The table shows the types and numbers of prizes at a carnival game what is the ratio of stuffed animals to posters

Answer:

245 miles

Step-by-step explanation:

210 = 6 gallons

210/6 = how far you can travel with one gallon

210/6 = 35

7*35 = how far you can travel with 7 gallons

7*35 = 245

Answer:

Ann drove 245 miles during her drive last weekend.

Step-by-step explanation:

If Ann used 7 gallons of gas during her drive last weekend, we can use the car's MPG to find out how far she drove by multiplying the number of gallons used by the MPG:

7 gallons * 35 miles/gallon = 245 miles

Five vectors in Span (V₁ V₂) where V₁ = (8 2 7 ) and V₂ = (-6 4 0 ) is.

n(V₁ + V₂), n ∈ I, I = 1, 2, 3, 4, 5.

In mathematics, the set of all linear combinations of the vectors in S is referred to as the linear span, Denoted span(S), Either the intersection of all linear subspaces containing S, or the smallest subspace containing S, can be used to describe it. A vector space is therefore nothing more than the linear range of a set of vectors.

The vectors that are in the same span should be a multiple of the vectors

V₁ = (8 2 7 ), V₂ = (-6 4 0 )

Now, V₁ + V₂ = (2 6 7).

So, The five vectors in the span of V₁ and V₂ is,

2×(2 6 7).

= (4 12 14).

- 2×(2 6 7).

= (- 4 - 12 - 14).

3×(2 6 7).

= (6 18 21)

- 3×(2 6 7)

= (- 6 - 18 - 21).

5×(2 6 7).

= (10 30 35).

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Answer: Set of integers

Integers are positive and negative whole numbers, with 0 included.

Answer: Set of Integers

Step-by-step explanation:

{...,-2,-1,0,1,2...}

since we can see that here is a zero as well as positive and negative numbers, therefore, we call this set, a set of integers.

hope that helps...

Luca's average trip will be 58 miles per hour.

Speed is the rate at which an object's location changes in a particular direction. The distance traveled on relation changes to a particular direction. The distance in relation to the time it took to travel the distance is the speed. It's a scalar quantity.

In this case, it took Luca 8 hours to drive 464 miles from Richmond VA to Cleveland, OH. In miles per hour, Luca's average trip will be:

= Distance / Time

= 464 / 8

= 58 miles per hour.

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Answer:
Here is a sequence of numbers using the rule "x+8":

x+8=9 (x=1)

x+8=10 (x=2)

x+8=11 (x=3)

x+8=12 (x=4)

x+8=13 (x=5)

x+8=14 (x=6)

Here is the sequence of ordered pairs:

(1, 9)

(2, 10)

(3, 11)

(4, 12)

(5, 13)

(6, 14)

So the person talked for 6 minutes.

The unitary approach involves calculating the value of a single unit, from which we may calculate the values of the necessary number of units.

Two quantities are compared to form a ratio. An equality of two ratios is a percentage. How to format a ratio Analyze the ratio to see whether it is part to part or part to whole. Calculate the whole and the pieces as necessary.

To solve this problem, we can use the following equation:

Cost = (Number of minutes x $0.31) + $0.89 + $1.23

We know that cost is $6.15 and the call lasted 6 hours. Since there are 60 minutes in an hour, we can convert the time in hours to minutes by multiplying 6 hours by 60 minutes/hour

So the number of minutes is 6 hours * 60 minutes/hour = 360 minutes

Now we can substitute the values into the equation:

Cost = (360 minutes x $0.31) + $0.89 + $1.23

Cost = $111.6 + $0.89 + $1.23

Cost = $113.72

The equation does not match the $6.15 cost, which means that the person talked for 6 minutes

So the person talked for 6 minutes.

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Answer:316.8

Step-by-step explanation:

Answer:316.8

Step-by-step explanation:

Answer:

8RST. That is, N has thousands digit 8, hundreds digit R, tens digits S, and ones

(units) digit T, which means that N = 8000 + 100R + 10S + T. Suppose that the

following conditions are all true:

• The two-digit integer 8R is divisible by 3.

• The three-digit integer 8RS is divisible by 4.

The four-digit integer 8RST is divisible by 5.

The digits of N are not necessarily all different.

The number of possible values for the integer N is

(A) 8

(B) 16

(C) 12

(D) 10

87

(E) 14

Since 8R is divisible by 3, R must be a multiple of 3. The possible values for R are 3, 6, and 9.

Since 8RS is divisible by 4, S must be a multiple of 2. The possible values for S are 0, 2, 4, 6, and 8.

Since 8RST is divisible by 5, T must be 0 or 5.

The possible values for N are therefore:

8000 + 300 + 00 + 0 = 8300

8000 + 600 + 00 + 0 = 8600

8000 + 900 + 00 + 0 = 8900

8000 + 300 + 20 + 0 = 8320

8000 + 600 + 20 + 0 = 8620

8000 + 900 + 20 + 0 = 8920

8000 + 300 + 40 + 0 = 8340

8000 + 600 + 40 + 0 = 8640

8000 + 900 + 40 + 0 = 8940

8000 + 300 + 60 + 0 = 8360

8000 + 600 + 60 + 0 = 8660

8000 + 900 + 60 + 0 = 8960

8000 + 300 + 80 + 0 = 8380

8000 + 600 + 80 + 0 = 8680

8000 + 900 + 80 + 0 = 8980

8000 + 300 + 00 + 5 = 8305

8000 + 600 + 00 + 5 = 8605

8000 + 900 + 00 + 5 = 8905

8000 + 300 + 20 + 5 = 8325

8000 + 600 + 20 + 5 = 8625

8000 + 900 + 20 + 5 = 8925

8000 + 300 + 40 + 5 = 8345

8000 + 600 + 40 + 5 = 8645

8000 + 900 + 40 + 5 = 8945

8000 + 300 + 60 + 5 = 8365

8000 + 600 + 60 + 5 = 8665

8000 + 900 + 60 + 5 = 8965

8000 + 300 + 80 + 5 = 8385

8000 + 600 + 80 + 5 = 8685

8000 + 900 + 80 + 5 = 8985

There are a total of 30 possible values for N. The answer is therefore (E) 14.

Step-by-step explanation:

Answer: jump off a cliff and shatter your bones

Step-by-step explanation:

Answer:

- 2x +29

Step-by-step explanation:

Open up the parenthesis, then simplify

14 + 5x + 15 - 7x

5x - 7x + 14 + 15

-2x + 29

[tex]14+5(x+3) - 7x[/tex]

Distribute:

[tex]14+(5)(x)+(5)(3)-7x[/tex]

[tex]14+5x+15-7x[/tex]

Combine Like Terms:

[tex](5x-7x)+(14+15)[/tex]

[tex]\fbox{-2x + 29}[/tex]

The elevation at which the race ends is given by the equation A = 195 feet

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the elevation at which the race ends be A

Now , the equation will be

The bike road race starts at an elevation of 500 feet

So , the initial elevation = 500 feet

The number of stages = 5 stages

The elevation at first stage = -139 feet

The elevation at second stage = -63 feet

The elevation at third stage = 197 feet

The elevation at fourth stage = 27 feet

The elevation at fifth stage = -327feet

So , the total elevation of all the stages during the bike race = initial elevation + elevation at first stage + elevation at second stage + elevation at third stage + elevation at fourth stage + elevation at fifth stage

Substituting the values in the equation , we get

The total elevation of all the stages during the bike race = elevation at which the race ends A

So ,

Elevation at which the race ends A = 500 + (-139) + (-63) + (197) + (27) + (-327)

On simplifying the equation , we get

Elevation at which the race ends A = 500 - 305

Elevation at which the race ends A = 195 feet

Therefore , the value of A is 195 feet

Hence , the race ends at an elevation of 195 feet

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Answer: I say 13

Step-by-step explanation:

Total cost is the sum of all expenses incurred to produce a particular type of product. The answer is $1.50.

Total cost is the sum of all expenses incurred to produce a specific kind of output. Financial reporting, when overhead costs must be allocated to specific assets, is where the total cost approach is more useful from an accounting standpoint.

$8 was spent in total.

Xavier bought four $1.25 snacks.

4 x 1.25 = $5

The 2 cans cost $3 because 5 + 3 = 8, and we know how much the snacks cost ($5), making the total cost ($8).

Each can cost $1.50 because, if the price of the two cans was $3, we would have to divide it by two to get the price of the second can, which comes out to be $1.50. As a result, each can was $1.50.

Therefore, the answer is $1.50.

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Greatest common factor (GCF) of 50 and 65 is 5.

We will first find the prime factorization of 50 and 65. After we will calculate the factors of 50 and 65 and find the biggest common factor number .

Step-1: Prime Factorization of 50

Prime factors of 50 are 2, 5. Prime factorization of 50 in exponential form is:

50 = 21 × 52

Step-2: Prime Factorization of 65

Prime factors of 65 are 5, 13. Prime factorization of 65 in exponential form is:

65 = 51 × 131

Step-3: Factors of 50

1, 2, 5, 10, 25

Final Step: Biggest Common Factor Number

We found the factors and prime factorization of 50 and 65. The biggest common factor number is the GCF number.

So the greatest common factor 50 and 65 is 5.

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Step-by-step explanation:

the area of a trapezoid is

(a + b)/2 × x

a and b being the 2 bases. and x, as requested, is the height.

A

it does not matter which base is which, as long as we keep using them consistently.

so, let's assume a is the first base :

a = x + 5

and then for the second base

b = 2x - 1

now we use that in the main formula :

(x + 5 + 2x - 1)/2 × x = (3x + 4)/2 × x = (3x² + 4x)/2

A = (3/2)x² + (4/2)x = (3/2)x² + 2x ft²

B

now the height is increased by 4 ft.

that means we need to replace x by x + 4.

(3/2)(x+4)² + 2(x+4) = (3/2)(x² + 8x + 16) + 2x + 8 =

= (3/2)x² + (24/2)x + (48/2) + 2x + 8 =

= (3/2)x² + 12x + 24 + 2x + 8 =

= (3/2)x² + 14x + 32 ft²

with x being the original height, of course.

Answer:

X > -20

Step-by-step explanation:

-10 - 9/2 x < 80

Move 10 to the other side

- 9/2 x < 80 + 10

Simplify

-9/2 x < 90

-9 x < 180

x > -20

(We switch the inequality sign if we are dividing with negatives)

This is a separable differential equation, which means we can separate the variables y and x on either side of the equation. To do this, we'll move all the terms involving y to one side and all the terms involving x to the other side.

dy/dx = (1+y²)e^x

We'll divide both sides by (1+y²)e^x:

dy/(1+y²)e^x = dx

Now we'll integrate both sides with respect to their respective variables. The integral of dy/(1+y²) with respect to y is the inverse tangent (tan^-1) function, so we'll use that on the left side:

∫ dy/(1+y²) = ∫dx + C

tan^-1(y) = x + C

On the right side, we'll integrate e^x with respect to x, which gives us e^x. So we have:

tan^-1(y) = e^x + C

We can solve for y by reversing the tan^-1 function:

y = tan(e^x + C)

Where C is an arbitrary constant of integration.

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Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:

One side of a square field is 92m. Find the cost of raising lawn on the field at the rate of 1.50 per sq.m

Square area = l²

Square area = 92²

Square area = 8466 m²

Cost = Area × rate of 1.50 per sq.m

Cost = 8466 × 1.50

Cost = 12696

Answer: To find the value of g(2+h)-g(2) divided by h, we can use the definition of the derivative. The derivative of a function at a point is a measure of the slope of the function at that point, and it can be calculated by taking the limit of the difference quotient as h approaches 0.

The difference quotient is defined as:

[g(2+h) - g(2)] / h

So, to find the derivative of g at x=2, we can substitute the value of x in the function g(x) and take the limit as h approaches 0:

lim h→0 [g(2+h) - g(2)] / h

Substituting the value of x in the function g(x), we get:

lim h→0 [(2+h)³ - 2(2+h) - (2² - 2*2)] / h

This simplifies to:

lim h→0 [8+6h+h²-2h - 4] / h

Which simplifies to:

lim h→0 [h²+6h+4] / h

And, finally:

lim h→0 [h(h+6)] / h

The limit of a quotient is equal to the quotient of the limits, as long as the limit of the denominator is not 0. In this case, the limit of the denominator (h) is 0, but the limit of the numerator (h(h+6)) is not. Therefore, we can safely take the limit:

h+6

So, the derivative of g at x=2 is h+6. When h=0, the derivative is equal to the function's value at that point, so the value of g(2) is 6.

Therefore, the value of g(2+h)-g(2) divided by h is:

(h+6) - 6 / h

Which simplifies to:

h / h

Which is equal to:

1

So, the final answer is 1.

Step-by-step explanation:

Answer:

It is the first answer,

Step-by-step explanation:

The hypotenuse is always the longest side and opposite of the right angel.  Side b is the adjacent side to J and c is the opposite side of J.

An example of limit in polynomial will be the polynomial function f(x) = x³ + 2x² - 5. As x approaches 2, the value of the function approaches 11. So, the limit of f(x) as x approaches 2 is 11.

A polynomial simply means an expression which is composed of variables, constants and exponents, which are combined using mathematical operations such as addition, subtraction, multiplication and division

In mathematical notation, we can write it as: Here, lim x->2 (x³ + 2x² - 5)

= x³ + 2x² - 5

= 2³ + 2(2²) - 5

= 8 + 8 - 5

= 11

This means that as x gets arbitrarily close to 2, the values of the function gets arbitrarily close to 11.

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Therefore , the solution to the given problem of equation comes out to be quotient : x² +x+6+ [tex]\frac{2}{x+2}[/tex] and remainder is 2

A mathematical depiction of two equal variables, one on either side of a "equals" sign, is called an equation. Equations can be used to solve common problems. To solve challenges in real life, we frequently turn for pre algebra assistance. Lessons in pre-algebra cover the foundational ideas of mathematics.

Here,

Given : synthetic division for

x³ + 3x² + 8x + 14

------------------------

x + 2

Write the problem in synthetic division format

-2  | 1 3 8 14

         -2 -2  

------------------------

     1   1  6

Carry down the leading coefficient, unchanged, to below the division symbol

-2  |    1 3 8 14

           -2 -2

---------------------------

         1  1   6

Multiply the carry - down value by the zero of the denominator, and carry the result up into the next column:

1(-2)=-2

-2 |  1 3 8 14

        -2 - 2

------------------

     1    1   6

=> We get:

As

x² +x+6+ [tex]\frac{2}{x+2}[/tex]

and remainder is 2

Therefore , the solution to the given problem of equation comes out to be quotient : x² +x+6+ [tex]\frac{2}{x+2}[/tex] and remainder is 2.

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Carmen and her dog, Duke walked at a slower rate at 0.625 blocks/min

Carmen and her dog, Duke would take 19.2 minutes to work 12 blocks.

In math, a rate is a ratio that compares two different quantities which have different units. For example, if we say John types 50 words in a minute, then his rate of typing is 50 words per minute. The word "per" gives a clue that we are dealing with a rate. The word "per" can be further replaced by the symbol "/" in problems.

Carmen/Duke walks 5/8 = 0.625

Terell/Lady walks 8/12 = 0.677

Therefore, from the average time, Carmen and Duke walk slower.

Carmen and Duke will walk 12 blocks in;

= 12/0.625

= 19.2 minutes

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The range of the absolute function will be from 0 to 9. Then the correct option is A.

The absolute function is also known as the mode function. The value of the absolute function is always positive.

If the vertex of the absolute function is at (h, k). Then the absolute function is given as

f(x) = | x - h| + k

The domain means all the possible values of x and the range means all the possible values of y.

From the graph, the range of the absolute function will be from 0 to 9.

Then the correct option is A.

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The complete question is attached below.

Answer:

3.4 seconds

Step-by-step explanation:

Given function:

[tex]h(t)=-4.9t^2+2.45t+48.314[/tex]

where

The ball will strike the ground when its height is zero.

Therefore, to calculate when the ball strikes the ground, substitute h(t) = 0 and solve for t using the quadratic formula.

[tex]\boxed{\begin{minipage}{3.6 cm}\underline{Quadratic Formula}\\\\$x=\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}$\\\\when $ax^2+bx+c=0$ \\\end{minipage}}[/tex]

Therefore:

Substitute these values into the quadratic formula:

[tex]\implies t=\dfrac{-2.45 \pm \sqrt{(2.45)^2-4(-4.9)(48.314)}}{2(-4.9)}[/tex]

[tex]\implies t=\dfrac{-2.45 \pm \sqrt{6.0025+946.9544}}{-9.8}[/tex]

[tex]\implies t=\dfrac{-2.45 \pm \sqrt{952.9569}}{-9.8}[/tex]

[tex]\implies t=\dfrac{-2.45 \pm 30.87}{-9.8}[/tex]

[tex]\implies t=\dfrac{-2.45 + 30.87}{-9.8}=-2.9[/tex]

[tex]\implies t=\dfrac{-2.45 -30.87}{-9.8}=3.4[/tex]

As time cannot be negative, t = 3.4 s only.

Therefore, the ball strikes the ground 3.4 seconds after it is launched.