Need help with the currents and resistances of these circuits.

Need Help With The Currents And Resistances Of These Circuits.

Answers

Answer 1

The currents and resistances of the circuits are

0.00143 A and 4.2KΩ0.0068 A and 1.76KΩ0.032 A and 0.28 KΩ0.0068 A and 1.33KΩ

Calculating the currents and resistances of the circuits.

Circuit 1

The resistors are in series

The total resistance of resistors in series can be calculated using the formula:

Rtotal = R1 + R2 + R3 + ...

So, we have

Rtotal = 2.2 + 1 + 1

Rtotal = 4.2KΩ

The current is calculated as

I = V/R

So, we have

I = 6V/4.2KΩ

I = 6V/4.2 * 1000 Ω

Evaluate

I = 0.00143 A

Circuit 2

The resistors are in parallel

The total resistance of resistors in parallel can be calculated using the formula:

1/Rtotal = 1/R1 + 1/R2 + 1/R3 + ...

So, we have

1/Rtotal = 1/1 + 1/2.2 + 1/3.3

Rtotal = 1.76KΩ

The current is calculated as

I = V/R

So, we have

I = 12V/1.76KΩ

I = 12V/1.76 * 1000 Ω

Evaluate

I = 0.0068 A

Circuit 3

The resistors are in parallel band in series

So, we have

R = 3.3 + 2.2

R = 5.5

Next, we have

Rtotal = 1/5.5 + 1/10

Rtotal = 0.28 KΩ

The current is calculated as

I = V/R

So, we have

I = 9V/0.28KΩ

Evaluate

I = 0.032 A

Circuit 4

The resistors are in parallel band in series

So, we have

R = 1/6.1 + 1/6.1

R = 2/6.1

Next, we have

Rtotal = 1 + 2/6.1

Rtotal = 1.33KΩ

The current is calculated as

I = V/R

So, we have

I = 9V/1.33KΩ

Evaluate

I = 0.0068 A

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Related Questions

For a thrust of 130,000 N and a thrust time of 100 S, what is the rockets mass that makes the rocket reach 220 KM

Answers

The rocket mass that would make a rocket with a thrust of 130,000 N reach 220 Km would be 2,954.55 kg.

How to find the rocket mass ?

To solve this problem, we need to apply the basic equations of motion. We will assume that the only force acting on the rocket is the thrust force, and we will ignore the effects of air resistance and gravity.

Calculate acceleration (a) using thrust (F) and mass (m):

Given the thrust F = 130,000 N, we have:

a = 130,000 / m

Apply the equation of motion:

Given y = 220,000 m (220 km), y0 = 0 m (initial position), v0 = 0 m/s (initial velocity), and t = 100 s, we can write the equation as:

220,000 = 0 + 0 * 100 + 0.5 * (130,000 / m) * (100)^2

Solve for mass (m):

220,000 = 0.5 * (130,000 / m) * 10,000

440,000 = 130,000 * 10,000 / m

m = 130,000 * 10,000 / 440,000

m = 2, 954.55 kg

In conclusion, the mass of the rocket that makes it reach 220 km with a thrust of 130,000 N and a thrust time of 100 s is approximately 2, 954.55 kg.

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U-Haul takes precautions to provide a safe and secure storage environment; however, the following are examples of events outside of our control.

Answers

U-Haul takes precautions to provide a safe and secure storage environment; however, events like natural disasters (such as floods, fire, hurricanes, or earthquakes), criminal activity (such as theft or vandalism), are example of events outside our their control.

What should you know about  U-Haul?

The American moving truck, trailer, and self-storage rental company U-Haul has its headquarters in Phoenix, Arizona, and has been around since 1945.

Leonard Shoen and Anna Mary Carty Shoen founded the company in Ridgefield, Washington.

The business was initially established in the garage owned by his wife's family, and it was later expanded through gas station franchising.

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Hello can Someone PLEASE HELP ME with this
Pascal’s Law
1. Are fluids only liquids, only gases, or both?
2. Hydraulics involve pushing/pulling ?
3. Pneumatics involve pushing/pulling ?
4. How can water make your car go up and down?
5. Does increased pressure in the pneumatic tube make the chair go up or down?
6. Holding down the pump lets air out, which decreases pressure, making the chair do what?
7. What happens when you push all the water from a little syringe into a big syringe? Does the big syringe pop out the same distance as the little syringe was pushed in? Why or why not?
8. Should the car move up as far as the thinner “small force” moves down? Why or why not? _
9. The pressure under piston 1 is ___________________ the pressure under piston ?

Answers

Answer:

1. Fluids can be both liquids and gases.

2. Hydraulics involve pushing.

3. Pneumatics involve pulling.

4. Water can be used in hydraulic systems to lift and lower a car using a hydraulic lift. The water is pumped into a hydraulic cylinder which then pushes a piston up to lift the car.

5. Increased pressure in the pneumatic tube makes the chair go up.

6. Holding down the pump lets air out, which decreases pressure, making the chair go down.

7. When you push all the water from a little syringe into a big syringe, the big syringe does not pop out the same distance as the little syringe was pushed in. This is because the pressure under the larger piston is less than the pressure under the smaller piston due to the difference in the size of the pistons.

8. Yes, the car should move up as far as the thinner "small force" moves down according to Pascal's Law, which states that pressure applied to a confined fluid is transmitted equally in all directions and acts with equal force on equal areas.

9. The pressure under piston 1 is equal to the pressure under piston 2 according to Pascal's Law.

how terminal has a bulb​

Answers

Answer:

I think your question is :-

Explanation:

● How many terminal has a bulb??

=>Bulb has two terminals:--

◆ To connect the filament with the terminals of a cell.

◆A battery so that the current can pass through the filament.

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