Answer:
B) -2
Step-by-step explanation:
[tex]log_{6} \frac{1}{36}[/tex] ORIGINAL
[tex]log_{6} 6^{-2}[/tex] REWRITE 1/36
-2 LOG RULE - 6's CANCEL
Hope this helsp!
A triangle is dilated by a scale factor of n = one-third. which statement is true regarding the dilation? it is a reduction because n > 1. it is a reduction because 0 < n < 1. it is an enlargement because n > 1. it is an enlargement because 0 > n > 1.
The second statement is true. It is a reduction because 0 < n < 1.
What is dilation?
Dilation means changing the size of an object without changing its shape. The size of the object may be increased or decreased based on the scale factor.
Given: A triangle is dilated by a scale factor of n = 1/3. As n is less than 1 but greater than 0.
A dilation is a rigid transformation that forms an image that is the same shape as of the original figure but with a different size. A dilation transforms a figure by scalar factor 'n' about the center of dilation is a fixed point in the plane which never changes.
A dilation that forms a larger image is known as enlargement. A dilation that forms a smaller image is known as reduction.
• If n is greater than 1, then the image is an enlargement.
• If n is between 0 and 1, then the image is a reduction.
• If n is 1, the figure and then the image is exactly the same.
Hence the second statement is true. It is a reduction because 0 < n < 1.
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Which function in vertex form is equivalent to f(x) = x2 x 1? f(x) = (x one-quarter) squared three-quarters f(x) = (x one-quarter) squared five-quarters f(x) = (x one-half) squared three-quarters f(x) = (x one-half) squared five-quarters
The function in vertex form is equivalent to [tex]\rm y = (x + 2/4)^2 + \frac{3}{4}[/tex].
What are quadratic equations?A quadratic equation is an equation of degree 2 in other words.Quadratic equations have the form ax² + bx + c = 0 and are second-degree algebraic expressions.
The standard quadratic function with vertex (h, k) is ;
[tex]\rm y = a(x - h)^2 + k[/tex]
The general quadratic equation is found as;
[tex]\rm y = ax^2 + bx + c[/tex]
The value of h is given as;
[tex]\rm h = \frac{-b}{2a}[/tex]
For the given equation in the problem;
[tex]\rm y = x^2 + x + 1[/tex]
The value of the k is found by;
[tex]\rm y =( \frac{-1}{2}) ^2 - \frac{1}{2} + 1 \\\\ y= \frac{1}{4} - \frac{1}{2}+ 1 \\\\ y= \frac{1}{4}- \frac{2}{4}+ \frac{4}{4}\\\\ y= \frac{3}{4}[/tex]
So the vertex is at [tex]\frac{-2}{4}[/tex] and [tex]\frac{1}{4}[/tex] then the vertex form is:
[tex]y = (x +\frac{2}{4} )^2 + \frac{3}{4}[/tex]
Hence the functions in vertex form are equivalent [tex]\rm y = (x + 2/4)^2 + \frac{3}{4}[/tex].
To learn more about the quadratic functions refer to the link;
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Answer: OPTION 3
Step-by-step explanation:
Mr. Jones sold two pipes at $1.20 each. Based on the cost, his profit one was 20% and his loss on the other was 20%. On the sale of the pipes, he:
(a) broke even,
(b) lost 4 cents,
(c) gained 4 cents,
(d) lost 10 cents,
(e) gained 10 cents
two pipes= $1.20
solution:Selling price of the first pipe = $1.20
Profit = 20%
Let’s try to find the cost price of the first pipe
CP = Selling price - Profit
CP = 1.20 - 20% of CP
CP = 1.20 - 0.20CP
CP + 0.20CP = 1.20
1.20CP = 1.20
CP = 1.20/1.20
CP = $ 1
Selling price of the Second pipe = $1.20
Loss = 20%
Let’s try to find the cost price of the second pipe
CP = Selling price + Loss
CP = 1.20 + 20% of CP
CP = 1.20 + 0.20CP
CP - 0.20CP = 1.20
0.80CP = 1.20
CP = 1.20/0.80
CP = $1.50
Therefore, total cost price of the two pipes
= $1.00 + $1.50
= $2.50
And total selling price of the two pipes
= $1.20 + $1.20
= $2.40
Loss = $2.50 – $2.40 = $0.10
Therefore, Mr. Jones loss 10 cents.
answer= option d.
Q: The ratio of the numbers of Nick's marbles to Michael's is 3:5. Nick has 36 marbles. If Nick receives
another 9 marbles, what will be the new ratio of the number of Nick's marbles to Michael's?
Answer:
[tex]\frac{3}{4}[/tex]
Step-by-step explanation:
[tex]\frac{3}{5} = \frac{36}{x}[/tex]
3x = 36 x 5
3x = 180
x = 60
Michael has 60 marbles.
Nick recieves 9 more marbles so he has 36 + 9 = 45 marbles
The new ratio will be:
[tex]\frac{45}{60}[/tex] = [tex]\frac{3}{4}[/tex]
A waitress earned a 18% tip.What decimal is equivalent to 18%
0.18
Step-by-step explanation:Percentages and decimals are closely related. As a matter of fact, we don't need to use any actual math to solve this question because there is a shortcut.
Answer by Dividing
One way to solve the question is by dividing. Percentages are numbers that represent a portion of 100. So, to find the decimal form we can divide the percentage by 100.
18/100 = 0.18Shortcut
While dividing by 100 can work, there is an easier way to find the decimal form. Dividing by 100 will always be equivalent to moving the decimal point 2 digits to the left.
This means that 18.0 becomes 0.18 when using this shortcut.What is the volume of the rectangular prism?
write the equation from each line, Plus helpp
Answer:
the slope u find by looking for where the line hits an exact + and the y-int is where the line touches the y-axis
1. A cake recipe requires 4 cups of flour to make 12 cupcakes. Using the same cake recipe, what is the amount of flour needed for 1 cupcake?
Answer:
1/3rd a cup
Step-by-step explanation:
make me brainly
A tunnel with a parabolic arch is 12 m wide. If the height of the arch 4 m
from the left edge is 6 m, can a truck that is 5 m tall and 3.5 m wide pass
through the tunnel? Justify your decision.
Check the picture below.
A closed cylinder has how many faces ?
Answer:
3 faces
A cylinder has 3 faces - 2 circle ones and a rectangle (if you take the top and bottom off a tin can then cut the cylinder part on the seam and flatten it out you would get a rectangle). It has 2 edges and no vertices (no corners).
Step-by-step explanation:
[tex] \huge\fbox\blue{ANSWER} [/tex]
A cylinder has 3 faces - 2 circle ones and a rectangle
What is the surface area of the prism?
Length: 15mm
Width: 3mm
Height: 4mm
Answer:
234mm
Step-by-step explanation:
Use the box method to distribute and simplify (5x+2)(3x+3)
Answer:
3(5x^2+7x+2)
Step-by-step explanation:
(5x+2)(3x+3)
I use the foil method, but if you need to use a different method you can look online at how it is done, but this should give you the correct answer.
First
Outside
Inside
Last
First you multiply 5x and 3x together (the first values in each bracket), which gives you 15x squared (15x^2)
Then you multiply the 5x and 3 (the values on the "outside" of the equation --> first and last) which gives you 15x
Then you multiply the "inside" values (the ones in the middle of all the terms), which is 2 and 3x, and gives you 6x
Last you multiply the 2 values that are last in each bracket, 2 and 3, which gives you 6
So then you put then in order of the exponent
15x^2+15x+6x+6
Then you collect like terms (which means terms that have the same number of the variable) and you're left with the answer
15x^2+21x+6
Then most likely you need to further simplify and you can common factor a number out (take the highest number that evenly mutiplies into each term and divide it out of each), so that you have,
3(5x^2+7x+2)
45/8 ÷ 11/9 in simplest form
Answer:
high chance tat it is 405/88. mixed farction = 4 53/88
Step-by-step explanation:
Pls pls pls help ill give you whatever :(
Answer:
I'm not positive but it should be 16/625
Step-by-step explanation:
if it is brainlist would be nice
y
=
x
−
1
and
y
=
−
5
x
−
13
?
Answer:
x = -3
y = 2
Step-by-step explanation:
Solve for the first variable in one of the equations, then substitute the result into the other equation.
Point Form:
(-3,2)
Equation Form:
x = -3, y = 2
Why is V10 equal to 5
You roll a die repeatedly, stopping when you roll a 1. Your score is the sum of values of all your rolls. What is the expected score
Using the binomial distribution, it is found that the expected score of the game is of 21.
What is the binomial probability distribution?It is the probability of exactly x successes on n repeated trials, with p probability of a success on each trial.
The expected number of trials until q successes is:
[tex]E_s(X) = \frac{q}{p}[/tex]
In this problem, a die has a p = 1/6 probability of resulting in a 1, hence the expected number of trials is:
[tex]E_s(X) = \frac{1}{\frac{1}{6}} = 6[/tex]
In each trial, each outcome from 1 to 6 is equally as likely, hence the expected score of a single trial is given by:
[tex]E = \frac{1 + 6}{2} = 3.5[/tex]
Then, the expected score of the six trials is:
6 x 3.5 = 21.
More can be learned about the binomial distribution at https://brainly.com/question/24863377
A confidence interval is constructed to estimate the value of.
Pls answer quick;-; 20 points!
The top and bottom lines are parallel. What is the value of x?
A. 105
B. 45
C. 100
D. 65
Answer:65
Step-by-step explanation:
Hi
It’s 65 bc 35+80= 115. And triangles are 180° so 115-180= 65.
Hope it helped
Answer:
65
Step-by-step explanation:
The value of 35 degrees can be translated from the opposite diagonal. Adding the 80 degrees and 35 degrees equals 115 degrees. Finally find the remainder 180-115= 65
A circular piece of fabric has a radius of 1. 2 ft. The fabric sells for $5. 40 per ft². What is the total cost of the circular piece of fabric? use 3. 14 for pi. $6. 48 $20. 35 $24. 42 $40. 69.
Answer:
$24.42
Step-by-step explanation:
3.14*r^2= area
3.14*1.2^2=4.52
5.40*4.52=24.42
Answer:
Step-by-step explanation:
Remark
First find the area of the circular piece of fabric. Then deal with cost per square foot.
Area of the fabric
Area = pi * r^2
Area = 3.14 * 1.2^2
Area = 3.14 * 1.44
Area = 4.5216 square feet
Cost
1 square foot costs 5.40 dollars
4.5216 square feet costs x Cross multiply
x = 5.40 * 4.5216
Answerx = 24.42 dollars for the fabric bought.
GIVING BRAINLEST TO THE PERSON THAT CAN EXPLAIN HOW TO DO THIS THE BEST :)
At his school's book fair, Tristan paid $37.70 for 5 books by his favorite author. Each book would have cost $9 if he had purchased it online instead. In all, how much more money would Tristan have paid if he had purchased the books online?
Answer:
$7.30
Step-by-step explanation:
All you have to do is 9 x 5= 45
Then 45 - 37.70= 7.30
HGD
-ghost
Tristan would have paid $7.3 more, if he had purchased the books online.
What is the unitary method?The unitary method is a technique for solving a problem by first finding the value of a single unit, and then finding the necessary value by multiplying the single unit value.
Given that, Tristan paid $37.70 for 5 books by his favorite author.
Each book would have cost $9 if he had purchased it online instead.
Total money paid to purchase books online = 5×9
= $45
Difference in cost = 45-37.70
= $7.3
Therefore, Tristan would have paid $7.3 more, if he had purchased the books online.
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Derek is hang gliding on a clear day at an altitude of a feet. His visibility, v, is 67.1 mi. Use the formula v = 1.225 to find the altitude at which Derek is hang gliding.
Step-by-step explanation:
since the equation is v = 1.225 × sqrt(a)
we can plug in the known values to find the altitude.
so:
(67.1/1.225)^2 = a
a = 3000
Base on the visibility formula v = 1.225√a, the altitude at which Dereck is hang gliding is 7.4 miles
How to find altitude using visibility formula?The visibility formula is given as follows:
v = 1.225√a
where
a = altitudev = visibilityTherefore,
v = 67.1 miles
v = 1.225√a
67.1 = 1.225√a
divide both sides by 1.225
√a = 67.1 / 1.225
√a = 54.7755102041
square both sides
√a² = √54.7755102041
a = 7.40104789878
a = 7.4 miles
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whats the answer to 98÷24
Solve for x: 5-(x + 5) >-2(x + 4)
x>-8
x<-8
x>-18
x<-18
Cooper asked his classmates, "How many days do you floss your teeth in a
typical week?" The table shows Cooper's data.
How many observations did he record?
A. 24
B. 7
C. 27
D. 21
Answer:
D
Step-by-step explanation:
Each box represents one observation.The data table is 7 boxes by 3 boxes. 7 * 3 is 21, so the answer is D.
Hope this helps :)
Have a nice day!
I need help finding this answer, check the screenshot for all the info
need this question now I think it's only a good answer
For ellipses:
-First, let's use completing the square method to determine values of a(semi-major axis), b(semi-minor axis), and the coordinates of the center of the ellipse.
[tex]\mathsf{x^2+4y^2-10x-24y+45=0}[/tex][tex]\mathsf{x^2-10x+4y^2-24y=-45}[/tex][tex]\mathsf{(x^2-10x)+4(y^2-6y)=-45}[/tex][tex]\mathsf{(x^2-10x+25)+4(y^2-6y+9)=-45+25+4(9)}[/tex][tex]\mathsf{(x-5)^2+4(y-3)^2=16}[/tex][tex]\mathsf{\dfrac{(x-5)^2}{16}+\dfrac{(y-3)^2}{4}=1}[/tex][tex]\mathsf{\dfrac{(x-5)^2}{(4)^2}+\dfrac{(y-3)^2}{(2)^2}=1}[/tex]-The center of the ellipse is at C(5, 3), semi-major axis, a = 4, and semi-minor axis, b = 2.
-Since the major axis of the ellipse is horizontal, the distance between the center of the ellipse and the co-vertices of the ellipse is ±b.
[tex]\mathsf{CoV_1=(5,3+b)}[/tex][tex]\mathsf{CoV_2=(5,3-b)}[/tex]-The coordinates of the co-vertices of the ellipse are:
[tex]\mathsf{CoV_1=(5,3+2)} \longrightarrow \mathsf{CoV_1=(5,5)}[/tex][tex]\mathsf{CoV_2=(5,3-2)} \longrightarrow \mathsf{CoV_2=(5,1)}[/tex]For the parabola:
-We have the following data:
The parabola is opening to the left and axis symmetry along the major axis of the ellipse (axis of symmetry: y = 3):
[tex]\mathsf{(y-k)^2=-4a(x-h)}[/tex]The focus of the parabola is the center of the ellipses.
F = (5, 3)-The parabola is passing through the co-vertices of the ellipse:
-The parabola is passing through poînts (5, 5) and (5, 1)
-From the first data, we know that the value of k is equal to 3 because the axis of symmetry of the parabola is y = 3.
[tex]\mathsf{(y-3)^2=-4a(x-h)}[/tex]-From the second data, we know that the x-coordinate of the vertex is at h = 5 + a. (Note: the distance of the focus of the parabola and the vertex of the parabola is equal to ±a, since the parabola is opening the the left we use -a)
[tex]\mathsf{F=(5,3)}[/tex]
[tex]\mathsf{F=(h-a,k)}[/tex][tex]\mathsf{5=h-a}[/tex][tex]\mathsf{h=5+a}[/tex][tex]\mathsf{V=(h,k)}[/tex][tex]\mathsf{V=(5+a,3)}[/tex]-Substitute the coordinates of the vertex of the parabola
[tex]\mathsf{(y-3)^2=-4a[x-(5+a)]}[/tex][tex]\mathsf{(y-3)^2=-4a(x-5-a)}[/tex][tex]\mathsf{(y-3)^2=-4ax+20a+4a^2}[/tex]-From the third data, we know that if the poînts lies on the parabola, the coordinates of the poînts must satisfy the equation of the parabola.
Using the point (5, 5), x = 5, y = 5:
[tex]\mathsf{(y-3)^2=-4ax+20a+4a^2}[/tex][tex]\mathsf{(5-3)^2=-4a(5)+20a+4a^2}[/tex][tex]\mathsf{4=-20a+20a+4a^2}[/tex][tex]\mathsf{4a^2=4}[/tex][tex]\mathsf{a^2=1}[/tex][tex]\mathsf{a=1}[/tex]-Another way to solve for the value of a is using the formula for the length of the latus rectum (LR = 4a). Since the length of the latus rectum is equal to the minor axis of the ellipse, we can easily solve for the value of a.
[tex]\mathsf{LR=4a}[/tex][tex]\mathsf{4=4a}[/tex][tex]\mathsf{a=1}[/tex]-Substitute the value of a in the equation:
[tex]\mathsf{(y-3)^2=-4a[x-(5+a)]}[/tex][tex]\mathsf{(y-3)^2-4(1)[x-(5+1)]}[/tex][tex]\mathsf{(y-3)^2=-4(x-6)}[/tex][tex]{\boxed {\red{{\mathsf{(y-3)^2=-4(x-6)}}}}}[/tex](ノ‥)ノ
The radius of a circle is 2.6 ft. Find the circumference
to
the
nearest
tenth
to the nearest tenth.
Answer:
16.3 ft
Explanation:
circumference of circle = 2πr ( r is the radius )
Here radius = 2.6 ft
Circumference:
2 * π * 2.65.2 π16.3 ftDigram :
[tex] \setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\qbezier(2.3,0)(2.121,2.121)(0,2.3)\qbezier(-2.3,0)(-2.121,2.121)(0,2.3)\qbezier(-2.3,0)(-2.121,-2.121)(0,-2.3)\qbezier(2.3,0)(2.121,-2.121)(-0,-2.3)\put(0,0){\line(1,0){2.3}}\put(0.5,0.3){\bf\large 2.6ft\ cm}\end{picture}[/tex]
[tex] \\ \\ [/tex]
Given :
radius of circle = 2.6 ft[tex] \\ \\ [/tex]
To find :
Circumference = ?[tex] \\ \\ [/tex]
Solution :-
We know :
[tex] \boxed{ \rm Circumference_{(\sf circle)} = 2\pi \: radius}[/tex]
[tex] \\ [/tex]
So:-
[tex] \dashrightarrow\sf Circumference_{(\sf circle)} = 2\pi \: radius \\ [/tex]
[tex] \\ \\ [/tex]
[tex] \dashrightarrow\sf Circumference_{(\sf circle)} = 2 \times \dfrac{22}{7} \times 2.6\\ [/tex]
[tex] \\ \\ [/tex]
[tex] \dashrightarrow\sf Circumference_{(\sf circle)} = 2 \times \dfrac{22}{7} \times \dfrac{26}{10} \\ [/tex]
[tex] \\ \\ [/tex]
[tex] \dashrightarrow\sf Circumference_{(\sf circle)} =\dfrac{44}{7} \times \dfrac{26}{10} \\ [/tex]
[tex] \\ \\ [/tex]
[tex] \dashrightarrow\sf Circumference_{(\sf circle)} =\dfrac{1144}{7 \times 10} \\ [/tex]
[tex] \\ \\ [/tex]
[tex] \dashrightarrow\sf Circumference_{(\sf circle)} =\dfrac{1144}{70} \\ [/tex]
[tex] \\ \\ [/tex]
[tex] \dashrightarrow\bf Circumference_{(\bf circle)} =16.34~ft\{approx\} \\ [/tex]
Can you help me solve this two questions please??? :(