Please help me i really need help

Answer:

The 4th would be 0.25

Step-by-step explanation:

I dont know

I would just pick c

Answer:

Step-by-step explanation:

Let the number be x then,

1) 4 * x + 11

2) 8 * (x + 7)

3) 2x - 1

4) x+ 3x

5) 5x + 12

6) 16 + 1 + x = 17 + x

7) 20 - ( x - 5) = 20 - x + 5 = 25 - x

8) x - 6 + 15 = x +9

Answer:

Way too many

Step-by-step explanation:

(92)

Answer:

5, 9, 13, 17, 21, 25

Step-by-step explanation:

Given a₁ = 5 and d = 4

Add d = 4 to the previous term, that is

a₁ = 5

a₂ = a₁ + 4 = 5 + 4 = 9

a₃ = a₂ + 4 = 9 + 4 = 13

a₄ = a₃ + 4 = 13 + 4 = 17

a₅ = a₄ + 4 = 17 + 4 = 21

a₆ = a₅ + 4 = 21 + 4 = 25

Answer:

X=32, y=-5

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

q3 - q1

7 -1 = 6

Answer:

6 is the IQR

Step-by-step explanation:

To determine the IQR, you need to evaluate the box. The first quartile starts at 1, and the third quartile ends at 7. To calculate IQR, subtract Q1 (1) from Q3 (7). So it would be 7 - 1 = 6

So your answer is 6.

Answer:

30

Step-by-step explanation:

The slope formula, or the ratio of the change in the y values to the change in the x values, is m=(y2-y1)/(x2-x1).

A line's steepness and direction are measured by the line's slope.

Without actually using a compass, determining the slope of lines in a coordinate plane can assist in forecasting whether the lines are parallel, perpendicular, or none at all.

A line's slope is determined by how its y coordinate changes in relation to how its x coordinate changes.

The y coordinate's net change is y, and the x coordinate's net change is x.

Hence, The slope formula, or the ratio of the change in the y values to the change in the x values, is m=(y2-y1)/(x2-x1).

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Answer:

1=B

Step-by-step explanation:

Therefore, there are 12 bandages in 2 boxes, which is the answer to the unitary method presented problem.

The term "unitary" refers to a single or separate unit or variable . As a result, this strategy's objective is to establish values in terms of a single unit. For instance, if a car travels 44 kilometres on two litres of gas, the unitary technique can be used to determine how many kilometers it will drive on one.

Here,

Given: Each box of bandages has three packs, with two bandages in each pack.

Now, determine how many bandages there are in two boxes.

Therefore, we solve using the unitary method:

One pack contains two bandages.

In 3 packs, there are therefore = 2*2 = 6 bandages.

One box contains three packs as stated.

Consequently, we multiply 2 by 6 to obtain the bandages in 2 boxes:

=> 2 * 6 = 12

Therefore, there are 12 bandages in 2 boxes, which is the answer to the unitary method's presented problem.

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The Value of the two constants K and R are 5 and 3 respectively.

a) To find u2, you can substitute u1 = 8 into the term-to-term rule to get:

u2 = 2u1 + 20 = 2(8) + 20 = 36

So u2 = 36.

b) To find the values of k and r, you can use the given values of u1, u2, and u3 to set up a system of equations. Using the term-to-term rule:

Substituting in the given values:

Solving for r and k, we get:

k = 5 and r = 3.

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Answer:

A

Step-by-step explanation:

If you substitute each x value from the input boxes into the equations, you can find your answer.

The first input value is 1, and the output value is 12, so plug those into the first equation in the answer options.

y = 4x + 8

(12) = 4(1) + 8

12 = 4 + 8

12 = 12

Because the simplified equation ended in a true equality statement, that pair works with the equation.

The next x value is 3 and the y value is 20:

y = 4x + 8

(20) = 4(3) + 8

20 = 12 + 8

20 = 20

Again, it ends in  true equality statement, so it also works with the equation.

(28) = 4(5) + 8 = 28 so that one works as well.

Then check the second equation with the second set of input and output values.

(2) = -7(-1) - 5 = 2

The first x and y values of that system work.

(9) = -7(-2) - 5 = 9

The second one works as well.

(16) = -7(-3) - 5 = 16

The last one is equal as well.

So the equations in A, or the first option, work with all of the inputs and outputs.

Answer:

Step-by-step explanation:

1) The domain is related to the behaviour of the x

the graph started when x is -11 and finish when x is 1

so

D : [-11 ; 1]

or -11 ≤x ≤ 1

the range is related to the behavior of y

the graph start when y is -7 and finish when y = 0

Range : [-7;0]

or -7≤ y ≤ 0

Answer:

isosceles triangles have two congruent acute angles

1) The formula for area is,

⇒ Area of rectangle = Length × Width

And, The formula for perimeter is,

⇒ Perimeter = 2 (Length + width)

2) An expression for the length of the south side of the yard is,

⇒ Length = (5x + 2) + (x² - 9) + (x² - 7x + 12)

3) The simply expression for the length of the south side of the yard is,

⇒ Length =  2x² - 2x + 5

4) An expression for the perimeter of the pool area is,

⇒ Perimeter = 2 ( (x² + 10) + (8x + 8) )

5) 5) The simply expression for the perimeter of the pool area is,

⇒ Perimeter = 2x² + 16x + 36

A rectangle is a two dimension figure with 4 sides, 4 corners and 4 right angles. The opposite sides of the rectangle are equal and parallel to each other.

Given that;

The Johnson family is redesigning their backyard this spring. They want to include a sandbox area, a swing set area, a patio area, a pool area and a grill area.

Now,

1) The formula for area is,

⇒ Area of rectangle = Length × Width

And, The formula for perimeter is,

⇒ Perimeter = 2 (Length + width)

2) An expression for the length of the south side of the yard is,

⇒ Length = (5x + 2) + (x² - 9) + (x² - 7x + 12)

3) The simply expression for the length of the south side of the yard is,

⇒ Length = (5x + 2) + (x² - 9) + (x² - 7x + 12)

                = 5x + 2 + x² - 9 + x² - 7x + 12

                = 2x² - 2x + 5

4) An expression for the perimeter of the pool area is,

⇒ Perimeter = 2 ( (x² + 10) + (8x + 8) )

5) The simply expression for the perimeter of the pool area is,

⇒ Perimeter = 2 ( (x² + 10) + (8x + 8) )

                    = 2 (x² + 10 + 8x + 8)

                    = 2 (x² + 8x + 18)

                    = 2x² + 16x + 36

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Answer:

B

Step-by-step explanation:

The output of function g(r) = -5x + 13 when r is 3 is -2.

A function is a relationship between inputs where each input is related to exactly one output.

Example:

f(x) = 2x + 1

f(1) = 2 + 1 = 3

f(2) = 2 x 2 + 1 = 4 + 1 = 5

The outputs of the functions are 3 and 5

The inputs of the function are 1 and 2.

We have,

g(r) = -5r + 13

Input r = 3

g(3)

= -5 x 3 + 13

= -15 + 13

= - 2

Thus,

The output is -2.

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The simplest form of the value of the trigonometric identity cos(A-B) is

1508/1517.

What is are the trigonometric identities?

Trigonometric Identities are equality conditions that apply to all values of the equation's variables and which require trigonometry functions.

There are numerous unique trigonometric identities that involve both the side length and angle of a triangle. Only the right-angle triangle is  valid for the trigonometric identities to work.

cos(A-B) = cosA cosB + sinA sinB

Given,

    tan A = 12 / 35

So sin A = 12 / [tex]\sqrt{12^2 + 35^2}[/tex]  = 12 / 37

    cos A = 35 / 37

Now,

    sin B = 9/41

     cos B = [tex]\sqrt{1 - sin^{2} B }[/tex] = [tex]\sqrt{1 - (\frac{9}{41} )^{2} }[/tex] = 40/41

  Now substituting the above values in the cosine formula

cos(A-B) = cosA cosB + sinA sinB

              = (35/37) (40/41) + (12/37) (9/41)

              = 1508/1517 = 0.994

Therefore the simplest form of cos(A-B) is 1508/1517.

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Answer:

6

Step-by-step explanation:

delta math

The required measure of the other leg will be 6 cm in the given right triangle.

Pythagoras's theorem states that in a right-angled triangle, the square of one side is equal to the sum of the squares of the other two sides.

We have been given that one of the legs of a right triangle measures 8 cm and its hypotenuse measures 10 cm.

Let the measure of the other leg would be x cm.

According to Pythagoras's theorem,

⇒ c² = a² + b²  ....(i)

As per the given question, we have

c = 10cm, a = 8 cm and b = x

Substitute the values in the above formula, and solve for x

⇒ 10² = 8² + x²

⇒ 100 = 64 + x²

⇒  x² = 100 - 64

⇒  x² = 36

⇒  x² = 6²

⇒  x = 6

Therefore, the required measure of the other leg will be 6 cm in the given right triangle.

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Answer:

1357.17 cubic feet

Step-by-step explanation:

The volume of a cylinder is

[tex]\pi {r}^{2} h[/tex]

We know the height is 12, and the radius is simply half our diameter, which in this case is

[tex] \frac{12}{2} = 6[/tex]

plug these two numbers into our formula and we have found our volume.

Answer:

4 sweets per friend

Step-by-step explanation:

so first you want to minus 10 sweets since she ate 10 leaving her with 40 sweets. then she gives 8 sweets to her brother leaving her with 32 sweets left. If you divide the remaining sweets ( 32 ) by 8 you get 4 sweets per friend

The third side of a triangle, the following formula can be used c² = a² + b² - 2abcos(C)

To calculate the third side of a triangle, first find the lengths of the other two sides and the angle opposite the third side. Then plug these values into the formula above and solve for c.

Where c is the third side of the triangle, a and b are the other two sides, and C is the angle between them.

For example, for a triangle with two sides of length 4 and 6, and an angle between them of 75 degrees, the formula would look like this:

c² = 42 + 62 - 2(4)(6)cos(75)

Solving for c yields a third side length of 8.4.

To solve for c, first square the two side lengths: 42 = 16 and 62 = 36. Then, multiply the two side lengths together and multiply by the cosine of the angle between them: 2(4)(6)cos(75) = 43.9. Finally, add the two squared values together and subtract the result of the multiplication: 16 + 36 - 43.9 = 8.1. Then, take the square root of this result to get the length of the third side: √8.1 = 8.4.

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Amelie needed 335 cups of flour for the recipe.

Given data :

She is making 2 1/2 or 2.5 times the original recipe.

Cups in original recipe= 134 cups

cups Amelie will need= 2.5 × 134

                                     = 335 cups

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The sum of the greatest common factor (HCF) and least common multiple (LCM) of 3 and 6 is 9.

The H.C.F. defines the highest common factor present in between given two or more numbers, while L.C.M. defines the least common multiple number which is exactly divisible by two or more numbers.

factors of 3 are 1 and 3

factors of 6 are 1, 2, 3, and 6

3 = 1 × 3

6 = 2 × 3

LCM = 2 × 3

LCM = 6

HCF = 3

sum of HCF and LCM of 3 and 6 = 3 + 6

sum of HCF and LCM of 3 and 6 = 9

Therefore, 9 is the sum of the greatest common factor HCF least common multiple LCM of 3 and 6.

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Answer:

[tex]b = 90[/tex]

[tex]d = 100[/tex]

[tex]c = 80[/tex]

Step-by-step explanation:

The problem is asking for the values of the variables [tex]b[/tex], [tex]c[/tex], and [tex]d[/tex] in the given parallelogram with angles [tex]d\textdegree[/tex], [tex]c\textdegree[/tex], [tex](b-10)\textdegree[/tex], and [tex](b+10)\textdegree[/tex].

To solve for these variables, we can construct three equations using the knowledge that any two adjacent angles of a parallelogram are supplementary (their measures add to 180º).

The first equation shows that the top two angles are supplementary:

[tex]d\textdegree + c\textdegree = 180\textdegree[/tex]

The second equation shows that the bottom two angles are supplementary:

[tex](b-10)\textdegree + (b+10)\textdegree = 180\textdegree[/tex]

The third equations shows that the left two angles are supplementary:

[tex]d\textdegree + (b-10)\textdegree = 180\textdegree[/tex]

First, we can solve for [tex]b[/tex] in the second equation using simple algebraic manipulation.

[tex](b-10)\textdegree + (b+10)\textdegree = 180\textdegree[/tex]

[tex](b+b)\textdegree + (10-10)\textdegree = 180\textdegree[/tex]

[tex]2b\textdegree = 180\textdegree[/tex]

[tex]b\textdegree = 90\textdegree[/tex]

[tex]b = 90[/tex]

Using this [tex]b[/tex]-value, we can solve for [tex]d[/tex] by rewriting the third equation, plugging [tex]90[/tex] in for [tex]b[/tex]:

[tex]d\textdegree + (b-10)\textdegree = 180\textdegree[/tex]

[tex]d\textdegree + (90-10)\textdegree = 180\textdegree[/tex]

[tex]d\textdegree + 80\textdegree = 180\textdegree[/tex]

[tex]d\textdegree = 100\textdegree[/tex]

[tex]d = 100[/tex]

Finally, we can solve for [tex]c[/tex] in the first equation by plugging [tex]100[/tex] in for [tex]d[/tex]:

[tex]d\textdegree + c\textdegree = 180\textdegree[/tex]

[tex]100\textdegree + c\textdegree = 180\textdegree[/tex]

[tex]c\textdegree = 80\textdegree[/tex]

[tex]c = 80[/tex]