What makes a hypothesis testable?
A. It must be predictable.
O
B. It must be able to be proved right or wrong.
C. It must ask a scientific question.
OD. It must follow the scientific method.

Answer:

You haven't put an image so that I can determine your answer

Explanation:

Answer:

Point A represents a location on a tectonic plate boundary. Plates X and Y represent major tectonic plates. The island of Crete; the Anatolian Plate, which is a minor tectonic plate; and the Hellenic Trench have been labeled. Arrows indicate the relative directions of plate motion.

Explanation:

the answer I think is the metamorphic rock

Answer:

metamorphic

Explanation:

sedimentary rocks under heat and pressure form metamoephoc rocks

If 87 grams of K₂SO₄ is dissolved in enough water to make 250 milliliters of solution,  the concentrations of the potassium [K⁺] is 4 M and the sulfate ions [SO₄²⁻] is 2 M.

The molar mass of the  K₂SO₄ = 174 g/mol

The mass of the  K₂SO₄ = 87 g

the moles of the  K₂SO₄ = 87 / 174

                                         = 0.50 mol

moles of K⁺ = 0.50 × 2

                    = 1 mol

moles of SO₄²⁻ = 0.50 × 1

                          = 0.50

The concentration of [K⁺] = 1 / 0.250 = 4 M

The concentration of [SO₄²⁻] =  0.50 / 0.250 = 2 M

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Mole measure the number of elementary entities of a given substance that are present in a given sample. Therefore, 25.98g/mol is the molar mass of the unknown acid that was dissolved.

The SI unit of amount of substance in chemistry is mole. The mole is used to measure the quantity or amount of substance. We know one mole of any element contains 6.022×10²³ atoms which is also called Avogadro number.

Mathematically,

mole =given mass ÷ molar mass

Molar mass of  unknown acid= ?

mass of  unknown acid= 0.178 grams

moles of  unknown acid= 0.00685 moles

Substituting the values in above formula we get

0.00685  = 0.178  ÷ molar mass

molar mass=25.98g/mol

Therefore, 25.98g/mol is the molar mass of the unknown acid that was dissolved.

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The importance of the carbon dioxide, CO₂ and the oxygen O₂ in the water is they both are important for the aquatic animals and for the aquatic plant.

The CO₂ and O₂ are both important for the aquatic animals and also for the aquatic plants. the concentration of the oxygen in to the water is important for the aquatic animals that the dissolved oxygen for the respiration. the carbon dioxide will be more soluble in water than the oxygen in the water.

The carbon dioxide forms the carbonic acid in the water. the carbon dioxide is useful for the aquatic plants for the growth.

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The product could have been lost if this experiment was conducted in a physical laboratory: Human Error, Incomplete Reaction, Inadequate Stirring, Impurities and Loss of Product.

Product is a tangible or intangible good that is produced for sale on the market.

1. Human Error: Inaccurate measurements or miscalculations during the experiment may have caused the percent yield not to be 100%.
2. Incomplete Reaction: Depending on the reaction conditions, it is possible that the reaction did not go to completion, leading to a lower percent yield than expected.
3. Inadequate Stirring: If the reactants were not adequately mixed during the experiment, some reactants may not have been able to properly react, resulting in a lower percent yield.
4. Impurities: If the reactants used in the experiment were impure, it could lead to a lower percent yield due to the presence of undesirable substances that can interfere with the reaction or are not involved in the reaction.
5. Loss of Product: If the experiment was conducted in a physical laboratory, it is possible that some of the product was lost during the experiment due to improper handling or other factors.

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Answer:

what do u need help with sir

Answer:

mettaliods

Explanation:

It has the both property of metal and non metal so it is called mettaliod.

Answer:

metalloids

Explanation:

they are solid at roomtempreture and alloys with metals.

examples boron,silicon,arsenic,tellurium

Option B, Using an excess of aldehyde in the aldol-dehydration reaction is done primarily to ensure complete conversion of the reactants to the desired product.

An excess of aldehyde is used to ensure that there is a sufficient concentration of the aldehyde present in order to form the enolate anion, which is the reactive intermediate in the aldol-dehydration reaction. To achieve high yield: Using an excess of aldehyde allows for the formation of multiple enolate anions, which increases the chances of a double aldol-dehydration reaction taking place, resulting in the formation of the desired product. Using an excess of aldehyde helps aldol-dehydration to prevent this by reducing the exposure of the aldehyde to air.

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Answer:

yes

Explanation:

60/500 is less than 133/1000 meaning that the glucose will be able to disolve without a salute

The total number of moles contained in 115 grams of C₂H5OH is 2.50 moles .

The term "mole" refers to the quantity of a substance that has the same amount of subatomic particles (ions, molecules, or atoms) as there are carbon atoms.

Atomic weight of carbon(C)= 12 gm

Atomic weight of Hydrogen (H)=1 gm

Atomic weight of oxygen (o)=16 gm

∴Molecula weight of C2H5OH =(12×2 + 1×6 + 16×1) gm

24 + 6 + 16 gm = 46 gm

∴ 46 gm of C2H5OH contains 1 mole

1 gm of C2H5OH contain = 1/46 moles

115 gm of C2H5OH contains = 115×1/46 moles

⇒2.5 moles

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Answer:

One problem that people may encounter when using a hot and cold compress pillow is that the pillow may not stay hot or cold for a long enough period of time. This can be frustrating for people who are using the pillow to alleviate muscle pain or reduce inflammation, as they may need to continually reheat or refreeze the pillow in order to maintain its therapeutic benefits. To solve this problem, people may need to find a pillow that is better at retaining heat or cold, or they may need to use additional heating or cooling elements (such as hot water bottles or ice packs) in conjunction with the pillow.

Explanation:

Answer:

Freezing T° of solution = - 3.72°C

Boiling T° of solution =  101.02°C

Explanation:

To solve this we apply colligative properties. Firstly, freezing point depression:

ΔT = Kf . m . i

ΔT = Freezing T° of pure solvent - Freezing T° of solution

Kf = Cryoscopic constant, for water is 1.86 °C/m

m = molality (moles of solute in 1kg of solvent)

i = Ions dissolved in solution

Our solute is sucrose, an organic compound so no ions are defined. i = 1.

Let's determine the moles: 68.4 g . 1mol/ 342g = 0.2 moles

molality = 0.2 mol / 0.1kg of water = 2 m

We replace data: ΔT = 1.86°C/m . 2m . 1

Freezing T° of solution = - 3.72°C

Now, we apply elevation of boiling point: ΔT = Kb . m . i

ΔT = Boiling T° of solution - Boiling T° of  pure solvent

Kf = Ebulloscopic constant, for water is 0.512 °C/m

We replace:

Boiling T° of solution - Boiling T° of pure solvent = 0.512 °C/m . 2 . 1

Boiling T° of solution = 0.512 °C/m . 2 . 1 + 100°C → 101.02°C

Answer:

convection

Explanation:

Oxidation of methane to soot:

CH4(g)+O2(g)⟶C(s)+2H2O(g)

Among the hydrocarbons is methane, CH4(g). Only the elements carbon (C) and hydrogen (H) are present in the complex. When methane burns with too much oxygen, it produces water vapor and carbon dioxide gas CO2(g) (g). Complete combustion is defined as combustion with extra oxygen.

Methane can be partially oxidized into a variety of compounds when it is burned inefficiently, including CO, methanol, formic acid, formaldehyde, and higher hydrocarbons.

Carbon monoxide is an extremely toxic gas. It is invisible and odorless. Without anybody being aware of it, malfunctioning gas fireplaces or boilers can poison the air in a room by emitting carbon monoxide.

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The complete question is

Problems that can be caused by both the complete and incomplete

combustion of methane in a gas fire.

The major organic product of this reaction is 2-bromobutane, a saturated hydrocarbon with a bromine atom attached to the second carbon atom.

The major organic product is 2-bromobutane.

Structure:

CH3 CH2 CH2 CH2 Br

    |   |   |

    CH3 CH2 Br

1) The reaction begins with bromine reacting with the 2-methylpropane molecule to form the intermediate 2-bromo-2-methylpropane.

2) The intermediate then reacts with hydroxide ions to form the final product, 2-bromobutane.

3) The final product is a saturated hydrocarbon with a bromine atom attached to the second carbon atom.

The major organic product of this reaction is 2-bromobutane, a saturated hydrocarbon with a bromine atom attached to the second carbon atom.

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Answer:

8

Explanation:

Its official chemical symbol is O, and its atomic number is 8, which means that an oxygen atom has eight protons in its nucleus

If the molecular weight is 230.26 g/mol carbon = 73.03% = 230.26*73.03/100 = 168.15/12 = 14 Carbons Hydrogen = 6.13% = 230.26*6.13/100 = 14/1 = 14 Hydrogens Oxigen = 20.84% = 230.26*20.84/100 = 47.98/16 = 3 Oxygens Hence the empirical formula is C14H14O3

The International System for Units (SI) defines the newton as the unit of force, which is used to measure weight. For instance, a kilogram of matter weighs around 9.8 newtons on Earth's surface and around each as much on Moon.

Weight, which is expressed in newtons, is a unit of measurement for the gravitational force acting on an object. The mass of a bird with a mass of 15 g changes with the strength of the gravity influence acting on it, and would differ significantly if it were measured, for instance, on the Moon rather than on Earth.

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After solving the equation: The half-life for this reaction is 0.693/0.271 = 2.56 s.

Reaction is the response of a system to an external or internal stimulus. It is the way a person or object behaves in response to a change in their environment. Reactions can be physical, chemical, or psychological. Physical reactions involve changes in the body, such as muscle tension, sweating, or heart rate.

The half-life for this reaction is the time it takes for the concentration of molecular iodine to decrease by a factor of 2, or for half of the original amount of molecular iodine to react. This can be calculated using the equation:

T1/2 = 0.693/k

where k is the first-order rate constant.

Therefore, the half-life for this reaction is 0.693/0.271 = 2.56 s.

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Answer:

29.07778262 (i don't know what you have to round to, but just be aware of rounding)

Explanation:

to answer this you have to convert both elements into grams, you do this by finding their atomic weight on a periodic table then multiplying it by how many moles of the molecule you have, k=39.098 and S=32.06, so you have to multiply k by two since you have two moles, so now you know that k2=78.196. then add the two amounts together to get the total weight of the compound, 110.256, now that you have that you can create a proportion to solve for the percent, the proportion is equal to the mass of one element, in this case S, over the total weight of the compound, 110.256. then divide [tex]\frac{32.06}{110.256}[/tex] =.290777... this is your percent in decimal form, so multiply by 100 to get you percentage.

if you have any questions, leave them in the comments and i will try to answer them, if this helped, pls give brainliest

The limiting reactant, O₂, forms 2.7 mole Al₂O₃. Therefore, the mass of Al₂O₃ is 280 g.

The term mole (M) is defined as the amount of substance in a system which include as many elementary entities as there are atoms present in it. It is denoted by the symbol “mol”. The word mole is coming from the Latin word moles, which means “a mass”.

Molar Mass of Al₂O₃ = 101.96 g/mol

2.7 mole Al₂O₃          101.96 g

------------------------  x  -------------------    

             X                       1 mole

= 280 g Al₂O₃

Thus, The limiting reactant, O₂, forms 2.7 mole Al₂O₃. Therefore, the mass of Al₂O₃ is 280 g.

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When only 1 mol of oxygen was intended to be produced, a process instead yields 4.93 L of oxygen. The percent yield of the reaction is 493%.

Percent yield is a measure of how much of the desired product is produced in a chemical reaction. It is calculated by comparing the actual yield of a product to the theoretical yield, which is the amount of product that would be produced if the reaction were 100% efficient.

To calculate the percent yield, you can use the formula:

= percent yield

= (actual yield / theoretical yield) x 100%

The theoretical yield of a reaction is calculated by multiplying the number of moles of reactant used by the stoichiometry of the reaction. In this case, the reaction is supposed to produce 1 mol of oxygen, which is the theoretical yield. To calculate the actual yield, we can use the Ideal gas law PV = nRT, where P is the pressure, V is the volume, n is the number of mol. Since we know that V = 4.93 L, we can use this information to find n:

= n

= (PV) / RT

The actual yield is 4.93 L of O2 or 4.93 L of any gas at STP (Standard Temperature and Pressure) is equivalent to 4.93 moles of O2.

Then we can use this information to calculate the percent yield:

= percent yield

= (actual yield / theoretical yield) x 100%

= (4.93 moles O2 / 1 mole O2) x 100%

= 493%

So, the percent yield of the reaction is 493%.

It's important to note that a percent yield of greater than 100% is usually an indication of an error in the measurement or calculation of the actual yield, or it could be an indication that the theoretical yield is incorrect.

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Answer:

C) N2O5

Explanation: