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Light - emitting diode lightbulbs known as LED lightbulbs are energy saving lightbulbs. They consume very small amount of energy compare to other lightbulbs. Therefore, LED lightbulbs are the most energy efficient way to light your home, as they use about ten percent (10%) of the energy of a comparable compact fluorescent bulb.

There are varieties of different light bulbs. some of them are  incandescent, compact fluorescent (CFL), halogen, and light-emitting diode (LED) to mention a few.

Before the advent of light - emitting diode (LED) bulbs, some of the bulbs consume a lot of energy. For instance, we have incandescent bulbs of 20 watts, 50 watts, 100 watts and even 200 watts.

But with the advent of light - emitting diode (LED) bulbs, consumers can save energy because light - emitting diode (LED) bulbs save a lot of energy and they are very bright.

We can therefore conclude that light - emitting diode lightbulbs known as LED lightbulbs are the most energy efficient way to light your home, as they use about ten percent (10%) of the energy of a comparable compact fluorescent bulb.

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Hi there!

We can begin by using the derived kinematic equation:

[tex]t = \sqrt{\frac{2h}{g}[/tex]

Plug in the given values and let g = 9.8 m/s²:

[tex]t = \sqrt{\frac{2(20)}{g}} = \boxed{2.02 s}[/tex]

Now, we can solve for its final velocity using the equation:

[tex]v_f = v_i + at[/tex]

It is dropped from rest, so vi = 0 m/s.

[tex]v_f = at[/tex]

[tex]v_f = 9.8(2.02) = \boxed{19.796 m/s}[/tex]

Answer:

a. The ball would reach the ground in approximately [tex]2.02\; \rm s[/tex].

b. The velocity of the ball right before landing would be approximately [tex]19.8\; \rm m\cdot s^{-1}[/tex].

(Assumptions: the ball was dropped with no initial velocity; air resistance on the ball is negligible; [tex]g = 9.81\; \rm m\cdot s^{-2}[/tex].)

Explanation:

Under these assumptions, the acceleration of this ball would be constantly [tex]a = g = 9.81\; \rm m\cdot s^{-2}[/tex] (same as the gravitational field strength) during the descent.

Displacement of the ball: [tex]x = 20.0\; \rm m[/tex].

Initial velocity of the ball: [tex]v_{0} = 0\; \rm m\cdot s^{-1}[/tex].

Let [tex]t[/tex] denote the duration of this descent.

The SUVAT equation [tex]x = (1/2)\, a\, t^{2} + v_{0}\, t[/tex] relates the known quantities [tex]a[/tex], [tex]x[/tex], and [tex]v_{0}[/tex] to the unknown [tex]t[/tex].

Substitute the known quantities into this equation and solve to find the value of [tex]t\![/tex]:

[tex]\displaystyle 20.0\; {\rm m} = \frac{1}{2}\times 9.81\; {\rm m\cdot s^{-2}} \times t^{2} + 0\; {\rm m \cdot s^{-1}} \times t[/tex].

[tex]\displaystyle 20.0\; {\rm m} = \frac{1}{2}\times 9.81\; {\rm m\cdot s^{-2}} \times t^{2}[/tex].

[tex]\displaystyle t^{2} = \frac{20.0\; \rm m}{(1/2) \times 9.81\; \rm m\cdot s^{-2}}[/tex].

Since [tex]t > 0[/tex]:

[tex]\begin{aligned}t &= \sqrt{\frac{20.0\; \rm m}{(1/2) \times 9.81\; \rm m\cdot s^{-2}}} \\ &\approx 2.01928\; \rm s\\ &\approx 2.02\; \rm s \\ & (\text{Rounded to 2 sig. fig.})\end{aligned}[/tex].

Since the acceleration of this ball is constant, the velocity of the ball right before landing would be:

[tex]\begin{aligned}v_{1} &= a\, t \\ &\approx 9.81\; \rm m\cdot s^{-2} \times 2.01928\; \rm s \\ &\approx 19.8\; \rm m \cdot s^{-1} \end{aligned}[/tex].

Answer: 100 and 1000

Explanation:

If the kinetic energy of an object changes, then the collision is considered inelastic. This is regardless of whether the objects sticks together or not.

My best answer for this question would be D) inelastic, because kinetic energy is not conserved.

We can tell from the collision that it is not elastic.

Momentum is is conserved, it transfers to the other player.

Kinetic energy is not conserved, at it turns into internal friction.

I hope this helps! :)

A football tackle is an inelastic collision , because kinetic energy is not conserved.

When two bodies or particles move towards enough to interact with each other it is called the particles or the bodies are colliding.

So, when the football tackles it's kinetic energy changes.

Thus, A football tackle is an inelastic collision , because kinetic energy is not conserved.

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Answer:

Star formation occurs most rapidly in the spiral arms, where the density of interstellar matter is highest.

What is the weight of a car with the mass of 1000 kg?

Answer: it is 9800 N.

The mass of the orange after it has been cut into pieces will still remain the same as the mass of the whole orange.

Let us recall that the law of conservation of mass states that, mass can neither be created nor destroyed but is converted from one form to another. In accordance with this law of conservation of mass. The mass of the orange must remain the same after it has been cut in pieces.

Hence, If the mass of an orange is measured after it has been cut into pieces, the mass of the orange after it has been cut into pieces will still remain the same as the mass of the whole orange.

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Answer:

So this is just a ratio/proportion problem

so lets say its in boys:minutes

so in the first scenario

20:8

and we want to find

x:10

So proportion really

20/8=x/10

cross multiply

25

25 boys can sweep it in 10 minutes

Hi there!

We know that:

[tex]P = \frac{W}{t}\\\\[/tex]

Where:

W = Work done (J)

t = time (s)

We can calculate the work using the equation:

[tex]W = \Delta U = mg\Delta h[/tex]

Plug in the given values:

[tex]W = 60(9.8)(4) = 2352J[/tex]

Now, divide by time:

[tex]P = \frac{W}{t} = \frac{2352}{4.2} = \boxed{560W \text{ (Watts)}}[/tex]

Answer:

Explanation:

A decrease in the density of something is rarefaction. ... Most of the time, rarefaction refers to air or other gases becoming less dense. When rarefaction occurs, the particles in a gas become more spread out. You may come across this word in the context of sound waves.

Answer:

whats the question

Explanation:

Answer:

Below

Explanation:

On the moon, an objects weight will be different than it is on earth. This is because we cannot change the mass of an object, the mass of an object is the measure of matter an object has. However the weight is depended on the gravitational pull of whatever planet you are on. In this case, weight will be lighter on the moon than it is on earth because the moon's gravitational pull is 1.62 m/s^2 while earths is around 9.8 m/s^2.

Hope that helps!

This question involves the concepts of potential difference, inductance, and current.

The minimum time that should be allowed for the current to change is "0.694 ms".

The inductance of an inductor is given by the following formula:

[tex]E=L\frac{\Delta I}{\Delta t}\\[/tex]

where,

E = potential difference across the inductor = 360 volts

L = inductance of the inductor = 250 mH = 0.25 H

ΔI = change in current = 2.5 A - 1.5 A = 1 A

Δt = time required = ?

Therefore,

[tex]\Delta t = \frac{(0.25\ H)(1\ A)}{360\ volts}[/tex]

Δt = 6.94 x 10⁻⁴ s = 0.694 ms

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Answer:

65km/h

Explanation:

Here,

Relative velocity of car moving in different directions with different velocities =Va + Vb

=25+40

=65 km/h

Please find attached photograph for your answer.

Hope it helps.

Do comment if you have any query.

Answer:

Noah has run 600 metres north east

Answer:

D and B.

Explanation:

The wavelength must be taken from the same corresponding point. D and B are both at the crests of a wave, with no other crests in between, which means the distance between them is equal to one wavelength.

The answer is option A. 0.75 m/s^2

the formula needed to solve this is acceleration = force/mass

we know the following:

mass of the backpack = 20KG

the force is 15N

therefor- acceleration = 15/20

which can also be written as 3/4, leaving us with the final answer of .75 m/s^2

Answer:

0.75 m/s2

Explanation:

0.75 m/s2

Answer:

B. surface wave

Answer:

3.09594

Explanation:

hope this helps

Answer:

[tex]150 kg\cdot m/s[/tex]

Explanation:

Same as if he was walking uphill, or horizontally. Momentum is defined as the product of mass times velocity. [tex]p = mv = 15\cdot 10 = 150 kg\cdot m/s[/tex]

Answer:

Explanation:

Givens

m = 15000 kg

t = 12.1 seconds

vi = 86 km / hr

vf =0

Formula

F = m*a

a = (vf - vi)/ t

vi has to be converted to m/s

86 km/hr [1000 m / 1 km] * [1 hour / 3600 seconds]

86 * 1000 / 3600 = 23.89 m/s

Solution

a = (vf - vi) / t

a = (0 - 23.89)/12.1

a = - 1.97 m/s^2 The minus means that the trains is slowing down.

F = 15000 kg * - 1.97 m/s^2

F = -29615.7 Newtons.

Answer:

The answer is (C) E= 1/2 kx^2

Explanation:

Answer:

ITS C JUST FINISH

Explanation:

Answer:

Velocity/time =acceleration

Acceleration x time = velocity

Velocity/acceleration=time

Answer:

Energy = Power × Time

[tex]{ \tt{E = ( \frac{60}{1000} ) \times ( \frac{5}{60}) }} \\ \\ { \tt{E = 0.005 \: kwh {}^{ } }}[/tex]

A bowling ball is dropped off a 300 meter high bridge. A water bottle is dropped from the same position 3 seconds later. the ground is the water bottle, when the bowling ball has a speed of 64 m/s is zero.

Speed is measured as the ratio of distance to the time in which the distance was covered. Speed is a scalar quantity as it has only direction and no magnitude.

The formula of speed is represented as s=d/t, Where, s is the speed in m.s-1, d is the distance traveled in m, t is the time taken in s

There are four types of speed such as Uniform speed, Variable speed, Average speed, Instantaneous speed

Uniform speed is an uniform speed when the object covers equal distance at equal time intervals, variable speed is defined as when the object covers a different distance at equal intervals of times.

Average speed is defined as the uniform speed the ratio of total distance travelled by an object to the total time taken by the object.

Instantaneous speed is defined as an object is moving with variable speed, then the speed at any instant of time is known as instantaneous speed.

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Answer:

transverse wave, motion in which all points on a wave oscillate along paths at right angles to the direction of the wave's advance. Surface ripples on water, seismic S (secondary) waves, and electromagnetic (e.g., radio and light) waves are examples of transverse waves.

Explanation:

Uhhhh here is an example

a=vt. =27 m/s10 s. =2.7 m/s2.

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Acceleration of the car is ~

[tex] \boxed{1.5 \: \: m/s}[/tex]

[tex] \large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}[/tex]

We know that,

Acceleration = rate of change in velocity ~

that is ~

where,

now, let's solve ~