force required to decelerate the stone from v_C to zero:

F_spring = ma = m(v_C - 0)/t = mv_C/t

where t is the time it takes for the stone to come to a stop. We can calculate t using the equation:

v_C = at

where a is the acceleration of the stone, which is equal to -F_spring/m. Substituting values, we get:

t = v_C/(-F_spring/m) = -mv_C/k = -(14.0 kg)(9.31 m/s)/(2.10 N/m) = -62.4 s

(Note that the negative sign indicates that the force of the spring is opposite in direction to the motion of the stone.)

Substituting t into the equation for x, we get:

x = F_spring/k = (mv_C/t)/k = -(14.0 kg)(9.31 m/s)/(-62.4 s)(2.10 N/m) = 0.098 m

Therefore, the stone will compress the spring by 0.098 m.

what types of exoplanets are easiest to detect with the transit method? group of answer choices large planets far from their host stars hot planets far from their host stars large planets close to their host stars hot planets close to their host stars

Answers

The types of exoplanets that are easiest to detect with the transit method are: large planets close to their host stars and hot planets close to their host stars.

What is an exoplanet, An exoplanet or extrasolar planet is a planet that orbits a star outside of the Solar System's planetary system. It is detected indirectly by measuring its gravitational influence on its host star, its thermal or other radiation, or the effects of its atmosphere on the light from its host star as it passes through it.

What is the transit method, The transit method is one of the ways that exoplanets can be detected. It entails detecting a dip in a star's brightness when an exoplanet passes in front of it. A change in the star's apparent brightness is caused by the decrease in the amount of light reaching the observer due to the exoplanet being in the way.

What types of exoplanets are easiest to detect with the transit method, The transit method is most effective for detecting large planets close to their host stars or hot planets close to their host stars. This is due to the fact that such exoplanets are more likely to cause a significant decrease in their host star's brightness when they transit. As a result, smaller exoplanets or those far from their host stars may be difficult to detect with this technique.

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the north pole of a magnet is moved toward a copper loop, as shown below. if you are looking at the loop from above the magnet, will you say the induced current is circulating clockwise, counterclockwise, or is equal to 0?

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When the north pole of a magnet is moved toward a copper loop, if you are looking at the loop from above the magnet, you will say the induced current is circulating counter clockwise.

An induced current is a current that is generated when a magnetic field moves through a conductor or wire loop. When the magnetic field lines cut across a wire loop or conductor, it generates a voltage across the loop, causing an electric current to flow through it, which is known as an induced current.

The direction of the induced current is dependent on the polarity and direction of the magnetic field lines and the direction of motion of the magnetic field relative to the wire loop.

To determine the direction of the induced current, we must use the right-hand rule, which states that if the thumb of your right hand points in the direction of the magnetic field line, and your fingers wrap around the wire loop in the direction of motion of the magnetic field,

then the direction of the induced current in the wire loop is determined by the direction of your extended fingers.

In this case, the north pole of the magnet is moving toward the copper loop, which generates a magnetic field in the wire loop in the opposite direction to that of the north pole of the magnet. As a result, the induced current will circulate counterclockwise through the copper loop if you are looking at it from above the magnet.

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light from a slit passes through a transmission diffraction grating of 400 lines/mm, which is located 2.9 m from a screen. what are the distances on the screen (from the unscattered slit image) of the three brightest visible (first-order) hydrogen lines?

Answers

Distances on the screen from the central maximum to the first-order maximum for the three brightest visible hydrogen lines are:

y1 = 0.487 m, y2 = 0.357 m and y3 = 0.319 m.

How to determine Distances?

The distance on the screen from the central maximum (unscattered slit image) to the first-order maximum can be found using the formula:

d sin θ = mλ

where d is the spacing between adjacent lines on the diffraction grating, θ is the angle between the incident beam and the diffracted beam, m is the order of the maximum, and λ is the wavelength of the light. For the first-order maximum, m = 1.

The spacing between adjacent lines on the diffraction grating is:

d = 1/400 mm/line

   = 2.5 × 10⁻⁶ m/line

For hydrogen, the wavelengths of the three brightest visible lines in the Balmer series are:

λ1 = 656.3 nm

λ2 = 486.1 nm

λ3 = 434.0 nm

To find the angles θ for each of these wavelengths, we rearrange the equation:

θ = sin⁻¹ (mλ/d)

For m = 1 and λ = λ1:

θ1 = sin⁻¹ (1 × 656.3 × 10⁻⁹m / (2.5 × 10⁻⁶m)) = 0.168 radians

The distance on the screen from the central maximum to the first-order maximum for this wavelength is:

y1 = θ1 L = (0.168 radians) (2.9 m) = 0.487 m

Similarly, for m = 1 and λ = λ2:

θ2 = sin⁻¹ (1 × 486.1 × 10⁻⁹ m / (2.5 × 10⁻⁶m))

     = 0.123 radians

y2 = θ2 L = (0.123 radians) (2.9 m) = 0.357 m

And for m = 1 and λ = λ3:

θ3 = sin⁻¹ (1 × 434.0 × 10⁻⁹m / (2.5 × 10⁻⁶m)) = 0.110 radians

y3 = θ3 L = (0.110 radians) (2.9 m) = 0.319 m

Therefore, the distances on the screen from the central maximum to the first-order maximum for the three brightest visible hydrogen lines are:

y1 = 0.487 m

y2 = 0.357 m

y3 = 0.319 m

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forces and motion until test for physical science eginuity credit recovery ????

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Forces and motion are fundamental concepts in physics that help us understand the behavior of objects in motion. Forces can cause objects to accelerate, change direction, or stop moving altogether.

The three laws of motion proposed by Sir Isaac Newton provide a framework for understanding how forces affect motion. The first law states that an object at rest will stay at rest, and an object in motion will stay in motion, unless acted upon by an external force. The second law states that the acceleration of an object is directly proportional to the net force acting on the object and inversely proportional to its mass. The third law states that every action has an equal and opposite reaction. To test these concepts in physical science, experiments can be designed to measure the effects of forces on motion, such as the acceleration of objects on inclined planes, the motion of objects in free fall, or the forces involved in collisions.

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The complete question is

Forces and motion until test for physical science eginuity credit recovery ?

two wires meet at a junction, merging into one wire, and 6 a and 4 a flow into the junction. how much current flows out of the junction? two wires meet at a junction, merging into one wire, and 6 a and 4 a flow into the junction. how much current flows out of the junction? 4 a 2 a 10 a 6 a 5 a

Answers

According to Kirchhoff's Current Law, the current flowing out of the junction is 10 A, since the total current entering equals the total current leaving.

Kirchhoff's Flow Regulation (KCL) is an essential law of electric circuits which expresses that the complete flow entering an intersection (or hub) in a circuit should rise to the all out flow leaving the intersection. This regulation depends on the guideline of protection of charge, which expresses that electric charge can't be made or annihilated, just moved starting with one spot then onto the next.

In the given issue, two wires meet at an intersection and converge into one wire. This intersection can be viewed as a hub in the circuit, and as per KCL, the all out current entering the hub should be equivalent to the complete current leaving the hub. The issue expresses that 6 An and 4 A stream into the intersection, so the complete current entering the intersection is 6 A + 4 A = 10 A. Since there is just a single wire leaving the intersection, the ongoing streaming out of the intersection should likewise be 10 A.

KCL is an integral asset for dissecting complex circuits, as it permits us to decide the ongoing stream at each point in the circuit in light of the ongoing stream at different places. By applying KCL to every hub in a circuit, we can decide the ongoing move through each part of the circuit and eventually comprehend how the circuit works.

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an 80.0 kg skydiver jumps out of a balloon at an altitude of 1000 m and opens the parachute at an altitude of 200.0m (A). Assuming that the total resisting force on the driver is constant at 50.0 N with the parachute closed and constant at 3 600 N with the parachute open, what is the speed of the driver when he lands on the ground?(B) do you think the skydiver will get hurt? explain(C) At what height should the parachute be opened so that the final speed of the skydiver when he hits the ground in 5.00 m/s?(d) how realistic is the assumption that the total resisting force is constant? explain

Answers

ANSWERS:

A.
38.3 m/s
B.
Yes. 38.3 m/s is a very high speed and could potentially cause serious injury or death
C.
656.1 m
D.
Not very realistic. The resisting force depends on the speed of the skydiver.

EXPLANATIONS:

(A)
To solve for the speed of the skydiver when he lands on the ground, we can use conservation of energy. The initial potential energy of the skydiver is equal to the final kinetic energy plus the final potential energy.

Initial potential energy = mgh1 = 80.0 kg x 9.8 m/s^2 x 1000 m = 784000 J

Final potential energy = mgh2 = 80.0 kg x 9.8 m/s^2 x 200.0 m = 156800 J

With the parachute closed, the total resisting force is 50.0 N, so we can use the work-energy principle to find the final kinetic energy:

Work done by resisting force = Fd = 50.0 N x (1000 m - 200 m) = 40000 J

Final kinetic energy = Initial potential energy - Work done by resisting force - Final potential energy

Final kinetic energy = 784000 J - 40000 J - 156800 J = 587200 J

Finally, we can solve for the speed using the equation for kinetic energy:

Final kinetic energy = (1/2)mv^2

587200 J = (1/2)(80.0 kg)v^2

v = sqrt(1468 m^2/s^2) = 38.3 m/s

Therefore, the speed of the skydiver when he lands on the ground is 38.3 m/s.

(B) It's difficult to say whether the skydiver will get hurt based solely on the speed of impact. However, 38.3 m/s is a very high speed and could potentially cause serious injury or death. Other factors, such as the angle of impact and the condition of the ground, would also affect the outcome.

(C) We can use the same conservation of energy equation as in part (A), but solve for the height at which the parachute should be opened to achieve a final speed of 5.00 m/s.

Initial potential energy = mgh1 = 80.0 kg x 9.8 m/s^2 x h1

Final potential energy = mgh2 = 80.0 kg x 9.8 m/s^2 x 0

With the parachute open, the total resisting force is 3600 N, so we can use the work-energy principle to find the work done by the resisting force:

Work done by resisting force = Fd = 3600 N x (h1 - 0) = 3600h1 J

Then we can solve for the height using the equation:

Initial potential energy - Work done by resisting force = Final kinetic energy + Final potential energy

mgh1 - 3600h1 = (1/2)mv^2 + 0

Simplifying and solving for h1:

h1 = (v^2)/(2g) + 3600/g = (5.00 m/s)^2 / (2 x 9.8 m/s^2) + 3600/9.8 = 656.1 m

Therefore, the parachute should be opened at a height of 656.1 m to achieve a final speed of 5.00 m/s.

(D) The assumption that the total resisting force is constant is not very realistic because the resisting force depends on the speed of the skydiver. As the skydiver falls faster, the resisting force will increase due to air resistance. Therefore, the actual speed of the skydiver with the parachute closed and the actual speed with the parachute open would not be constant.

reflections from a thin layer of air between two glass plates cause constructive interference for a particular wavelength of light l. by how much must the thickness of this layer be increased for the interference to be destructive?

Answers

To achieve destructive interference, the thickness of the air layer must be increased by a distance of (m + 1/4) times the wavelength of the light.

2t = mλ

2t = (m + 1/2)λ

To find the difference in the thickness required for destructive interference, we can subtract the two equations:

2t - 2t' = (m + 1/2)λ - mλ

Simplifying this equation, we get:

t' = (m + 1/4)λ

Interference refers to the phenomenon where two or more waves overlap and interact with each other. When waves of the same frequency and amplitude meet, they can either add up or cancel out, depending on their relative phase. This phenomenon is known as constructive interference and destructive interference, respectively.

Constructive interference occurs when two waves are in phase with each other, meaning that their peaks and troughs line up, resulting in a wave with a larger amplitude. Destructive interference, on the other hand, occurs when two waves are out of phase with each other, meaning that their peaks and troughs are offset, resulting in a wave with a smaller amplitude. Interference is a fundamental concept in many areas of physics, including optics, acoustics, and quantum mechanics.

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a mass m is attached to a spring with spring constant k. when this system is set in motion with amplitude a, it has a period t. what is the period if the amplitude of the motion is increased to 2a?

Answers

If the motion's amplitude is increased to 2a, the period stays the same.

The amount of time is how long it takes for a wave to pass a location after going through one full cycle.

The formula for the springtime season is:

[tex]t = 2\ \sqrt{ \binom{m}{k} } [/tex]

where the spring constant k and time period = T and mass of the system = m

Motion's amplitude is a

We can infer from the equation that,

A spring-mass system's period is inversely proportional to the square root of the mass and proportionate to the spring constant.

The period of time stays the same even if we raise the motion's amplitude to 2a.

The time period is independent of a since it does not depend on amplitude.

Hence, if the motion's amplitude is increased to 2a, the period stays the same.

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suppose you only sampled the above signal at 45 hz. assuming that the motor vibrated at exactly 1800 rpm, at what frequency would a peak appear on your fft?

Answers

A peak would appear at 15 Hz on your FFT when sampling the signal at 45 Hz, and the motor is vibrating at exactly 1800 RPM.

To determine the frequency at which a peak would appear on your FFT when sampling a signal at 45 Hz and the motor vibrating at 1800 RPM, follow these steps:

1. Convert the motor's speed from RPM to Hz:

1800 RPM * (1 min / 60 sec) = 30 Hz. So, the motor vibrates at 30 Hz.

2. Use the Nyquist theorem, which states that the sampling rate should be at least twice the highest frequency present in the signal. In this case, the sampling rate is 45 Hz.

The highest frequency that can be correctly detected is 45 Hz / 2 = 22.5 Hz.

3. Since the motor's frequency (30 Hz) is higher than the Nyquist limit (22.5 Hz), aliasing will occur. Aliasing is when higher frequencies are incorrectly detected as lower frequencies due to insufficient sampling rate.

4. To find the aliased frequency, subtract the motor's frequency from the sampling rate and then find the absolute value: |45 Hz - 30 Hz| = 15 Hz.

Hence, a peak would appear at 15 Hz on your FFT when sampling the signal at 45 Hz, and the motor is vibrating at exactly 1800 RPM.

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which of the following is not a form of kinetic energy a. thermal energy b. mechanical energy c. elastic energy d. sound energy

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Answer down below:

C: Elastic energy

Elastic energy is a form of potential energy, because it is stored in the bonds between atoms in an object or substance when it is temporarily under stress. This stress could be due to the object being stretched or squashed.

c. Elastic energy is not a form of kinetic energy.

What is kinetic energy?

Kinetic energy is the energy generated by an object's movement or motion. It's the energy stored in moving objects, and it's dependent on the object's mass and speed. As the object's mass and velocity rise, so does the amount of kinetic energy it possesses.

Types of kinetic energy include:

Mechanical energy: The total energy stored in a moving object's position and motion is known as mechanical energy.

Thermal energy: Thermal energy is the energy that results from the motion of particles in a substance. The greater the speed of the particles, the greater the thermal energy.

Sound energy: The energy created by the vibration of an object is known as sound energy. It travels in the form of waves through the air.

Elastic energy: Elastic energy is the energy kept in an object when it is compressed or extended. For instance, when you extend a rubber band or compress a spring, the energy stored in them is elastic energy.

Therefore, from the given options, elastic energy is not a type of kinetic energy.

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question 11 pts which of the following statements about inductors is correct? group of answer choices inductors store energy by building up charge. when an inductor and a resistor are connected in series with a dc battery, the current in the circuit is reduced to zero in one time constant. when it is connected in a circuit, an inductor always resists having current flow through it. when an inductor and a resistor are connected in series with a dc battery, the current in the circuit is zero after a very long time. an inductor always resists any change in the current through it.

Answers

An inductor always resists any change in the current through it. The correct statement about inductors is D.


This is due to the property of inductance, which is the ability of an inductor to generate a voltage that opposes any change in the current through it. This is described by Faraday's law of electromagnetic induction. As a result, inductors are commonly used in circuits to smooth out changes in current, and also to filter out high-frequency signals.

Option A is incorrect because inductors store energy in a magnetic field, not by building up charge. Option B is incorrect because an inductor allows current to flow through it, but opposes changes in the current. Option C is incorrect because the current in the circuit will eventually become steady, but not zero. Hence option D is correct.

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What is the initial energy for the scenario below? You and a bike have a combined mass of 100 kg and are going 5 m/s. You then go up a hill as far as you can before coming to a stop.

Answers

The initial energy of the system is 1250 J, which is the kinetic energy of the bike and rider before they start going up the hill. This energy is then converted to potential energy as the bike and rider move up the hill and come to a stop at the top.

To calculate the initial energy, we need to use the kinetic energy formula:

KE = 0.5 * m * v²

where KE is the kinetic energy, m is the mass, and v is the velocity.

Substituting the given values, we get:

KE = 0.5 * 100 kg * (5 m/s)²

= 0.5 * 100 kg * 25 m²/s²

= 1250 J

Therefore, the initial energy of the system is 1250 joules.

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imagine that radar had never been invented and that we instead had to rely on a less reliable method of measuring distances in our solar system. if that method led us to underestimate the earth-sun distance by 10%, how would it affect other measurements in the distance chain?

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Underestimating the Earth-Sun distance by 10% would lead to a 10% error in all other measurements in the distance chain within our solar system, which would significantly impact our understanding of the size and scale of our solar system.

If radar had never been invented and we relied on a less reliable method of measuring distances in our solar system, underestimating the Earth-Sun distance by 10% would significantly affect other measurements in the distance chain.
Step 1: Determine the underestimated Earth-Sun distance
The actual Earth-Sun distance, also known as 1 astronomical unit (AU), is approximately 149.6 million kilometres. If we underestimated this distance by 10%, the measured distance would be:
149.6 million km * 0.9 = 134.64 million km
Step 2: Understand the impact on other measurements
Distances within our solar system are often measured using astronomical units (AU). If our measurement of 1 AU is off by 10%, then all other distance measurements based on this unit will also be off by 10%. This would impact our understanding of the size and scale of our solar system.
Step 3: Apply the error to other distance measurements
For example, the distance between Earth and Mars, on average, is about 225 million kilometers, or 1.52 AU. If our measurement of 1 AU was 10% less, we would underestimate the Earth-Mars distance as well:
1.52 AU * 134.64 million km = 204.656 million km (incorrect measurement)
The actual Earth-Mars distance would still be 225 million km, but our underestimated measurements would make us believe that it is only 204.656 million km.

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HELP PLS URGENT
(b) Three forces of magnitude 6 N, 2 N, and 3 N act on a small object in directions North, South, and West respectively. Find the direction and magnitude of the resultant force. If the object is free to move and its mass is 0.2 kg calculate the initial acceleration.​

Answers

Answer:

The net force in the North-South direction is 6 N - 2 N = 4 N towards the North. The net force in the East-West direction is 3 N towards the West. The magnitude of the resultant force can be found using the Pythagorean theorem: sqrt(4^2 + 3^2) = 5 N.

The direction of the resultant force can be found using trigonometry: tan(θ) = 3/4, so θ = arctan(3/4) = 36.87° West of North.

The acceleration of the object can be found using Newton’s second law: F = ma, so a = F/m = (5 N)/(0.2 kg) = 25 m/s^2.

So, the initial acceleration of the object is 25 m/s^2 in the direction

Explanation:

36.87° West of North.

What type of water is most of the water on the earth?
A.
saltwater
B.
groundwater
C.
lake water
D.
freshwater

Answers

Answer:

Saltwater

Explanation:

Because of the oceans.

Answer:

A: Saltwater

Explanation:

97% of all water on earth is saltwater.

What type of reaction occurs when a cadle is burned

Answers

on the candle wick a chemical reaction is occurring because it’s burning and creating ash. But for the candle wax it’s a physical reaction because the candle wax is simply melting but it’s still wax.

which type of scale has all the properties of an interval scale with the additional attribute of representing absolute quantities, characterized by a meaningful absolute zero?

Answers

The type of scale that has all the properties of an interval scale with the additional attribute of representing absolute quantities, characterized by a meaningful absolute zero, is a ratio scale.

The type of scale that has all the properties of an interval scale with the additional attribute of representing absolute quantities, characterized by a meaningful absolute zero is a ratio scale. In a ratio scale, the values not only have an order and equal intervals but also a true, non-arbitrary zero point.

This means that ratios of values are meaningful, and one can meaningfully say that a value is, for example, twice or half of another value. Examples of ratio scales include measurements of weight, length, time, temperature in Kelvin, and counts of discrete objects. Ratio scales provide the most precise and informative type of measurement and are widely used in scientific and statistical analysis.

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