Using x as the variable for the problem, solve for x.
PLEASE HELP!!!! Hosting a party for 28 people, you plan to serve pizza for dinner. Each pizza
has 8 slices. How many pizzas must you buy so each guest gets at least 2
slices?
A. x56
B. x 6
C. x27
D. X>7

Answer:

8.2

Step-by-step explanation:

(4.5)^2+(6.9)^2=c^2

20.25+47.61=67.86

sqrt of 67.86= 8.2 (rounded already) :)

Answer:

Step-by-step explanation:

You can start by splitting one whole complex shape into multiple shapes. Then find the areas of the shapes and add them together. Check the image I attached.

Answer:

Step-by-step explanation:

34x60

60 minutes in a hour

34x60=204

204+204= 408

408 copies in 2 hours

Answer:

4080

Step-by-step explanation:

First you would multiply 34 by 120. After you multiply those numbers you should get 4080 as your answer.

Answer:

12mm

Step-by-step explanation:

circumference (distance around) is equal to πd.

here, if π is 3, we do 3 x the diameter, which is 4. 3 x 4 = 12mm

Answer:

The result of the integral is [tex]\frac{\pi}{4}(-\cos{16} + \frac{9})[/tex]

Step-by-step explanation:

Polar coordinates:

In polar coordinates, we have that:

[tex]x^2 + y^2 = r^2[/tex]

And

[tex]\int \int_{dA} f(x,y) da = \int \int f(r) r dr d\theta[/tex]

In this question:

[tex]\int \int_{dA} \sin{(x^2+y^2)} dA = \int \int_{dR} = \sin{r^2}r dr d\theta[/tex]

Region in the first quadrant between the circles with center the origin and radii 3 and 4

First quadrant means that [tex]\theta[/tex] ranges between [tex]0[/tex] and [tex]\frac{\pi}{2}[/tex]

Between these circles means that r ranges between 3 and 4. So

[tex]\int \int_{dR} = \sin{r^2}r dr d\theta = \int_{0}^{\frac{\pi}{2}} \int_{3}^{4} \sin{r^2} r dr d\theta[/tex]

Applying the inner integral:

[tex]\int_{3}^{4} \sin{r^2} r dr[/tex]

Using substitution, with [tex]u = r^2, du = 2rdr, dr = \frac{du}{2r}[/tex], and considering that the integral of the sine is minus cosine, we have:

[tex]-\frac{\cos{r^2}}{2}|_{3}{4} = \frac{1}{2}(-\cos{16} + \frac{9})[/tex]

Applying the outer integral:

[tex] \int_{0}^{\frac{\pi}{2}} \frac{1}{2}(-\cos{16} + \frac{9}) d\theta[/tex]

Has no factors of [tex]\theta[/tex], so the result is the constant multiplied by [tex]\theta[/tex], and then we apply the fundamental theorem.

[tex]\frac{\theta}{2}(-\cos{16} + \frac{9}) = \frac{\pi}{4}(-\cos{16} + \frac{9})[/tex]

The result of the integral is [tex]\frac{\pi}{4}(-\cos{16} + \frac{9})[/tex]

R = (ax - p)/(q + bx)

(ax - p) = R(q + bx)

ax - p = Rq + Rbx

ax - Rbx = Rq + p

x(a - Rb) = Rq + p

x = (Rq + p)/(a - Rb)

Answer:

  x = 3

Step-by-step explanation:

You want to know the value of x, given that NM = 5x-1 and QP = 3x+5 in congruent triangles NMQ and QPN.

Corresponding parts of congruent triangles are congruent, so we have ...

  NM = QP

  5x -1 = 3x +5

  2x = 6 . . . . . . . . . . add 1-3x

  x = 3 . . . . . . . . . . divide by 2

Answer:

(a)

[tex]List = \{(1,1),(1,2),(1,3),(1,4),(2,1),(2,2),(2,3),(2,4),(3,1),(3,2),(3,3),(3,4),\\(4,1),(4,2),(4,3).(4,4)\}[/tex]

(b) Sampling Distribution (Table)

[tex]\begin{array}{cccccccc}{\bar x} & {1} & {1.5} & {2} & {2.5} & {3} & {3.5} & {4} & {Pr}& {\frac{1}{16}} & {\frac{1}{8}} & {\frac{3}{16}} & {\frac{1}{4}} & {\frac{3}{16}} & {\frac{1}{8}} & {\frac{1}{16}} \ \end{array}[/tex]

(b) Sampling Distribution (Histogram)

See attachment

Step-by-step explanation:

Given

[tex]Set = \{1,2,3,4\}[/tex]

[tex]n =4[/tex]

Solving (a): A list of sample size 2

We have:

[tex]n =4[/tex]

[tex]r = 2[/tex] --- the sample size

First, we calculate the number of list using permutation (orders matter)

[tex]n(List) = n^r[/tex]

So, we have:

[tex]n(List) = 4^2[/tex]

[tex]n(List) = 16[/tex]

And the list is:

[tex]List = \{(1,1),(1,2),(1,3),(1,4),(2,1),(2,2),(2,3),(2,4),(3,1),(3,2),(3,3),(3,4),\\(4,1),(4,2),(4,3).(4,4)\}[/tex]

Solving (b): Sample distribution  of sample means of (a)

First, calculate the mean of each set using:

[tex]Mean = \frac{Sum}{2}[/tex]

So, we have:

[tex](1,1) \to \frac{1+1}{2} \to 1[/tex]       [tex](1,2) \to \frac{1+2}{2} \to 1.5[/tex]    [tex](1,3) \to \frac{1+3}{2} \to 2[/tex]    [tex](1,4) \to \frac{1+4}{2} \to 2.5[/tex]

[tex](2,1) \to \frac{2+1}{2} \to 1.5[/tex]    [tex](2,2) \to \frac{2+2}{2} \to 2[/tex]     [tex](2,3) \to \frac{2+3}{2} \to 2.5[/tex]    [tex](2,4) \to \frac{2+4}{2} \to 3[/tex]

[tex](3,1) \to \frac{3+1}{2} \to 2[/tex]       [tex](3,2) \to \frac{3+2}{2} \to 2.5[/tex]    [tex](3,3) \to \frac{3+3}{2} \to 3[/tex]    [tex](3,4) \to \frac{3+4}{2} \to 3.5[/tex]

[tex](4,1) \to \frac{4+1}{2} \to 2.5[/tex]    [tex](4,2) \to \frac{4+2}{2} \to 3[/tex]    [tex](4,3) \to \frac{4+3}{2} \to 3.5[/tex]    [tex](4,4) \to \frac{4+4}{2} \to 4[/tex]

Write out the sample means (sorted)

[tex]\bar x =\{1,1.5,1.5,2,2,2,2.5,2.5,2.5,2.5,3,3,3,3.5,3.5,4\}[/tex]

Construct a frequency table

[tex]\begin{array}{cc}{\bar x} & {f} & {1} & {1} & {1.5} & {2} & {2} & {3} & {2.5} & {4} & {3} & {3} & {3.5} &{2} & {4} & {1} & Total & 16\ \end{array}[/tex]

Construct the sampling distribution where the probability is calculated using: [tex]\frac{f}{Total}[/tex]

So, we have:

[tex]\begin{array}{cccccccc}{\bar x} & {1} & {1.5} & {2} & {2.5} & {3} & {3.5} & {4} & {Pr}& {\frac{1}{16}} & {\frac{1}{8}} & {\frac{3}{16}} & {\frac{1}{4}} & {\frac{3}{16}} & {\frac{1}{8}} & {\frac{1}{16}} \ \end{array}[/tex]

Answer:

281/100

the mixed number would be 2 81/100

Step-by-step explanation:

Times 2.81 by 100

Hope it helps :)

By analyzing the inequality and solving, the range of values of x for which the inequality is true is x € (-4/3, 4)

Domain is the input to the function.

Range is the output of the function.

First, we'll consider the case where |2x+1|-x-3<0.

|2x+1|-x-3<0

|2x+1|<x+3

Now we need to take the absolute value of 2x+1, we have two cases to consider:

Case 1:

2x + 1 > 0

2x + 1 < x + 3

2x - x < 3 + 1

x < 4

Case 2:

2x + 1 < 0

-2x - 1 < x + 3

-2x - 1 -x - 3 < 0

-3x - 4 < 0

x > -4/3

Now we must find the intersection between the two cases:

x € (-4/3, 4)

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Answer: y = -150x + 1800

Step-by-step explanation:

1. Find the linear slope of the line between two points.

(Change in Y)/(Change in X)

2. Write out an equation in point slope form.

(y-y1) = m(x-x1)

y-1800 = -150(x-0)

3. Simplify the equation and turn it into slope-intercept form.

y = -150x + 1800

Answer:

a) 47.55

b) 58

c) 47.88

Step-by-step explanation:

Given that the size of the orders is uniformly distributed over the interval

$25 ( a ) to $80 ( b )

a) Determine the value for the first order size generated based on 0.41

parameter for normal distribution is given as ;  a = 25,  b = 80

size/value of order  = a + random number ( b - a )

                                = 25 + 0.41 ( 80 - 25 )

                                =  47.55

b) Value of the last order generated based on random number (0.6)

= a + random number ( b - a )

= 25 + 0.6 ( 80 - 25 )

= 25 + 33 = 58

c) Average order size

= ∑ order 1 + order 2 + ----- + order 10  ) / 10

= (47.55 + ...... + 58 ) / 10

= 478.8 / 10 = 47.88

The mail order seed follows a uniform distribution

(a) The value of the first order size generated by 0.41

The given parameters are:

[tex]a = 25[/tex] -- the lower bound

[tex]b = 80[/tex] -- the upper bound

To calculate the required value, we make use of the following order formula

[tex]Value = a + r(b - a)[/tex]

Where r represents the random number.

So, we have:

[tex]Value= 25 + 0.41 \times ( 80 - 25 )[/tex]

Open bracket

[tex]Value= 25 + 0.41 \times 55[/tex]

Evaluate the product

[tex]Value= 25 + 22.55[/tex]

Add the terms

[tex]Value= 47.55[/tex]

Hence,  the value for the first order size generated randomly based on random number 0.41 is 47.55

(b) The value of the last order size generated by 0.60

In (a), we have:

[tex]Value = a + r(b - a)[/tex]

So, we have:

[tex]Value= 25 + 0.60 \times ( 80 - 25 )[/tex]

Open bracket

[tex]Value= 25 + 0.60 \times 55[/tex]

Evaluate the product

[tex]Value= 25 + 33[/tex]

Add the terms

[tex]Value= 58[/tex]

Hence, the value for the last order size generated randomly based on random number 0.61 is 58

(c) The average order size

To do this, we calculate the order size from 1 to 10, and then calculate the average value of the 10 orders.

Using a calculator, the sum of the 10 orders is:

[tex]\sum x= 478.8[/tex]

The average order size is then calculated as:

[tex]\bar x = \frac{\sum x}{n}[/tex]

This gives

[tex]\sum x= \frac{478.8}{10}[/tex]

[tex]\sum x= 47.88[/tex]

Hence, the average order size is 47.88

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The trigonometric ratios for the angle x in the triangle are given as follows:

The three trigonometric ratios are defined as follows:

In the right triangle in this problem, we have that d represents the hypotenuse, while the sides relative to angle x are given as follows:

These sides are used along with the definitions of each ratio to give the three trigonometric ratios of angle x.

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Answer:

C

Step-by-step explanation:

20 - 13 = 7

Answer:

C)

Step-by-step explanation:

7 + 13 = 20

The answer is C

[tex] \huge \mathrm{Answer࿐ }[/tex]

[tex] \boxed{\mathrm{volume = area \times height}}[/tex]

_____________________________

[tex]\mathrm{ \#TeeNForeveR}[/tex]

Answer:

324

Step-by-step explanation:

if you do 36 times 9 you get 324

Answer:

You started correctly....

Step-by-step explanation:

d = c/n      Multiply both sides by 'n'

dn = c        now divide both sides of the equation by 'd'

n = c/d       Done.

Answer:

x = 26

Step-by-step explanation:

180=(4x+10)+(x+40)

180 = 4x + x +10 + 40

180 - 50 = 5x

130 = 5x

130 / 5 = x

26 = x

Answer: Here, let X,Y,ZX,Y,Z indicate the amount in dollars to be invested

Step-by-step explanation: Here, let X,Y,ZX,Y,Z indicate the amount in dollars to be invested

The complete statement about the product of the polynomials is that:

The product of f(x) and g(x) is always a polynomial because the coefficients are real numbers and the exponents are whole numbers. Real numbers and whole numbers are closed under addition

From the question, we have the following parameters that can be used in our computation:

Polynomials f(x) and g(x)

When these polynomials are multiplied;

We get another polynomial

This is because, when you multiply two polynomials you get a sum of monomials.

A sum of monomials is always a polynomial

The sum of monomials stated above implies that the whole exponents and the real coefficients are closed under addition

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The equation that justifies  ten to the one third power equals the cube root of ten is ten to the one third power all raised to the third power equals ten to the one third times three power equals ten. Option B

we are to find [tex]10^{\frac{1}{3} } = \sqrt[3]{10}[/tex]

The justification has to be done with the use of the properties of powers as well as roots.

[tex]a^\frac{m}{n} = \sqrt[n]{a^m}[/tex]

then we would have:

[tex]\sqrt[3]{10} = \sqrt[3]{10^1} =10^\frac{1}{3}[/tex]

then we would have

[tex](10^\frac{1}{3} )^3\\\\= 10^\frac{3}{3}[/tex]

= 10

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Answer:

Step-by-step explanation:

The first equation:

The second equation:

Convert to slope-intercept form:

The graph is attached

Intersection point is (9, 7)

Answer:

To rewrite the radical expression "the seventh root of x to the thrid power" as an expression with a rational exponent, we need to use the property that allows us to rewrite a root of a power as a power with a rational exponent. This property states that "the nth root of x to the mth power" is equal to "x to the m/nth power".

Using this property, we can rewrite "the seventh root of x to the thrid power" as "x to the 3/7th power". Therefore, the correct answer is "x to the 3/7th power".

The other answer choices are not equivalent to the original expression. "x to the seven thirds power" is not a valid expression because "thirds" is not a unit of measurement. "x^21" is not equivalent to the original expression because the base and exponent are not related in the same way as in the original expression. "x^4" is not equivalent to the original expression because the base is the same but the exponent is not.

Answer: x to the 3/7th power

Step-by-step explanation:

so you dont have to read a essay to get the answer lol

The solution to the equations is

Addition : 2.49 + 6.7 = 9.19  ;  6.7 + 2.49 = 9.19

Subtraction : 9.19 - 6.7 = 2.49  ;  9.19 - 2.49 = 6.7

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the equation be represented as A

Now , the value of A is

Let the three decimals be represented as set x = { 2.49 , 6.7 , 9.19 }

Now , the addition facts are given by equations ,

2.49 + 6.7 = 9.19  be equation (1)

6.7 + 2.49 = 9.19   be equation (2)

And , the subtraction facts are given by the equations ,

9.19 - 6.7 = 2.49  be equation (3)

9.19 - 2.49 = 6.7  be equation (4)

Hence , the equations are solved

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Answer:

taking b as reference angle

using cos rule

cos b=b/h

cos b=1.3/2.8

cos b=0.46

cos 62 =0.46

Step-by-step explanation:

therefore the value of b is 62 degree

Answer:

I'd say A or D but I have a feeling it's A

320 ft is the perimeter