Answer:
the proton speed of the proton was 1.6 × 10⁶ m/s
Explanation:
Given the data in the question;
Radius r = 6.42 cm = 0.0642 m
magnetic field B = 0.260 T
we know that; charge of proton q = 1.602 × 10⁻¹⁹ C
And mass of proton m = 1.672 × 10⁻²⁷ kg
we know that; Magnetic Force F = qvBsinθ
where q is the charge of proton, v is velocity, B is the magnetic field and θ is angle ( 90° )
Also the Centripetal force experienced by the particle is;
F = mv² / r
where r is radius, m is mass of proton and v is velocity
hence;
qvBsinθ = mv² / r
we solve for v
rqvBsinθ = mv²
divide both sides by mv
rqvBsinθ / mv = mv² / mv
rqBsinθ / m = v
so we substitute
v = [ 0.0642 m × (1.602 × 10⁻¹⁹ C) × 0.260 T × sin(90°) ] / 1.67 × 10⁻²⁷ kg
v = 2.6740584 × 10⁻²¹ / 1.672 × 10⁻²⁷
v = 1.6 × 10⁶ m/s
Therefore, the proton speed of the proton was 1.6 × 10⁶ m/s
Question
Stopping Distance
48.0 ft
49.0 ft
50.0 ft
51.0 ft
52.0 ft
2
The stopping distance for 10 cars traveling at 55 miles per hour is shown in the table above. What is the
mean (average) stopping distance for the 10 cars?
Frequency
1
2
3
2
Mention four factors on which the amount of precipitation intercepted by vegetal cover depend on
Precipitation amount, storm frequency, and severity, storm duration, kind of precipitation, wind during storm, and wind during evaporation are the main precipitation and storm elements that influence interruption loss (Kenneth, 1996).
What does it signify when vegetation blocks precipitation?All procedures that stop rainfall from instantly reaching the soil are referred to as interceptions. The two main ways that vegetation intercepts water are by catching it on leaf surfaces throughout the canopy and by depositing litter on the ground.
Intercepted precipitation: What is it?Precipitation that is intercepted by leaves, plant branches, and the forest floor prevents it from reaching the soil and instead stays on the surface.
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Ways to calculate an “average” include _____
Answer:
Adding together and dividing by how many terms you added
Explanation:
Two students push on a box in the same direction, and one student pushes in the opposite direction. What is the net force on the
box if each student pushes with a force of 50 N?
Net force on the box is 50 N if 2 students push it in the same direction with 50 N of force each and one student pushes it in the other direction with 50 N of force.
Define force.An object with mass experiences a pull or push, which changes its velocity. An agent with the ability to change a body's rest or moving condition is known as an external force. It has both magnitude as well as direction.
The force formula according to Newton is what?F = ma, meaning force is equal to the mass times acceleration, is the second of Newton's three laws of motion.
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The anterior cruciate ligament in a woman's knee is 2.5 cm long and has a cross- sectional area of 0.54 cm2. If a force of 3000 N is applied longitudinally, how much will the ligament stretch? assume that young's modulus (1.8x10¹0 N/m²)
If a longitudinal force exceeding 3000 N is applied. Young's modulus for that object equals DL = 0.0139m.
Which is better, a greater or lower Young's modulus?The greater the modulus, or the lesser elasticity strain that arises from the application of a given stress, the stronger that medium is. Young's modulus, sometimes referred to as mechanical performance, is a metric used to determine how stiff a material is. In other words, it is readily bent or stretched.
Young's modulus really measures a material's ability to withstand changes in length when compressed or under stress along its length. Divide the primary stresses by the strain to get Young's modulus, commonly known also as young's modulus.
Young's modulus Y= stress/strain
= (F/A) /(DL/L)
F=3000N,
A=0.54 cm²,
L=2.5cm,
Y=0.1 Gpa
0.1 * 10⁹ = (3000/(0.54* 10⁻⁴) (2.5 ⋆ 0.01/DL)
DL = 0.0139m
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The heaviest train ever pulled by a single engine was over 2 km long. Suppose a force of 1.13 X 10^8 N is needed to overcome static friction in the train's wheels. If the coefficient of static friction is 0.741, what's the train's mass?
The overcoming force is equal to the friction. The train's mass is 15,560,880.5 Kg
What is Friction ?Friction can simply be defined as a force that opposes the movement of an object in a plain surfaces.
Given that the heaviest train ever pulled by a single engine was over 2 km long. Suppose a force of 1.13 X 10^8 N is needed to overcome static friction in the train's wheels. If the coefficient of static friction is 0.741, what's the train's mass?
F = μN
Where
F = Frictional force = overcoming force = 1.13 X 10^8 Nμ = coefficient of static friction = 0.741N = Normal reaction = mgSubstitute all the necessary parameters
1.13 X 10^8 = 0.741N
N = 1.13 X 10^8/0.741
N = 152496626.2 N
N = mg
152496626.2 = 9.8m
m = 152496626.2/9.8
m = 15,560,880.5 Kg
Therefore, the mass of the train is 15,560,880.5 Kg.
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3. An electron moves along the trajectory from i to f as shown.
a) Does the electric potential energy increase, decrease or stay the same? Explain.
b) Is the electron's speed at f greater than, less than or equal to its speed at i? Explain.
Answer:
decrease
Explanation:
this is for part a
16. A car A is moving at a speed of 6m/s due north and car B is moving at a speed of 8m/s due east. Find the magnitude and direction of the velocity of car A relative to car B
acceleration to move 650N with mass of 100 kg
A car accelerates from the rest at 1.5 m/s^2 for 10 sec. What made the car move?
Accelerating linearly is simple.
What is Acceleration?When the velocity vector length of an object moving in a straight line changes in response to changes in the object's speed (speed being the magnitude of the velocity vector), we have acceleration. Increasing speed is frequently referred to as "positive acceleration" and decreasing speed as "negative acceleration."
A particle's acceleration is the rate at which its velocity changes over time. The term "constant acceleration" refers to the pace at which a particle's velocity changes.
We shall measure acceleration in metres per second per second because our basic units are metres and seconds.
Therefore, Accelerating linearly is simple.
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H
Question 12 of 15:
Select the best answer for the question.
12. A 150-lb block of ice has a temperature of 22 F. How much heat will the ice absorb before it begins to melt?
O A. 1500.0 Btu
O B. 1663.2 Btu
C. 756.0 Btu
OD. 2419.2 Btu
Answer:
I think it is A
Explanation:
It is A because if you calculate the weight minus the F, then you have to divide that by the amount of absorbation (the lb) before timsing it by 1000.
Concluding statement about electricity like a sentence or two
Things are:
Wind turbines
Hydroelectric
Geothermal heat
Write it in like a concluding statement feel
Wind turbines, hydroelectric, and geothermal heat have been relied upon for decades to provide a renewable and clean energy source to people around the world. These alternative energy technologies provide optimal clean and renewable energy sources for many communities and countries striving for sustainable development.
need help with Kirchhoff's rules
The nodal voltage is V and the currents are as defined in the diagram.
At the upper node, Kirchhoff's current law equation is I1+I5=I2+I3
What is Kirchhoff's rules?The voltage around a loop equals the sum of every voltage drop in the same loop for any closed network and equals zero. Put differently, the algebraic sum of every voltage in the loop has to be equal to zero and this property of Kirchhoff's law is called conservation of energy.Kirchhoff's circuit laws are two equalities that deal with the current and potential difference in the lumped element model of electrical circuits. They were first described in 1845 by German physicist Gustav Kirchhoff. This generalized the work of Georg Ohm and preceded the work of James Clerk Maxwell.Kirchhoff's first rule—the junction rule. The sum of all currents entering a junction must equal the sum of all currents leaving the junction. Kirchhoff's second rule—the loop rule. The algebraic sum of changes in potential around any closed circuit path (loop) must be zeroTo learn more about Kirchhoff's rules refers to:
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HELPPP PLEASEEEEE, BRIANLEST WILL BE GIVEN ON CORRECT!
work done =force /area
=500/50
power =work done * time taken
A man is attempting to train his dog. He is pulling on the dog with a force of 52.4 Newtons at an angle of 35.1 degrees above the horziontal. Fimd the X and Y component of the applied Force
The formula for the horizontal component (Fx), which is the angle the force makes with the horizontal, is Ftens•cosine(). Ftens• sine() can be used to compute the upward component (Fy), where is the angle that the force produces with the horizontal.
What is the force's horizontal component?The portion of a force that works horizontally with regard to a body is known as its horizontal component. Its vertical component is known as its vertical component.
Why is moving the box with the rope horizontal easier?The pulling of the box is with the rope horizontal. When the rope is angled Because Is less than, the horizontal component (= F cos ) is less. As a result, it is the proper response.
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In a particular crash test, an automobile of mass 1245 kg collides with a wall and bounces back off the wall. The x components of the initial and final speeds of the automobile are 18 m/s and 2.9 m/s, respectively. If the collision lasts for 0.11 s, find the magnitude of the impulse due to the collision. Answer in units of kg · m/s. Answer in units of kg · m/s.
Answer:
Δp=-18799.5kg*m/s
Explanation:
Δv=Vf-Vi
Δv=2.9m/s-18m/s
Δv=-15.1m/s
m*Δv=Δp
1245kg*(-15.1m/s)=Δp
Δp=-18799.5kg*m/s
Extra:
Deriving mΔv=Δp
Δp=Pf-Pi
Δp=m*Vf-m*Vi
Δp=m(Vf-Vi)
Vf-Vi=Δv
Δp=m(Δv) or Δp=mΔv
a taxi accelerates from 10m/s to 28m/s in 6sec find the average acceleration ?
Answer:
3m/s^-2
Explanation:
a=(v-u)/t where v is the final velocity at 28 m/s and u is the initial velocity at 10m/s and t is the time taken at 6 seconds
a=(28-10)/6 = 3
Helen is para sailing. She sits in a seat harness which is attached by a tow rope toba speedboat. The rope makes an angle of 59.9* with the horziontal and has a tension of 364N. Determine the horziontal and vertical component of the tension force
To find the horizontal and vertical components of the tension force in para sailing, we can use the basic trigonometric ratios of sine, cosine and tangent.
How to use trigonometric ratios ?First, given the rope's angle (59.9 degrees) and the tension force (364 N), we can apply the following formula to determine the tension force's horizontal component (Fx): Fx = Tension force x cos(angle) = 364 N x cos (59.9).Next, we can use the angle of the rope and the tension force to find the vertical component (Fy) of the tension force using the formula: Fy = Tension force x sin(angle) = 364 N x sin(59.9)You must convert the angle to radians because these calculations, as you should be aware, employ radians rather than degrees.As a result, the tension force's horizontal component has the following formula: Fx = 364N x cos(59.9) = 225.98N roughly.Additionally, the vertical component of the tension force is roughly 318.6N, or Fy = 364N x sin(59.9)According to these calculations, the tension force has two components: a horizontal component that is 225.98 N and a vertical component that is 318 N.To know more about trigonometric ratios , check out :
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What is meant by half life ?
How does the horizontal velocity of a projectile affect the velocity at which it falls?
A. faster horizontal objects fall slower
B. slower horizontal objects fall slower
C. No horizontal motion means the object will not fall
D. Horizontal motion does not have an effect on how an object will fall
a) What is the magnitude of the force F⃗ on the −10 nC charge in (Figure 1)? Express your answer using two significant figures.
b) What is the direction of the force F⃗ on the −10 nC charge in (Figure 1)? Give your answer as an angle measured cw or ccw (specify which) from the +x-axis. Express your answer in degrees. Enter a positive value if the angle is counterclockwise and negative value if the angle is clockwise.
a) The magnitude of the force F on the −10 nC charge is 0.00134 Newton.
b) The direction of the force F on the −10 nC charge is 41.99° with horizontal line.
What is electric force?Electric force is the attractive or repulsive interaction between any two charged things.
a) the magnitude of the force F on the −10 nC charge = √{k (q₁Q/r₁²)²+(q₂Q/r₂²)²}
= kQ √( (q₁/r₁²)²+ (q₂/r₂²)²}
= 9×10⁹×10×10⁻⁹ √{ (1×10⁻⁹/(0.01)²)² +(10×10⁻⁹/(0.03)²)² }
= 0.00134 Newton.
b) the direction of the force F on the −10 nC charge
= tan⁻¹( (1×10⁻⁹/(0.01)²) ÷(10×10⁻⁹/(0.03)²) )
= 41.99°
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How a body is charged ?
Answer:
Explanation:
Following are the three important ways by which a body can get charged. ⇒ By conduction :When an uncharged body is made in contact with a charged body, the charge flow into the non charged body and the body gets charged. ⇒ By rubbing: When a body is rubbed with another body, both of them gets charged.
Which organelle produces energy for the cell? a. The nucleus b. The cytoplasm c. The mitochondria d. The cell membrane
Answer:
[tex]\boxed {\boxed {\sf C. \ The \ Mitochondria}}[/tex]
Explanation:
Let's examine each organelle and its function.
A. The Nucleus
This organelle is the control center. It regulates a cell's activities and processes. It also contains the DNA or genetic information.
B. The Cytoplasm
The cytoplasm is a jelly like liquid that fills the inside the cell. Organelles and molecules are suspended in it.
C. The Mitochondria
This is also called the powerhouse of the cell, because it produces energy! This is the site of cellular respiration, the process that turns oxygen and glucose into ATP (energy), water, and carbon dioxide.
D. The Cell Membrane
This covers and protects the entire cell. It keeps important substances in and allows them to enter the cell, while preventing harmful ones from entering.
Based on this information, we see that the mitochondria is the organelle producing energy for the cell and choice C is correct.
Gravity on earth is 9.8
Jaydens mass is 50 kilograms his weight is
Read the following poem by Lola Ridge. Then, respond to the prompt that follows.
Wild Ducks
By Lola Ridge
That was a great night we spied upon
See-sawing home,
Singing a hot sweet song to the super-stars
Shuffling off behind the smoke-haze …
Fog-horns sentimentalizing on the river …
Lights dwindling to shining slits
In the wet asphalt …
Purring lights …red and green and golden-whiskered …
Digging daintily pointed claws in the soft mud …
…But you did not know …
As the trains made golden augers
Boring in the darkness …
How my heart kept racing out along the rails,
As a spider runs along a thread
And hauls him in again
To some drawing point …
You did not know
How wild ducks' wings
Itch at dawn …
How at dawn the necks of wild ducks
Arch to the sun
And new-mown air
Trickles sweet in their gullets.
In a well-written paragraph of 5–7 sentences, analyze the ambiguous nature of "Wild Ducks." Your response should include:
an explanation of your interpretation of the poem's meaning
evidence from the poem (PReP) that supports your interpretation
an explanation of how another reader could interpret the poem differently
evidence from the poem to support an alternative interpretation
Due to the possibility of misinterpretation, the poem "Wild Duck" can be read as either the speaker leaving her lover or the lover leaving her.
What does the poem discuss?Lola Ridge's poem "Wild Duck" allows for more than one interpretation of the speaker's meaning. As a result, it is ambiguous. The ambiguity of the poem can be examined, and the following response to the prompt:
You could say that according to your interpretation of the poem, the speaker is telling us about a night when she bid her lover farewell.
You could argue that the metaphor comparing the speaker to wild ducks and the speaker's statement that her heart "races along the train rails" are examples from the poem that support your claim.
You could argue that a different reading would imply that the speaker is the one being dumped by her lover.
You could cite the second stanza, which is not included here, where the speaker claims that the "known you" have emptied her soul, as proof for your claim.
But it's crucial to remember that the first interpretation appears to be the most plausible one. The metaphor involving the wild duck and the personification of the heart that runs on rails are quite clear, even though the poem does leave some room for ambiguity. The person who wants to leave someone behind is the speaker.
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Periodic motion
This question is about the stretching of springs
The diagram below shows an unblocked spring of length 100 mm
hanging suspended from a clamp. When an object of mass 50g is
hung on the spring, it becomes 180 mm long.
The spring constant K=50N/m
100 mm
50g
1- Calculate x in (mm) then convert it to meter
X is the distance that the spring is stretched from its
equilibrium position.
2- Use Hooke's law to calculate the restoring force of the spring
Hooke's law :
F=-K.X
The value of x is 0.04m and restoring force is 9 N
(a) From the figure, the spring force balances force due to gravity.
So, [tex]\frac{1}{2} kX^{2} = mg[/tex]
Where, k = spring constant = 50N/m
X = compressed distance = L+x = 0.1+x
m = mass = 50 g = 0.05Kg
g = acceleration due to gravity = 10
Putting these values in above equation, we get: x= 0.04m
(b) Using Hooke's law, F = kx
Where, k = spring constant =50N/m
x = distance = 180mm = 0.18 m
Putting these values in above equation, we get restoring force F = 9N
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A sample of copper (specific heat capacity of copper is 0.386J/g*C) absorbs 1200 J of heat and
the temperature of the water it is being heated in increases from 27*C to 95*C, what mass of
copper was heated?
The mass of copper heated from a temperature of 27°C to 95°C is 45.72 g.
What is mass?Mass is the quantity of matter contained in a body, The units of mass are
Kilogram (kg)Gram (g)Milligram (mg) etc.To calculate the mass of the copper, we use the formula below.
Formula:
m = Q/cΔt.................. Equation 1From the question,
Given:
m = MassQ = Amount of heatc = Specific heat capacity of copperΔt = Change in temperatureFrom the question,
Given:
Q = 1200 Jc = 0.386 J/g°CΔt = 95-27 = 68°Substitute these values into equation 1
m = 1200/(0.386×68)m = 45.72 gHence, the mass of copper is 45.72 g.
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How are the states of water and the water cycle related?
Answer: Various forms or states of water are the parts of water cycle
Explanation:
The water cycle initiates with the evaporation of liquid water that can on the surface of earth or a part of water body (hydrosphere). The evaporated water becomes the part of water vapors. The water vapor is the gaseous form of water. The water vapors accumulate in the higher atmosphere. They condense and precipitate in the form of rain or liquid water or solid water in the form of snow that is the solid form of water.
For science class your teacher gives you and your partner a ball she ask you to figure out a way to Balance forces that you apply to the ball how do you partner show this?
Two forces are said to be balanced when their strengths are equal but their directions of action are opposing.
What is Balanced Force?The forces are balanced if the pullers are exerting equal force but going in the opposite direction on either side of the rope.
Forces that are balanced can cancel one another out. The thing stays in place whenever there is a balanced force.
To lift, turn, move, open, close, push, pull, and many other things requires forces. You apply force to a ball when you throw it in order for it to travel through the air. An object can be under the influence of multiple forces at once.
Therefore, Two forces are said to be balanced when their strengths are equal but their directions of action are opposing.
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As shown in the picture above, an ice skater is skating at a constant speed in a circle. Is she accelerating? Explain your answer and draw the direction of the velocity in point A, B, C, and D.
Yes, the skater is accelerating.
Acceleration is a change in speed OR direction OR both. Since she's skating in a circle, her direction is constantly changing, so she is accelerating.
At A, her velocity points down.
At B, her velocity points right.
At C, her velocity points up.
At D, her velocity points left.