Why does 250 N not push an object when frictional force is 188 N while 251 N is pushing with fast acceleration.

The solenoid contains 75 turns to create a 0.295 t magnetic field at the center of the solenoid.

To find the number of turns in the solenoid, we can use the formula for the magnetic field inside a solenoid:

B = μ₀ * n * I

where B is the magnetic field strength (0.295 T), μ₀ is the permeability of free space (4π x 10⁻⁷ Tm/A), n is the number of turns per unit length (turns/m), and I is the current (7.45 A).

n = B / (μ₀ * I)
n = 0.295 T / (4π x 10⁻⁷ Tm/A * 7.45 A)
n ≈ 625.57 turns/m

Now, we need to find the total number of turns in the solenoid. Since the solenoid has a length of 12.0 cm, we need to convert that to meters:

Length = 12.0 cm * (1 m / 100 cm) = 0.12 m

Total turns = n * Length
Total turns = 625.57 turns/m * 0.12 m
Total turns ≈ 75.07

Since the number of turns must be a whole number, we can round this to the nearest whole number, which is 75 turns. So, the solenoid contains 75 turns.

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To remain stationary in a downward-directed electric field of magnitude 670 N/C, the electric force acting on the charged particle must be equal in magnitude and opposite in direction to the gravitational force acting on the particle.

The gravitational force acting on the particle can be calculated using the formula Fg = mg, where m is the mass of the particle and g is the acceleration due to gravity (9.81 m/s^2).

Fg = mg = (1.46 g)(9.81 m/s^2) = 14.33 × 10^-3 N

The electric force acting on the charged particle can be calculated using the formula Fe = qE, where q is the charge of the particle and E is the electric field strength. Fe = qE = (q)(670 N/C)

To remain stationary, the electric force and gravitational force must be equal and opposite, so we can set them equal to each other and solve for the charge q: Fe = Fg

[tex](q)(670 N/C) = 14.33 × 10^-3 N[/tex]

[tex]q = (14.33 × 10^-3 N) / (670 N/C)[/tex]

[tex]q = 2.14 × 10^-5 C[/tex]

Since the particle is stationary in a downward-directed electric field, the charge must be negative, so the charge of the particle is[tex]-2.14 × 10^-5 C.[/tex]

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When the switch is closed, the capacitor will start to charge. The bulb will light up and its brightness will gradually decrease as the capacitor charges. If the capacitor was twice as large, it would take longer for it to charge and the bulb would stay bright for a longer period of time.

If the bulb had half as much resistance, it would allow more current to flow through it and the bulb would be brighter. The capacitor would also charge faster. When the switch in the circuit is closed, the capacitor will start charging up from zero voltage. Once the capacitor is fully charged, the current in the circuit stops, and the voltage across the capacitor is equal to the voltage of the battery.

When the switch is closed, the capacitor starts charging up from zero voltage, and the voltage across the capacitor increases while the current flowing through the circuit decreases.  The resistor in the circuit limits the flow of current, causing the charging process to take some time.

During this charging process, the voltage across the capacitor increases, while the current flowing through the resistor and the capacitor decreases. As time goes on, the voltage across the capacitor approaches the voltage of the battery in the circuit, which is 12 volts in this case. Once the capacitor is fully charged, the current flowing through the circuit stops since no more charge can be stored in the capacitor.

During the charging process, the voltage across the resistor decreases, as the voltage across the capacitor increases. Once the capacitor is fully charged, the voltage across the resistor becomes zero, and the voltage across the capacitor is equal to the voltage of the battery.

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Complete question:

In the circuit on the right, the capacitor is initially uncharged. a. Describe what is observed when the switch is closed. b. How would your observations be changed capacitor were twice as large? c. How would your observations be changed if the bulb had half as much resistance?

The one property of a main-sequence star that determines all its other properties is its mass. Option c is correct.

The main-sequence is a sequence of stars in which they spend most of their lifetimes. The position of a star on the main-sequence depends on its mass, which determines its luminosity, temperature, spectral type, and other properties. The more massive a star is, the hotter and brighter it is, and the shorter its lifetime.

Conversely, less massive stars are cooler and dimmer, and live much longer. The mass of a star also determines the reactions that occur in its core and the elements that are produced, shaping its evolution and eventual fate. Therefore, the mass of a main-sequence star is a fundamental property that determines most of its other characteristics. Hence option c is correct.

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Values for P1, V1, and P2 to find the size of the tank needed to contain the helium at atmospheric pressure.

To determine the size of the tank needed to contain the helium at atmospheric pressure (1 atm), we need to use the ideal gas law formula:

PV = nRT
Where:
P = Pressure (in atm)
V = Volume (in liters)
n = Moles of gas
R = Ideal gas constant (0.0821 L atm/mol K)
T = Temperature (in Kelvin)
From the student question, we know that the initial pressure (P1) and volume (V1) are given. We also know that the final pressure (P2) is 1 atm. We need to find the final volume (V2).
Step 1: Calculate the moles of helium gas (n) using the initial conditions.
P1V1 = nRT1
n = (P1V1) / (RT1)
Step 2: Calculate the final volume (V2) using the moles of helium gas (n) and atmospheric pressure (1 atm).
P2V2 = nRT2
V2 = (nRT2) / P2
Since we want the tank size for the same amount of helium at atmospheric pressure, we can assume the temperature remains constant (T1 = T2). Therefore, you can simply use the initial conditions to find the final volume:
V2 = (P1V1) / P2
Plug in the given values for P1, V1, and P2 to find the size of the tank needed to contain the helium at atmospheric pressure.

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Water pressure 2m below the surface of a small pond is the same as water pressure 2m below the surface of any other body of water, which is determined by the weight of the water above it.

Water pressure is determined by the depth of water, the density of the water, and gravity. The pressure at a particular depth is determined by the weight of the water column above that point. Therefore, the water pressure 2m below the surface of a small pond is greater than the water pressure 2m below the surface of a larger body of water, such as a lake or ocean. This is because the weight of the water column above a given point is greater in a larger body of water.

Additionally, water pressure increases with depth regardless of the size of the body of water. This is due to the increasing weight of the water column above and the corresponding increase in the force of gravity acting on the water molecules.

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The volume of the helium in the balloon when the atmospheric pressure is 380 mmHg is 1520 mL.

To determine the volume of helium in the balloon, the combined gas law must be applied. The formula for the combined gas law is given by:

PV/T = constant

where P is pressure, V is volume, and T is temperature. Since the temperature and the amount of helium remains unchanged, the combined gas law can be written as P1V1 = P2V2 where P1 is the initial pressure, V1 is the initial volume, P2 is the final pressure, and V2 is the final volume.

Given that the initial pressure P1 = 760 mmHg and the final pressure P2 = 380 mmHg, the final volume V2 can be determined using:

P1V1 = P2V2

V2 = (P1V1)/P2

V2 = (760 mL)(760 mmHg)/(380 mmHg)

V2 = 1520 mL

Hence, the volume of the helium in the balloon when the atmospheric pressure is 380 mmHg is 1520 mL.

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Answer:

The name for this type of movie is "anthology film" or "portmanteau film."

The name for the type of movie where an object is passed from one person to another like The Red Violin or The Yellow Rolls Royce is called an "anthology film."

An anthology film is a type of film consisting of several short stories, often linked by a common theme or object. In this case, the object being passed from one person to another is the linking element that ties the stories together. Other examples of anthology films include Four Rooms, The Ballad of Buster Scruggs, and Pulp Fiction.

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The magnitude of the momentum of the rifle due to recoil after firing is 0.13 kg*m/s. The negative sign indicates that the rifle recoils in the opposite direction of the bullet's motion, by the law of conservation of momentum.

According to the law of conservation of momentum, the total momentum before and after an event must be the same. In this case, the momentum of the rifle and the bullet before firing is zero because they are at rest. After firing, the momentum of the bullet is given by the product of its mass and velocity, which is:

p_bullet = m_bullet * v_bullet

= 0.050 kg * 600 m/s

= 30 kg*m/s

The momentum of the rifle due to recoil can be found by multiplying the negative of the bullet's momentum by the mass ratio of the rifle to the bullet since the total momentum must be zero:

p_rifle = -m_bullet/m_rifle * p_bullet

= -(0.050 kg)/(11.5 kg) * 30 kgm/s

= -0.13 kgm/s

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The charge on the positive plate of each capacitor is q/2, and the potential difference across each capacitor is q/2×C1 and q/2×C2 respectively.

Assuming that the capacitors have capacitances C1 and C2, and the charge on the positive plate of each capacitor is q1 and q2 respectively. During the charging process, the battery supplies a potential difference v to the capacitors, which causes a charge q to flow through the circuit. According to the conservation of charge, the charge on the positive plate of each capacitor must be equal to q/2 (since the capacitors are in series, the charge on each capacitor is the same).

The potential difference across each capacitor can be calculated using the formula:

V = Q/C

where V is the potential difference, Q is the charge on the capacitor, and C is the capacitance.

For the first capacitor, we have:

V1 = q/2×C1

For the second capacitor, we have:

V2 = q/2×C2

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When the planet Mars is, on average, about 228 million km from the Sun, the correct option is about 1.52 hours.

The time it takes light from the Sun to reach Mars when the planet Mars is, on average, about 228 million km from the Sun is about 12.7 minutes.

The given question can be solved using the formula; Time = Distance / Speed of light

Given that Distance of Mars from the Sun = is 228 million km

The speed of light = 300,000 km/sNow, let's plug in the values in the formula.

Time = Distance / Speed of light = 228 × 106 km / 300,000 km/s = 760 secondsTherefore, the time taken for light to reach Mars from the Sun is 760 seconds.1 hour is equal to 3600 seconds.

Therefore, the time taken for light to reach Mars from the Sun is about 760 / 3600 hours = 0.21 hours or about 1.52 hours.

Hence, the correct option is about 1.52 hours.

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Answer:

The first step is to calculate the potential energy of the ball at the top of the first hill using the formula PE = mgh, where m is the mass of the ball, g is the acceleration due to gravity, and h is the height of the hill. PE = (8 kg) x (9.8 m/s^2) x (20 m) = 1568 J Next, we can use the law of conservation of energy, which states that the total energy of a closed system remains constant. This means that the potential energy at the top of the first hill must be equal to the kinetic energy at the bottom of the hill, since there is no external work done on the ball. So, using the formula KE = 1/2mv^2, where v is the velocity of the ball, we can solve for v: KE = 1

E_total(θ) = Σ (Eθ e^(j(kd(i-1)cos(θ) + βi)))
This expression represents the total radiated field of the array, considering the individual contributions from horizontally polarized dipole elements with the given electric field Eθ and taking into account their positions and phase shifts within the array.

To find the expression for the total radiated field of the array, we need to consider the individual contributions of each dipole element in the array and sum them up. Since the antenna elements are horizontally polarized dipoles, we can express the radiated electric field Eθ for a single dipole as:

Eθ = âθ jµ (kIol / 4πr) e^(-jkr) |cos θ|

Here, âθ represents the unit vector in the θ direction, j is the imaginary unit, µ is the permeability, k is the wave number, Iol is the current at the location of the dipole, r is the distance from the dipole, and θ is the angle between the observation point and the dipole axis.

Now, we need to consider an array of N dipoles, each with its own location and phase shift. For simplicity, let's assume that all dipoles have the same current amplitude I0 and are uniformly spaced with a distance d along the x-axis.

To find the total radiated field for the array, we need to sum the contributions of each dipole element:

E_total(θ) = Σ E_i(θ)

where E_i(θ) is the radiated field of the i-th dipole, and the summation goes from i=1 to N.

For each dipole in the array, we need to account for the phase shift due to its position along the x-axis and the additional phase shift βi introduced by the array feeding network:

E_i(θ) = Eθ e^(j(kd(i-1)cos(θ) + βi))

So, the total radiated field of the array is given by:

E_total(θ) = Σ (Eθ e^(j(kd(i-1)cos(θ) + βi)))

This expression represents the total radiated field of the array, considering the individual contributions from horizontally polarized dipole elements with the given electric field Eθ and taking into account their positions and phase shifts within the array.

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An inflated beach ball pushed beneath the water surface will swiftly shoot above the water surface when released due to the principle of buoyancy.

Buoyancy is a physical phenomenon that describes the upward force this is exerted on an item submerged in a fluid, inclusive of water or air. This pressure is a result of the pressure differences between the top and backside of an item in a fluid, and it is referred to as buoyant pressure.

Here, the beach ball is pushed beneath the water surface, it displaces a certain amount of water which will weight more than the beach ball itself. This cause acceleration upwards towards the surface when ball released.

If the object is less dense than the liquid, it will float. if the object is more dense than the liquid, it will sink.

Beach ball has a lower density than the water it displaces. So the buoyant force is so higher than a solid object of the same size and weight. The combination of buoyancy and the low density of air inside the beach ball causes it to shoot up quickly to the water surface when released.

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The maximum reading on the ammeter will be determined by the rate of change of the magnetic field through the coil, and the number of turns in the coil.

The maximum reading on an ammeter when a magnet is pulled away from a coil as quickly as possible depends on several factors. Firstly, it depends on the strength of the magnetic field of the magnet, the number of turns in the coil, and the rate of change of the magnetic field. A faster change in the magnetic field will induce a larger current in the coil and produce a higher reading on the ammeter.

Additionally, the resistance of the circuit and the sensitivity of the ammeter also play a role in determining the maximum reading. Therefore, the maximum reading on the ammeter will be higher if the magnetic field is stronger, the number of turns in the coil is larger, the rate of change of the magnetic field is faster, the resistance of the circuit is lower, and the sensitivity of the ammeter is higher.

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--The complete question is, On what factors does the maximum reading on the ammeter when the magnet is pulled away from the coil as quickly as possible?--

Explanation:

Potential energy = m * g * h    re-arrange to

PE/mg  = h     plug in the numbers

.06615 J / (9.81 m/s^2 * .0025 kg) = 2.7 m

[tex]h=v_i_yt+\frac{1}{2}gt^2\\ \\h=\frac{1}{2}(9.81m/s^2)(4s)^2\\[/tex]

h = 78.48 m

Answer:

Explanation:

where h is the height of the cliff, g is the acceleration due to gravity, and t is the time it takes for the ball to hit the ground.

where d is the distance traveled, v is the initial horizontal velocity, and t is the time it takes to travel the distance.

Since the ball is projected horizontally, its initial horizontal velocity is constant, and we can assume it is the same as the speed at which it hits the ground. Therefore, we can write:

Substituting in the given values, we get:

When an ambulance with a siren emitting a whine at 1600 Hz overtakes and passes a cyclist pedaling a bike at 2.44m/s, the cyclist hears a frequency of 1590 Hz. the speed of The ambulance is 2.44625 m/s.

Since the cyclist is moving in the same direction as the ambulance, the relative speed between the two is the difference in their speeds.

Therefore, The relative speed between them is v = 1600 - 1590 = 10 Hz

For the observer, the ambulance appears to be moving away from him because the frequency heard by him is less than the actual frequency emitted by the ambulance.

 As per the Doppler effect, the following formula can be used to determine the relative velocity between the source and observer:

v = (f₂ - f₁) / f₁

where v is the relative velocity between the source and observer, f₁ is the frequency of the source, and f₂ is the frequency heard by the observer.

Substituting the given values in the above formula, we get:

v = (1590 - 1600) / 1600 = -0.00625

The relative velocity is negative because the ambulance is moving away from the cyclist.

As the cyclist is moving at 2.44 m/s, and the relative velocity between the two is -0.00625, the velocity of the ambulance can be determined as follows:

v = 2.44 - (-0.00625) = 2.44625 m/s

Therefore, the speed of the ambulance is 2.44625 m/s.

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The photoelectric effect for a certain alloy has a threshold frequency of 6.90 x 10^14 hz. For light of this frequency The energy of one mole of photons is approximately 2.75 x 10^-13 kJ/mol.

To find the energy of one mole of photons, we can use the formula E = nhf, where E is the energy, n is the number of photons in a mole (Avogadro's number), h is Planck's constant, and f is the frequency.

the threshold frequency (f) = 6.90 x 10^14 Hz, Planck's constant (h) = 6.63 x 10^-34 Js, and Avogadro's number (n) = 6.022 x 10^23 mol^-1.
E = (6.022 x 10^23 mol^-1) x (6.63 x 10^-34 Js) x (6.90 x 10^14 Hz)
E = 2.754 x 10^-10 J/mol
Now, convert the energy from Joules to Kilojoules (kJ):
E = 2.754 x 10^-10 J/mol * (1 kJ / 1000 J)
E ≈ 2.75 x 10^-13 kJ/mol
So, the energy of one mole of photons for the given frequency is approximately 2.75 x 10^-13 kJ/mol.

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(a) Kinetic Energy: 216 J, Potential Energy: 353.4 J. (b) Work Done: 2160 J.

(b) Total work done is equals to 2160J

(a) To find the kinetic energy (KE) and potential energy (PE) of a 12 kg cat running on a 3 m high wall with a speed of 6 m/s, we use the following formulas:

KE = 0.5 * mass * velocity²
KE = 0.5 * 12 kg * (6 m/s)²
KE = 216 J

PE = mass * gravity * height
PE = 12 kg * 9.81 m/s^²* 3 m
PE = 353.4 J

(b) To find the work done when the cat runs 10 m and then stops, we use the work-energy principle:

Work Done = Change in Kinetic Energy
Since the cat comes to a stop, the final KE is 0 J.

Work Done = Initial KE - Final KE
Work Done = 216 J - 0 J
Work Done = 2160 J

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Average yearly high temperature decreases as elevation increases.

The difference in elevation between the two cities results in a difference in atmospheric pressure and thus a difference in temperature.

A decrease in latitude would likely increase the average yearly high temperatures of both cities due to the increased amount of solar radiation they receive.

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The force the floor typically applies to the ball is on average magnitude  is 750 N.

The initial momentum of the ball:

[tex]p_1 = m*v_1 = 0.3 kg * 4 m/s = 1.2 kg m/s[/tex]

The final momentum of the ball:

[tex]p_2 = m*v_2 = 0.3 kg * (-1 m/s) = -0.3 kg m/s[/tex]

The difference in momentum of the ball is therefore:

Δp = [tex]p_2 - p_1 = -1.5 kg m/s[/tex]

Δp = FΔt

Δt = 2×10^-3 s.

F = Δp/Δt = (-1.5 kg m/s)/(2×10^-3 s) = -750 N

|F| = 750 N

Magnitude is a term used to describe the size, amount, or extent of something. In science and mathematics, magnitude often refers to the numerical value or quantity of a measurement or vector. For example, the magnitude of a force is the amount of force being applied, while the magnitude of an earthquake is a measure of the energy released.

In astronomy, magnitude is used to describe the brightness of celestial objects such as stars and galaxies. The magnitude scale was developed by ancient Greek astronomers, with lower magnitudes indicating brighter objects. Today, astronomers use the apparent magnitude scale, which takes into account both the intrinsic brightness of an object and its distance from Earth. In general usage, magnitude can refer to the importance, impact, or significance of something.

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A correlation of -0.9 mean : 2.) as one variable increases, the other variable decreases.

A correlation of -0.9 indicates a strong negative correlation between two variables, which means that as one variable increases, then other variable decreases. Closer is the correlation coefficient to -1,  stronger is the negative correlation between the variables. Hence, option 2)as one variable increases, the other variable decreases is the correct answer.

Since correlation is symmetrical and represents the strength of the association between two variables, it follows that the correlation between variables A and B and B and A are identical.

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The component of the magnetic field along the y-axis should be zero when the dipole is oriented along the y-axis.

This is because the magnetic field lines of a dipole magnet are perpendicular to the axis of the magnet. When the dipole is oriented along the y-axis, the axis of the dipole is also along the y-axis. Therefore, the magnetic field lines of the dipole are oriented in the x-z plane and are perpendicular to the y-axis. As a result, the component of the magnetic field along the y-axis is zero.

In contrast, when the dipole is oriented along the x-axis, the axis of the dipole is parallel to the x-axis, and the magnetic field lines of the dipole are perpendicular to the x-axis. Therefore, the component of the magnetic field along the x-axis is zero. Similarly, when the dipole is oriented along the z-axis, the axis of the dipole is parallel to the z-axis, and the magnetic field lines of the dipole are perpendicular to the z-axis. Therefore, the component of the magnetic field along the z-axis is zero.

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When you are working on a magnetic levitation experiment in a lab and beta radiation is emitted directly at you, passing through the magnets first, you are not safe because it was beta radiation and very dangerous.

The correct answer is option a.

Beta radation is a form of ionizing radiation that is made up of high-energy beta particles. Beta particles are high-energy, high-speed electrons or positrons that are emitted by certain radioactive isotopes. The emission of beta radiation from radioactive materials is referred to as beta decay.

Beta particles, unlike alpha particles, have a longer range and can penetrate through paper, skin, and other low-density materials but can be blocked by high-density materials.

Therefore, option a is correct.

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Based on the information, we can infer that the correct answer is D. Frequency and wavelength are directly proportional, and pitch is the perception of frequency.

Sound waves are longitudinal waves that travel through a medium, such as air or water. The frequency of a sound wave refers to the number of cycles of compression and rarefaction that occur in one second, measured in Hertz (Hz). The wavelength of a sound wave refers to the distance between two consecutive points in the wave that are in phase, such as the distance between two consecutive compressions or rarefactions.

The pitch of a sound refers to how high or low it sounds to a listener. This perception of pitch is directly related to the frequency of the sound wave. A higher frequency sound wave produces a higher-pitched sound, while a lower frequency sound wave produces a lower-pitched sound.

Therefore, as the frequency of a sound wave increases, so does its pitch, while the wavelength decreases. Conversely, as the frequency decreases, the wavelength increases, and the pitch becomes lower.

In the case of the chirping bird, the students in the Physics classroom can observe that as the frequency of the bird's chirping increases, the pitch of the sound also increases, while the wavelength decreases. This relationship between frequency, wavelength, and pitch is an important concept in the study of sound waves and acoustics.

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When switch S1 is closed, the current in the circuit increases and flows through both the inductor and the resistor. The inductor opposes changes in current, so it initially behaves like a short circuit and the voltage across it is zero.

At this point,  voltage across  inductor starts to increase. When switch S2 is closed, current in the circuit starts to decrease. As a result, the voltage across the inductor will initially be greater than voltage across the resistor. The voltage across the inductor will gradually decrease as the magnetic field in the inductor collapses and  current approaches zero. Therefore, the voltage across  inductor will be larger than the voltage across the resistor at the moment switch S2 is closed.

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The maximum kinetic energy of the ejected electrons is approximately 1.16 eV. To find the maximum kinetic energy (KE) of ejected electrons, we can use the photoelectric effect equation:

KE = hf - W

where h is Planck's constant [tex](4.14 × 10^(-15) eV·s)[/tex], f is the frequency of the electromagnetic radiation, W is the work function (2.34 eV), and KE is the maximum kinetic energy.

First, we need to find the frequency (f) using the wavelength (λ) given:

c = λf

where c is the speed of light [tex](3 × 10^8 m/s)[/tex].

1. Convert the wavelength to meters: [tex]442 nm × 10^(-9) m/nm = 4.42 × 10^(-7) m[/tex]

2. Rearrange the equation to solve for [tex]f: f = c / λ[/tex]

3. Calculate [tex]f: f = (3 × 10^8 m/s) / (4.42 × 10^(-7) m) ≈ 6.79 × 10^14 Hz[/tex]

Now, we can find the maximum kinetic energy (KE) using the photoelectric effect equation:

4. Calculate KE: [tex]KE = (4.14 × 10^(-15) eV·s × 6.79 × 10^14 Hz) - 2.34 eV ≈ 1.16 eV[/tex]

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By shooting past it's equilibrium position and then oscillate before settling to the equilibrium position is characterize the response of the mass once you let go. So, option A is corect choice.

The given mass-spring-damper system can be represented by the differential equation:

[tex]my'' + \mu_fy' + k\timesy = F_{ext}[/tex]

where y is the displacement of the mass from its equilibrium position, and [tex]F_{ext}[/tex] is any external force acting on the system.

To determine the response of the mass once you let go, we need to solve the above differential equation for the initial condition y(0) = 0.2 and y'(0) = 0 (assuming that the mass is released from rest).

To solve the differential equation, we first need to determine the damping ratio, which is given by:

damping ratio (ζ) = [tex]\mu_f / (2 \times \sqrt{(k \times m)})[/tex]

Substituting the given values, we get:

damping ratio (ζ) = [tex]7 / (2 \times \sqrt{160 \times 80})[/tex] = 0.1106

Since the damping ratio is less than 1, the system is underdamped.

Therefore, the response of the mass once you let go will oscillate with a decreasing amplitude until it reaches its equilibrium position.

The frequency of oscillation (ω) can be determined using the following formula:

ω = [tex]\sqrt{(k / m - \zeta ^2 times (\mu_f^2 / 4 \times m^2))}[/tex]

Substituting the given values, we get:

ω = [tex]\sqrt{160 / 80 - 0.1106^2 \times (7^2 / (4 \times 80^2)}[/tex]= 4.352 rad/s

The time period of oscillation (T) can be determined using the formula:

T = 2π / ω

Substituting the value of ω, we get:

T = 2π / 4.352 = 1.444 s

Therefore, once you let go, the mass will oscillate around its equilibrium position with a decreasing amplitude and a time period of 1.444 s until it eventually comes to rest.

Hence, the correct answer is option A: "It would shoot past its equilibrium position and then oscillate before settling to the equilibrium position."

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Question:-

you have a mass spring damper system as descried by

[tex]m\frac{d^2y}{dt^2}+\mu_f\frac{dy}{dt}  +ky =F_{ext}[/tex]

where

m= 80 kg

[tex]\mu_f[/tex]  = 7 N*s/m

k = 160 N/m

The unit of Newtons (N) is equivalent to kg m/s²

If you were to displace the mass by 0.2 m from its equilibrium position, how would you characterize the response of the mass once you let go? (Hint: you need to determine the value of the damping ratio).

a. It would shoot past it's equilibrium position and then oscillate before settling to the equilibrium position

b. It will approach the equilibrium position very slowly but not oscillate.

c. The answer depends on the value of the time constant

d. The system will be critically damped.

Dylan's weight (the gravitational force due to the earth) would decrease to 1/9 of its original value if he tripled his distance from the center of the earth by flying in a spacecraft.

The force of gravity, which determines the weight of an object, is proportional to the mass of the two objects involved (in this case, Dylan and the Earth) and inversely proportional to the square of the distance between them.

The formula for the gravitational force is F = GmM/r², where G is the gravitational constant, m and M are the masses of the two objects, and r is the distance between them.

If Dylan tripled his distance from the center of the Earth, his distance from the center would become three times larger than before. Using the inverse square law, the gravitational force he experiences would be nine times smaller (3²) than it was before.

Therefore, his weight would decrease to 1/9 of its original value, which is 600 N/9 = 66.67 N.

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