Answer:
1. lava
2. caldera
3. true
4. true
5. before
For the reaction H2O) =H% + OH", if x moles of H and y moles of OH are formed K. is y A. *?/(1 – x) C. 1/xy D. xy
Answer: Correct option is B)
The standard enthalpy change of formation of a compound is the enthalpy change which occurs when one mole of the compound is formed from its elements under standard conditions. The equation showing the standard enthalpy change of formation of water is
H
2
(g)+
2
1
O
2
(g)⟶H
2 ↑
O(l) 1 mole of water formed.
∴ Enthalpy of formation is −X2kJ/mol.
________________________________________________________
Explanation:I hope this helped
Consider the following generic chemical equation.
A+3B→C
What is the limiting reactant when each of the following amounts of A and B are allowed to react?
A. 1 mol A; 4 mol B
B. 2 mol A; 3 mol B
C. 0.5 mol A; 1.6 mol B
D. 24 mol A; 75 mol B
Answer:
[tex]\fbox{ A) A \: is \: limiting \: reactant }[/tex]
[tex]\fbox{ B) B \: is \: limiting \: reactant }[/tex]
[tex]\fbox{ C) A \: is \: limiting \: reactant }[/tex]
[tex]\fbox{ D) A \: is \: limiting \: reactant }[/tex]
Explanation:
Given equation:
[tex]A+3B \rightarrow \: C [/tex]
To find:
Limiting reactant for corresponding number of moles=?
Solution:
We know that the liming reactant is any atom, ion or molecule which is completely consumed during a reaction and other reactant is still left in reactant vessel.
For the given reaction A+3B→C
for every one mole of A three moles of B are required.
﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌
in A) there is one mole of A and 4 mole of B,
if 1 mole of A will react with 3 moles of B, 1 mole of B will be still there in reaction, the reactant was completely consumed is A which is limiting reactant.
﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌
in B) there is 2 mole of A and 3 mole of B,
if 1 mole of A will react with 3 moles of B, 1 mole of A will be still there in reaction, the reactant was completely consumed is B which is limiting reactant.
﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌
in C) there is 0.5 mole of A and 1.6 mole of B
if one mole of A requires three moles of B to complete the reaction then,
0.5 moles of A will require 1.5 moles of B
if 0.5 mole of A will react with 1.6 moles of B, 0.1 mole of B will be still there in reaction, the reactant was completely consumed is A which is limiting reactant.
﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌
in D) there is 24 mole of A and 72 mole of B
if one mole of A requires three moles of B to complete the reaction then,
24 moles of A will require 72 moles of B.
if 24 mole of A will react with 75 moles of B, 3 mole of B will be left over in reaction, the reactant was completely consumed is A which is limiting reactant.
﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌
[tex]\fbox{ A) A \: is \: limiting \: reactant }[/tex]
[tex]\fbox{ B) B \: is \: limiting \: reactant }[/tex]
[tex]\fbox{ C) A \: is \: limiting \: reactant }[/tex]
[tex]\fbox{ D) A \: is \: limiting \: reactant }[/tex]
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Calculate the pH of the following aqueous solution:
0.35 M NaF (pKa for HF = 3.14)
I'm pretty sure I know how to calculate the pH by itself, but I am confused on how to get the equation. I'm not sure what HF has to do with this, other than it's an acid. I'm probably overthinking it because it's worded differently. Thanks in advance!
The pH of an aqueous solution that has a concentration of 0.35 M NaF and pKa for HF = 3.14 is 3.6.
How to calculate pH?The pH of a solution refers to the degree of acidity or alkalinity of the solution. It can be calculated using the Henderson-Hasselbalch Equation as follows:
pH = pka + log ([A-]/[HA])
Where;
A- = conjugate baseHA = weak acidpH = pKa + log([F-]/[HF])
pH = 3.14 + log(1/0.35)
pH = 3.14 + 0.4559 = 3.595
Therefore, the pH of an aqueous solution that has a concentration of 0.35 M NaF and pKa for HF = 3.14 is 3.6.
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What is the molarity of a solution made by adding 1.565 moles of
PbNO3 to 0.500 L?
300. M
31.3 M
3.13 M
1.56 M
Answer:
3.13M
Explanation:
Using the Molaitry equation ( M = n/v ) just plug numbers in and solve.
A lab technician determines the boiling point elevation of an aqueous solution of a nonvolatile, nonelectrolyte to be 1.12 C. What is the solution’s molality?
Answer:
2.19m
Explanation:
quizlet
Which statement is an opinion expressed in "Stick to Real Microscopes"?
A) Smartphone microscopes are not great scientific tools.
B) Many real microscopes cost between $150 and $300.
C) A fairly good real microscope can enlarge objects up to 2000 times their actual size.
D) It is quite inexpensive to turn a smartphone into a microscope.
Answer:it’s Smartphone microscopes are not great scientific tools.
Explanation:
The statement expressed in stick to real microscopes Smartphone microscopes are not great scientific tools.
What is scientific tools?Getting to use all the great tools is one of the best parts of constructing something. Power saws, drills, and electric sanders are tools that builders employ to transform basic materials into original designs.
Scientists employ tools to achieve their goals, just like builders do. Researchers can do experiments, make observations, and take precise measurements with the aid of scientific gear.
In this session, we'll talk about some basic scientific instruments that you could find in the science lab at your school, as well as some more sophisticated instruments that biologists use to study the world around us.
Therefore, The statement expressed in stick to real microscopes Smartphone microscopes are not great scientific tools.
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10. Boron has two naturally occurring isotopes, 10B with an atomic mass of 10.0129370amu and 11Bwith an atomic mass of 11.0093054amu. The atomic mass of boron is 10.81 (from the periodic table). The percent abundances of the boron isotopes are __________% 10Band __________% 11B.
Explanation:
allowing 20% discount on the market price of a watch the value of the watch will be rs 2376 when a VAT of 10% is added ,find it's market price
If the actual yield for a substance is 39.487g but the theoretical yield is 38.000g, what is
the percent yield?
a. 2%
b. 96%
c. 50%
d. 104%
Answer:
b. 96%
Explanation:
Reactivity Series
Iron, tin and zinc all react with dilute hydrochloric acid to produce hydrogen.
Plan an experiment to determine the order of reactivity of iron, tin and zinc.
You are provided with powdered samples of the metals and common laboratory apparatus.
Answer:
Measuring electode potential
Explanation:
Make an electrode of all of them and measure standard reductive potential metals with lower srp will be more reactive
The metals which are placed above the hydrogen in the reactivty series can produce hydrogen gas with HCl. The order of reactivity of given metals is as follows: Zinc > iron > tin.
What is reactivity series?The reactivity series of elements or the activity series can be defined as the arrangement of metals in descending order according to their reactivities.
The metals placed at the top of the activity series are strong reducing agents and can be readily oxidized. These metals readily tarnish/corrode. The reducing ability becomes weaker while moving down the reactivity series.
The electropositivity of the elements decreases as we move down in the reactivity series of metals. All metals which are placed above hydrogen in the activity series can able to release hydrogen gas upon reacting with dilute HCl.
Therefore, the metals Iron, tin, and zinc release hydrogen gas when they react with the HCl. The order of reactivity is according to their reduction potential which is Zinc > iron > tin.
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Which type of covalent bond is the least stable?
A.Covalent bonds
B.Double bonds
C.Single bonds
D.Triple Bonds
Answer:
D because: A Triple bond is when three pairs of electrons are shared between two atoms in a molecule. It is the least stable out of the three general types of covalent bonds.
8. Thermal Energy is?
A. Kinetic
B. Potential
c. Potential and Kinetic
D. Neither Potential and Kinetic
Thermal energy is the sum of the kinetic and potential energy of all the particles in an object. The figure shows that if either potential or kinetic energy increases, thermal energy increases.
hope it really helps...!!!
A manometer measures 450 torr of pressure in a container with 0.500-L sample of carbon dioxide, CO2. The gas is compressed to a volume of 0.100 L. What is the new pressure reading in the manometer?
Let's see
Apply boyles law
P1V1=P2V2450(0.5)=0.1P_2225=0.1P_2P_2=2250TorrHELP ME OUT PLS!!!!!!!!!
All stars begin their life in a
O black hole
O main sequence
O protostar
O nebula
Answer:
nebula
Explanation:
I am well informed
a 21.0 kg rock rests on the edge of a cliff 32.0 m high. how much gravitational potential energy does the rock have
Explanation:
Formula for Potential energy=mgh mass* gravity*height
21kg × 10 ×32=6720joules
If a 21.0 kg rock rests on the edge of a cliff 32.0 m high, the gravitational potential energy gained by the rock would be 6585.6 Joules.
What is mechanical energy?Mechanical energy is the combination of all the energy in motion represented by total kinetic energy and the total stored energy in the system which is represented by total potential energy.
As given in the problem a 21.0 kg rock rests on the edge of a cliff 32.0 m high, then we have to calculate the potential energy gained by the rock,
The potential energy of the rock = 21 × 9.8 × 32
= 6585.6 Joules.
Thus ,If a 21.0 kg rock rests on the edge of a cliff 32.0 m high, the gravitational potential energy gained by the rock would be 6585.6 Joules.
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Question 4 of 15
The types of radiation produced by alpha, beta, and gamma decay differ in
many ways. Which characteristic do they all have in common?
A. The ability to treat cancer
B. The ability to cause cancer
C. The ability to trace the movement of chemicals
D. The ability to damage human tissue
Answer:
D. The ability to damage human tissue
please give me brainliest.
A 0.15 M NaOH solution has a volume of 0.125 L but is then diluted to 0.15 L. What is the concentration of the new solution
Answer:
.125 M
Explanation:
.15 M/L * .125 L = .01875 moles
now dilute to 150 cc (by adding 25 cc)
.01875M / (150/1000) = .125M
What is the molarity of a solution where 2.2 mol of KCl is dissolved to make 5.7 L of solution?
is mixing water and glue a chemical or physical change?
Answer:
physical
Explanation:
because it would still remain as a liquid. if you were to add borax or something to it, then it would be a chemical change.
What is the equilibrium constant K at 25°C for an electrochemical cell when E° = +0.0140 V and n = 2?(F = 96,500 J/(V・mol), R = 8.314 J/(mol・K))
The equilibrium constant of the electriochmeical cell as shown is 2.976.
What is the equilibrium constant?The equilibrium constant of a reaction shows the extent of the conversion of the reactants to products.
Now we know that;
ΔG = -nFE°cell
n = 2
F = 96,500 J/(V・mol)
E°cell = +0.0140 V
ΔG = -(2 * 96,500 * 0.0140)
ΔG = -2702 J
But;
ΔG = -RTlnK
lnK = -(ΔG/RT)
K = e^[-(ΔG/RT))
K = e^[-(( -2702)/8.314 * 298]
K = 2.976
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Which of the following are true about photosynthesis and cellular respiration. (Select all that apply.)
The products of one process are the reactants of the other.
The relationship between them enables life to survive as we know it.
They both happen only in plants.
They both take place in human cells.
Answer:
2 and 4 are the best answers
Explanation:
Answer:
A and B
Explanation:
Took the k12 test.
How many Si atoms are there in 1.00 g of silicon
Which substance will hold its shape?
plasma
liquid
gas
solid
Answer:
solid
Explanation:
plasma = no
liquid= shapes is container it is in
gas = shaped to container also
Identify the type of energy conversion represented by each picture.
solar energy to light energy
electric energy to light energy
electric energy to heat energy
wind energy to electric energy
[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]
The given pictures show conversion of energy from one form to another.
#Picture 1Electric energy to Heat energy
#Picture 2Wind energy to electric energy
#Picture 3Solar energy to light energy
#Picture 4Electric energy to light energy
Consider the following reaction where Kc = 55.6 at 698 K.
H2(g) + I2(g) 2HI(g)
A reaction mixture was found to contain 2.29×10-2 moles of H2(g), 3.80×10-2 moles of I2(g) and 0.254 moles of HI(g), in a 1.00 liter container.
Is the reaction at equilibrium?
If not, what direction must it run in order to reach equilibrium?
The reaction quotient, Qc, equals
.
The reactionfill in the blank 2
A. must run in the forward direction to reach equilibrium.
B. must run in the reverse direction to reach equilibrium.
C. is at equilibrium.
Answer:
B
No the reaction is not at equilibrium
The reaction must run to the left (reactants) to reach equilibrium
Qc = 74.14
Explanation:
Qc = (0.254)^2 / ((2.29 x 10-2)(3.8 x 10-2))
Qc = 74.14
74.14 > 55.6
Qc > Kc
Which unit is used to measure the distance between galaxies? Question 3 options: kilometers decades years light years
Answer:
light years
Explanation:
light year is the DISTANCE light travels in one year ...a very large distance
Answer:
light years
Explanation:
since distance between galaxy space ,objects .
Which types of particles are involved in a fission reaction?
A neutral neutron strikes a large neutral nucleus.
A positive proton strikes a large positive nucleus.
A neutral neutron strikes a large positive nucleus.
A positive proton strikes a large neutral nucleus.
Why is it important for scientist to be objective when using the design process like the scientific method when doing there investigations?
Answer:
Scientists use the scientific method to make testable explanations and predictions about the world. A scientist asks a question and develops an experiment, or set of experiments, to answer that question. Engineers use the engineering design process to create solutions to problems.
plese help
Using the rules that you learned during the session, what is the answer to the following question?
55.78 * 23.7
Answers
A) 1,322
B) 1,320
explain:
Calculate AHræn for the following reaction
2 AX (g) + 7 BY (g) →4AY (g) + 6 BX (g)
Use the following AHformation values for AX, BY, AY and BX
AX: AHformation = -80 kJ/mol
BY: AH formation = 57 kJ/mol
AY: AHformation = -379 kJ/mol
BX: AHformation = -251 kJ/mol
Answer:
60ax 70by 67ay ah251
Explanation:
Which technique can be used to remove air bubbles from a syringe? a) Hold the syringe downward, shake vigorously for 10 seconds, and expel the bubbles through the needle using the syringe plunger. Hold the syringe upright, provide a firm tap or flick to the b) barrel, and expel the bubbles through the needle using the syringe plunger. Hold the syringe upright, shake vigorously for 10 seconds, c) and expel the bubbles through the needle using the syringe plunger. Hold the syringe downward, provide a firm tap or flick to the d) barrel, and expel the bubbles through the needle using the syringe plunger.
Answer:
Point the syringe upright and tap firmly to move the bubbles to the top and expel by pushing the plunger
Explanation:
If you hold the syringe upside down the bubbles will end up at the bottom of the syringe by the plunger since they float up when tapped