I need the answers asap pls

Answer:

The radius is 3 and it is the same all around

Step-by-step explanation:

Since The hypotenuse equals the two other sides squared, let's find out what those are.

[tex]\sqrt{9} + \sqrt{9} = \sqrt{18}[/tex]

Now, let's find the square root of those 9s.

[tex]\sqrt{9} = 3[/tex]

Those other sides we talked about (more specifically the base of the triangle) are the radius of the circle because of how they extend to the exterior of the circle, which means since their length is 3, the radius is also 3.

The radius is always constant so it is supposed to be the same all around.

Starting time:-

Now

Ending time:-

Total active time:-

Or

Answer:

2 hours 8 minutes

Step-by-step explanation:

Let the total amount of time of Annabeth's being on the computer be x hours

since she paused using computer for a snack break for 30 minuted, our x turns out to be

[tex]x+0:30[/tex]

Thus our equation would like

solving the equation yields:

[tex]1:09+x+0:30=3:47\\\implies 1:39+x=3:47\\\implies x=3:47-1:39\implies \boxed{x=2:08}\rm hours [/tex]

hence,

Annabeth was on her computer for 2 hours 8 minutes

Note:

The other possibilities include that she chooses at least one book that is not a mystery; this means the complement is not choosing all mysteries.

Probability refers to a possibility that deals with the occurrence of random events. The probability of all the events occurring need to be 1.

The formula of probability is defined as the ratio of a number of favorable outcomes to the total number of outcomes.

P(E) = Number of favorable outcomes / total number of outcomes

Mariah is randomly choosing three books to read from the following: 5 mysteries, 7 biographies, and 8 science fiction novels.

The complement of an event is the remaining possibilities.

Our event is Mariah choosing 3 mysteries.

The other possibilities include that she chooses at least one book that is not a mystery; this means the complement is not choosing all mysteries.

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Answer:

Options:

A- There are 20C3 possible ways to choose three books to read.

B- There are 5C3 possible ways to choose three mysteries to read.

E- The probability that Mariah will not choose all mysteries can be expressed as 1 − StartFraction 5 C 3 Over 20 C 3 EndFraction.

Step-by-step explanation:

Answer:

d

Step-by-step explanation:

god a 100 on edg

ΔABC cannot be congruent to ΔADC by SSS?l because D. No, because AB ≅ DA.

It should be noted that when the three corresponding sides of the figures have the same length, it can be concluded that the triangles are congruent by SSS.

In this case, ΔABC cannot be congruent to ΔADC by SSS?l because AB is not equal to DA.

Therefore, the correct option is D.

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Answer:

6 and 7

Step-by-step explanation:

Answer: a) 6 and 7

Step-by-step explanation:

The square root of 48 is 6.928… so it’s between those two numbers

The value of the variable x for the provided equation  –9x 1 = –x 17 when it is solved, is -2. Option 2 is correct.

The solution of an equation is the value of the variable of the equation, for which the equation is satisfied.

The equation given in the problem is,

[tex]-9x +1 = -x +17\\[/tex]

To solve this equation, take the terms of variable x left side of the equation and constant term other side,

[tex]-9x +x = 17-1\\-8x=16[/tex]

Divide both side of the equation with number 8 as,

[tex]\dfrac{-8x}{8}=\dfrac{16}{8}\\-x=2\\x=-2[/tex]

Hence, the value of the variable x for the provided equation  –9x 1 = –x 17 when it is solved, is -2. Option 2 is correct.

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Answer: The Answer Is; B) x = –2

Step-by-step explanation: Correct Answer On Edge2020.

(And the correct way to write the equation is; –9x + 1 = –x + 17 , other wise others wouldn't know if it was " +'s " OR " -'s " ..)

The equations which have a leading coefficient of 3 and a constant term of –2 are 0 = 3x² +2x - 2 and 0=3x²-1x-2.

A quadratic equation is the equation in which the unknown variable is one and the highest power of the unknown variable is two.

The standard form of the quadratic equation is,

[tex]ax^2+bx+c=0[/tex]

Here,(a,b, c) is the real numbers and (x) is the variable.In this equation, a is the coefficient of the highest term and c is the constant term.

The equations which has the leading coefficient of 3 and a constant term of –2 has to be find out.

The first equation given in the problem is,

[tex]0 = 3x^2 +2x - 2[/tex]

In this equation, the coefficient of the term which has the highest power is 3 and the constant term is -2. Thus, this option is correct.

The second equation given in the problem is,

[tex]0 = -2 - 3x^2 +3[/tex]

Rearrange the equation as,

[tex]0 = -2 - 3x^2 +3\\0=-3x^2+1[/tex]

In this equation, the coefficient of the term which has the highest power is -3 and the constant term is 1. Thus, this option is not correct.

The third equation given in the problem is,

[tex]0 = 3x^2 +x +2[/tex]

In this equation, the coefficient of the term which has the highest power is 3 and the constant term is 2. Thus, this option is not correct.

The fourth equation given in the problem is,

[tex]0 = -1x - 2 +3x^2[/tex]

Rearrange the equation as,

[tex]0=3x^2-1x-2[/tex]

In this equation, the coefficient of the term which has the highest power is 3 and the continuant term is -2. Thus, this option is correct.

Hence, the equations which have a leading coefficient of 3 and a constant term of –2 are 0 = 3x² +2x - 2 and 0=3x²-1x-2.

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The railroad crew repair 1500 km in 25 days if the railroad crew can replace 360 meters of rails in 6 days

Fraction number consists of two parts one is the top of the fraction number which is called the numerator and the second is the bottom of the fraction number which is called the denominator.

We have:

A railroad crew can replace 360 meters of rails in 6 days.

Let's suppose the x kilometers of rail they can repair in 25v days

Per day they repair = 360/6 = 60 km/day

Then the x can be found:

x = 60×25

x = 1500 km

Thus, the railroad crew repair 1500 km in 25 days if the railroad crew can replace 360 meters of rails in 6 days.

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Answer:

PX = 10

Step-by-step explanation:

PR = 20

PX = PR/2 (diagonals of parallelogram bisect eachother)

or, PX = 20/2

so, PX = 10

The 3 rules that we need to use to simplify the expression are:

As I understand, the expression that we have is:

[tex]\frac{((-8)^4)^{-5}}{(-8)^6}[/tex]

The first rule we need to use, is the exponent of an exponent rule, it says that:

[tex](a^n)^m = a^{n*m}[/tex]

If we apply that to the denominator, we get:

[tex]\frac{((-8)^4)^{-5}}{(-8)^6} = \frac{(-8)^{-20}}{(-8)^6}[/tex]

Now we need to use the quotient of powers:

[tex]\frac{a^m}{a^n} = a^{m - n}[/tex]

Using that we get:

[tex]\frac{((-8)^4)^{-5}}{(-8)^6} = \frac{(-8)^{-20}}{(-8)^6} = (-8)^{-20 - 6} = (-8)^{-26}[/tex]

Finally, we use the rule for a negative exponent:

[tex]a^{-n} = \frac{1}{a^n}[/tex]

So we get the simplified form:

[tex]\frac{((-8)^4)^{-5}}{(-8)^6} = \frac{(-8)^{-20}}{(-8)^6} = (-8)^{-26} = \frac{1}{(-8)^{26}}[/tex]

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Answer:

B, C, and E

Step-by-step explanation:

Answer:

  52°

Step-by-step explanation:

The sum of an angle and its complement is 90°.

__

The sum of 38° and its complement, x, is 90°:

  38 +x = 90 . . . . . an equation to find the complement of 38°

  x = 90 -38 . . . . subtract 38 from both sides

  x = 52 . . . . degrees

The measure of x is 52°.

option 3

center (-1,-5)

radious √41

hope this helped!

Answer:

[tex]\displaystyle (x,y) \longrightarrow (x+3, y+1)[/tex]

Step-by-step explanation:

We want to write a rule for the transformation shown.

We can see that ΔA'B'C' is the figure ΔABC shifted rightwards 3 units and upwards 1 unit.

In other words, all x-coordinates of ABC is increased by 3, and all y-coordiantes of ABC is increased by 1.

Therefore, the rule for the x-coordinate is:
[tex]\displaystyle x \longrightarrow x + 3[/tex]

And the rule for the y-coordinate is:

[tex]\displaystyle y \longrightarrow y + 1[/tex]

In conclusion, we have that:

[tex]\displaystyle (x,y) \longrightarrow (x+3, y+1)[/tex]

Answer:

16% or 16.9492% I'm going to be honest I'm not 100% sure though

Answer:

B) -2

Step-by-step explanation:

[tex]log_{6} \frac{1}{36}[/tex]                           ORIGINAL

[tex]log_{6} 6^{-2}[/tex]                          REWRITE  1/36

-2                                  LOG RULE - 6's CANCEL

Hope this helsp!

Answer:

8 x 8 x 8 = 512

Step-by-step explanation:

Hope this helps! Have a great day :)

Answer:

512

Step-by-step explanation:

LxWxH

8x8x8=512

The equation in slope-intercept form of the line that passes through the point (2,-2) and is perpendicular to the line represented by y = x + 2 is y = -1/2 - 3

The equation of a line in slope intercept form is expressed as:

y = mx + c

m is the slope

c is the intercept

Given the equation of a line y = x + 2, the slope of the line perpendicular is -1/2. If this line pass through the point (2, -2), the required equation will be

y - (-2) = -1/2(x+2)
2(y+2) = -(x+2)
2y + 4 = -x - 2

2y = -x - 6
y = -1/2 - 3

Hence the equation in slope-intercept form of the line that passes through the point (2,-2) and is perpendicular to the line represented by y = x + 2 is y = -1/2 - 3

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The inequality in both inequality expressions is the less than or equal to sign

Inequality 1

The inequality is given as:

[tex]-1 \le \frac x2[/tex]

Multiply both sides by 2

[tex]-2 \le x[/tex]

Rewrite as:

[tex]x \ge - 2[/tex]

The above means that the correct values of x are at least -2.

See attachment for the complete table is as follows:

Inequality 2

The inequality is given as:

[tex]1 \le \frac {-x}2[/tex]

Multiply both sides by 2

[tex]2 \le -x[/tex]

Rewrite as:

[tex]-x \ge 2[/tex]

Multiply both sides by -1

[tex]x \le -2[/tex]

The above means that the correct values of x are at most -2.

See attachment for the complete table is as follows:

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The approximate area of the decagon with a side of 8cm is 492.37 cm².

Given side of the regular decagon = 8cm

A decagon is a polygon with 10 equal sides.

We know that area of a regular decagon with side a is given by:

[tex]A=\frac{5}{2} a^{2} \sqrt{5+2\sqrt{5} }[/tex]

So, the area A of the regular decagon with a side of 8cm=[tex]\frac{5}{2} 8^{2} \sqrt{5+2\sqrt{5} }[/tex]

[tex]A=160\sqrt{5+2\sqrt{5} }[/tex]

A=492.37 cm²

Therefore, the approximate area of the decagon is 492.37 cm².

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Answer:

r= 0.402

Step-by-step explanation:

The questions are illustrations of inequalities

The inequality is given as:

x² - 18x < -77

Add 77 to both sides

x² - 18x + 77 < 0

Expand the inequality

x² - 7x - 11x + 77 < 0

Factorize the inequality

x(x - 7) - 11(x - 7) < 0

Factor out x - 7

(x- 7)(x - 11) < 0

Solve for x

x < 7 or x < 11

This means that the solution to the inequality is 7 < x < 11

The inequality expression is given as:

y ≤ x² + 2

See attachment for the graph of the inequality

The function is given as:

f(x) = |x| + 5

The smallest value of |x| is 0.

So, we have:

f(x) > 0 + 5

Evaluate

f(x) > 5

Hence, the range of the function is (c) R: {f(x) ∈ ℝ | f(x) > 5}

The inequality expression is given as:

|2x + 3| < 7

Remove the absolute expression

2x + 3 < 7 or 2x + 3 < -7

Subtract 3 from both sides

2x < 4 or 2x < -10

Divide both sides by 2

x < 2 or x < -5

Hence, the solution to the inequality is x < –5 or x > 2

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The best measure of centre is the mean , don't take median as we need average of marks here.

Mean of Lamar

Mean of Mimi

Mimi has been better

Answer:

Option A :- if finding lateral surface area

Other information

radius r = 6 m

height h = 8 m

slant height s = 10 m

volume V = 301.592895 m3

lateral surface area L = 188.495559 m2

base surface area B = 113.097336 m2

total surface area A = 301.592895 m2

Step-by-step explanation:

Using the formulas

A=πrl+πr²

l=√r²+h²

Solving forA

A=πr(r+√h²+r²)=π · 6 · (6+√8²+6²)≈301.59289

The final answer of the solution is x∈ (-13,1) ∪ [1, 15 ] or, x∈(-13, 15] and x∈ (-∞ , 1) ∪ [1, ∞) or, x∈ (-∞, ∞) or x∈ R.

Inequality is defined as the relation which makes a non-equal comparison between two given functions.

For |x - 1 | + 1 < 15 , we should first break the modulus function .

Two cases are possible for this inequality ,

case 1 - when x ≥ 1

x - 1 + 1 < 15 ⇒ x < 15

putting the number line both x ≥ 1 and x≤ 15

Then, x∈ [1, 15)

case 2 - when x < 1

-x + 1 + 1 < 15

⇒ -x + 2 < 15

⇒ -x < 13 ⇒ x > -13

putting the number line both x > -13 and x < 1

then, x∈ (-13, 1)

now, answer is x∈ (-13,1) ∪ [1, 15 ] or, x∈(-13, 15]

Again, for |x - 1| + 1 > 15

Similarly z there are two cases possible for this

case 1 :- when x ≥ 1

x - 1 + 1 > 15 ⇒ x > 15

Putting the number line both x ≥ 1 and x > 15

then, x ∈ [1, ∞)

case 2 - when x < 1

-x + 1 + 1 > 15 ⇒ x < -13

putting the number line both x < 1 and x < -13

Then, x∈ (-∞, 1)

hence, final answer is x∈ (-∞ , 1) ∪ [1, ∞) or, x∈ (-∞, ∞) or x∈ R

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Answer:

a club has 2 dollar down payment and 4 $ per week how much money is owed after 2 weeks

Step-by-step explanation:

Total money Tammy has = $70

Money she is left with now = $19.54

Therefore, the money she used on coffee =

70 - 19.54 = $50.46

Now,

1 pound coffee costs $8.41

Pounds of coffee she bought = 50.46 ÷ 8.41

= 6 pounds

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

Let's see what's the domain and range for the given function ~

[tex]\qquad \tt \dashrightarrow \:domain \in [ -5 , 4 ] [/tex]

or

[tex]\qquad \tt \dashrightarrow \: - 5 \leqslant x \leqslant 4[/tex]

Because domain = all values of x between its maximum (4) and minimum (-5) value [ including them ]

[tex]\qquad \tt \dashrightarrow \:range \in[ -4 , 9 ][/tex]

or

[tex]\qquad \tt \dashrightarrow \: - 4 \leqslant y \leqslant 9[/tex]

Because range = all values of y between its maximum (9) and minimum (-4) value [ including them ]

The derivative of a function may be used to determine whether the function is increasing or decreasing on any intervals in its domain. If f′(x) > 0 at each point in an interval I, then the function is said to be increasing on I. f′(x) < 0 at each point in an interval I, then the function is said to be decreasing on I.

Answer:

x∈(-∞; 0).

Step-by-step explanation:

1) the given function is a parabola with its vertex in (0;0). Then

2) the increasing interval is (0:+∝), decreasing interval is (-∝;0).