Which set of population data is the least dispersed from its mean?
O 2, 3, 2,9
O 4, 0, 4,0
O 6, 2, 2, 2
O 9, 3, 5,3​

Answers

Answer 1

Answer: (C)

6,2,2,2

Step-by-step explanation:

Answer 2

A mean is an arithmetic average of a set of observations. The set of population data that is the least dispersed from its mean is {6, 2, 2, 2}.

What is Mean?

A mean is an arithmetic average of a set of observations. it is given by the formula,

[tex]\rm Mean=\dfrac{\text{Sum of all obervation}}{\text{Number of observation}}[/tex]

To solve the problem we will find the mean of each population set and then add the difference between the mean and each data point.

A.)

[tex]Mean = \dfrac{2+3+2+9}{4} = \dfrac{16}{4} =4[/tex]

Dispersion of each point from the mean,

[tex]\rm |Mean - data\ point|\\|4-2|=2\\|4-3|=1\\|4-2|=2\\|4-9|=5[/tex]

Thus, the dispersion of the population from the means is 10 (2+1+2+5).

B.)

[tex]Mean = \dfrac{4+0+4+0}{4} = \dfrac{8}{4} =2[/tex]

Dispersion of each point from the mean,

[tex]\rm |Mean - data\ point|\\|2-4|=2\\|2-0|=2\\|2-4|=2\\|2-0|=2[/tex]

Thus, the dispersion of the population from the means is 8 (2+2+2+2).

C.)

[tex]Mean = \dfrac{6+2+2+2}{4} = \dfrac{12}{4} =3[/tex]

Dispersion of each point from the mean,

[tex]\rm |Mean - data\ point|\\|3-6|=3\\|3-2|=1\\|3-2|=1\\|3-2|=1[/tex]

Thus, the dispersion of the population from the means is 6 (3+1+1+1).

D.)

[tex]Mean = \dfrac{9+3+5+3}{4} = \dfrac{20}{4} =5[/tex]

Dispersion of each point from the mean,

[tex]\rm |Mean - data\ point|\\|5-9|=4\\|5-3|=2\\|5-5|=0\\|5-3|=2[/tex]

Thus, the dispersion of the population from the means is 8 (4+2+0+2).

Hence, the set of population data that is the least dispersed from its mean is {6, 2, 2, 2}.

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

i took the test

Supply and demand coordinate to determine prices by working together.

What is supply and demand?

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Step-by-step explanation:

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[tex]\huge\boxed{\mathcal{HELLO!}}[/tex]

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[tex]\huge\boxed{Answer:-12a-48}[/tex]

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Answers

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Step-by-step explanation:

Step 1: Write equation

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Step 2: Solve for s

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Step 3: Check

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