Astroid one has less asked her to. Able to use enough force to not only change or keep it self go in the same direction.
(a) If the initial speed both asteroids before collision is the same, then the asteroid with greater mass will have more momentum before collision while the asteroid with lesser mass will have greater momentum after collision.
(b) The force of the impact depends of the velocity change and time of collision of the asteroids.
According to the principle of conservation of linear momentum, the sum of the momentum of each asteroid before collision must equal the sum of their momentum after collision.
[tex]m_1 u_1 + m_2 u_2 = m_1v_1 + m_2 v_2[/tex]
where;
m is the mass of the asteroidsu is the initial speed of the asteroidsv is the final speed of the asteroidsIf the initial speed both asteroids before collision is the same, then the asteroid with greater mass will have more momentum before collision while the asteroid with lesser mass will have greater momentum after collision to conserve the momentum.
The force of the impact depends of the velocity change and time of collision of the asteroids.
[tex]F = \frac{m\Delta v}{t}[/tex]
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PLZ EXPLAIN AND I WILL GIVE YOU BRANILEST
How do two interacting objects exert equal and opposite forces on each other when they collide, even though they have different masses?
Answer:
Did a little research.
Explanation:
The Law of Action-Reaction:
Newton's third law of motion is naturally applied to collisions between two objects. In a collision between two objects, both objects experience forces that are equal in magnitude and opposite in direction. Such forces often cause one object to speed up (gain momentum) and the other object to slow down (lose momentum). According to Newton's third law, the forces on the two objects are equal in magnitude. While the forces are equal in magnitude and opposite in direction, the accelerations of the objects are not necessarily equal in magnitude. In accord with Newton's second law of motion, the acceleration of an object is dependent upon both force and mass. Thus, if the colliding objects have unequal mass, they will have unequal accelerations as a result of the contact force that results during the collision.Consider the collision between the club head and the golf ball in the sport of golf. When the club head of a moving golf club collides with a golf ball at rest upon a tee, the force experienced by the club head is equal to the force experienced by the golf ball. Most observers of this collision have difficulty with this concept because they perceive the high speed given to the ball as the result of the collision. They are not observing unequal forces upon the ball and club head, but rather unequal accelerations. Both club head and ball experience equal forces, yet the ball experiences a greater acceleration due to its smaller mass. In a collision, there is a force on both objects that causes an acceleration of both objects. The forces are equal in magnitude and opposite in direction, yet the least massive object receives the greatest acceleration.
Consider the collision between a moving seven ball and an eight ball that is at rest in the sport of table pool. When the seven ball collides with the eight ball, each ball experiences an equal force directed in opposite directions. The rightward moving seven ball experiences a leftward force that causes it to slow down; the eight ball experiences a rightward force that causes it to speed up. Since the two balls have equal masses, they will also experience equal accelerations. In a collision, there is a force on both objects that causes an acceleration of both objects; the forces are equal in magnitude and opposite in direction. For collisions between equal-mass objects, each object experiences the same acceleration.
Temperature is a measure of
Answer:
The average kinetic energy
The amount of heat a substance has or the average kinetic energy of particles in a substance
list of energy changes when hydroelectricity city is made
Answer:
A turbine and generator produce the electricity
Explanation:
"A hydraulic turbine converts the energy of flowing water into mechanical energy. A hydroelectric generator converts this mechanical energy into electricity.
Please help in 5 mintues
A piece of chess game called master
a. king
b. queen
c. rook
d. bishop
Playing with a stress ball you squeeze it as
hard as you can. How does this affect the
density of the ball?
Answer:
it dies
Explanation:
MWUAHHAHAHHA
Change in Energy Quick Check
1 of 5
Which change occurs as an object falls toward the surface of Earth? (1 point)
The force of gravity on the object decreases.
The potential energy of the object decreases.
The acceleration due to gravity decreases.
The kinetic energy of the object decreases
IF SOMEONE GETS THE ANSWERS TO 1-5 of quick check pls post them here
Answer:
The force of gravity on the object decreases. (FALSE)
The potential energy of the object decreases. (TRUE)
The acceleration due to gravity decreases. (FALSE)
The kinetic energy of the object decrease (FALSE)
Explanation:
FORCE OF GRAVITY:
Force of gravity on the object is the weight of object, which depends upon the mass and value of acceleration due to gravity (W = mg). Since, the value mass is constant on Earth and acceleration due to gravity is also constant on earth.
Therefore, force of gravity remains same on the object. The statement is false.
POTENTIAL ENERGY:
Potential energy of object depends upon the mass, value of acceleration due to gravity, and change in height of object (P.E = mgΔh). Since, the value mass is constant on Earth and acceleration due to gravity increases as the object moves towards the surface of earth. But, the height of object is decreasing.
Therefore, potential energy of object decreases. The statement is true.
ACCELERATION DUE TO GRAVITY:
Acceleration due to gravity depends upon the altitude (gh = g[1 - 2h/Re]). Since, the height of object is decreasing.
Therefore, acceleration due to gravity increases. The statement is false.
But, this change is not significant.
KINETIC ENERGY:
Kinetic Energy of object, which depends upon the mass and velocity of the object (K.E = mv²/2). Since, the value mass is constant on Earth and velocity increases as the object moves towards the surface of earth.
Therefore, kinetic energy of the object also increases. The statement is false.
As the object falls towards the surface of the earth, the potential energy of the object decreases.
The earth is a large gravitational field. The potential energy of an object is dependent on its height. As a body falls through a height, its mass remains constant but its height decreases therefore its potential energy decreases also.
Hence, the true statement is that as the object falls towards the surface of the earth, the potential energy of the object decreases.
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A 20-kg bicycle carrying a 50-kg girl is traveling with a kinetic energy of 2,290 J.
What is the velocity of the girl and bicycle?
8 m/s
16 m/s
64 m/s
4 m/s
Answer:
64 m/s
Explanation:
64m/s is the answer of question
64/m/s the answer
Picture a long, straight corridor running east-west, with a water fountain located somewhere along it. Starting from the west end of the corridor, a woman walks a short distance east along the corridor and stops before reaching the water fountain. The distance from her to the fountain is twice the distance she has walked. She then continues walking east, passes the water fountain, and stops 60 m from her first stop. Now the distance from her to the fountain is twice the distance from her to the east end of the corridor. How long is the corridor
Answer:
The corridor's distance is "90 m".
Explanation:
She heads in the east directions but creates the first pause, meaning she crosses the distance 'x' in step 1. Now, provided that perhaps the distance by her to another fountain or waterfall just after the first stop is twice as far away she traveled. Because she moved the distance of 'x,' then, therefore, her distance towards the fountain of '2x.' She casually strolls and once again pauses 60 m beyond her stop. The gap about her to the waterfall during that time approximately twice the distance and her to the eastern end of the hallway.Assume her gap from either the east end of the platform seems to be 'y' at either the second stop, after which '2y' may become the distance between the 2nd pause and the waterfall.Now,
⇒ [tex]2x + 2y = 60[/tex]
⇒ [tex]x + y = 30[/tex]
The total distance of the corridor will be:
= [tex]x + 2x + 2y + y[/tex]
= [tex]3\times (x + y)[/tex]
= [tex]3\times 30[/tex]
= [tex]90 \ m[/tex]
What is magnetic poles always come in pair
3 Points
The half-value layer for lead for g rays from 60Co is 12.8 mm. An electrometer gave a count rate of 35 pulses per second when at a
certain distance from a source, with no lead between source and detector. If 6 mm of lead were then inserted between source and
detector, the count rate (in pulses per second) would be nearest to:
A. 16
OB. 8
OC. 20
D. 25
OE. 75
Answer:
D. 25
Explanation:
The number of pulses per second (p) for x mm of lead can be modeled by the exponential equation ...
p = 35(0.5^(x/12.8))
Then for x=6, the value of p is ...
p = 35·0.5^(6/12.8) ≈ 25.29
The expected count rate would be nearest 25 pps.
Help pls it’s urgent
Answer:
A
Explanation:
Refraction
What type of climate would be near cold ocean currents? PLEASE HELP QUICK!!
Answer:
hot humid with lots of rain.
Explanation:
ocean currents act as conveyer belts of warm and cold water sending heat to the polar regions and helping the tropical areas cool off, thus influencing both weather and climate. the tropics are particularly rainy because heat absorption , and thus ocean evaporation, is highest.
Mild with cooler weather than similar latitudes type of climate would be near cold ocean currents.
What is cold ocean currents?On the eastern side of ocean basins, lower latitudes or the tropics are where cold currents migrate in a direction toward the equator. They carry cold water into regions of the continent that have warm water, which are usually found on the west coastlines.
The Labrador Ocean Current and East Greenland Current flows are two noteworthy examples of cold currents.
From the perspectives of ecology and climate, ocean currents are also advantageous. For example, they are responsible for changing global temperatures.
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how far will a body move in 4sec if uniformly accelerated from rest at the rate of 2m/s2
Answer:
32m
Explanation:
v=u+at
v=0+2×4
v=8m/s
d=vt
d=8×4
d=32m
An airplane flies with a constant speed of 540 miles per hour. How far can it travel in 1 1/4 hours?
Answer:
Hey!
Your answer is 675 MILES!
Explanation:
Using the S = D x T formula...
We first need to convert any values... 1 1/4 hours--75 mins (1.25hrs)
So now we substitute into the formula!
D (distance)= 540 x 1.25 = 675 (Distance = Speed x Time)
Distance Travelled= 675 MILES!
I HOPE THIS HELPED YOU!A 12,000-N car is raised using a hydraulic lift, which consists of a U-tube with arms of unequal areas, filled with oil with a density of 800 kg/m3 and capped at both ends with tight-fitting pistons. The wider arm of the U-tube has a radius of 18.0 cm and the narrower arm has a radius of 5.00 cm. The car rests on the piston on the wider arm of the U-tube. The pistons are initially at the same level. What is the force that must be applied to the smaller piston in order to lift the car after it has been raised 1.20 m
Answer:
The answer is below
Explanation:
Pascal's law states that pressure is exerted in all parts of a static fluid equally.
The area of the narrower arm with a radius of 0.05 m (5 cm) is given as:
Area of narrow arm = π(0.05)²
The area of the wider arm with a radius of 0.18 m (18 cm) is given as:
Area of narrow arm = π(0.18)²
The ratio if the wider arm area to the narrow arm area = π(0.18)² / π(0.05)² = 12.96
To move the 12000 N car, the amount of force needed = 12000/12.96 = 926 N
If a car moves at a velocity of 1.45 x102 m/s for 1.8 x103
seconds. How far does the car go?
Answer:
The answer is
[tex]2.61 \times {10}^{5} \: \: m[/tex]Explanation:
The distance covered by an object given it's velocity and time taken can be found by using the formula
distance = velocity × timeFrom the question
velocity = 1.45 × 10² m/s
time = 1.8 × 10³ s
We have
distance = 1.45 × 10² × 1.8 × 10³
We have the final answer as
[tex]2.61 \times {10}^{5} \: \: m[/tex]
Hope this helps you
3 A stationary car accelerates uniformly
for 20 s. Its velocity reaches 80
km h-1. What is the acceleration of the
car during this period?-
A 1.11 ms-2
B 2.22 ms-2
C 4.00ms-2
D 22.2ms-2
When an object remains stationary, any forces acting on it must be balanced.
Choose 1 answer:
True
False
PLEASE HELP GIVING BRAINLIEST!!
Electrically neutral objects become___when they or lose electrons.
Answer: positively charged
Explanation: basically when a neutral atom gets some electrons it becomes negatively charged and when a neutral atom loses elections it's positively charged Ik science is weird lol.
I hope this was the answer you were looking for.
How many atoms of each element are in 4Na3PO4?
A.) 3 sodium, 1 phosphorus, 4 oxygen
B.) 4 sodium, 4 phosphorus, 4 oxygen
C.) 12 sodium, 1 phosphorus, 4 oxygen
D.) 12 sodium, 4 phosphorus, 16 oxygen
Answer:
D) 12 sodium, 4 phosphorus. 16 oxygen
Explanation:
there is a four in front of the full formula, so you multiply all of the sub numbers by 4
1. Tectonic plates that move toward each other ...A Mantle
2. Layer with partially melted material that can flow easily _....B. Convergent
3. Tectonic plates that move away from each other C. Transform
4. Tectonic plates that slide past each other D. Divergent
Answer:
Its convergent
Explanation:
There areas where plates move toward each other and collide Also known as compressional pr destructive boundaries.
Newton
10. Your mass on Earth is 50kg. Planet Xenon has half the gravitational force of Earth. What
are your weight and mass on Planet Xenon?
Given parameters:
Mass on earth = 50kg
Unknown:
Mass on planet Xenon = ?
Weight on planet Xenon = ?
Mass is the amount of matter contained in a particular substance.
Weight is the force on a body and it is derived from the product of mass and acceleration due to gravity.
Weight = mass x acceleration due to gravity
Planet Xenon has half the gravitational force of Earth.
This translated gives [tex]\frac{9.8}{2}[/tex] = 4.9m/s²
Now, mass is always the same every where if the amount of matter in a substance does not change.
In this problem, mass = 50kg on planet xenon.
Weight = mass x acceleration due to gravity = 50 x 4.9 = 245N
The weight on Xenon is 245N and the mass is 50kg
What is the product of 0.0322 cm x 6.5 cm rounded to the correct number of significant figures?
Answer:
2.093 × 10⁻³ cm²
Explanation:
Given:
0.0322 cm × 6.5 cm
Find:
Product
Computation:
⇒ 0.0322 cm × 6.5 cm
⇒ 0.2093 cm²
2.093 × 10⁻³ cm²
A bowling ball of mass m = 1.7 kg drops from a height h = 14.2 m. A semi-circular tube of radius r = 6.2 m rest centered on a scale. Write an expression for the reading of the scale when the bowling ball is at its lowest point, in terms of the variables in the problem statement.
Answer:
W_net = mg + 2mgh/r
Explanation:
The forces applied in this motion of the bowling ball are both gravitational and centripetal forces.
Now, gravitational force is; F_g = mg
While centripetal force is; F_c = mv²/r
Since we want to express the net force in terms of the variables in the statement and we are not given "v", let's find an expression of v with the variables given.
Now, from Newton's equation of motion, at initial velocity of 0, v² = 2gh.
Thus;
F_c = 2mgh/r
Where;
m is ball mass
r is tube radius
h is fall height
Thus, the net force will be;
F_net = F_g + F_c
Now, Net force would be equal to the net weight that will be read on the scale.
Thus;
W_net = F_net = F_g + F_c
W_net = mg + 2mgh/r
At its lowest point, the net force of the bowling ball is equal to its net weight and this is given by [tex]F_{net} = mg + \frac{2mgh}{r}[/tex]
Given the following data:
Mass, m = 1.7 kg.Height, h = 14.2 meters.Radius, r = 6.2 meters.To write an expression for the reading of the scale when the bowling ball is at its lowest point, in terms of the given variables:
The forces acting on the ball.In this scenario, there are two (2) forces acting on the bowling ball and these include:
Centripetal forceGravitational forceMathematically, centripetal force is given by this formula:
[tex]F_c = \frac{mv^2}{r}[/tex] .....equation 1.
Mathematically, gravitational force is given by this formula:
[tex]F_g= mg[/tex] ....equation 2.
Where:
m is the mass.g is the acceleration due to gravity.v is the velocity.Next, we would derive an expression for the velocity of the ball by applying the Law of Conservation of energy:
[tex]P.E = K.E\\\\mgh = \frac{1}{2} mv^2\\\\V^2=2gh[/tex] .....equation 3.
Substituting eqn. 3 into eqn. 2, we have:
[tex]F_c = \frac{m(2gh)}{r}\\\\F_c = \frac{2mgh}{r}[/tex]
At its lowest point, the net weight of the bowling ball is equal to its net force and this is given by this mathematical expression:
[tex]W_{net} = F_{net} = F_g + F_c\\\\F_{net} = mg + \frac{2mgh}{r}[/tex]
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write .00000023 in scientific notation
Answer: 2.3 x 10^-7
Explanation:
When you move the decimal to the right, you decrease the exponent. So lets count how many spots you have to move the decimal spot to get an answer between 1 and 10. I counted seven spots.
So:
[tex]2.3 *10^-^7[/tex]
2.3 * 10 °−7
The degree indicates that the number is that small thing that floats above
Researchers have measured the acceleration of racing greyhounds as a function of their speed; a simplified version of their results is shown in (Figure 1). The acceleration at low speeds is constant and is limited by the fact that any greater acceleration would result in the dog pitching forward because of the force acting on its hind legs during its power stroke. At higher speeds, the dog's acceleration is limited by the maximum power its muscles can provide.
How far does the dog run until its speed reaches 4.0 m/s?
[tex]\Huge\boxed{\boxed{\dfrac{4}{5}\ \text{meters}}}[/tex]
Let's start by finding the time it takes for the dog to reach a velocity of [tex]4[/tex] m/s.
We can use the following equation, where [tex]v_i[/tex] is initial velocity, [tex]v_f[/tex] is final velocity, [tex]t[/tex] is time, and [tex]a[/tex] is acceleration.
[tex]v_f-v_i=at[/tex]
We're trying to solve for [tex]t[/tex] first, so divide both sides by [tex]a[/tex].
[tex]\dfrac{v_f-v_i}{a}=t[/tex]
Substitute in the known values.
[tex]\dfrac{4-0}{10}=t[/tex]
[tex]\dfrac{4}{10}=t[/tex]
[tex]\dfrac{2}{5}=t[/tex]
Now, we can use the following formula to find the distance.
[tex]s=v_it+\dfrac{1}{2}at^2[/tex]
Substitute in the known values.
[tex]s=0*\dfrac{2}{5}+\dfrac{1}{2}*10*(\frac{2}{5})^2[/tex]
Anything multiplied by [tex]0[/tex] is
[tex]s=\dfrac{1}{2}*10*(\frac{2}{5})^2[/tex]
Just simplify from there.
[tex]s=\dfrac{1}{2}*10*\dfrac{4}{25}[/tex]
[tex]s=5*\dfrac{4}{25}[/tex]
[tex]s=\dfrac{20}{25}[/tex]
[tex]s=\boxed{\dfrac{4}{5}}[/tex]
Hey there!
The hind legs of the dog create it to accelerate.
We know the mass of the dog is 36km (m).
We know that the acceleration of the dog it 10m/s² (a).
Find the average force with the formula [ f = ma ] where m = mass and a = acceleration.
f = 36*10
f = 360 newtons
We don't know the traveled distance but we do know that the starting speed of the dog was 0m/s and the ending speed was 4m/s.
We can use the formula [ vf² = vo² + 2ad ] where vf = final speed, vo = starting speed, a = acceleration, and d = distance.
We know all the variables except the distance, so we are going to solve for d.
(4)² = (0)² + 2(10)(d)
16 = 0 + 20d
16 = 20d
16/20 = 20d/20
0.8 = d
Therefore, the dog runs 0.8 meters until it reaches 4m/s.
Best of Luck!
A block of mass 12.2 kg is sliding at an initial velocity of 6.65 m/s in the positive x-direction. The surface has a coefficient of kinetic friction of 0.253. (Indicate the direction with the signs of your answers.)
a.) What is the force of kinetic friction (in N) acting on the block?
(b What is the block's acceleration (in m/s2)?
(c) How far will it slide (in m) before coming to rest?
Explanation:
Given that,
Mass of the block, m = 12.2 kg
Initial velocity of the block, u = 6.65 m/s
The coefficient of kinetic friction, [tex]\mu_k=0.253[/tex]
(a)The force of kinetic friction is given by :
[tex]f=\mu_k mg[/tex]
mg is the normal force
So,
[tex]f=0.253\times 12.2\times 9.8\\\\f=30.24\ N[/tex]
(b) Net force acting on the block in the horizontal direction,
f = ma
a is the acceleration of the block
[tex]a=\dfrac{f}{m}\\\\a=\dfrac{30.24}{12.2}\\\\a=2.47\ m/s^2[/tex]
(c) Let d is the distance covered by the block before coming to the rest. Using third equation of motion as follows :
[tex]v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{-(6.65)^2}{2\times 2.47}\\\\d=-8.95\ m[/tex]
Hence, this is the required solution.
This question involves the concepts of the frictional force, Newton's second law of motion, and the equations of motion.
a) The force of kinetic friction acting on the block is "-30.28 N".
b) The acceleration of the block is "-2.48 m/s²".
c) The block will slide "8.9 m" before coming to rest.
a)
The kinetic friction force is given by the following formula:
[tex]F=\mu_k mg[/tex]
where,
F = frictional force = ?
[tex]\mu_k[/tex] = coefficient of kinetic friction = 0.253
m = mass of block = 12.2 kg
g = acceleration dueto gravity = 9.81 m/s²
Therefore,
[tex]F=(0.253)(12.2\ kg)(9.81\ m/s^2)[/tex]
F = - 30.28 N (negative sign due to resistive force)
b)
According to Newton's Second Law of Motion:
F = ma
[tex]a=\frac{F}{m} = \frac{-30.28\ N}{12.2\ kg}\\\\[/tex]
a = -2.48 m/s² (negative sign due to deceleration)
c)
Using the third equation of motion to calculate the distance:
[tex]2as=v_f^2-v_i^2[/tex]
where,
s = distance = ?
vf = final speed = 0 m/s
vi = initial speed = 6.65 m/s
Therefore,
[tex]2(-2.48\ m/s^2)s=(0\ m/s)^2-(6.65\ m/s)^2\\\\s=\frac{-(6.65\ m/s)^2}{2(-2.48\ m/s^2)}[/tex]
s = 8.9 m
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The attached picture shows Newton's Second Law of Motion.
1
A truck increases its speed from 15 m/s to 60 m/s in 15 s. Its acceleration is
______ is a disease in which the body does not produce or probory use inslin
Answer:
Diabetes
Explanation:
Insulin is an important hormone that helps the body convert sugar, starches, and other foods into energy.