At the given erro in angle, the error in the measurement of sin 90 degrees would be 0.001.
Percentage errorThe percentage error of any measurement is obtained from the ratio of the error to the actual measurement.
The error of sin 90 degrees is calculated as follows;
sin 90 = 1
error in measurement = sin(90 - 0.5)
error in measurement = sin(89.5) = 0.999
Error in sin 90 degreesError in sin 90 degrees = 1 - 0.999
Error in sin 90 degrees = 0.001
Thus, at the given erro in angle, the error in sin 90 degrees would be 0.001.
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2.3c. What is the frequency of a wave with a length of 12 m that travels at a speed of 36 m/s?
the frequency of the wave is 3
36/12= 3
PLEASE HELP
Which statement about matter is true?
Matter is anything that is made of atoms and that has mass (and volume).
Matter is anything that is made of organic substances and is found on the earth.
Matter is an element.
Matter is a compound
Answer: Matter is anything that is made of atoms and that has mass (A)
Explanation: All everyday objects that can be touched are ultimately composed of atoms. Even you are made of atoms. Anything that you can touch has moving particles unless the object is at absolute zero, which is not possible.
Hope this helps!
Which of the following is not part of the control system? steering wheel exhaust pipe brake accelerator
Answer:
Brakes unevenly adjusted: Brakes pulling in one direction or the other can lead to a skid. Tires with worn tread: Tread is necessary for traction in wet weather
Explanation:
Answer: exhaust pipe
Explanation: It doesn't really control anything so I'm assuming this is the answer
Obtain the potential on the x-axis at x = 0 for the following point charge distributions on the x-axis: 200 μC at x = 20 cm, -300 μC at x = 30 cm and -400 μC at x = 40 cm.
The eletric potential on the x - axis at x = 0 cm for the given three charges is determined as 9 x 10⁶ V.
Electric potentialThe electric potential at a point is the work done in moving a test charge from infinity to a certain point.
Eletric potential at x = 0 cmV(net) = V1 + V2 + V3
[tex]V = - \frac{kq}{r} \\\\V(net) = V_1 + V_2 + V_3\\\\V_{(net)} = -\frac{9\times 10^9 \times 200\times 10^{-6}}{0.2} + \frac{9\times 10^9 \times 300\times 10^{-6}}{0.3}+ \frac{9\times 10^9 \times 400\times 10^{-6}}{0.4}\\\\V_{(net)} = -9\times 10^6 \ + \ 9\times 10^6 \ + \ 9\times 10^6 \\\\V_{(net)} = 9\times 10^6 \ V[/tex]
Thus, the eletric potential on the x - axis at x = 0 cm for the given three charges is determined as 9 x 10⁶ V.
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Why is cellular reproduction important for homeostasis?
It helps cells make oxygen.
It helps cells make glucose.
It removes waste from cells.
It splits a cell into new cell
Answer:
(It was a remove waste from cells)
Explanation:
the cell produces carbon dioxide and water, which are released as waste.
Identify a scenario from
gym class that has an action-reaction force. Describe the situation
Answer:
A person is doing push-ups against a wall (action force), and the wall exerts an equal and opposite force against the person (reaction force).
Explanation:
The diagram shows a box being pulled along a horizontal surface with a force of 200.0 N.
Calculate the work done on the box to pull it a distance of 5.0 m.
Answer:
The formula for work is
W= fd
work= force X distance
so, this is
200 X 5 =1,000
and the unit for work is Joules
so.. 1,000 joules
Explanation:
hope that helps!
What is the average velocity if the initial velocity of an object is 10 and the a final velocity is 28
Answer:
19
Explanation:
Avg. Vel = (28 + 10)/2
= 19
BTW, don't forget your units!
In which of the following situations would an electromagnet be more useful than a magnet? *
1 point
A teacher uses a magnet to attach their name tags to her shirt.
B child is linking magnetic balls together to make a necklace.
C parent is hanging up a good grade on a refrigerator.
D scrapyard worker is sorting car parts.
The answer to your question is: C
the base is a polygon and its faces are triangles (cone, cube, cylinder, pyramid, rectangular prism
please solve the given question
I know the answer but I need explanation also
PLEASE help
R² = F1² + F2² + 2 F1.F2 cos α ⇒cosinus
F1 and F2 perpendicular, α = 90°, cos 90° = 0
[tex]\tt R=\sqrt{3^3+4^2}=5[/tex]
If you place 1 C of positive charge on Earth and 1 C of negative charge on the moon, 384,500 km away, how much force would the positive charge on Earth experience?
Answer:
6.1 x 10^-8 newtons
Explanation:
F = 8.98 *109 *1*1/3845000002
A swimming pool is an example of an open system. Ther pool loses 10.500 J of its thermal energy to the surrounding air at night, and the surrounding air adds 2,500 J of thermal energy to the morning. According to the law of conservation of energy, what is the change in energy
Answer:
2 and a half cows
Explanation:
There are 14 cows and the farmer consumes 10.
His child then slaughters and consumes one and a half cows.
The farmers wife then takes one to the market.
At todays prices, a singular cow is around £1,577, so to answer your question, the family made £1,577 from the one cow the wife sold.
To reduce auto emissions in the United States, modifications to automobile engines have been required since the 1960s.
a) true
b) false
Answer:
True
Explanation:
Multiple choices. 1)when two groups are playing tug of war the forces of the two groups are:- A)same direction B)opposite direction C)different direction but not possible D)A and B
Answer:
Explanation:
Multiple choices. 1)when two groups are playing tug of war the forces of the two groups are:- A)same direction B)opposite direction C)different direction but not possible D)A and B
When a potential difference of 2 volt is applied across the ends of a wire of 5 metre length a current of 1 ampere flows through it,calculate :-
(i) the resistance per unit length of the wire
(ii) the resistance of 2 metre length of the wire
(iii) the resistance across the ends of the wire if it is doubled on itself
[tex]\huge\underline{\red{A}\green{n}\blue{s}\purple{w}\pink{e}\orange{r} ⟿}[/tex]
(i) 0.4 Ω m^-1
(ii) 0.8 Ω
(iii) 0.5 Ω
Explanation:
(i) Given, V = 2 volt, I = 1 AResistance of 5 m length of wire :-
[tex] = > R = \frac{V}{I} = \frac{2}{1} = 2 \: Ω [/tex]
Resistance per unit length of the wire :-
[tex] = > \frac{R}{l} = \frac{2}{5} = 0.4 \: Ω \: {m}^{ - 1} [/tex]
(ii) Resistance of 2m length of the wire~
[tex] = \: 0.4 \: Ω \: {m}^{ - 1} \times 2 \: m = 0.8 \: Ω [/tex]
(iii) When the wire is doubled on itself, its area of cross section becomes twice and the length becomes half. Let a be the initial cross section and ρ be the specific resistance of the material of wire. Then,
[tex]from \ relation \: \: ➪ \: R = ρ \times \frac{1}{a}. \\ \\ we \: have, \\ \\ initial \: resistance \:➪ \: 2 = ρ\times \frac{5}{a}....eqn(i) \\ \\ new \: resistance \: ➪ \: R` = ρ\times \frac{2.5}{2a}....eqn(ii) \\ \\ on \: dividing \: eqn(ii) \: by \: eqn(i)... \\ \\ \frac{R`}{2} = \frac{2.5ρ}{2a} \div \frac{5ρ}{a} = \frac{1}{4} \\ \\ R` = \frac{2}{4} = 0.5 \: Ω[/tex]
Thus, on doubling the wire on itself, its resistance becomes one-fourth.
Hope it helps you!!4. An object has a mass in air of 0.0832 kg, apparent mass in water of 0.0673 kg, and apparent mass in another liquid of 0.0718 kg. What is the specific gravity of the other liquid
Question
4. An object has a mass in air of 0.0832 kg, apparent mass in water of 0.0673 kg, and apparent mass in another liquid of 0.0718 kg. What is the specific gravity of the other liquid
Hold on, our servers are swamped. Wait for your answer to fully load.
Answer:
Explanation:4. An object has a mass in air of 0.0832 kg, apparent mass in water of 0.0673 kg, and apparent mass in another liquid of 0.0718 kg. What is the specific gravity of the other liquid
Which definition refers to electrical power?
A. The rate at which an electric charge flows past a point in a circuit
B. The energy of an electric charge minus the resistance in a circuit
C. The energy of an electric charge due to its position in an electric
field
D. The rate at which electrical energy is transferred in a circuit
A car starts moving from rest; If it gains avelocity of 72km/ht after to seconds what is the acceleration of the car.
Answer:
10 m/s²
Explanation:
Given
u = 0 (initial velocity as it is at rest)v = 72 km/h x 5/18 = 20 m/st = 2sSolving
v = u + at20 = 0 + 2a2a = 20a = 10 m/s²The correct answer is 10 m/s² .
A 2.8 F capacitor and a 3,440
Ω
resistor are connected to a battery of voltage 5 V as shown in the circuit. After
closing the switch, how long will it take for the capacitor voltage to be 45 % of
the battery voltage?
Express your answer in seconds (s)
The time taken for the capacitor voltage to be 45 % of the battery voltage is 5,750.3 s.
Discharge of the capacitor voltage
The rate at which the capacitor voltage discharges is given by the following formula;
[tex]V = V_0(1 - e^{-t/RC})[/tex]
Where;
V₀ is the initial voltageV is the final voltaget is the time of dischargeR is resistanceC is capacitanceThe final voltage = 0.45 x 5 V = 2.25 V
[tex]2.25 = 5(1 - e^{-t/RC})\\\\(1 - e^{-t/RC}) = \frac{2.25}{5} \\\\(1 - e^{-t/RC}) = 0.45\\\\e^{-t/RC} = 1- 0.45\\\\e^{-t/RC} = 0.55\\\\\frac{-t}{RC} = ln(0.55)\\\\\frac{-t}{RC} = -0.597\\\\t = 0.597 (RC)\\\\t = 0.597(3440 \times 2.8)\\\\t = 5,750.3 \ s[/tex]
Thus, the time taken for the capacitor voltage to be 45 % of the battery voltage is 5,750.3 s.
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Which of the following is true about how pressure varies with depth in a fluid? a. Pressure decreases with depth because it must support the fluid weight above it. b. Pressure increases with depth because it must support the fluid weight above it. c. Pressure decreases with depth because it is supported by the fluid weight below it. d. Pressure increases with depth because it is supported by the fluid weight below it.
Answer:
b) pressure increases with depth because of the weight of the fluid above
P = ρ g H density * gravity * fluid depth
(Note - force from the fluid below is an example of Newton's Third Law - for every action there is an equal and opposite reaction)
how do i turtle answer fast
Answer:
Take your TIme maaaaaan
Explanation:
Chillax
Here's a question for you Care to go bowling?
Answer:
By taking it Slow.
Don't go too fast
A 3.0-kg block moves up a 40° incline with constant speed under the action of a 26-N force acting up and parallel to the incline. What magnitude force must act up and parallel to the incline for the block to move down the incline at constant velocity?
Explanation:
Sooooo, first,
Constant Speed means that the body isn't accelerating.
a= 0
Let the force that causes it to move up the incline be P and Q be the force that causes the body to move down the incline. Let Fr be the frictional force.
The force that pulls the body downwards is given by,
F = mgsin40°
F= 18.898N
P -(F+Fr) = ma, but, a= 0
P = F + Fr
Fr = 26-18.898
= 7.102N
If the block must move down the incline, Q and Fr will act in the same direction.
Q + Fr = F
Q = 11.796N
A rugby player sits on a scrum machine that weighs 200 Newtons. Given that the coefficient of static friction is 0.67, the coefficient of kinetic friction is 0.56 and the force required to push both the scrum machine and the player into motion is 850 Newtons, calculate the following: a) The mass of the player ( 4marks) b) The magnitude of the force required to keep both the scrum machine and the player in motion?
a. 850 N is the minimum force needed to get the machine/player system moving, which means this is the maximum magnitude of static friction between the system and the surface they stand on.
By Newton's second law, at the moment right before the system starts to move,
• net horizontal force
∑ F[h] = F[push] - F[s. friction] = 0
• net vertical force
∑ F[v] = F[normal] - F[weight] = 0
and we have
F[s. friction] = µ[s] F[normal]
It follows that
F[weight] = F[normal] = (850 N) / (0.67) = 1268.66 N
where F[weight] is the combined weight of the player and machine. We're given the machine's weight is 200 N, so the player weighs 1068.66 N and hence has a mass of
(1068.66 N) / g ≈ 110 kg
b. To keep the system moving at a constant speed, the second-law equations from part (a) change only slightly to
∑ F[h] = F[push] - F[k. friction] = 0
∑ F[v] = F[normal] - F[weight] = 0
so that
F[k. friction] = µ[k] F[normal] = 0.56 (1268.66 N) = 710.45 N
and so the minimum force needed to keep the system moving is
F[push] = 710.45 N ≈ 710 N
brainly an andean condor with a wingspan and a mass soars along a horizontal path. model its wings as a rectangle with a width. determine the difference between the pressure at the top surfaces of the condor's wings and the pressure at the bottom surfaces brainly
The difference between the pressure at the top surfaces of the condor's wings and the pressure at the bottom surfaces is 101,204 Pa.
Difference in pressure between the top and bottom of the wingspanThe difference in pressure between the top and bottom of the wingspan is calculated as follows;
ΔP = P(top) - P(bottom)
Area of the wingspanA = bh
A = 2.7 m x 0.27 m
A = 0.729 m²
Weight of the Andean condorW = mg
W = 9 x 9.8
W = 88.2 N
Pressure at the top surface of condor's wingsThe pressure at the top surface of condor's wings is due to atmospheric pressure
P(top) = 14.7 Psi = 101,325 Pa
Pressure at the bottom surface of condor's wingsThe pressure at the bottom surface is due to weight of andean condor.
P = W/A
P(bottom) = 88.2/0.729
P(bottom) = 120.99 Pa
The difference between the pressure at the top surfaces of the condor's wings and the pressure at the bottom surfaces is calculated as;
ΔP = P(top) - P(bottom)
ΔP = 101,325 Pa - 120.99 Pa
ΔP = 101,204 Pa
The complete question is below;
An Andean condor with a wingspan of 270 cm and a mass of 9.00 kg soars along a horizontal path. Model its wings as a rectangle with a width of 27.0 cm.
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Calculate the solar angle for the day at 10am and 2pm individually for the location of 21.23 south latitude on the 18th march 1993 (Assume it is non leap year)
Based on the latitude and time of the place, the solar angle for the day at 10am and 2pm is 51.6° and 73.0°.
What is the solar hour angle?The solar hour angle of a point on the earth’s surface is the angle through which the earth would turn to bring the meridian of the point directly under the sun.
The rotation of the earth on its axis is 15° per hour where before noon is negative and after noon is positive. For example, at 10:00 a.m. local apparent time the hour angle is −30°.
Therefore, based on the latitude and time, the solar angle for the day at 10am and 2pm is 51.6° and 73.0°.
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HELP PLS! Mrs. Frazier was on a jet ski traveling 25 km/min NE in Lake Norman last weekend. She started slower at 5 km/min but within 5 mins she had increased her speed. What was her acceleration?
21 km/hr
4 km/min2
100 km/min
6.2 km/hr
Answer:
4 km/min^2
Explanation:
acceleration is the rate of change of speed per time
25 -5 = 20 km/min speed change
20 km/min / 5 min = 4 km /min^2
T F
Organisms get energy from food
Answer:
It's true that organisms get energy from food.
Answer:
Explanation:
Organisms ingest large molecules, like carbohydrates, proteins, and fats, and convert them into smaller molecules like carbon dioxide and water. This process is called cellular respiration, a form of catabolism, and makes energy available for the cell to use
PLSSSS HELPPPP ASAPPP
A fluorescent light bulb produces just as much light in the same electrical circuit as an incandescent bulb , but requires much less energy to produce it. Which of the following is the most logical explanation for this?
A. The incandescent bulb produces more forms of energy than just light, like heat.
B. The fluorescent light bulb produces more light than any other bulb.
C. The incandescent bulb has to be connected to another circuit.
D. The fluorescent light bulb generates more current than any other type.
Answer:
The most logical explanation is A.
Explanation:
because we are explaining why the incandescent bulb uses less energy we can eliminate answers B and D then, because we are talking about energy efficiency which has nothing to do with connecting to another circuit we can go with, A because Ultraviolet light generated by fluorescent light bulbs is nothing compared to the heat of an incandescent light bulb because it was engineered to be so.
An 80.0 kg merry-go-round of radius 1.20 m is accelerating horizontally from rest by a constant force of 70.0 N applied tangentially to the merry-go-round. Find the kinetic energy of the merry-go-round after 5.00 s. (Assume it is a solid cylinder.)
The kinetic energy of the merry-go-round after 5.00 s, when a constant force is applied tangentially to it, is determined as 3,069.5 J.
Conservation of angular momentumThe kinetic energy of the merry-go-round is determined by applying the principle of conservation of angular momentum as follows;
Iα = rF
where;
I is moment of inertia of the merry-go-round (solid cylinder)I = ¹/₂mr²
I = ¹/₂ x 80 x (1.2)²
I = 57.6 kgm²
α = (rF)/I
α = ( 1.2 x 70) / (57.6)
α = 1.46 rad/s²
Tangential acceleration of the merry-go-rounda = αR
a = 1.46 x 1.2
a = 1.752 m/s²
Velocity of the merry-go-roundThe velocity of the merry-go-round after 5 s is calculated as follows;
v = u + at
v = 0 + (1.752x 5)
v = 8.76 m/s
Kinetic energy of the merry-go-roundK.E = ¹/₂mv²
K.E = ¹/₂ x 80 x 8.76²
K.E = 3,069.5 J
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