The final balanced chemical equation is:
C₉H₂₀(l) + 14O₂(g) → 9CO₂(g) + 10H₂O(l)
What is a balanced chemical equation?A balanced chemical equation is a representation of a chemical reaction using chemical formulas and coefficients to show the reactants and products involved in the reaction.
To balance a chemical equation, coefficients are placed in front of the chemical formulas to ensure that the number of atoms of each element is equal on both sides of the equation. This results in a balanced equation that accurately represents the reactants and products involved in the reaction, and their relative amounts.
To balance the chemical equation, we need to make sure that the number of atoms of each element is the same on both sides of the equation.
Let's start by counting the number of atoms of each element in the reactants and products:
Reactants:
C₉H₂₀(l) → 9 carbon atoms (C), 20 hydrogen atoms (H)
O₂(g) → 2 oxygen atoms (O) per molecule, so 14 O₂ molecules give 28 oxygen atoms (O)
Products:
9CO₂(g) → 9 carbon atoms (C), 18 oxygen atoms (O)
10H₂O(l) → 20 hydrogen atoms (H), 10 oxygen atoms (O)
Now, we can see that the number of carbon and hydrogen atoms are already balanced, but we need to balance the oxygen atoms.
To do so, we can see that 14 O₂ molecules give us 28 oxygen atoms, which means we need 28/2 = 14 molecules of CO₂ and 14 molecules of H₂O to balance the equation.
The final balanced equation is:
C₉H₂₀(l) + 14O₂(g) → 9CO₂(g) + 10H₂O(l)
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Based on the amounts of starting materials used, a cheimst calculates a possible yield of 216.4 g in a reaction. However, after isolating her purified product, she finds that she has only 199.6 g of products. What is her percent yield for this reaction?
The chemist's percent yield for this reaction is approximately 92.27%.
What is percent yield?The percent yield for a chemical reaction is the ratio of the actual yield to the theoretical yield, expressed as a percentage. The theoretical yield is the amount of product that is expected to be obtained based on the stoichiometry of the reaction and the amounts of starting materials used. The actual yield is the amount of product that is actually obtained after the reaction is carried out and the product is purified.
Equation:To calculate the percent yield, we can use the formula:
Percent yield = (actual yield / theoretical yield) x 100%
In this case, the chemist calculated a theoretical yield of 216.4 g based on the amounts of starting materials used. However, she obtained an actual yield of 199.6 g after isolating and purifying the product.
So we can substitute these values into the formula and solve for the percent yield:
Percent yield = (199.6 g / 216.4 g) x 100%
Percent yield = 0.9227 x 100%
Percent yield = 92.27%
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to lower the impacts of climate change we can do the following activities
1
2
3
4
5
science:
Answer:
To lower the impacts of climate change, we can undertake the following activities:
Invest in low-carbon technologies: Utilize renewable energy sources such as solar panels, tidal energy, wind, wave, and geothermal power to reduce greenhouse gas emissions and minimize our reliance on fossil fuels.
Improve transportation: Opt for fuel-efficient cars, electric vehicles, and better public transport systems to reduce CO2 emissions and pollution.
Adopt sustainable diets: Shift towards plant-based diets, reduce meat and dairy consumption, and support sustainable farming practices to help mitigate climate change.
Restore nature: Plant trees, engage in rewilding schemes, and protect forests and oceans to increase their natural ability to absorb carbon dioxide.
Reduce consumption and waste: Minimize consumption of energy-intensive products, reduce plastic use, and adopt energy-efficient practices in homes, such as insulating walls and roofs and using heat pumps.
help please please. need.
The 37.2g of water must be heated from -15C to 135C using 23,447.04 joules of energy.
What alters heat and why?Heat transfer between two things is a result of their different masses. Heat transfer between two things is a result of their different densities. Heat transfer is a result of the temperature difference between two systems. Heat transmission between two objects is a result of pressure differences.
For calculating the heat:
Q = m × c × ΔT
Where:
Q = amount of heat (in joules)
m = mass of the substance (in grams)
c = specific heat capacity of the substance (in J/g·°C)
ΔT = change in temperature (in °C)
The specific heat capacity of water is approximately 4.184 J/g·°C.
Now, we have to calculate the change in temperature:
ΔT = final temperature - initial temperature
ΔT = 135⁰C - (-15⁰C)
ΔT = 150⁰C
Now, we can substitute the values,
Q = 37.2g × 4.184 J/g·°C × 150⁰C
Q = 23,447.04 J
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name the process which takes place when a red litmus paper turns white when dropped into chlorine water
Explanation:
The process is called bleaching. Chlorine gas (Cl2) reacts with water to form hypochlorous acid (HOCl) and hydrochloric acid (HCl). Hypochlorous acid acts as a powerful oxidizing agent and removes electrons from the red litmus paper, causing it to turn white.
A solution is made from 19.10 g of an unknown solute in 500. grams of water. The solution has a concentration of 0.400 m. What is the molar mass of the solute?
Answer:
95.5 g/mol
Explanation:
To find the molar mass of the solute, we need to first calculate the number of moles of the solute in the solution.
Number of moles of solute = concentration x volume
We are given the concentration (0.400 m) and the volume (500 grams) of the solution, but we need to convert the mass of water to volume. We can do this using the density of water:
Density of water = 1 g/mL
Volume of water = mass of water / density of water = 500 g / 1 g/mL = 500 mL
Now we can calculate the number of moles of solute:
Number of moles of solute = 0.400 m x 500 mL = 200 mmol
Next, we need to find the mass of the solute:
Mass of solute = number of moles x molar mass
We are given the number of moles (200 mmol), so we can rearrange the equation to solve for the molar mass:
Molar mass = mass of solute / number of moles
Molar mass = 19.10 g / 200 mmol = 95.5 g/mol
Therefore, the molar mass of the solute is 95.5 g/mol.
Hopes this helps
If a student weighs out 0.600 g of potassium hydrogen phthalate (MW 204.22 g/mol) and titrates it with sodium hydroxide solution, what is the molarity of the sodium hydroxide solution if it takes 32.21 mL of it to titrate the potassium hydrogen phthalate?
Hint: one mole of hydrogen phthalate reacts with one mole of sodium hydroxide.
The molarity of the sodium hydroxide solution is 0.09111 M.
What is Molarity?
Molarity is a measure of the concentration of a solution. It is defined as the number of moles of solute dissolved in one liter of solution.
Molarity is an important concept in chemistry because it allows us to quantify the amount of solute in a solution and to make predictions about the behavior of the solution in various chemical reactions.
First, we can calculate the number of moles of potassium hydrogen phthalate using its molecular weight:
moles of KHP = mass / molecular weight
moles of KHP = 0.600 g / 204.22 g/mol
moles of KHP = 0.002938 mol
Since one mole of KHP reacts with one mole of NaOH, we know that there are also 0.002938 moles of NaOH in the titrated solution. We can calculate the molarity of the NaOH solution using the formula:
molarity = moles of solute / volume of solution (in liters)
First, we need to convert the volume of the NaOH solution from milliliters to liters:
volume of NaOH solution = 32.21 mL = 0.03221 L
Now we can calculate the molarity of the NaOH solution:
molarity = 0.002938 mol / 0.03221 L
molarity = 0.09111 M
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CAN SOMEONE HELP WITH THIS QUESTION?✨
The molarity of the sodium hydroxide solution is 0.0911 M.
We must figure out how many molecules of potassium hydrogen phthalate there are.
moles of KHP = mass / molar mass = 0.600 g / 204.22 g/mol = 0.00294 mol
We know that 0.00294 moles of NaOH were used in the titration because one mole of KHP interacts with one mole of NaOH. This data can be used to determine the molarity of the NaOH solution:
molarity of NaOH = moles of NaOH / volume of NaOH used in liters
volume of NaOH = 32.21 mL = 0.03221 L
calculation of the molarity of NaOH:
molarity of NaOH = 0.00294 mol / 0.03221 L = 0.0911 M
The molarity of the sodium hydroxide solution is 0.0911 M.
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Calculate the heat gained by the cold liquid
To calculate the heat gained by the cold liquid, we need to use the formula: q = m * c * ΔT
where q is the heat gained or lost by the substance, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature of the substance.
Let's assume that we have a cold liquid with a mass of 100 grams and an initial temperature of 10°C. We then add 50 grams of a hot solid that has been heated to 80°C. After the solid and liquid are allowed to equilibrate, the final temperature of the mixture is 20°C.
We can first calculate the heat lost by the hot solid using the same formula:
q = m * c * ΔT
q = 50 g * 0.385 J/g°C * (80°C - 20°C)
q = 15400 J
The negative sign indicates that the solid lost heat to the colder liquid.
To calculate the heat gained by the cold liquid, we can use the same formula and the final temperature of the mixture:
q = m * c * ΔT
q = 100 g * 4.184 J/g°C * (20°C - 10°C)
q = 4184 J
Therefore, the heat gained by the cold liquid is 4184 J.
The complete question is :
Use the equation qliquid = m × c × ΔT to calculate the heat gained by the cold liquid. Use the specific heat for the liquid you selected.
Use the equation qwater = m × c × ΔT to calculate the heat lost by the hot water. Show your work using the problem-solving method shown in previous rubrics.
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Enthalpy Lab + Questions NEED HELP ASAP FOR THE ANALYSIS QUESTIONS (be sure to show your work) + CONCLUSION
PURPOSE OF EXPERIMENT: To find Heat of Solution of sodium hydroxide and to find the heat of neutralization between sodium hydroxide and hydrochloric acid.
Experiment 1 Procedure:
1. Measure 50.0 mL of water (tap) into a 100 mL graduated cylinder and pour it into a large coffee cup.
2. Determine the temperature of this water
3. Measure out 2.00 g of sodium hydroxide into a piece of paper towel *tare scale!
4. Add the sodium hydroxide to the water in the coffee cup and put a small cup over it, with the thermometer through the hole. Stir GENTLY with the thermometer and record the temperature every 30 seconds for 3 minutes or until it peaks. Record this in a properly labelled table.
5. Let this stand for 45 minutes before proceeding to Exp. 2.
WHAT WE FOUND IN EXP 1:
T (temp.) initial = 20 degrees C
T (temp) FINAL = 28.5 degrees C
moles of sodium hydroxide = 0.0518mol
the molar mass of sodium hydroxide = 39.969g/mol
C (specific heat of water) = 4.184J/g degrees C
THE NUMBER OF TRIALS FOR TEMP IN EXP 1
1st trial = 21 C
2nd trial = 24.5 C
3rd trial = 26 C
4th trial = 26 C
5th trial = 28 C
6th trial = 28.5 C
7th trial = 28.5 C (final temp)
ANALYSIS FOR EXPERIMENT ONE:
1. Determine the moles of sodium hydroxide (NaOH) from the experiment.
2. Determine Qsurroundings and Qrxn
3. Determine the enthalpy for the dissociation of sodium hydroxide (delta H sol)
4. Write the thermochemical equation for the dissociation of sodium hydroxide TWO ways and write an enthalpy diagram
5. What assumptions did you make to calculate #2? (some example assumptions to make: assume that the solution is water and that heat and density COULD be the same as water, etc)
6. Research the actual value and determine the percent error
7. In terms of bonds breaking and forming, what is RESPONSIBLE FOR ENTHALPY CHANGE?
EXPERIMENT 2 PROCEDURE:
1. Measure out 50.0 mL of 0.75 concentration M HCl into a graduated cylinder
2. Measure and record the temperature of the sodium hydroxide solution from exp. 1.
3. Add the hydrochloric acid solution to the sodium hydroxide solution, put the small cup on, and record the temperature change every 15 seconds for 1 minute. Stir GENTLY. Record this in a properly labelled table (will be given below)
4. Solutions can be discarded down the sink.
WHAT WE FOUND IN EXP. 2:
T (temp) initial = 23.5 C
T (temp) FINAL = 27 C
THE NUMBER OF TRIALS FOR TEMP IN EXP 2
1st trial = 27 C
2nd trial = 27 C
3rd trial = 27 C
4th trial = 27 C (FINAL TEMP)
ANALYSIS FOR EXPERIMENT 2:
1. Determine the moles of HCl added to this mixture
2. Write the chemical equation for this reaction
3. Determine the limiting reagent
4. Determine the Qsurr and Qrxn *CONVERT TO kJ*
5. Determine the enthalpy for the neutralization reaction.
6. Write the thermochemical equation for the dissociation of sodium hydroxide TWO WAYS and write an enthalpy diagram
7. Research the actual value and determine the percent error.
8 Explain sources of experimental error for both experiments and BE SPECIFIC! (NOT CALCULATION ERRORS, SPILLING, OR LOSING REACTANTS - DO NOT COUNT AS ERRORS! They can be EXPERIMENTAL due to heat loss/gain, room temp *specific heat capacity is for 25 C*, and atmospheric pressure is constant. And they can be MEASUREMENTS - consider the precision and the potential range of error for each measurement)
9. In terms of bonds breaking and forming, what's responsible for the enthalpy change?
CONCLUSION: write a brief statement that refers to the purpose.
The difference between the energy needed to break the bonds in the reactants and the energy released when new bonds are created in the products is what essentially determines the enthalpy change.
What impact does bond breaking have on enthalpy?In general, a bond must be broken by a positive change in enthalpy, whereas a bond must be formed by a negative change in enthalpy. In other words, the process of breaking a bond is endothermic, whereas the process of forming a bond is exothermic.
What is the bond-breaking and bond-forming reaction's enthalpy change?The energy needed to break the links between the reactants less the energy released during the formation of new bonds in the products is the enthalpy of reaction.
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In terms of bonds breaking and forming, what's responsible for the enthalpy change?
Calculate the buffer capacity for OH- of the buffer composed of 1.0 L of 1.0 M CH3COOH / 0.575 M NaCH3COO. (Change in pH = 4.52)
The buffer capacity for OH- is equal to the concentration of OH- added, which is [tex]1.87 × 10^-9[/tex] M.
The buffer capacity for OH- is given by the Henderson-Hasselbalch equation:
pH = pKa + log([A-]/[HA])
where pH is the desired pH change, pKa is the dissociation constant of the acid, [A-] is the concentration of the conjugate base, and [HA] is the concentration of the acid.
Rearranging the equation, we get:
[A-]/[HA] = [tex]10^(pH - pKa)[/tex]
In this case, CH3COOH is the acid, and NaCH3COO is its conjugate base. The dissociation constant of acetic acid (CH₃COOH) is 4.76. We can calculate the concentrations of CH₃COOH and NaCH₃COO as follows:
[CH₃COOH] = 1.0 M
[NaCH₃COO] = 0.575 M
To calculate the buffer capacity for OH-, we first need to find the pH of the buffer before adding OH-. We can use the Henderson-Hasselbalch equation to do this:
pH = pKa + log([A-]/[HA])
pH = 4.76 + log(0.575/1.0)
pH = 4.19
Now, if we add OH- to the buffer, it will react with CH₃COOH to form CH₃COO-, according to the following balanced equation:
CH₃COOH + OH- → CH₃COO- + H₂O
The concentration of OH- added to the buffer can be calculated using the pH change:
pH = 4.19 + 4.52 = 8.71
[OH-] = 10^-(pH) = 1.87 × [tex]10^-9[/tex]M
The change in concentration of CH3COOH and CH3COO- due to the addition of OH- can be calculated using stoichiometry:
Δ[CH₃COOH] = -[OH-]
Δ[CH₃COO-] = [OH-]
Therefore, the new concentrations of CH₃COOH and CH₃COO- after adding OH- are:
[CH₃COOH] = 1.0 - [OH-] = 1.0 - 1.87 ×[tex]10^-9[/tex] = 1.0 M
[CH₃COO-] = [NaCH₃COO] + [OH-] = 0.575 + 1.87 × [tex]10^-9[/tex] = 0.575 M
Using the Henderson-Hasselbalch equation, we can calculate the new pH of the buffer:
pH = pKa + log([A-]/[HA])
pH = 4.76 + log(0.575/1.0)
pH = 4.19
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A solution is prepared by dissolving 396 g of sucrose (C12H22O11) in 604 g of water. What is the vapor pressure of this solution at 30°C? (The vapor pressure of water is 31.8 mmHg at 30°C.)
The vapor pressure of the solution at 30°C is 0.9676781. The pressure that a vapor exerts on its condensed phases (solid or liquid) in a closed system at a specific temperature is known as vapor pressure.
The pressure of the solvent above the solution is known as the vapour pressure of a solution. Temperature, ambient pressure, and solute concentration all have an impact on a solution's vapour pressure. A manometer or a barometer can be used to determine a solution's vapour pressure. When a liquid is contained in a closed container, its molecules frequently crash into the walls of the container. Due to these collisions, the container's walls experience pressure equal to the liquid's vapour pressure.
Solution of P = (0.9677 x 31.8 mmHg)
P solution = 30.8 mmHg
X Solvent = 34.63588 mol/1.156 + 34.635
X Solvent = 0.9676781
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For the reaction below, which change would cause this endothermic reaction in equilibrium to shift left?
CH4 + 2H₂S → CS2(g) + 4H₂(g)
B
(a) Increase the concentration of dihydrogen monosulfide
(b) Decrease the pressure on the system
(c) Decrease the temperature of the system
(d) Decrease the concentration of carbon disulfide
(e) Increase the concentration of methane
An endothermic reaction absorbs heat from the surroundings, so heat is a reactant in this case. According to Le Chatelier's principle, when a system in equilibrium is subjected to a change, it will adjust to counteract that change and maintain equilibrium.
What is Endothermic Reaction?
An endothermic reaction is a chemical reaction that absorbs heat from its surroundings. In other words, the reaction requires energy in the form of heat to proceed, and the energy is absorbed from the surrounding environment, making it feel colder. Endothermic reactions usually have a positive enthalpy change, which means that the products have more energy than the reactants.
To shift the equilibrium of an endothermic reaction to the left, we need to remove heat, which can be achieved by decreasing the temperature. Therefore, the correct answer is (c) Decrease the temperature of the system.
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An element exists as 4 different isotopes. 4.35% have a mass of 49.9461 amu, 83.79% have a mass of 51.9405 amu, 9.50% have a mass of 52.9407 amu, and 2.36% have a mass of 53.9389 amu. a. What is the average atomic mass of this element? b. What is the identity of this element? Show calculations to receive full credit.
Answer:
Explanation:
Average Atomic Mass
In order to find the identity of the element, we must first find the average mass of all isotopes.
To do this, we multiply each mass by its percent abundance and add them together.
[tex](0.0435*49.9461)+(0.8379*51.9405)+(0.0950*52.9407)+(0.0236*53.9389)=51.9959[/tex]
51.9959 is the calculated average of the mass of each isotope.
Identity
Looking at a periodic table, this value for atomic mass most closely resembles the atomic mass of Chromium, which is 51.9961
Suppose hydroxide ion, OH–, is the only anion contributing to the alkalinity of the sample. How will the “P” and “T” alkalinity values compare?
In comparison to the "P" alkalinity, the "T" alkalinity will be higher.
The "P" alkalinity of a sample is determined by the amount of hydrogen ions ([tex]H^+[/tex]) that are neutralized by the anions present. The "T" alkalinity of a sample is determined by the amount of hydroxide ions ([tex]OH^-[/tex]) that are neutralized by the cations present. In a sample where the only anion contributing to alkalinity is hydroxide ion, [tex]OH^-[/tex], the "P" alkalinity will be zero since there are no hydrogen ions ([tex]H^+[/tex]) to be neutralized. However, the "T" alkalinity will be equal to the amount of hydroxide ions ([tex]OH^-[/tex]) present since all of the [tex]OH^-[/tex] ions will be neutralized by the cations present. Therefore, in this case, the "T" alkalinity will be greater than the "P" alkalinity.
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WORTH 50 POINTS, ANSWER ALL PARTS
For each of the following gemstones, determine the mass of compound present in the given moles of each compound.
PART A. The chemical formula for ruby is Al₂O₃. What is the mass in grams of ruby that are in 0.0924 moles?
PART B. The chemical formula for emerald is Be₃Al₂(SiO₃)₆. What is the mass in grams of emerald that are in 0.0165 moles?
PART C. The chemical formula for garnet is MgAl₂(SiO₄)₃. What is the mass in grams of garnet that are in 0.0380 moles?
Answer:
0.0924 mol Al₂O₃ = 9.42 g
0.0165 mol Be₃Al₂(SiO₃)₆ = 8.87 g
0.0380 mol MgAl₂(SiO₄)₃ = 13.5 g
Explanation:
mass = number of moles * molar mass
(PART A) The molar mass of Al₂O₃ is 101.96 g/mol. To find the mass in grams of Al₂O₃ that are in 0.0924 moles:
0.0924 mol * 101.96 g/mol = 9.42 g
(PART B) The molar mass of Be₃Al₂(SiO₃)₆ is 537.51 g/mol. To calculate the mass in grams of 0.0165 moles of Be₃Al₂(SiO₃)₆:
0.0165 mol * 537.51 g/mol = 8.87 g
(PART C) The molar mass of MgAl₂(SiO₄)₃ is 354.52 g/mol. To calculate the mass in grams of 0.0380 moles of MgAl₂(SiO₄)₃:
0.0380 mol * 354.52 g/mol = 13.5 g
The mass of ruby in grams is 9.43 g.
The mass of emerald in grams is 8.87 g.
The mass of garnet in grams is 16.56 g.
To calculate the mass of a compound in grams, we need to know the molar mass of the compound, which is the sum of the atomic masses of all the atoms in the formula. Once we know the molar mass, we can use the formula:
mass in grams = number of moles x molar mass
where the number of moles is given and the molar mass is calculated from the formula. In each case, we plug in the numbers and perform the calculation to obtain the mass in grams.
PART A: molar mass of Al₂O₃ is 101.96 g/mol (2 x 26.98 g/mol for Al and 3 x 16.00 g/mol for O).
As a result, the ruby mass in grammes is:
0.0924 moles x 101.96 g/mol = 9.43 g
PART B: The molar mass of Be₃Al₂(SiO₃)₆ is 537.54 g/mol (3 x 9.01 g/mol for Be, 2 x 26.98 g/mol for Al, 6 x 28.09 g/mol for SiO₃).
Therefore, The mass of an emerald in gram is :
0.0165 moles x 537.54 g/mol = 8.87 g
PART C: The molar mass of MgAl₂(SiO₄)₃ is 435.52 g/mol (1 x 24.31 g/mol for Mg, 2 x 26.98 g/mol for Al, 3 x 60.08 g/mol for SiO₄).
Therefore, the garnet mass in grams is :
0.0380 moles x 435.52 g/mol = 16.56 g
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forgot how to solve this
The value of the equilibrium constant, Kc is 0.33.
The correct option is A.
What is the value of the equilibrium constant, Kc?The balanced chemical equation for the oxidation of NO by O2 is:
2 NO (g) + O2 (g) → 2 NO2 (g)
From the stoichiometry of the equation, we see that the mole ratio of NO to O2 consumed is 2:1. Therefore, if 3 moles of O2 are present at equilibrium, then 1.5 moles of NO have been consumed:
1.5 moles NO = 15.0 moles NO (initial) - 3.0 moles NO2 - 3.0 moles O2
Using the law of mass action, we can express the equilibrium constant (Kc) for the reaction as:
Ke = ([NO2]^2 / [NO]^2 [O2])
We know that at equilibrium, [O2] = 3.0 moles / 1.0 L = 3.0 M. To calculate [NO2], we need to use the stoichiometry of the equation and the fact that 1.5 moles of NO are consumed at equilibrium:
2 mol NO → 2 mol NO2
1.5 mol NO → 1.5 mol NO2
Therefore, [NO2] = 1.5 mol NO2 / 1.0 L = 1.5 M. Substituting the values into the equilibrium constant expression, we get:
Ke = ([NO2]^2 / [NO]^2 [O2])
Ke = (1.5 M)^2 / (1.5 M)^2 (3.0 M)
Ke = 0.333
Therefore, the answer is (a) 0.33.
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Calculate the volume of oxygen produced in the decomposition of 5 moles of KCIO3 at STP?
The volume of oxygen produced in the decomposition of 5 moles of KCIO3 at STP is 168 L. The balanced chemical equation for the decomposition of KCIO3 is:
2KClO3(s) → 2KCl(s) + 3O2(g)
From the equation, we can see that for every 2 moles of KCIO3, 3 moles of O2 are produced. Therefore, for 5 moles of KCIO3, the number of moles of O2 produced can be calculated as follows:
5 moles KCIO3 x (3 moles O2/2 moles KCIO3) = 7.5 moles O2
Since the conditions are given as STP (standard temperature and pressure), we can use the molar volume of a gas at STP (22.4 L/mol) to calculate the volume of O2 produced:
7.5 moles O2 x 22.4 L/mol = 168 L O2
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The rate law for the reaction: A + B → D has been found to be: rate = (397 mol-2 L2 s-1) [ A]2[ B]. What is the rate of the reaction if the concentration of A is 0.0615 mol L-1 and the concentration of B is 0.583 mol L-1?
The rate of a chemical reaction can be calculated using its rate law and the concentrations of its reactants. The rate of reaction is 7.64 x 10⁻⁵ mol L⁻¹ s⁻¹.
The rate law for the given reaction is given as:
rate = (397 mol⁻² L² s¹) [A]²[B]
where [A] and [B] are the concentrations of reactants A and B, respectively.
We are given the concentrations of A and B as 0.0615 mol L⁻¹ and 0.583 mol L⁻¹, respectively. We can substitute these values into the rate law and solve for the rate of the reaction:
rate = (397 mol⁻² L² s¹) (0.0615 mol L⁻¹)² (0.583 mol L⁻¹)
rate = 7.64 x 10⁻⁵ mol L⁻¹ s⁻¹
Therefore, the rate of the reaction is 7.64 x 10⁻⁵ mol L⁻¹ s⁻¹.
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You are measuring the Kc for the reaction: A (g)
⇔
B (g) + C (g)
A 2.00 mol sample of A is sealed in a 1.00 L flask and allowed to reach equilibrium with B and C. The equilibrium concentration of B is found to be 0.39 M. What is the numerical value of Kc for this reaction?
The numerical value of Kc for this reaction is 0.0804 if a 2.00 mol sample of A is sealed in a 1.00 L flask and allowed to reach equilibrium with B and C. The equilibrium concentration of B is found to be 0.39 M.
The equilibrium constant expression for the reaction A (g) ⇔ B (g) + C (g) is:
Kc = [B] [C] / [A]
where [A], [B], and [C] are the molar concentrations of A, B, and C at equilibrium, respectively.
We are given that the equilibrium concentration of B is 0.39 M. However, we are not given the equilibrium concentration of A or C. To solve for Kc, we need to find the equilibrium concentrations of all three species.
Since the reaction is in a 1.00 L flask and we started with a 2.00 mol sample of A, the initial concentration of A is 2.00 M. At equilibrium, the concentration of A will be equal to (2.00 - [B]) M, and the concentration of C will also be equal to [B] M (because the stoichiometric coefficients for B and C are equal).
Substituting these values into the equilibrium constant expression, we get:
Kc = (0.39 M)^2 / (2.00 M - 0.39 M) = 0.0804
Therefore, the numerical value of Kc for this reaction is 0.0804.
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Carbon tetrachloride (CCI4) was prepared by reacting 125 g of carbon disulfide and 125 g of chlorine. Calculate the percent yield if 60.4 g of CCI4 were obtained from the reaction CS2 + 3 Cl2 ➡️CCI4 + S2Cl2
Answer:
The balanced chemical equation for the reaction is:
CS2 + 3 Cl2 ➡️ CCl4 + S2Cl2
According to the equation, one mole of CS2 reacts with three moles of Cl2 to produce one mole of CCl4. The molar mass of CS2 is 76.14 g/mol, and the molar mass of CCl4 is 153.82 g/mol.
Theoretical yield of CCl4:
125 g CS2 × (1 mol CS2/76.14 g) × (1 mol CCl4/1 mol CS2) × (153.82 g CCl4/1 mol CCl4) = 318.3 g CCl4
This means that 318.3 g of CCl4 should have been produced according to the balanced equation.
Actual yield of CCl4 = 60.4 g
Percent yield = (actual yield / theoretical yield) × 100%
Percent yield = (60.4 g / 318.3 g) × 100%
Percent yield = 19%
Therefore, the percent yield of CCl4 is 19%.
Please help high to lowest
The order of the arrangement of the wavelengths from strongest to weakest is;
447 > 492 > 588 > 668
What is the wavelength?The wavelength is a fundamental property of a wave and is related to its frequency and speed through the equation:
wavelength = speed of light / frequency
where the speed of light is approximately 299,792,458 meters per second (m/s) and the frequency is measured in Hertz (Hz), which represents the number of cycles per second.
The wavelength is an important concept in many areas of physics, including optics, acoustics, and electromagnetic radiation.
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Will give 80 points pls help i need good grade plss need it fast
Introduction: The formation of the solar system has been a subject of scientific inquiry for centuries. One of the most significant forces at play in the formation of the solar system is the law of universal gravitation.
This law states that every object in the universe attracts every other object with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between them. In this virtual lab, we will investigate the law of universal gravitation by manipulating the size of the star and the positions of planets within Solar System X.
How to explain the informationHypothesis:
As the size of the star in Solar System X increases, the gravitational force experienced by the planets will increase, causing them to move closer to the star. Additionally, as the distance between the planets and the star decreases, the gravitational force experienced by the planets will also increase, causing them to move faster around the star.
Materials
Computer with internet connection
Virtual lab software
Solar System X simulation
Procedure:
Open the virtual lab software and access the Solar System X simulation.
Set the size of the star to the smallest setting and record the positions of the planets.
Increase the size of the star to the next setting and record the new positions of the planets.
Repeat step 3 until the largest size of the star is reached.
Analyze the data and record observations.
Results:
As the size of the star in Solar System X increased, the gravitational force experienced by the planets also increased. This caused the planets to move closer to the star and move faster around it. Additionally, as the distance between the planets and the star decreased, the gravitational force experienced by the planets also increased, causing them to move faster around the star. These observations support the hypothesis that the law of universal gravitation plays a significant role in the formation and movement of planets in a solar system.
Conclusion:
The law of universal gravitation is a fundamental force that plays a significant role in the formation and movement of planets in a solar system. This virtual lab demonstrated the effects of manipulating the size of the star and the positions of planets within Solar System X on the gravitational force experienced by the planets. The results of the experiment supported the hypothesis that increasing the size of the star and decreasing the distance between the planets and the star increased the gravitational force experienced by the planets, causing them to move faster and closer to the star. These observations provide valuable insight into the forces at play in the formation and movement of our own solar system and those found throughout the universe.
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What is the [NaNO3] (in mole/liter) of a solution made by mixing 2.00 grams of solid sodium nitrate with enough water to make a total volume of 50.0 mL?
Answer:
the concentration of sodium nitrate in the solution is 0.470 M.
Explanation:
To calculate the concentration of sodium nitrate in the solution, we need to first convert the mass of solid sodium nitrate to moles. We can do this using the molar mass of NaNO3, which is 85.0 g/mol:
moles NaNO3 = mass NaNO3 / molar mass NaNO3
moles NaNO3 = 2.00 g / 85.0 g/mol
moles NaNO3 = 0.0235 mol
Next, we need to calculate the total volume of the solution in liters, since concentration is usually expressed in moles per liter (M):
volume solution = 50.0 mL / 1000 mL/L
volume solution = 0.0500 L
Finally, we can use the moles of sodium nitrate and the total volume of the solution to calculate the concentration in moles per liter:
[NaNO3] = moles NaNO3 / volume solution
[NaNO3] = 0.0235 mol / 0.0500 L
[NaNO3] = 0.470 M
Therefore, the concentration of sodium nitrate in the solution is 0.470 M.
Determine the minimum concentration of the precipitating agent on the right to cause precipitation of the cation from the solution on the left.
a. 9.0x10^-2 M CaI2 ; K2SO4
b. 2.0x10^-3 M AgNO3 ; RbCl
Answer:
a. The chemical equation for the reaction between CaI2 and K2SO4 is:
CaI2 + K2SO4 → 2 KI + CaSO4
The solubility product constant (Ksp) for CaSO4 is 2.4 x 10^-5 at 25°C.
Using the Ksp expression for CaSO4, we can write:
Ksp = [Ca2+][SO42-]
Let x be the concentration of Ca2+ ions in the solution. Then, the concentration of SO42- ions will also be x, since the reaction is 1:1. Substituting into the Ksp expression, we get:
Ksp = x^2
Solving for x, we get:
x = sqrt(Ksp) = sqrt(2.4 x 10^-5) = 0.0049 M
Therefore, the minimum concentration of CaI2 needed to cause precipitation is 0.0049 M.
b. The chemical equation for the reaction between AgNO3 and RbCl is:
AgNO3 + RbCl → AgCl + RbNO3
The solubility product constant (Ksp) for AgCl is 1.8 x 10^-10 at 25°C.
Using the Ksp expression for AgCl, we can write:
Ksp = [Ag+][Cl-]
Let x be the concentration of Ag+ ions in the solution. Then, the concentration of Cl- ions will also be x, since the reaction is 1:1. Substituting into the Ksp expression, we get:
Ksp = x^2
Solving for x, we get:
x = sqrt(Ksp) = sqrt(1.8 x 10^-10) = 1.34 x 10^-5 M
Therefore, the minimum concentration of AgNO3 needed to cause precipitation is 1.34 x 10^-5 M.
Answer:
2.67 x 10^-4 M & 8.85 x 10^-8 M
Explanation:
The minimum concentration of the precipitating agent required to cause precipitation of the cation from the solution can be determined using the solubility product constant (Ksp) of the salt that would be formed. The Ksp is an equilibrium constant that represents the maximum amount of solid that can dissolve in water to form a saturated solution.
For part a, calcium iodide (CaI2) and potassium sulfate (K2SO4) are mixed. The reaction that occurs is:
CaI2(aq) + K2SO4(aq) → CaSO4(s) + 2KI(aq)
The solubility product constant for calcium sulfate (CaSO4) is 2.4 x 10^-5. Let x represent the minimum concentration of K2SO4 required to cause precipitation. The concentration of Ca2+ ions in solution is 9.0 x 10^-2 M. The Ksp expression for CaSO4 is:
Ksp = [Ca2+][SO42-]
Substituting the known values gives:
(2.4 x 10^-5) = (9.0 x 10^-2)(x)
Solving for x gives:
x = (2.4 x 10^-5)/(9.0 x 10^-2)
x = 2.67 x 10^-4 M
So, the minimum concentration of K2SO4 required to cause precipitation of CaSO4 is 2.67 x 10^-4 M.
For part b, silver nitrate (AgNO3) and rubidium chloride (RbCl) are mixed. The reaction that occurs is:
AgNO3(aq) + RbCl(aq) → AgCl(s) + RbNO3(aq)
The solubility product constant for silver chloride (AgCl) is 1.77 x 10^-10. Let y represent the minimum concentration of RbCl required to cause precipitation. The concentration of Ag+ ions in solution is 2.0 x 10^-3 M. The Ksp expression for AgCl is:
Ksp = [Ag+][Cl-]
Substituting the known values gives:
(1.77 x 10^-10) = (2.0 x 10^-3)(y)
Solving for y gives:
y = (1.77 x 10^-10)/(2.0 x 10^-3)
y = 8.85 x 10^-8 M
So, the minimum concentration of RbCl required to cause precipitation of AgCl is 8.85 x 10^-8 M.
What should you do if your hypothesis was incorrect based on the results of your experiment?
Responses
Find a scientific reason why your hypothesis might have been incorrect and what new information you have learned from your experiment
Change your data so that your hypothesis is correct
Choose a different experiment
Keep repeating your experiment until your hypothesis is correct
What would be a good scientific reason to explain why the plants that receive more light have greater growth?
Responses
Plants require light to conduct photosynthesis, which is how plants make their own food.
More light doesn't impact plant growth.
The radiation from the light increases the moisture in the soil.
Light makes plants feel better.
Based on the experiments we have done in the Plant Growth Gizmos, how can you determine a healthy plant?
Responses
Only plant height
Type of seed
Both plant height and mass
Only plant mass
Which of the following conclusions can NOT be drawn from the data table below?
Car Mass (g) Trial 1 Time (s) Trial 2 Time (s) Triam 3 Time (s) Average Time (s)
Car A 15.5 4.7 4.9 4.7 4.8
Car B 20.2 3.3 2 3.1 2.8
Car C 7.9 5.9 5.6 5.8 5.8
Responses
The length of the car affects how fast it travels down the ramp
The mass of the car affects how fast it travels down the ramp
The car with more mass will travel the fastest down the ramp
The car with the least mass will travel slowest down the ramp
Pots A and B both have plain soil, bean seeds, and the same amount of light. Pot B receives more water (see table). After 50 days the plants are measured. Based on the data, what is the correct conclusion?
Responses
The amount of water does not affect the mass or the height.
The amount of water affects the mass but not the height.,
The amount of water affects the height but not the mass.
The amount of water affects the mass and the height.
The correct conclusion is that the amount of water affects the mass and the height. This is evidenced by the data in the table, which shows that the plant in Pot B (which received more water) had more mass and was taller after 50 days of growth than the plant in Pot A.
What is mass?Mass is a measure of the amount of matter an object contains. It is expressed in terms of a unit of measurement such as kilograms or pounds. Mass is different from weight, which is a measure of the force of gravity acting on an object. Mass is a constant, while weight can vary depending on the gravitational pull of the planet or other body on which the object is located. Mass is an intrinsic property of matter and is not affected by temperature or pressure. Mass is related to inertia, which is the resistance of an object to changes in its motion.
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What is absolute zero?
A
The temperature at which water freezes
B
The lowest temperature ever reached on Earth
C
The highest temperature an object or substance can reach before boiling
D
The temperature an object would be if its molecules were completely still
Fast i got a few mins
Answer:
D
The temperature an object would be if its molecules were completely still. Absolute zero is the lowest possible temperature that can be achieved, at which the particles of matter would have zero thermal energy and all molecular motion would stop.
Need help with problem
The number of moles of CO contained in the 20.0 L tank at 93 °C and 4.52 atm is 3.01 moles (3rd option)
How do i determine the number of mole contained in the tank?First, we shall list out the given parameters from the question. Details below:
Volume of tank (V) = 20.0 L Temperature (T) = = 93 °C = 93 + 273 = 366 KPressure (P) = 4.52 atmGas constant (R) = 0.0821 atm.L/molKNumber of mole (n) =?We can obtain the number of mole in the tank as follow:
PV = nRT
4.52 × 20 = n × 0.0821 × 366
90.4 = n × 30.0486
Divide both sides by 30.0486
n = 90.4 / 30.0486
n = 3.01 moles
Thus, we can conclude that the number of mole of the gas is 3.01 moles (3rd option)
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When limestone (which is principally CaCO3) is heated, carbon dioxide and quicklime (CaO) are produced by the reaction
CacOs (s) A CaO (s) + CO2(8).
If 16.6 g of CO2 was produced from the thermal decomposition of 40.7 g of CaCOs, what is the percentage yield of the reaction?
Answer in units of %.
The percentage yield of the reaction is 99.5%.
What is the definition of percentage yield in a chemical reaction?Percentage yield is the ratio of the actual yield of a reaction to the theoretical yield, expressed as a percentage. It is a measure of the efficiency of a reaction and indicates how much of the desired product was obtained relative to the amount that could have been produced under ideal conditions.
What factors can affect the yield of a chemical reaction?The yield of a chemical reaction can be affected by a variety of factors, including the purity and amount of the reactants, the conditions under which the reaction occurs (e.g. temperature, pressure, and reaction time), and the efficiency of the reaction process (e.g. whether the product is recovered efficiently).
Other factors that can affect yield include the presence of impurities or side reactions, the stability of the reactants and products, and the skill and experience of the person carrying out the reaction.
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How many milliliters (mL) of a 0.310 M NaOH solution are needed to neutralize 10.0 mL of 0.115 M H2SO4
10.0 mL of 0.115 M [tex]H_2SO_4[/tex] needs to be neutralised with 0.370 mL of a 0.310 M NaOH solution.
Calculate how much 0.310 M NaOH is required to neutralise 10.0 mL of 0.115 M [tex]H_2SO_4[/tex] in millilitres, we can apply the following formula:
Moles of [tex]H_2SO_4[/tex] = (Concentration of [tex]H_2SO_4[/tex])(Volume of [tex]H_2SO_4[/tex])
Moles of [tex]H_2SO_4[/tex] = (0.115 M)(10.0 mL) = 0.00115 moles
Since the reaction is 1 mole of [tex]H_2SO_4[/tex] to 2 moles of NaOH, we must have 0.00115 moles of NaOH to neutralize the [tex]H_2SO_4[/tex].
Moles of NaOH = (Concentration of NaOH)(Volume of NaOH)
0.00115 moles = (0.310 M)(Volume of NaOH)
Volume of NaOH =[tex]\frac{ 0.00115 moles}{0.310 M } = 0.370 mL[/tex]
Therefore, 0.370 mL of a 0.310 M NaOH solution are needed to neutralize 10.0 mL of 0.115 M [tex]H_2SO_4[/tex].
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if you start with 2.196 g of salivic acid what is the theoretical yield of aspirin