Two students are balancing on a 10m seesaw. The seesaw is designed so that each side of the seesaw is 5m long. The student on the left weighs 60kg and is sitting three meters away from the fulcrum at the center. The student on the right weighs 45kg. The seesaw is parallel to the ground. The mass of the board is evenly distributed so that its center of mass is over the fulcrum. What distance from the center should the student on the right be if they want the seesaw to stay parallel to the ground?
a. 4m
b. 5m
c. 2m
d. 3m
Answers
Answer:
Option A. 4 m
Explanation:
Please see attached photo for diagram.
In the attached photo, X is the distance from the centre to which the student on the right must sit in order to balance the seesaw.
Clockwise moment = X × 45
Anticlock wise moment = 3 × 60
Clockwise moment = Anticlock wise moment
X × 45 = 3 × 60
X × 45 = 180
Divide both side by 45
X = 180 / 45
X = 4 m
Thus, the student must sit at 4 m from the centre.
The distance from the center the student on the right will be if they want the
seesaw to stay parallel to the ground is 4m
The question tells us that X is the distance to the center , each side of the
see saw is 5m with total length being 10m. This is explained in the
attached picture.
Clockwise moment = X × 45
Anticlock wise moment = 3 × 60
Clockwise moment = Anticlock wise moment
X × 45 = 3 × 60
X × 45 = 180
= 180 / 45
= 4m
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Related Questions
An electric current in a copper wire is produced by the motion of which of the following particles? a. copper atoms b. neutrons c. protons d. electrons
Answers
Answer:
electrons
Explanation:
Because electric current is flowed due to the presence of free electrons.
Which switches must be pressed to make bulb x come on
Answers
Answer:
Did you forget to attach the image?
Explanation:
So far, we're not sure that you even HAVE a bulb or any switches.
If you had them, you probably would have included a diagram of the circuit you built with them. THEN we could look at the diagram and answer this question.
Right now, we can't. We haven't seen such a diagram.
During a neighborhood baseball game in a vacant lot, a particularly wild hit sends a 0.144 kg baseball crashing through the pane of a second-floor window in a nearby building. The ball strikes the glass at 14.9 m/s , shatters the glass as it passes through, and leaves the window at 10.5 m/s with no change of direction.
Requied:
a. What is the direction of the impulse that the glass imparts to the baseball?
b. Calculate the magnitude of this impulse (a positive number).
Answers
Answer:
a)The direction of the impulse that the glass imparts to the baseball Is opposite the direction of the balls motion
b) [tex]I=0.6336Ns[/tex]
Explanation:
From the Question we are told that:
Mass [tex]m=0.144kg[/tex]
Initial Speed [tex]v_1=14.9m/s[/tex]
Final speed [tex]v_2=10.5[/tex]
a)The direction of the impulse that the glass imparts to the baseball Is opposite the direction of the balls motion
b)
Generally the equation for impluse magnitude is mathematically given by
[tex]I=m(v_1-v_2)[/tex]
Therefore
[tex]I=0.144(14.9-10.5)[/tex]
[tex]I=0.6336Ns[/tex]
The leaning tower of Pisa is about 56 meters tall. A ball released from the top takes 3.4 seconds to reach the ground. The final velocity of the ball before it hits the ground is 33 meters/second. Assuming that the ball experienced a constant acceleration throughout this descent, calculate the magnitude of the acceleration.
Answers
The magnitude of the constant acceleration of the ball is 9.7 m/s².
What is acceleration?Acceleration is the rate of change of velocity.
To calculate the constant acceleration of the ball, we use the formula below.
Formula:
a = (v-u)/t................. Equation 1From the question,
Given:
a = Acceleration,v = Final velocityu = Initial velocityt = TimeFrom the question,
Given:
v = 33 m/su = 0 m/s t = 3.4 secondsSubstitute these values into equation 1
a = (33-0)/3.4a = 9.7 m/s²Hence, the acceleration is 9.7 m/s².
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A group of students wants to determine the internal resistance of a battery. They connect the battery to a variable resistor. The students measure the potenial differnce across the battery as a function of the current throught the battery as they vary the resistance. Which of the following analyses of the data could be used to determine the internal resistance of the battery?
A. Divide the potential difference across the battery by the current through it for each data point. The average of these calculations gives the internal resistance of the battery.
B. Graph the potential difference across the battery as a function of the current through it. Extrapolate to find the y- intercept and divide this by the average of the current measurements to find the internal resistance of the battery.
C. Find the best-fit straight line for a graph of potential difference across the battery as a function of the current through it. The absolute value of the slope represents the internal resistance of the battery.
D. This data cannot be analyzed to give the internal resistance of the battery, because the potential difference across the battery does not depend on the current.
Answers
Answer:
The answer is "Option C"
Explanation:
Ohm's Rule we remember [tex]V = I\times R[/tex]
It looks like the sample is drawn y=mx while m is curve slope
The slope of the graph is its resistance if they draw a graph v vs I.
However, the internal battery presence resistance can be modified as the straight line equation
[tex]y = mx -c[/tex]
where c is y-intercept:
[tex]E = I(R+r) \\\\ E = IR+ Ir\\\\E = V + Ir\\\\V = E- Ir\\\\V = -Ir+E[/tex]
R is really the internal battery resistance to draw graph V vs I, the slope is internal resistance to the negative slope cure.
The same resultant force acts on objects 1 and 2. Object 1 accelerates at 2m/s² and Object 2 accelerates at 5m/s². Which object has the greater mass?
Answers
Answer:
Object 1
Explanation:
Newton's 2nd Law: F = ma, therefore m = F/a
This shows that mass is inversely proportional to acceleration. Because the resultant force (F) is held constant in this problem, the lower the acceleration, the greater the mass. Therefore, the object that accelerates at 2 m/s² has the greater mass. In other words, if the net force on both objects is the same, the object with the slower acceleration has the greater mass.
Sally and Sam are in a spaceship that comes to within 15,000 km of the asteroid Ceres. Determine the force Sally experiences, in N, due to the presence of the asteroid. The mass of the asteroid is 8.7 1020 kg and the mass of Sally is 68 kg. For calculation purposes, assume the two objects to be point masses.
Answers
The gravitational force that is acting on the masses is 1.73 * 10^-2 N.
What is the force?We know that the force of gravity is that kind of force that is going to act on any two of the objects that we have on the earth. This force as we know it is attractive force. The implication of this is that any two masses that we find on the earth are the forces that would have to be attracted to each other.
Let us note that we would have the masses that we have of the asteroid and that of sally as m1 and m2 while we have the force as;
F = G m1m2/r^2
G = gravitational constant
F = magnitude of the force
m1 and m2 = masses
r = distance of separation.
We then have;
F = 6.6 * 10^-11 * 8.7 * 10^20 * 68/(15 * 10^6)^2
F = 3.9 * 10^12/2.25 * 10^14
F = 1.73 * 10^-2 N
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Help yea I need help
Answers
a charge of 2 * 10^-9C is placed at the origin, and another charge of 4 * 10^-9C is placed at x = 1.5m. find the point between these charges where a charge of 3 * 10^-9C should be placed so that the net electric force on it is zero
Answers
Answer:
x₁ = 0.62 m
Explanation:
In this exercise the force is electric, given by Coulomb's law
F =[tex]k \frac{q_1q_2}{r^2}[/tex]
This force is a vector, since the three charges are in a line we can reduce the vector sum to a scalar sum.
For the sense of force let us use that charges of the same sign repel and charges of the opposite sign attract.
∑ F = F₁₂ - F₂₃
They ask us to find the point where the summaries of the force is zero.
F₁₂ - F₂₃ = 0
F₁₂ = F₂₃
let's fix a reference system located in the first charge (more to the left), the distance between the two charges is d = 1.5 m and x is the distance to the location of the second sphere
k q₁q₂ / x² = k q₂q₃ / (d-x) ²
q₁ (d-x) ² = q₃ x²
let's solve
d² - 2 x d + x² = [tex]\frac{q_3}{q_1}[/tex] x²
x² (1 - [tex]\frac{q_3}{q_1}[/tex]) - 2x d + d² = 0
we substitute the values
x² (1- 4/2) - 2 1.5 x + 1.5² = 0
x² (-1) - 3.0 x + 2.25 = 0
x² + 3 x - 2.25 = 0
let's solve the quadratic equation
x = [-3 ± [tex]\sqrt{ 3^2 + 4 \ 2.25}[/tex]] / 2
x = [-3 ± 4.24] / 2
x₁ = 0.62 m
x₂ = 3.62 m
since it indicates that the charge q₂ e places between the spheres, the correct solution is
x₁ = 0.62 m
A rock is thrown horizontally of a bridge at 8.00 m/s. It hits the water's surface below 3.4 seconds later. How high is the bridge? How far from the bridge does it hit the water?
I was provided with the equations:
x= v * t and y= (Vi * t)1/2 * a * t^2
Answers
Answer:
56.7m
Explanation:
horizontal velocity does not matter in this situation because it stays constant (no unbalanced force acting upon it)
a=9.81m/s^2
t=3.4s
Vi=0m/s
d=Vi*t+1/2at^2
d=1/2at^2
d=1/2*9.81m/s^2*(3.4s)^2
d=4.905m/s^2*11.56s^2
d=56.7m
Most stars are main-sequence stars, a group of stars for which size, mass, surface temperature, and radiated power are closely related. The sun, for instance, is a yellow main sequence star with a surface temperature of 5800 K. For a main-sequence star whose mass M is more than twice that of the sun, the total radiated power, relative to the sun, is approximately P/Psun = 1.5(M/Msun)3.5. The star Regulus A is a bluish main-sequence star with mass 3.8Msun and radius 3.1Rsun. What is the surface temperature of Regulus A?
Answers
Answer:
the surface temperature of Regulus A is 11724.13 K
Explanation:
Given the data in the question;
Sun's surface temperature T = 5800 K
total radiated power, relative to the sun is; P/P[tex]_{sun[/tex] = [tex]([/tex] 1.5(M/M[tex]_{sun[/tex] [tex])^{3.5[/tex]
The star Regulus A is a bluish main-sequence star with mass 3.8M[tex]_{sun[/tex] and radius 3.1R[tex]_{sun[/tex] .
First, we determine the value power emitted by the sun or sun as follows;
P = eσAT⁴
where P is the power, e is surface emissivity, σ is Stefan Boltzmann, A is area and T is temperature.
so, lets assume emissivity of star and sun is same;
let p be power related to star and p[tex]_{sun[/tex] be power related sun.
Ratio of power radiated by star and power radiated by sun;
P/P[tex]_{sun[/tex] = eσAT⁴ / eσA[tex]_{sun[/tex]T[tex]_{sun[/tex]⁴
we know that AREA A = πR²
we input the formula for area
P/P[tex]_{sun[/tex] = eσ(πR²)T⁴ / eσ(π(R[tex]_{sun[/tex])²)T[tex]_{sun[/tex]⁴
such that we now have;
P/P[tex]_{sun[/tex] = R²T⁴ / R[tex]_{sun[/tex]²T[tex]_{sun[/tex]⁴
given that P/P[tex]_{sun[/tex] = [tex]([/tex] 1.5(M/M[tex]_{sun[/tex] [tex])^{3.5[/tex], we substitute
[tex]([/tex] 1.5(M/M[tex]_{sun[/tex] [tex])^{3.5[/tex] = R²T⁴ / R[tex]_{sun[/tex]²T[tex]_{sun[/tex]⁴
we find temperature of the star T
T = 5800 × [tex][[/tex] 1.5[tex]([/tex]M/M[tex]_{sun[/tex][tex])^{3.5[/tex] (R[tex]_{sun[/tex]²/R²)[tex]]^{1/4[/tex]
Given that; mass M is 3.8M[tex]_{sun[/tex] and radius R is 3.1R[tex]_{sun[/tex] .
we substitute
T = 5800 × [tex][[/tex] 1.5[tex]([/tex]3.8M[tex]_{sun[/tex]/M[tex]_{sun[/tex][tex])^{3.5[/tex] (R[tex]_{sun[/tex]²/( 3.1R[tex]_{sun[/tex] )²)[tex]]^{1/4[/tex]
T = 5800 × [tex][[/tex] 1.5[tex]([/tex]3.8[tex])^{3.5[/tex] ( 1/( 3.1)²)[tex]]^{1/4[/tex]
T = 5800 × [tex][[/tex] 1.5( 106.9652 ) ( 1/(9.61) [tex]]^{1/4[/tex]
T = 5800 × [tex][[/tex] 16.69592 [tex]]^{1/4[/tex]
T = 5800 × 2.02140152
T = 11724.13 K
Therefore, the surface temperature of Regulus A is 11724.13 K
Why the specific heat of water changed as the water state changed?
Answers
Answer:
Infinity. Yes, specific value of water during phase change is infinity. This is because, as long as water is present and it is changing phase (at boiling point or at any other constant temperature), the temperature of the water does not change no matter what amount of heat you are supplying to the water. Thus, its specific heat value is infinity.
Heat Transfer 12 Directions: Drag the arrows to the correct locations on the image. directions in which heat flows. The diagram below shows three solid objects. Two of the objects are hot and one is cold. If heat is transferred between these objects via conduction, use the arrows to indicate the direction.
That's the question and please someone help me I can't figure this out because of how much I've been absent throughout this lesson
Answers
If heat is transferred between these objects via conduction, both arrows will point towards the cold.
Heat energy is transferred through the mechanism of conduction when nearby atoms or molecules collide. In solids and liquids, where particles are more closely spaced, conduction happens more easily than in gases, where particles are more widely spaced. Heat transfers through solid materials via conduction. The roof, walls, and windows of your house all carry heat on hot days.
The act of heating a skillet on a stovetop is a typical illustration of conduction. The surface of the pan receives heat directly from the burner. The amount of kinetic energy that the particles in a sample of matter have converted to heat is measured by temperature. Conduction mostly comes in two flavors. Steady-state conduction is what they are. temporary conduction.
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calculate the maximum capillary rise of water to be expected a, in a vertical glass tube 1mm in diameter b, in between tow concentric glass tubes of radii 4 and 5 mm. take 6=0.0733n c, in between two vertical parallel.clean glass plates spaced a distance of 2mm apart.
Answers
The maximum capillary rise of water to be expected in the vertical glass tube is 15 mm.
What is capillary rise?The process of a liquid flowing in a small area without the aid of, or even in opposition to, any outside forces like gravity is known as capillary rise.
The effect can be observed in a biological cell, in a thin tube, in porous materials like paper and plaster, in some non-porous materials like sand, liquid carbon fiber, and some other porous materials.
The maximum capillary rise of water = 4σcosθ/ρgd
= ( 4 × 0.0733 × cos0°)/(10³ × 9.81 × 2 × 10⁻³) meter
= 0.015 meter
= 15 mm.
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Batman shoots a grappling hook
34.6 m/s at an 80.2° angle. What is the magnitude only (no direction) of the velocity of the hook 1.09 s later?
(Unit = m/s)
Answers
Answer:
24.132 m/s
Explanation:
Note
[tex]U[/tex] = Initial Velocity
[tex]U_x[/tex] = Initial Horizontal Velocity
[tex]U_y[/tex] = Initial Vertical Velocity
[tex]V[/tex] = Final Velocity
[tex]V_x[/tex] = Final Horizontal Velocity
[tex]V_y[/tex] = Final Vertical Velocity
[tex]B[/tex] = launch angle
[tex]g[/tex] = gravity
[tex]t[/tex] = time
[tex]U_x=U*cos(B)[/tex]
[tex]U_y=U*sin(B)[/tex]
The horizontal component of the velocity is constant throughout the flight. So [tex]U_x=V_x[/tex] It can be defined as
[tex]V_x=U*cos(B)[/tex]
We can use the kinematics equation
[tex]V=U+at[/tex]
Gravity is acting downwards; gravity would be negative
[tex]V_y=U_y-gt[/tex]
The magnitude of the velocity can be defined as
[tex]V=\sqrt{V_x^2+V_y^2}[/tex]
Inserting some of the other equations gives us an equation at a given time (t).
[tex]V=\sqrt{(U*cos(B))^2+(U*sin(B)-gt)^2}[/tex]
[tex]V=\sqrt{(UcosB)^2+(UsinB)^2+(gt)^2-2gtU*sinB[/tex]
[tex]V=\sqrt{U^2+g^2*t^2-2*t*g*U*sinB}[/tex]
[tex]V(t)=\sqrt{U^2+g^2t^2-2tgUsinB}[/tex]
We are given
[tex]U=34.6[/tex]
[tex]B=80.2[/tex]
[tex]t=1.09[/tex]
[tex]g=9.81[/tex]
[tex]V(1.09)=\sqrt{34.6^2+9.81^2*1.09^2-2*1.09*9.81*34.6*sin80.2}[/tex]
[tex]V(1.09)=\sqrt{34.6^2+114.338-2*1.09*9.81*34.6*sin80.2}[/tex]
[tex]V(1.09)=\sqrt{34.6^2+114.338-739.94868*sin80.2}[/tex]
[tex]V(1.09)=\sqrt{34.6^2+114.338-729.151}[/tex]
[tex]V(1.09)=\sqrt{1197.16+114.338-729.151}[/tex]
[tex]V(1.09)=\sqrt{582.347}[/tex]
[tex]V(1.09)=24.132[/tex]
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A diving board 3.00 m long is supported at a point 1.00 m from the end, and a diver weighing 500 N stands at the free end. The diving board is of uniform cross section and weighs 280 N. Find:
a. the force at the support point
b. the force at the left-hand end.
Answers
Answer:
[tex]F_l=1140N[/tex]
Explanation:
From the question we are told that:
Length[tex]l=3.00m[/tex]
Support distance [tex]d=1.00m[/tex]
Weight of diver [tex]W_d=500N[/tex]
Weight of board [tex]W_b=280N[/tex]
Generally the equation for Total Torque is mathematically given by
[tex]F_T=W_d-W_b[/tex]
[tex]F_T=F_d-f_b[/tex]
[tex]F_T=-280-500[/tex]
[tex]F_T=-780[/tex]
[tex]F_T=780[/tex]
Since we consider the horizontal axis
[tex]\sum Y=0[/tex]
[tex]Fs-(\frac{1}{2}l*w_b)-(l-w_d)[/tex]
[tex]Fs-1.5*280-3*300=0[/tex]
[tex]F_s=1920N[/tex]
Therefore the force at the support point 1.00m from the force at the left-hand
[tex]F_l=F_s-F_l[/tex]
[tex]F_l=1920-780[/tex]
[tex]F_l=1140N[/tex]
What is the unit of work in SI system?
Answers
Answer:
Joule ;)
Explanation:
In the case of work (and also energy), the standard metric unit is the Joule (abbreviated J). One Joule is equivalent to one Newton of force causing a displacement of one meter. In other words, The Joule is the unit of work.
Hope this helps!
Answer:
Explanation:
Joule
In the case of work (and also energy), the standard metric unit is the Joule (abbreviated J). One Joule is equivalent to one Newton of force causing a displacement of one meter. In other words, The Joule is the unit of work.
An astronaut in a satellite 1600km above the Earth experience a gravitational force magnitude 700N on earth.The Earth's radius is 6400km calculate the magnitude of the gravitational force which the astronaut experience in satellite
Answers
Answer:
The magnitude of the gravitational force which the astronaut experience in satellite [tex]= 448[/tex] Newton
Explanation:
As we know
Gravitational force F = [tex]\frac{GMm}{r^2}[/tex]
Where G is the gravitational constant [tex]6.67 * 10^{-11}[/tex]
M is the mass of earth [tex]= 6* 10^{24}[/tex]
m is not given
r is the radius of earth [tex]6 400*10^3[/tex]
Substituting the given values, we get -
[tex]F = \frac{6.67*10^{−11}*6*10^{24}* m}{(6400*10^3)^2}[/tex]
[tex]m = 71.6[/tex] Kg
Gravitational force in the satellite
[tex]F = \frac{6.67*10^{−11}*6*10^{24}* m}{(6400*10^3 + 1600 *10^3)^2}\\F = 448[/tex]N
A mass on a string is swung in a circle of radius 0.75m at 7.0m/s.what its rate of acceleration.
Answers
Explanation:
ac = v^2/r
= (7.0 m/s)^2/(0.75 m)
= 65 m/s^2
file:///C:/Users/Admin/Downloads/GUIA%20N.%206%20(2).pdf
porfa copia el link
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Answers
1. Create a new question
2. Provide an image of your question/work so we don't have to download anything.
It is a “new moon” (the Moon is totally dark in the sky). Using the masses of the Earth, Sun, and Moon and the average distances between the Earth-Moon and Earth-Sun, find the net gravitational force on the Earth from the Sun and the Moon combined.
Find also distance when it is full moon
Answers
It is a “new moon” (the Moon is totally dark in the sky). The gravitational force between the Earth and the Moon is:
2.9 x 10^20 N3.5 x 10^22 N3.5 x 10^22 NWhat is gravitational force?Generally, The gravitational force between two objects is given by the equation:
force = G * (mass1 * mass2) / distance^2
Where G is the gravitational constant (6.67 x 10^-11 N*(m/kg)^2), mass1 and mass2 are the masses of the two objects, and distance is the distance between the two objects.
The mass of the Earth is 5.972 x 10^24 kg, the mass of the Moon is 7.347 x 10^22 kg, and the mass of the Sun is 1.989 x 10^30 kg. The average distance between the Earth and the Moon is 384,400 km, and the average distance between the Earth and the Sun is 149.6 million km.
The gravitational force between the Earth and the Moon is:
force = (G * (mass of Earth) * (mass of Moon)) / (distance between Earth and Moon)^2 force
= (6.67 x 10^-11 N*(m/kg)^2) * (5.972 x 10^24 kg) * (7.347 x 10^22 kg) / (384400 x 10^3 m)^2 force
= 2.9 x 10^20 N
The gravitational force between the Earth and the Sun is:
force = (G * (mass of Earth) * (mass of Sun)) / (distance between Earth and Sun)^2 force
= (6.67 x 10^-11 N*(m/kg)^2) * (5.972 x 10^24 kg) * (1.989 x 10^30 kg) / (149.6 x 10^9 m)^2 force
= 3.5 x 10^22 N
To find the net gravitational force on the Earth from the Sun and Moon combined, we add the two forces we found above.
Net force = 2.9 x 10^20 N + 3.5 x 10^22 N
= 3.5 x 10^22 N
When it is a Full Moon the distance is the same 384,400 km
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PLZ HELP NO SNEAKY LINK OR I WILL REPORT U OR NON ANSWERS
Answers
Home of atoms of hydrogen also the lightest element in the universe.
Radiative Zone
Outside the inner Core it radiates energy through the process of photon emission.
Convection Layer
Outer most Layer of the Core, it extends form a depth of 200,000 kilometres to the visible surface. Energy is created by Convection. This is where light is produced.
Photosphere
Surrounds the stars and is where light and heat radiate.
Chromosphere
Reddish gas layer outside of the photosphere I think it also works with the Corona.
Corona
Aura of Plasma that surrounds the Sun and other stars, it extends millions of kilometres and easily seen during a total eclipse.
How long does it take the Earth to spin on its axis once?
Answers
Explanation:
it takes the earth 24 hours to spin on it's axis once
Decide which examples are Nuclear Fission reaction.
A. The reaction that is currently used in nuclear power plants.
B. Two small atoms combine together to form one larger atom.
C. A heavy atom is split when bombarded by neutrons.
D. Often involves isotopes of uranium
A) A, C, D
B) A, B, C
C) B, C, D
Answers
a,c,d, is your answer I think I hope it helps
Which one has more momentum if they are all traveling at the same speed?
1. A basketball
2. A golf ball
3. A tennis ball
4. A bowling ball
Answers
Answer:
the answer is a bowling ball
When gas condense it ______ heat and temperature _____
A. gain heat, temperature decrease
B. gain heat, temperature increase
C. loses heat, temperature decrease
D. loses heat, temperature doesn't change
Answers
Answer:
C. loses heat, temperature decreases
Explanation:
When gas condenses, energy decreases, therefore it would lose heat and the temperature would decrease.
What kind of nuclear reaction is seen in 30Y0Zr+e?
→40
OA. Beta decay
OB. Alpha decay
OC. Nuclear fusion
D. Nuclear fission
Answers
Beta decay is seen in the nuclear reaction: ⁹⁰₃₉Y → ⁹⁰₄₀Zr + ⁰₋₁e. Hence, option (A) is correct.
What is Beta (β) decay?A proton can change into a neutron or vice versa inside the radioactive sample's nucleus through a process known as beta decay.
The radioactive sample's nucleus can approach the ideal neutron/proton ratio as closely as feasible through processes like beta decay and alpha decay. The nucleus releases a beta particle during this process, which can either be an electron or a positron.
As electron releases here, it is a Beta (β) decay.
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A catapult of pole length 4r throws a pumpkin from one
end of a pole which rotates about an axis at the other
end with angular speed w.
A smaller catapult of pole length r throws another
pumpkin from one end of a pole which rotates about an
axis at the other end with the same angular speed was
the first catapult.
How does the linear speed of the larger catapult's
pumpkin Vlarge compare with the smaller catapult's
pumpkin Vsmall?
Answers
Answer:
vlarge = 4vsmall
Explanation:
Khan Academy
Across a resistor, voltage
a. drops
b. builds
c. speeds up
Answers
Answer:
drops
Explanation:
Ohm's Law states that V=I*R, where V is voltage, I is current and R is resistance. In a series circuit, the voltage drop across each resistor will be directly proportional to the size of the resistor. In a parallel circuit, the voltage drop across each resistor will be the same as the power source
HELP How are the forces on an object added or subtracted to get net force?
Answers
Answer:
Explanation:
Net force is determined by adding up all of the individual forces on an object. For example, to determine the net force on an airplane, you would add up the lift, weight, thrust, and drag. If forces are in opposite directions, like lift and weight, then you subtract them