Answer:
Shallow foundations, often called footings, are usually embedded about a metre or so into soil. ... Another common type of shallow foundation is the slab-on-grade foundation where the weight of the structure is transferred to the soil through a concrete slab placed at the surface.
Explanation:
Because I said so.
Think about a good game story that made you feel a mix of positive and negative emotions. What was the story, what emotions did you feel, and how did it make you feel them? Why did those emotions draw you into the story?
3.94 x 105) + (2.04 x 105)
Which of the following best describes empathy?
the understanding of the feelings and beliefs of others
the lack of pride or boastfulness
the courage to speak up with one’s ideas
the possession of honesty and high morals
Answer:
the first one is the correct answer
Answer:
the first one would be correct
Explanation:
What is a computer ? Does it work or not I’m asking this Bc I’m stupid
Answer:
A computo is a box and it works really well if its good
Find the volume of the rectangular prism
9 cm
10 cm
Answer:
V= 90h cm³ where h is the height of the rectangular prism.
Explanation:
The formula for volume of a rectangular prism is ;
V=l*w*h where;
V=volume in cm³
l= length of prism=10cm
w =width of the prism = 9 cm
Assume the height of the prism as h cm then the volume will be;
V= 10* 9*h
V= 90h cm³
when the value of height of the prism is given, substitute that value with h to get the actual volume of the prism.
Shania has started a new job as an app developer. Her first task was to make an old designed for Android available on other platforms. which of the following would make her job easiest and fastest?
2
A spring balance pulls with 5 N on a beam of 0.5 m.
What is the torque at the end of the beam?
Answer:
The torque at the end of the beam is 2.5 Nm
Explanation:
Given;
length of beam, r = 0.5 m
applied force, F = 5 N
The torque at the end of the beam is given by;
τ = F x r
where;
τ is the torque
F is applied force
r is length of the beam
τ = 5 x 0.5
τ = 2.5 Nm
Therefore, the torque at the end of the beam is 2.5 Nm
. On Juan's twenty-sixth birthday, he deposited $7,500 in a retirement account. Each year thereafter, he deposited $1,000 more than the previous year. Using a gradient series factor, determine how much was in the account immediately after his thirty-fifth deposit if
Answer:
$1,783,805
Explanation:
Okay, if we are going to answer thus question efficiently, we need to take time to understand each and every sentence in the question. Hence, from the question we have the following data or information and they are;
1. The initial deposit in which Juan deposited on his 26th birthday = $7500.
2. After the statement in [1] above, Juan decided to be depositing $1000 more than the one he deposited on his 26th birthday.
Therefore, we are given that there is 5% in the interest rate. Thus, after his thirty-fifth deposit he will have;
$7500[90.3203] + [5.516] × $1000 × 200.581] = $1,783,805
Consider a 1.5-m-high and 2.4-m-wide glass window whose thickness is 6 mm and thermal conductivity is k = 0.78 W/m⋅K. Determine the steady rate of heat transfer through this glass window and the temperature of its inner surface for a day during which the room is maintained at 24°C while the temperature of the outdoors is −5°C. Take the convection heat transfer coefficients on the inner and outer surfaces of the window to be h1 = 10 W/m2⋅K and h2 = 25 W/m2⋅K, respectively, and disregard any heat transfer by radiation.
Answer:
The steady rate of heat transfer through the glass window is 707.317 watts.
Explanation:
A figure describing the problem is included below as attachment. From First Law of Thermodynamics we get that steady rate of heat transfer through the glass window is the sum of thermal conductive and convective heat rates, all measured in watts:
[tex]\dot Q_{total} = \dot Q_{cond} + \dot Q_{conv, in} + \dot Q_{conv, out}[/tex] (Eq. 1)
Given that window is represented as a flat element, we can expand (Eq. 1) as follows:
[tex]\dot Q_{total} = \frac{T_{i}-T_{o}}{R}[/tex] (Eq. 2)
Where:
[tex]T_{i}[/tex], [tex]T_{o}[/tex] - Indoor and outdoor temperatures, measured in Celsius.
[tex]R[/tex] - Overall thermal resistance, measured in Celsius per watt.
Now, we know that glass window is configurated in series and overall thermal resistance is:
[tex]R = R_{cond} + R_{conv, in}+R_{conv, out}[/tex] (Eq. 3)
Where:
[tex]R_{cond}[/tex] - Conductive thermal resistance, measured in Celsius per watt.
[tex]R_{conv, in}[/tex], [tex]R_{conv, out}[/tex] - Indoor and outdoor convective thermal resistances, measured in Celsius per watt.
And we expand the expression as follows:
[tex]R = \frac{l}{k\cdot w\cdot d} + \frac{1}{h_{i}\cdot w\cdot d} + \frac{1}{h_{i}\cdot w\cdot d}[/tex]
[tex]R = \frac{1}{w\cdot d}\cdot \left(\frac{l}{k}+\frac{1}{h_{i}}+\frac{1}{h_{o}} \right)[/tex] (Eq. 4)
Where:
[tex]w[/tex] - Width of the glass window, measured in meters.
[tex]d[/tex] - Length of the glass window, measured in meters.
[tex]l[/tex] - Thickness of the glass window, measured in meters.
[tex]k[/tex] - Thermal conductivity, measured in watts per meter-Celsius.
[tex]h_{i}[/tex], [tex]h_{o}[/tex] - Indoor and outdoor convection coefficients, measured in watts per square meter-Celsius.
If we know that [tex]w = 2.4\,m[/tex], [tex]d = 1.5\,m[/tex], [tex]l = 0.006\,m[/tex], [tex]k = 0.78\,\frac{W}{m\cdot ^{\circ}C}[/tex], [tex]h_{i} = 10\,\frac{W}{m^{2}\cdot ^{\circ}C}[/tex] and [tex]h_{o} = 25\,\frac{W}{m^{2}\cdot ^{\circ}C}[/tex], the overall thermal resistance is:
[tex]R = \left[\frac{1}{(2.4\,m)\cdot (1.5\,m)}\right] \cdot \left(\frac{0.006\,m}{0.78\,\frac{W}{m\cdot ^{\circ}C} }+\frac{1}{10\,\frac{W}{m^{2}\cdot ^{\circ}C} }+\frac{1}{25\,\frac{W}{m^{2}\cdot ^{\circ}C} } \right)[/tex]
[tex]R = 0.041\,\frac{^{\circ}C}{W}[/tex]
Now, we obtain the steady rate of heat transfer from (Eq. 2): ([tex]R = 0.041\,\frac{^{\circ}C}{W}[/tex], [tex]T_{i} = -5\,^{\circ}C[/tex], [tex]T_{o} = 24\,^{\circ}C[/tex])
[tex]\dot Q_{total} = \frac{24\,^{\circ}C-(-5\,^{\circ}C)}{0.041\,\frac{^{\circ}C}{W} }[/tex]
[tex]\dot Q_{total} = 707.317\,W[/tex]
The steady rate of heat transfer through the glass window is 707.317 watts.
what was the first roblox player A.bob B.roblox C.builderman
Answer:
actually, it was John Doe and Jane Doe, as they were created as testers on the exact same say when Roblox was created.
Explanation:
The first player was builderman. Option C
Who was the first player?The first player was one whose user handle was builderman.
However, the account was terminated. It was replaced with
‘Builderman’ is the account that belonged to the CEO and Co-Founder of , David Baszucki. He manages all of the admins.
When you make a new account, he's automatically your friend.
Note that ‘John Doe’ and ‘Jane Doe’ were two test accounts that were created by David.
The accounts were later rumored to hack others’
Learn about username at: https://brainly.com/question/28344005
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