If the width and length of a rectangle is 3 by 8 what is the width and length actually if the width is 10. 5

Answer:

linear equations produce straight lines when graphed, and their rate of change remains constant

Nonlinear equations do not produce straight lines when graphed.

To determine whether its linear or nonlinear, you can graph it and see if it produces a straight line, or check if it can be written in the form y= Mx+b

Step-by-step explanation:

Total volume of the composite figure using volume of cuboid formula is = 120ft³.

A cuboid's volume is a measurement of how much room it occupies. A three-dimensional shape with dimensions of length, breadth, and height is the cuboid. We can keep stacking them, starting with a rectangular sheet, until we achieve a shape with a particular length, breadth, and height.

The shape of this stack of sheets is a cuboid, which has 6 faces, 12 edges, and 8 vertices. The (unit)³ is used to represent a cuboid's volume.

In the given figure,

Length of cuboid = 6ft.

Breadth of cuboid = 3ft.

Height of cuboid = 5ft.

Length of second cuboid = 4ft.

Height of second cuboid = 5ft.

Breadth of second cuboid = 3ft.

Volume of first cuboid = length × breadth × height.

= 6 × 3 × 5

= 90ft³

Volume of second cuboid = 4 × 3 × 5

= 60ft³

Now the second cuboid is half.

So, volume becomes = 60/2

= 30ft³.

So, total volume of the figure = 90 + 30 = 120ft³.

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The process of trying out the resulting equation on a second sample to see if it still fits well is called “cross-validation”.

Cross-validation is a technique used to evaluate the performance of a statistical model on a new independent dataset, which was not used in training the model. This process helps to assess the generalization capability of the model and helps to determine whether the model is overfitting or underfitting the data. By testing the model on a new independent dataset, we can get a better idea of how well the model is likely to perform on new data in the future. Cross-validation can also help in selecting the best model from a set of competing models.

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Let (x1, y1) = (9,7) and (x2, y2) = (6,3)

By distance formula,

d = (x2 - x1)² + (y2 - y1)²

d = (6 - 9)² + (3 - 7)²

d = (-3)² + (-4)²

d = 9 + 16

d = 25 units

Answer:

25 and 22

Step-by-step explanation:

Answer:

Sure, I can help you solve these problems using substitution. Let's start with problem 1:1. y=x+4 y=3x To solve this system of equations, we need to substitute one of the variables from one equation into the other equation. We can solve the second equation for y:y=3x Now we can substitute this expression for y into the first equation:y=x+4 3x=x+42x=4x=2 Now we can substitute this value for x into either equation to solve for y:y=x+4 y=2+4y=6 So the solution to this system of equations is x=2, y=6. You can follow the same procedure to solve the rest of the problems. 2. x=-2y+1 x-y=-53. y=x-7 2x+y=84. y=3x-6 -3x+y=-65. x+2y=200 x=y+506. 4x+3y=1 x=1-y Let me know if you need any further assistance.

The variance of 2X + 3Y is 35.52.

The solution to the problem is as follows:

First, find the mean and variance of X and Y:

E(X) = 3/5

Var(X) = 3/25

E(Y) = 1

Var(Y) = 1/25

Then, use the properties of variance to find the variance of 2X + 3Y:

Var(2X + 3Y)

= 4Var(X) + 9Var(Y) + 12Cov(X,Y)Cov(X,Y)

= E[(2X - 6/5)(3Y - 1)]

= 6E(XY) - 6E(X) - 3E(Y) + 2

= 6 * (integral from 0 to infinity integral from 0 to infinity of xyf(x,y)dxdy) - 6 * 3/5 - 3 * 1 + 2 = 6 * (integral from 0 to infinity 15xye^-3xdydx) - 8

= 54/5

Therefore,

Var(2X + 3Y) = 4(3/25) + 9(1/25) + 12(54/5)

                     = 888/25

                     = 35.52.

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Answer:

3P-3q

Step-by-step explanation:

you want to distribute the 3, to the whole parenthesis.

Answer:[tex]3\sqrt{2}[/tex]

Step-by-step explanation:

in order to make a right triangle point should be either (1,4) or (4,1)

each way hypotenuse of this triangle is

[tex]known coordinates are (4,4)-- > (x1,y1)\\ and (1,1)-- > (x2,y2) \\\sqrt{(x1-x2)^{2}+(y1-y2)^{2}} =\sqrt{(4-1)^{2}+(4-1)^{2}}=\sqrt{9+9}=\sqrt{3^{2}*2}=3\sqrt{2}[/tex]

Answer:

Step-by-step explanation:

Standard: 2x^3 - 7x^2 -x-2

Quotient: 2x^3- 7x^2 -x-2

remainder: 0

The mean weight of an individual cauliflower being between 400 and 409 grams has a greater probability.

Standard deviation of the given data is 20 grams. The mean weight of the cauliflower is 400 grams. Now, for calculating the probability, we need to standardize the given mean weight of cauliflower. It will be as follows. Z-score for the mean weight of cauliflower is given as:

z = (X - μ) / σwhere X = 400 grams (mean weight of cauliflower)

μ = 400 grams (mean weight of the population)

σ = 20 grams (standard deviation)z = (400 - 400) / 20 = 0

Now, the probability of the mean weight of an individual cauliflower being between 400 and 409 grams is as follows:

P(400 < X < 409) = P(0 < Z < 0.45)

Using the standard normal distribution table, the probability is 0.1745.

The mean weight of a random sample of 36 of the cauliflowers is between 400 and 409 grams. The mean weight of a random sample of 36 of the cauliflowers is given by:

(X-μ)/ (σ/√n)where μ = 400 grams (mean weight of cauliflower)

σ = 20 grams (standard deviation)

n = 36 (number of samples)

Now, we need to standardize the sample mean. It will be as follows:

z = (X - μ) / (σ/√n)z = (400 - 400) / (20 / √36)

z = 0

As the z-score is zero, the probability will be equal to 0.5. Hence, the mean weight of an individual cauliflower being between 400 and 409 grams has a greater probability than the mean weight of a random sample of 36 of the cauliflowers being between 400 and 409 grams.

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Answer:

Step-by-step explanation:

E

Answer:

Step-by-step explanation:

# elements = 292 - 268 - 1 = 23 elements

G has 2^23 subsets = 8388608

G has 2^23 - 1 proper subsets = 8388607

Answer:

a) 1.4665787 × 10^7

b) 2.869 × 10^8

Step-by-step explanation:

Answer:

14,665,787 that's the answer for that question

Answer: 580

Step-by-step explanation: i learned that just like 1 hour ago in school

Therefore, the wheel has made 8 complete revolutions after 8 seconds.So, the correct answer is option A) 8.

The given problem is about a wheel that is initially at rest, but then starts to turn with a constant angular acceleration. After four seconds, it has made four complete revolutions. The question asks us to find out how many revolutions it has made after eight seconds.The problem can be solved by using the formula for angular displacement. For a body moving with a constant angular acceleration, the angular displacement, θ can be given as,θ = ω1t + 1/2 α t²Where ω1 is the initial angular velocity and α is the angular acceleration of the body.

Substituting the given values, ω1 = 0 (since the wheel is initially at rest), α is unknown, and t = 4 seconds, we get the equation,[tex]θ = 1/2 α t² = 4 × 2π[/tex]revolutions (since the wheel has made four complete revolutions in four seconds)Solving for α,α = (8π) / (16) = π/2 rad/s²Now, to find out the number of revolutions made after eight seconds, we need to calculate the angular displacement after eight seconds.θ = [tex]ω1t + 1/2 α t²Here, ω1 = 0, α = π/2 rad/s²[/tex], and t = 8 seconds[tex].θ = 0 + 1/2 (π/2) (8)² = 8π[/tex] revolutions

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Therefore, the probability of getting a total of 7 is 6/36, which reduces to 1/6. The probability of getting a total of 8 is 5/36.

In mathematics, probability is a measure of the likelihood that an event will occur. It is usually expressed as a number between 0 and 1, with 0 indicating that the event is impossible and 1 indicating that the event is certain to occur. The probability of an event A is denoted by P(A), and it is defined as the ratio of the number of outcomes favorable to A, to the total number of possible outcomes in the sample space.

Here,

a) The sample space for tossing two fair dice can be represented as a table, where each row represents the outcome of one die, and each column represents the outcome of the other die. The sample space for this experiment would consist of all possible combinations of the two dice outcomes. Here's how the sample space table would look like:

       1 2 3 4 5 6

1 2 3 4 5 6 7

2 3 4 5 6 7 8

3 4 5 6 7 8 9

4 5 6 7 8 9 10

5 6 7 8 9 10 11

6 7 8 9 10 11 12

b) To find the probability of getting a total of 7 or 8, we need to count the number of possible outcomes that result in these totals, and then divide by the total number of possible outcomes in the sample space.

For a total of 7, there are 6 possible outcomes (1+6, 2+5, 3+4, 4+3, 5+2, 6+1).

=6/36

For a total of 8, there are 5 possible outcomes (2+6, 3+5, 4+4, 5+3, 6+2).

=5/36

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Complete question:

Two fair dice are tossed together once, what is:

a. draw the sample space for the following outcome

b. find the probability of getting a total of 7 and 8 ​

The probability density of the two patterns  at 0.4 and 0.6,  for one nearest-neighbour is 0.6

Given two patterns at 0.4 and 0.6, the probability density of these patterns can be estimated analytically using a rectangular window of width 0.3, a triangular window of width 0.3, and one nearest-neighbour.

Probability density can be calculated using the following formula: [tex]$p(x)=\frac{n}{aN}$[/tex] where n is the number of samples that fall in the window centered at x, a is the window's width, and N is the total number of samples.

For the rectangular window of width 0.3, the probability density can be calculated as the sum of the two rectangular windows multiplied by 0.3, giving a probability density of 0.6.

For the triangular window of width 0.3, the probability density can be calculated as the sum of the two triangular windows multiplied by 0.3, giving a probability density of 0.45.

Finally, for one nearest-neighbour, the probability density is the maximum of the two patterns, which in this case is 0.6.

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we can say that the entries in the matrix are highly constrained, with only one unique value per row or column. The matrix is usually denoted as a scalar multiple of the identity matrix or a vector of constants, depending on whether it is row-wise or column-wise identical.

In the row-wise identical matrix, all entries in each row are the same, but the entries in different rows can be different.

In the column-wise identical matrix, all entries in each column are the same, but the entries in different columns can be different.

Thus, we can say that the entries in the matrix are highly constrained, with only one unique value per row or column. The matrix is usually denoted as a scalar multiple of the identity matrix or a vector of constants, depending on whether it is row-wise or column-wise identical.

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Answer:

16

Step-by-step explanation:

First you figure out how many days are in 4 weeks which is 28. Then you do 448 divided by 28 which equals 16. There's your answer.

The sales price of the item is $48.

The sale price of an item that costs 60% of its original price which is $80 is $48. The original price of the item is $80, and it costs 60% of the original price. The amount of money we'll be spending is calculated as follows: 60 per cent of $80 (60/100) × $80= $48 Therefore, the sales price is $48. The percentage discount for the item is calculated as follows:$80 - $48 = $32

$32 is the amount of money saved due to the discount, which is then divided by the original price, $32/$80 = 0.4 or 40%. Thus, there was a 40% discount on the original price.

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Answer:

$25.96

Step-by-step explanation:

Since the tip is 18% of the fare, he pays 118% of the fare.

118% of $22 =

= 1.18 × $22

= $25.96

The division expression shown in the model attached to this question is 1/2 ÷ 3

The model missing in the question is added as an attachment

In the model, we have

Shaded sections = 3

Partitons = 1/2

This means that

Division expression = Partitons ÷ Shaded sections

Substituting the above expressions, we have

Division expression = 1/2 ÷ 3

This means that the division expression is 1/2 ÷ 3

When the expression is solved, we have

Division expression = 1/6

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Complete question

Which division expression is shown in the model?

See attachment

Using expressions,

4a. x= 0 is not possible.

4b. x= 1 is not possible.

5a. (9x-5)(9x+5)

5b. (x-3)(2x+1)

6. 1/(3x-7)

7a. x = (-5,∞)

7b. x = (∞,2]

7c. x = (-3,7]

A mathematical expression is a phrase that has a minimum of two numbers or variables and at least one mathematical operation.

Let's examine the writing of expressions.

The other number is x, and a number is 6 greater than half of it.

As a mathematical expression, this proposition is denoted by the expression x/2 + 6.

Here the values of x has to be such that the denominator is not equal to zero.

So, x cannot be zero and x cannot be 1 as these two values in the respective questions will make the denominator zero.

a. 81x²-25

= 81x² + 45x-45x-25

=9x(9x+5)-5(9x+5)

= (9x-5)(9x+5)

b. 2x²-5x-3

= 2x² + x - 6x -3

= x(2x+1)-3(2x+1)

=(x-3)(2x+1)

Next, the intervals for x are as follows:

x = (-5,∞)

x = (∞,2]

x = (-3,7]

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First, note that the degree of the polynomial is the highest power of x that appears in the expression. In this case, the degree is max(n, 5, m, 2).

Next, consider the leading coefficient of the polynomial, which is the coefficient of the term with the highest power of x. In this case, the leading coefficient is a.

Based on this information, here are some possible general shapes of the graph of y=f(x):

If n is even and a > 0, the graph of y=f(x) looks like a "U" shape, with both ends pointing upwards.

If n is even and a < 0, the graph of y=f(x) looks like an upside-down "U", with both ends pointing downwards.

If n is odd and a > 0, the graph of y=f(x) looks like a "v" shape, with the vertex pointing upwards.

If n is odd and a < 0, the graph of y=f(x) looks like an upside-down "v", with the vertex pointing downwards.

Note that these are just general shapes, and the actual graph could be modified by the other terms in the polynomial. Additionally, the values of b, c, d, and the constants could also affect the shape and behavior of the graph.

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Complete Question is : let f(x)=ax^n+bx^5+36/cx^m-dx^2+9 where m and n are integers and a,b,c and d are unknown constants. what is the possible graph of the function?

The speed of the particle is 8 m/s, the force of resistance is [tex]0.3(8)^2[/tex], or 19.2 N.

A particle of mass 1.2 kg is moving with a speed of 8 m/s in a straight line on a horizontal table. A resistance force is applied to the particle in the direction of the motion. The magnitude of the force is proportional to the square of the speed, such that [tex]F=0.3v^2[/tex]

The force of resistance is an opposing force that acts to reduce the speed of the particle. As the particle moves faster, the resistance force increases. The force is proportional to the square of the speed, meaning that if the speed doubles, the force is multiplied by four. The force is also in the same direction as the motion, meaning that it will reduce the speed of the particle.

The equation for the force of resistance is [tex]F=0.3v^2[/tex], where v is the speed of the particle. Therefore, if the speed of the particle is 8 m/s, the force of resistance is [tex]0.3(8)^2,[/tex] or 19.2 N. This means that the force of resistance acting on the particle is 19.2 N.

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Answer:

We can find the point that partitions line segment AB into a 3:6 ratio by using the formula for finding a point that divides a line segment into two parts in a given ratio.

Let's call the point we're looking for "P". According to the formula, the coordinates of point P can be found using the following equations:

x-coordinate of P = [(6 * x-coordinate of A) + (3 * x-coordinate of B)] / 9

y-coordinate of P = [(6 * y-coordinate of A) + (3 * y-coordinate of B)] / 9

Using the coordinates of points A and B given in the problem, we can plug them into these equations and simplify to find the coordinates of point P:

x-coordinate of P = [(6 * -1) + (3 * 2)] / 9 = 0

y-coordinate of P = [(6 * 2) + (3 * 5)] / 9 = 3.33 (rounded to two decimal places)

Therefore, the point that partitions line segment AB into a 3:6 ratio is approximately (0, 3.33), which is closest to option A: 4,5/3.