C. Explain why triangle PQR is isosceles. ​

Answer:

56

Step by step explanation:

[tex]62+x-x^2\\\\\text{When x = 3}\\\\62+3 -3^2 = 62+3-9 = 65-9 = 56[/tex]

Model mural::

L*W = 0.3 sq. ft

--------------

Actual mural::

(5L)(5W) = 25*LW = 25*0.3 = 7.5 sq ft.

Answer:

the remNING MAS IS 345

Step-by-step explanation:

I DID THIS BEFORE

Answer:

39.37 in

Step-by-step explanation:

Answer:

530 m²

Step-by-step explanation:

First of all we need to label the missing sides ,please check the figure I provided for that :

x = 37 - (10+ 15) = 37 - 25 = 12

z = 10

y = 2 × 10 = 20

The shade does area = area of the whole rectangle − the white area

                                    = 37 × 20 − [ (15×20)÷2 + (10×12)÷2 ]

                                    =  740      − [    150        +      60       ]

                                    = 740.      −               210

                                    = 530

Answer:

Can you help me............. In my question

Answer:

-1

Step-by-step explanation:

g(2) = (2) - 3(2) + 4(2) - 5

g(2) = 2 - 6 + 8 - 5

g(2) = 2 - 6 + 3

g(2) = 2 - 3

g(2) = -1

Answer:

Odd: f(-x) = -f(x)

Step-by-step explanation:

Odd: f(-x) = -f(x)

f(-1) = 5

-(f(1)) = 5

Answer:

d

Step-by-step explanation:

I got it right on the test

Step-by-step explanation:

quotient is a result of the number

divided by a number

and if u want to divided with zero so division are not exis

can't divided by 0

Answer:

173 degrees

Step-by-step explanation:

we know AED + AEB + BEC + CED = 360

AEB = 112

to find BEC, we have B + BCE + BEC = 180 because they form a triangle. so BEC = 180 - B - BCE = 180 - 73 - 79 = 28

to find CED, follow the same steps as BEC: 180 - 37 - 96 = 47

now AED = 360 - AEB - BEC - CED = 360 - 112 -  28 - 47 = 173

I'(-4, -3)     J'(-4, -2)

K'(-2, -2)     L'(0, -4)    

[tex]I(0,-3)\rightarrow I'(0-4,-3)\rightarrow I'(-4,-3)\\ J(0,-2)\rightarrow J'(0-4,-2)\rightarrow J'(-4,-2)\\ k(2,-2)\rightarrow k'(2-4,-2)\rightarrow k'(-2,-2)\\ L(4,-4)\rightarrow L'(4-4,-4)\rightarrow L'(0,-4)\\ \{Conversion\ principle\}[/tex]

I hope this helps you

:)

Answer:

answer recent question of my pr.ofil.e

Answer:

x ≥ -1

Step-by-step explanation:

Hello!

Solve for x by isolating the variable.

The inequality is true for all values of x greater than or equal to -1.

PEMDAS

Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS. PEMDAS is the order of operations, and stands for:

Parenthesis, Exponents (& Roots), Multiplication, Division, Addition, Subtraction.

First, divide 3 from both sides of the equation:

[tex]\frac{(3x^2)}{3} = \frac{(48)}{3}[/tex]

[tex]x^{2} = \frac{48}{3}\\ \\x^2 = 16[/tex]

Next, isolate the variable, x, by rooting both sides of the equation:

[tex]\sqrt{x^{2} } = \sqrt{16}\\ x = \sqrt{16} = \sqrt{4 * 4}[/tex]

x = ±4

C) ±4 is your answer.

~

Step-by-step explanation:

given :

h = 50 ft

the angle if elevation , a = 50°

find :

the distance , d =?

the answer:

tan a = h/d

d = h /tan a

= 50/ tan 50°

= 50 / 1,19

= 42,02 ft

Let's see

The linear equation that shows the total number of square yards refinished after x weekdays is given by:

y = 10 + 8x.

A linear function is modeled by:

y = mx + b

In which:

In this problem:

Thus, the equation is given by:

y = 10 + 8x.

More can be learned about linear equations at https://brainly.com/question/24808124

Answer:

Give options :/

Step-by-step explanation:

Answer: False

Step-by-step explanation:

The lower case letter denotes a relation, not a function

Answer: Reflection across the y-axis

Step-by-step explanation:

A reflection over a y-axis means that the original point (x, y) becomes (-x, y)

The original point (-2, 1) should become (-(-2), 1) which becomes just (2, 1).

(2, 1) is the reflected point hence it is a reflection across the y-axis

Answer:

a= 28.27

Step-by-step explanation:

[tex]a=\pi r^2[/tex]

[tex]a=\pi 3^2\\a=28.27[/tex]

Answer:

WFF

Step-by-step explanation:

savoy..it's me Wolfie it's been so long, I really hope you remember me...

Answer:

800 bacteria

Step-by-step explanation:

Answer of this question depend upon number of hours at the end of day

Let Take Full Day of 24 hrs

Colby bacteria will doubled 12 times ( doubled once in 2hrs => 24/2 = 12)

Colby bacteria at end of day = 50 * 2¹²

Jaquan bacteria will doubled 8 times ( doubled once in 3hrs => 24/3 = 8)

Let say Jaquan bacteria at start  of Day = J

Jaquan bacteria at end of day = J * 2⁸

Equating Both

J * 2⁸ = 50 * 2¹²

=> J = 50 * 2⁴

=> J = 50 * 16

=> J = 800

Jaquan will start  with 800 Bacteria

Answer:

x=-50

Step-by-step explanation:

I used the method of balancing equations:

Add -40x to both sides

-38x+43 + 40x = -40x-57+40x

Simplify:

2x+43 = -57

Subtract 43 from both sides:

2x+43 -43 = -57 -43

Simplify:

2x =  -100

Solve for x

2x÷2 = -100÷2

x = -50

Hope this helped and brainliest please

Answer:

Step-by-step explanation:

In this question we have given an equation that is -38x + 43 = -40x - 57 . And we have to find the solution of this question that means we have to find the value of x .

So let's start our Solution : -

[tex] \hookrightarrow \: -38x+43=-40x-57 [/tex]

Step 1 : Subtracting 43 on both sides :

[tex] \hookrightarrow \: \: - 38x + \cancel{43} - \cancel{43 }= - 40x - 57 - 43[/tex]

On calculating further , We get :

[tex] \hookrightarrow \: - 38x = - 40x - 100[/tex]

Step 2 : Adding 40x on both sides :

[tex] \hookrightarrow \: - 38x + 40x = - \cancel{40x} - 100 + \cancel{40x}[/tex]

On calculating further , We get :

[tex] \hookrightarrow \:2x = - 100[/tex]

Step 3 : Dividing by 2 on both sides :

[tex] \hookrightarrow \: \frac{ \cancel{2}x}{ \cancel{2} } = \cancel \frac{ - 100}{2} [/tex]

On calculating further , We get :

[tex] \hookrightarrow \: \purple{\boxed{\frak{x = - 50}}}[/tex]

Verifying : -

Now we're verifying our answer by substituting value of x in given equation . So ,

Therefore , our solution is valid .

Answer:

the total mass of the products is equal to the total mass of the reactants

Step-by-step explanation:

The sum of the relative formula masses of the reactants is equal to the sum of the relative formula masses of the products.