Say that Australia has a working population of 11,565,470 people, and that the average salary is $26.450
annually. How much tax revenue would Australia generate each year by instituting a 31.4% income tax?
a $81,528,467,671
b. $90,224,333,274
c$96.054,697.991
d $209,851,983,509

Answer:

Step-by-step explanation:

Remark

Make a very crude diagram of what these points look like. You will find that

That gives you a hint about how to find the Length and width.

Givens

From (-8,-3) and (-3, 3) L = -8 - -3 = - 5

From (-8,6) and  (-8,3) w = 6 - 3 = 3

Solution

The length cannot be minus 5. The way to get around that is to call it and absolute value of (-5) which is 5

So the area = L*W

area = 5 *3

area = 15

Answer

Area = 15

Answer:

c)20 1/4

Step-by-step explanation:

[tex]9x^{2}y^{-2}[/tex]

If We replace x by -3 and y by 2 we get  :

[tex]9\left( -3\right)^{2} \left( 2\right)^{-2}[/tex]

Or we have :

[tex]\left( -3\right)^{2} =9\ \text{and} \ \left( 2\right)^{-2} =\frac{1}{2^{2}} =\frac{1}{4}[/tex]

then

[tex]9\left( -3\right)^{2} \left( 2\right)^{-2}=9\times9\times\frac{1}{4} = \frac{81}{4}[/tex]

on the other hand :

[tex]\frac{81}{4} =\frac{80+1}{4} =\frac{80}{4} +\frac{1}{4} =20+\frac{1}{4}=20\frac{1}{4}[/tex]

Answer:

D

Step-by-step explanation:

to find the value in grams, we just multiply by a 1000

so, 31.8 × 1000 = 31,800 grams

Answer:

it's 460 I think, because the last number is a five so if it's over a five you round up

Answer:

To round 376.77 to the nearest dollar consider the tenths’ value of 376.77, which is 7 and equal or more than 5. Therefore, we have to round the amount up: the dollar part of 376.77, 376, increases by 1 to 377, and the decimal point and all digits (.77) are removed.

Step-by-step explanation:

[tex]( 7 . 3^{6} ) ^{4}[/tex]Answer:

= [tex](7^{-3--2}[/tex] x [tex]3^{-8--2} ) ^{-4}[/tex]

= [tex](7^{-1}[/tex] x [tex]3^{-6}) ^{-4}[/tex]

= [tex]( 7^{1}[/tex] x [tex]3^{6}) ^{4}[/tex]

= [tex]7^{4}[/tex] x [tex]3^{24}[/tex]

OR

= [tex](\frac{3^{-8} }{7 . 3^{-2} }) ^{-4}[/tex]

= [tex](\frac{1}{7 . 3^{6} } ) ^{-4}[/tex]

= [tex]( 7 . 3^{6} ) ^{4}[/tex]

= [tex]7^{4}[/tex] x [tex]3^{24}[/tex]

Step-by-step explanation:

Answer:

11/14-2/10=41/70=0.58

Answer:

3. -1/3  ± 2i√5 / 3

Step-by-step explanation:

3x^2 + 2x = -7

Divide through by 3:

x^2 + 2/3 x = -7/3

Completing the square:

x^2 + 2/3 x + (1/3)^2 = -7/3 + (1/3)^2

(x + 1/3)^2 = -7/3 + 1/9

(x + 1/3)^2 = -20/9

x + 1/3 =  ±√(-20) / 3

x + 1/3 = ± 2√-5/3

x  = -1/3  ± 2i√5 / 3

Answer:

x = 4  or x = -3

-1

Step-by-step explanation:

26.

x² = x + 12

x² - x - 12 = 0

(x - 4)(x + 3) = 0

x - 4 = 0  or  x + 3 = 0

x = 4  or x = -3

27.

(-6 + 4)/2 = -2/2 = -1

Answer:

  see attached

Step-by-step explanation:

The vector difference u -v can be represented on a vector diagram by the sum u +(-v), where -v is a vector the same length as v, but in the opposite direction.

__

This sum is shown in the attachment.

The house will cost approximately $246,359.85 seven years from now.

It is the interest we earned on the interest.

The formula for the amount earned with compound interest after n years is given as:

A = P [tex](1 + r/n)^{nt}[/tex]

P = principal

R = rate

t = time in years

n = number of times compounded in a year.

We have,

In this problem,

P = $140,000

r = 0.07

n = 1 (compounded annually)

t = 7.

Plugging in these values.

A = $140,000 (1 + 0.07/1)^(1 x 7)

A = $140,000 (1.07)^7

A = $246,359.85

Therefore,

The house will cost approximately $246,359.85 seven years from now.

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Answer:

Each pencil costs 50 cents

Step-by-step explanation:

Step 1:  Determine the price per unit

(Price of Items) / (Amount of items)

($3) / (6)

$0.5

Answer:  Each pencil costs 50 cents

Answer:

1 trapezoid

2 triangle

3 rectangle

Answer:

-6x-10

Step-by-step explanation:

you multiply 3x by -2

and 5 by -2

never forget the negative

Answer:

14.9 %

Step-by-step explanation:

2  = double

2 = ( 1+ i)^5       i  = interest in decimal   5 = years

i = .149   = 14.9 %  

Answer:

The answer is 12

Step-by-step explanation:

Answer: 12

Step-by-step explanation:

Option B will be the best option.

Answer:

x = -3/2

Step-by-step explanation:

note: 1/125 can be written as 5 exponent -3 thus, 5^-3

Expressing it in this form, we can rewrite the above equation as

5^2x = 5^-3

As part of the laws of indices and logarithms, when the bases are the same and they are equating, You equate only the exponents

therefore, we have;

2x = -3

divide through by 2

x = -3/2

The line of best fit is an illustration of a linear regression

Using the assumed parameters, the value of x when x = 24 is 30.75

The equation of the line of best fit is not given, and the parameters to calculate the line of best fit are missing.

So, I will assume the following parameter values.

Assume that the line of best fit passes through the points

(x,y) = (1,2) and (5,7)

The slope of the line would be:

m = (7 - 2)/(5- 1)

m = 1.25

The equation is then calculated as:

y =m(x - x1) + y1

This gives

y = 1.25(x - 1) + 2

Expand

y = 1.25x - 1.25 + 2

Evaluate

y = 1.25x + 0.75

When x = 24, we have:

y = 1.25 * 24 + 0.75

Evaluate

y = 30.75

Using the assumed values, the value of x when x = 24 is 30.75

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The value in the part (c) is 1/(b-a) if the graph of any continuous function y = f(x) for a ≤ x ≤ b is rotated about the horizontal line y = L, the volume obtained depends on L.

It is defined as the mathematical calculation by which we can sum up all the smaller parts into a unit.

We have a graph of any continuous function y = f(x) for a ≤ x ≤ b is rotated about the horizontal line y = L.

For part(c)

[tex]\rm V(L) = \int\limits^b_a {\pi(f(x) -L)^2} \, dx\\\\\rm V(L) = \int\limits^b_a {\pi((f(x))^2 -2f(x)+L^2)} \, dx\\\\\rm V(L) = \pi \int\limits^b_a {(f(x))^2} \, dx-2\pi L \int\limits^b_a {f(x)} \, dx +L^2\pi\int\limits^b_a {} \, dx[/tex]

Now finding V'(L)

[tex]\rm V'(L) = -2\pi \int\limits^b_a {f(x)} \, dx+2\pi L \int\limits^b_a {} \, dx[/tex]

[tex]\rm V'(L) = -2\pi \int\limits^b_a {f(x)} \, dx+2\pi L (b-a)[/tex]

Now equation V'(L) to zero; V'(L) = 0

[tex]\rm -2\pi \int\limits^b_a {f(x)} \, dx+2\pi L (b-a)=0[/tex]

[tex]\rm \int\limits^b_a {f(x)} \, dx= L (b-a)[/tex]

[tex]\rm L = \frac{1}{b-a} \int\limits^b_a {f(x)} \, dx[/tex]

The above expression is representing the critical point.

Now finding V''(L)

V''(L) = 2π(b-a) >0 at L

[tex]\rm L = \frac{1}{b-a} \int\limits^b_a {f(x)} \, dx[/tex]   (minimizines the volume)

Thus, the value in the part (c) is 1/(b-a) if the graph of any continuous function y = f(x) for a ≤ x ≤ b is rotated about the horizontal line y = L, the volume obtained depends on L.

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circumference= 3.14m

the radius of the circle

Circumference of a circle = 2πr

Given, circumference = 3.14 meters

Therefore:

2πr = Circumference of a circle

2πr = 3.14

2 × 3.14r = 3.14,[Putting the value of pi (π) = 3.14]

6.28r = 3.14

r = 3.14/6.28

r = 0.5

Answer:

first one is correct second one is 6 and third one is 2 and a half

Answer:

If one counts the blocks on the graph from the school to the stadium and back, there are three blocks one way and three blocks going back.

Altogether 6 blocks.

If Catelyn lives halfway between the park and the school, the amount of blocks is 5.

She lives halfway between.  Hence, what is 5 divided by 2?

2.5 or 2 1/2 blocks.

Step-by-step explanation:

Step-by-step explanation:

p(p-q) - q(q-p)

p²-pq - q² +pq

p² - q²

Choice 1

Answer:

Step-by-step explanation:

f(-6) is the corresponding number of -6 and you can spot it on the y-axis

Answer:

  6076π ≈ 19088.3 cubic units

Step-by-step explanation:

The volume of a cylinder is found using the formula ...

  V = πr²h

__

For the given dimensions, the volume is ...

  V = π(14²)(31) = 6076π ≈ 19088.3 . . . cubic units

Answer:

y= .45x + 11/3

Step-by-step explanation:

Those points are not on the same line but you can get pretty close with

y= .45x + 11/3

Answer:

The anwer is B 1200 in

Step-by-step explanation:

Answer:

[tex] \: [/tex]

Step-by-step explanation:

It is given that, The circumference of a circle is 198 cm and we are to find the radius of the circle.

[tex] \: [/tex]

To find the radius of the circle we must know this formula first :

[tex]\\{ \longrightarrow \qquad{ \underline {\boxed{ \pmb{ \mathfrak{ \: 2 \pi r \: =Circumference_{(circle)}}}}}}} \: \: \bigstar \\ \\ [/tex]

Now substituting the values in the formula :

[tex]\\{ \longrightarrow \qquad{ {{ \tt{ \: 2 \times 3.14 \times r \: =198}}}}} \\ \\ [/tex]

[tex]{ \longrightarrow \qquad{ {{ \tt{ \: 6.28 \times r \: =198}}}}} \\ \\ [/tex]

[tex]{ \longrightarrow \qquad{ {{ \tt{ r \: = \frac{198}{6.28} }}}}} \\ \\ [/tex]

[tex]{ \longrightarrow \qquad{ \pmb {{ \frak{ r \: = 31.528 }}}}} \\ \\ [/tex]

Therefore,