help Rn help please help

Unreasonable Time is the nest option for running the group raffle at an upcoming assembly to give away a prize.

As given that;

Reasonable Time: Algorithms with a polynomial efficiency or lower (constant, linear, square, cube, etc.) are said to run in a reasonable amount of time.

Unreasonable Time: Algorithms with exponential or factorial efficiencies are examples of algorithms that run in an unreasonable amount of time.

Your school is considering running the group raffle at an upcoming assembly to give away a prize.

We have to write a brief explanation of what advice you would give them.

We can use the unreasonable time because  running the group raffle at an upcoming assembly to give away a prize cannot complete their work is the given amount of time.

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Answer:

the answer is 6.63

[tex]\cfrac{45p^5q^4-60p^3q^2 - 15p^2q^3}{15p^2 q^3}\implies \cfrac{45p^5q^4}{15p^2 q^3}-\cfrac{60p^3q^2}{15p^2 q^3}-\cfrac{15p^2q^3}{15p^2 q^3}\implies 3p^3q-\cfrac{4p}{q}-1[/tex]

Answer:

1800

Step-by-step explanation:

Let us solve this question by Modular Airthmatic.

Let the lowest 4 digit number be X.

X= 1 (mod 5)

X =2 (mod 5)

X=3 (mod 5)

X =4 (mod 5)

X=1+5 t where t is any integer.

1+5 t=2 (mod 5)

5 t=1 (mod 5 )

5 is the Modular Inverse of modulo 5

t=1 (mod 5)

t =1+5 u : u= any integer.

X becomes 1+ 5 (1+5u )=6+25 u

6+25u =3 (mod 5)

25 u= -3 (mod 5)=2 (mod 5)

25 is Modular Inverse of Modulo 5

u=2 (mod 5)

u =2+5 v : v= any integer.

X becomes 6 +25 (2+5 v)=56+125 v .

56 +125 v=4 (mod 5)

125 v=-52 (mod 5)=3 (mod 5)

125 is Modular Inverse of modulo 5

v = 3 (mod 5)

v =3 +5 w where w is any integer.

For lowest 4 digit number, take

w=200

X=1003 : Lowest 4 digit number.

Take w=201

X=208 : Next number.

For 4 digit largest number, take

w=1995

X= 9978 : Largest number.

No. of Numbers =(1995 - 200 )+1=1800 □Ans.

Answer:

1800 ways.

Step-by-step explanation:

Answer:

Kumain ka Ng pansit para ka Maka sagot

Step-by-step explanation:

follow pleas helpme

Answer:

Both

Step-by-step explanation:

You can find both from the given 85

Answer:

The hight of the box is 1.2 m

Step-by-step explanation:

250cm= 2.5m

100cm= 1m

2.5x1=2.5

3/2.5=1.2

2.5 x 1 x 1.2=[tex]3m^{3}[/tex]

Four hemispheres are present in the shaded area. One large hemisphere and three smaller hemispheres each have a radius of 18 cm.

Consequently, the hemisphere's total surface area is 3(pi)R2. A semicircle has a curved line and a straight line that are both equal to the circle's diameter. The curving line is 2R in length while the straight line is (pi)R in length. So, 2R + (pi)R is the semicircle's total perimeter.

The shaded regions' area is calculated as follows:

initially, area of a hemisphere = 2r2 square units

the area of three small hemispheres

(2*3.14*6 r).3 = 226.08 cm2

Area of the larger hemisphere

2*3.14*18^2 = 2034.72cm^2

Total area of the shaded regions = 226.08 + 2034.72 = 2260.8cm^2

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The solution is Option B.

Number of seats for the students is given by the equation A = 231 seats

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the number of seats for the students be A

Now , the equation will be

The total number of buses = 3 buses

The total number of seats on each buses = 80 seats

So , the total number of seats = number of buses x number of seats on each buses

Substituting the values in the equation , we get

The total number of seats = 80 x 3

The total number of seats = 240 seats

Now , the teachers has 3 seats each on 3 buses

So , the number of seats for teachers = 3 x 3 = 9 seats

And , the remaining number of seats = total number of seats of students

The total number of seats for students A = total number of seats - number of seats for teachers

Substituting the values in the equation , we get

The total number of seats for students A = 240 - 9

The total number of seats for students A = 231 seats

Therefore , the value of A is 231 seats

Hence , the number of seats for students is 231 seats

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Answer: 256b

Step-by-step explanation: So, first we need to find the square root of 16b.

That'd be 4b, because a square root is when a number can be divided by a number, such as 4 can go into 16 4 times, and like 5 can go into 25 5 times. So, we got 4b

So, 4 to the power of 4 (ignore the b right now) is the same as 4 x 4 x 4 x 4.

So simplified, that'd be 16 x 4 (64). So, 64 x 4 = 256.

So, I'd be 256b

Answer:218

explanation: 162 divided by 9 = 18 and 18 multiplied by 12 =218

Answer:

yes thats your answer

Step-by-step explanation:

Answer:

I would say $55.............

Answer:

is there any other picture or part you did not show, because sales and week sis not enough for me

Step-by-step explanation:

The explicit formula for the sequence -28, -31, -34, -37, ..., is aₙ= -28 -3d.

A series of integers called an arithmetic progression or arithmetic sequence (AP) has a constant difference between the terms.

Given:

-28, -31, -34, -37, ...

The general formula of an arithmetic sequence:

aₙ= a₁ + (n)d,

where a₁ is the first term and d is the common difference.

First, we will find the common difference between consecutive terms.

Here,

a₁ = -28

To find the common difference:

a₂ - a₁ = -31 + 28 = -3

a₃ - a₂ = -34 + 31 = 3

a₄ - a₃ = -37 + 34 = 3

Hence, d = -3.

Substitute the values to the formula,

aₙ= a₁ + (n)d,

aₙ= -28 + (-3)d,

aₙ= -28 -3d

Therefore, aₙ= -28 -3d is the required sequence.

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Answer: 10.56 cups.

Step-by-step explanation:

1 liter = 4.22 cups; 1.5 liters = 6.34 cups; 2 liters = 8.45 cups; 2.5 liters = 10.56 cups.

Answer:

She missed 15 questions.

Step-by-step explanation:

25% of 60 = 15

(25/100) * 60 = 15

Therefore, she missed 15 questions.

Mark me brainliest and thenksss :))

Answer:

By exterior angle theorem, we have;

∠DBE = ∠H + ∠HEB = ∠ECD = ∠H + ∠HDC

∴ ∠H + ∠HEB = ∠H + ∠HDC

By addition property of equality, we have

∠HEB = ∠HDC

∠H = ∠H by reflexive property

∴ ΔHCD ~ ΔHEB by Angle Angle AA similarity postulate

∴ HE/HD = EB/DC, by the definition of similarity

Therefore, by cross multiplication, we have;

HE × DC = EB × HD

Therefore, by commutative property of multiplication, we have;

HE × DC = HD × EB

Step-by-step explanation:

Answer:

46 i think because 20+26 is 46

Answer: B, F

Step-by-step explanation: I did the test

The mean and median of Data set A are close to each other.

The mean of the data sets are within 3 units from each other.

The correct option is (B) and (F)

Data Set A: 25 26 27 28 29 30 31 32 33 34 35

Data Set B: 25 26 27 28 29 30 31 32 33 34 35

For Data A,

For Data B,

So, from above observation we can see that:

The mean and median of Data set A are close to each other.

The mean of the data sets are within 3 units from each other.

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Answer:

No, I will not simplify -164

Step-by-step explanation:

You can not Simplify -164

so the answer will be you can not simplify it

Answer:

point form is: (-7,2)

equation form is: x = -7, y = 2

Step-by-step explanation:

add the equations in order to solve for the first variable. plug this value into the other equations in order to solve for the remaining variables

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The ratio of money earned in August to July is 5/4.

Now, According to the question:

Let's know

What is Ratio?

A ratio is an ordered pair of numbers a and b, written a / b where b does not equal 0. A proportion is an equation in which two ratios are set equal to each other. For example, if there is 1 boy and 3 girls you could write the ratio as: 1 : 3 (for every one boy there are 3 girls) 1 / 4 are boys and 3 / 4 are girls.

Mason worked at the water park over the summer. He made $425 in June and $680 in July.

And if he made twice as much money In August as he did in June.

That means, he made $850 in August.

Then, The ratio will be :

= August / June

= 850/680

= 5/4

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the range of the function shown in the graph -1 [tex]\leq[/tex] y[tex]\leq[/tex] 1.

All real numbers fall within the domain of the sine and cosine functions. Both the sine and cosine functions have a range of [1,1]. An angle's sine and cosine have the same absolute value as their respective reference angles.

An illustration of the function's range in the graphs of cos and sine

The cosine function's graph appears as follows: The range of the function y=cos(x) is 1y1, and the domain is all real numbers (cosine is defined for any angle measure).

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The function form of the given function would be  [tex]f(x)=log_b(x)[/tex].

What is a function?

In mathematics, a function from a set X to a set Y assigns to each element of X exactly one element of Y. The set X is called the domain of the function and the set Y is called the codomain of the function.

The given function is f(x) = logbx.

So the function form would be the function of x is equal to the logarithmic of x having base b.

so this can be written as

       [tex]f(x)=log_b(x)[/tex]

Hence, the function form of the given function would be  [tex]f(x)=log_b(x)[/tex].

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The function form of the given function would be  [tex]f(x)=log_b(x)[/tex].

What is a function?

In mathematics, a function from a set X to a set Y assigns to each element of X exactly one element of Y. The set X is called the domain of the function and the set Y is called the codomain of the function.

The given function is f(x) = logbx.

So the function form would be the function of x is equal to the logarithmic of x having base b.

so this can be written as

[tex]f(x)=log_b(x)[/tex]

Hence, the function form of the given function would be  [tex]f(x)=log_b(x)[/tex].

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Answer:

  lower left (already identified)

Step-by-step explanation:

You want the graph showing x < 2.

The boundary line of the solution area will be x = 2. Because that line is not included in the space x < 2, the line is dashed. (Eliminates graphs on the right.)

The solution space includes values of x that are less than 2. That means they are to the left of the boundary line. Shading will be left of the dashed line. (Eliminates graphs on the top.)

The correct graph of x < 2 is the one at lower left, already highlighted in the image.