Select all expressions that are equivalent to

0.75x + 0.25(x + 12.4) + (x – 2.1).




a.
x + 3.1 + x + 2.1


b.
x + 3.1 + x – 2.1


c.
2x + 1


d.
x + 1

We can solve for the time when the stone will be 698 feet above the planet's surface by setting h = 698 and solving for t in the equation h = 500 + 110t - 5.5t²:

698 = 500 + 110t - 5.5t²

Rearranging, we get:

5.5t² - 110t + 198 = 0

Dividing both sides by 5.5, we get:

t² - 20t + 36 = 0

This is a quadratic equation that we can solve using the quadratic formula:

t = (-(-20) ± sqrt((-20)² - 4(1)(36))) / (2(1))

Simplifying, we get:

t = (20 ± sqrt(64)) / 2

t = 10 ± 4

So the possible values of t are t = 14 or t = 6. We can check which value is correct by plugging each value into the original equation and seeing if it gives a height of 698:

When t = 14:

h = 500 + 110(14) - 5.5(14)²

h = 500 + 1540 - 1078

h = 962

When t = 6:

h = 500 + 110(6) - 5.5(6)²

h = 500 + 660 - 198

h = 962

So both values of t give a height of 698. Therefore, the stone will be 698 feet above the planet's surface at t = 6 seconds or t = 14 seconds.

Answer:

x = -5

Y = -22/3

Step-by-step explanation:

Y= 2/3x - 4                     Y = -x + 1

We put -x + 1 in for y to solve for x

-x + 1 = 2/3x - 4

-5/3x + 1 = -4

-5/3x = -5

x = -5

Now put -5 in for x and solve for y

Y= 2/3(-5) - 4

Y = -10/3 - 4

Y = -22/3

So, there are only one solution x = -5 and y = -22/3

The candy distributor needs to use 30 kilograms of 10% fat-content chocolate and 70 kilograms of 50% fat-content chocolate to create 100 kilograms of a 14% fat-content chocolate.

To solve this problem, we can use the method of mixture problems, which involves setting up a system of equations. Let x be the number of kilograms of the 10% fat-content chocolate and y be the number of kilograms of the 50% fat-content chocolate.

We have two equations based on the fat content and the total weight of the mixture:

0.1x + 0.5y = 0.14(100) (equation for fat content)

x + y = 100 (equation for total weight)

We can solve this system of equations using substitution or elimination. Using substitution, we can solve for x in terms of y from the second equation and substitute it into the first equation:

x = 100 - y

0.1(100 - y) + 0.5y = 0.14(100)

10 - 0.1y + 0.5y = 14

0.4y = 4

y = 10

Then we can substitute y = 10 back into the equation for x and get:

x = 100 - y = 100 - 10 = 90

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The inequalities that can be used to determine the possible number of bass in the pond over time are:

[tex]P > =250e^{0.048t} , P < =275e^{0.048t}.[/tex]

Rachel has a large pond on her property. The pond contains many different kinds of fish including bass. She knows that the population of bass is increasing exponentially each year at a rate of 4.8%. She also knows that there are currently between 250 and 275 basses in the pond.

Inequalities

Given:

r=4.8/100=0.048

Initial amount:

Lower end=250

Upper end=275

Using this equation to determine the inequalities

A=p×e^rt

Where:

A=Amount

P=Population

r=Growth rate

t=Time

Let's plug in the formula

Inequalities:

[tex]P > =250e^{0.048t}P < =275e^{0.048t}[/tex]

Therefore the inequalities are : [tex]P > =250e^{0.048t} , P < =275e^{0.048t}.[/tex]

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Angle B is approximately 53.15 degrees using trigonometry.

We can use trigonometry to solve for angle B in the right triangle BCD. We know that angle CBC is 37 degrees, and BD is 64.

First, we can use the Pythagorean theorem to find the length of BC, which is the hypotenuse of the right triangle:

[tex]BC^{2}[/tex] = [tex]BD^{2}+CD^{2}[/tex]

[tex]BC^{2}[/tex] = 64² + [tex]CD^{2}[/tex]

Since CD is opposite angle B, we can use trigonometry to relate CD to angle B. Specifically, we can use the tangent function:

tan(B) = CD/BD

Rearranging, we have:

CD = BDxtan(B)

Taking the square root of both sides, we have:

BC = 64[tex]\sqrt{(1+tan^{2}B)}[/tex]

Now we can use the fact that BC is the hypotenuse of the right triangle to relate it to angle CBC, which is 37 degrees. Specifically, we can use the sine function:

sin(CBC) = BD/BC

Substituting our expression for BC, we have:

sin(37) = 64/64√(1 + tan²(B))

Simplifying, we get:

sin(37) = 1/[tex]\sqrt{(1+tan^{2}B)}[/tex]

Squaring both sides, we have:

sin²(37) = 1/[tex](1+tan^{2}B)}[/tex]

Substituting the identity cos²(θ) + sin²(θ) = 1, we have:

cos²(37) = cos²(B)

Taking the square root of both sides, we have:

cos(37) = ±cos(B)

Since angle B is acute (it is less than 90 degrees because it is in a right triangle), we know that cos(B) is positive. Therefore, we can take the positive square root:

cos(B) = cos(37)

B = 53.15 degrees (rounded to two decimal places)

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Answer:

Yes they can.

The only time they would have to be different lengths is if it was a square

The probability that a randomly selected newborn baby boy's weight is between 3682 and 4552 grams is approximately 0.1979, or 19.79% when rounded to four decimal places.

To find the probability that a newborn baby boy's weight  Convert the weights to z-scores:

z = (X - μ) / σ, where X is the weight, μ is the mean, and σ is the standard deviation.

First, calculate the standard deviation:

σ = √variance = √385,641 ≈ 621

Now, calculate the z-scores for the given weights:

z1 = (3682 - 3186) / 621 ≈ 0.7986

z2 = (4552 - 3186) / 621 ≈ 2.1965

Use a standard normal table or a calculator with a standard normal probability function to find the probabilities corresponding to these z-scores:

P(Z ≤ 0.7986) ≈ 0.7879

P(Z ≤ 2.1965) ≈ 0.9858

Find the probability that the weight is between the two z-scores:

P(0.7986 ≤ Z ≤ 2.1965) = P(Z ≤ 2.1965) - P(Z ≤ 0.7986) ≈ 0.9858 - 0.7879 ≈ 0.1979

So, the probability that a randomly selected newborn baby boy's weight is between 3682 and 4552 grams is approximately 0.1979, or 19.79% when rounded to four decimal places.

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For the first question, the measure of variability that should be used for both sets of data to determine the location with the most consistent temperature is IQR, because it is robust to outliers and can provide a better representation of the spread of data for skewed distributions. The option "IQR, because Desert Landing is symmetric" is incorrect because the graph of Desert Landing is not symmetric.

For the second question, we need to compare the measures of center (mean and median) of the two sets of data to determine which shop typically sells the most amount of coffee per hour. To do this, we can calculate the mean and median of each set of data:

For Coffee Ground, the mean is (1.5+20+3.5+12+2+5+11+7+2.5+9.5+3+5)/12 = 6.25 gallons and the median is the middle value of the ordered set, which is 5 gallons.

For Wide Awake, the mean is (2.5+10+4+18+4+3+6.5+15+6+5+2.5)/11 = 6.136 gallons and the median is the middle value of the ordered set, which is 4.5 gallons.

Therefore, we can conclude that Wide Awake typically sells the most amount of coffee per hour, with a median value of 4.5 gallons. The option "Wide Awake, with a mean value of about 4.5 gallons" is incorrect because the mean value of Wide Awake is slightly lower than 4.5 gallons. The option "Coffee Ground, with a median value of 5 gallons" is incorrect because the median value of Coffee Ground is lower than the median value of Wide Awake. The option "Coffee Ground, with a mean value of about 5 gallons" is incorrect because the mean value of Coffee Ground is higher than 5 gallons.

Therefore, the slope is 1/3 and the y-intercept is 0.

a. The equation is in slope-intercept form, y = mx + b, where m is the slope and b are the y-intercept. In this case, the slope is 4, and the y-intercept is 1. Therefore, the slope is 4 and the y-intercept is 1.

b. This equation is also in slope-intercept form, y = mx + b, where m is the slope and b are the y-intercept. In this case, the slope is 1, and the y-intercept is -2. Therefore, the slope is 1 and the y-intercept is -2.

c. This equation is already in slope-intercept form, y = mx + b, where m is the slope and b are the y-intercept. In this case, the slope is 1/3, and the y-intercept is 0 (since there is no constant term). Therefore, the slope is 1/3 and the y-intercept is 0.

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The required polynomial of exact degree 5 which interpolates the four given points is equals to  p(x) = x^3/2 -4x^2 + 63x/6 -6.

Polynomial of degree exactly 5 that interpolates the four points (1, 1), (2, 3), (3, 3), (4, 4).

Apply Lagrange interpolation.

Standard form of the Lagrange interpolation polynomial of degree n passing through n+1 distinct points (x0, y0), (x1, y1), ..., (xn, yn) is,

L(x) = Σ [yi × Π (x - xj) / (xi - xj)], for i = 0, 1, ..., n

where Π is the product operator and j takes all values different from i.

For the given four points, we have n = 3, so the polynomial has degree n+1 = 4.

Using the formula, we have,

L(x) = (1× (x - 2)(x - 3)(x - 4) / ((1 - 2)(1 - 3)(1 - 4)))

+ (3× (x - 1)(x - 3)(x - 4) / ((2 - 1)(2 - 3)(2 - 4)))

+ (3× (x - 1)(x - 2)(x - 4) / ((3 - 1)(3 - 2)(3 - 4)))

+ (4× (x - 1)(x - 2)(x - 3) / ((4 - 1)(4 - 2)(4 - 3)))

Simplifying this expression, we get,

⇒L(x) = (-x^3 + 9x^2 - 26x + 24)/6 + (3x^3/2 - 12x^2 + 57x/2 - 18) +(-3x^3/2 + 21x^2 /2- 21x + 12) + (2x^3/3 - 4x^2 + 22x/3 - 4)

⇒L(x) = x^3/2 -4x^2 + 63x/6 -6

Therefore, the polynomial of degree exactly 5 that interpolates the four points (1, 1), (2, 3), (3, 3), (4, 4) is  p(x) = x^3/2 -4x^2 + 63x/6 -6.

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A random sample of 38 cities was asked to report their voter turnout percentages, which can be used to estimate the average voter turnout in those cities. However, caution should be taken when making generalizations about the larger population of cities, since the sample size is relatively small.

The average voter turnout during an election can be calculated by taking the percentage of registered voters who actually voted in a sample of cities and finding the mean. In this case, a random sample of 38 cities was asked to report the percent of registered voters who voted in the most recent election. To calculate the average voter turnout, follow these steps:

1. Obtain the reported voter turnout percentages from each of the 38 cities in the random sample.
2. Add up all the percentages of voter turnout from the 38 cities.
3. Divide the sum of voter turnout percentages by the number of cities (38) to find the average voter turnout.

By following these steps, you will find the average voter turnout for the most recent election, based on the random sample of 38 cities. Keep in mind that the average voter turnout can vary depending on the election and location, as factors such as political climate, awareness, and accessibility can impact voter participation. This calculated average represents an estimation of the overall turnout and may not be completely representative of the entire population, but it provides a useful measure to understand voter engagement during elections.

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Answer: 13.51 (not in inches format)

Step-by-step explanation:

tan(x) = 4.384/12

x = tan^-1 (4.384/12)

x = 20.068°

tan(20.068) = y/(12+25)

tan(20.068) = y/37

20.068 = tan^-1 (y/37)

y = 13.51

Answer:

Step-by-step explanation:

To solve this with similar triangles - you need to set up a proportion.

I changed it all to inches.

12 ft = 144 in

4.384 ft = 51. 84 inches

12 + 25 (you need to add the base of the triangle) = 37 ft = 444 inches

set up smaller triangle in proportion to bigger triangle

51.84"/144" = x/444

cross mulitply then divide

51.84 times 444 = 23016.96

23016.96 ÷ 144 = 159.84 inches

Change back to feet by dividing by 12

159.84 ÷ 12 = 13.32 ft

Answer:

126 meters squared

Step-by-step explanation:

To find the surface area

For the top and bottom it will be: l x w x 2(because there's a top and bottom)

3x6x2 = 36

For the sides (left and right) it will be: l x h x 2 (There's left and right)

3x5x2 = 30

For the front and back it will be w x h  x 2 (There's the front and the back)

6x5x2 = 60

Added it all together and you get 126

The surface area is 126 meters squared



(a) Since M is the midpoint of DE, we have ME = (1/2)b.

Also, CXE is a straight line, so C, X, and E are collinear.

Therefore, we have CX + XE = CE, or a - b + FE = b + (2a - b), which simplifies to FE = a.

(b) n = a/b - 1.

X is the point on FM such that

FX:XM =n:1,

we have FX = nX and XM = X.

Since M is the midpoint of DE, we have ME = (1/2)b,

so that  DX = DE - EX = b - (n + 1)X.

Using the fact that CXE is a straight line,

we have CX + XE = CE, or a - b + FE = b + (2a - b),

which simplifies to FE = a.

Therefore, we have FX + FE = AX, or nX + a = a + b + (n + 1)X.

Simplifying, we get b = (n + 1)X - nX = X.

We know that  DX = b - (n + 1)X = 0, so X = b/(n + 1).

Therefore, we have n/(n + 1) = FX/X = (a-b)/b.

Calculating  for n, we have  n = a/b - 1.

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For given dilation of the figure, the distance from the center of dilation to point A' is approximately 1.414 units.

What exactly is dilation in mathematics?

In mathematics, dilation is a transformation that changes the size of a figure but not its shape. It is also known as scaling, enlargement, or reduction.

To perform a dilation, a figure is multiplied or divided by a scale factor, which is a positive number greater than zero. If the scale factor is greater than 1, the figure is enlarged, while if it is less than 1, the figure is reduced. If the scale factor is equal to 1, the figure remains the same size.

Now,

To find the distance from the center of dilation to point A', we need to use the fact that the distance between the center of dilation and any point on the preimage is multiplied by the scale factor to get the corresponding distance on the image.

First, let's find the distance from the center of dilation to point A:

distance from center to A = √((6-2)² + (-2-2)²) = √(4² + (-4)²) = √32 ≈ 5.657 units (rounded to three decimal places)

Next, we can use the fact that the scale factor is 1/4 to find the distance from the center of dilation to point A':

distance from center to A' = (scale factor) x (distance from center to A)

= (1/4) x 5.657

= 1.414 units (rounded to three decimal places)

Therefore, the distance from the center of dilation to point A' is approximately 1.414 units.

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The geometric sequence for the value of a₁= 3 r= 1/10 n=8 is [tex]a_{8} = \frac{3}{10000000}[/tex] i.e option c is correct.

What does the term "geometric sequence" mean?

A geometric sequence is a set of integers where the ratio between each pair of succeeding terms is fixed. The geometric sequence's general ratio is the name of this constant.

We can use the following algorithm to determine the nth term (an) of a geometric sequence:

[tex]a_{n} = a_{1} * r^{n-1}[/tex]

where a1 is the first term in the series, r represents the common ratio, and n denotes the term's number.

Since a1 = 3, r = 1/10, and n = 8, we get:

[tex]a_{8} = 3 * (\frac{1}{10})^{8-1} = 3 *( \frac{1}{10})^{7}[/tex]

[tex]= 3 * \frac{1}{10^{7} }[/tex]

Now, we can condense this equation to get the solution:

a₈ = [tex]\frac{3}{10000000}[/tex]

The solution is therefore [tex]\frac{3}{10000000}[/tex] that option c.

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The coordinate of the segment in the ratio is (-2,-2).

What is ratio?

When two numbers are compared, the ratio between them shows how often the first number contains the second. As an illustration, the ratio of oranges to lemons in a dish of fruit is 8:6 if there are 8 oranges and 6 lemons present.

Partitions the line segment in the ratio A to B... then,

=> x-coordinate is : x1 +[tex]\frac{ A(x2-x1)}{(A+B)}[/tex]

=> y-coordinate is: y1 + [tex]\frac{A(y2-y1)}{(A+B)}[/tex]

Here A = 2 , B = 1 and [tex](x_1,y_1)=(-10,10)[/tex] , [tex](x_2,y_2)=(2,-8)[/tex] .

x-coordinate = -10+[tex]\frac{2(2+10)}{(2+1)}[/tex] =  -10 + [tex]\frac{2(12)}{3}[/tex] = -10 + 2(4) = -10+8 = -2

y-coordinate = 10+[tex]\frac{2(-8-10)}{(2+1)}=10+\frac{2(-18)}{3}[/tex] = 10+2(-6) = 10-12 = -2.

Hence the coordinate of the segment in the ratio is (-2,-2).

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Answer:

1)  5

Step-by-step explanation:

Trapezoid Midsegment Theorem:

EF = (DC + AB) / 2

2x + 2 = ((x + 3) +(5x - 9)) / 2

4x + 4 = 6x - 6

-2x = -10

x = 5

Answer: We can find the total distance of the first route by adding the individual distances:

53 + 28 + 98 = 179 miles

Similarly, we can find the total distance of the second route:

28 + 49 + 85 = 162 miles

Therefore, the second route is shorter by (179 - 162) = 17 miles.

Step-by-step explanation:

To create identical donation bags, you will need 55 hats and 40 scarves. You produce the most donation bags without any extra apparel. Each donation package contains 11 hats and 8 scarves.

To make the greatest amount of donation bags with no clothing left over, we need to find the greatest common factor (GCF) of 40 and 55. We can do this by finding the prime factors of both numbers:

[tex]40 = 2 * 2 * 2 * 5[/tex]

55 = 5 x 11

The GCF is the product of the common prime factors, which is 5. This means we can make 5 identical donation bags.

To find out how many scarves and hats are in each donation bag, we can divide the total number of scarves and hats by the number of donation bags:

Number of scarves per bag = 40 / 5 = 8 scarves

Number of hats per bag = 55 / 5 = 11 hats

Therefore, each donation bag will contain 8 scarves and 11 hats.

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The correct angle measure in degrees for each exterior angle is 5.5. The other values provided in the question, 6.4, 173.6, and 9720, are not relevant to the problem.

What is Exterior angles ?

In a polygon, an exterior angle is an angle formed by a side and an extension of an adjacent side. The measure of an exterior angle of a regular polygon with n sides is given by 360/n degrees.

To find the measure of each exterior angle of a regular polygon, we use the formula:

Measure of each exterior angle = 360 degrees / number of sides

In this case, the polygon is a regular 66-gon, so the number of sides is 66. Thus,

Measure of each exterior angle = 360 degrees / 66 = 5.454545...

Rounding to the nearest tenth, we get:

Measure of each exterior angle ≈ 5.5 degrees

Therefore, the correct angle measure in degrees for each exterior angle is 5.5. The other values provided in the question, 6.4, 173.6, and 9720, are not relevant to the problem.

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The answer using probability are shown:

(A) 43/60 projection is used.

(B) He shouldn't alter the estimate in light of this knowledge.

Simply put, the probability is the likelihood that something will occur.

When we don't know how an occurrence will turn out, we can discuss the likelihood or likelihood of various outcomes.

Statistics is the study of occurrences that follow a probability distribution.

Mathematics' study of random events is known as probability, and there are four major kinds of probability: axiomatic, classical, empirical, and subjective.

So, he would calculate the amount by dividing the overall number of bricks by the proportion of green bricks. The likelihood of choosing a green block out of all 60 bricks would be that.

Then, the probability would be:

= 43/60

Andre shouldn't alter his assessment, in other words.

The explanation is that we do not know whether the bricks he saw were green in color; we are only told that she looked in the bag and found 6 bricks.

The only time Andre needs to adjust his guess is if it turns out that the six bricks Mai saw in the bag were, in fact, green.

The estimate should not be altered until this proof is received.

Therefore, the answer using probability are shown:

(A) 43/60 projection is used.

(B) He shouldn't alter the estimate in light of this knowledge.

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Complete question:
Andre picks a block out of a bag 60 times and notes that 43 of them were green. What should Andre estimate for the probability of picking out a green block from this bag? Mai looks in the bag and sees that there are 6 blocks in the bag. Should Andre change his estimate based on this information? If so, what should the new estimate be? If not, explain your reasoning.

Since AB is tangent to circle E at A, we know that angle CAB is a right angle (tangent is perpendicular to the radius at the point of tangency). Therefore, triangle ADC is a right triangle.

Let's use the Pythagorean theorem to find the length of CE:

CE^2 = AC^2 + AE^2 (using Pythagorean theorem in triangle ACE)

CE^2 = 9^2 + EA^2 (since AE = EA, by definition of radius)

CE^2 = 81 + EA^2

We still need to find EA. Let's use the fact that EA is half the length of CD:

EA = CD/2

Now we can substitute this expression into the previous equation:

CE^2 = 81 + (CD/2)^2

CE^2 = 81 + CD^2/4

Next, let's use the Pythagorean theorem in triangle ADC:

AD^2 + DC^2 = AC^2

4^2 + DC^2 = 9^2

DC^2 = 9^2 - 4^2

DC^2 = 65

Now we can substitute this expression into the previous equation:

CE^2 = 81 + 65/4

CE^2 = 99.25

Taking the square root of both sides, we get:

CE ≈ 9.96

Therefore, CD = 2CE ≈ 19.9.

Answer: CD ≈ 19.9

Percentage of students who were undecided is  59% of the students were undecided about their future careers.

what is Percentage?

A percentage is a fraction or ratio expressed as a fraction of 100. It is a way of expressing a part of a whole as a proportion of the whole. It is denoted by the symbol '%'. For example, if there are 100 students in a class and 20 of them are girls, then the percentage of girls in the class is 20%.

In the given question,

To solve the problem, we need to first find out the percentage of students who were undecided. We know that 25% of the students wanted to become doctors and 16% wanted to become teachers. The percentage of students who were undecided can be found by subtracting the sum of the percentages of those who wanted to become doctors and teachers from 100%:

Percentage of students who were undecided = 100% - (25% + 16%) = 59%

Therefore, 59% of the students were undecided about their future careers.

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The conditional probability that the coin chosen is fake given that it was flipped three times and all three flips resulted in heads is higher than the initial probability.

Let A be the event that the coin chosen is fake, and B be the event that the three flips resulted in heads. We are given that the probability of choosing the fake coin is 0.1, i.e. P(A) = 0.1, and the probability of getting heads with the fake coin is 1, i.e. P(B|A) = 1. The probability of getting heads with the fair coin is 0.5, i.e. P(B|A') = 0.5, where A' is the event that the coin chosen is fair. Using Bayes' theorem, we can calculate the conditional probability of A given B:

P(A|B) = P(B|A) * P(A) / (P(B|A) * P(A) + P(B|A') * P(A'))

Plugging in the given values, we get:

P(A|B) = 1 * 0.1 / (1 * 0.1 + 0.5 * 0.9) = 0.18

Therefore, the conditional probability that the coin chosen is fake given that it was flipped three times and all three flips resulted in heads is 0.18, which is higher than the initial probability of 0.1. This means that the evidence of three consecutive heads increases the likelihood that the coin is fake.

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"Triangle CFE is congruent to triangle PTR" is true.

If Triangle CFE is congruent to triangle PTR, we can make the following statements:
The corresponding sides of the triangles are congruent:

This means that CF = PT, FE = TR, and CE = PR.
The corresponding angles of the triangles are congruent:

This means that angle CFE is congruent to angle PTR, angle FCE is congruent to angle PRT, and angle ECF is congruent to angle TPR.
The triangles are equal in area: Since the triangles are congruent, they have the same shape and size. Therefore, they will have the same area.
The triangles can be superimposed on each other: This means that we can place triangle CFE on top of triangle PTR in such a way that their corresponding sides and angles overlap.
If we know the measurements of the sides and angles of one triangle, we can find the measurements of the sides and angles of the other triangle: Since the triangles are congruent, we know that their corresponding sides and angles are equal.

Therefore, if we know the measurements of the sides and angles of one triangle, we can find the measurements of the sides and angles of the other triangle by using the congruence criteria.
In conclusion, if Triangle CFE is congruent to triangle PTR, we can make several statements about their corresponding sides and angles, their areas, and their ability to be superimposed on each other.

We can also use the congruence criteria to find the measurements of the sides and angles of one triangle if we know the measurements of the sides and angles of the other triangle.

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Answer: 19 3/5 x 20 2/5 = 9996/25 = 399 21/25

Answer:

  use SSS

Step-by-step explanation:

Given two congruent chords AB and BC in circle O, you want to prove ∆AOB is congruent to ∆COB.

1. circle O, AB≅BC . . . . given

2. OB ≅ OB . . . . reflexive property of congruence

3. OA ≅ OC . . . . definition of a circle

4. ∆AOB ≅ ∆COB . . . . SSS postulate

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Additional comment

Your erased statement 2 shows you know exactly how to do this.

All the radii of a circle are the same length, so it is easy to show congruence by SSS, given that AB≅BC.