the astronaut's weight in orbit will be 1/16th of her weight on the planet's surface.
(a) Yes, the astronaut will be weightless when she reaches the station and floats inside it. This is because the space station is in freefall around the planet, and the astronaut will be in the same state of freefall as the station.
(b) The ratio of the astronaut's weight in orbit to her weight on the planet's surface can be found using the equation:
w_orbit/w_surface = [tex](R_surface / R_orbit)^2[/tex]
where w_surface is the astronaut's weight on the planet's surface, w_orbit is her weight in orbit, R_surface is the planet's radius, and R_orbit is the radius of the station's orbit.
Substituting R_orbit = 4R_surface and simplifying, we get:
w_orbit/w_surface = (1/16)
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Find the position of the center of mass of the system of the sun and Jupiter. (Since Jupiter is more massive than the rest of the planets combined, this is essentially the position of the center of mass of the solar system.)
it's only beyond the surface of the sun! There is a barycenter throughout our entire solar system. All of the planets in the solar system, including the sun, center of mass.
Is the Sun more massive than the solar system as a whole?The sun is significantly more massive than Earth and has a radius that is likewise much greater. The mass of the sun is more than 333,000 times more than the mass of the Earth and makes up nearly all of the solar system's mass (99.8%).
How much more does the Sun compare to Jupiter?The Sun is 1000 times more than Jupiter, the solar system's most planet , but Jupiter is still 1000 times less than it.
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A green ball and a blue ball have a mass of 10 kg each one. The green ball, traveling at 10 m/s, strikes the blue ball, which is at rest. Assuming that the balls slide on a frictionless surface and all collisions are head-on, find the final speed of the blue ball in each of the following situations:
a. The green ball stops moving after it strikes the blue ball
b. The green ball continues moving after the collision at 4 m/s in the same direction.
(a) The final velocity of the blue ball is 5 m/s after the collision
(b) The final velocity of the blue ball is 6 m/s after the collision.
What is the final velocity of the balls?To solve this problem, we can use the conservation of momentum and the conservation of kinetic energy. The total momentum and total kinetic energy of the system before and after the collision must be the same.
a. When the green ball stops moving after the collision, its final velocity is 0 m/s. Let's call the final velocity of the blue ball v. The conservation of momentum equation is:
m_green x v_green + m_blue x v_blue = (m_green + m_blue)v
Substituting the values, we get:
10 kg x 10 m/s + 10 kg x 0 m/s = 20 kg x v
Simplifying, we get:
v = 5 m/s
b. When the green ball continues moving after the collision at 4 m/s in the same direction, its final velocity is 4 m/s. Let's call the final velocity of the blue ball v.
The conservation of momentum equation is the same as before:
m_green x v_green + m_blue x v_blue = (m_green + m_blue)v
Substituting the values, we get:
10 kg x 10 m/s + 10 kg x 0 m/s = 10 kg x 4 m/s + 10 kg x v
Simplifying, we get:
v = 6 m/s
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Consider a converging lens with focal length 9.56 cm. The distance between an object and
a real image of the object created by the lens is 59.6 cm. Find the distance between the
object and the lens if the lens is closer to the object than it is to the image. Answer in cm
The object's distance from the lens is 11.4 cm.
Calculation-The thin lens equation can be used to determine how a converging lens's object distance (p), image distance (q), and focal length (f) relate to one another:
1/p + 1/q = 1/f
where p denotes the distance to the object, q is the distance to the picture, and f is the focal length.
Let's solve for the object distance using the thin lens equation:
1/p + 1/59.6 = 1/9.56
Combining both sides with p59.69.56 results in:
59.69.56 + p9.56 = p*59.6
Adding and subtracting:
570.176 + 9.56p = 59.6p
50.04p = 570.176
p = 11.4 cm
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A horizontal force of 25 N is exerted on a box (mass 10 kg), as shown in the diagram. The box accelerates at 2.0 m.s-2. What is the magnitude of the frictional force acting between the box and the floor?
Answer:
the magnitude of the frictional force acting between the box and the floor is 5 N.
Explanation:
If astronomers were to find they have made a mistake and our solar system is actually 7.2 (rather than 8.2) kpc from the center of the galaxy, but the orbital velocity of the sun is still 240 km/s, what is the minimum mass of the galaxy?
Assuming a circular orbit for the Sun, we can use the equation:
v^2 = GM/r
where v is the orbital velocity of the Sun, r is the distance from the center of the galaxy, G is the gravitational constant, and M is the mass of the galaxy.
We can solve for M:
M = v^2 * r / G
Using the given values of v = 240 km/s and r = 7.2 kpc = 7.2 * 3.086e+19 m, and G = 6.6743e-11 N m^2/kg^2, we get:
M = (240000 m/s)^2 * 7.2 * 3.086e+19 m / 6.6743e-11 N m^2/kg^2
M = 1.47e+42 kg
Therefore, the minimum mass of the galaxy, if the distance of the solar system from the center is actually 7.2 kpc, is approximately 1.47 x 10^42 kg.
4. An ice skater is spinning on the ice at 4.00 rev/s. If the skater’s nose is 0.120 m from the axis of rotation, what is the centripetal acceleration of his nose?
Answer:
a = 3.02 m/s^2
h
Explanation:
we know that centripetal acceleration (a) is
[tex] \frac{v {}^{2} }{r} = a[/tex]
since v = rω, we can substitute it into the equation, which now gives us the centripetal acceleration in terms of angular velocity and radius (check image).
now we use the values given and find the answer
6. Construct a new physical equations having in terms of G, C and h dimensions of length where G is universal gravitational constant, c is the speed of light and I is planck's Constant.
Basic values of mass in the existing program are c1/2 G-12 h1/2 if the speed of light (c), newtonian constant (G), and Planck's parameter (h) are taken as the fundamental units.
What is the G equivalent of the principle of the universal gravitational equation?According to the Universal Gravitation Equation, G is equal to 6.673 x 10-11 N m2/kg2. Everything because of how a fruit falls from a tree to the reason the moon rotates around the earth may be explained by the Universal Gravitational Law.
What does the formula for the universal law of gravity mean?This rule states that the distance is proportional to the product of the mass of the two objects. The Universal Law of Force of gravity is summed up by the following gravitational force equation: FG = (G.m1.
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I need help with this ty
Answer:
4 & 2
Explanation:
If you plug in experimental values into the formula for kinetic energy, you will see the relationship.
1.
[tex]\frac{1}{2}(2 kg)(2 m/s)^{2} = 4 kg * m^{2} /s^{2} \\\\\frac{1}{2}(8 kg)(2m/s)^{2} = 16 kg * m^{2} /s^{2}\\\\\frac{16}{4} = 4[/tex]
2.
[tex]\frac{1}{2}(6 kg)(2m/s)^{2} = 12 kg * m^{2} /s^{2} \\\\\frac{1}{2}(3 kg)(2 m/s)^{2} = 6 kg * m^{2}/s^{2}\\ \\\frac{12}{6} = 2[/tex]
A car slows down from -27.7m/s to -10.9m/s while undergoing a displacement of -105. What was the acceleration? (Unit=m/s^2)
The acceleration of the car was 6.88 [tex]m/s^2[/tex]. The negative sign indicates that the car was decelerating, or slowing down.
To find the acceleration of the car, we can use the following formula:
acceleration = (final velocity - initial velocity) / time
However, we are not given the time it took for the car to undergo the displacement. To find the time, we can use the following formula:
displacement = (final velocity + initial velocity) / 2 * time
Solving for time, we get:
time = displacement / ((final velocity + initial velocity) / 2)
Plugging in the given values, we get:
time = [tex]-105 / ((-10.9 - 27.7) / 2) = 2.29 s[/tex]
Now that we have the time, we can use the first formula to find the acceleration:
acceleration = [tex](-10.9 - (-27.7)) / 2.29 = 6.88 m/s^2[/tex]
Therefore, the acceleration of the car was [tex]6.88 m/s^2[/tex]. The negative sign indicates that the car was decelerating, or slowing down.
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QUICK ANSWER Rainbows are caused by the refraction of visible wavelengths of light. TRUE OR FALSE
Answer:
true it is refraction of visible
A metal weigh 20N in air, 12N in water, and 14N in Kerosene. Cal the the Relative density of (a) Metal (b) kerosene
The relative density of kerosene is 0.006, or 6 kg/m³.
A metal block that weighs 60 tonnes in the air and 40 tonnes beneath water, what is its density?1 Response. Employ the Archimedes' Principle to your advantage: the buoyant force of a fluid is equal to the apparent loss of weight in water and is also equal to the weight of the displaced fluid. Weight of the displaced water equals 60 - 40 N, or the apparent loss in weight of the metal block. Water displacement mass is calculated as 20 / 9.8 = 2.04 kg.
Buoyant force = Weight of the displaced water = 20 N - 12 N = 8 N
Volume of water displaced = Buoyant force / Density of water = 8 N / 9.8 m/s² = 0.8163 kg
Density of metal = Weight of metal in air / Volume of metal = 20 N / (density of air x volume of metal)
Density of metal = 20 N / 0.8163 kg = 24.5 kg/m³
Buoyant force = Weight of the displaced kerosene = 20 N - 14 N = 6 N
Volume of kerosene displaced = Buoyant force / Density of kerosene = 6 N / 9.8 m/s² = 0.6122 kg
Density of kerosene = Mass of kerosene / Volume of kerosene displaced = 14 N / 0.6122 kg = 22.86 kg/m³
Relative density of kerosene = Density of kerosene / Density of water = 22.86 kg/m³ / 1000 kg/m³ = 0.006, or 6 kg/m³.
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What is the charge of an electric field 0.40 m away from a
source charge of 3.00 x 10-5C?
The electric field 0.40 m away from a source charge of 3.00 x 10^-5 C is 1.69 x 10^6 N/C, directed away from the source charge.
How to find the chargeThe electric field created by a point charge at a distance r from the charge is given by the equation:
E = kQ/r^2
where
E is the electric field in N/C,
k is Coulomb's constant (9.0 x 10^9 N m^2/C^2),
Q is the source charge in Coulombs, and
r is the distance from the source charge in meters.
Substituting the given values into the equation, we get:
E = (9.0 x 10^9 ) x (3.0 x 10^-5) / (0.40)^2
E = 1.69 x 10^6 N/C
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Remember the steps that the American Heart Association recommends for saying no to cigarettes. Which one of these will you use if you are faced with peer pressure to smoke? Which one of these will you use if you are faced with peer pressure to drink or take drugs? Explain the method you will use and why you chose it.
Answer: just say no and never talk to that person again.
Explanation:
because that is what i would do to prevent drugs and/or nicotine to enter my body.
Cathode ray tubes (CRTs) used in old-style televisions have been replaced by modern LCD and LED screens. Part of the CRT included a set of accelerating plates separated by a distance of about 1.70 cm. If the potential difference across the plates was 24.5 kV, find the magnitude of the electric field (in V/m) in the region between the plates.
the magnitude of the electric field in the region between the plates is 1.44 × [tex]10^6[/tex]V/m.
The electric field between the plates of the CRT can be calculated using the formula:
E = V/d
where E is the electric field, V is the potential difference across the plates, and d is the distance between the plates.
Substituting the given values, we get:
E = 24.5 kV / 0.017 m
Converting kV to V and simplifying, we get:
E = 24.5 × [tex]10^3[/tex]V / 0.017 m
E = 1.44 × [tex]10^6[/tex] V/m
An electric field is a force field created by a charged object or collection of charged objects that exerts a force on other charged objects within its vicinity. The electric field is a vector quantity and is measured in units of volts per meter (V/m).
The electric field at a point in space is defined as the force per unit charge acting on a positive test charge placed at that point. The direction of the electric field is given by the direction of the force that would be experienced by a positive test charge placed at that point.
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A student decides to devise a new temperature scale with the freezing and boiling points at 0° X and
70° X. What Celsius temperature would correspond to a temperature of 35° X?
O 50
O 35
O 90
O 70
Answer:
To convert temperature from the new scale (X) to Celsius, we simply subtract 0 from the value in X and then multiply the resulting number by a factor of 100/70. This gives us the Celsius temperature.
For 35° X, we can use the formula as follows:
C = (35 - 0) * (100/70)
C = 35 * 1.4286
C = 50°C
Therefore, the correct answer is option A, which is 50.
A 10,000 kg freight car is rolling along a track at 3.00m.s.Calculate the time needed for a force of 1000N for stop the car
It takes 0.3 seconds for a force of 1000 N to halt a 10,000 kg goods car moving at 3.00 m/s along a track.
Calculate the time needed for a force of 1000N for stop the carWe must first establish the car's starting kinetic energy in order to calculate the time required to stop the vehicle:
Kinetic Energy (KE) is equal to half of mass times speed, or 10,000 kg times 3.00 m/s.
KE = 45,000 J
Then, we may use the designed with the intent, which asserts that an object's change in kinetic energy equals the jobs performed by an external force: Work equals Force x Distance x Change in KE.
The gain in kinetic energy is equal to the starting kinetic energy because the car is coming to a stop: KE Change = -45,000 J
As a result, the external force's work is: Work equals force times distance, or -45,000 J.
When we solve for distance, we obtain: Work / Force = -45,000 J / 1000 N Distance
Location = -45 m
Because the force is against the direction of the car's motion, you'll see that the range is negative.
Finally, we can calculate the travel time using the kine model for uniformly accelerated motion: Distance is equal to 1/2*acceleration*time2. Time is calculated as sqrt(2 * Distance / Acceleration) as well as sqrt(2 * 45 m / (1000 N / 10,000 kg)).
time equals sqrt(0.09 s2/kg).
time = 0.3 s
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QUICK ANSWER Fiber optic cables utilize internal reflection to transmit signals. TRUE OR FALSE
PLS MRK ME BRAINLIEST
Answer:
True
Explanation:
optical fibre consists of core and cladding. The signal is converted to light using transducers. The light travels across the cable undergoing multiple internal reflections. At the other end the light is converted back to Signal using transducers.
Answer: True
Explanation: Optical fiber uses the optical principle of "total internal reflection" to capture the light transmitted in an optical fiber and confine the light to the core of the fiber.
If I get this wrong im sorry
In an electric circuit, what is one material that the connector can be made of?
31. IP Point charges +4.1 µC and -2.2 μC are placed on the x axis at (11 m, 0) and (-11 m, 0), respectively. (a) Sketch the electric potential on the x axis for this system. (b) Your sketch should show one point on the x axis between the two charges where the potential vanishes. Is this point closer to the +4.1-C charge or closer to the -2.2-µC charge? Explain. (c) Find the point referred to in part (b).
Explanation:
let at a distance x from the c
Need help with this
Explanation:
See image for definitions....look at the units and fill the blanks appropriatly
a person that just start driving a car is called
Answer:
A person who drives a car for themselves, generally taking themselves back and forth to work or errands, is generally referred to as a driver.
A machine has a velocity ratio of 5. ut requires a 50kg weight to overcome 20kg weight. calculate the efficiency of the machine ( take g= 10m/s^2)
Answer:
The answer is 8%
Explanation:
We know that the efficiency of the machine is given by,
E=(M.A)*100
=([tex]\frac{20}{50}[/tex])*[tex]\frac{1}{5}[/tex]*100
=8%
From time to time, people claim to have invented a machine that will run forever without energy input and develop more energy than it uses (perpetual motion). What is wrong with this claim?
Explanation:
It ignores some basic laws of physics:
You cannot get more work out of a machine than goes in
You cannot ignore friction
MS-PS2-1, MS-PS2-2: Newton...
16
Distance (m)
Distance vs. Time
B
120
Time (sec.)
A
B
Which car is faster, A or B? Choose the statement that BEST fits the graph.
Car A is faster than B because A's speed is 120 m/s.
Car B is faster than A because B's speed is 90 m/s.
Car A is faster than B because A's speed is 20 m/s and B is 15 m/s.
D) Car B is faster than A because B's motion is accelerating and A is constant speed.
The statement that best fits the graph is: D) Car B is faster than A because B's motion is accelerating and A is constant speed.
Which car is faster, A or B?From the graph, we can see that the distance traveled by both cars increases over time. However, the slope of the distance-time graph for car B is steeper than that of car A. This means that car B covers more distance in the same amount of time as car A, indicating that car B is traveling faster than car A.
Furthermore, we can see that the speed-time graph for car B is a straight line with a positive slope, indicating that its speed is increasing over time. On the other hand, the speed-time graph for car A is a horizontal line, indicating that its speed is constant.
Therefore, we can conclude that car B is faster than car A because car B's motion is accelerating, while car A is moving at a constant speed.
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The lightweight wheel on a road bike has a moment of inertia of 0.097 kg⋅m2
. A mechanic, checking the alignment of the wheel, gives it a quick spin; it completes 5 rotations in 2.2 s. To bring the wheel to rest, the mechanic gently applies the disk brakes, which squeeze pads against a metal disk connected to the wheel. The pads touch the disk 7.1 cm from the axle, and the wheel slows down and stops in 1.2 s.
What is the magnitude of the friction force on the disk?
the magnitude of the friction force on the disk is approximately 1.16 N.
We can use the conservation of energy to find the friction force on the disk. The initial kinetic energy of the wheel is equal to the work done by the friction force on the disk:
K_i = W_friction
The initial kinetic energy of the wheel can be found from its moment of inertia and angular velocity:
K_i = (1/2) I [tex]ω^2[/tex]
where I is the moment of inertia, ω is the angular velocity, and the factor of 1/2 comes from the rotational kinetic energy formula.
The final kinetic energy of the wheel is zero, since it comes to a stop. The work done by the friction force can be found from the distance over which it acts:
W_friction = F_friction d
where F_friction is the friction force and d is the distance over which the pads act on the disk. We can find the distance from the angular displacement of the wheel:
θ = ω t
where θ is the angle through which the wheel rotates, t is the time for the wheel to come to a stop, and the factor of 1/2π converts from rotations to radians. The distance over which the pads act is then:
d = r θ = 0.071 m × (5/2π) ≈ 0.562 m
Now we can put everything together:
K_i = W_friction
(1/2) I [tex]ω^2[/tex] = F_friction d
We can solve for the friction force:
F_friction = (1/2) I [tex]ω^2[/tex] / d
Plugging in the given values:
F_friction = (1/2) ×[tex]0.097 kg⋅m^2[/tex] × [tex](5/2.2π rad/s)^2[/tex] / 0.562 m ≈ 1.16 N
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Q37. A major source of heat loss from a house in cold weather is through the windows. Calculate the rate of heat flow through a glass window 2.0m x 1.5m in area and 3.2mm thick, it the temperatures at the inner and outer surfaces are 15.00C and 14.0°C
The rate of heat flow through the window is approximately 84.38 W.
To calculate the rate of heat flow through a glass window
The rate of heat flow through the window can be calculated using the formula:
Q = (kA (T1 - T2))/d
Where
Q is the rate of heat flowk is the thermal conductivity of the glassA is the area of the windowT1 is the temperature at the inner surfaceT2 is the temperature at the outer surfaced is the thickness of the glassWe first need to convert the temperatures to Kelvin, since temperature differences must be in Kelvin in this formula:
T1 = 15.0°C + 273.15 = 288.15 K
T2 = 14.0°C + 273.15 = 287.15 K
The thermal conductivity of glass can vary depending on the type of glass, but a typical value is around k = 0.9 W/(m·K) for plate glass.
Substituting the given values into the formula, we get:
Q = (0.9 W/(m·K) x 2.0 m x 1.5 m x (288.15 K - 287.15 K))/0.0032 m
Simplifying this expression, we get:
Q ≈ 84.38 W
Therefore, the rate of heat flow through the window is approximately 84.38 W.
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At the point 0, there are 2 point sources, emitting the same constant sound power,
with intensity in inversely proportional to the square of the distance from the source. At the point A, the sound level intensity is [tex]20dB[/tex]
(a) What is the sound level intensity at A of one source?
(b) What is the number of sources that we have to add at A so that the sound level intensity at the midpoint M of OA is [tex]30dB[/tex]?
The number of sources that we have to add at A so that the sound level intensity at M is doubled is 2.
(a) Let the distance of point A from one source be x. Then the distance from the other source is (OA - x), where OA is the distance between the two sources. The sound intensity at point A due to one source is proportional to 1/x^2. So, if the sound power of one source is P, then the sound intensity at A due to one source is given by I = P/(4πx^2), where 4πx^2 is the surface area of a sphere with radius x.
The sound level intensity is defined as L = 10log(I/I0), where I0 is a reference intensity (I0 = 10^-12 W/m^2). Since there are two sources, the total sound intensity at A is twice the sound intensity due to one source, i.e., I_total = 2I = 2P/(4πx^2). Therefore, the sound level intensity at A is L = 10log(2P/(4πx^2I0)) = 10log(2P/(4πI0)) - 20log(x).
(b) Let the distance of point M from one source be y. Then the distance from the other source is (OM - y), where OM is the distance between O and M. The sound intensity at M due to one source is proportional to 1/y^2. So, if the sound power of one source is P, then the sound intensity at M due to one source is given by I = P/(4πy^2), where 4πy^2 is the surface area of a sphere with radius y.
The sound level intensity at M due to one source is L_M = 10log(I/I0) = 10log(P/(4πy^2I0)).
Since the sound intensity is inversely proportional to the square of the distance, the sound intensity at A due to one source is four times the sound intensity at M due to one source. Therefore, I_A = 4I = 4P/(4πy^2), and the sound level intensity at A due to one source is L_A = 10log(I_A/I0) = 10log(P/(πy^2I0)).
We want the total sound level intensity at M due to all sources to be L_M = L_A + 10log2, where 10log2 is the sound level intensity increase due to adding a second source. Therefore, we have:
10log(P/(4πy^2I0)) + 10log2 = 10log(P/(πy^2I0))
10log2 = 10log(4/π)
log2 = log(4/π)
2 = 4/π
π = 2
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The following conversion equivalents are given:
1 m 100 cm 1 in = 2.54 cm 1 ft = 12 in
A bin has a volume of 1.5 m3. The volume of the bin, in ft3, is closest to:
Answer:52.972ft^3
Explanation:
It is unit conversion based and for a volume of a bin from cubic meter to cubic foot as we know 1 meter =3.281 foot.
where volume=1.5m^3
multiply 1.5*(3.281)^3 ft^3
v=52.972 ft^3
WHAT IS QUANTUM PHYSICS
hi!
Answer:
Quantum physics is the study of matter and energy at the most fundamental level. It aims to uncover the properties and behaviors of the very building blocks of nature.
why would the acceleration not change when adding mass to an air cart?
Answer:
The acceleration of an air cart, which is an object moving on a cushion of air, would not change when adding mass to it because the force of air resistance acting on the cart is negligible compared to the force applied by the air source that propels it. Therefore, the total force acting on the cart remains almost constant, regardless of the cart's mass, and according to Newton's second law of motion, the cart's acceleration would remain the same. This assumes that the air source provides a constant force and that the added mass does not significantly affect the friction between the cart and the surface on which it is moving.