Help pls!

A 3 kg mass is raised a distance of 14 m above the earth by a vertical force of 93 N.
The final kinetic energy of the mass, to 3 significant figures, if it was originally at rest is:

Answer:

D

Explanation:

Process of elimnination + it's the only one that makes sense

An object will begin moving from rest when acted upon by forces that are greater in one direction than in any other direction. Hence, Option (D) is correct.

The definition of force in physics is: The push or pull on a massed object changes its velocity. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.

When  forces that are greater in one direction than in any other direction, resultant will be  unbalanced forces.  Unbalanced forces are those acting on a body when the net force acting on the body is greater than zero. The body alters its state of motion when unbalanced forces act on it.

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Answer:

Explanation:

In the vertical analysis assuming launch from ground level.

0 = 0 + (41.3sinθ)(5.1) + ½(-9.8)5.1²

(41.3sinθ)(5.1) = ½(9.8)5.1²

(41.3sinθ) = ½(9.8)5.1

sinθ = ½(9.8)5.1/41.3

sinθ = 0.60508...

θ = 37.235°

vx = 41.3cos37.235

vx = 32.881452...

vx = 32.9 m/s

Answer:

C number is write i think

Answer:

What is kinetic friction?

Kinetic friction is defined as a force that acts between moving surfaces. A body moving on the surface experiences a force in the opposite direction of its movement.

What causes it?

When the mass is not moving, the object experiences static friction. The friction increases as the applied force increases until the block moves. After the block moves, it experiences kinetic friction, which is less than the maximum static friction.

What does it generate?

When surfaces in contact move relative to each other, the friction between the two surfaces converts kinetic energy into thermal energy (that is, it converts work to heat). This property can have dramatic consequences, as illustrated by the use of friction created by rubbing pieces of wood together to start a fire.

Answer:

F12 = G M1 M2 / R12^2

F12' = G M1 M2 / R12'^2

F12' / F12 = R12'^2 / R12^2 = (1/3)^2

F12' = 1/9 F12

The new force is 1/9 the of the old force

Answer:

.192 kg x m^2

Explanation:

I= mass of a times radius of a squared + mass of b times radius of b squared +...

I= .6 kg x .4m^2 + .6 kg x .4m^2

= .192 kg x m^2

Hope this helps :)

Hi there!

A.

We can calculate the gravitational field strength using the following equation:

[tex]g = \frac{Gm_p}{r^2}[/tex]

G = Gravitational Constant

mp = mass of planet (kg)

r = radius (m)

Plug in the given values:

[tex]g = \frac{(6.67*10^{-11})*(5.68*10^{24})}{(6.03*10^7)^2} = \boxed{0.104 N/kg}[/tex]

B.

The force can be calculated using:

[tex]F_g = \frac{Gm_1m_2}{r^2}[/tex]

Plug in the values:

[tex]F_g = \frac{(6.67*10^{-11})(5.68*10^{24})(50)}{(6.04*10^7)^2} = \boxed{5.209N}[/tex]

Answer:

[tex]\boxed {\boxed {\sf g=0.104 \ N/kg \ and \ F_g= 5.2 \ N }}[/tex]

Explanation:

A. Gravitational Field Strength

The gravitational field strength can be calculated using the following formula:

[tex]g= \frac{Gm}{r^2}[/tex]

G, or the universal gravitational constant, is 6.67 × 10⁻¹¹ N*m²/kg². The mass of Saturn is 5.68 × 10²⁴ kilograms. The radius of Saturn is 6.03×10⁷ meters.

Substitute these values into the formula.

[tex]g= \frac{ (6.67 \times 10^{-11} \ N*m^2/kg^2) (5.68 \times 10^{24} \ kg)}{(6.03 \times 10^{7} \ m )^2}[/tex]

Multiply the numerator and square the denominator.

[tex]g= \frac{ 3.78856 \times 10^{14} \ N *m^2/kg }{3.63609 \times 10^{15} \ m^2}[/tex]

Divide.

[tex]g= 0.1041932405 \ N/kg[/tex]

The original measurements of mass and radius have 3 significant figures, so our answer must have the same. For the number we found, that is the thousandth place. The 1 in the ten-thousandth place tells us to leave the 4 in the thousandth place.

[tex]\boxed {g \approx 0.104 \ N/kg}[/tex]

B. Force of Gravity

The force of gravity is calculated using the following formula:

[tex]F_g= mg[/tex]

The mass of the object is 50 kilograms. We just calculated the gravitational field strength, which is 0.104 Newtons per kilogram. Substitute these values into the formula.

[tex]F_g= (50 \ kg)(0.104 \ N/kg)[/tex]

Multiply. The units of kilograms cancel.

[tex]\boxed {F_g=5.20 \ N}[/tex]

The magnitude of the total initial velocity of the rocket is determined as 9.82 m/s.

The magnitude of the total initial velocity of the rocket is calculated as follows;

V = D/T

where;

V = (54)/(5.5)

V = 9.82 m/s

Thus, the magnitude of the total initial velocity of the rocket is determined as 9.82 m/s.

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Answer:

200J

Explanation:

work done = force x distance

                  = 20 x 10

                  = 200J

Answer:

A. 2.7 m/s

Explanation:

Answer:

[tex]\boxed {\boxed {\sf A. \ 2.7 \ m/s}}[/tex]

Explanation:

We want to find how fast a branch is falling after 0.28 seconds.

Essentially, we want to find its final velocity at exactly 0.28 seconds. We will use the following kinematic equation:

[tex]v_f= v_i+at[/tex]

The branch fell from the tree, so it initially started at rest or 0 meters per second. The branch is in free fall, so its acceleration is due to gravity, or 9.8 meters per second squared. It falls for 0.28 seconds.

Substitute the values into the formula.

[tex]v_f= 0 \ m/s + (9.8 \ m/s^2)(0.28 \ s)[/tex]

Multiply the numbers in parentheses.

[tex]v_f= 0 \ m/s +(9.8 \ m/s/s * 0.28 \ s )[/tex]

[tex]v_f= 0 \ m/s +2.744 \ m/s[/tex]

Add.

[tex]v_f= 2.744 \ m/s[/tex]

The original measurement of time has 2 significant figures, so our answer must have the same. For the number we found, that is the tenth place. The 4 in the hundredth place tells us to leave the 7.

[tex]v_f \approx 2.7 \ m/s[/tex]

The branch is moving at a velocity of approximately 2.7 meters per second.

Answer:

In space we feel weightlessness because the earth's gravity has less effect on us. The Earth's gravitational attraction at those altitudes is only about 11% less than it is at the Earth's surface. If you had a ladder that could reach as high as the shuttle's orbit, your weight would be 11% less at the top.

Explanation:

Hope this helps:)

Answer:

Albert Einstein WAS a very well known Theoretical physicist

The USA claims he did not ever get his hands directly on an atomic bomb but in fact, other country textbooks like in Germany say he did.

Explanation:

A fun fact is that he was hired by the United States to make the Atomic bomb. Albert Einstein was a german yet many believed him to be a Smart American, they were wrong.

Answer:

Sample Response: No image will be formed because the rays will not converge to or diverge from a common point.

Explanation:

Answer:

Cement, iron, and steel all work great!

Addition of a proton to germanium  will convert it to arsenic (element 33) having different properties.

The atomic number of an atom is the number of protons in the nucleus of the atom. The atomic number serves as the identity of an atom. If the atomic number is changed by adding or removing protons, the identity of that atom changes.

Hence, when a proton is added to germanium, the  atom would become arsenic (element 33) and have different properties.

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Answer: Its B and D

I had the same question on usatestprep

The elevation at the top of the hill is 1,653.85 m.

The given parameters;

The elevation at the top of the hill is calculated as follows;

[tex]P.E = mg\Delta h\\\\P.E = mg(h_2 -h_1)\\\\h_2 -h_1 = \frac{P.E}{mg} \\\\h_2 = \frac{P.E}{mg} + h_1\\\\h_2 = \frac{9.2 \times 10^5 }{72 \times 9.8} \ + \ 350 \ m\\\\h_2 = 1,653.85 \ m[/tex]

Thus, the elevation at the top of the hill is 1,653.85 m.

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Answer:

c.

Explanation:

If the two plates that meet at a convergent plate boundary both are of oceanic crust, the older, denser plate will subduct beneath the less dense plate. The older plate subducts into a trench, resulting in earthquakes. Melting of mantle material creates volcanoes at the subduction zone.

When two oceanic plates converge, the denser plate will end up sinking below the less dense plate, leading to the formation of an oceanic subduction zone. Old, dense crust tends to be subducted back into the earth. An example of a subduction zone formed from a convergent boundary is the Chile-Peru trench….

Answer:

a divergent plate boundary

Answer:

it would decrease

Explanation:

f=1/T

Answer:

d = -33.1 m and Vf = -25.5 m/s

Explanation:

a = -9.8 m

t = 2.6 s

Vᵢ = 0 m/s

d = ?

Vf = ?

Now,

d = Vᵢ × t + 0.5 × a × t²

d = (0 m/s) × (2.60 s) + 0.5 × (-9.8 m/s²) × (2.60 s)²

d = -33.1 m (- indicates direction)

Vf = Vᵢ + a × t

Vf = 0 + (-9.8 m/s²) × (2.60 s)

Vf = -25.5 m/s (- indicates direction)

Thus, d = -33.1 m and Vf = -25.5 m/s

-TheUnknownScientist 72

Answer:

how long does it take? we need it to answer ure question

Explanation:

cause we don't know how many feet until we know how long it was falling

If a  stone is dropped from the edge of a roof and hits the ground with a velocity of -150 feet per second, then the height of the roof would have been 1148 feet.

There are three equations of motion given by  Newton

v = u + at

S = ut + 1/2 × a × t²

v² - u² = 2 × a × s

As given in the problem, a penny is dropped from a building that is 95 m tall, the initial velocity of the penny is zero, and the acceleration acting is due to the acceleration due to gravity,

By using the second  equation of the motion for the vertical motion ,

v²  = ( 2 × g ×h )

150²  = 2 × 9.8 × h

h = 22500 / 19.6

  = 1148 feet

Thus, the height of the roof would have been 1148 feet.

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The moment of inertia of the wheel is 4.27 kg.m²

The kinematics equation explains the variables associated and related of motion.

From the information given, applying the kinematic equation of motion to determine the acceleration of the block, we have:

[tex]\mathbf{y = ut + \dfrac{1}{2}at^2}[/tex]

[tex]\mathbf{y = (0)t + \dfrac{1}{2}at^2}[/tex]

[tex]\mathbf{y = \dfrac{1}{2}at^2}[/tex]

Making acceleration (a) the subject, we have:

[tex]\mathbf{a = \dfrac{2y}{t^2}}[/tex]

where;

[tex]\mathbf{a = \dfrac{2\times 1.5 }{2.0^2}}[/tex]

a = 0.75 m/s²

The angular acceleration of the wheel can be estimated by the formula:

[tex]\mathbf{\alpha = \dfrac{a}{r}}[/tex]

[tex]\mathbf{\alpha = \dfrac{0.75 \ m/s^2}{0.40 \ m}}[/tex]

[tex]\mathbf{\alpha = 1.875 \ rad/s^2}[/tex]

Finally, the torque acting on the wheel is:

[tex]\mathbf{\tau = I \alpha}[/tex]

[tex]\mathbf{Tr = I \alpha}[/tex]

where;

∴

[tex]\mathbf{I =\dfrac{T\times r}{\alpha} }[/tex]

[tex]\mathbf{I =\dfrac{20 \ N\times 0.40 \ m}{1.875 \ rad/s^2} }[/tex]

I = 4.27 kg.m²

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Answer:  You need to use Newton's law for the equation --->

Explanation: G  ×  M  ×  m / separation. Thats how youll get your answer !!

The volume of a material is the total amount of matter that it can contain. The volume of the given coin has been determined to be 5.85 x [tex]10^{-6}[/tex] [tex]m^{3}[/tex]. Since the gold doubloon do not absorb water, then its volume remains constant at the ocean floor.

The volume of the gold doubloon can be determined by;

volume = [tex]\pi r^{2}[/tex] + h

where r is the radius of the coin and h is its thickness.

Such that; diameter = 6.1 cm (61 mm) and h = 2.0 mm

r = [tex]\frac{diameter}{2}[/tex]

 = [tex]\frac{61}{2}[/tex]

r = 30.5 mm

Thus,

volume of the coin = [tex]\frac{22}{7}[/tex] x [tex](30.5)^{2}[/tex] x 2

                               = 5847.2857

Therefore, the volume of the gold doubloon is 5847.3 [tex]mm^{3}[/tex]. This can also be expressed as 5.85 x [tex]10^{-6}[/tex] [tex]m^{3}[/tex].

Since the gold doubloon is  not miscible with water, thus its volume at a depth of 770 m at the ocean floor is the same as its initial volume.

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Hi there!

We know that:

U (Gravitational Potential Energy) = mgh

Where:

g = acceleration due to gravity (m/s²)

m = mass (kg)

h = height/displacement (m)

Plug in the values:

U = 3 × 9.8 × 14 = 412 J

Explanation:

Fgravity = G*(mass1*mass2)/D²

G is the gravitational constant throughout the universe.

D is the distance between the 2 objects.

the distance is now quadrupled.

Fgravitynew = G*(mass1*mass2)/(4D)² =

= G*(mass1*mass2)/(16D²) =

= (G*(mass1*mass2)/D²) / 16 = Fgravity/16

the new gravitational force will be 179/16 = 11.1875 units

Answer:

Explanation:

conservation of momentum during the collision

0.035(214) + 0.15(0) = 0.185v

v = 40.486 m/s

The kinetic energy after impact will convert to gravity potential energy

(ignoring air resistance)

mgh = ½mv²

     h = v²/2g

     h = 40.486² / (2(9.8))

     h = 83.6303...

     h = 84 m