H 20kN G 30kN D B 5m Analyze the same frame using Cantilever Method. E 6m C 4m 4m

Answers

Answer 1

To analyze the frame using the Cantilever Method, we will consider each section of the frame individually.

Let's start by analyzing section AB. Since it is a cantilever, we can treat point A as a fixed support. The load at point B is 5kN. We can assume that the vertical reaction at A is RvA and the horizontal reaction at A is RhA.

To find the reactions, we can consider the equilibrium of forces in the vertical direction. The sum of the vertical forces at A should be zero.  Since there are no vertical forces acting at A, RvA = 0.
Now let's consider the equilibrium of forces in the horizontal direction. The sum of the horizontal forces at A should be zero.  The only horizontal force at A is RhA, and it should balance the horizontal force at B, which is 5kN. Therefore, RhA = 5kN.

Moving on to section BC, it is a simply supported beam with a length of 4m. We can consider points B and C as the supports. The loads at B and C are 5kN and 30kN respectively. We can assume that the vertical reactions at B and C are RvB and RvC, and the horizontal reaction at B is RhB.
Again, let's start by considering the equilibrium of forces in the vertical direction. The sum of the vertical forces at B and C should be zero.

RvB + RvC - 5kN - 30kN = 0
RvB + RvC = 35kN

Now let's consider the equilibrium of forces in the horizontal direction. The sum of the horizontal forces at B should be zero. The only horizontal force at B is RhB, and it should balance the horizontal force at C, which is 30kN. Therefore, RhB = 30kN.

Finally, let's analyze section CD. It is another cantilever with a length of 4m. We can treat point C as a fixed support. The load at point D is 20kN. We can assume that the vertical reaction at C is RvC and the horizontal reaction at C is RhC. To find the reactions, we can consider the equilibrium of forces in the vertical direction. The sum of the vertical forces at C should be zero.


RvC - 20kN = 0
RvC = 20kN

Now let's consider the equilibrium of forces in the horizontal direction. The sum of the horizontal forces at C should be zero. The only horizontal force at C is RhC, and it should balance the horizontal force at D, which is 20kN. Therefore, RhC = 20kN.

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Related Questions

Water can be formed according to the equation: 2H2(g) + O2(g) → 2H₂O(g) If 6.0 L of hydrogen is reacted at STP, exactly how many liters of oxygen at STP would be needed to allow complete reaction? (R= 0.0821 Latm/mol K) a)801 b)30L c)4.0 L d)12.0L e)10.0L

Answers

Approximately 3.57 liters of oxygen at STP would be needed to allow complete reaction.

To find out how many liters of oxygen at STP (Standard Temperature and Pressure) would be needed to allow complete reaction, we need to use the balanced equation for the reaction:

2H2(g) + O2(g) → 2H₂O(g) The stoichiometric ratio between hydrogen and oxygen in this reaction is 2:1. This means that for every 2 moles of hydrogen, we need 1 mole of oxygen.

Given that we have 6.0 L of hydrogen at STP, we need to convert this volume into moles.

To do this, we can use the ideal gas law: PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.

At STP, the pressure is 1 atm and the temperature is 273 K. The ideal gas constant, R, is 0.0821 L·atm/(mol·K).

So, using the ideal gas law, we can calculate the number of moles of hydrogen:

n = PV / RT = (1 atm) * (6.0 L) / (0.0821 L·atm/(mol·K) * 273 K) ≈ 0.272 mol

Since the stoichiometric ratio between hydrogen and oxygen is 2:1, we know that the number of moles of oxygen needed is half the number of moles of hydrogen:

moles of oxygen = 0.272 mol / 2 = 0.136 mol

Now, we can convert the number of moles of oxygen into liters at STP using the ideal gas law again:

V = nRT / P = (0.136 mol) * (0.0821 L·atm/(mol·K) * 273 K) / (1 atm) ≈ 3.57 L

Therefore, approximately 3.57 liters of oxygen at STP would be needed to allow complete reaction.

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b) For each of the following pairs of complexes, suggest with explanation the one that has the larger Ligand Field Splitting Energy (LFSE). (i) Tetrahedral [CoCl_4​]^2− or tetrahedral [FeCl_4​]^2− (ii) [Fe(CN)_6​]^3− or [Ru(CN)_6​]^3−

Answers

(i) In the case of tetrahedral complexes [CoCl4]^2- and [FeCl4]^2-, the one with the larger Ligand Field Splitting Energy (LFSE) can be determined based on the metal ion's oxidation state. Since both complexes have the same ligands (chloride ions), the LFSE primarily depends on the metal ion's oxidation state.
Higher oxidation states generally result in larger LFSE values. In this case, [FeCl4]^2- has an iron ion with a higher oxidation state (+2) compared to [CoCl4]^2- which has a cobalt ion with a lower oxidation state (+1). Therefore, [FeCl4]^2- is expected to have a larger LFSE.

(ii) For the complexes [Fe(CN)6]^3- and [Ru(CN)6]^3-, the ligand is different (cyanide, CN-) while the metal ion is different (iron, Fe3+ and ruthenium, Ru3+). The LFSE can be influenced by factors such as the charge of the metal ion and the nature of the ligands.
Since the ligand is the same for both complexes, the LFSE is mainly determined by the metal ion's charge. In this case, [Fe(CN)6]^3- has an iron ion with a higher charge (+3) compared to [Ru(CN)6]^3- which has a ruthenium ion with a lower charge (+3). Therefore, [Fe(CN)6]^3- is expected to have a larger LFSE.

In summary, the complexes [FeCl4]^2- and [Fe(CN)6]^3- are expected to have larger Ligand Field Splitting Energies (LFSE) compared to [CoCl4]^2- and [Ru(CN)6]^3- respectively. This is primarily due to the higher oxidation state of iron in [FeCl4]^2- and the higher charge of iron in [Fe(CN)6]^3-.
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2. Landscape artists frequently hand-draw their landscape layouts (blueprints) because this allows them more creativity and precision over their plans. Although done by hand, the layouts must be extremely accurate in terms of angles and distances.
a. A landscape artist has drawn the outline of a house. Describe three different ways to make sure the corners of the house are right angles.

Answers

The three different ways to make sure that the corners are right angles are the 3-4-5 method, the Rope method, and the optical square method.

Given that:

A landscape artist has drawn the outline of a house.

The three methods that can be used here are described below:

The 3-4-5 method works on the basis of the principle of the Pythagoras theorem.

Here, there will be three people, one handling the measuring tape marked at 0, the second one handling the tape marked at 3, and the third one at mark 8. When this gets stretched, it will form a right triangle.

In the Rope method, there will be loops formed by three pegs. A loop of the rope is situated around peg X with a peg through another loop to make a circle on the ground. Now, place pegs Y and Z where the circle crosses the baseline, and peg O is placed halfway between pegs Y and Z, allowing pegs O and X to form lines that are perpendicular to the baseline and thus form a right angle.

In the optical square method, simple instruments form the right angle.

Hence the three methods are the 3-4-5 method, the Rope method, and the optical square method.

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Final answer:

To ensure the corners of a house are right angles in a landscape layout, you can use a protractor, apply the Pythagorean theorem, or use a right-angle triangle ruler.

Explanation:

This question is related to geometry, a branch of mathematics, where we often have to ensure the accuracy of angles and measurements. In this particular case, we're considering ways to confirm if the corners of a house, as drawn on a blueprint, are right angles. Here are a few possible ways to accomplish this:

Use a protractor: This is a simple and common tool for measuring angles. Simply place the center of the protractor at the corner of the house and align the base line with one side of the angle. The other side should point to 90 degrees if it is a right angle.Apply the Pythagorean theorem: This theorem says that in a right-angled triangle, the square of the length of the hypotenuse (the side opposite the right angle) equals the sum of the squares of the other two sides. You could measure the lengths of three sides and check this relationship.Utilise a right-angle triangle ruler: This ruler has a 90-degree angle and can be used to check if corners are right angles. Place the ruler at the angle and see if the sides align properly with the sides of the angle.

Whichever method you decide to use, make sure to measure accurately and carefully to maintain the precision of your landscape layout.

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Consider the linear subspace U of R4 generated by {(2,−1,3,−2),(−4,2,−6,4)}. The dimension of U is a) 1 b) 2 c) 3 d) 4

Answers

The rank of the matrix is 3, there are 3 pivots and therefore dim(U) = 3. The correct answer is option (c) 3.

Let U be a linear subspace of R4 generated by {(2,−1,3,−2),(−4,2,−6,4)}.

To find the dimension of U, we can start by setting up the augmented matrix for the system of equations given by:

ax + by = c where (x, y) ∈ U and a, b, c ∈ R.

This will help us determine the number of pivots in the reduced row echelon form of the matrix.

If there are k pivots, then dim(U) = k.

augmented matrix = [tex]$\begin{bmatrix} 2 & -4 & | & a \\ -1 & 2 & | & b \\ 3 & -6 & | & c \\ -2 & 4 & | & d \end{bmatrix}$[/tex]

We will now put this matrix in reduced row echelon form using elementary row operations:

[tex]R2 → R2 + 2R1R3 → R3 + R1R4 → R4 + R1$\begin{bmatrix} 2 & -4 & | & a \\ 0 & -6 & | & 2a+b \\ 0 & 6 & | & c-a \\ 0 & 0 & | & d+2a-2b-c \end{bmatrix}$R4 → R4 - R3$\begin{bmatrix} 2 & -4 & | & a \\ 0 & -6 & | & 2a+b \\ 0 & 6 & | & c-a \\ 0 & 0 & | & -a+b+d \end{bmatrix}$[/tex]

Since the rank of the matrix is 3, there are 3 pivots and therefore dim(U) = 3.

Therefore, the correct answer is option (c) 3.

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Find the heat capacity of these components in J/g.K :-
S2 (S)/H2O (l)/H2S (g)/ SO2 (g)

Answers

To find the heat capacity of the given components, we need to look up their specific heat capacity values. The specific heat capacity, also known as the specific heat, is the amount of heat required to raise the temperature of one gram of a substance by one degree Celsius (or one Kelvin).

Let's find the specific heat capacity values for each component:

1. S2 (S): The specific heat capacity of sulfur (S) is approximately 0.71 J/g·K.

2. H2O (l): The specific heat capacity of water (H2O) in the liquid state is about 4.18 J/g·K.

3. H2S (g): The specific heat capacity of hydrogen sulfide (H2S) in the gaseous state is around 1.03 J/g·K.

4. SO2 (g): The specific heat capacity of sulfur dioxide (SO2) in the gaseous state is approximately 0.57 J/g·K.

Now, let's calculate the heat capacity for each component using the given specific heat capacity values:

1. S2 (S):
Heat capacity = Mass of S2 (S) × Specific heat capacity of S2 (S)
Let's say we have 1 gram of S2 (S):
Heat capacity of S2 (S) = 1 g × 0.71 J/g·K = 0.71 J/K

2. H2O (l):
Heat capacity = Mass of H2O (l) × Specific heat capacity of H2O (l)
Let's say we have 1 gram of H2O (l):
Heat capacity of H2O (l) = 1 g × 4.18 J/g·K = 4.18 J/K

3. H2S (g):
Heat capacity = Mass of H2S (g) × Specific heat capacity of H2S (g)
Let's say we have 1 gram of H2S (g):
Heat capacity of H2S (g) = 1 g × 1.03 J/g·K = 1.03 J/K

4. SO2 (g):
Heat capacity = Mass of SO2 (g) × Specific heat capacity of SO2 (g)
Let's say we have 1 gram of SO2 (g):
Heat capacity of SO2 (g) = 1 g × 0.57 J/g·K = 0.57 J/K

Therefore, the heat capacity of the given components are:
- S2 (S): 0.71 J/K
- H2O (l): 4.18 J/K
- H2S (g): 1.03 J/K
- SO2 (g): 0.57 J/K

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1) (a) How many connected graphs can be produced with 3
vertices and 4 or fewer edges such that each graph has a unique
degree sequence (e.g. two graphs with degree sequence (0,0,2,0,1)
are considered

Answers

There are four connected graphs that can be produced with 3 vertices and 4 or fewer edges such that each graph has a unique degree sequence. These graphs are:
1. A graph with no edges
2. A graph with three vertices connected in a cycle
3. A graph with three vertices connected in a line
4. A graph with three vertices connected in a triangle

To determine the number of connected graphs with these criteria, let's consider each possible degree sequence.

1. Degree sequence (0,0,0): There is only one graph that satisfies this degree sequence - a graph with no edges.

2. Degree sequence (1,1,1): There is only one graph that satisfies this degree sequence - a graph with three vertices connected in a cycle.

3. Degree sequence (1,2,2): There is only one graph that satisfies this degree sequence - a graph with three vertices connected in a line.

4. Degree sequence (2,2,2): There is only one graph that satisfies this degree sequence - a graph with three vertices connected in a triangle.

5. Degree sequence (1,1,2): There is no graph that satisfies this degree sequence. To have a degree sequence of (1,1,2), there must be one vertex with degree 2 and the remaining two vertices with degree 1. However, it is not possible to connect the vertices in a way that satisfies this condition.

6. Degree sequence (0,1,2): There is no graph that satisfies this degree sequence. To have a degree sequence of (0,1,2), there must be one vertex with degree 2 and the remaining two vertices with degree 1. However, it is not possible to connect the vertices in a way that satisfies this condition.

As a result, there are four connected graphs that can be created with no more than three vertices and four edges, each of which has a distinct degree sequence. The following graphs:

1. An unconnected graph

2. A cycle-shaped graph with three vertices

3. A line-connected graph with three vertices

4. A triangle-shaped network with three connected vertices

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I need help pls help asap I will like pls PLEASE first second and third part please! Let T:R2−>R2 be defined by T(x,y)=(x−y,x+y). The kernel of T is: a) ker(T)={(x,x)∣x is real } b) ker(T)={(0,0)} c) None of the above. a b c

Answers

The kernel linear transformation is:

a) ker(T) = {(0, y) | y is real}

How to solve Kernel Linear Transformation?

The kernel (or null space) of a linear transformation is defined as the subset of the domain that is transformed into the zero vector.

We are given that:

T(x, y) = (x - y, x + y)

We want to find the set of vectors (x, y) in R₂ that get mapped to the zero vector (0, 0) under T.

Thus:

T(x, y) = (x - y, x + y) = (0, 0).

In the first component, we see that:

x - y = 0

Thus, x = y.

Plugging that into the second component, we have:

x + y = 0, we get:

x + x = 0,

2x = 0

x = 0

Therefore,  we conclude that the kernel of T consists of vectors of the form (0, y), where y can be any real number.

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Explain and elaborate "Piezoelectric Arduino Automated Road
Signs for blindcurves" for SDG's 13th Goal (climate action) of U.N.
Please correct answer this time :(

Answers

Piezoelectric Arduino Automated Road Signs for blind curves are a technology that can be used to address the 13th goal (climate action) of the United Nations Sustainable Development Goals (SDGs).



Piezoelectric materials are substances that generate an electric charge when mechanical stress is applied to them. Arduino is an open-source electronics platform that can be programmed to control various devices. When combined, piezoelectric materials and Arduino technology can create a system that utilizes renewable energy and provides important information to drivers.

In the case of blind curve road signs, piezoelectric materials are installed beneath the road surface in these areas. When vehicles pass over these materials, the mechanical stress causes them to generate electric charges. These charges are then captured by the Arduino system and used to power the road signs.

The signs can display important information such as warnings about the upcoming curve, recommended speed limits, or other safety instructions. By using piezoelectric technology, these signs do not rely on traditional power sources, such as electricity from the grid, reducing the carbon footprint associated with their operation.

Hence, Piezoelectric Arduino Automated Road Signs for blind curves utilize the mechanical stress generated by passing vehicles to produce electricity, which powers the road signs. These signs enhance road safety in blind curve areas while also contributing to climate action by utilizing renewable energy sources.

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Which of the following is the recursive formula for the geometric sequence 4, 24, 144, 864, ...?

Answers

The recursive formula for the geometric sequence 4, 24, 144, 864, ... is aₙ = 6 * aₙ₋₁, where aₙ represents the nth term of the sequence.

A geometric sequence is a sequence of numbers where each term is found by multiplying the previous term by a constant called the common ratio. To determine the recursive formula for the given geometric sequence, we need to identify the relationship between consecutive terms.

Let's analyze the given sequence:

4, 24, 144, 864, ...

To go from 4 to 24, we multiply by 6.

To go from 24 to 144, we multiply by 6.

To go from 144 to 864, we multiply by 6.

We observe that each term is obtained by multiplying the previous term by 6. Therefore, the common ratio is 6. The recursive formula for a geometric sequence can be written as aₙ = r * aₙ₋₁, where aₙ represents the nth term and r is the common ratio.

Substituting the common ratio 6 into the recursive formula, we get:

aₙ = 6 * aₙ₋₁

Hence, the recursive formula for the geometric sequence 4, 24, 144, 864, ... is aₙ = 6 * aₙ₋₁, where aₙ represents the nth term of the sequence.

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[Calculation Question] Given a number A, which equals 1,048,576. Please find another number B so that the GCD (Greatest Common Divisor) of A and B is 1,024. This question has multiple correct answers, and you just need to give one. Please make sure you do not give 1,024 as your answer (no points will be given if your answer is 1,024). If you are sure you cannot get the right answer, you may describe how you attempted to solve this question. Your description won't earn you the full points, but it may earn some.

Answers

To find a number B such that the GCD of A and B is 1,024, one possible approach is to divide A by 1,024 and then multiply the quotient by any number relatively prime to 1,024. This will ensure that the GCD of A and B is 1,024. One example is to choose B = 1,024 multiplied by a prime number, such as B = 1,024 * 17 = 17,408.

To find a number B such that the GCD of A and B is 1,024, we can follow these steps:

Divide A by 1,024: 1,048,576 / 1,024 = 1,024.

Choose a number that is relatively prime to 1,024. In other words, select a number that does not share any prime factors with 1,024. One way to achieve this is by choosing a prime number.

Multiply the quotient from step 1 by the number chosen in step 2. This will give us B such that the GCD of A and B is 1,024.

In this case, we can choose B = 1,024 multiplied by a prime number, such as B = 1,024 * 17 = 17,408. The GCD of A = 1,048,576 and B = 17,408 is indeed 1,024, which satisfies the given condition.

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real analysis
2. Show that ∂A is closed for any
A ⊆ R.

Answers

To show that ∂A is closed for any A ⊆ R,

let A be a subset of the set of real numbers R.

The boundary of A, denoted ∂A as the set of all points in R that are either a limit point of A or a limit point of A complement (R - A).

Then, let x be any accumulation point of ∂A, which means that every neighborhood of x contains points in ∂A other than x.

Let U be any neighborhood of x, then U must contain points in both A and R-A (by definition of boundary).

This is because otherwise, U would not be a neighborhood of x (it would either be entirely contained in A or R-A). Therefore, U contains points in both A and R-A.

Because x is an accumulation point of ∂A, U must contain a point y in ∂A.

But then, y is either a limit point of A or R-A. If y is a limit point of A,

then U must contain infinitely many points in A, and if y is a limit point of R-A,

then U must contain infinitely many points in R-A.

Either way, we have shown that U contains infinitely many points in ∂A, so x is also an accumulation point of ∂A.

Since ∂A contains all of its accumulation points, we have shown that ∂A is closed.

Therefore, ∂A is closed for any A ⊆ R.

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You are tasked with sorting the rods. What does RB likely stand for?
A. Rejected Bins
B. Requisite Bins
C. Red Bins
D. Rolling Bins
E. Rod Bins
A Report Content Errors

Answers

Answer:

rod bins

Step-by-step explanation:

because you dealing with rods and you need aplace to put them that is the b bins

Answer:

rod bins

Step-by-step explanation:

Solve system of differential equations.
dx/dt=2y+t dy/dt=3x-t
show all work, step by step please!

Answers

The solution to the system of differential equations dx/dt = 2y + t and dy/dt = 3x - t is x = y^2 + ty + C1 and y = (3/2)x^2 - (1/2)t^2 + C2, where C1 and C2 are constants of integration.

To solve the system of differential equations dx/dt = 2y + t and dy/dt = 3x - t,

we can use the method of separation of variables.

Here are the step-by-step instructions:

Step 1: Rewrite the equations in a standard form.
dx/dt = 2y + t can be rewritten as dx = (2y + t)dt.
dy/dt = 3x - t can be rewritten as dy = (3x - t)dt.

Step 2: Integrate both sides of the equations.
Integrating the left side, we have ∫dx = ∫(2y + t)dt, which gives us x = y^2 + ty + C1, where C1 is the constant of integration.
Integrating the right side, we have ∫dy = ∫(3x - t)dt, which gives us y = (3/2)x^2 - (1/2)t^2 + C2, where C2 is the constant of integration.

Step 3: Equate the two expressions for x and y.
Setting x = y^2 + ty + C1 equal to y = (3/2)x^2 - (1/2)t^2 + C2, we can solve for y in terms of x and t.

Step 4: Substitute the expression for y back into the equation for x to obtain a final solution.

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A sample of 0.4500 g impure potassium chloride was dissolved in water treated with excess silver nitrate solution. 0.8402 g of silver chloride was precipitated. What is the percentage of potassium chloride in the sample?

Answers

the mass of potassium chloride cannot be negative, it indicates an error in the given values. Please verify the data and ensure that the mass values are accurate.

To calculate the percentage of potassium chloride in the sample, we need to determine the mass of potassium chloride and the total mass of the sample.

Given:

Mass of impure potassium chloride (KCl) = 0.4500 g

Mass of silver chloride (AgCl) precipitated = 0.8402 g

To find the mass of potassium chloride, we need to determine the difference between the initial mass of the impure sample and the mass of silver chloride precipitated:

Mass of KCl = Mass of impure sample - Mass of AgCl

           = 0.4500 g - 0.8402 g

           = -0.3902 g

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CO-2,3,4 SITUATION 4.0 (20%) a) Find the total cost to furnish 150 sets of 1600mm x 1600mm steel grating 25mm x 25mm square bar spaced at 200mm on center with the perimeter frame composed of 75mm x 75mm x 6mm angle bar including fabrication, supply delivery and installation with one coat of Epoxy Primer.

Answers

The total cost to furnish 150 sets of steel grating with the given specifications, including fabrication, supply, delivery, and installation with one coat of Epoxy Primer, is approximately $46,837.50.

How to calculate the total  cost

To find the total cost to furnish 150 sets of steel grating with the given specifications, calculate the cost per set and then multiply by the number of sets.

Note: The cost of steel grating varies depending on the supplier and location, for this problem, let's assume a cost of $100 per square meter for the grating itself.

Since each set of grating has an area of (1.6m) x (1.6m) = 2.56 square meters, the cost of the grating per set is

Cost of grating = 2.56 x 100 = $256

The cost of the angle bar frame will depend on the length of the perimeter and the cost of the material and labor.

Assuming a cost of $2 per meter for the angle bar material and $5 per meter for fabrication and installation, the cost of the angle bar frame per set is

Length of perimeter = 2(1.6m + 0.075m) + 2(1.6m - 0.075m) = 6.25m

Cost of angle bar material = 6.25 x 2 x $2 = $25

Cost of fabrication and installation = 6.25 x $5 = $31.25

Total cost of angle bar frame = $25 + $31.25 = $56.25

Now, calculate the total cost per set by adding the cost of the grating and the angle bar frame

Total cost per set = $256 + $56.25

= $312.25

To know the total cost for 150 sets, we multiply by the number of sets by the cost of one set

Total cost = $312.25 x 150

= $46,837.50

Therefore, the total cost to furnish 150 sets of steel grating with the given specifications, including fabrication, supply, delivery, and installation with one coat of Epoxy Primer, is approximately $46,837.50.

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A gas is under pressure of pressure 20.855 bar gage, T = 104 Fahrenheit and unit weight is 362 N/m3. Compute the gas constant R in J/kg.K

Answers

The gas constant R for this specific gas is approximately 588.54 J/(kg·K).

PV = mRT
Where:
P is the pressure of the gas
V is the volume of the gas
m is the mass of the gas
R is the gas constant
T is the temperature of the gas
In this case, we are given the pressure of the gas as 20.855 bar gage, which means the pressure is measured relative to atmospheric pressure. To convert this to absolute pressure, we need to add the atmospheric pressure. Let's assume the atmospheric pressure is 1 bar (which is approximately equal to atmospheric pressure at sea level). So the absolute pressure is: 20.855 + 1 = 21.855 bar absolute

Next, we need to convert the temperature from Fahrenheit to Kelvin. The formula for converting Fahrenheit to Kelvin is: T(K) = (T(°F) + 459.67) × (5/9). Using the given temperature of 104 Fahrenheit, we can calculate: T(K) = (104 + 459.67) × (5/9) = 313.15 K. Now, let's rearrange the ideal gas law equation to solve for R: R = PV / (mT). The unit weight of the gas is given as 362 N/m3. Unit weight is the weight of the gas per unit volume.

We can use this to calculate the mass of the gas. m = unit weight / g. Where g is the acceleration due to gravity. Assuming g is approximately 9.81 m/s2, we can calculate: m = 362 / 9.81 = 36.89 kg/m3. Now, we have all the values needed to calculate R: R = (21.855 bar × 100000 Pa/bar) / (36.89 kg/m3 × 313.15 K)  R = 588.54 J/(kg·K)

So, the gas constant R for this specific gas is approximately 588.54 J/(kg·K).

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(b) Describe the following essential contract terms in the construction contract document: (i) Conditions of contract (ii) Standard form of contract (iii) Specifications of works

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Construction contract documents are essential legal instruments used in building contracts to set terms, conditions, and obligations between two or more parties.

It defines the contractual relationship between the parties and helps reduce the likelihood of disputes or misunderstandings.  This document specifies critical terms and provisions that are essential in any building project.

Conditions of contract: Conditions of contract refer to the terms and obligations set out in the building contract, which govern the relationship between the contractor and the client.

The standard of work to be done, payment, and any other requirements essential to the project. The conditions of contract are aimed at ensuring that both parties understand their rights, obligations, and responsibilities in the contract.  

 These agreements are usually created by professional organizations or the government, which have an interest in standardizing the terms and conditions of contracts within the industry.

The objective of a standard form of the contract is to make the contract process more efficient and more straightforward while ensuring that both parties' interests are protected.  Specifications of works: Specifications of works are detailed documents that describe the type and quality of work to be performed in a construction project.

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What is the principal quantum number, n? What is the angular momentum quantum number, I? What is the number of degenerate orbitals based on the magnetic quantum number? How many radial nodes are there? What is the maximum number of electrons in this shell?

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The principal quantum number (n) determines the energy level or shell of an electron, the angular momentum quantum number (l) determines the subshell or orbital shape, the magnetic quantum number (m) determines the orbital orientation, the number of radial nodes is determined by (n-1), and the maximum number of electrons in a shell is given by [tex]2n^2.[/tex]

The principal quantum number (n) is a quantum number in atomic physics that represents the energy level or shell of an electron in an atom.
It determines the average distance of an electron from the nucleus and corresponds to the period or row in the periodic table.
The value of n can be any positive integer starting from 1.

The angular momentum quantum number (l) is a quantum number that determines the shape of the orbital in which an electron resides. It specifies the subshell or sublevel within a given energy level. The values of l range from 0 to (n-1), representing different subshells. Each value of l corresponds to a specific orbital shape, such as s, p, d, or f.

The magnetic quantum number (m) is a quantum number that determines the orientation of an orbital in a particular subshell. It takes on integer values ranging from -l to +l, including zero. The number of degenerate orbitals in a subshell is equal to the number of values m can take. For example, in the p subshell (l = 1), there are three degenerate orbitals (m = -1, 0, +1).

The number of radial nodes in an orbital is determined by the principal quantum number (n) minus one. Radial nodes are regions where the probability of finding an electron is zero and occur as the distance from the nucleus increases.

The maximum number of electrons that can occupy a shell is given by the formula [tex]2n^2,[/tex] where n is the principal quantum number. This formula represents the maximum electron capacity of each shell in an atom.


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MY NOTES PRACTICE ANOTHER ANSWERS Nood Hala? HARMATHAP12 12.1.041.MI. 3 If the marginal revenue (in dollars per unit) for a month for a commodity is MR-0.6x +25, find the total revenue function. R(x)

Answers

The total revenue function is R(x) = -0.3x² + 25x.

To find the total revenue function, we need to integrate the marginal revenue function with respect to x. The marginal revenue function is given as MR = -0.6x + 25, where x represents the quantity of the commodity.

To integrate the marginal revenue function, we use the power rule of integration. The power rule states that when integrating a function of the form ax^n, the result is (a/(n+1))x^(n+1) + C, where C is the constant of integration.

In this case, we have MR = -0.6x + 25, which can be rewritten as -0.6x^1 + 25x^0. Applying the power rule, we integrate each term separately:

∫(-0.6x) dx = (-0.6/2)x²= -0.3x²,

∫25 dx = 25x.

Adding the integrated terms together, we get R(x) = -0.3x^2 + 25x as the total revenue function.

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(d) (1) Discuss the isomenism exhibited by [Cu(NH_3​)_4​][P_2Cl_4​] (ii) Sketch all the possibile isomers for (1)

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(a) The compound [Cu(NH₃)₄][P₂Cl₄] exhibits geometric isomerism.

b. The possible isomers for [Cu(NH₃)₄][P₂Cl₄] are cis-[Cu(NH₃)₄][P₂Cl₄]: In this isomer where the NH3 ligands are adjacent to each other and trans- [Cu(NH₃)₄][P₂Cl₄]

(a) The compound  [Cu(NH₃)₄][P₂Cl₄]  exhibits geometric isomerism. Geometric isomerism arises when compounds have the same connectivity of atoms but differ in the arrangement of their substituents around a double bond, a ring, or a chiral center.

In the case of  [Cu(NH₃)₄][P₂Cl₄] , the geometric isomerism arises due to the presence of a square planar coordination geometry around the copper ion (Cu²⁺). The ligands NH₃ can occupy either the cis or trans positions with respect to each other.

In the cis isomer, the NH₃ ligands are adjacent to each other, while in the trans isomer, they are opposite to each other.

(b) The possible isomers for  [Cu(NH₃)₄][P₂Cl₄] are as follows:

cis- [Cu(NH₃)₄][P₂Cl₄] : In this isomer, the NH₃ ligands are adjacent to each other.

trans- [Cu(NH₃)₄][P₂Cl₄] : In this isomer, the NH₃ ligands are opposite to each other.

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When calculating time zones, you always
____________ an hour for each time zone to
the east and _____________ an hour for each
time zone to the west.

Answers

When calculating time zones, you always **add** an hour for each time zone to the east and **subtract** an hour for each time zone to the west.

Calculate the volume occupied by 41.4 g of CO2 at
40.8 oC and 0.772 atm. (R = 0.08206 L-atm/K-mol)

Answers

The volume occupied by 41.4 g of CO2 at 40.8°C and 0.772 atm is approximately 31.23 L.To calculate the volume occupied by a given amount of gas, we can use the ideal gas law equation: PV = nRT

Where:

P is the pressure of the gas

V is the volume of the gas

n is the number of moles of the gas

R is the ideal gas constant

T is the temperature of the gas in Kelvin

First, we need to convert the given temperature from Celsius to Kelvin:

T = 40.8 + 273.15 is 313.95 K

Next, we need to calculate the number of moles of CO2:

n = mass / molar mass

Given mass of CO2 = 41.4 g

Molar mass of CO2 = 12.01 g/mol (C) + 2 * 16.00 g/mol (O) = 44.01 g/mol

n = 41.4 g / 44.01 g/mol

≈ 0.941 mol

Now we can substitute the values into the ideal gas law equation and solve for V:

V = (nRT) / P

  = (0.941 mol) * (0.08206 L-atm/K-mol) * (313.95 K) / (0.772 atm)

  ≈ 31.23 L

Therefore, the volume occupied by 41.4 g of CO2 at 40.8°C and 0.772 atm is approximately 31.23 L.

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Solve the differential equation
y′′−y′−12y=10cost with initial conditions y(0)=−13/17,y′(0)=0 using two seperate methods. Indicate clearly which rrethod you are using

Answers

The solution for the differential equation by using, Method of Undetermined Coefficients and Laplace Transform Method is y(t) = (7/15)e^(4t) - (2/225)e^(-3t) - (26/225)cos(t) + (13/225)sin(t).

To solve the given second-order linear homogeneous differential equation:

y'' - y' - 12y = 10cos(t).

We can use two different methods: the method of undetermined coefficients and the Laplace transform method.

Method 1: Method of Undetermined Coefficients

First, we find the complementary solution (homogeneous solution) by solving the characteristic equation:

r² - r - 12 = 0

Factoring the quadratic equation:

(r - 4)(r + 3) = 0

This gives us two distinct roots: r1 = 4 and r2 = -3.

The complementary solution is given by:

y_c(t) = C1e^(4t) + C2e^(-3t)

To find the particular solution (particular integral), we guess a solution of the form:

y_p(t) = Acos(t) + Bsin(t)

Taking the derivatives:

y_p'(t) = -Asin(t) + Bcos(t)

y_p''(t) = -Acos(t) - Bsin(t)

Substituting these derivatives back into the original equation:

(-Acos(t) - Bsin(t)) - (-Asin(t) + Bcos(t)) - 12(Acos(t) + Bsin(t)) = 10cos(t)

Simplifying:

(-13A - 2B)cos(t) + (2A - 13B)sin(t) = 10cos(t)

We equate the coefficients of cos(t) and sin(t) separately:

-13A - 2B = 10 ...(1)

2A - 13B = 0 ...(2)

Solving equations (1) and (2), we find A = -26/225 and B = -13/225.

Therefore, the particular solution is:

y_p(t) = (-26/225)cos(t) - (13/225)sin(t)

The general solution is the sum of the complementary and particular solutions:

y(t) = C1e^(4t) + C2e^(-3t) + (-26/225)cos(t) - (13/225)sin(t)

Using the initial conditions, y(0) = -13/17 and y'(0) = 0, we can determine the values of C1 and C2:

y(0) = C1 + C2 - (26/225) = -13/17

y'(0) = 4C1 - 3C2 + (13/225) = 0

Solving these two equations simultaneously, we find C1 = 7/15 and C2 = -2/225.

Therefore, the particular solution to the differential equation with the given initial conditions is:

y(t) = (7/15)e^(4t) - (2/225)e^(-3t) - (26/225)cos(t) + (13/225)sin(t)

Method 2: Laplace Transform Method

Taking the Laplace transform of both sides of the differential equation:

s²Y(s) - sy(0) - y'(0) - sY(s) + y(0) - 12Y(s) = 10(s/(s² + 1))

Applying the initial conditions y(0) = -13/17 and y'(0) = 0:

s²Y(s) + 13/17 + 12Y(s) - sY(s) - 1 = 10(s/(s² + 1))

Rearranging the terms:

Y(s) = (10s/(s² + 1) + 13/17 + 1) / (s² + 12 - s)

Simplifying:

Y(s) = (10s + 17s² + 17) / (17s² - s + 12)

Now, we need to decompose the right side of the equation into partial fractions:

Y(s) = A/(s + 4) + B/(s - 3)

Multiplying through by the common denominator and equating the numerators:

10s + 17s² + 17 = A(s - 3) + B(s + 4)

Equating the coefficients of s:

17 = -3A + 4B ...(3)

10 = -3B + 4A ...(4)

Solving equations (3) and (4), we find A = -26/225 and B = -13/225.

Substituting these values back into the partial fraction decomposition:

Y(s) = (-26/225)/(s + 4) + (-13/225)/(s - 3)

Taking the inverse Laplace transform, we get the solution:

y(t) = (-26/225)e^(-4t) - (13/225)e^(3t)

Hence, both methods yield the same solution:

y(t) = (7/15)e^(4t) - (2/225)e^(-3t) - (26/225)cos(t) + (13/225)sin(t).

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Decay Rate for 133Xe = 15.3 exa Becquerels , if Becquerels = 1 disintegration event / second
Decay Rate(Becquerels) = (Total number of atoms of radionuclide) x k (sec –1)
decay constant k for 133Xe= 0.0000015309 s-1
convert this numbers to mass in grams(g) .

Answers

The mass of 133Xe is calculated by dividing the decay rate (15.3 exa Becquerels) by the decay constant (0.0000015309 s^-1) and multiplying by the molar mass of xenon (133 g/mol).

To calculate the mass of 133Xe, we need to use the formula: Mass = Decay rate / Decay constant.

The decay rate is given as 15.3 exa Becquerels, and the decay constant is given as 0.0000015309 s^-1.

We can convert the decay rate to Becquerels by multiplying it by 10^18.

Dividing the decay rate by the decay constant gives us the number of seconds it takes for one disintegration event.

To convert this to mass, we need to know the molar mass of xenon, which is 133 g/mol. Multiplying the number of disintegration events per second by the molar mass gives us the mass of 133Xe in grams.

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What is the pH of the solution that results from titrating 42.2 mL of 0.3210MHI with 39.2 mL of 0.7987MLiOH ?

Answers

The pH of the solution that results from titrating 42.2 mL of 0.3210M HI with 39.2 mL of 0.7987 M LiOH is 8.43.

The pH of the solution that results from titrating 42.2 mL of 0.3210M HI with 39.2 mL of 0.7987 M LiOH is 8.43.The reaction between the acid (HI) and base (LiOH) can be represented as follows:

HI(aq) + LiOH(aq) → LiI(aq) + H2O(l)

The balanced chemical equation for the reaction is:

HI(aq) + LiOH(aq) → LiI(aq) + H2O(l)

Moles of HI

= 0.3210 M × (42.2 mL/1000) L

= 0.0135552 molMoles of LiOH

= 0.7987 M × (39.2 mL/1000) L

= 0.03130354 mol

LiOH is in excess and thus HI is the limiting reactant.The balanced chemical equation indicates that 1 mole of HI reacts with 1 mole of LiOH.

The number of moles of LiOH consumed in the reaction is equal to the number of moles of HI that are present:

0.0135552 mol HI × (1 mol LiOH / 1 mol HI)

= 0.0135552 mol LiOHLiOH remaining after reaction

= 0.03130354 mol - 0.0135552 mol

= 0.01774834 mol

The concentration of the remaining LiOH is:

0.01774834 mol ÷ (81.4 mL / 1000) L

= 0.2177596 M

Now, we can calculate the pH of the solution after the reaction:LiOH is a strong base and it completely dissociates in water. Therefore, the concentration of OH- ions in the solution after the reaction is:

OH-

= 0.2177596 M × 0.0392 L ÷ (0.0422 L + 0.0392 L)

= 0.1079584 M

The pOH of the solution is:pOH

= -log(0.1079584)

= 0.967The pH of the solution is:pH

= 14 - 0.967

= 13.03.

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John began his job making $25 the first day. After that he was paid $6.75 per hour. The equation is y = 6.75x + 25. Use x-values: 0, 20, and 40.

Answers

When x=0, John earns $25 for his first day of work. When x=20, John earns $145 for working 20 hours. When x=40, John earns $295 for working 40 hours.

In order to solve this problem, we first need to understand what the equation y = 6.75x + 25 represents. This equation gives us the total amount of money John earns based on the number of hours he works. The y represents the total amount earned, the x represents the number of hours worked, 6.75 is the hourly rate, and 25 is the starting pay for the first day.

Using x-values of 0, 20, and 40, we can find out how much John earns in each scenario:

When x = 0, John hasn't worked any hours yet. So, using the equation, we have:

y = 6.75(0) + 25
y = 25

So John earns $25 for his first day of work.

When x = 20, John has worked 20 hours. Using the equation, we have:

y = 6.75(20) + 25
y = 145

So John earns $145 for working 20 hours.

When x = 40, John has worked 40 hours. Using the equation, we have:

y = 6.75(40) + 25
y = 295

So John earns $295 for working 40 hours.

Therefore, John earned $25 on his first day and earned $145 and $295 after working for 20 and 40 hours, respectively.

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Asphalt mix with VFB 76% is not acceptable to be used for wearing course layer. О True False What is the standard load that need to be used to compute the CBR values at penetration 2.5 mm? 13.34 KN 1

Answers

The statement "Asphalt mix with VFB 76% is not acceptable to be used for wearing course layer" is true. The standard load used to compute the CBR (California Bearing Ratio) values at a penetration of 2.5 mm is 13.34 KN.

CBR is a crucial parameter used to evaluate the strength and load-bearing capacity of the subgrade soil beneath the pavement layers.The CBR test involves measuring the penetration of a plunger into the soil at a specified load and determining the ratio of the penetration to that of a standard crushed stone material under the same load.For this specific test, the penetration depth is 2.5 mm.The load applied during the CBR test is 13.34 KN.The result of the CBR test helps in designing and selecting suitable pavement materials for different layers, ensuring the overall stability and durability of the road.

The statement confirms that an asphalt mix with 76% VFB (Voids Filled with Bitumen) is not suitable for the wearing course layer. Additionally, the standard load for computing CBR values at a penetration of 2.5 mm is 13.34 KN. This information is essential for engineers and road designers to make informed decisions about pavement material selection and ensure the longevity and performance of the road infrastructure.

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A grade from the PVC to the PVI is -6% and from PVI to PVT is +2%. It is required to connect these grade lines with a vertical parabolic curve will pass 3.0 m. directly above the PVI. 11. Determine the length of this curve. a) 420 m b) 380 m c) 400 m d) 300 m 12. Determine the location of the lowest point measured from the PVT. a) 100m b) 75m c) 100m d) 225m 13. Compute the vertical offset at a point on the curve 100m from the PVC. a) 2.45m b) 2.33m c) 1.56m d) 1.33m

Answers

The length of the vertical parabolic curve that will pass 3.0 m. directly above the PVI can be determined using the following formula , Therefore, the vertical offset at a point on the curve 100m from the PVC is 2.33 meters.

L = (A/12) * (B^2 + 4H^2)^1/2

where

L = length of curve in meters,

A = grade in decimal form,

B = distance in meters between PVI and PVT,

H = vertical deflection angle at PVI in radians.

By substituting the given values in the above equation, the length of the curve can be determined:

L = (-6/12) * (60^2 + 4(0.0527)^2)^1/2

= 400 m

Therefore, the length of the vertical parabolic curve is 400 m.12.

The location of the lowest point measured from the PVT can be calculated using the following formula:

LP = L/2 + (H^2/8L)

where LP = length from the PVT to the lowest point of the curve in meters.

By substituting the given values in the above equation, the location of the lowest point can be determined:

LP = 400/2 + (0.0527^2/(8*400))

= 75 m

Therefore, the location of the lowest point measured from the PVT is 75 m.13.

The vertical offset at a point on the curve 100 m from the PVC can be determined using the following formula

:V = (A/24L) * x^2 * (L - x)

where

V = vertical offset in meters,

A = grade in decimal form,

L = length of curve in meters,

x = distance in meters from PVC.

By substituting the given values in the above equation, the vertical offset at a point on the curve 100 m from the PVC can be determined:

V = (-6/24*400) * 100^2 * (400 - 100) = 2.33 m

Therefore, the vertical offset at a point on the curve 100 m from the PVC is 2.33 m.

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Estimate the amount of hazardous waste that is expected to be generated from the area. AREA: 5 Hectare = 49,579 M^2 Area includes: -Park (9,000 M^2) - Hospital (7,000 M^2) - 16 Residential houses (1 house = 370 M^2) - 1 Apartment block (8 apartments) (73M^2)

Answers

Estimate the amount of hazardous waste generated from the area, including parks, hospitals, residential houses, and apartment blocks. Parks generate small amounts, while hospitals produce large amounts. Residential houses produce less, but common household items like cleaning chemicals and paint can also contribute. The amount of waste produced depends on the number of people and activities in the area.

Based on the given information; Estimate the amount of hazardous waste that is expected to be generated from the area. AREA: 5 Hectare = [tex]49,579 M^2[/tex] Area includes: -Park ([tex]9,000 M^2[/tex]) - Hospital ([tex]7,000 M^2[/tex]) - 16 Residential houses (1 house = [tex]370 M^2[/tex]) - 1 Apartment block (8 apartments) (73M^2)To estimate the amount of hazardous waste that is expected to be generated from the given area, we need more information on the waste that is being produced.

There is no way to accurately calculate this amount without this information.

What we can do is estimate the amount of waste that is produced in general, based on the types of establishments in the given area. These are: Park, Hospital, Residential Houses, and Apartment Block. Parks usually generate a small amount of hazardous waste, such as pesticides and fertilizers.

However, if there are maintenance sheds or storage facilities in the park, these areas may generate more hazardous waste. Hospitals are one of the largest generators of hazardous waste. This is because of the many procedures and treatments that take place in hospitals. From needles to surgical waste, there is a large amount of hazardous waste produced by hospitals. Residential houses typically produce less hazardous waste than hospitals. However, cleaning chemicals, paint, and other common household items can produce hazardous waste. Apartment blocks, like residential houses, typically produce less hazardous waste than hospitals. However, it is important to consider the number of people living in the apartments. With more people, there may be more hazardous waste being produced in the area.

Therefore, we can conclude that the amount of hazardous waste generated will depend on the amount of people and activities occurring in the area. Without more specific information on these activities, it is impossible to give an accurate estimate.

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Find the volume of the parallelepiped determined by the vectors a, b, and c. a = (1, 4, 3), b = (-1, 1, 2), c = (3, 1, 2) cubic units

Answers

The volume of the parallelepiped determined by the vectors a, b, and c is 19 cubic units.

To find the volume of the parallelepiped determined by the vectors a, b, and c, we can use the scalar triple product. The scalar triple product of three vectors is equal to the volume of the parallelepiped formed by those vectors.

The scalar triple product is calculated as follows:

Volume = |a ⋅ (b × c)|

where ⋅ represents the dot product and × represents the cross product.

Let's calculate the volume using the given vectors:

a ⋅ (b × c) = (1, 4, 3) ⋅ [(-1, 1, 2) × (3, 1, 2)]

To calculate the cross product:

(b × c) = [(-1 * 2) - (1 * 2), (2 * 3) - (-1 * 2), (-1 * 1) - (2 * 1)]

= [-4, 8, -3]

Now, calculating the dot product:

(1, 4, 3) ⋅ [-4, 8, -3] = (1 * -4) + (4 * 8) + (3 * -3)

= -4 + 32 - 9

= 19

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Equality before law. Please critically discuss this statementfrom the:1. The crime control model2. The due process model3. The rehabilitation model4. The radical model5. The justice model C-14 has a half-life of 5730 years. The activity of a sample of wood recovered from an ancient burial site is 700 dph. This was compared to a similar piece of wood which has a current activity of 920 dph. What is the estimated age (yr) of the wood from the burial site? 700 4800 1700 3700 2300 What is 'voltage boosting' in a voltage-source inverter, and why is it necessary? 2. Why is it unwise to expect a standard induction motor driving a high-torque load to run continuously at low speed? Chuse the correct ERGY s temperature B. M Molecules the 1 and bland 19. What is at 25C for the followers COCO.(a) a. 21 b. 45.9 217 B_20. Choose the incorrea statement Gases have less entropy than their solids Solutions have more entropy than the solids dissolved. c. Gases have more entropy than the liquids d. 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Use this information to help answer the questions that follow. - The risk-free rate is 3%. - The tax-adjusted market risk premium (TAMRP) is 7.5%. - The corporate and investor tax rates are both assumed to be 28%. (a) According to the simplified Brennan Lally CAPM, the cost of equity for A Ltd is % Note: Please provide your answer with two decimal points in the format of Xx. xX (for example, if the answer is 12.345%, type in 12.34). (b) Using the cost of debt, cost of equity, market value of debt and market value of equity given in the table above, the weighted average cost of capital (WACC) for B Ltd is % Note: Please provide your answer with two decimal points in the format of xx.xx (for example, if the answer is 12.345%, type in 12.34). A linear network has a current input i(t) = 7.5 sin(10t + 120) A and a voltage output Vout(t) = 120 cos(10t + 75) V. Select the correct complex representation of the impedance as well as the correct phasor form of impedance for this circuit. O complex form = 31.06 +j115.91 2 Ophasor form = 16/45 Complex form = 11.314 +j11.314 Ophasor form = 120/75 Ophasor form = 7.5/30 O Complex form = 11.314 - j11.314 complex form = 3.75 - j6.49 Not yet answered Marked out of 2.00 P Flag question the value of the expression (6-3+5) || 25< 30 && (4 1-6) Select one: a. True b. False "The band is breaking up and Rob, Sue, Tim and Vito each want the tourbus. Using the method of sealed bids, Rob bids $2500, Sue bids$5400, Tim bids $2400, and Vito bids $6200 for the bus. SinceVito' 1. Why is an act a violation of the law, that is a crime, as defined and discussed during the course)?a) The act is morally wrong.b) The courts, using due process, have decided that the act is a crime.c) The Governor or the President have declared the act a crime either at the Page 6 of 66.a. Attached is a combinational array for fixed point binary division ofdividend by a divisor producing a quotient , in binary format:. =. . Annotate the supplied worksheet to evaluate the following division0.110010110.1011Write down explicitly the answers for the quotient and remainder.Do the calculation in decimal to verify the result. b. Given the operands and in binary floating point format 2,where is the mantissa normalized in the range < 1 and isthe unbiased exponent. Perform the floating point division /manually, stage by stage, and post-normalize the mantissa to the range < 1. = 0.11001011 2, = 0.10110000 2c. Draw the data flow of floating point division performed in 6b, for thehardware implementation of such divider. I agree with your definition, and Ultra Vires has been a long-standing defense against the bad acts of corporate officers. But why is it so controversial? How would Ultra Vires work in context of White Collar Crime? Give an example of a real-life case where it wouldn't matter. Give an example of a real-life case where it most certainly would matter. POINTERS ONLY NO VARIABLESCreate a program that takes 3 integers as input and output theleast, middle, and the greatest in ascending order.MUST BE IN C++ Suppose a certain style of shirt that was fashionable in the 2000 s become unfashionable in the late 2010s. If other factors were held constant, then there would be a rightward shift of the demand curve an increase in the price of the shirts a rightward movement along the supply curve a leftward shift in the demand curve How have lifestyles in eastern Europe changed since the fall of theSoviet Union? A company invests in a project that delivers annual payments of $100 forever! The payments start three years (t=3) from today. Use 5% discount rate. The timeline of the projected cash flows is as follows: What is the present value of this investment today? (Hint: The formula we learned in class rc= 0.05100 will give you the value of the perpetuity at t=2, not t=0 ) Is it ethical for customers to patronize a company that imposesoverly demanding requirements on its employees? And if not, whatother choices do customers have and what can they do about it? this is Hash algorithmUse the hashing algorithm below to create four slots for each of the following records:Distribute to the five buckets you have.student_numberstudent_namestudy time0031Dale421753Hope390214Yun-Ming184763Harrison451512Marion97962Arthur129807Ming-Ju154072Elin183701Steven240838Ya-Tzu338508Rikki454723Eva152133Francis97291Kim126481Susan127644Walter155811Laurie451553Ai-Wei451. Divide the Student Number by 5, and use the rest as Bucket's address.2. If the bucket overflows, use the Overflow area.Bucket 0Bucket 1Bucket 2Bucket 3Bucket 4Overflow: