How to solve this problem?

Answers

Answer 1

Answer:

301

Step-by-step explanation:

You want a number that has a remainder of 1 when divided by 2, 3, 4, 5, or 6, and has a remainder of 0 when divided by 7.

LCM

If 1 is subtracted from the number of eggs, the remaining number will be an even multiple of 2, 3, 4, 5, 6. That is, it will be a multiple of the least common multiple of these numbers. That LCM will be ...

LCM(LCM(6, 5), 4) . . . . . . 6 is already a multiple of 2 and 3

= LCM((6·5/GCF(6, 5)), 4) = LCM(30, 4)

= (30·4)/GCF(30, 4) = 120/2 = 60

Multiple of 7

The number of eggs will be 1 more than a multiple of 60 that is a multiple of 7.

We only need to try multiples of 60 up to 7×60. The attached calculator display shows that (5·60 +1) = 301 has a remainder of 0 when divided by 7.

The number of eggs in the cart is 301.

Additional comment

The answer can be found by solving the Diophantine equation 7m -60n = 1. Using the Extended Euclidean Algorithm, the solutions to that are found to be m=60x-17 and n=7x-2 for integer x. The value x=1 gives (m, n) = (43, 5), or 301 -300 = 1. The next higher value for 7m is 721.

Related Questions

find the steady state response value yss and the steady state error value ess for the systems in figures 5.74 a,b, 5.75, 5.76 for unit step, unit ramp, and unit parabolic inputs.

Answers

Plug the corresponding R(s) for each input type and the transfer functions of the given systems into the equations above to find yss and ess for each case. Keep in mind that some systems might not have a finite steady-state response or error for specific input types, depending on the system's type (order and poles).

To determine the steady-state response (yss) and steady-state error (ess) values for the given systems, we need to use their transfer functions and input types (unit step, unit ramp, and unit parabolic). Unfortunately, without information about the specific transfer functions for figures 5.74 a, b, 5.75, and 5.76, it is not possible to provide a definitive answer.

In general, for a system with transfer function G(s), you can calculate the steady-state response and error using the Final Value Theorem:

yss = lim (s -> 0) s * Y(s), where Y(s) = G(s) * R(s) is the system's output.
ess = lim (s -> 0) s * E(s), where E(s) = R(s) - Y(s) is the system's error.

For different input types:
- Unit step input: R(s) = 1/s
- Unit ramp input: R(s) = 1/s^2
- Unit parabolic input: R(s) = 1/s^3

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you have taken up gardening for relaxation and have decided to fence in your newrectangular shaped masterpiece. the length of the garden is 4 meters and 52 meters offencing is required to completely enclose it. what is the width of the garden?

Answers

If the length of the garden is 4 meters and 52 meters of fencing is required to completely enclose it, the width of the garden is 22 meters.

To find the width of the garden, we need to use the formula for the perimeter of a rectangle, which is:

P = 2l + 2w

Where:

P = perimeter of the rectangle

l = length of the rectangle

w = width of the rectangle

We know that the length of the garden is 4 meters and the perimeter is 52 meters, so we can plug in the values and solve for the width:

52 = 2(4) + 2w

52 = 8 + 2w

44 = 2w

w = 22

To verify our answer, we can check if the perimeter using this width is indeed 52 meters:

P = 2l + 2w = 2(4) + 2(22) = 8 + 44 = 52

As expected, the perimeter is 52 meters. This means that if we fence in the garden with a width of 22 meters and a length of 4 meters, we will require 52 meters of fencing to completely enclose it.

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what is $510,451 rounded to the nearest 1,000 dolllars?

Answers

Answer:

$510,000

Step-by-step explanation:

Since we are rounding to the nearest thousand, we can use the hundreds place to determine the if we need to round down or up.

Remember, 4 or less, round down. 5 or more, round up.

Since the hundreds digit is 4, we do not need to round.

We only need to change the rest of the digits to 0.

So, our answer would be $510,000.

Geometry, and Slope. Worth 15 Points
Please Explain

Answers

The equation of the line perpendicular to the line QR in slope intercept is y= [tex]\frac{1}{2}x+\frac{7}{2}[/tex].

Given,

x+2y=2

y = 1 - [tex]\frac{x}{2}[/tex]

Slope = -1/2 = [tex]m_{1}[/tex]

Let Slope of line perpendicular to line x+2y=2 is [tex]m_{2}[/tex]

⇒ [tex]m_{1}[/tex] * [tex]m_{2}[/tex] = -1

Then [tex]m_{2}[/tex] = 1/2

Equation of line perpendicular is given by

[tex]y = \frac{1}{2}x + c[/tex]

Since it contains point (5,6)

6 = [tex]\frac{1}{2} (5) + c[/tex]

c= [tex]\frac{7}{2}[/tex]

Then the equation of line is:

[tex]y = \frac{1}{2}x+ \frac{7}{2}[/tex].

Therefore, the equation of the line perpendicular to the line QR in slope intercept is y= [tex]\frac{1}{2}x+\frac{7}{2}[/tex].

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2. Kathy can run 2 miles to the beach in the same amount of time Dennis can ride his bike 10 miles to work. Kathy runs 8 mph slower than Dennis rides his bike. Find their speeds

Answers

Kathy's speed is 2 mph and Dennis's speed is 2+8 = 10 mph.

Let's assume that Kathy's speed is "x" mph. Since Dennis rides 8 mph faster than Kathy, his speed is "x+8" mph.

We know that Kathy can run 2 miles to the beach in the same amount of time Dennis can ride his bike 10 miles to work. Therefore, we can use the formula:

time = distance/speed

For Kathy: time = 2 miles / x mph

For Dennis: time = 10 miles / (x+8) mph

Since they both take the same amount of time, we can set these two equations equal to each other:

2 / x = 10 / (x+8)

We can then solve for "x" as follows:

2(x+8) = 10x

2x + 16 = 10x

16 = 8x

x = 2 mph

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A random survey of enrollment at 35 community colleges across the United States yielded the following figures:
6,414; 1,550; 2,109; 9,350; 21,828; 4,300; 5,944; 5,722; 2,825; 2,044; 5,481; 5,200; 5,853; 2,750; 10,012; 6,357; 27,000; 9,414; 7,681; 3,200; 17,500; 9,200; 7,380; 18,314; 6,557; 13,713; 17,768; 7,493; 2,771; 2,861; 1,263; 7,285; 28,165; 5,080; 11,622.
Assume the underlying population is normal.
a.
i. = __________
ii. sx = __________
iii. n = __________
iv. n – 1 = __________
b. Define the random variables X and in words.
c. Which distribution should you use for this problem? Explain your choice. d. Construct a 95% confidence interval for the population mean enrollment at community colleges in the United States.
i. State the confidence interval.
ii. Sketch the graph.
iii. Calculate the error bound.
e. What will happen to the error bound and confidence interval if 500 community colleges were surveyed? Why?

Answers

The larger sample size also reduces the impact of individual outliers, which could potentially skew the results. Therefore, increasing the sample size will result in more reliable results, and a smaller error bound and confidence interval.

The error bound (E) for the sample size of 35 community colleges is calculated using the formula: E =[tex]1.96 * √[p*(1-p)/n].[/tex]

With n = 35, p = 0.5 (assuming the mean of the enrollment figures is 0.5), the error bound is calculated to be E = 0.823.

If the sample size is increased to 500 community colleges, the error bound would be reduced to 0.338. This is because the larger the sample size, the smaller the error bound. The confidence interval would also be reduced, since it is directly proportional to the error bound.

In practical terms, a larger sample size means more reliable results. This is because when the sample size is increased, the results tend to be more representative of the entire population, leading to more accurate conclusions.

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the intersection of two events a and b is the event that: a) both a and b occur. b) the union of ac and bc occurs. c) the union of a and b does not occur. d) either a or b or both occur. e) either a or b, but not both. f) none of the above.

Answers

The intersection of two evens a and b is the event that both a and b occur that is option A is correct.

The intersection of two events A and B is defined as the event that occurs when both A and B occur simultaneously. It is denoted by A ∩ B, where the symbol ∩ represents intersection.

For example, if event A is "getting a head when flipping a coin" and event B is "rolling a 6 on a fair die", then the intersection of A and B would be the event "getting a head when flipping a coin and rolling a 6 on a fair die".

For example, suppose A represents the event "rolling an even number on a dice" and B represents the event "rolling a number greater than 3 on a dice". The intersection of A and B is the event that "rolling a number that is both even and greater than 3 on a dice", which consists of the outcomes {4, 6}.

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Complete Question:

the intersection of two events a and b is the event that:

a) both a and b occur.

b) the union of ac and bc occurs.

c) the union of a and b does not occur.

d) either a or b or both occur.

e) either a or b, but not both.

f) none of the above.

Algebraic Inequalities
Help pls need assistance
DUE today in

Answers

Answer:

8, 8.001, 8.01, 8.1, 9, 11, 13, 16

Step-by-step explanation:

From the instructions given, we know that variable u [tex]\geq[/tex] 8. the [tex]\geq[/tex] sign means that the number is greater than or is equal to the number, which is in this case, 8. In the numbers given, (0, 7, 7.999, 8.01, 11, 3, 7.9, 8, 8.1, 13, 5, 7.99, 8.001, 9, 16) we name the numbers greater than or equal to 8 that are stated in the list.

antonio rolls the 10-sided die from the example. what is the probabilty of rolling a number 10 or less? a number greater than 10

Answers

The probability of rolling a number 10 or less is 1, and the probability of rolling a number greater than 10 is 0.

The 10-sided die has 10 faces, each marked with a unique number from 1 to 10. When we talk about the probability of rolling a particular number, we're asking what the chances are of that number coming up when the die is rolled.

In this case, the question asks for the probability of rolling a number 10 or less, which means we're interested in the probability of rolling any number from 1 to 10. Since all the possible outcomes are numbers from 1 to 10, the probability of rolling a number 10 or less is certain, or 1.

This is because the sum of probabilities of all possible outcomes of an experiment is always 1.

Similarly, the probability of rolling a number greater than 10 is impossible, or 0. This is because there are no possible outcomes greater than 10 on the 10-sided die. In general, the probability of an event that cannot occur is always 0.

So, the probability of rolling a number 10 or less is 1, and the probability of rolling a number greater than 10 is 0.

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Please help :( I don't quite understand...

Answers

Step-by-step explanation:

For Part A, use the function f(x) to find the average of tests taken.

X is number of test taken

f(x) is the average score given said num of tests taken,x,

We want after test number 3 so using the function,

[tex]f(x) = 0.2x + 79[/tex]

Plug in. 3 for x, and we will get our answer.

[tex]f(3) = 0.2(3) + 79 = 79.6[/tex]

Part B: Use the table for the answer.

When 2 test are taken, the average test score is

So part B is 84.

Part C:

[tex]f(2) = 0.2(2) + 79 = 79.4[/tex]

[tex]g(2) = 84[/tex]

Since

[tex]g(2) > f(2)[/tex]

The science class had a higher average after 2 tests

Answer:

you shoulda payed attention in class

Step-by-step explanation:

also u know it's bad when the test is so hard you can't even cheat on it

there are 3 soccer games in a month, and 8 are played at night. the season is 4 months. how many games are the season?

Answers

There are a total of 48 soccer games in the season.

Since there are 3 soccer games in a month, there will be 12 games in a season (3 games/month x 4 months). Since 8 games are played at night and assuming that all games are played either during the day or at night, we can calculate the number of games played during the day as:

Number of day games = Total number of games - Number of night games

= 12 games/month x 4 months - 8 night games/month x 4 months

= 48 games - 32 games

= 16 games

Therefore, the total number of games in the season is:

Total number of games = Number of day games + Number of night games

= 16 games + 32 games

= 48 games

So, there are 48 soccer games in the season.

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The graphs of line a and b are shown in this coordinate grid
Match each line with it's equation. Drag each equation to the corresponding box for each line

Answers

The correct option for the given graph is option 1 and option 3. The equation matches the intersection point (1,1).

For option 1: intersection point (1,1)