which food does not require the process of glycolysis and fermentation? group of answer choices tofu french bread cheese yogurt saurkraut

Answers

Answer 1

Cheese does not require the process of the glycolysis and the fermentation. Option C is correct.

While cheese is made from milk, the cheese-making process involves coagulating the milk proteins (casein) and separating the curd (solid) from the whey (liquid), rather than breaking down the lactose (milk sugar) through glycolysis and fermentation. The curd is then typically pressed and aged, which can result in a wide range of different cheese varieties with distinct textures and flavors.

Glycolysis and fermentation are both important metabolic processes that allow cells to produce energy, particularly in anaerobic conditions. Glycolysis is the first step in both aerobic and anaerobic respiration, while fermentation is a backup process that allows cells to continue producing energy when oxygen is not available.

Hence, C is the correct option.

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--The given question is incomplete, the complete question is

"Which food does not require the process of glycolysis and fermentation? group of answer choices A) Tofu B) French bread C) Cheese D) yogurt E) Saurkraut."--


Related Questions

in a human pedigree that traces the inheritance of sickle cell disease, a half-filled circle represents a:

Answers

For any attribute on the X chromosome, a female can have either a homozygous or heterozygous distribution of genes. The full sign depicts the diseased person's human pedigree, which is an autosomal recessive type. Hence (d) is the correct option,

In a pedigree, a circle represents a female and a square a man. Each affected male or female is represented by a coloured circle or square. A half-filled square denotes a heterozygous male for the characteristic, and a half-filled circle denotes a heterozygous female for the illness allele or alleles. These heterozygous people are referred to as disease allele or trait carriers.

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In a human pedigree that traces the inheritance of sickle cell disease, a filled circle represents a:

A) male with the disease.

B) female with the disease.

C) heterozygous male.

D) heterozygous female.

after being frightened by a barking dog on her walk, michele stopped to engage in some deep breathing to slow down her heart rate and return to a state of calm. what part of the nervous system was she attempting to engage? group of answer choices sympathetic nervous system somatic nervous system central nervous system parasympathetic nervous system

Answers

She was attempting to engage in parasympathetic part of nervous system.

D is the correct answer.

In calm "rest and digest" situations, the parasympathetic nervous system predominates, whereas the sympathetic nervous system activates the "fight or flight" reaction in stressful circumstances. The main functions of the PNS are to control bodily processes like digestion and urination as well as to store energy for later use.

After experiencing stress or peril, the body is able to relax because of the parasympathetic nervous system, which is a network of nerves. During times when you feel secure and at ease, it also aids in the operation of life-sustaining processes like metabolism.

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The complete question is:

After being frightened by a barking dog on her walk, michele stopped to engage in some deep breathing to slow down her heart rate and return to a state of calm. what part of the nervous system was she attempting to engage?

A) sympathetic nervous system

B) somatic nervous system

C) central nervous system

D) parasympathetic nervous system

susceptibility testing performed on quality control organisms using a new media lot number yielded zone sizes that were too large for all antibiotics tested. the testing was repeated using media from a previously used lot number, and all zone sizes were acceptable. the unacceptable zone sizes are best explained by the:

Answers

The unacceptable zone sizes observed in the susceptibility testing performed on quality control organisms using a new media lot number are likely due to inconsistencies or variations in the media composition. Media quality is critical in antibiotic susceptibility testing, as it can directly impact the results and interpretations.

When the testing was repeated using media from a previously used lot number, and all zone sizes were acceptable, it indicates that the issue lies with the new media lot number.

Factors that could contribute to the larger zone sizes in the new media lot include differences in the media's pH, nutrient content, or agar concentration. These factors can affect the diffusion of antibiotics through the media and subsequently alter the zone sizes observed.

In this scenario, the best course of action would be to report the issue to the media manufacturer, as it may represent a quality control problem with that specific lot.

Additionally, performing further quality control tests with different media lots can help to determine if the issue is isolated to a single lot or if it is more widespread. Ensuring that the media used in susceptibility testing is consistent and reliable is essential for obtaining accurate and reproducible results.

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Pls help me
A wetland area is a fully functioning ecosystem that contains a diversity of plant, insect, and animal populations. Which of the following ecosystem services does this wetland most likely provide? (3 points)
1. Clean water
II. Nutrient control
III. Soil preservation

I only
l, ll and lll
Il and lll only
Ill only

Answers

Wetlands are important features in the landscape that provide numerous beneficial services for people and for fish and wildlife. Some of these services, or functions, include protecting and improving water quality, providing fish and wildlife habitats, storing floodwaters and maintaining surface water flow during dry periods. These valuable functions are the result of the unique natural characteristics of wetlands.

See the Wetland Factsheet Series for more information about wetlands.

which formed element can be described as cytoplasmic fragments? pathway of thrombopoiesis. which formed element can be described as cytoplasmic fragments? pathway of thrombopoiesis. platelets megakaryocytes monocytes erythrocytes

Answers

Platelets can be described as cytoplasmic fragments. They are small, disc-shaped cell fragments that play a crucial role in blood clotting and wound healing.

Platelets are formed through the pathway of thrombopoiesis, which starts with the differentiation of hematopoietic stem cells into megakaryocytes. Megakaryocytes are large cells found in the bone marrow, and they undergo a process called endomitosis, where they replicate their DNA without cell division, resulting in a large, multinucleated cell.

As the megakaryocyte matures, it extends long cytoplasmic extensions called proplatelets, which fragment into smaller platelets. These platelets are then released into the bloodstream to perform their essential functions. This process is regulated by a hormone called thrombopoietin, which stimulates the production of megakaryocytes and the formation of platelets.

To recap, platelets are the formed elements that can be described as cytoplasmic fragments, and they are produced through the pathway of thrombopoiesis, which involves the differentiation of hematopoietic stem cells into megakaryocytes, the maturation of megakaryocytes, and the fragmentation of their cytoplasm into platelets.

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Which of the following describes research that would be considered basic science?

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The following describes research that would be considered basic science : b. A college student curious about the growth of desert plants in the presence of excess amounts of water.

What is meant by basic science?

Basic science is an area of research that seeks to increase our understanding of fundamental principles of nature and universe. It is driven by curiosity and the desire to expand knowledge, rather than by practical considerations.

Basic science is conducted in laboratory settings, and research findings are used to inform future applied research. Basic science is essential for gathering actual data to strengthen the scientific record.

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Note: The question given on the portal is incomplete. Here is the complete question.

Question: Which of the following describes research that would be considered basic science? a. a farmer is trying to improve his crop yields by using a new kind of fertilizer. b. a college student is curious about the growth of desert plants in the presence of excess amounts of water. c. government officials are trying to prevent the spread of a new strain of influenza virus. d. a doctor is trying to determine why a patient is feeling tired and sick.

hpv initiates cancer development through increased expression of group of answer choices cell surface receptors. viral antigens. tumor suppressor genes. viral oncogenes.

Answers

HPV initiates cancer development through increased expression of cell surface receptors.The human papillomavirus (HPV) initiates cancer development through increased expression of cell surface receptors. HPV is a group of more than 150 related viruses that can cause warts and some cancers, including cervical cancer.

The virus infects the basal layer of the epithelium and replicates in keratinocytes. HPV infects the skin and mucous membranes of the body. The virus can spread from person to person through skin-to-skin contact.

The virus is able to initiate cancer development through several mechanisms. One of the ways that HPV initiates cancer development is through increased expression of cell surface receptors. HPV can infect cells that express specific cell surface receptors, called the heparan sulfate proteoglycans.

The expression of these receptors is increased in cancer cells, which makes them more susceptible to HPV infection.The expression of viral oncogenes is another mechanism by which HPV initiates cancer development. HPV encodes several viral oncogenes, including E6 and E7. These oncogenes are able to inactivate tumor suppressor genes, such as p53 and pRb, which are important in regulating cell proliferation and apoptosis. The inactivation of these genes can lead to uncontrolled cell growth and the development of cancer.

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the final pattern you wish to obtain expresses the uasg-gfp construct only in cell c2. how will you drive uasg-gfp expression specifically in cell c2? for each regulatory dna construct, decide if it should express gal4, gal80, or not be used in order to produce the desired pattern.

Answers

Use a C2-specific regulatory DNA construct to express GAL4, a construct active in all cells except C2 to express GAL80, and the UASG-GFP construct. This setup will result in the expression of GFP only in cell C2, achieving the final desired pattern.

To drive the UASG-GFP expression specifically in cell C2, you would need to use a combination of the GAL4 and GAL80 systems. GAL4 is a transcription activator, while GAL80 is a repressor of GAL4 activity.

To achieve the desired pattern, follow these steps:

Identify a regulatory DNA construct (promoter) that is specific to cell C2. This construct should express GAL4. By having a C2-specific promoter, you ensure that GAL4 is only expressed in cell C2.

Find another regulatory DNA construct (promoter) that is active in all cells except cell C2. This construct should express GAL80. GAL80 will repress GAL4 activity in all cells, except for cell C2 where it is not expressed.

Introduce the UASG-GFP construct into the system. The GAL4 expressed specifically in cell C2 will bind to the UASG region and activate GFP expression.

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Why doesn’t the Antibodies in Lyme Disease Antigens (orange line) decrease after the first immune response, compared to non-Lyme Disease Antigens (blue line)?

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The bacterium Borrelia burgdorferi, which causes Lyme disease, enters humans through the bite of an infected tick.

Why, in contrast to non-Lyme Disease Antigens, do the Antibodies in Lyme Disease Antigens not decline after the initial immune response?

The production of antibodies against Borrelia burgdorferi is a component of the immune response to the bacterium. However, unlike many other infectious diseases, after the initial immune response, the antibodies against Borrelia burgdorferi do not diminish.This is due to the ability of Borrelia burgdorferi to alter the surface proteins that are the targets of the antibodies. As a result, the bacterium can continue to infect people while evading the immune system. As a result, the immune system has to continually make fresh antibodies to keep up with the bacterium's evolving surface proteins. Antigenic variation is the term for this phenomenon, which is a common tactic employed by many pathogens to avoid detection by the immune system.

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which of the following statements applies to all frameshift mutations? group of answer choices they change the amino acid sequence downstream from the mutant site. they cause the insertion or deletion of a single amino acid from the polypeptide chain. they create a premature stop codon at the site of mutation. they result in colon cancer.

Answers

The statement applicable for all the frameshift mutations is: (1) they change the amino acid sequence downstream from the mutant site.

Frameshift mutations are the ones where insertion or deletion of nucleotide occurs. This is therefore also called indel mutations. The indel can cause change in the reading frame of the sequence because the amino acid sequence changes entirely.

Amino acids are the organic compounds that are required by the living body for various functions. Th amino acids act as the monomers for the synthesis of proteins. Inside the living body, 20 different amino acids are involved in protein synthesis.

Therefore the correct answer is option 1.

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52) the procerus originates on the a) angle of the mouth. b) skin around the eyelids. c) lateral nasal cartilages. d) orbicularis oris. e) sides of the tongue.

Answers

It is a powerful superficial quadrangular muscle that inserts along the angle and lateral surface of the mandibular ramus and originates from the zygomatic arch. The correct answer is (C).

The buccinator's fibers join those of the orbicularis oris, risorius, depressor anguli oris, and zygomaticus major at the angle of the mouth to form the modiolus.

Near the junction of the nasal bones and the superolateral nasal cartilage, the procerus muscle is a pyramidal muscle that arises from the superior nasal fascia. The fibers of the procerus muscle run superiorly and join the frontalis muscle. Between the eyebrows, muscle fibers insert themselves into the skin.

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which of the following is most likely to result in a nonfunctional polypeptide? group of answer choices a silent mutation a missense mutation a nonsense mutation a transition mutation

Answers

A nonsense mutation is most likely to result in a nonfunctional polypeptide.

In genetics, a nonsense mutation is a point mutation in a DNA sequence that causes an early stop codon, or nonsense codon, in the transcribed mRNA and causes a shortened, incomplete, and nonfunctional protein product. The functional impact of a nonsense mutation relies on a variety of factors, including the placement of the stop codon within the coding DNA. Nonsense mutations are not necessarily deleterious.

For instance, the outcome of a nonsense mutation relies on the distance between the nonsense mutation and the original stop codon as well as the degree to which the protein's functional subdomains are impacted. Chain termination mutations are sometimes known as nonsense mutations because they cause polypeptide chains to end prematurely.

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compose a four to five-sentence paragraph that contrasts the circulatory systems of a fish and an amphibian.

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Fish and amphibians are two groups of animals with different circulatory systems. Fish have a single-loop circulatory system, where the heart pumps blood in one direction through the gills to the body and then back to the heart. This system is efficient for extracting oxygen from water. In contrast, amphibians have a double-loop circulatory system, with a three-chambered heart that separates oxygenated and deoxygenated blood. This allows amphibians to breathe through their lungs and skin, and to live both in water and on land. Despite these differences, both fish and amphibians rely on their circulatory systems to deliver oxygen and nutrients to their cells and remove waste products.

which condition below would inhibit a cell from beginning division? responses abundant nutrients abundant nutrients crowding of cells crowding of cells excess hgh leading to larger cells

Answers

A condition that would inhibit a cell from beginning division is the crowding of cells.

The correct answer is crowding of cells.

In a high-density cellular environment, cells come into contact with each other, which can trigger contact inhibition, a regulatory mechanism that prevents cells from dividing when they are too close to each other. This process helps maintain the balance between cell proliferation and cell death, ensuring that tissues and organs maintain their appropriate size and function.

Abundant nutrients, on the other hand, generally promote cell growth and division. Cells require sufficient amounts of nutrients, such as glucose, amino acids, and vitamins, to provide the energy and building blocks needed for cell growth and division. When nutrients are abundant, cells can undergo a series of metabolic reactions that ultimately lead to cell division.

Excess human growth hormone (HGH) can lead to larger cells, but it does not directly inhibit cell division. HGH can influence cell growth and metabolism, promoting the synthesis of proteins and other cellular components.

However, its effect on cell division is complex and can depend on various factors, such as the specific cell type, the presence of other signaling molecules, and the overall physiological state of the organism.

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which of the following statements is true of brain development? question 4 options: the spinal cord and brain stem grow fastest during the first year of life. the cerebellum experiences the least development in the first two years of life. the brain reaches its complete adult size by the end of gestation. the regions of the cerebral cortex that govern vision, hearing, and other sensory information grow rapidly in the first few months after birth and are mature by 6 months.

Answers

When the brain more than doubles in size in the first year, brain growth is particularly quick. A baby's brain doubles in size throughout the first year of life, during which it grows quickly. Hence (a) is the correct option.

Average adult brain size is around one-fourth the size of the average baby's brain at birth. Incredible to say, it grows by a factor of two in the first year. By the time it reaches the ages of 3 and 5, it will have grown to a size that is almost 80% of that of an adult. The human body's central processing unit is the brain. The brain grows quickly beginning before birth and continuing throughout early infancy, which is one of the key causes.

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which of the following statements is true of brain development? question 4 options:

a. the spinal cord and brain stem grow fastest during the first year of life.

b. the cerebellum experiences the least development in the first two years of life.

c. the brain reaches its complete adult size by the end of gestation.

d. the regions of the cerebral cortex that govern vision, hearing, and other sensory information grow rapidly in the first few months after birth and are mature by 6 months.

Which of the following is likely to have occurred during differentiation of an un specialized cell into a sperm cell?

Answers

Histone acetylation of the gene responsible for the production of enzymes within the acrosome is likely to have occurred during the differentiation of an unspecialized cell into a sperm cell.

What is Histone acetylation?

Histone acetylation is described aas a process that can lead to increased gene expression, which is necessary for the production of enzymes within the acrosome of a sperm cell.

Less frequently happens during the differentiation of an unspecialized cell into a sperm cell, including methylation of the gene responsible for the creation of the sperm tail and demethylation of the gene producing cortical granules.

It is also unlikely that the active site will be deleted during splicing of the acrosome proteins' pre-mRNA because the active site is necessary for the acrosome's enzymes to operate.

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Make a Slogan related to Organ Systems: Reproductive system or endocrine system or nervouse system (pick one )– roles, functions and regulation in our body.

need answer pls

Answers

Growth, fertility, and metabolism are just a few of the many facets of human behaviour that the endocrine system and nervous system jointly control. Additionally, the endocrine system is crucial to feelings.

The hormonal nervous and reproductive system: what is it?

Hormones are secreted into the blood and other bodily substances by the endocrine system. These substances are crucial for metabolism, growth, mineral and water equilibrium, and stress reaction. Hormones give the brain input to influence neural processing. The nervous system's growth is impacted by reproductive hormones.

What component is referred to as the nervous system?

A brain, spinal cord, or a sophisticated neural network are all parts of the nervous system. The brain as well as the body are communicated with via this mechanism. All bodily processes are managed by the brain. From the brain, the spinal nerve descends through the back.

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the a and the b gene both contribute to pigment production in a plant with dark purple petals; aa mutants are uniformly light purple while bb mutants have patches of purple. if the a and b genes work together to perform an essential cellular function, what progeny ratios will result when aabb is self-fertilized?

Answers

If the a and b genes work together to perform an essential cellular function, then aabb is likely to be lethal, and no viable progeny will be produced.

In genetics, the principle of dominance states that when two different alleles (versions of a gene) are present, one allele will be expressed over the other. In this case, both A and B contribute to pigment production, and therefore, they are both dominant over their respective recessive alleles, a and b.

When a plant with genotype AaBb is self-fertilized, the gametes produced will have one allele from each gene pair. The possible gametes are AB, Ab, aB, and ab. When these gametes combine, the resulting offspring can have the genotypes AABB, AABb, AaBB, AaBb, aaBB, aaBb, AAbb, and aabb.

However, if aabb is lethal, then it will not be present among the progeny. Therefore, the remaining genotypes and their corresponding phenotypes can be arranged into the following Punnett square: that the expected progeny ratios are 1:2:1 for the genotypes AABB, AABb, AaBB, and AaBb, respectively.

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blood test are only for measuring the number of red blood cells a person has. group of answer choices true false

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Blood tests are solely used to count a person's red blood cells. True. A complete blood count frequently includes a red blood cell count (CBC).

This implies that additional blood constituents are also measured. White blood cells, your hemoglobin level, and platelets are a few of them. A blood test called an RBC count counts the number of red blood cells (RBCs) in your body. Hemoglobin, an oxygen-carrying protein, is present in RBCs.

The term "mean corpuscular volume" (MCV) refers. The average size of your red blood cells is determined by an MCV blood test. Every cell in your body receives oxygen from your lungs through red blood cells. To develop, reproduce, and maintain health, your cells require oxygen.

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A scientist was studying a population of mice. In mice, the brown allele (B) has complete dominance over the white allele (b). There were 1000 mice in the population. Of these mice, 840 had brown fur and 160 had white fur. Feel free to use your notes/equations from the review to help you with this problem. What is the frequency of the recessive allele? What is the frequency of the dominant allele?

q= 0.4, p= 0.6
q= 0.6 , p= o.4
q= 0.16, p=.36
q= .36,p= 0.16​

Answers

The frequency of the recessive allele (b) can be determined using the Hardy-Weinberg equation:

p^2 + 2pq + q^2 = 1

where p is the frequency of the dominant allele (B) and q is the frequency of the recessive allele (b).

We know that 840 mice had brown fur, which means they were either BB or Bb. Since B is dominant, we know that all the BB mice will have brown fur, and only the heterozygous Bb mice will have brown fur. Therefore, the frequency of the dominant allele (B) can be calculated as follows:

p^2 + 2pq = 840/1000
p^2 + 2pq = 0.84

We also know that 160 mice had white fur, which means they were homozygous recessive (bb). Therefore, we can use this information to calculate the frequency of the recessive allele (b):

q^2 = 160/1000
q^2 = 0.16
q = sqrt(0.16)
q = 0.4

Now that we know the value of q, we can substitute it back into the first equation to solve for p:

p^2 + 2pq = 0.84
p^2 + 2p(0.4) = 0.84
p^2 + 0.8p - 0.84 = 0
(p - 0.6)(p + 1.4) = 0

Since p cannot be negative, the only valid solution is:

p = 0.6

Therefore, the frequency of the recessive allele (b) is q = 0.4, and the frequency of the dominant allele (B) is p = 0.6.

So the correct answer is option (a) q = 0.4, p = 0.6.

which of the following is not true of collecting a pediatric urine specimen? the bag is sealed and sent to the lab for testing. the bag is sealed and sent to the lab for testing. the adhesive opening must surround the urethra. the adhesive opening must surround the urethra. the perineal area needs to be cleansed before collecting the sample. the perineal area needs to be cleansed before collecting the sample. if a 24-hour specimen is needed, empty the bag into a 24-hour specimen container and attach a new bag.

Answers

The statement which is not true of collecting a pediatric urine sample is option A: the bag is sealed and sent to the lab for testing.

Using a sterile, plastic urine collection bag with a hypoallergenic skin adhesive is the proper approach to collect a kid urine sample. Before taking the sample, the perineal area needs to be thoroughly cleaned. The urethra must be encircled by the adhesive opening. Empty the bag into a 24-hour specimen container if one is required, then fasten a new bag.

A laboratory test called a 24-hour urine collection is performed to evaluate the amount of urine in a sample and assess kidney function. A 24-hour urine collection often goes like this: One or more containers will be provided to you so that you can collect and store your urine. Usually, a brown plastic container is utilised. To collect the urine, a unique pan that fits in a urinal or toilet might be employed.

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Correct question is:

which of the following is not true of collecting a pediatric urine specimen?

the bag is sealed and sent to the lab for testing.

the adhesive opening must surround the urethra.

the perineal area needs to be cleansed before collecting the sample.

if a 24-hour specimen is needed, empty the bag into a 24-hour specimen container and attach a new bag.

Please could someone tell me how to get full marks on this question?

Answers

Answer:

exercise increase breathing rate because when we are exercise our body need more oxygen than before. It is easy to check 1. do any exercise especially cardiovascular exercise without eating anything 2. during exercise your body will suffer shortage of oxygen.  Then you will start breathing fast and deeply. By this means your breathing rate will be increase. I hope it will be help you

what do you predict would happen in these new areas to the frequency of alleles controlling the colorful coral-snake-like pattern in scarlet kingsnakes as a result of this event and continued natural selection? the frequency of the alleles would decrease in this part of the kingsnake's range it is not possible to predict what would happen based upon prior evidence

Answers

The frequency of alleles controlling the colorful coral-snake-like pattern in scarlet kingsnakes. The frequency of alleles controlling a particular trait can change in response to various factors, including natural selection, genetic drift, gene flow, and mutation.

If there was a strong selective pressure against the coral-snake-like pattern in scarlet kingsnakes in these new areas, such as predators avoiding them due to their resemblance to venomous snakes, then the frequency of the alleles controlling the pattern may decrease over time through natural selection. If the coral-snake-like pattern provided some adaptive advantage, such as camouflage or warning coloration, then the frequency of these alleles may increase over time through natural selection.

It is also possible that genetic drift or gene flow may play a role in altering the frequency of these alleles in the new areas. Genetic drift occurs when chance events cause random fluctuations in allele frequencies, while gene flow occurs when individuals migrate between populations, potentially introducing new alleles or altering the frequency of existing ones.

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Peppered moths evolved due to a change in the environment in order to survive the moths had to be the same color of the environment what choice represents the correct variation adaption and environmental change

The variation is the size of the moths, the adaptation is having a larger size, and the environment that caused it was darker trees.

The variation is the color of the moths, the adaptation is having a dark color, and the environment that caused it was lighter trees.

The variation is the color of the moths, the adaptation is having a dark color, and the environment that caused it was darker trees

The variation is the color of the moths, the adaptation is having a dark color, and the environment that caused it was taller trees.

Answers

Answer:

The variation is the color of the moths, the adaptation is having a dark color, and the environment that caused it was darker trees.

Explanation:

The variation was the color because they changed color. They would adapt  and have a darker color if the environment became a darker color.

Describe, fully, how you could use a microscope to observe some blood cells.

Answers

Answer:

Place a drop of blood onto a microscope slide. Add a drop of stain to the blood to make the cells easier to see. Carefully place a coverslip over the drop of blood. Sliding it slightly along the microscope slide will spread out the blood cells making them easier to see.

Answer:

To observe blood cells using a microscope, you will need a microscope, microscope slide, cover slip, a sample of blood, and a dropper.

First, clean the microscope slide and cover slip with a cleaning solution and let them dry.Next, use a dropper to place a small drop of blood in the center of the slide.Place the cover slip over the blood drop carefully, ensuring there are no air bubbles.Place the slide on the microscope stage and secure it with the clips.Turn on the microscope and adjust the objective lens to the lowest magnification.Use the coarse adjustment knob to bring the blood cells into focus.Once you have located the blood cells, you can increase the magnification by adjusting the objective lens to a higher magnification.Observe the blood cells under the microscope and take note of their shape, size, and color.To get a better view of the blood cells, you can adjust the focus using the fine adjustment knob.Once you have finished observing the blood cells, turn off the microscope and remove the slide.

bacteria that can live in your stomach are select one: a. alkaliphiles. b. psychrophiles. c. acidophiles. d. thermophiles.

Answers

Bacteria that can live in your stomach are acidophiles.

C is the correct answer.

Microorganisms known as acidophiles thrive in extremely acidic habitats. These come in two varieties. Extreme acidophiles live in habitats with pH values below 3, while moderate acidophiles thrive in environments with pH values between 3 and 5.

Examples of acidophiles include the bacterial species Thiobacillus acidophilus, the eukaryotic species Vorticella, and the organisms Crenarchaeota. (a type of archaea).

They are used in the bioremediation procedure used on locations with acid mine drainage. They are helpful in biomining as well.

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if a transmembrane protein is synthesized with its n-terminal facing the er lumen and its c-terminal facing the cytoplasm, when the protein reaches the plasma membrane will the n-terminal be facing the extracellular space?

Answers

Yes, if a transmembrane protein is synthesized with its N-terminal facing the ER lumen and its C-terminal facing the cytoplasm, the N-terminal will be facing the extracellular space when the protein reaches the plasma membrane.

This is because during the process of protein maturation and trafficking, the transmembrane protein is inserted into the membrane with its N-terminal facing the extracellular space and its C-terminal facing the cytoplasm. This orientation is determined by specific signals within the protein sequence, which guide the protein to the correct location in the cell and ensure that it is correctly inserted into the membrane.

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if o~e molecule of glucose undergoes all the glycolytic reactions upto 3-phosphoglycerate, then stops because the phosphoglycerate mutase enzyme is inhibited (so stops after step 7), what is the net amount of atp used/produced upto this point? [hint: subtract atps used and add atps produced.]

Answers

If one molecule of glucose undergoes all the glycolytic reactions up to 3-phosphoglycerate but stops because the phosphoglycerate mutase enzyme is inhibited, the net amount of ATP used/produced up to this point is a net production of 2 ATP molecules.


Glycolytic reactions step-by-step explanation:


Step 1: Glucose is phosphorylated to glucose-6-phosphate, consuming 1 ATP.


Step 2: Glucose-6-phosphate is converted to fructose-6-phosphate.


Step 3: Fructose-6-phosphate is phosphorylated to fructose-1,6-bisphosphate, consuming another ATP.


Step 4: Fructose-1,6-bisphosphate is cleaved into two molecules: glyceraldehyde-3-phosphate and dihydroxyacetone phosphate.


Step 5: Dihydroxyacetone phosphate is converted to glyceraldehyde-3-phosphate.


Step 6: Each glyceraldehyde-3-phosphate is converted to 1,3-bisphosphoglycerate, generating 2 ATPs (1 for each molecule).


Step 7: Each 1,3-bisphosphoglycerate is converted to 3-phosphoglycerate, generating 2 more ATPs (1 for each molecule).

Now, let's calculate the net amount of ATP used/produced:
- 2 ATPs consumed in steps 1 and 3.
+ 4 ATPs produced in steps 6 and 7.
Net ATP: 4 - 2 = 2 ATPs.

So, the net amount of ATP used/produced up to this point is 2 ATPs.

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PLS HELP ME!!! THIS IS DUE TODAY!!!!!!!!!!!!!!!!!

Use the Punnett square below to answer the following questions

R = round seeds; r = wrinkled seeds; Y = yellow seeds; y = green seeds


Predict the genotypes and phenotypes of the three possible gamete combinations labeled A, B, and C in the Punnett square. Be sure to describe the seed color and shape.
A. B. C.

Answers

Punnett squares are used to get the probability of getting certain genotypes and phenotypes from a cross. A) RRYY. B) RRyy. C) RrYy

What is a Punnett square?

The Punnett square is a graphic representation that shows the different types of gamete combinations according to the alleles involved in a cross.

Punnett square shows the probabilities of getting offspring with different genotypes and their consequent phenotypes.

In the exposed example,

R = round seeds; r = wrinkled seeds; Y = yellow seeds; y = green seeds

Punnett square

          RY        Ry         rY          ry  

RY   RRYY   RRYy    RrYY    RrYy

Ry     RRYy    RRyy    RrYy      Rryy

rY      RrYY   RrYy     rrYY      rrYy

ry      RrYy     Rryy      rrYy      rryy

F1) Genotype

1/16 RRYY2/16  RRYy1/16 RRyy2/16 RrYY4/16 RrYy2/16 Rryy1/16 rrYY2/16 rrYy1/16 rryy

   

     Phenotype

9/16 round and yellow seeds, R-Y-3/16 round and green seeds, R-yy3/16 wrinkled and yellow seeds, rrY-1/16 wrinkled and green seeds, rryy

A) RRYY

B) RRyy

C) RrYy

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Science project can anyone help

Answers

Arteries differ from veins in several ways. Arteries are thick-walled, elastic vessels that carry oxygenated blood away from the heart to the body's tissues.

What is the circulatory pathway of blood through the heart?

The circulatory pathway of blood through the heart:

a) Deoxygenated blood enters the right atrium through the superior and inferior vena cava

b) The right atrium contracts and forces the blood through the tricuspid valve into the right ventricle

c) The right ventricle contracts and pumps the blood through the pulmonary valve into the pulmonary artery

d) The pulmonary artery carries the deoxygenated blood to the lungs where it picks up oxygen and releases carbon dioxide

e) The oxygenated blood returns to the heart through the pulmonary veins and enters the left atrium

f) The left atrium contracts and forces the blood through the mitral valve into the left ventricle

g) The left ventricle contracts and pumps the oxygenated blood through the aortic valve into the aorta

h) The aorta carries the oxygenated blood to the rest of the body

They have a smooth muscle layer that allows them to constrict and dilate, regulating blood flow. In contrast, veins are thin-walled vessels that carry deoxygenated blood back to the heart from the body's tissues. They have valves that prevent the backflow of blood and rely on the contraction of surrounding muscles to help move blood back to the heart.

The pathway of a breath of air from the nose to the alveoli:

a) Air enters the nasal cavity through the nostrils

b) Hairs and mucus in the nasal cavity filter and moisten the air

c) Air passes through the pharynx and larynx and enters the trachea

d) The trachea branches into two bronchi, each leading to a lung

e) The bronchi divide into smaller bronchioles and eventually lead to the alveoli

f) Gas exchange occurs in the alveoli, where oxygen diffuses into the blood and carbon dioxide diffuses out of the blood

g) The deoxygenated blood is carried back to the heart and then to the lungs to pick up more oxygen.

Three diseases of the respiratory system and their triggers/causes:

a) Asthma - caused by inflammation and narrowing of the airways in response to irritants or allergens such as pollen or dust

b) Chronic obstructive pulmonary disease (COPD) - caused by long-term exposure to irritants such as tobacco smoke or air pollution, which leads to inflammation and damage to the airways and lung tissue

c) Pneumonia - caused by infection with bacteria, viruses, or fungi, which inflame and fill the air sacs in the lungs with fluid or pus.

Organs of the excretory system and their functions:

a) Kidneys - filter blood to remove waste products and excess water, and regulate electrolyte and acid-base balance

b) Ureters - transport urine from the kidneys to the bladder

c) Bladder - stores urine until it is released from the body

d) Urethra - transports urine from the bladder to the outside of the body.

Nephrons filter blood and form urine by:

a) Glomerular filtration - blood is filtered through the glomerulus, a network of tiny blood vessels in the nephron, to remove waste products and excess water

b) Tubular reabsorption - useful substances such as glucose and amino acids

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