The table below represents the cost that a computer repair company charges for the amount of hours that they will work to repair a computer.

Write an equation that can be used to determine the charge for a computer repair for any possible number of hours the repair takes to complete. Explain what each part of the equation represents.

Total area of shaded region in trapezoid is 54.4in²

A trapezoid is a four-sided, quadrilateral shape with two parallel sides, which are called the bases, and two non-parallel sides, which are called the legs.

The formula for the area of a trapezoid is:

Area = (1/2) × (sum of the bases) × (height)

The Shaded region in trapezoid form right angled triangle.

Area of 1st shaded region=area of right triangle

=1/2×b×h

=1/2×6.8×7.4

=25.16in²

Area of 2nd shaded region=area of right triangle

=1/2×b×h

=1/2×6.8×8.6

=29.24in²

Hence, total area of shaded region in trapezoid is 54.4in²

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Therefore, the approximate dimensions of the rectangle to the nearest tenth of a meter are width = 7.9 m and length = 10.8 m.

Area is a measure of the size of a two-dimensional surface or shape. It is typically expressed in square units, such as square meters (m²), square centimeters (cm²), square feet (ft²), or square inches (in²).

Here,

Let's denote the width of the rectangle as "w" in meters. Then, according to the problem statement, the length of the rectangle can be expressed in terms of the width as:

length = 2w - 5

The area of the rectangle is given as 97 square meters, so we can write:

area = length × width

Substituting the expression for length in terms of the width, we get:

area = (2w - 5) × w

Expanding this expression, we get a quadratic equation in standard form:

2w² - 5w - 97 = 0

We can solve this equation using the quadratic formula:

w = (-(-5) ± √((-5)² - 4×2×(-97))) / (2×2)

Simplifying this expression, we get:

w ≈ 7.9 or w ≈ -6.2

Since the width of a rectangle cannot be negative, we discard the negative solution and approximate the width to the nearest tenth of a meter:

w ≈ 7.9 m

Using the expression for the length in terms of the width, we can find the length:

length = 2w - 5

≈ 10.8 m

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If the sample size is large and the probability of success is not too close to 0 or 1, using the normal distribution to approximate the binomial probability will generally give a more accurate answer than using the binomial tables. However, if the sample size is small or the probability of success is very close to 0 or 1, using the binomial tables may be more accurate.

If the sample size is large (typically, n ≥ 30) and suppose that the probability of success (p) is not too close to 0 or 1, then we can use the normal distribution. As it gives more approximate value to the binomial probability which will generally give a more accurate answer than using the binomial tables.

This is because the normal distribution provides a more precise approximation of the binomial distribution as the sample size increases.

However, if the the probability of success is very close to 0 or 1 or sample size is small then using the binomial tables to calculate the probability directly may be more accurate. In general, it's important to check the conditions for using the normal approximation before using it and to use good judgment in deciding which method is more appropriate for a given problem.

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To graph g(x), we must replace x with x + 1 in the function f(x) = 2x - 5: g(x) = f(x + 1) = 2(x + 1) - 5 = 2x - 3 (a) To display the g of x line that passes through the coordinates 0, -4, and 2, 0, we replace x = 0 and x = 2 in the equation g(x) = 2x - 3:

g(0) = 2(0) - 3 = -3

g(2) = 2(2) - 3 = 1

Hence the line's points are (0, -3) and (2, 1):

yaml Copy code | 5 |- * (2,1) | 4 |- | 3 |- * (0,-3) | 2 |- | 1 |- | 0 |—————————— 0 1 2 3 4 5\s(b) (b) To display the g of x line that passes through points 0, -3, 4, 5, we replace x = 0 and x = 4 in the equation g(x) = 2x. - 3:

g(0) = 2(0) - 3 = -3

g(4) = 2(4) - 3 = 5

Hence the line's points are (0, -3) and (4, 5):

Copy code in yaml | 5 |- * (4,5)

|\s4 |-\s |\s3 |- * (0,-3)\s |\s2 |-\s |\s1 |-\s |\s0 |

————————-\s 0 1 2 3 4 5\s(c) (c) To display the line labeled g of x that goes through points -5, -3, and 0, 7, we use the equation g(x) = 2x - 3:

g(-5) = 2(-5) (-5) - 3 = -13\sg(0) = 2(0) - 3 = -3

Thus the line points are (-5, -13) and (0, -3):

| 5 |- | 4 |- | 3 |- | 2 |- | 1 |- | 0 |- * (0,-3) | -1 |- (-5,-13)

\ \s ——————-\s -5 -4 -3 -2 -1 0\s(d) To draw the g of x line that passes between points 0, -7, and 5, 3, In the equation g(x) = 2x - 3 we substitute x = 0 and x = 5:

g(0) = 2(0) - 3 = -3

g(5) = 2(5) (5) - 3 = 7

Hence the line's points are (0, -3) and (5, 7):

| 7 |- * yaml Copy code (5,7)

|\s6 |-\s |\s5 |- \s | * (0,-3) (0,-3)

4 |-\s |\s3 |-\s |\s2 |-\s |\s1 |-\s |\s0 |

————————-\s 0 1 2 3 4 5.

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The statement of Chang's is not correct.

Here given Chang's equation is x = 3y, which means that the length of the longest ski trail (x) is three times the length of the shortest ski trail (y).

Therefore, if we assume that the length of the shortest ski trail is y, then the length of the longest ski trail would be 3y.

So, in Chang's statement, he says that the longest ski trail is more than three times the length of the shortest ski trail. This would mean that x > 3y. However, according to Chang's equation, x = 3y, which contradicts his statement.

Therefore, Chang is incorrect in saying that the longest ski trail is more than three times the length of the shortest ski trail. In fact, the longest ski trail is exactly three times the length of the shortest ski trail, as per Chang's equation.

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Correct question is "Chang has an equation x=3y where x is length of longest ski trail and y is length of the shortest ski trail.

Chang says the longest ski trail is more than three times the length of the shortest ski trail.

Is Chang correct? Explain."

Answer:

yes these 2 triangles are similar

Step-by-step explanation:

triangle ABC is similar to triangle ADE. it has a scale factor of 1.5. It is a dilated. 10×1.5=15 so it has a scale factor of 1.5 which is an enlargement. any scale factor greater than 1 increases the size of the triangle. it is proportional if you multiply both sides by the scale factor (1.5) you get 15. also The angles are equal (AA similarity) these two triangles are NOT congruent but they are similar the degrees are equal. btw SSS and SAS are congruence postulates NOT similarity. so therefore they are similar because of AA

i hope this helps :)

The experimental probabilities have their values to be P(3) = 1/12, P(6) = 1/4 and P(Less than 4) = 1/2

Experimental probability of 3

From the table of values, we have

n(3) = 1

Total = 12

So, we have

P(3) = 1/12

Experimental probability of 6

From the table of values, we have

n(6) = 3

Total = 12

So, we have

P(6) = 3/12

P(6) = 1/4

Experimental probability of less than 4

From the table of values, we have

n(Less than 4) = 6

Total = 12

So, we have

P(Less than 4) = 6/12

P(Less than 4) = 1/2

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Answer:

[tex]\boxed{\frac{1}{12}}[/tex]

Step-by-step explanation:

The multiplication of fractions satisfies the following rule:

[tex]\displaystyle{\frac{a}{b}\times\frac{c}{d}=\frac{a\times c}{b\times d}[/tex]

applied to our exercise, it looks like this

[tex]\displaystyle{\frac{5}{14}\times\frac{7}{30}=\frac{5\times 7}{14\times 30}[/tex]

also, we can "decompose" denominator numbers as follows:

[tex]14=7*2[/tex]

[tex]30=5*6[/tex]

Therefore:

[tex]\displaystyle\frac{\not{5}\times \not{7}}{2 \times \not{7}\times \not{5}\times 6}= \frac{1}{12}[/tex]

In this way, only one multiplication was necessary.

[tex]\text{-B$\mathfrak{randon}$VN}[/tex]

The correct answer is: No, because for each input there is not exactly one output.

In mathematics, a function is a relation between two sets, where each element in the first set (called the domain) is associated with exactly one element in the second set (called the codomain or range). A function assigns a unique output value (dependent variable) to each input value (independent variable) from the domain.

The given relation does not represent a function because for some inputs there are multiple outputs, violating the "one-to-one" or "vertical line test" rule.

The correct answer is: No, because for each input there is not exactly one output.

In this relation, we can see that x = 1 has two different outputs, y = 5 and y = -1/2. Therefore, the relation does not meet the criteria of a function as it violates the requirement of having exactly one output for each input.

Therefore, The correct answer is: No, because for each input there is not exactly one output.

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The line that is parallel to AC and passes through B has the equation y: 1/5x + 12/5.

The formula for a straight line is y=mx+c where c is the height at which the line intersects the y-axis, also known as the y-intercept, and m is the gradient.

The benefit of expressing a linear equation in this way is that the values for m and b correspond to the slope and y-intercept, respectively.

This makes it easy to graph the line that the equation describes.

So, the slope of AC is:

6-1/1/2= 5/-1 = -5

The equation of line D, which passes through B and is perpendicular to AC, is given as y: mx + p.

Where p is the y value of the y-intercept point and m is the slope.

The fact that line D is perpendicular to line AC indicates that their slopes add up to one.

Therefore,

(−5) × m = −1

Now,

m = -1/-5 = 1/5

We discover that the D equation is:

Y: 1/5x + p

To complete the equation of D at this time, we still require the value of p.

B(3, 3)∈ D

3 = 1/5(3) + p

p = 3 - 3/5 = 12/5 = 2.4

Hence, equation D will be:

y: 1/5x + 12/5

Therefore, the line that is parallel to AC and passes through B has the equation y: 1/5x + 12/5.

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Correct question:

Finding the area of a triangle is straightforward if you know the length of the base and the height of the triangle. But is it possible to find the area of a triangle if you know only the coordinates of its vertices? In this task, you’ll find out. Consider ΔABC, whose vertices are A(2, 1), B(3, 3), and C(1, 6); let line segment AC represent the base of the triangle.

Part A

Find the equation of the line passing through B and perpendicular to AC .

Answer: 48.5 sq units

Step-by-step explanation:

7*8=56, 56-7.5= 48.5

Answer: they are adding 30 each time

Step-by-step explanation:

in 320 to 350, it adds 30 because 20 plus 30 equals 50 then you can add 300 which is 350 then 350 plus 30 is 380 which is also the next number which means you are adding 30 each time and for the first box you subtract 30 from 350 which is 320 and for the last box you add 30 which is 380 + 30 which is 410 so that is your answer.

The aggregate functions that can be used with grouped data include:
COUNT(), SUM(), AVG(),  MIN().,MAX().

1. COUNT(): This function counts the number of rows in a group.
2. SUM(): This function adds up the values of a specified column within a group.
3. AVG(): This function calculates the average of a specified column within a group.
4. MIN(): This function finds the minimum value of a specified column within a group.
5. MAX(): This function finds the maximum value of a specified column within a group.
These functions can be used in combination with the GROUP BY clause in SQL to perform calculations on grouped data.

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The cosine of angle X is 0.75 of triangle WXV.

In a right-angled triangle, the cosine of an angle is equal to the adjacent side divided by the hypotenuse. Therefore, to find cos(X) in triangle XWV, we need to find the adjacent and hypotenuse sides that correspond to angle X.

We know that WV = 72, which is the length of the side opposite the right angle. To find the length of the hypotenuse XV, we can use the Pythagorean theorem: [tex]XV^{2}[/tex] = [tex]WV^{2}[/tex] + [tex]WX^{2}[/tex], where WX is the length of the side adjacent to angle X.

Solving for WX, we get:

[tex]WX^{2}[/tex] = [tex]XV^{2}[/tex] - [tex]WV^{2}[/tex]

[tex]WX^{2}[/tex]= [tex]90^{2}[/tex] - [tex]72^{2}[/tex]

[tex]WX^{2}[/tex] = 2916

WX = 54

Now we can find cos(X):

cos(X) = adjacent/hypotenuse

cos(X) = WX/WV

cos(X) = 54/72

cos(X) = 0.75

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Answer:

P=40 and y was decreased by 40%

Step-by-step explanation:

Let's set up an equation as follows. In this case, we will set y will be equivalent to 1, as the number can be any value for this equation in the other fraction as the original number. Let us then represent the new number, 0.6y, or 0.6*1 which will be equivalent to 0.6 itself, and we will set that equal to 100-p as p will be the amount of percent it was decreased by. Here is the equation as follows:

We can use a method of solving fractions that is known as the Cross-multiplication property, which demonstrated in the image attached below this answer. Using this property, we can determine and simplify the equation to as follows:

[tex]1*(100-p)=0.6(100)[/tex], which can be simplified to [tex]100-p=60[/tex], and then solving the equation gives us the answer:

[tex]p=40[/tex]

P=40

For the the inequality –3(2x – 5) < 5(2 – x) the correct options are: x < 5, –6x + 15 < 10 – 5x

What is inequalities?

In mathematics, an inequality is a mathematical statement that indicates that two expressions are not equal. It is a statement that compares two values, usually using one of the following symbols: "<" (less than), ">" (greater than), "≤" (less than or equal to), or "≥" (greater than or equal to).

The correct representations of the inequality –3(2x – 5) < 5(2 – x) are:

x < 5 (obtained by simplifying the inequality and solving for x)

–6x + 15 < 10 – 5x (obtained by distributing the terms and simplifying the inequality)

Therefore, the correct options are:

x < 5

–6x + 15 < 10 – 5x

The options that describe number lines are not applicable to this inequality since they represent a single value, whereas an inequality represents a range of values that satisfy the inequality.

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Answer:

x= 7

Step-by-step explanation:

The quarterly dividend fοr οne share οf Bοοtle is $12.52.

A divisiοn is οne οf the fundamental mathematical οperatiοns that divides a larger number intο smaller grοups with the same number οf cοmpοnents. Hοw many tοtal grοups will be established, fοr instance, if 20 students need tο be separated intο grοups οf five fοr a spοrting event?

The divisiοn οperatiοn makes it simple tο tackle such issues. Divide 20 by 5 in this case. 20 x 5 = 4 will be the οutcοme. There will therefοre be 4 grοups with 5 students each. By multiplying 4 by 5 and receiving the result 20, yοu may cοnfirm this value.

Tο find the quarterly dividend fοr οne share οf Bοοtle, we can divide the tοtal quarterly dividend payment by the number οf shares Leslie οwns:

Quarterly dividend per share = Tοtal quarterly dividend payment / Number οf shares

Quarterly dividend per share = $1,490 / 119

Quarterly dividend per share = $12.52 (rοunded tο twο decimal places)

Therefore, the quarterly dividend for one share of Bootle is $12.52.

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To determine the length of the third side of the triangle, we can use the triangle inequality theorem, which states that the sum of the lengths of any two sides of a triangle must be greater than the length of the third side.

In this case, we have two sides of lengths 24 ft and 15 ft. Let x be the length of the third side. Then, according to the triangle inequality theorem, we have:

24 + 15 > x

39 > x

and

15 + x > 24

x > 9

Combining these inequalities, we have:

9 < x < 39

Therefore, the length of the third side of the fence could be any value between 9 ft and 39 ft, but it cannot be exactly 7 ft, 8 ft, or 10 ft. Out of the given options, the closest value to the range is 9 ft.

There are 2,139,792,767,488,000 ways to assign scores to the problems if the sum of the scores is 100 and each question is worth at least 5 points.

To solve this problem, we will use the concept of combinations with repetition.

First, let's subtract 5 points from each question, since each question is worth at least 5 points. Now, we need to distribute the remaining 50 points (100 - 10*5) among the 10 questions.

Imagine that we have 50 identical balls (points) to distribute among 10 distinct boxes (questions). To do this, we can use a technique called "stars and bars". We need to place 9 dividers (bars) between the 50 balls (stars) to divide them among the 10 questions.

We will have a total of 59 positions (50 stars + 9 bars). We need to choose 9 of these positions for the bars, and the stars will fill the remaining positions.

The number of ways to do this is given by the combination formula:

C(n, k) = n! / (k! * (n - k)!)

In our case, n = 59 (total positions) and k = 9 (dividers). So, we need to calculate C(59, 9):

C(59, 9) = 59! / (9! * (59 - 9)!)
C(59, 9) = 59! / (9! * 50!)
C(59, 9) = 2,139,792,767,488,000

Therefore, there are 2,139,792,767,488,000 ways to assign scores to the problems if the sum of the scores is 100 and each question is worth at least 5 points.

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Step-by-step explanation:

Area of a triangle = 1/2 * base * height

 For this triangle   base =  9 m   height =  8 m

1/2 ( 9 ) ( 8) = 36 m^2

There are  212520  ways by which guests arrange themselves on a four person coach.

The term permutation refers to a mathematical calculation of the number of ways a particular set can be arranged. Put simply, a permutation is a word that describes the number of ways things can be ordered or arranged. With permutations, the order of the arrangement matters.

there are total 23 guests and they arranged themselves in 4 person coach,

so,

n = 23 and r = 4

npr = n!/(n-r)!

= 23!/(23-4)!

= 23!/19!

= 23x 22 x 21 x 20x 19!/19!

now cancel the factorial 19 from numerator as well as denominator

=  23x 22 x 21 x 20

= 212520

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Answer: The answer is 7

Step-by-step explanation:

The surface area of a rectangular prism can be found using the formula:

A = 2lw + 2lh + 2wh

where l, w, and h are the length, width, and height of the prism, respectively.

Substituting the given values, we get:

A = 2(5 cm)(6 cm) + 2(5 cm)(7 cm) + 2(6 cm)(7 cm)

A = 60 cm² + 70 cm² + 84 cm²

A = 214 cm²

Therefore, the surface area of the rectangular prism is 214 cm².

Answer:41,328

Step-by-step explanation:

18+7+11=36 36%

100-36=64 64%

25,200 x 164%=41,328

Answer:

$30

Step-by-step explanation:

6x3=18

        +

4x3=12

=30

The data set as there are some large residuals, such as 4 and -7, indicating that the actual fares are not well-predicted by the linear equation.

In statistics, residuals refer to the differences between the observed values of a variable and the values predicted by a statistical model. They are calculated by subtracting the predicted values from the observed values.

To calculate the residuals, we first need to find the predicted fares for each distance using the equation y = 0.1 x + 12;

Miles        Fares $          Predicted Fares $              Residuals $

50               14                          17                                     -3

40               16                          16                                     0

60               16                          18                                     -2

30               14                          15                                     -1

60               22                         18                                     4

70               12                          19                                     -7

80               24                         20                                     4

To find the residuals, we subtract the predicted fare from the actual fare. If the predicted fare is greater than the actual fare, the residual is negative, and if the predicted fare is less than the actual fare, the residual is positive. We can see that a linear model may not be appropriate for the data set as there are some large residuals, such as 4 and -7, indicating that the actual fares are not well-predicted by the linear equation.

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a) The probability that more than 180 customers will take your free sample is approximately 0.9999.

b) The probability that fewer than 200 customers will take your free sample is approximately 0.0119.

c) Therefore, the probability that a customer will take a free sample and buy the product is 0.21.

d) The probability that between 60 and 80 customers will take the free sample and buy the product is approximately 0.043

a) Let X be the number of customers who take the free sample.

We know that X follows a binomial distribution with n = 327 and p = 0.58. To find the probability that more than 180 will take free sample, we need to find P(X > 180).

Using a binomial calculator or software, we get:

P(X > 180) = 1 - P(X ≤ 180) = 1 - binomial distribution (180, 327, 0.58, TRUE) ≈ 0.9999

Therefore, the probability that more than 180 customers will take your free sample is approximately 0.9999.

b) To find the probability that fewer than 200 will take your free sample, we need to find P(X < 200).

Using a binomial calculator or software, we get:.

P(X < 200) = binomial distribution (199, 327, 0.58, TRUE) ≈ 0.0119

Therefore, the probability that fewer than 200 customers will take your free sample is approximately 0.0119.

c) Let A be the event that a customer takes a free sample, and B be the event that the customer buys the product.

We are given P(B|A) = 0.35 and P(A) = 0.60.

Using the multiplication rule for dependent events, we get:

P(A ∩ B) = P(B|A) × P(A) = 0.35 × 0.60 = 0.21

Therefore, the probability that a customer will take a free sample and buy the product is 0.21.

d) Let Y be the number of customers who take the free sample and buy the product. We know that Y follows a binomial distribution with n = 327 and p = 0.21 (from part c). .

To find the probability that between 60 and 80 customers will take the free sample and buy the product, we need to find P(60 ≤ Y ≤ 80).

Using a binomial calculator or software, we get:

P(60 ≤ Y ≤ 80) = binomial distribution (80, 327, 0.21, TRUE) - binomial distribution (59, 327, 0.21, TRUE) ≈ 0.0434

Therefore, the probability that between 60 and 80 customers will take the free sample and buy the product is approximately 0.0434.

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Question: Do You Take The Free Samples Offered In Supermarkets? About 58 % Of All Customers Will Take Free Samples.

Furthermore, Of Those Who Take The Free Samples, About 37% Will Buy What They Have Sampled. Suppose You Set Up A Counter In A Supermarket Offering Free Samples Of A New Product. The Day You Were Offering Free Samples, 327Customers Passed By Your

Do you take the free samples offered in supermarkets? About 58% of all customers will take free samples. Furthermore, of those who take the free samples, about 37% will buy what they have sampled. Suppose you set up a counter in a supermarket offering free samples of a new product. The day you were offering free samples, 312 customers passed by your counter.(round your answers to four decimal places.)

a.) What is the probability that more than 180 will take your free sample?

b.) What is the probability that fewer than 200 will take your free sample?

c.) What is the probabilty that a customer will take a free sample and buy the product? Hint: Use the multiplication rule for dependent events. Notice that we are given the conditional probability P(buy|sample)=0.35, while P(sample)=0.60

d.) What is the probability that between 60 and 80 customers will take the free sample and buy the product? HInt: Use the probability of success calculated in part(c).

The correct order of the set of numbers from least to greatest is 2, 3 over 4, 2.71 repeating 71, 5 over 2, square root 5 option (D) is correct.

To order the given set of numbers from least to greatest, we need to compare their values. We start by noticing that 2 and 3 over 4 are equivalent to 2.75. Next, we compare the values of the remaining numbers. Since the square root of 5 is approximately 2.236 and 5 over 2 is equivalent to 2.5, we have:

2, 3 over 4 < 2.71 repeating 71 < 2.5 < square root 5

Therefore, the set of numbers in order from least to greatest is 2, 3 over 4, 2.71 repeating 71, 5 over 2, square root 5.

Ordering the set of numbers from least to greatest, we get:

2, 3 over 4, 2.71 repeating 71, square root 5, 5 over 2.

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The complete question is:

Order the set of numbers from least to greatest: (Group of answer choices)

A. 2.71 repeating 71, 2, and 3 over 4, square root 5, 5 over 2.

B. square root 5, 5 over 2, 2.71 repeating 71, 2 3 over 4

C. 5 over 2, square root 5, 2.71 repeating 71, 2 3 over 4

D. 2, 3 over 4, 2.71 repeating 71, 5 over 2, square root 5

Answer:

5x−5≥−185x-5≥-18Move all terms not containing xx to the right side of the inequality.Tap for more steps...5x≥−135x≥-13Divide each term in 5x≥−135x≥-13 by 55 and simplify.Tap for more steps...x≥−135x≥-135The result can be shown in multiple forms.Inequality Form:x≥−135x≥-135Interval Notation:[−135,∞)

The required answer is  x represents any real number greater than or equal to -13/5 in terms of the result of solving linear inequalities,

Given that, linear inequalities 5x−5≥− 18

To solve the inequality 5x - 5 ≥ -18, we can follow these steps:

Step 1: Add 5 to both sides of the inequality to isolate the term with x:

5x - 5 + 5 ≥ -18 + 5

This simplifies to:

5x ≥ -13

Step 2: Divide both sides of the inequality by 5 to solve for x:

(5x)/5 ≥ (-13)/5

Simplifying further:

x ≥ -13/5

So, the solution to the solving linear inequality is x ≥ -13/5.

In terms of the result of solving linear inequalities, x represents any real number greater than or equal to -13/5.

Learn more about solving linear inequalities here:

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