What is the Hairdryer energy transfers

Answer:

the last one: weight force

Since torque is directly proportional to body mass, while the lever arm remains fixed and the mass of the stone grows, so does the torque.

Lever:

Lever is a type of simple machine composed of a stiff beam and a fulcrum. The fulcrum is the point on which the beam pivots. The effort and load are delivered to either end of the beam. A load is applied to the opposite end of a lever when force is applied to the one end.

The three classes of levers are first, second, and third class levers.

The fulcrum of superior levers is positioned between the weight and the effort.

Levers of inferior quality with weight between the fulcrum and the effort

Third-class levers need effort between movements fulcrum and load.

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Answer:

2 inches

Explanation:

Volume of a sphere = 4/3  pi r^3

   for the EIGHT balls   total volume =   8  *  4/3 pi (1^3) = 32/3 pi

This is the volume of the made-up ONE ball

    4/3 pi r^3  = 32/3 pi

       4/3 r^3 = 32/3

            r^3 = 32/3  * 3/4

             r^3 = 8

              r = 2 inches

Important Formulas:

[tex]v=\dfrac{d}{t}[/tex]

velocity(measured in m/s) = distance(measured in meters) / time(measured in seconds)

__________________________________________________________

Given:

[tex]d=15m[/tex]

[tex]t=3s[/tex]

[tex]v=?[/tex]

__________________________________________________________

Finding velocity:

[tex]v=\dfrac{d}{t}[/tex]

[tex]v=\dfrac{15}{3}[/tex]

__________________________________________________________

[tex]\fbox{v = 5 m/s}[/tex]

The tides are considered an example of shallow-water waves because the tidal bulges have a wavelength that is on the order of thousands of kilometers.

Complete Response.The tides are caused by the sun and moon's tremendous gravitational pulls on the surface of the planet, which is the right answer.

Response and Justification:Tides are not primarily caused by the gravitational influence of the sun, as is commonly believed.In reality, the Moon's gravitational pull is what mostly causes tides.

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Answer:

a) The direction of the current in the copper rod that causes the springs to stretch is left-to-right. This is because the magnetic field is oriented perpendicular to the surface of the table and the force exerted on the rod by the magnetic field is given by F = qVB, where F is the force, q is the charge of the particle, V is the velocity of the particle, and B is the strength of the magnetic field. Since the force is perpendicular to the velocity of the particle, the direction of the current that produces this force must be parallel to the magnetic field. In this case, the magnetic field is oriented perpendicular to the surface of the table, so the current must flow in the direction left-to-right to produce a force that stretches the springs.

b) To find by how much each spring stretches, you can use the formula F = kx, where F is the force exerted by the spring, k is the spring constant, and x is the distance the spring stretches. In this case, the force exerted by the spring is given by F = qVB, and the spring constant is k = 76 N/m. The charge of the particle is q = Ie, where I is the current and e is the charge of an electron. The velocity of the particle is V = L / t, where L is the length of the rod and t is the time it takes the particle to travel the length of the rod. Since the current is 14 A and the length of the rod is 0.77 m, the velocity of the particle is V = 0.77 m / (1 / 14 A) = 10.78 m/s. The strength of the magnetic field is 0.14 T, so the force exerted by the spring is F = (14 A)(1.60 x 10^-19 C)(10.78 m/s)(0.14 T) = 2.40 x 10^-17 N. Therefore, the distance each spring stretches is x = F / k = 2.40 x 10^-17 N / 76 N/m = 3.16 x 10^-19 meters.

Answer: The distance between the objects

Explanation:

The film strip that emerges from the camera is usually a Negative. That is, its color and light values are the opposite of those in the original scene.

One of the three camera settings that affects exposure is the aperture. The shutter speed, aperture, and ISO settings are together referred as as the "exposure triangle." By adjusting the relative amount of light entering a camera lens, an aperture can change the exposure.

A camera's shutter can close or open depending on how much light is required to expose the film at the rear of the device.

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Answer:2.30

Explanation:

Answer:

Explanation:

Some harmful environmental factors can change the nucleotide sequence of a gene. UV rays, for example, can harm DNA strands.

Genetic variations arise during meiosis as a result of mutation and recombination. Chemical or biological mutagens frequently result in mutations. The genetic diversity of organisms is also altered by accidental mating.

The length at which you want to wear your hair. Scars – from your own unique accidents. The strength of your muscles depends on how much exercise you get. Piercings, whether you decide to have them or not. Mutations are the primary cause of the emergence of genetic variation.

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The magnitude of force, must an 82.5-kg grouper exert to stay submerged in salt water is 8.12 N.

To find the magnitude of force that the grouper must exert to stay submerged, we can use the buoyancy force equation, which states that the buoyancy force is equal. The buoyancy force is equal to the weight of the fluid displaced, which is the density of the fluid multiplied by the volume of the fluid displaced and the gravitational acceleration. The volume of the fluid displaced is equal to the volume of the object and can be found using the equation of volume of an object. The weight of the object can be found by multiplying the mass of the object and the gravitational acceleration.

The net force on the object is the difference between the buoyancy force and the weight of the object.

= Fb

= V * (density of fluid - density of object) * g

= Fb

= (82.5 kg / (1015 kg/m3) ) * (1025 kg/m3 - 1015 kg/m3) * 9.8 m/s^2

= Fb

= 8.12 N

The magnitude of force that the grouper must exert to stay submerged is 8.12 N

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Hydroelectric power accounts for between 16 and 17 percent of global electricity production, making it one of the most significant renewable energy sources.

In 2016, hydropower contributed more than twice as much to the grid as the next largest renewable energy source, solar. Hydropower can provide many valuable services to the power grid beyond just energy generation. These include frequency regulation, voltage support, contingency reserves, load following, and black start service, all of which contribute to the reliability and safety of the power system. Hydropower's role in grid-scale energy storage, balancing services for other intermittent renewables like wind and solar power, and water management services by reservoirs are growing.

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The spring with the higher spring constant (15.0 N/cm) will be more difficult to stretch than the spring with the lower spring constant (10.0 N/cm).

This is because the spring constant is directly related to the amount of force required to stretch the spring. Therefore, the higher the spring constant, the more force that is required to stretch the spring.

The spring constant is a measure of how difficult it is to stretch or compress a spring. It is determined by the stiffness of the spring material, its shape and size, and how much the spring is compressed or stretched.

The higher the spring constant, the more force is required to stretch or compress the spring. The lower the spring constant, the less force is required to stretch or compress the spring.

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Answer:

Below

Explanation:

To fall 1.8 m the time will be found with :

 d = 1/2 a t^2

 1.5 = 1/2 ( 9.81) t^2      shows t = .55 s

in this .55 s it travels .8 m horizontally    

     Horizontal velocity = .8 m / .55 s = 1.45 m/s

When it hits the ground , horizontal velocity will still be 1.45 m/s

  vertical velocity will be    v = at = 9.81 m/s^2  * .55 = 5.42 m/s

Platform moves towards to west with a speed of v0/2 when the dog moves towards to east at a speed of v0, in accordance with the rule of conservation of momentum.

The speed at which an object's location changes in any direction. The distance travelled to the time needed to travel that distance is known as speed. Since speed only has a magnitude and no direction, it is a scalar quantity.

Acceleration is the method of changing a speed with which an object moves. If a substance's velocity does not change, it is not accelerating. Acceleration is a vector quantity.

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Answer:

law of gravity

Explanation:

cause the ball was still moving

Answer: the answer is law of gravity

Explanation:

Answer:

1.constant acceleration.

2.0 ms

3. 0 ms

Explanation:

1. (D) uniformly accelerated motion

2. (A) zero

3. (B) -10 m/s

4. (C) -9.8 m/s^2

5. (B) projectile motion

Answer:

speed will be constant and so no acceleration

Explanation:

the body will move toward the weaker force, but since the forces are constant there will be no acceleration.

C. Most stars are too far away to show a parallax shift.we make parallax measurements for most of the stars in our galaxy

What is galaxy?

Galaxy is a term used to describe a large system of stars, star clusters, interstellar gas, and dust bound together by gravity. Galaxies are often classified by their shape, size, and composition.

The Milky Way, our own galaxy, is a barred spiral galaxy, composed of hundreds of billions of stars and gas, bound together by gravity. Other types of galaxies include elliptical, irregular, and dwarf galaxies. Galaxies are often found clustered together in groups and superclusters, which are some of the largest structures in the universe.

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The object accelerates at a constant rate as it moves down the slope because of the constant gravitational force acting on it in a major portion and the rolling tangential force on the object is acting in the smaller form.

Rolling motion of any object occurs when the object starts sliding in a different methods from the other objects such as when the objects starts to roll from the ramp or any other sloppy surface and it rolls down due to the gravitational force and with many other forces such as the rolling tangential force. many forces are acting on the object at the same moment and we are just seeing the gravitational force which is playing a major portion. Hence by this information we can consider that the ball accelerates at a constant rate as it moves down the slope because of the constant gravitational force acting on it in a major portion and the rolling tangential force on the object is acting in the smaller form.

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Answer:

[tex]from \: snell {}^{.} s \: law : \\ n = \frac{ \sin(i) }{ \sin(r) } \\ \sqrt{3} = \frac{ \sin(i) }{ \sin(30 \degree) } \\ \sin(i) = \sqrt{3} \times \sin(30 \degree) \\ \sin(i) = 0.866 \\ i = { \sin}^{ -1 } (0.866) \\ i = 60 \degree[/tex]

A

Explanation:

just  pick a

The magnitude of the magnetic field is 7.27 x 10-6 T and its direction is perpendicular to the velocity of the proton.

The force experienced by a charged particle in a magnetic field is given by the equation F = q(v x B), where F is the force, q is the charge of the particle, v is the velocity of the particle, and B is the magnetic field.

Given the information provided in the question, we can set up the following equation:

1.60 1013 m/s2 = (q)(2.20 107 m/s) x B

To find the magnitude of the magnetic field, we can divide both sides of the equation by the velocity:

B = 7.27 x 10-6 T

To find the direction of the magnetic field, we know that the force on the proton is perpendicular to its velocity and the direction of the magnetic field. The direction of the magnetic field can be found using the right-hand rule which states that if you point your fingers in the direction of the velocity and then curl them in the direction of the force, your thumb will point in the direction of the magnetic field.

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The energy stored in the capacitor is 0.045 mJ. Under DC conditions, the capacitors will be open-circuited.

Energy stored in a capacitor can be calculated by

E = ½ CV²

Where

The picture of circuit in the attached plot is in the attachment.

Find the energy stored in the capacitor under DC conditions!

We have

Under DC (Direct Current) conditions, the capacitors will be open-circuited. It means that there is no current will flow through the 20 Ω resistor. So, I across the 10 Ω resistor is the same as I source.

See the picture below in the attachment!

The voltage across the 10 Ω resistor is

V = IR

V = 3(10)

V = 30 V

The voltage across the capacitor is the same as the voltage across the 10 Ω resistor.

Vc = V = 30 V

The energy stored would be

E = ½ C Vc²

E = ½ (0.1)(10⁻⁶)(30)²

E = ½ (10⁻⁷)(900)

E = 450 × 10⁻⁷

E = 0.045 × 10⁻³

E = 0.045 mJ

Hence, the energy stored in the capacitor under DC conditions is 0.045 mJ. The correct option is (c).

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Answer:

metric ruler

Explanation:

it counts legnth

Answer:

  d.  600 J

Explanation:

You want to know the work done to lift a box using a lever with a mechanical advantage of 2, if the work required without the lever is 600 J.

A lever trades force for distance. That is raising the box a distance of 6 m requires moving the lever arm a distance of 12 m, but only half the force is required. The product of force and distance is the same.

The total required work is unchanged: 600 J.

__

Additional comment

Actually, more work is required to lift the box using the lever. There is work applied to the box, and there is more work applied to moving the lever. (We have to assume a massless lever with no friction in these problems.)

Answer:

(a)

[tex]v(t) = \frac{At^2}{2} -\frac{Bt^3}{3}[/tex] --- velocity

[tex]x(t) = \frac{At^3}{6} -\frac{Bt^4}{12} + x(0)[/tex] --- position

(b) The maximum velocity is: 39.0625m/s

Explanation:

Given

[tex]a_x(t) =At -Bt^2[/tex]

[tex]A = 1.5m/s^3[/tex]

[tex]B = 0.120m/s^4[/tex]

Solving (a): The position and velocity as a function

To calculate the change in velocity, we integrate the given acceleration

i.e.

[tex]\int\limits^{v(t)}_{v(0)} {dv} = \int\limits^t_0 {a(t)} \, dt[/tex]

Integrate

[tex]v|\limits^{v(t)}_{v(0)} = \int\limits^t_0 {a(t)} \, dt[/tex]

Substitute v(t) and v(0) for v

[tex]v(t) - v(0) = \int\limits^t_0 {a(t)} \, dt[/tex]

[tex]v(0) = 0[/tex] ---- The initial velocity.

So, we have:

[tex]v(t) - 0 = \int\limits^t_0 {a(t)} \, dt[/tex]

[tex]v(t) = \int\limits^t_0 {a(t)} \, dt[/tex]

Substitute: [tex]a_x(t) =At -Bt^2[/tex]

[tex]v(t) = \int\limits^t_0 {[At -Bt^2]} \, dt[/tex]

Integrate

[tex]v(t) = {\frac{At^2}{2} -\frac{Bt^3}{3}}|\limits^t_0[/tex]

Substitute 0 and t for t

[tex]v(t) = [\frac{At^2}{2} -\frac{Bt^3}{3}] - [\frac{A*0^2}{2} -\frac{B*0^3}{3}][/tex]

[tex]v(t) = [\frac{At^2}{2} -\frac{Bt^3}{3}] - 0[/tex]

[tex]v(t) = \frac{At^2}{2} -\frac{Bt^3}{3}[/tex]

To calculate the change in position, we integrate the calculated velocity

i.e.

[tex]\int\limits^{x(t)}_{x(0)} {dx} = \int\limits^t_0 {v(t)} \, dt[/tex]

Integrate

[tex]x(t)|\limits^{x(t)}_{x(0)} = \int\limits^t_0 {v(t)} \, dt[/tex]

Substitute x(t) and x(0) for x(t)

[tex]x(t) - x(0) = \int\limits^t_0 {v(t)} \, dt[/tex]

Substitute: [tex]v(t) = \frac{At^2}{2} -\frac{Bt^3}{3}[/tex]

[tex]x(t) - x(0) = \int\limits^t_0 {\frac{At^2}{2} -\frac{Bt^3}{3}} \, dt[/tex]

Integrate

[tex]x(t) - x(0) = \frac{At^3}{6} -\frac{Bt^4}{12}}|\limits^t_0[/tex]

Substitute t and 0 for t

[tex]x(t) - x(0) = [\frac{At^3}{6} -\frac{Bt^4}{12}] - [\frac{A*0^3}{6} -\frac{B*0^4}{12}][/tex]

[tex]x(t) - x(0) = [\frac{At^3}{6} -\frac{Bt^4}{12}] - [0][/tex]

[tex]x(t) - x(0) = \frac{At^3}{6} -\frac{Bt^4}{12}[/tex]

Make x(t) the subject

[tex]x(t) = \frac{At^3}{6} -\frac{Bt^4}{12} + x(0)[/tex]

Where x(0) represents the initial position

Solving (b): The maximum velocity

First, we calculate the time at which it attains the maximum height

Set acceleration to 0

[tex]a_x(t) =At -Bt^2[/tex]

[tex]At - Bt^2 = 0[/tex]

Factorize

[tex]t(A - Bt) = 0[/tex]

Split

[tex]t = 0\ or\ A - Bt = 0[/tex]

t can't be 0.

So, we have:

[tex]A - Bt = 0[/tex]

Solve for t

[tex]-Bt = -A[/tex]

[tex]t = \frac{-A}{-B}[/tex]

[tex]t = \frac{A}{B}[/tex]

Substitute: [tex]A = 1.5m/s^3[/tex] and [tex]B = 0.120m/s^4[/tex]

[tex]t = \frac{1.5m/s^3}{0.120m/s^4}[/tex]

[tex]t = \frac{1.5}{0.120}s[/tex]

[tex]t = 12.5s[/tex]

Substitute [tex]t = 12.5s[/tex] in v(t) to get the maximum velocity

[tex]v(t) = \frac{At^2}{2} -\frac{Bt^3}{3}[/tex]

[tex]v(t) = \frac{A*12.5^2}{2} -\frac{B*12.5^3}{3}[/tex]

[tex]v(t) = \frac{156.25A}{2} -\frac{1953.125B}{3}[/tex]

Substitute: [tex]A = 1.5m/s^3[/tex] and [tex]B = 0.120m/s^4[/tex]

[tex]vmax = (156.25*1.5)/2 -(1953.125*0.120)/3[/tex]

[tex]v_{max} = 117.1875 - 78.125[/tex]

[tex]v_{max} = 39.0625[/tex]