A 1,000 kg truck is traveling at 3 m/s. Suddenly, the driver sees a herd of cows on the road ahead and applies the brakes. The truck's tires could fail after doing 5,000 J of work to slow the vehicle. Can the truck stop before the tires fail?


A. Yes, the total KE the tires need to transfer out of the system is less than 5,000 J.


B. Yes, the tires do not do any work, it is only the brakes that do work.


C. No, the truck had to stop suddenly and the quick change in KE will cause the tires to fail.


D. No, the total KE the tires need to transfer out of the system is more than 5,000 J.

Answers

Answer 1

This question involves the concepts of the law of conservation of energy and kinetic energy.

The correct option is "A. Yes, the total KE the tires need to transfer out of the system is less than 5,000 J".

According to the law of conservation of energy:

Loss in Kinetic Energy = Work done by the tires

[tex]\frac{1}{2}mv^2=W[/tex]

where,

W = work done by tires = ?

m = mass of the truck = 1000 kg

v = speed of the truck = 3 m/s

Therefore,

[tex]W=\frac{1}{2}(1000\ kg)(3\ m/s)^2[/tex]

W = 4500 J

Since the failure limit of work done by the tire is 5000 J, which is greater than the actual work done by the tire in this scenario. Hence, the tire will not fail in this case.

Learn more about the law of conservation of energy here:

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The attached picture explains the law of conservation of energy.

A 1,000 Kg Truck Is Traveling At 3 M/s. Suddenly, The Driver Sees A Herd Of Cows On The Road Ahead And

Related Questions

PLEASE ANSWER ASAP
A 5 kg bowling ball traveling at 2 m/s hits a motionless 10 kg bowling ball. If the smaller ball bounces back at a speed of -1 m/s, what will be the speed of the larger ball after the collision?

Answers

Hi there!

Recall the conservation of momentum:

m1v1 + m2v2 = m1v1' + m2v2'

Let m1 = 5 kg ball and m2 = 10 kg ball

Since m2 is at rest, we can rewrite:

m1v1 = m1v1' + m2v2'

Plug in the given values:

5(2) = 5(-1) + 10v2'

Solve for v2':

10 = -5 + 10v2'

15 = 10v2'

15/10 = 1.5 m/s

Given ↷

m1 =5kgm2=10( since it's at rest)v1=2m/sv2=0(since it's at rest)v1' = -1To find ↷the speed of the larger ball after the collisionSolution↷

We know that,

m1v1 + m2v2 = m1v1' + m2v2'

5 x 2 + 0 = 5 x -1 + 10 x v2'

10= -5 +10 x v2'

15 = 10 x v2'

v2' = 15/10

v2' = 1.5 m/s

hence , the speed of the larger ball after the collision will 1.5m/s

In which of the cases below is friction most helpful?

A.

between a moving box and a ramp

B.

between car tires and a road

C.

between a person and a playground slide

D.

between ice skates and an ice rink

Answers

Answer:

between car tires and a road

Explanation:

What kind of feature results from the convergence of two oceanic plates?
A.
island arcs
B.
massive continental volcanoes
C
rift valleys
D.
tall mountain ranges

Answers

Answer:

A

Explanation:

Convergence is pushing them together so C is out of the question.

B and D are wrong because it is an oceanic plate. B and D are for continental plates.

Terri is excited about the baby she is carrying in her womb. One day, she tells her
cousin that the child is now the size of a grape. Weeks later, she describes the child as
the size of an apple. A few weeks after that, she describes the child as the size of a
banana. "Seriously, Terri, are you having a baby or shopping for groceries?" asks her
cousin. Terri explains that this is just the easiest way to describe the size of the baby
now that it is a(n)
Zygote
O Fetus
O Embryo
Infant

Answers

Answer:

Fetus

Explanation:

the outsiders I got nuggets out of the elder and I get to make it in and I got I got

• What net force is needed to accelerate a 1200 kg car along a
horizontal surface from rest to 130 km/h in 80 seconds?

Answers

Hi there!

We can begin by converting 130 km/h to m/s:

[tex]\frac{130km}{1hr} * \frac{1hr}{3600s} * \frac{1000m}{1km} = 36.11 m/s[/tex]

Find the acceleration associated with this velocity change in the given time frame:

vf = vi + at (vi = 0 m/s)

vf = at

vf/t = a

36.11/80 = 0.45 m/s²

Now, we can calculate Net Force using Newton's Second Law:

∑F = ma

∑F = (1200)(0.45) ≈ 540 N

What is meant by collisions?

Answers

Answer:

come into conflict or opposition.

"in his work, politics and metaphysics collide

Answer:

It could mean, “an instance of one moving object or person striking violently against another.”

If F = 4.0 N and m = 2.0 kg, what is the magnitude a of the acceleration for the block shown below? The surface is frictionless. *

Answers

Since f=ma when f=4.0 and m=2.0 so the magnitude of acceleration for the block is 2.0m

The magnitude of the acceleration of the block is 3.5 [tex]\bold{m/s^2.}[/tex]

The correct option is (C) 3.5 [tex]\bold{m/s^2.}[/tex]

What do you mean by acceleration?

Acceleration is the rate of change of velocity with time.

By Newton’s Second law

This law establishes the relationship between the net applied force on an object with the resultant acceleration. For a constant magnitude of force, the more is the mass of the object, the lesser will be its acceleration.

Given,

The mass of the block is 2.0 kg.

The force in the horizontal direction on the block is [tex]\bold{4.0 N + 4.0 N \cos 40{}^\circ.}[/tex]

a is the acceleration in the horizontal direction.

The acceleration for the block can be determined using Newton’s Second law,

[tex]\begin{aligned} \Sigma F&=ma \\ F+F\cos 40{}^\circ &=ma \\ a&=\frac{F\left( 1+\cos 40{}^\circ \right)}{m} \\ &=\frac{4.0\text{ N}\left( 1.766 \right)}{2.0\text{ kg}} \\ &=3.5\text{ m/}{{\text{s}}^{2}} \end{aligned}[/tex]

Thus, the acceleration is 3.5 [tex]\bold{m/s^2.}[/tex]

Learn more about acceleration, here:

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1 Loudness and pitch are two important properties of a musical sound.
a If a musician plays a softer note, which property has been changed,
loudness or pitch?
b If the musician makes the note lower, which property has been
changed, loudness or pitch?

Answers

pitch loudness is with you lower you tone & get quite

Gas sample A has a mass of 32.00 grams. Gas sample B has a mass of 28.00
grams. If the two gas samples are both at 25°C, which sample has the greatest
average kinetic energy?

Answers

Answer:

I think 32.00

Explanation:

Because the equation is mass times velocity so is you mutiply 32 by 25 and 28 times 25 sample A would be greater.

The sample with the greatest average kinetic energy is sample A

The average kinetic energy of a sample can be estimated by the formula one-half of the mass sample multiplied by the speed (RMS) squared.

Mathematically, we have:

[tex]\mathbf{K.E_{avg} = \dfrac{1}{2}mv_{rms}^2}[/tex]

If the mass of sample A = 32.00 grams, andThe mass of sample B = 28.00

Provided that the speed (RMS) is constant, the average kinetic energy of sample A will be greater than the average kinetic energy of sample B because sample A has a greater mass than sample B.

Learn more about average kinetic energy here:

https://brainly.com/question/13868723

Please help thank you!

Answers

Answer:

mass, weight

Explanation:

mass is constant, and weight is dependant on your location

Answer:

I think d

Explanation:

because distance j

has to be the last one that's the only one with distance

Two cars a and b are moving along a straight road in the same direction with velocities of 25km/h and 40km/h . Find the velocity of car b relative to car a

Answers

Please find attached photograph for your answer.

Hope it helps.

Do comment if you have any query.

A tennis ball thrown with a velocity of 25m/s[Fwd] in the horizontal direction from the top of an 80m high building.
1. How long does it take the tennis ball to reach the ground?
2. How far is the range (how far from the base of the building will the ball land) ?
3. What is the final velocity?
Even answering one will help me out and i will give brainlest!

Answers

Answer:

Explanation:

Ignoring air resistance

1) from vertical rest

s = ½at²

t = √(2s/a)

t = √(2(80)/9.8)

t = 4.040610...

t = 4.0 s

2) d = vt

   d = 25(4.0)

   d = 100 m

3) v² = u² + 2as

   v² = 25² + 2(9.8)(80)

   v² = 2193

   v = 46.8294...

    v = 47 m/s

θ = - 90 + arcsin(25/46.8294)

θ = -57.7339...

θ = 58° below the horizontal

how can the motion of an object that is already moving change?

Answers

Answer: A force can change the direction in which an object is moving

Explanation: A bigger force of an object will produce a bigger change in motion

URGENT NEED GIVING POINTS question is how do i find R and the angle THANK YOU

Answers

Answer:

Theta = 26.93°

R = 0.38m

Explanation:

Theta = cos^-1(0.74m/0.83m)

Theta = 26.93°

R = sqrt(0.83²-0.74²)

R = 0.38m

what is the full meaning of hip​

Answers

Answer:

History in Perspective (education) HIP. Health Information Professional. HIP.

Explanation:

hope this helps

What is the potential energy of a 2 kg bowling ball resting at the top of a 5 m high hill? Show all of your work and include the correct units to receive full credit.​

Answers

Answer:

[tex]\boxed {\boxed {\sf 98 \ J}}[/tex]

Explanation:

We are asked to find the potential energy of a bowling ball.

Potential energy is the energy an object possesses due to its position. It is calculated using the following formula.

[tex]E_p= mgh[/tex]

In this formula, m is the mass, g is the acceleration due to gravity, and h is the height.

The bowling ball has a mass of 2 kilograms. The hill is 5 meters high. Assuming this situation is occurring on Earth, the acceleration due to gravity is 9.8 meters per second squared.

m= 2 kg g= 9.8 m/s²h= 5 m

Substitute the values into the formula.

[tex]E_p= (2 \ kg )(9.8 \ m/s^2)(5 \ m)[/tex]

Multiply the numbers together.

[tex]E_p=19.6 \ kg*m/s^2(5 \ m)[/tex]

[tex]E_p=98 \ kg*m^2/s^2[/tex]

Convert the units. 1 kilogram meter squared per second squared is equal to 1 Joule. Our answer of 98 kg*m²/s² is equal to 98 Joules.

[tex]E_p= 98 \ J[/tex]

The bowling ball has 98 Joules of potential energy.

A piece of wood has a mass of 8g and a volume of 10cm³. Work out the density of the wood in /3 .
no links please just explain how you got the answer.​

Answers

Answer:

8×10^-3÷10×10^-6=8×10^2=800 kg/m^3

Answer:

2.4/3

Explanation:

first we make 8g/10cm then 0.8 so the only number that can fit for /3 is 2.4

hope helped!

a person walks 9 meters to the right and 8 meters to the left what's the distance and displacement​

Answers

the distance is 17 and the displacement is 1

Answer:

walked: 17 meters

displacement: 1

Explanation:

so you add 9+8 and the displacement is 1 b/c when you moved back those 8 meters you were still 1 meter away from where you where originally standing

true and false? When an object remains stationary, any forces acting on it must be balanced.

Answers

Answer:

Balanced forces acting on a stationary object cause the object to remain at rest. True: Forces can give energy to an object it acts on causing the object to change it state of motion. If forces acting on an object are balanced, they do not cause a change in motion.

Answer:

False

Explanation:

It is NOT possible for just three forces to be acting upon an object and they still balance each other. A free-falling object experiences a balance of forces.

A small ball is attached to one end of a spring that has an unstrained length of 0.201 m. The spring is held by the other end, and the ball is whirled around in a horizontal circle at a speed of 3.41 m/s. The spring remains nearly parallel to the ground during the motion and is observed to stretch by 0.0176 m.

Required:
By how much would the spring stretch if it were attached to the ceiling and the ball allowed to hang straight down, motionless?

Answers

The extension of the spring when the ball is allowed to hang straight down, motionless is 0.0032 m.

The given parameters;

unstrained length, l₁ = 0.201 mextension of the string, x = 0.0176 mspeed of the ball, v = 3.41 m/s

The radius of the circular path when spring is stretched is calculated as;

R = l₁ + x

R = 0.201 + 0.0176

R = 0.2186 m

The spring constant is calculated as follows;

[tex]F = ma\\\\Kx = \frac{mv^2}{R} \\\\K = \frac{mv^2}{Rx} \\\\K = \frac{(3.41)^2 m}{0.2186 \times 0.0176} \\\\K = 3,022.4 m \ N/m[/tex]

The extension of the spring when the ball is allowed to hang straight down, motionless;

[tex]F = mg\\\\Kx=mg\\\\x = \frac{mg}{K} \\\\x = \frac{9.8 m}{3022.4 m} \\\\x = 0.0032 \ m[/tex]

Thus, the extension of the spring when the ball is allowed to hang straight down, motionless is 0.0032 m.

Learn more here:https://brainly.com/question/15589287

the small lightweight particles outside the nucleus of an atom are called___.​

Answers

The neutron has no charge, and a mass of slightly over 1 amu. Some scientists propose the neutron is made up of a proton and electron-like particle. The electron is a very small particle located outside the nucleus.

Electron: -1

Neutron: 0

Proton: +1

What is Space debris ?

Answers

Answer:

Space junk, or space debris, is any piece of machinery or debris left by humans in space. It can refer to big objects such as dead satellites that have failed or been left in orbit at the end of their mission. It can also refer to smaller things, like bits of debris or paint flecks that have fallen off a rocket.

Answer:

In addition to derelict man-made objects left in orbit, other examples of space debris include fragments from their disintegration, erosion and collisions or even paint flecks, solidified liquids expelled from spacecraft, and unburned particles from solid rocket motors. Space debris represents a risk to spacecraft.

Explanation:

If the ball has a positive electric charge, what should the charge of the coilgun be to push the ball away?

A)positive
B) negative
C)neutral

Answers

Answer:

A

Explanation:if the things have the same charge they will repel makeing the ball move away form its positively charged guy = that the coil gun works.

A galaxy spectrum has a redshift of 70,000 km per second. If the Hubble constant is 70 km per second per Mpc (megaparsec), how far away from us in this galaxy

Answers

Using the Hubble law v = H₀d where v = recessional speed = 70,000 km per second H₀ = hubble constant = 70 km/s/Mpc and d = distance of galaxy.

Making d subject of the formula, we have

d = v/H₀

Substituting the values of the variables into the equation, we have

d = v/H₀

d = 70000 km/s/70 km/s/Mpc

d = 1000 Mpc

So, the galaxy is 1000 Mpc away from us.

Learn more about hubble law here:

https://brainly.com/question/18484687

A block of wood mass 0.60 kg is balanced on top of a vertical port 2.0 m high. A 10 gm
bullet is fired horizontally into the block and the embedded bullet land at a 4.0 m from
the base of the port. Find the initial velocity of the bullet.
A. 10 3 m/s B. 8.32 m/s C. 3.82 m/s D. 1.0 m/s

Answers

Answer:

m V1 = (m + M) V2 conservation of momentum

T = time to fall 2 m

2 = 9.8 / 2 T^2    initial vertical velocity zero

T^2 = 4/9.8       T = .639 sec

Sx = V2 * .639 sec     distance traveled horizontally

V2 = 4 /.639 = 6.26 m/sec

V1 = (m + M) / m * 6.26 m/sec       from first equation

V1 = (600 + 10) / 10 * 6.26 m/s = 382 m/s

There seems to be some confusion on units

Note that 382 m/s is a reasonable answer for speed of bullet

1100 ft/sec is reasonable for a .22 cal bullet

1100 ft/sec / 3.28 ft/m = 335 m/sec

In the very distant future, given our best model of the accelerating universe, what will the universe look like?

Answers

The models of the universe allow finding the result for how serious the universe in the distant future is:

In the distant future the galaxies are far apart and the interaction between them would be negligible.

The Big Bang model shows that the universe was created at a certain point and time where from which all matter is separating at a speed from these objects.

Based on these models and the measurements that the galaxies are moving away, in the distant future the galaxies must be very far from each other so that the universe would be composed of isolated entities without the possibility of interaction between them.

Within each galaxy the bodies are not separated because in each one there is a black body whose gravity holds the stars within its galaxy together.

In conclusion of the models of the universe we can find the result for how serious the universe in the distant future is:

In the distant future the galaxies are far apart and the interaction between them would be negligible.

Learn more about the motion of the galaxies here:  brainly.com/question/18212080

People wear special snowshoes when there is a snowfall in the cold countries. Why?

Answers

Answer:

The fundamental function of snowshoes is to offer float, allowing you to avoid sinking into snow. Hikers who do not have snowshoes may find themselves knee- or waist-deep in unconsolidated snow if they attempt to traverse it without snowshoes, a practice known as post-holing.

Explanation:

Answer:

Explanation:

I live in a cold country and I own snow shoes. I have to confess I've never thought about this question before.

If the snow is fresh, it is also very loosely packed. If you wear ordinary shoes, the first thing that will happen is that you will sink. How far depends on how deep the snow is. I can see you up to your waist in snow, if the snowfall is heavy enough.

So to prevent that, my snowshoes are 3 feet long and about 1 foot wide, Except for a small hole near the middle, the entire area is covered. I weigh about 140 pounds.

A very small calculation should tell you that if I wear house shoes (mine are 8" long by about 3 inches wide). The pressure is going to be 140 pounds / (2/3 * 1/4) = 140 // 2/12 = 140 / 1/6 = 140 *  6 = 840 pounds / square foot. Trust me, that is a lot of pressure.

What do the snowshoes accomplish?

140 / (3*1) = 46.7 pounds per square foot. You might sink a little, but you are not going down as far as you would with street clothes shoes.

The units are not the normal units you would use, but the ratio is going to be roughly the same. 840 / 46.

All of this is very approximate. That's what physics is all about. Approximations lead you to understanding.

A boy standing on a bridge 150m above the canyon floor throws a stone downward with a speed of 20.0m/s.
A) with what velocity will it hit the ground?
B) How long will it take to descend?

Answers

Answer:

57.97m/s

12.1s

Explanation:

Use one of the key equations of accelerated motion and sub in the values

vf^2=vi^2+2aΔd

vf^2=(20)^2+(2*9.8)(150)

vf^2 = 3340

vf = 57.79m/s (square rooted both sides)

now use another equation

Δd = (vi+vf/2)Δt

and rearrange for Δt

Δt = (2Δd-vf)/vi

sub in values

Δt = (2*150-57.79)/20

Δt = 12.1s

mark me as brainliest if this helped!

Explain how work and power are different. Give an example of doing the same amount of work, but producing different amounts of power.

Answers

Answer:Work is a measurement of energy.

Power is a measurement of energy per time.

So, power measures how fast work is done.

If we raise 1kg up to a height of 1 meter it takes a certain amount of work. It doesn't matter if it takes us 1 second or 1 hour to raise it. It takes more power, energy per second, to raise it in 1 second than to raise it in one hour.

An engines power rating is in horsepower. A higher horsepower car engine will get a certain car up a hill more quickly than if it had a lower horsepower engine. Even though both engines did the same amount of work in getting the car up the hill

Answer:

work is a measurement of energy, but power is how much energy it takes. Two people could do the same amount of work. Sally and James. James may finish his work in 2 days due to the amount of power he puts in, but it may take Sally a week.

A fan operating at 260V with a current being supplied at 13A. What is the effective resistance at which it is being operated?

Answers

Answer:

20 ohms

Explanation:

Resistance=Potential difference÷Electric current

X=260÷13

X=20

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