Answer:
The intensity of the electric field is
[tex]|E|=10654.37 \:N/C[/tex]
Explanation:
The electric field equation is given by:
[tex]|E|=k\frac{q}{d^{2}}[/tex]
Where:
k is the Coulomb constant q is the charge at 0.4100 m from the balloond is the distance from the charge to the balloonAs we need to find the electric field at the location of the balloon, we just need the charge equal to 1.99*10⁻⁷ C.
Then, let's use the equation written above.
[tex]|E|=(9*10^{9})\frac{1.99*10^{-7}}{0.41^{2}}[/tex]
[tex]|E|=10654.37 \:N/C[/tex]
I hope it helps you!
Answer:
10650
Explanation:
just round that answer to four significant figures and you get that answer
An athlete runs 140 m across a level field at an angle of 45.0° north of east. What is the north component of this displacement?
Displacement is a vector quantity thus, having different directional component. The component of the given displacement to the north is 98.99 m.
What is displacement ?The displacement is the measure of how long and in which direction an object is moved from the starting position. Displacement is a vector quantity thus, characterized by a magnitude and direction.
In physics, displacement is the product of velocity and time. The vertical component of the displacement = d sin θ
horizontal component = d cos θ.
The component to the north for a displacement of 140m with the angle of 45° is = 140 × sin 45 = 98.99 m.
Therefore, the north component of the displacement is about 99 m.
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it is natural tendency of bodies to eventually come to a rest position .(true or false )physic question
Answer:
True
Explanation:
Newton's first law of motion is applicable to both moving and nonmoving objects. ... It would take an unbalanced force to keep an object in motion at a constant velocity. False- balanced force. It is the natural tendency of all objects to eventually come to a rest position.
Assuming the acceleration is still -9.81 m/s2, what is the instantaneous velocity of the shuttlecock when it hits the ground
The acceleration is still -9.81 m/s2, and the instantaneous velocity of the shuttlecock when it hits the ground is [tex]V_{int}[/tex] = [tex]\sqrt{U^{2} + 19.6H }[/tex]
Acceleration is determined as the rate of change of velocity of an object with respect to time. Acceleration is represented by the SI unit is meter per second squared (m/[tex]s^{2}[/tex]). Acceleration is denoted by "a".
Instantaneous velocity is the rate of change of position for a time interval which is almost zero (very small). The magnitude of the instantaneous velocity is instantaneous speed. It is measured by using SI unit m/s.
Mathematically, the equation for acceleration is:
a = [tex]v\frac{dv}{dt}[/tex]
ah = [tex]v^{2}[/tex] - [tex]u^{2}[/tex]
Where the acceleration is still -9.81 m/s2
Hence, [tex]v^{2}[/tex] - [tex]u^{2}[/tex] = 2 (-9.81) * -H
Therefore, [tex]v_{int}[/tex] = [tex]\sqrt{U^{2} + 19.6H }[/tex]
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A 2.5 kg block is initially at rest on a horizontal surface. A horizontal force of magnitude 6.0 N and a vertical force are then applied to the block (Fig. 6-17). The coefficients of friction for the block and surface are ms 0.40 and mk 0.25. Determine the magnitude of the frictional force acting on the block if the magnitude of is (a) 8.0 N, (b) 10 N, and (c) 12 N.
Kinetic friction force, or f k = k F N = 3.1N, is the amount of frictional force acting on the block.
Static friction is the friction that exists between two systems when they are in contact and immobile with respect to one another. Kinetic friction is the term for the resistance that exists between two systems while they are in contact and moving in relation to one another.
Calculation:Either static or kinetic friction We decide on +x right and +y up. Applying Newton's second law to these axes:
F−f=ma
P+F n −mg=0
where F=6.0 N and m=2.5 kg is the mass of the block.
(a) P=8.0 N in this scenario results inF N =(2.5kg)(9.8m/s 2 )–10N=14.5N.
This implies ,fs, max =μ s F N=6.6N, which is larger than the 6.0N rightward force. The block, which was previously at rest, stays in place as a result.
Putting a = 0
f=P=6.0 N is the static friction force that results from plugging the first of our equations above.
(b) With P=10 N in this instance, the normal force isThis suggests that, fs, max = s F N =5.8N, which is smaller than the 6.0 N rightward
force, which causes the block to move. Therefore, we are working with kinetic data instead of static data.
Eq. reveals that friction is f k = k F N =3.6 N.
(c) In the last scenario, P=12 N results in FN=12.5 N and fs, max = s F N = 5.0N.which (as expected) is less than the 6.0 N rightward force. Thus, the block moves. The kinetic friction force, then, is f k =μ k F N =3.1N.
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Using the principle of conservation of energy and the final height the golf ball reaches after bouncing, determine the theoretical speed with which the ball must have left the floor (i.e on its way back up).
Mass: 0.0453kg
Initial height: 1m
Initial potential energy: 0.444J
Final height: 0.61m
Final potential energy: 0.271J
Efficiency: 61.0%
Answer:
2.58 m/s
Explanation:
To determine the theoretical speed at which the golf ball must have left the floor, you can use the principle of conservation of energy, which states that the total energy in a closed system remains constant. In this case, we can use the fact that the ball's potential energy changes as it rises and falls.
First, we know that the efficiency of the ball is 61.0%, so we can assume that 39% of the energy is lost as heat, sound, etc. We can calculate the initial kinetic energy (Ei) of the ball as:
Ei = Efficiency * (Initial Potential energy - Final Potential energy)
Ei = 0.61 * (0.444 - 0.271) = 0.119J
Now, we can use this value to calculate the velocity (Vi) of the ball as it left the floor, by using the equation of kinetic energy:
Ei = 0.5 * m * Vi^2
Where:
m = mass of the ball = 0.0453 kg
Vi = velocity of the ball when it left the floor
By substituting the values in the equation we get:
0.119 = 0.5 * 0.0453 * Vi^2
Solving for Vi:
Vi = sqrt(0.119 / (0.5 * 0.0453))
Vi ≈ 2.58 m/s
So, the theoretical speed with which the ball must have left the floor is approximately 2.58 m/s
Keep in mind that this is a theoretical speed and there may be a variance with real-world observations.
600 Joules of work is used to lift a box from the ground to a height of six meters. How much work would have been done if a lever would have been used with an effort arm of 12 meters and a load
arm of 6 meters? († point)
O 50 J
O 100 J
O 600 J
0 72 J
The work that would have been done if a lever would have been used with an effort arm of 12 meters and a load arm of 6 meters is 50 J.
option A is the correct answer.
What is the work done by the lever?
A lever is a simple machine that makes work easier and faster. When a lever is used, a small effort will be used to overcome a large load.
The efficiency of a machine increases when the output force is greater than the input force.
Mathematically, the formula for the efficiency of a machine is given as;
Eff = ( output force / input force ) x 100 %
The output force is given by the following formula;
F ( out ) = load x distance moved by load
The input force is given by the following formula;
F ( input ) = effort x distance moved by effort
The work that would have been done if a lever would have been used with an effort arm of 12 meters and a load arm of 6 meters is calculated as;
work = ( 600 x 6 ) / ( 12 x 6 )
work = 50 J
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Answer:
600 J
Explanation:
The work is not equal to the initial work divided by the effort arm.
If it takes 4 hours for the Hogwarts express, moving at a speed of 100 mi/hr,to make it from Platform 9 and 3/4 to Hogwarts,how far apart are they?
The distance between Platform 9 and 3/4 and Hogwarts at a speed of 100miles/hour is 400miles.
What is distance?Distance is defined as an object's total movement with or without regard for direction. Distance can be defined as how much ground an object has covered regardless of its starting or ending point. Distance can be measured as Speed multiplied by Time.
If it takes 4 hours from Hogwarts express, at a speed of 100mi/hr to Platform 9 and 3/4 to Hogwarts, using the formula;
Distance = Speed x Time
Distance = 100 miles/hour x 4 hours
Distance = 400 miles
Therefore, the distance to platform 9 and 3/4 from Hogwarts express is 400 miles.
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A helicopter blade spins at exactly 120 revolutions per minute. Its tip is 3.00 m from the center of rotation. (a) Calculate the average speed (in m/s) of the blade tip in the helicopter's frame of reference. m/s (b) What is its average velocity (in m/s) over one revolution
94.32m/s is the average speed (in m/s) of the blade tip in the helicopter's frame of reference.
What is the typical blade tip speed, measured in metres per second, when viewed from a helicopter perspective?We discover that the sub average is 73.3 metres per second after entering this formula into our calculator and finding it to three significant numbers. The helicopter blade tip travels at an average speed of that.
How quickly does the blade tip typically move?After one revolution, the blade point has moved nothing since it goes back to its original position. The average velocity is consequently zero.
FPM = RPM x . 262 x Blade Diameter (inches).
FPM = 120 x . 262 x 3.00 = 94.32m/s
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calculate the kinetic energy of a 50 kg object that is moving at a speed of 12 m/s
Hello there!
Answer:
3600 J
Explanation:
[tex]E = \frac{mv^2}{2}[/tex]
So m = 50 kg and v = 12 m/s then
[tex]E = \frac{50 * 12^2}{2} J = 3600 J[/tex]
Mass = 50 kg
Velocity = 12 m/s
FindThe kinetic energy of an object.
SolutionThe formula that is used to find the kinetic energy of an object is given by :
[tex]K = \frac{1}{2}mv^{2} \\K = \frac{1}{2} X 50 X 12^{2} \\K = \frac{1}{2} X 50 X 144[/tex]
Answer= 3, 600 JA conducting bar moves along a circuit with a constant velocity. A constant magnetic field is perpendicular to the bar and circuit. The bar has covered 13.00 m2 of area by a certain time and then 15.60 m2 1.00 second later. The average EMF induced in the circuit over the 1.00 second time interval is 1.30 V. What is the strength of the magnetic field?
Answer:
0.500 T
Explanation:
Since the change in time and the number of coils are both 1, I set the problem up to be 1.3=(1.5(x)-13(x)). I then plugged in numbers for x until I got the answer to be 1.3 V.
what is the reading of the energy meter in figure 1 when an appropriate laser is used in pac to dissociate a particular chemical bond?
Because alkylbenzenes, phenols, and thiophenols all share an aromatic hydrocarbon constituent, the answer to this question is A.
Compounds 1 and 2 are both used to create liposomes, and their kinetics are controlled. Compound 1 are controlled kinetically, whereas those made from Compound 2 are controlled thermodynamically. UV lasers like nitrogen lasers (337 nm) and frequency-tripled and quadrupled Nd:YAG lasers are frequently used in MALDI methods (355 nm and 266 nm respectively). An artificial substrate for lactase is hydrolyzed to extract lactase from dietary supplement tablets, which is then measured using a colorimetric assay (ortho-nitrophenol-beta-D-galactopyranoside, ONPG). Because alkylbenzenes, phenols, and thiophenols all share an aromatic hydrocarbon constituent, the answer to this question is A.
The complete question is- What is the reading of the energy meter in Figure 1 when an appropriate laser is used in PAC to dissociate a particular chemical bond?
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ritmo al que cambia la velocidad
A 14 N force to the right keeps a 72 N normal force mass at constant
velocity on a horizontal surface. What is the coefficient of kinetic friction
between the surface and the mass?
The coefficient of kinetic friction between the surface and the mass is 0.1944.
What is kinetic friction?A force that acts between moving surfaces is referred to as kinetic friction. A force acting in opposition to the direction of a moving body on the surface is felt. The two materials' coefficient of kinetic friction will determine how much force is applied.
The ratio of the normal force to the kinetic friction force generated by contacting surfaces is known as the coefficient of kinetic friction.
Hence, The coefficient of kinetic friction between the surface and the mass is = 14 N/72 N
= 0.1944
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A bronze statue weighs 2400N. Its base is 4 meters in length and 1 meter wide. What is the statue's pressure on the floor?
Answer:
the pressure exerted by the bronze on the floor is 600 N/m²
Explanation:
Given;
weight of the bronze statue, F = 2400 N
width of the bronze base, w = 1 m
length of the bronze base, l = 4 m
The area of the bronze base = l x w
= 4 x 1
= 4 m²
The pressure exerted by the bronze on the floor is calculated as;
P = F/A
P = 2400/4
P = 600 N/m²
Therefore, the pressure exerted by the bronze on the floor is 600 N/m²
A girl travels along the circumference of a circle of radius 14 m. What is her total distance travelled and displacement when she has described half a circle, three fourth of a circle and full circle.
Answer:
87.976meters, 43.988 meters, 65.982 meters
Explanation:
Given data
Radius= 14m
Let us find the circumference of the circle
This is equivalent to the total distance covered
C= 2πr
C= 2*3.142*14
C= 87.976 meters
Hence the total distance is
87.976meters
The displacement when she has covered 1/2 the circle is
=87.976/2
=43.988 meters
The displacement when she has covered 3/4 the circle is
=87.976* 3/4
=65.982 meters
Why does acceleration increase down a ramp?
Acceleration increase down a ramp, due to an object is free to move under the influence of gravity. That's why acceleration increases.
Acceleration is a measure of how quickly an object's velocity changes. On a ramp, an object is free to move under the influence of gravity. The gravitational force acting on an object is always directed downward, and the force of friction acting on an object is directed upward. The force acting on an object moving down a ramp is the force of gravity minus the force of friction. Since the force of gravity is greater than the force of friction, the net force acting on the object is directed downward, which causes the object to accelerate downward. The angle of the ramp affects the force of friction, as the greater the angle of the ramp, the greater the force of friction, and the less the net force acting on the object and less acceleration. Therefore, acceleration increases down a ramp because the net force acting on an object is directed downward and the angle of the ramp affects the force of friction.
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The Law of Conservation of Energy states: Energy cannot be created or destroyed; it can be transformed fr
one form to another but the total amount of energy never changes. Car crashes can involve huge amounts
of energy. How does the crashworthiness of the car affect the transfer and transformations of energy and
ultimately, protect the occupants?
The kinetic energy does the work that crushes the car’s crumple zones.
Conversion of collision energy Because the metal plastic deformation after the impact greatly increases the internal energy of the automobile, the majority of the kinetic energy in the collision process is turned into internal energy. Other types of kinetic energy are turned into heat energy, sound energy, and so on.
A serious vehicle accident can result in PTSD, acute anxiety, sadness, and crippling phobias. According to studies, crash-related mental traumas might have symptoms that continue up to a year following a car accident, especially in youngsters. Objects with potential energy, or stored energy, collide, and the energy transfers to kinetic energy, or the energy of an object in motion. This energy transfer from one to anotheanother
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The heat of fusion of a substance is 42. 5 J/g. How much energy is released when 40 g of this substance at its freezing point completely changes into a solid? Show your work.
A. ) 1. 700
B. ) 1. 06
C. ) 42. 5
D. ) 0 J
The heat energy of the substance option (A) -1700J is correct.
We are given that,
Heat of fusion of a substance = ΔHf = 42.5J/g
Mass of the substance = m= 40g
The latent heat of fusion is the quantity of heat required to transform one gramme of a substance from a solid to a liquid. But in this case, it's important to figure out how much heat is released as liquid copper solidifies. So, ΔHf = -42.5 J/g
Thus , we have to calculated here the heat energy of the substance by the formula,
q = m·ΔHf
Where, q is heat energy ,m is mass ΔHf is the heat of fusion of a substance,
q = m·ΔHf
q = -42.5 J/g× 40g
q = -1700J
Therefore , the heat energy of the substance would be option (A) -1700J
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Lab motion
Table E: Average Speeds for Higher Racetrack
Time (Initial) |Time (Final) |Elapsed |Time |Average speed
| | | |
(s) (s) (s) (m/s)
1st ¼ of the Track
-------------------------------------------------------------------------------------------------------
2nd ¼ of the Track
-------------------------------------------------------------------------------------------------------
3rd ¼ of the Track
-------------------------------------------------------------------------------------------------------
Final ¼ of the Track
-------------------------------------------------------------------------------------------------------
R is the radius of speed curvature of the turn, g is the acceleration due to gravity, and μs is the coefficient of static friction.
θ is the angle of banking. For no slippage to occur even when the contribution of the frictional force in the centripetal force is not considered, we ignore the effect of friction and get the Time. Well, if the radius must be a single measurement, then the turn will be perpendicular.
While you're gathering necessary data, there's a discrepancy in your Average speed. Unless there are also tighter or unbanked turns, it's difficult to imagine the average speed=cornering speed.
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A person pushes a book against a wall so that the book does not move. a. Draw a free-body diagram for the book. Label the forces as you did in the tutorial Forces. b. For each force that appears on your free-body diagram, identify the corresponding force that completes the Newton's third law (or action-reaction) force pair.
Which statement best explains the path light takes as it travels? A. Light takes a curved path through matter and takes a straight path through space. B. Light moves in a straight line except at surfaces between different transparent materials, where its path bends. C. Light curves to spread out through openings and move around barriers.
Answer:
The answer is B
Explanation:
I took the test for k12 and the answer was "Light moves in a straight line except at surfaces between different transparent materials, where its path bends.
Hope this is helpful to anyone wondering what the answer is :)
The path which light takes as it travels is: B. light moves in a straight line except at surfaces between different transparent materials, where its path bends.
What is light?In Science, light can be defined as a form of electromagnetic wave that travels without any medium for its propagation. Also, light refers to a form of wave known as a visual signal because it can be seen with the eyes.
According to the model of light wave, the path which light takes as it travels is a straight line except when at surfaces between different transparent materials such as glass, where its path bends due to a phenomenon known as refraction.
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If a non-rotating object has no acceleration, then we can say for certain that it is A) in mechanical equilibrium. B) moving at constant non-zero velocity. C) at rest. D) all of the above E)none of the above
(A) in mechanical equilibrium is correct option, as there is no net force acting on it. A non-rotating object that has no acceleration can be said to be in mechanical equilibrium.
What is the definition of mechanical equilibrium?Mechanical Balance When all forces acting on an object of interest are equal to zero, mechanical equilibrium has occurred. The balance of all the forces must exist for this to occur.
What distinguishes mechanical equilibrium from static equilibrium?A reversible reaction is in a stable state called dynamic equilibrium when the rate of the forward reaction equals the rate of the backward reaction. The reaction has come to an end when there is static equilibrium, sometimes referred to as mechanical equilibrium. Or to put it another way, the system is idle.
Can mechanical equilibrium exist for an object in motion?When an object's acceleration is equal to zero, it is said to be in mechanical equilibrium. The object is either at rest with no change in position over time or it is traveling at a constant pace in this state. The net force acting on the object is equal to zero since the acceleration is zero.
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How do movement skills in square dancing transfer to ballroom dancing?
Answer:
Movement skills in square dancing transfer to ballroom dancing when they both require you to dance in a rhyme.
Explanation:
two objects gravitationally attract with a force of 36 N if the distance between the two objects centers is decreased by a factor of threee then the new force of attraction is
The new force of attraction is 324N if the distance between the centres of the two objects is reduced by a factor of 3e.
The equation for the force of gravitational attraction between two objects is: F = G*(m1*m2)/r^2 Where F is the force of attraction, G is the gravitational constant (6.67 x 10^-11 Nm^2/kg^2), m1 and m2 are the masses of the two objects, and r is the distance between their centers. If the distance between the two objects' centers is decreased by a factor of three, the new force of attraction will be: F' = G*(m1*m2)/(r/3)^2The ratio of the new force of attraction to the original force of attraction is:
F'/F = (r/3)^2 If we substitute in the original force of attraction, we have:
F'/36 = (r/3)^2 = F' = 36 * (r/3)^2
As we decrease the distance by a factor of 3, the new force of attraction will increase by a factor of 9.
F' = 36*9 = 324 N
Therefore, the new force of attraction is 324 N.
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You throw a ball vertically upward so that it leaves the ground with velocity 5. 68 m/s.
(a) What is its velocity when it reaches its maximum altitude? magnitude 0 Correct: Your answer is correct. M/s direction Incorrect: Your answer is incorrect.
(b) What is its acceleration at this point? magnitude -9. 8 Incorrect: Your answer is incorrect. The response you submitted has the wrong sign. M/s2 direction Incorrect: Your answer is incorrect.
(c) What is the velocity with which it returns to ground level? magnitude -5. 68 Incorrect: Your answer is incorrect. The response you submitted has the wrong sign. M/s direction Correct: Your answer is correct.
(d) What is its acceleration at this point? magnitude 9. 8 Correct: Your answer is correct. M/s2 direction Correct: Your answer is correct
The length of time needed to descend back to the earth's surface. Gravitational acceleration is equal to -9.8 m/s2. 2 s^2 s2
Explanation for the above answer:When anything is sent vertically upward, it slows down due to gravity. Up until it reaches a maximum height, where the velocity is zero, its speed is decreasing. After that, gravity accelerates it uniformly downward.
The three equations are as follows: v = u + at, v2 = u + 2as, and s = ut + 12at2.
What is the vertical velocity formula?With this knowledge, the vertical velocity formula, vf=vi+gt v f = v I + g t, can be used to calculate the object's terminal velocity. This equation is used by physicists to predict how any object will move on a vertical plane.
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Suppose that the railcar passes by a horn that is emitting a sound with frequency f. Which of the following describes the frequency f PS-10-1-prime.gif that the person on the railcar hears?
A. f PS-10-1-prime.gif > f before passing the horn, f PS-10-1-prime.gif < f after passing it
B. f PS-10-1-prime.gif < f before passing the horn, f PS-10-1-prime.gif > f after passing it
C. f PS-10-1-prime.gif = f before passing the horn, f PS-10-1-prime.gif = f after passing it
D. f PS-10-1-prime.gif > f before passing the horn, f PS-10-1-prime.gif > f after passing it
F PS-10-1-prime.gif > f before passing the horn, f PS-10-1-prime.gif < f after passing it describes the frequency f PS-10-1-prime.
Hence, Option A is correct.
The Doppler effect causes the frequency heard by the railcar passenger prior to passing the horn to be higher than the real frequency of the sound released, whilst the frequency heard after passing the horn is lower than the actual frequency. This is why the answer to this question is A. A railcar is a self-propelled passenger-carrying railroad vehicle. A train with a single coach and a driver's cab at one or both ends is typically referred to as a "railcar." Such vehicles are referred to as "railmotors" by several railway companies, including the Great Western.To know more about railcars here
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A naval navigator is using sonar to look for sunken cargo. The waves he is using have a frequency of 120
kHz and a wavelength of 3 mm. How far away is the cargo if the sound wave is emitted at exactly 9:24 a.m.
and returns to hit the ship's sensor 3 seconds later?
Answer should be in meters
The distance between the Naval Navigator and the sunken cargo was found to be 2175 m by using sonar with 120kHz frequency and a wavelength of 3mm.
What is the purpose of sonar?Sonar is largely used by NOAA scientists to create nautical charts, find underwater navigational hazards, find and map things on the bottom like shipwrecks, and map the actual seafloor. Sonar comes in active and passive varieties.
Speed of sound in water =1450m/s
Time lag between transmission and reception of Sonar waves =3 s
sound waves travel a distance is twice the distance between the navigator and cargo (2S) in this time lag.
Time taken for the sound to reach the submarine = 1/2 ×3 = 1.5s
Distance between the Navigator and the sunken cargo, S=1450×1.5s =2175m.
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find the numerical value of the density of a nucleus of atomic number A
Answer:
(A)²
Explanation:
Atomic mass = density*volume of atom.
So, density of nucleus is in depend of mass number
d=
3
4
πr
3
Massno.
=
3
4
π×[1.3×10
−13
×A
1/3
]
3
A
=constant∗A
0
as R=R
0
A
1/3
(R
0
=1.1×10
−15
m)
The numerical value of the density of a nucleus of atomic number A is determined as 2.29 x 10¹⁷ kg/m³.
Density of the nucleus
The density of the nucleus of atomic number A is calculated as follows;
ρ = m/V
where;
m is mass of the atom = 1.66 x 10⁻²⁷ kgr is radius of the atom = 1.2 x 10⁻¹⁵ m[tex]\rho = \frac{m}{V} \\\\\rho = \frac{m}{\frac{4}{3} \pi r^3} \\\\\rho = \frac{1.66 \times 10^{-27}}{\frac{4}{3} \pi (1.2 \times 10^{-15})^3} \\\\\rho = 2.29 \times 10^{17} \ kg/m^3[/tex]
Thus, the numerical value of the density of a nucleus of atomic number A is determined as 2.29 x 10¹⁷ kg/m³.
The complete question is below:
find the numerical value of the density of a nucleus of atomic number A with a radius of 1.2 x 10⁻¹⁵ m and mass of 1.66 x 10⁻²⁷ kg.
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Select the correct answer. what are you calculating when you measure the disorder of a system?
a. enthalpy
b. efficiency
c. entropy
d. energy
e. equilibrium
Therefore, entropy is the measure of the disorder of a system.
What is the measure of disorder in entropy?More specifically, the second law of thermodynamics asserts that "any isolated or closed system will always have an increasing (or at least constant) net entropy as time progresses." Entropy, which measures disorder, has an impact on every element of our daily life. The term "entropy" used in thermodynamics also refers to statistical entropy. It is a measurement of a substance's disorder at the molecular level that is aggregated and assessed at the macroscopic level. The kinetic energy of the substance is also measured by the entropy. The total amount of heat is measured by enthalpy. - Entropy is a metric used to express the degree of chaos. Both have to do with the rules of thermodynamics.To learn more about entropy refer to:
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¿A qué altura se podría haber elevado un cuerpo de 100 kilogramos de peso con esa misma energía? Rta=3673.5m
Respuesta:
3673.5m
Explicación:
Falta el dato de energía para poder resolver el problema pero vamos a suponer un dato para ver el procedimiento.
Supongamos que se emplean 3600030 J para elevar un cuerpo de 100 kg una cierta altura, aumentando su energía potencial. Los datos son:
Energía potencial (Ep): 3,600,030 JMasa del cuerpo (m): 100 kgGravedad terrestre (g): 9.8 m/s²Para calcular la altura alcanzada (h), podemos usar la siguiente fórmula.
Ep = m × g × h
h = Ep/m × g
h = 3,600,030 J/100 kg × 9.8 m/s² = 3673.5m