how to find the area of a triangle without a given base

We can therefore find the other angle of right angle triangle by

Pythagoras , then x = 142 - y   and    y = 142 - x

A fundamental theorem in geometry that deals with the sides of a right triangle is known as the Pythagorean theorem. In it, it is said:

a+ b² = c²

where the lengths of the right triangle's legs are a, b, and c, and the length of the hypotenuse (the side across from the right angle) is c

Nevertheless, if we know the other two, we can use the fact that the total of the angles in a triangle is always 180 degrees to determine one of the angles. We are aware that angle C in this situation is 38 degrees.

We thus have:

x + y + 38 = 180

Calculating x and y results in:

x = 142 - y

y = 142 - x

We can therefore find the other angle if we know the value of one. To determine the real figures, we still want further details.

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First thing you need to do is raise the decimal. Once you've raised the decimal then you should continue through the problem as if it were a standard long division question.

Start with the first number which is 6.

6 divided by 3 is 2. That means you can subtract 6 from the first number.

Then, you bring down 3 and do the same thing.

3 divided by 3 is 1. Subtract 3 from 3 and then bring down the next number.

Finally, 3 divided by 9 is three.

By following this process, you should get 2.13 as your final answer.

Look at the image below for more reference.

Answer:  

vertex= 4,-25

y coordinate of vertex = (x+4)2-25

x coordinate of vertex= x2-8x-9

Step-by-step explanation:

Answer:

(a) = 0.92
(b) = 0.7613

Step-by-step explanation:

Here are some information to help us answer these problems:

Given That:

P(A) = 0.69
P(B) = 0.23

Then,

Problem (a): P(A ∪ B) when, A ∩ B = ∅:

P(A ∪ B) = 0.69 + 0.23 - 0 = 0.92



Problem (b): P(A ∪ B) when, A ∩ B ≠ ∅:

P(A ∪ B) = 0.69 + 0.23 - (0.69 × 0.23) = 0.7613




I hope you find this easy to understand....

Have any questions? Write in the comments.

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We can't make any inferece of any definitive conclusions about the entire populations of students in the two classes.

What is population in Mathematics?

In mathematics, population refers to a group of individuals, objects, or events that share a common characteristic or feature. This group is the target of a study, and the goal is to make generalizations about the entire population based on a sample from that population.

For example, in a study on the average height of adult males in a particular country, the population would be all adult males in that country. However, it is not practical to measure the height of every single adult male in the country, so a sample is taken instead. The sample is a subset of the population and should be chosen in such a way that it is representative of the entire population.

To make an inference about the quiz scores of all the students in class A compared to all the students in class B, we can compare the medians of the two classes. The median is the middle score when the scores are arranged in order.

The scores of the 20 students in class A are

85, 86, 88, 89, 90, 90, 91, 92, 93, 94, 94, 94, 95, 96, 97, 98, 99, 99, 100, 100

And the scores of the 20 students in class B are

75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94

To find the median score for each class, we need to find the middle score. For class A, the middle score is 94 (since there are an even number of scores, we take the average of the middle two). For class B, the middle score is also 87.

Comparing the medians of the two classes, we see that the median score for class A (94) is higher than the median score for class B (87). This suggests that the quiz scores for class A may be higher overall than the quiz scores for class B. However, it's important to note that this is only based on a sample of 20 students from each class, so we can't make any definitive conclusions about the entire populations of students in the two classes.

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Correct question is "Two math classes took the same quiz. The scores of 20 randomly selected students from each class are listed below. Based on the medians of the scores for each class, what inference would you make about the quiz scores of all the students in class a compared to all the students in class b?

Here the scores of the 20 students in class A are 85, 86, 88, 89, 90, 90, 91, 92, 93, 94, 94, 94, 95, 96, 97, 98, 99, 99, 100, 100

And the scores of the 20 students in class B are

75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94"

a. The middle 99.7% of students between 0.04 and 0.10.
b. The range for the 16% of lowest BACs is 0.06 or below.

c. 2.28% of students have a BAC above 0.09.

To find the range, use the properties of the normal distribution and the given mean (0.07) and standard deviation (0.01).

The middle 99.7% of students between 0.04 and 0.10.

To find the range use the z-score corresponding to the 16th percentile (z ≈ -1).

The range for the 16% of lowest BACs is 0.06 or below.

To find the percentage, find the z-score for 0.09 first.

Approximately 2.28% of students have a BAC above 0.09.

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Therefore there is graph below and whole process of graph

g(x) = -1/x (x).

g(x) = 1/(-x + 5).

Describe equation?

A mathematical equation is a formula that uses the equals symbol (=) to denote the equality of two expressions.

A formula would be 3x - 5 = 16,

for instance. We may determine the value of the variable x by solving this equation: x = 73.

We can apply a number of transformations on f to convert f(x) to g(x) (x).

A . Starting with the graph of f(x) = 1/x for function a, we can perform a vertical reflection to obtain the graph of g(x) = -1/x (x).

B . Starting with the graph of f(x) = 1/x, we can apply a horizontal shift to the function b's graph, g(x) = 3/(x + 2).

We can apply a number of transformations on f to convert f(x) to g(x) (x).

For instance, we can use the following transformations to change f(x) = x2 into g(x) = (x - 3)2 + 2:

- Replace x with to move the graph 3 units to the right (x - 3)

- Apply a horizontal shift to the left of two units and a vertical stretch of three factors to f f(x) = 1/x.

Starting with the graph of f(x) = 1/x, we may apply a horizontal shift to the right by 5 units and a vertical reflection to obtain the graph of function c, g(x) = 1/(-x + 5).

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The  expression that makes the equation true is A)40 ÷ (5 x 2) x 17.55.

What is expression?

Mathematical expressions consist of at least two numbers or variables, at least one arithmetic operation, and a statement. It's possible to multiply, divide, add, or subtract with this mathematical operation. Unknown variables, integers, and arithmetic operators are the components of an algebraic expression. There are no symbols for equality or inequality in it.

Here first solve given expression then,

=> 13.5 x (1.2 + 4) = 13.5×1.2+13.5×4 = 70.2

Now solving option expressions then,

A) 40 ÷ (5 x 2) x 17.55 = 40÷10×17.55 = 4×17.55 = 70.2

B) 36 ÷ (4.8 − 2.6) x 3 = 36÷2.4×3 = 45

C) 22 x (3.6 − 1.2) + 4 = 22×(2.4)+4 = 56.8

D) 18 ÷ (3 x 3) x 35.2 = 18÷ 9×35.2 = 2×35.2 = 70.4

Hence the  expression that makes the equation true is A)40 ÷ (5 x 2) x 17.55.

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Norma's expenses and earnings will both be $89, and she needs to teach 8 classes during her first month to earn back her certification cost.

To calculate Norma's expenses and earnings, we need to first determine how many classes she needs to teach to earn back her certification cost.
Let x be the number of classes Norma teaches in her first month.

Her earnings for the first month will be her base salary plus the additional amount per class, which can be represented as 57 + 4x.
To find out how many classes Norma needs to teach to cover her certification cost, we can set up the equation:
57 + 4x = 89
Now, we need to solve for x:

4x = 89 - 57
4x = 32
x = 8
So, Norma needs to teach 8 classes to earn back her certification cost.

Now, we can calculate Norma's total expenses and earnings for the first month.

Her expenses are the certification cost, which is $89.

Her earnings are the base salary plus the additional amount per class:
Earnings = 57 + 4 * 8
Earnings = 57 + 32
Earnings = $89.

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Answer:

If y=0, then 4y^2•2y^4 = 4(0)^2•2(0)^4 = 0.

Therefore, any of the options that involve y, such as A) 6y^6 or C) 8y^6, would also be equal to 0.

The only option that is still a valid answer is B) 6^8, which is simply 6 to the 8th power, or 1679616.

Hope This Helps!

when y = 5 in the equation y = -3x + 5, the value of variable x is 0.

An equation is a statement of equality between two mathematical expressions that contain variables and mathematical operations. The goal of solving an equation is to determine the value(s) of the variable(s) that make the equation true.

the steps to find out what x is in the equation y = -3x + 5 for y = 5:

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The complete question is:

I need a step by step process for to find out what, "x" is in this problem. y = -3x +5 for y=5

Answer:

Step-by-step explanation:

Using the distributive property, we can simplify the expression as follows:

3(r+2) + 5(r+t-2)

= 3r + 3(2) + 5r + 5t - 5(2)

= 3r + 6 + 5r + 5t - 10

= 8r + 5t - 4

Therefore, the simplified expression is:

8r + 5t - 4

Answer:

We need to find the probability that the two winners line in Pike.

We know that 2 out of the 10 customers who entered the drawing live in Pike.

Thus, the probability of the first winner line in Pike is:

[tex]\dfrac{2}{10}[/tex]

Then, considering the first winner live in Pike, there are left 9 customers, and 1 of them live in Pike. Thus, the probability that the second winner lives in Pike is:

[tex]\dfrac{1}{9}[/tex]

Now, the probability that the first one lives in Pike and the second one also lives in Pike is the product of the two probabilities we found:

[tex]\dfrac{2}{10}\times\dfrac{1}{9}=\dfrac{2}{10\times9} =\dfrac{1}{10\times4.5} =\dfrac{1}{45}[/tex]

Therefore, the probability that both winners live in Pike is:

[tex]\dfrac{1}{45}[/tex]

The probability that the mean yield of the 80 one acre plots chosen will be within 2 bushels of the population mean is 0.9332. The assumptions made to answer part (a) are that the population standard deviation is known, the sample is randomly selected, and the sample size is large (n>=30)

a) We can use the central limit theorem to approximate the distribution of the sample mean. The distribution of the sample mean can be approximated as a normal distribution with a mean of 107 bushels and a standard deviation of 12/√80=1.34 bushels. Therefore, we can find the probability that the sample mean falls within 2 bushels of the population mean using the standard normal distribution.

P(105 ≤ X ≤ 109) = P(Z ≤ (109-107)/1.34) - P(Z ≤ (105-107)/1.34)

= P(Z ≤ 1.49) - P(Z ≤ -1.49)

= 0.9319 - 0.0681

= 0.8638

Therefore, there is an 86.38% probability that the mean yield of the 80 one acre plots will be within 2 bushels of the population mean.

b) Assumptions made:

The sample of 80 one acre plots is selected at random.

The one acre plots are independent of each other.

The population standard deviation is known and remains constant.

The distribution of the yield of corn per acre is approximately normal.

The sample size is large enough (n≥30) to apply the central limit theorem.

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1. the equation of the quadratic function is: y = (8/65)(x + 5)(x - 13)

2. The axis of symmetry is the line x = 0 (the y-axis).

What is quadratic function?

The quadratic equation with roots -5 and 13 can be written as:

y = a(x + 5)(x - 13)

where a is a constant that depends on the coefficient of the quadratic term.

To find the value of a, we can use the fact that the coefficient of the quadratic term is the sum of the roots, multiplied by -1:

a = -(sum of roots) / (product of roots)

a = -(-5 + 13) / (-5 * 13)

a = 8 / 65

Therefore, the equation of the quadratic function is:

y = (8/65)(x + 5)(x - 13)

What is symmetry?

2. The axis of symmetry is the line x = 0 (the y-axis).

To find the axis of symmetry, we can use the formula:

x = -(b / 2a)

where a and b are the coefficients of the quadratic function. In this case, a = 8/65 and b = 0, since there is no linear term.

Substituting these values, we get:

x = -(0 / (2 * (8/65)))

x = -0

Therefore, the axis of symmetry is the line x = 0 (the y-axis).

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There are various techniques to simplify algebraic expressions, including:

1. Combining like terms: In an algebraic expression, like terms are terms that have the same variable raised to the same power. To simplify the expression, we can combine these like terms. For example, in the expression 3x + 2y + 5x - 4y, we can combine the x terms and the y terms to get 8x - 2y.

2. Distributing: When a number or variable is outside a set of parentheses and is being multiplied by a sum or difference inside the parentheses, the number or variable can be distributed to each term inside the parentheses. For example, in the expression 3(x + 2), the 3 can be distributed to both x and 2, resulting in the simplified expression 3x + 6.

3. Simplifying exponents: When an expression contains exponents, rules of exponentiation can be used to simplify the expression. For example, in the expression x^2 * x^3, the exponents can be added to give x^(2+3) = x^5.

4. Factoring: When an expression contains common factors, those factors can be factored out. For example, in the expression 2x^2 + 4x, both terms have a factor of 2 and a factor of x, so these factors can be factored out to give 2x(x + 2).

The number of committees with 4 members can be formed from a group of 10 people are 210 different committees

To find the number of different committees with 4 members that can be formed from a group of 10 people we can use the combination formula which is,

nCr = n!/r!(n-r)!

where:

nCr = number of combinations

n = total number of objects in the set

r = number of choosing objects from the set

from the given data:

n = 10

r = 4

From the above formula, we can write the equation as:

= 10C4

=C(10,4)

= 10! / (4! * 6!)

= (10 * 9 * 8 * 7) / (4 * 3 * 2 * 1)

= 210

Therefore, 210 different committees with 4 members can be formed from a group of 10 people.

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The angle m∠A + m∠C = 180° in the inscribed quadrilateral ABCD.

To prove that m∠A + m∠C = 180° in an inscribed quadrilateral ABCD with circle O, follow these steps:
1. Statement: Quadrilateral ABCD is inscribed in circle O.
  Reason: Given.
2. Statement: m∠BCD = 2(m∠A) and m∠DAB = 2(m∠C).
  Reason: Inscribed Angle Theorem
3. Statement: m∠BCD + m∠DAB = 360°.
  Reason: The sum of the measures of the angles in a circle is 360°.
4. Statement: 2(m∠A) + 2(m∠C) = 360°.
  Reason: Substitution Property (from steps 2 and 3).
5. Statement: m∠A + m∠C = 180°.
  Reason: Division Property of Equality (divide both sides of the equation in step 4 by 2).

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According to Benford's law, 5 will be the first digit of a random number set is d. less often than 4.

According to Benford's law, which is an empirical law about the frequency distribution of leading digits in many real-life collections of numerical data, the digit 5 is actually the second least frequent leading digit after 1 and is less common than 4 as a first digit. In actuality,

Benford's rule states that the likelihood of a number having four as its first digit is nearly thirty percent, whereas the likelihood of a number having 5 as its first digit is approximately 25%. This is due to the fact that numbers with smaller starting digits are more common than those with bigger leading digits in many naturally occurring datasets.

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(12, 23)  are the coordinates of the center of the rectangle with coordinates (6, 38) and (18, 8).

To find the coordinates of the center of the rectangle in the standard (x, y) coordinate plane, we can use the midpoint formula. The midpoint formula states that the coordinates of the midpoint of a line segment with endpoints (x₁, y₁) and (x₂, y₂) are:

((x₁ + x₂) / 2, (y₁ + y₂) / 2)

In this case, the opposite vertices of the rectangle have coordinates (6, 38) and (18, 8). We can use these coordinates to find the midpoint of the rectangle as follows:

The x-coordinate of the midpoint is (6 + 18) / 2 = 12.

The y-coordinate of the midpoint is (38 + 8) / 2 = 23.

Therefore, the coordinates of the center of the rectangle are (12, 23)

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Answer: To solve this problem, we can use trigonometry and the relationship between angle, distance, and altitude in a right triangle.

Let's denote the angle the pilot was flying at takeoff as θ. We can then use the tangent function to find θ, since:

tan(θ) = opposite/adjacent

In this case, the opposite side is the altitude the pilot reached (1500 feet), and the adjacent side is the distance the pilot traveled before reaching that altitude (2 miles = 10560 feet). So we can plug in these values and solve for θ:

tan(θ) = 1500/10560

θ = tan⁻¹(1500/10560)

θ ≈ 7.67 degrees

So the pilot was flying at an angle of approximately 7.67 degrees at takeoff from the runway.

Step-by-step explanation:

Answer:

x=56

Step-by-step explanation:

Solve for x by simplifying both sides of the equation, then isolating the variable.

Answer:

x = 56

Step-by-step explanation:

Given that-

x/7 - 4 = 4

x/7 - 4 + 4 = 4 + 4                 >> Add 4 to both sides

x/7 = 8                

7x/7 = 8 × 7                             >> Multiply both sides by 7

x = 56

Check Answer-

Substitute x in the equation the check.

56/7 - 4 = 4              >> 56/7 = 8

8 - 4 = 4                  >> 8 - 4 = 4

4 = 4                        >> Correct

RevyBreeze

The probability calculation resulted in (a) 2.28% (b) zero.

a) To find the proportion of components that exceed 10,200 kilograms per square centimeter in tensile strength, we need to find the area to the right of 10,200 under the normal distribution curve. Using the z-score formula, we have:

z = (x - mu) / σ

z = (10,200 - 10,000) / 100

z = 2

Looking up the area to the right of z = 2 in a standard normal distribution table or using a calculator, we find this to be approximately 0.0228. Therefore, about 2.28% of the components exceed 10,200 kilograms per square centimeter in tensile strength.

b) To find the probability that a randomly chosen metal component has a tensile strength of fewer than 9,500 kilograms per square centimeter, we need to find the area to the left of 9,500 under the normal distribution curve. Using the z-score formula, we have:

z = (x - mu) / σ

z = (9,500 - 10,000) / 100

z = -5

Looking up the area to the left of z = -5 in a standard normal distribution table or using a calculator, we find this to be approximately 0.

Therefore, the probability that a randomly chosen metal component has a tensile strength of fewer than 9,500 kilograms per square centimeter is essentially 0.

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The value of the given term in which it represent  in standard notation and scientific notation is (a) 0,000914 mole per lit (b) [tex]4.2[/tex] x [tex]10^{5}[/tex] pound

What about standard notation?

In mathematics, standard notation refers to the conventional way of writing mathematical expressions and equations using commonly accepted symbols, signs, and rules. This notation is widely recognized and used by mathematicians, scientists, engineers, and other professionals in the field.

Define scientific notation:

Scientific notation is a way of representing numbers that are either very large or very small. It is a shorthand way of writing numbers using powers of 10. In scientific notation, a number is expressed as the product of a coefficient and a power of 10.

For example, the number 3,000,000 can be written in scientific notation as 3 x 10^6. The coefficient 3 is multiplied by 10 raised to the power of 6 (or 1,000,000), which represents the number of zeros in the original number.

According to the given information:

(a) Given that there is [tex]9.14[/tex] x [tex]10^{-4}[/tex] mole per lit.

So, obtain it in standard notation we have that,

⇒ [tex]9.14[/tex] x [tex]10^{-4}[/tex] = [tex]9.14[/tex] x [tex]\frac{1}{10000}[/tex]

                      = [tex]0.000914[/tex] mole per lit.

(b) Given that there is 420000 pounds

So, obtain it in scientific notation we have that,

⇒ [tex]420000[/tex] = [tex]42[/tex] x [tex]10^{4}[/tex]

                = 4.2 x [tex]10^{5}[/tex] pounds.

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Answer:

  radius : height = 7 : 3

Step-by-step explanation:

You want the ratio of the base radius to the height of a cylinder that has 30% of its surface area as lateral area.

The lateral area of a cylinder is ...

   LA = 2πrh

The base area of a cylinder is ...

  A = 2(πr²) = 2πr·r

Then the ratio of lateral area to total area is ...

  [tex]\dfrac{\text{LA}}{\text{LA+A}}=\dfrac{2\pi rh}{2\pi rh+2\pi rr}=\dfrac{h}{h+r}=\dfrac{30}{100}[/tex]

Inverting this relation lets us solve for r/h:

  [tex]\dfrac{h+r}{h}=\dfrac{100}{30}\\\\1+\dfrac{r}{h}=1+\dfrac{70}{30}\\\\\boxed{\dfrac{r}{h}=\dfrac{7}{3}}[/tex]

To find the amount of interest you will owe, we need to calculate the interest using the formula:

Interest = Principal * Rate * Time

Where:

- Principal = $777 (the amount you owe)

- Rate = 18% per year (expressed as a decimal, or 0.18)

- Time = 1 year (since you have been making payments for a year)

Plugging in these values, we get:

Interest = $777 * 0.18 * 1

Interest = $139.86

So, the amount of interest you will owe is approximately $139.86.

The range interval of the given data is {73,80]

and range for term 2 is [74,80]

You may have studied the techniques for determining a representative value for the provided data in statistics, or the measure of central tendency. Remember that there are three ways to measure central tendency: mean, median, and mode.

Spatial Statistics

Due to the fact that the measurements of central tendency do not provide sufficient detail about a given set of data. Another factor that must be investigated in statistics is variability. We require a single number to characterize variability, much like measures of central tendency. This one number has demonstrated a certain amount of dispersion. You will discover more about range, one of the dispersion measures, in this post.

According to the given problem

the range of any date is equal to the interval of lower and upper limits,

So

Form term 1

Our data start from 73, 74,,75,76,78,79,80

So according to the given data 73 is the lower limit and 80 is the upper limit

The range interval of the given data is {73,80]

and range for 2

in  term 2 the lower limit is 74 so our range  is [74,80]

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The lateral surface area of the triangular prism container is 270 cm².

We will begin with the calculation of perimeter of equilateral triangle.

Perimeter = 3 × sides

Perimeter = 3 × 6

Perimeter = 18 cm

Now calculating the lateral surface = perimeter of base × height

Keep the values in formula

Lateral surface of equilateral triangle prism = 18 × 15

Performing multiplication again

Lateral surface area = 270 cm²

Thus, the lateral surface area of the container is 270 cm².

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The picture is added of equilateral triangle with dimensions.