a horizontal of 5 n is required to maintain a velocity of 2m/s for a block of 10kg​

The acceleration of the snowboarder is 0.466 m/s².

Acceleration is the rate of change of velocity.

To calculate the acceleration of the snowboarder, we use the formula below.

Formula:

Where:

From the question,

Given:

Susbtitute these values into equation 1

Hence, the acceleration is 0.466 m/s².

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Answer:

c. more redder

def not blue cuz thats hottest and def not luminous

Answer:

it is c... redder

Explanation:

because i just look it up on googl3

Answer:

ahhahsvdjdjkd

Explanation:

sbnwtauajababcahajanavgzuz

Answer: A) as speed changes, wavelength changes and frequency remains constant

Explanation: edg test

Answer: it always opposes the directions of motion is the right answer

Explanation:

Answer:

B.KEEN EYESIGHT thats for predators !

Explanation:

Herbivores have multiple stomachs to process tough foods, coats to blend in so they don't get eaten, and tough teeth for chewing on the plants. THEY DO NOT HAVE PREY, THEY ARE THE PREY.

Answer:

d= -2

Explanation:

t=5s

S=100 meters

V= 10 m/ s

d=?

deceleration = (final velocity - initial velocity) / time. d = (vf - vi)/t.

The formula for acceleration can be used, recognizing that the final result must have a negative signe.

d= (0-10)/5

d= -2

Answer: A. The Sun

Explanation: A. The Sun makes water move through the water cycle

Answer:

the f is 1.3 m

Explanation:

Given that

An object 2.0m is from the concave mirror

And, the image is 4.0m from the mirror

We need to find out the f

So,

u = -2 m

v = -4 m

1 ÷ f = 1 ÷ v + 1 ÷ u

= (-1 ÷ 4) + (-1 ÷ 2)

= -3 ÷4

f = -4 ÷ 3

= |1.3| m

Hence, the f is 1.3 m

Answer:

ii. N

Explanation:

N is not laterally symmetrical. so it shows inversion in a mirror.

Answer:

ii) N

hope it is helpful to you

If deceleration = 5 m/s²

then acceleration = -5 m/s²

According to third law of motion,

= v² = 2as + u²

= v² = 2×-5×10 + 27²

= v² = -100 + 729

= v =√ 629

= 25.08 m/s

Answer:

a) capacitance is doubled., b)  Q = cte, c) oltage doubling the distance doubles, d)    ΔE =0, e)  U = Q² / 2C, f) W>0

Explanation:

he capacitance of a condensate is

          C =[tex]\frac{ Q}{ \Delta V} =\epsilon_o \frac{A}{d}[/tex]

let's use this expression to answer the question

a) Capacitance.

Without distance, the capacitance is doubled.

Answer: Half

b) The charge.

As the battery is disconnected, no more electrons reach the capacitor, so the charge remains the same

           Q = cte

c) the voltage

          ΔV = E d = ([tex](\frac{Q}{\epsilon_o A}) \ d[/tex]

so the voltage doubling the distance doubles

d) The electric field between parallel plates is constant

           E = Q / A eo

           E =0

e) The stored energy is described by the expression

          U = Q² / 2C

as capacitance decreases and discant increases, stored energy increases

f) The work to separate the positive charge, that the force must be in the same direction as the electric force

g) when the battery is disconnected the energy in the capacitor remains constant

Answer: [tex]0.1066\ psi, 15.611\ kN[/tex]

Explanation:

Given

the height of the tank is [tex]h=10\ cm[/tex]

The diameter of the tank is [tex]d=520\ cm[/tex]

Density of solution [tex]\rho=0.75\ g/cm^3\ or\ 750\ kg/m^3[/tex]

[tex](a)[/tex] Water pressure at the bottom of the tank is

[tex]P=\rho gh\\P=750\times 9.8\times 0.1\\P=735\ Pa[/tex]

[tex]1\ Pa=0.000145038\ psi[/tex]

[tex]\Rightarrow P=735\ Pa\ or\ 0.1066\ psi[/tex]

[tex](b) \text{Average force on the bottom is the product of pressure and area of the base}[/tex]

[tex]F_{avg}=735\times \pi \cdot (\frac{520}{200})^2\\\\F_{avg}=735\times 3.142\times 6.76\\F_{avg}=15,611.34\ N\ or\ 15.611\ kN[/tex]

Answer:

666.7 W

Explanation:

Power = P = W/t = 4000 J/6 s = 666.7 W (watts)

Answer:

the  correct  answers B

It needs to be moving horizontally at a high speed, in order for the satellite to stay in orbit once it's released from the rocket.

Explanation:

In this exercise, let's look for the solution to the problem before reviewing the statements to find out which one is correct.

When the satellite is in orbit it must comply with Newton's law

          F = m a

the force of the universal attractive force and the acceleration is centripetal

          a = v² / r

we substitute

         - G m M /r² = -m v² / r

            v² = G M / r

            v = [tex]\sqrt{\frac{GM}{r} }[/tex]

When analyzing this expression, the satellite is in a stable orbit because its centripetal acceleration creates a change in the direction of the velocity in such a way that it remains in an orbit

when reviewing the  correct  answers B

The shape of the coastlines and the slope of the ocean floor, as well as the gravitational pull of the Sun and Moon, all have an impact on the tides of the ocean.

Tides are extremely long-period waves that travel across the water as a result of the moon's and the sun's gravitational pull. The rise and fall of the sea's surface on a regular basis is what tides, which originate in the ocean, appear as as they move toward the coastlines.

High tide is when the wave's highest portion, or crest, reaches a specific area; low tide is when the wave's lowest portion, or trough, reaches that location. The term "tidal range" refers to the height difference between high tide and low tide.

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Answer:

Therefore The hypothesis is not plausible Because

[tex]P.E \geq P.E_e[/tex]

[tex]P.E=12.435*10^{-5}J \geq 1.4*10^{-7}J[/tex]

Explanation:

From the question we are told that:

Mass [tex]M=0.45mg[/tex]

Jump height [tex]h=3.5cm \approx 0.03m[/tex]

Percentage strain [tex]\mu =100\%[/tex]

Generally the equation for potential energy is mathematically given by

[tex]P.E=mgh[/tex]

[tex]P.E=0.45*10^{-3}*9.8*0.03[/tex]

[tex]P.E=12.435*10^{-5}J[/tex]

Generally the equation for Elastic potential energy is mathematically given by

[tex]P.E_e=0.5*stress*strain *volume[/tex]

[tex]P.E_e=0.5*1*2*10^6*1*1.4*10^{-4*(10^-3)^3}[/tex]

[tex]P.E_e=1.4*10^{-7}J[/tex]

The hypothesis is only plausible at conditions where

[tex]P.E\leq P.E_e[/tex]

Therefore The hypothesis is not plausible Because

[tex]P.E \geq P.E_e[/tex]

[tex]P.E=12.435*10^{-5}J \geq 1.4*10^{-7}J[/tex]

The total work done by this force is 28.9-1457.86 N m.

Total work is the sum of all the energy expended in completing a job or task. It is the amount of effort and energy expended to accomplish a goal or complete a task. Total work can be calculated by adding up all of the individual components of the job or task, such as time, effort, and materials.

The total work done by this force can be calculated using the formula W = F * Δx, where F is the force vector, and Δx is the displacement vector. In this case, the total work done is:
W = (4.70-379, 2.09) * (4.25, 3.69-245) = (19.9-944.81, 8.00-513.05) N m
Therefore, the total work done is 28.9-1457.86 N m.

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Answer:

24.4

Explanation:

you would add all the numbers , 25.5+24.4+24.2= 73.1/3=24.36 and you round up you get 24.4

Answer:

-0.0069 rad/s

Explanation:

The change in angular velocity of the rod can be determined by using the conservation of angular momentum equation: Lf = Li.

The initial angular momentum of the rod is Li = Iwo and the final angular momentum of the rod is Lf = Iwf.

Plugging in the given values, we get:

(1.05 x 10^-3 kg•m^2)(0.606 rad/s) + (5 x 10^-3 kg)(0.609 m)^2(wf) = (1.05 x 10^-3 kg•m^2)(wo).

Solving for wf, we get wf = -0.0069 rad/s.

Therefore, the change in angular velocity of the rod is -0.0069 rad/s.

Answer:

A. 9.203 × 10⁻¹⁰ kg

B.  2.82 × 10¹⁰ V/m

C. 5.56 × 10³ V/m

Explanation:

A. Calculate the mass (in kg) of the hovering droplet if its radius is measured to be 65 um.

We know density, ρ = mass of oil drop, m/volume of oil drop, v

m = ρv

ρ = 800 kg/m³ and v = 4πr³/3 (ince the oil drop is a sphere) where r = radius of oil drop = 65 μm = 65 × 10⁻⁶ m.

So, m = ρv = ρ4πr³/3

= 800 kg/m³ × 4π(65 × 10⁻⁶ m)³/3

= 800 kg/m³ × 4π274625 × 10⁻¹⁸ m³/3

= 878800000π × 10⁻¹⁸ kg/3

= 2760831623.97 × 10⁻¹⁸ kg/3

= 920277207.99 × 10⁻¹⁸ kg

= 9.203 × 10⁻¹⁰ kg

B. Calculate the electric field (in V/m) required to counter the weight of the above droplet if it carries a charge q = 2e.

Since the electric force F = qE where q = charge on oil drop  = 2e where e = electron charge = 1.602 × 10⁻¹⁹ C and E = electric field equals the weight of the oil drop W = mg where m = mass of oil drop = 9.203 × 10⁻¹⁰ kg and g = acceleration due to gravity = 9.8 m/s².

So, F = W

qE = mg

E = mg/q

E = mg/2e

substituting the values of the variables into the equation, we have

E = 9.203 × 10⁻¹⁰ kg × 9.8 m/s²/(2 × 1.602 × 10⁻¹⁹ C)

E = 90.1894 × 10⁻¹⁰ kg-m/s²/3.204 × 10⁻¹⁹ C

E = 28.15 × 10⁹ V/m

E = 2.815 × 10¹⁰ V/m

E ≅ 2.82 × 10¹⁰ V/m

C. In the second trial, the hovering droplet has a mass of 10-15 kg. It carries a charge of q = 11e. calculate the electric field (in V/m) required to counter the weight of this droplet.

Since F = W

qE = mg

E = mg/q

E = mg/11e

E = 10⁻¹⁵ kg × 9.8 m/s²/(11 × 1.602 × 10⁻¹⁹ C)

E = 9.8 × 10⁻¹⁵ kg-m/s²/17.622 × 10⁻¹⁹ C

E = 0.556 × 10⁴ V/m

E = 5.56 × 10³ V/m

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The following which is not a safety tip for outdoor activities is to go alone for a sense of oneness with nature and is therefore denoted as option A.

This is referred to as the condition of being protected from harm or other danger and it involves the use of various methods and activities and an example is to ensure that a  basic first aid kit is available so as to help in the incident of an injury.

However going alone for a sense of oneness with nature is not a safety tip as should in case any issue arises there will be no one to support and rescue such individual.

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The full question is:

Which of the following is not a safety tip for outdoor activities

a. go alone for a sense of oneness with nature

b. bring a basic first aid kit

c. bring a flashlight or headlamp

d. pack plenty of water and energy-dense food

To solve this we must be knowing each and every concept related to interval. Therefore, values of the displacement of the string at x = 5.0 m at 1 s intervals from t = 0 s to t = 6 s can be listed as below.

An interval is any set of numbers that fall between two distinct integers. This range includes all real values that fall between those two. All real numbers that lie in any 2 of a set's numbers are collectively referred to as an interval within mathematics.

For instance, the set of integers x fulfilling 0 x 1 is the interval consisting of 0, 1, and all numbers in between. a snapshot graph of wave on a string moving toward one another at 1 m/s at time t = 0 s.

At time t = 0,Y₀= 0 cm

At At time t =1, Y₁= 0 cm

At time t = 2, Y₂= 0 cm

At time t =3, Y₃= 0 cm

At time t =4, Y₄= 0 cm

At time t = 5 ,Y₅=0 cm

At time t = 6, Y₆= 0 cm

Therefore, values of the displacement of the string at x = 5.0 m at 1 s intervals from t = 0 s to t = 6 s can be listed as above.

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Thus the electric field at the fourth corner of the square of side L is E4 = kQ.[2/a² + 1/a√2].

Electric field strength is a quantitative expression of the intensity of an electric field in an electric circuit at a particular location and time. The standard unit of the electric field strength is the volt per meter (V/m or V·m⁻¹). An electric field strength of 1 V/m represents a potential difference of about 1V between the two points which are separated by 1 meter distance.

We are given that:

Number of point charges = 3

Here, we shall use the superposition principle to calculate the net electric field at the fourth point, so

E4 = E1 + E2 + E3

E4 = kQ/a² + kQ/√(2a²) + kQ/a²

E4 = kQ [1/a² + 1/√(2a²) + 1/a²]

Thus the electric field at the fourth corner is  E4 = kQ [2/a² + 1/a√2].

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Answer:

the answer is c

Explanation:

melting = become liquefied by heat

solubility = a new bond formation

conductivity = electric transmitter

flammability = burnable

Answer:

The difference between mass and weight is that mass is the amount of matter in a material, while weight is a measure of how the force of gravity acts upon that mass.

Explanation:

Answer: Negative punishment includes taking away a certain reinforcing item after the undesired behavior happens in order to decrease future responses. Positive punishment involves adding an aversive consequence after an undesired behavior is emitted to decrease future responses.

HOPE THIS HELPS

SUKHMANJOT

Answer:

Node:-

A node is a point along a standing wave where the wave has minimum amplitude. For instance, in a vibrating guitar string, the ends of the string are nodes. By changing the position of the end node through frets, the guitarist changes the effective length of the vibrating string and thereby the note played.

Anti Node:-

An antinode is simply a point along a medium which undergoes maximum displacement above and below the rest position.

Wavelength:-

The total length of circle.

or

Wavelength can be defined as the distance between two successive crests or troughs of a wave.