state 2 precautionary measures you would take to maintain the efficiency of an accumulator​

According to the given statement The ships average acceleration is 2790 km/hr².

A measure of how quickly motion's speed and direction change over time. When a point or object advances or decelerates, it is moving straight forward. Motion on a circle increases despite the same speed because the direction is always changing.

We know that from newton's equation,

v² + u² = 2as

S = ut + 0.5 at²

Where, v = final speed

           u = initial speed

           a = acceleration

           S = distance covered

            t = time taken

Given, u = 0

So the equations becomes:

v² = 2as

S = 0.5 at²

Using these equations we get:

v² = 2a(0.5)at²

v² = a²t²

v = at

v/t = a

Given,  v = 93 km/hr

          t = 2 min = 2/60 hr

Putting these values in above equation we get, a = 2790 km/hr²

So, the ships average acceleration is 2790 km/hr²

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Answer:

The answer is 39.3

Explanation:

Answer:

1 MA= load/effort

MA= 240/60

MA=4

2.VR=Distance moved by effort/ Distance moved by Load

VR=4/1

= 4

5. Efficiency= MA/VR

4/4*100/1

=100%

Answer:

Different values of Q will make different values of electric potential V (shown in the image). The electric potential arising from a point charge Q, at a distance r from the charge is observed to be where ε0 is the permittivity of vacuum. VE is known as the Coulomb potential .Explanation:

The distance from the -5.35 × 10⁻⁶ C charge where the electric potential is -500 V is approximately 0.0935 meters or 9.35 cm.

To determine the distance from a charge where the electric potential is -500 V, we can use the formula for electric potential due to a point charge:

V = k × (Q / r)

Where:

V is the electric potential (in volts),

k is the Coulomb's constant (approximately 8.99 × 10⁹ Nm²/C²),

Q is the charge (in coulombs), and

r is distance from the charge (in meters).

Rearranging the formula, we solve for the distance:

r = k × (Q / V)

Substituting the given values into the equation

k = 8.99 × 10⁹ Nm²/C²,

Q = -5.35 ×10⁻⁶ C, and

V = -500 V,

r = (8.99 × 10⁹ Nm²/C²) × (-5.35 × 10⁻⁶ C / -500 V)

Calculating this expression:

r ≈ 0.0935 meters or 9.35 cm

Therefore, the distance from the -5.35 × 10⁻⁶ C charge where the electric potential is -500 V is approximately 0.0935 meters or 9.35 cm.

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Machines and equipment use a variety of energy sources, including electrical, mechanical, hydraulic, pneumatic, chemical, thermal, and others.

Equipment and machinery that draw power from electrical, mechanical, hydraulic, pneumatic, chemical, thermal, or other sources may put workers at risk.

hazards to safety

biological threats

bodily dangers

hazards of ergonomics

chemistry risks

threats to organisations during work.

environment-related risks.

Potential energy, or stored energy in an object, poses a risk to employees if it is suddenly released.

Lockout is only one aspect of hazardous energy control. It includes measures like machine guarding, alternative guarding arrangements that stop exposure to hazardous energy, lockouts, and other ways to protect workers from coming into touch with such energy. Anything that could be harmful, hurt someone, or have negative health impacts on something or someone is said to be in a hazardous condition.

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When 13.7-N force is being applied to the block parallel to the surface it will remain at rest, and the force of friction will be about 13.7 N. Hence option B is correct.

The resistive force of friction (Fr), which pushes the items together, is divided by the normal or perpendicular force (N), which pushes them apart, to produce the coefficient of friction (fr), which is a numerical value. The following formula represents it: fr = Fr/N.

Force which prevents one solid object from rolling or slipping over another. Although frictional forces can be advantageous, such as the traction required to walk without slipping, they also provide a significant amount of resistance to motion.

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Answer:

The Answer is gonna be True

Explanation : A hydrogen bond is a weak type of force that forms a special type of dipole-dipole intermolecular attraction when a hydrogen atom is bonded directly to one of the most electronegative elements like nitrogen (N), oxygen (O) or fluorine (F). This causes the hydrogen to acquire a significant amount of positive charge.

Or

Hydrogen bond is an attractive force between a partially positive charged hydrogen and a partially negative charged atom (oxygen and nitrogen). This is a very weak bond and strength of hydrogen bond (5-10 Kcal per bond) is much less than the strength of covalent bond. Hydrogen bonds are usually showed as dotted lines between two atoms.

This is the Answer for your question :3

I hope you are having a great day ❤️❤️❤️❤️❤️

Answer: The attraction of opposite charges between hydrogen and oxygen does not form a weak bond because oxygen-hydrogen makes hydrogen bonding. Hydrogen bonding is a very attraction force

The velocity of the object is 7.74m/s

Though it may sound sophisticated, velocity is simply the rate at which an object's location changes with regard to a frame of reference and time. Since it is a vector quantity, the definition of velocity requires both magnitude (speed) and direction.

We are given that,

Acceleration = 12m/s²

Radius = r = 5.0m

Velocity = v = ?

The velocity of the object can be calculated by the formula ,

a = v²/r

v = √ar

v = √12m/s²× 5m

v = √60m²/s²

v= 7.74m/s

Thus , the velocity of the object would be 7.74m/s.

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Pythagorean Theorem to determine the gap between second base and home plate.

The Pythagorean theorem and the coordinates of the two locations are used in the distance formula to determine the distance between them. The formula below can be used to determine the length of AB if A and B make up the hypotenuse of a right triangle: Leg2 plus Leg2 equals Hypotenuse 2.

measured from the middle of the backstop to the apex of home plate. Place second base in centre by drawing a line from the backstop's centre point over the pitcher's mound, through the apex. The distance that needs to be measured is between the centre of second base and the top of home plate.

The square root of (a,c)2 + (b,d)2 is used to calculate the distance between the points (a,b) and (c,d). The distance between points (a, b, c) and (d, e, f) in three dimensions is equal to the square root of (a, d), (b, e), and (c, f).

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These are just personal definitions of the following. They aren't official ones that may come from your textbook, but they are still accurate.

a. Friction is a force that acts against forces in contact with an object.

b. Sliding Friction is a force that acts against the forces making an object slide (e.g. the y component of the object's weight force if it's on an incline)

c. Static Friction is a force that acts on an object that is still/not moving.

d. Rolling Friction is the force making an object roll.

e. Air resistance is a frictional force that acts to slow down a falling object.

f. Terminal velocity is the maximum an object can reach while in free fall due to air resistance.

g. Gravity is a mutual attractive force in between two objects.

h. Weight is the mass of an object multiplied by the gravitational force (usually 9.81 for objects on earth). Weight is a force acting against the normal force keeping objects from phasing through each other.

i. Centripetal force is a force that acts on an object that is turning. This force pulls the object to the outside of the turning track.

j. Momentum is defined by mv (mass times velocity). Momentum is not a force, it is the idea that the motion of an object can depend on its mass and velocity.

I would check official dictionaries, just to make sure these definitions align with your textbook's.

This ride increases this person's gravity potential energy by 9000 Joules.

The force of attraction between any two bodies is directly proportional to the product of their masses and is inversely proportional to the square of their distance, according to Newton's universal law of gravitation.

The definition of energy is "the ability to do work, which is the capability to apply a force causing the displacement of an object." Despite this vague description, energy simply refers to the power that propels motion.

Weight of the person, W = 6 x 102 N = 600 N

Avg. Speed of elevator, v = 3 m/s

Time of ride, t = 5 sec.

Therefore,

Mass of the person, m = W/g = 600/9.8 = 61.2244 kg

Height of the elevator after 5 sec, h = v x t = 3 x 5 = 15 m

Potential energy increase , PE = mgh = 61.2244 x 9.8 x 15

                                              PE = 9000 Joule

Therefore, 9000 Joule does this person's gravitational potential energy increase as a result of this ride.

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The minimum amplitude of the resultant pulse is 10 cm.

The amplitude of a pulse is the maximum height of the waveform measured from the baseline, also known as the peak-to-peak amplitude. In the case of two pulses, A and B, the minimum amplitude of the resultant pulse is determined by the vector sum of the individual amplitudes of the two pulses.

When two pulses are in phase, the resultant pulse amplitude is the sum of the individual amplitudes, which in this case is 20 cm + 10 cm = 30 cm.

However, if the two pulses are out of phase, the minimum amplitude of the resultant pulse is determined by the difference between the amplitudes of the two pulses. In this case, the minimum amplitude of the resultant pulse would be |20 cm - 10 cm| = 10 cm.

So, the minimum amplitude of the resultant pulse is 10 cm.

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A theory must meet certain requirements in order to be accepted as a physical law , 1. It must explain the available data 2. It need to offer hypotheses that can be verified by science.

A physical law outlines the broad relationships between and, when necessary, changes in the physical quantities that define the states of a physical system. Typically, this is described mathematically. These laws are also known as natural laws or are associated with them in the physical realm. A physical law applies with a very high probability when it falls within its scope of applicability. Physical experiments and observations that are specifically focused are used to test this validity range. The law is established if the outcomes match the predictions.

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The bicyclist will need to ride for a total time of 120 seconds in order to cover 480 meters of distance at a constant velocity of 4.0 meters per second.

In this scenario, we are provided with:

The distance of the ride is 480 meters.

The velocity is four meters per second

In order to calculate the time, we can use the following formula:

Time = Distance : Velocity

= 480 meters : 4.0 meters per second

= 120 seconds

Therefore, the amount of time a cyclist needs to travel would be 120 seconds.

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A. The period of vibration is the time it takes for one complete oscillation to occur. It is the reciprocal of the frequency. The period of vibration can be calculated using the formula:

Period = 1/Frequency

Given that the frequency of vibration is 5.0Hz, the period of vibration is:

Period = 1/5.0 s

Period = 0.2 s

B. If the cart's mass is doubled while the spring constant remains unchanged, the frequency of vibration will not change. This is because frequency is dependent on the spring constant and the mass of the cart and not on the amplitude of the oscillation.

C. If the spring constant doubles while the cart's mass remains the same, the frequency of vibration will also double. This is because frequency is directly proportional to the square root of the spring constant. Therefore, doubling the spring constant would lead to an increase in the frequency of vibration by a factor of square root of 2.

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Answer:

The wavelength of the wave is [tex]5.45\times 10^5\ m[/tex] and time period is 0.0018 s.

Explanation:

The given question is, "A wave whose frequency is equal to 550 Hz, propagates in the air. What is its wavelength and its period?"

Given that,

The frequency of a wave, f = 550 Hz

The time period of a wave,

[tex]T=\dfrac{1}{f}\\\\T=\dfrac{1}{550}\\\\T=0.0018\ s[/tex]

Wavelength,

[tex]\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{550}\\\\\lambda=5.45\times 10^5\ m[/tex]

So, wavelength of the wave is [tex]5.45\times 10^5\ m[/tex] and time period is 0.0018 s.

The temperature difference of  1 K on the Kelvin scale is equivalent to the temperature difference of (5/9)°F on the Fahrenheit scale.  Triple-point temperature of water is approximately 491 degrees Rankine.

The unit of scales on the Rankine scale is the same as those on the Fahrenheit scale. Hence, from the freezing point of water (0⁰C) to the boiling point of water(100⁰C) , Rankine scale is divided into 180 scales.

The absolute zero is zero degrees Rankine.  In Celsius scale, absolute zero is −273 °C.

A). A unit scale on the Kelvin scale is the same size as a unit scale in the Celsius scale. Hence,

ΔT 1 K = ΔT 1°C

The ratio of Celsius and Fahrenheit scale is 5/9, therefore:

K/F = C/F = 5/9

Hence,

ΔT 1 K = ΔT (5/9)°F

B) Triple-point temperature of water is approximately 0 °C. Since zero degrees Rankine is equivalent to  −273 °C, hence:

0 °C = 0 - (9/5)(-273) = 491 degrees Rankine.

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Answer:

that is not physics pls dont do that again

Explanation:

A hydraulic lift's master cylinder must be subjected to a force of 136N.

According to Archimedes' principle, an object that is totally or partially submerged in a fluid will feel upward buoyant force that is equivalent in strength toward the point of gravity here on displaced fluid.

The design principle for vessels and submarines uses Archimedes' principle. The Archimedes principle is the foundation of hydrometers.

According to Archimedes' principle:

F1 / A1 = F2 / A2

F2 = (A2 / A1) * F1

Also, the formula for the force is F = mg.

The formula for the area of the cylinder is A = , therefore we get

F2 = ( π [tex](r2)^{2}[/tex] / π [tex](r1)^{2}[/tex] ) * mg

Since the cylinders' diameter is 2 cm and 24 cm, r1 = 12 and r2 = 1.

Substituting the values to the derived equation, we get

F2 = ( π [tex](1)^{2}[/tex] / π [tex](12)^{2}[/tex] ) * 2000 * 9.8

2 = 136 N

Thus, the force exerted must be 136N.

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Answer:

Approximately [tex](-61)\; {\rm m\cdot s^{-2}}[/tex], assuming that [tex]g = 9.81\; {\rm m\cdot s^{-2}}[/tex].

Explanation:

Under the assumptions, the vehicle would be in a free fall. Acceleration would be constant: [tex]a = (-g) = (-9.81)\; {\rm m\cdot s^{-2}}[/tex].

Let [tex]u[/tex] denote the initial velocity of the vehicle. Let [tex]v[/tex] denote the velocity of the vehicle at the bottom of the drop. Let [tex]x[/tex] denote the displacement of the vehicle during the drop.

It is given that the initial velocity is [tex]u = 0\; {\rm m\cdot s^{-1}}[/tex]. During the drop, displacement would be [tex]x = (-190)\; {\rm m}[/tex] (negative since the vehicle is below where it started.) The value of final velocity [tex]v[/tex] needs to be found.

It is known that the vehicle is moving downwards at the end of the fall. Therefore, the value of [tex]v\![/tex] would be negative. Apply the SUVAT equation [tex]v^{2} - u^{2} = 2\, a\, x[/tex] to find [tex]v[/tex] from [tex]u[/tex], [tex]a[/tex], and [tex]x[/tex].

[tex]\begin{aligned}v^{2} &= u^{2} + 2\, a\, x\end{aligned}[/tex].

[tex]\begin{aligned}v &= -\sqrt{u^{2} + 2\, a\, x} \\ &= -\sqrt{(0\; {\rm m\cdot s^{-1}})^{2} + 2\, (-9.81\; {\rm m\cdot s^{-2}})\, (-190\; {\rm m})} \\ &\approx (-61)\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].

(Note that [tex]v[/tex] is negative.)

In other words, the velocity of the vehicle would be approximately [tex](-61)\; {\rm m\cdot s^{-1}}[/tex] at the end of the drop.

Both reels will rotate at the same pace at some time throughout the game. This usual angle of rotation is 0.763 rad/s.

Given data:

The total length of the videotape cassette is, L = 196 m.

The time interval for the play is, t=2h=2×3600=7200s

The outer radius of the tape is, r₀ = 48mm

The inner radius of the tape is, r[tex]_{i}[/tex] = 14mm

The rotating motion of the videotape is indicated by the value of the angular velocity, which is as follows:

[tex]\omega=\frac{v}{r}[/tex].............................................................................(1)

Here, v denotes the cassette's linear speed, while r denotes the cassette's effective radius.

r=[tex]\sqrt{ \frac{r_{o}^{2} + r_{i}^{2} }{2} }[/tex]

r= [tex]\sqrt{ \frac{48^{2} + 14^{2} }{2} }[/tex]

r=35.35 mm

r ≅ 0.03535 m

And the cassette's linear speed is specified as,

[tex]v=\frac{L}{t}[/tex]

[tex]v[/tex] = 196/7200

[tex]v[/tex] = 0.027 m/s

Substitute the values in equation (1) as

[tex]\omega[/tex] = 0.027/0.03535

[tex]\omega[/tex] = 0.763 rad/s

As a result, we can infer that at some point throughout the game, both reels will be spinning at the same speed of 0.763 rad/s.

The angle of rotation in mathematics is a measurement of how much, specifically by what angle, a figure is rotated about a fixed point, frequently the center of a circle. Since an anticlockwise revolution of 310 degrees is equivalent to a full turn of 360 degrees because 310 degrees plus 50 degrees equals 360 degrees, an anticlockwise rotation of 310 degrees is also referred to as a rotation of -50 degrees.

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The mass of the car that was at rest is 4800kg.

What is mass?

Measurement of inertia, a fundamental characteristic of all matter. The resistance a body of matter offers to a change in its speed or location as a result of the application of a force is what it is in essence.

What is momentum?

As a measure of an object's kinetic energy, momentum is easily defined. Simply put, momentum is the result of mass times velocity. full response Simply said, momentum is concerned with the quantity of motion. The conserved quantity is another definition for it.

m= 3600kg

Vi= 21.0m/s

Vf = 9.0m/s

conservation of momentum

mVi= (m+M) Vf

mass of rest car M = (Vi-Vf )m/Vf

M = (21.0 m/s - 9.0m/s)* 3600 kg/ 9.0m/s

M= 4800kg

Therefore, the mass of the car that was at rest is 4800kg.

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Answer:

What is c and v

Explanation:

Answer:

96.2

Explanation:

I got it right on Acellus

14 a, 14 b, 14 c, and 14 d are the Expressions that require renaming mixed numbers before we can subtract.

Actually, there are a few steps to convert normal fractions into a mixed fractions. The steps are as follows:

Solving one by one with the help of the given options:

1) 14a

[tex]5\frac{2}{5}-2\frac{1}{4} \\\\\frac{17}{5} -\frac{9}{4} \\\\\frac{68-45}{20}\\\\ \frac{23}{20} =1\frac{3}{20}[/tex]

2)14b

[tex]5-2\frac{7}{8} \\\\\frac{5}{1} -\frac{7}{8} \\\\\\\frac{40-23}{8}\\\\ \frac{17}{8} =2\frac{1}{8}[/tex]

3)14c

[tex]7\frac{2}{3} -6\frac{1}{8} \\\\\frac{23}{3} -\frac{49}{8} \\\\\frac{184-147}{8} \\\\\frac{37}{24} =1\frac{13}{24}[/tex]

4)14d

[tex]9\frac{1}{6} -5\frac{2}{3}\\\\ \frac{55}{6}-\frac{17}{3}\\\\ \frac{165-102}{18} \\\\\frac{63}{18}=3\frac{9}{18}[/tex]

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A low bandwidth will result in a high ping (delay) and, most likely, lag while you're playing. It will also affect how quickly data is delivered and then received.

Because of the temporal lag caused by high latency, gaming might be much less enjoyable. It is essential because low latency allows for more fluid gameplay. Typically, a latency (or ping) of 40–60 milliseconds (ms) or less is considered to be acceptable.

Your website resources will load more quickly if server latency is reduced, which will also improve the time it takes for visitors to load all of your pages.

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Answer:

Oceanic crust moves easly. Continental crust does not move

When two bodies at equal temperature are brought in contact with each other then no heat flows between them and they are said to be in thermal equilibrium.

When the engine temperature eventually reaches the same level as the ambient temperature, thermal equilibrium has taken place. After being placed on the table and waiting a short while, a cup of hot tea cools to the same temperature as its surroundings.

This is where thermal equilibrium occurs. the set temperature at which all of a solid's mass melts. When the solid turns into a liquid, both the solid and the liquid coexist in the thermal equilibrium.

The individual drove himself to his location. The engine temperature was excessively high during that time, but it eventually dropped to the air temperature outside. When the engine temperature eventually reaches air temperature, thermal equilibrium has occurred.

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A(1) and (2) only of the following bodies are at thermal equilibrium when being put into contact. i.e. (1) A glass of water of internal energy E at 20 °C (2) Alcohol with unknown internal energy at 20 °C .

As internal energy is measured in terms of the body temperature, when two bodies are in thermal equilibrium, their internal energies will also be equal.

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The rate of fuel consumption is 6.69 kg/hr.

Solution:

To determine the rate of fuel consumption, we need to calculate the amount of energy required by the engine and divide that by the thermal efficiency.

From the question:

W = 110 hp

η = 28%.

r = ?

First, we can convert the power output from horsepower to watts:

1hp = 746 W

power output = 110 hp x 746 W/hp

                       = 82016 W

Then, we can calculate the energy required by the engine by multiplying the power output by the time the engine is running:

Energy = Power x time

Without knowing the time the engine runs, we cannot calculate the energy required.

We can calculate the fuel consumption by using the heating value of the fuel and the thermal efficiency.

Fuel consumption =           ( Power )                    

                                    (heating value * thermal efficiency))

So in this case:

Fuel consumption =     (82016)

                               (44200*0.28)

                            = (82016)

                                 12276

Fuel consumption = 6.69 kg/hr

Hence, the rate of fuel consumption is 6.69 kg/hr.

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The genetic and chemical variety of plant populations is influenced by environmental factors such as soil nutrients, temperature, water availability, and light intensity.

Sometimes a gene's DNA sequence or degree of activity is altered by the environment. Both of these effects have the capacity to change the proteins that a gene generates, which then affects traits. Some harmful environmental factors can change the nucleotide sequence of a gene. UV rays, for example, can harm DNA strands.

Successful competitors have a higher chance of surviving. Individual creatures with specific qualities are more likely to survive under specific environmental conditions than those without these traits.

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