Peregrine falcons, which can dive at 200 mph (90 m/s), grab prey birds from the air. The impact usually kills the prey. Suppose a 480 g falcon diving at 75 m/s strikes a 240 g pigeon, grabbing it in her talons. We can assume that the slow-flying pigeon is stationary. The collision between the birds lasts 15 ms.

The elevation at the top of the hill is 1,653.85 m.

The given parameters;

The elevation at the top of the hill is calculated as follows;

[tex]P.E = mg\Delta h\\\\P.E = mg(h_2 -h_1)\\\\h_2 -h_1 = \frac{P.E}{mg} \\\\h_2 = \frac{P.E}{mg} + h_1\\\\h_2 = \frac{9.2 \times 10^5 }{72 \times 9.8} \ + \ 350 \ m\\\\h_2 = 1,653.85 \ m[/tex]

Thus, the elevation at the top of the hill is 1,653.85 m.

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Answer:

Its acceleration will increase.

Explanation:

For an object spinning around a central point, Its acceleration will increase if its distance from the centre is decreased.

The rate at which an item changes its velocity is known as acceleration, a vector quantity. If an object's velocity is changing, it is acceleration. The net acceleration that objects get as a result of the combined action of gravity and centrifugal force is known as the Earth's gravity

This is the acceleration of an object in a circle of radius r at a speed v. So, centripetal acceleration is greater at high speeds and in sharp curves smaller radii and for lager radii acceleration will be less.

acceleration, a = v²/r

For an object spinning around a central point, Its acceleration will increase if its distance from the centre is decreased.

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The equation of the progressive wave is y = 12 cos(40t - 4x)

The general wave equation is given by:

y = A sin(ωt - kx)

Where A is the amplitude, ω is the angular frequency = 2πf, f is the frequency, k is the wave number and y, x is the displacement.

Given the equation for a progressive wave is y=6 cos⁡(20t-4x). Hence:

The amplitude A = 6,

ω = 20 = 2πf

f = 20/2π = 3.183 Hz

Twice the amplitude = 2 * 6 = 12, twice the frequency = 2 * 3.183.

ω = 2π(3.183*2) = 40

Therefore the other progressive wave has an equation of:

y = 12 cos(40t - 4x)

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From the diagram, the angular speed will increase clockwise, the sign of the angular acceleration will be negative and the direction of rotation will be clockwise direction and the sign of the angular acceleration is negative. The correct answer is option B

Given that two objects of masses m1 and m2 are attached to a seesaw. The seesaw is made of a bar that has length l and is pivoted so that it is free to rotate in the vertical plane without friction. Counterclockwise is considered the positive rotational direction.

If m1 is 24 kilograms, m2 is 12 kilograms, and mbar is 10 kilograms, The moment of object m1 will be equal to the moment of object m2 without the Mbar

Let assume that the length L of the seesaw is 9 cm.

Anticlockwise moment = 24 x 9/3 = 72Nm

Clockwise moment = 12 x 2(9/3) = 72 Nm

With the consideration of mass of the bar Mbar, this will add to clockwise moment of the seesaw.

Therefore, the direction of rotation will be clockwise direction.

Angular acceleration is positive when object is speeding up and negative when slowing down. Also, angular acceleration is positive when speed increases in an anticlockwise direction and negative when speed increases in the clockwise direction.

From the diagram, since the angular speed increase clockwise, the sign of the angular acceleration will be negative.

We can conclude that the direction of rotation will be clockwise direction and the sign of the angular acceleration is negative.

The correct answer is option B

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Hi there!

We can use the equation:

d = v₀t + 1/2at²

Where:

v₀ = initial velocity downward

a = acceleration due to gravity

t = time

Plug in given values:

d = 4(12) + 1/2(9.8)(12²)

d = 48 + 705.6 = 753.6 m

Answer:

20 volts

Explanation:

Use the equation [tex]P=VI[/tex]

[tex]60=V(3)[/tex]

[tex]V=20[/tex]

Answer:

No

Explanation:

Changing momentum of any kind requires work. Work is a force acting over a distance. While holding the weights at arms length and spinning will create a force (centripetal), there is no radial distance change incurred. Releasing the weights will reduce the force to zero, still no work done and no change in angular momentum.

If he was holding the weights at arms length while spinning and he pull his hands to his chest, there now exists both the centripetal force and a distance in the direction of that force (inward radial) this work will result in an increase in angular velocity as moment of inertia has decreased with the work done.

No, the skater doesn't succeed in changing his angular velocity.

The final angular velocity of the skater is determined by applying the principle of conservation of angular momentum as shown below;

Li = Lf

[tex]Ii\omega _i = I_f \omega _f[/tex]

where;

When the skater holds the weight, the momnet of inertia of both arms is the same. Also when the skater drops the weight, the moment of inertia of both arms is still the same. Thus, at any instant, the moment of inertia of the two arms is the same.

To change the angular speed, the initial and final moment of inertia of the two arms must be different. Thus, the skater doesn't succeed in changing his angular velocity.

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Answer:

Explanation:

The work of the brakes will equal the initial kinetic energy of the car

Fd = ½mv²

F = mv²/2d

F = 2457(18²) / (2(62))

F = 6,419.903...

F = 6.4 kN

The reason why a tiny 1.5 V cell can operate a calculator for a year, but would burn out in a few hours in a tiny robot is because the power demands of the calculator are way less than that of the tiny robot.

Cell capacity is measured by the amount of Amps and Amp Hour (A.H.) capacity for how long a battery can endure.

On the label or in the user's manual, batteries mention their reserve capability, which specifies the approximate amount of time they can operate between charges. You might notice a shorter or longer battery life if your circuit uses more or less power than this hypothetical circuit. Calculate the battery's entire capacity and divide it by the power of your circuit to see how long it can survive.

Load current, which is influenced by the power of the linked item, influences how quickly the battery's electrical capacity will be used up.

The reason the 1.5 V cell would operate the calculator for a year and yet die in a few hours with the robot is that the robot has a much higher load current than the calculator.

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Answer:

Explanation:

Let d be the distance to the center of mass from the front wheels

Sum moments about the front wheel contact point to zero

1240(9.8)[d] - 1240(9.8)(1 - 0.67)[3.2] = 0

1240(9.8)[d] = 1240(9.8)(1 - 0.67)[3.2]

                d = (1 - 0.67)[3.2]

                d = 1.056 m

Answer:

D.) the same.

They are traveling in the same vacuum so there is no resistance and no outside influences. They will travel at the same speed as each other will little to no variance in their speed.

Explanation:

hope this helps. . . <3

good luck!    uωu

Hi there!

Since the collision is elastic, we must also satisfy the following condition:

Ei = Ef, or:

KEi = KEf

Begin by writing an expression for momentum. (p = mv) Remember that one ball's direction is negative; in this instance, we can let the second ball be moving LEFT.

mv1 + mv2 = mvf1 + mvf2

0.220(1.84) + 0.220(-.530) = 0.220(vf1 + vf2)

0.2882/0.220 = vf1 + vf2

1.31 = vf1 + vf2

Now, we can express this as a conservation of energy:

1/2mv1² + 1/2mv2² = 1/2mvf1² + 1/2mvf2²

Plug in values and simplify:

0.403315 = 1/2m(vf1² + vf2²)

Simplify further:

3.6665 = vf1² + vf2²

Use the equation derived from momentum above and solve for one variable:

vf2 = 1.31 - vf1

Plug in this expression for vf2:

3.6665 = vf1² + (1.31 - vf1)²

Expand:

3.6665 = vf1² + 1.7161 - 2.62vf1 + vf1²

Simplify:

1.9504 = -2.62vf1 + 2vf1²

Solve for vf1 using a graphing calculator:

vf1 = -0.53 m/s or 1.84 m/s; we must figure out which one is correct.

Since v1 is heading to the right initially with a velocity of 1.84 m/s, we know that the ball's velocity could not have stayed the same in both magnitude and direction, so the final velocity must be -0.53 m/s.

Now, we can solve for the velocity of the other ball (initial of 0.53 m/s):

vf2 = 1.31 - (-0.53) = 1.84 m/s.

Now, you could have also made the connection that when two balls of the SAME MASS experience an ELASTIC collision, the velocities are simply "exchanged" from one to another. I just used this more "extensive" method to prove this.

Answer:

F = - K x for spring     (note that that F here is given in grams, F = m g is correct)

K here is 100 g / cm      for the spring constant

x = -420 g / 100 g/cm = -4.2 cm

The spring would compress 4.2 cm for a total length of 20 - 4.2 = 15.8

d)  to compress the spring 6.8 cm one can see that the load would be 680 g

[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]

Distance travelled by the truck is ~

And it's displacement is ~

[tex] \large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}[/tex]

See the diagram in attachment for reference ~

Let O be the initial point, It travels 60 km towards west till point B and then 80 km towards north till point P and returns to initial point O in a straight line, now as we can observe here, it forms a right angled Triangle.

The measure of two legs is 60 km and 80 km, let's find the hypotenuse ~

According to Pythagoras theorem ~

hypotenuse² = sum of squares of other two legs

that is ~

So, the distance between the point A and O is 100 km

Now, The total distance is equal to the distance covered through actual path that is ~

And displacement is the distance between the final point and initial point, but since the truck returns to the point from where it started the journey, so the final and initial point is same therefore displacement is equal to 0.

Answer: here you go i have to put 20 letters in so just ignore this and look at the link.

Answer:

Explanation:

An example of an intense aerobic activity would be running/ sprinting sprinting targets six specific muscle groups: hamstrings, quadriceps, glutes, hips, abdominals and calves. Sprinting is a total body workout featuring short, high-intensity repetitions and long, easy recoveries.

If the load is in the equilibrium, the magnitude of the tension in the cable is equal to 1,414.5 Newton.

Given the following data:

Scientific data:

To calculate the magnitude of the tension in the cable, if the load is in the equilibrium:

First of all, we would determine the tension caused by the horizontal component of the force:

[tex]\sum F_y ; Tcos\theta - mg=0\\\\Tcos\theta = mg\\\\T=\frac{mg}{cos\theta} \\\\T=\frac{250 \times 9.8}{cos30} \\\\T= \frac{2450}{0.8660}[/tex]

T = 2,829.1 Newton

The magnitude of the tension in the cable is given by:

[tex]\sum F_x ; F - Tsin\theta = 0\\\\F = Tsin\theta\\\\F = 2829.1sin30\\\\F = 2829.1 \times 0.5[/tex]

F = 1,414.5 Newton.

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dissimilar with respect to one or more particular characters

Answer:

Mark me as brainlist please.

Hi there!

With the work-energy theorem for oscillating springs:

ME = KE + PE

[tex]ME = \frac{1}{2}mv^2 + \frac{1}{2}kx^2[/tex]

Where:

m = mass (kg)

v = velocity (m/s)

k = Spring Constant (N/m)

x = displacement from equilibrium (m)

If the object is at the equilibrium position, there is NO potential energy since:

[tex]\frac{1}{2}k(0^2) = 0 J[/tex]

Thus:

[tex]ME = \frac{1}{2}mv^2[/tex]

Plug in the given values:

[tex]ME = \frac{1}{2}(0.50)(1.5^2) = \boxed{0.5625 \text{ J}}[/tex]

Answer:Climate change, emerging diseases, and increased exposure to ultraviolet radiation (due to ozone depletion) are all additional factors that could be contributing to falling amphibian populations. ... Instead, amphibians are disappearing thanks to a complex mixture of factors, including: Alien Specie

Explanation:

just look it up........

We have that for the Question "find (a) the mass of CCl4 per second that passes point A and (b) the concentration of CCl4 at point A."

Answers:

From the question we are told

The concentration of [tex]CCl_4[/tex] at the left end of the tube is maintained at 1.71 x 10-2 kg/m3, and the diffusion constant is 21.9 x 10-10 m2/s. The CCl4 enters the tube at a mass rate of 5.86 x 10-13 kg/s

A) the mass flow rate of CCI_4 as it passes point A is the same as the mass flow rate at which CCI_4 enters the left end of the tube

Therefore, the mass flow rate of CCI_4 at point A

=  [tex]5.86*10^{-13} kg/s[/tex]

B) From Fick's law

[tex]\deltaC = \frac{mL}{DAt}\\\\ Assume L = 5*10^{-3}, A = 3*10^{-4}\\\\\deltaC = \frac{5.86*10^{-13} * 5*10^{-3}}{21.9*10^{-10} * 3*10^{-4}}\\\\\deltaC = 4.46*10^{-3}kg/m^3[/tex]

Then,

[tex]Concentration = 1.71*10^{-2} - 4.46*10^{-3}\\\\= 12.6*10^{-3}kg/m^3[/tex]

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Answer:

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: [tex] \implies[/tex] The Photosynthesis is the process of capturing light energy and transforming it into chemical energy. Green plants and several other organisms use light energy and convert carbon dioxide and water into glucose. In this process, oxygen is produced as a by-product

→ We also who how it's process occur

Photosynthesis Equation

6CO2 + 6H2O = C6H12O6 + 6O2

Importance of Photosynthesis

Photosynthetic Pigments

The Factors Affecting Photosynthesis

Various factors influence/affect the photosynthesis process. These are:

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

Hope it's helps !!

Answer:Convex mirrors are used because these mirrors provide a wider viewing angle than a plane mirror. This wide angle will help you getting more information/overview than what is happening at a narrow spot right behind the car if you use a plane mirror.

With a convex mirror you are for example able to detect an overtake (by the car behind you) early, if you for some reason wanted to turn left into another lane at the same moment the overtake took place - so you then can prevent a collision. Convex mirrors are simply covering a much larger area behind the car than plane mirrors do. And in the US, on the mirrors there is a text explaining that the vehicle behind you is closer than it appears - some kind of an idiot explanation in case some driver took the mirror image literally….because in the mirror image of a convex mirror, everything looks smaller and further away than they actually are.

Explanation: mark me as brainliest this is my best answer till now

Answer:

I think the answer is (A)...

Hope this helps!

Answer:

The Aluminum

Explanation:

With a larger specific heat, water requires more heat to raise its temperature by a temperature degree.

In this system, with equal masses of water and aluminum, the heat moving from the aluminum lowering its temperature by one degree is not sufficient to raise the water temperature by one degree.

Answer:

According Lisa, both the ball and the balloon have the same forward velocity of Vx.

(D) is correct

The gravitational force acting between the two bodies is given by:

F=G

r

2

m

1

m

2

G=

m

1

m

2

Fr

2

The dimension of the force is [MLT

−2

]

=

[M][M]

[MLT

−2

][L

2

]

=M

−1

L

3

T

−2