In today's experiment, Solutions A and B are prepared as follows.
Solution A: Solution B:
2.0 mL of 3.00 x 10-4 M bromcresol green 2.0 mL of 3.00 x 10-4 M bromcresol green
5.0 mL of 1.60 M acetic acid (HAc) 2.0 mL of 0.160 M sodium acetate (NaAc)
2.0 mL of 0.200 M KCl diluted to a total volume of 50 mL
diluted to a total volume of 50 mL
What is the molarity of HAc in Solution A?
A. 6.4x 10-3
B. 3.20 x 10-4
C. 8.0 x 10-3
D. 0.160
E. 1.60

Answer:

The water will not interfere with the testing of flammable liquids.

When forensic scientists investigate this fire, the water will not interfere with the testing of flammable liquids. Therefore, option B is correct.

A flammable liquid is one with a flash point at or below the nominal threshold temperatures specified by a variety of national and worldwide standards organizations. This means that it can easily ignite in air at room temperature.

our home probably contains a sizable number of flammable liquids. Rubing alcohol, nail polish remover, hand sanitizer, and wart remover are some items that quickly catch fire in addition to gasoline and lighter fluid.

Gasoline is one of the most hazardous liquids in the home and causes over 8,000 home fires each year. One explanation is the frequent inappropriate storage of items in garages. Store it at room temperature, away from heat sources like your hot water heater or furnace, in a UL-approved container.

Thus, option B is correct.

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The complete question is: [tex]CH_{4}(g) + O_{2}(g) \rightarrow CO_{2}(g) + H_{2}O(g)[/tex] balance?

Answer:  [tex]CH_{4}(g) + 2O_{2}(g) \rightarrow CO_{2}(g) + 2H_{2}O(g)[/tex] is a balanced equation.

Explanation:

A chemical equation which contains same number of atoms on both reactant and product side is called a balanced chemical equation.

For example, [tex]CH_{4}(g) + O_{2}(g) \rightarrow CO_{2}(g) + H_{2}O(g)[/tex]

Here, number of atoms on reactant side are as follows.

Number of atoms on product side are as follows.

To balance this equation multiply [tex]O_{2}[/tex] by 2 on reactant side and multiply [tex]H_{2}O[/tex] by 2 on product side. Hence, the equation can be re-written as follows.

[tex]CH_{4}(g) + 2O_{2} \rightleftharpoons CO_{2}(g) + 2H_{2}O(g)[/tex]

Here, number of atoms on reactant side are as follows.

Number of atoms on product side are as follows.

Since, there are same number of atoms on both reactant and product side. So, this equation is a balanced equation.

Thus, we can conclude that [tex]CH_{4}(g) + 2O_{2}(g) \rightarrow CO_{2}(g) + 2H_{2}O(g)[/tex] is a balanced equation.

Answer: The volume of oxygen at STP is needed for complete given combustion is 1121.28 L.

Explanation:

The given reaction equation is as follows.

[tex]2C_{2}H_{18}(l) + 25O_{2}(g) \rightarrow 16CO_{2}(g) + 18H_{2}O(g)[/tex]

This shows that 2 moles of gasoline requires 25 moles of . Hence, moles of oxygen required to react with 4 moles of gasoline are calculated as follows.

[tex]\frac{25 mol O_{2}}{2 mol C_{2}H_{18}} \times 4 mol C_{2}H_{18}\\= 50 mol O_{2}[/tex]

At STP, the pressure is 1 atm and temperature is 273.15 K. Therefore, using ideal gas equation the volume of oxygen is calculated.

PV = nRT

where,

P = pressure

V = volume

n = no. of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

[tex]PV = nRT\\1 atm \times V = 50 mol \times 0.0821 L atm/mol K \times 273.15 K\\V = 1121.28 L[/tex]

Thus, we can conclude that volume of oxygen at STP is needed for complete given combustion is 1121.28 L.

The VSEPR drawing for the compounds in the question are shown in the images attached.

We have to know that according to the valence shell electron pair repulsion theory, the structure of the molecule can be found by looking at the number of electron pairs that surround the central atom in the molecule.

Now the structure of the compounds as we can see in the images that ahve been attached are based on the Vlence Shell electron pair repulsion drawing for each of the compounds that we have mentioned in the question.

We can see that the structure of the compound must have a central atom and then the other atoms in the molecule are arranged around the central atom of the molecule.

The molecule would have a definite shape that is based on the number of electron shells in the molecule.

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The mass of this isotope that is required to give an activity of 205 C is 1.187 mg.

Isotope is defined as two or more different types of atoms with the same atomic number, but different nucleon values at different positions on the periodic table. Isotopes are forms of an element that have the same number of protons and electrons but differing numbers of neutrons.

Let's first translate the 2.70 day half life into seconds to obtain the following half life:

T(1/2) = 233300 sec

By subtracting the half life from ln(2)? = 2.971x10⁻⁶, determine the decay constant.

Now that we have the decay constant, we can solve for the quantity of isotopes required to produce an activity of 290 Ci (which is equal to 1.073x10¹³ decays per second) using the rate of decay equation. Due to the fact that we are discussing the beginning action, t = 0 for this equation.

-1.073x10³ = -A?e^(-? x 0)

Since we are losing isotopes rather than acquiring them, the left side of the equation is negative.

Fill in the blanks: A = 3.611x10¹⁸ isotopes

Find out how much mass is contained in all of these isotopes now.

(3.611x10¹⁸) x(198u) =  7.150x10²⁰ u

To get the final result, convert to mg at this point:

1.187 mg

Thus, the mass of this isotope that is required to give an activity of 205 C is 1.187 mg.

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Answer:

3 (NH4)2SO4(aq) + 2 Al(NO3)3(aq) → 6 NH4NO3(aq) + Al2(SO4)3(aq)

Explanation:

In solubility rules, all ammonium and nitrates ions are solubles and all sulfates are soluble except the sulfates that are produced with Ca²⁺, Sr²⁺, Ba²⁺, Ag⁺ and Pb²⁺. That means the NH4NO3 and the Al2(SO4)3 produced are both soluble and no precipitate is predicted.

The reaction is:

Answer: 6.65bullfrogs/km²

Explanation:

The population density of the bullfrogs per square kilometer will be gotten by dividing the number of bullfrogs that live in the marsh by the land area. This will be:

= 452 bullfrogs/68km²

= 6.65bullfrogs/km²

The population density of the bullfrogs per square kilometer is 6.65.

Answer:

5.1044844 x 10^7/cm^3 = 5E7

Explanation:

The atomic weight and density (at 25 ° C) for copper are 63.5 g/mol or 0.0635 kg/mol and 8,960 kg/m^3

First lets find the value of N, number of atomic sites per cubic meter for copper, from its atomic weight Acu, its density, and Avogadro’s number NA

N = NA x ρ / Acu = 6.023 x 10^23 x 8,960 kg/m^3 / 0.0635 kg/mol = 8.4985953 x 10^28 atoms / m3

Temperature dependency can be given as :

Arrhenius equation

Nv = N e^(-EA/KT)

N = no. of atoms initially

Ev = activation energy

Nv = 8.4985953 x 10^28 atoms / m^3 exp^-(0.9ev/atom /8.617x10-5 eV/(atom-K) x 298 K

Nv = 5.1044844 x 10^13 /m3

vacancies per cm^3 = 5.1044844 x 10^7/cm^3 = 5E7

Answer:

True

Explanation:

both are chemical, got it right on my test

Answer:

b

Explanation:

because it is the balanced one

Answer: There are 7.4 moles of helium gas present in a 1.85 liter container at the same temperature and pressure.

Explanation:

Given: [tex]V_{1}[/tex] = 2.25 L,     [tex]n_{1}[/tex] = 9.0 mol

[tex]V_{2}[/tex] = 1.85 L,            [tex]n_{2}[/tex] = ?

Formula used to calculate the moles of helium are as follows.

[tex]\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}\\[/tex]

Substitute the values into above formula as follows.

[tex]\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}\\\frac{2.25 L}{9.0 mol} = \frac{1.85 L}{n_{2}}\\n_{2} = \frac{1.85 L \times 9.0 mol}{2.25 L}\\= 7.4 mol[/tex]

Thus, we can conclude that there are 7.4 moles of helium gas present in a 1.85 liter container at the same temperature and pressure.

Answer:

la respuesta es la letra: a

The hydroxide of the solution can give the pOH of the solution used to determine the pH of the solution. The solution has a pH of 7.7 and is basic. Thus, option a is correct.

The hydrogen potential of the solution is given by the concentration of the hydrogen or the hydroxide concentration dissolved in the solution.

The pH or the pOH of the solution can be used to determine the acidic and basic nature of the solution based on the range in which it lies.

If the pH of the solution lies below 7 then they are said to be acidic, whereas above 7 are alkaline in nature.

Given,

[OH⁻]  =5.6 x 10⁻⁷ M

First, pOH is calculated as,

pOH = -log [OH⁻]

pOH = - log (5.6 x 10⁻⁷ M)

pOH = 6.252

Now, pH from pOH is calculated as:

pH = 14 - pOH

pH = 14 - 6.252

pH = 7.748

Therefore, option a. the pH of the solution is 7.7 and is basic.

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Polyatomic ions are ions made up of more than one atom.

What are Atoms?

Atoms are the smallest particles of matter that make up all objects. They are composed of protons, neutrons, and electrons. Protons and neutrons make up the nucleus of the atom, while electrons orbit around the nucleus. Atoms are the basic units of matter and are the building blocks of all living and nonliving things.

Polyatomic ions are ions that consist of two or more atoms covalently bonded together and carrying a net electric charge. Examples of polyatomic ions include nitrate (NO3−), sulfate (SO42−), phosphate (PO43−), and carbonate (CO32−).

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Answer:

b. insoluble in water

Explanation:

triacylglycerols are insoluble in water

Answer:

Explanation:

1) The following balanced chemical equations are for based on the combustions of various fuels. Calculate the heats of combustion for each reaction a. C₂H₂OH + ...

Answer:

Explanation:

In water, silver nitrate (AgNO3) dissolves to generate the ions Ag+ (silver) and NO3- (nitrate). When the substance is dissolved in water, the ions are separated and become solvated, or surrounded by water molecules. Water molecules' oxygen atoms join the metal ion in a coordinate covalent bond that gives the metal ion a pair of electrons. By preventing it from interacting with other ions or molecules in the solution, this aids in stabilising the metal ion. As a result of their hydrogen bonds with the water molecules around them, the nitrate ions are likewise stabilised in solution.

Snowy Owl i Think  or weasel

Answer:

this is a animal cell..I hope you received this on time

Answer:

polymer mear least receptive to dye

,

Answer: C

Explanation:

I think the answers correct because, A says that the food chain will stay the same, but thats not true because, the frog ate most of the insects. And B says the population will decrease, but that doesn't make sense because a animal that eats grasshoppers would no longer be there. And C says that the population will increase and i think that correct because, one animal that does eat the grasshopper wouldn't be there so the grasshoppers will increase in population. And D says the population of snacks will increase but that was one of the foods the snacks ate so they would decrease because they lost one species to eat off of.

Hope This Helps!

Answer: D- ecotourism helps pay for conservation efforts

Explanation:

says help and the others exploit and harm

Answer:

True

Explanation:

It is TRUE that Phenylephrine is a nasal decongestant and is the active ingredient in Sudafed, which contains phenylephrine hydrochloride (PEHCl).

Phenylephrine is considered a prescription formula that is used in the production of Sudafed. Due to its direct-acting sympathomimetic amine property, it is used as a significant ingredient in the formation of Sudafed, a drug usually prescribed for nasal decongestion from regular cold, upper respiratory allergies, hay fever, etc.

The mass of 65% and 20% nitric acid that must be mixed to produce 4.5 kg of 30% nitric acid are 1.306 kg and 3.189 kg respectively.

The volume of 4.5 kg of 30% nitric acid is determined using the formula below:

The density of 30% nitric acid is 1.18 g/mL

The mass of the  30% nitric acid is 4.5 kg or 4500 g

Hence, the volume will be:

The volume of 30% nitric acid = 4500 / 1.18

The volume of 30% nitric acid = 3813.56 mL

The volume of 65% and 20% nitric acid required is then determined.

Let the volume of the 65% and 20% nitric acid be x and y respectively;

x + y = 3813.56 ---(1)

amount of acid in 3813.56 ml solution = 30% * 3813.56

amount of acid in 3813.56 ml solution = 1144.07 mL

therefore;

60% * x + 20% * y = 1144.07 mL

0.6x + 0.2y = 1144.07 ----(2)

Solving for x and y in the two equations

From (1), x = 3813.56 - y

Substitute x = 3813.56 - y in (2)

0.6(3813.56 - y) + 0.2y = 1144.07

0.4y = 1144.07

y = 2860.18 mL
x = 3813.56 - 2860.18

x = 953.38 mL

The mass of the acids required is then determined as follows:

The density of 60% nitric acid is 1.37 g/mL

Mass of 60% nitric acid required = 953.38 mL * 1.37 g/mL

Mass of 60% nitric acid required = 1306 g or 1.306 kg

The density of 20% nitric acid is 1.115 g/mL

Mass of 20% nitric acid required = 2860.18 mL * 1.115 g/mL

Mass of 20% nitric acid required = 3189 g or 3.189 kg

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Answer:

Just use a text book.. So that you get the concept

Answer:

A. C2H4

Ethene

step by step explanation:

Answer:

a

Explanation:

Answer:

the answer is C

Explanation: