Find the number of moles of oxygen atoms in 3.00 mol of copper(II) sulphate pentahydrate.

If the volume of the balloon was 4.21L when the temperature was 25.0°C, 8.42L will be the volume of the balloon be when the temperature is 50.0°C. if Mass and pressure is constant.

Hence, in the above case it is shown that temperature is rising twice of its original value so, the volume of that given mass of gas in the balloon will also increase by twice.

Solution:

4.21L=25.0°C

4.21L×2=50.0°C

8.42L=50.0°C

8.42L will be the volume of the balloon be when the temperature is 50.0°C.

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The amount, in grams, of carbon required to produce 14 moles of methane according to the reaction would be 168.0 grams.

From the balanced equation of the reaction, the mole ratio of the carbon that reacts and the methane produced is 1:1. In other words, 1 mole of carbon will produce 1 mole of methane.

Thus, for the production of 14 moles of methane:

1 mole methane = 1 mole carbon

14 moles methane = 14 x 1/1 = 14 moles carbon.

Recall that, mass = mole x molar mass.

The molar weight of carbon is given as 12 g/mol

Mass of 14 moles carbon = 14 x 12 = 168 grams

In other words, for the illustrated reaction, the amount of carbon required to produce 14 moles of methane would be 168.0 grams.

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Answer:

I believe it's mass? I may be wrong though...

Answer: The Equator because it divides the Earth into the Northern and Southern hemispheres.

Explanation:

Answer: A cold compress used by  athletes is an endothermic reaction.

Explanation:

A pack of cold compress used by athletes contains water that holds another bag or tube inside it which is filled with ammonium nitrate fertilizer.

So, on hitting the cold compress the tube breaks down due to which fertilizer gets mixed with water. This mixture absorbs the heat when placed on the area of body having pain, strain or bump.

As a result, we tend to feel cold at the affected area of our body.

Thus, we can conclude that a cold compress used by  athletes is an endothermic reaction.

Answer:

10.52g KOH

Explanation:

250.0 ml X 1L/1000ml X 0.75 mol KOH/1L X 56.105gKOH/1 mol KOH =10.52g KOH

Answer:

The concentration of the unknown HCl is 0.0851 M.

Explanation:

The equation of neutralization:

[tex]n_1M_1V_1=n_2M_2V_2[/tex]

Where:

[tex]n_1[/tex]= Basicity of acid

[tex]n_2[/tex] = Acidity of base

[tex]M_1[/tex]= concentration  of acid

[tex]M_2[/tex]= concentration  of base

[tex]V_1[/tex] = Volume of acid used in neutralization

[tex]V_2[/tex] = Volume of base used in neutralization

We have:

The acidity of HCl = [tex]n_1=1[/tex]

The concentration of HCl solution used = [tex]M_1=?[/tex]

The volume of HCl used in titration =[tex]V_1= 15.00 mL[/tex]

The acidity of NaOH =[tex]n_2=1[/tex]

The concentration of NaOH solution used = [tex]M_2=0.0670 M[/tex]

The volume of NaOH used in titration =[tex]V_2= 19.06 mL[/tex]

[tex]n_1M_1V_1=n_2M_2V_2\\1\times M_1\times 15.00 mL=1\times 0.0670 M\times 19.06 mL\\M_1=\frac{1\times 0.0670 M\times 19.06 mL}{1\tines 15.00 mL}\\M_1=0.085135 M\approx 0.0851 M[/tex]

The concentration of the unknown HCl is 0.0851 M.

Answer:

Water doesn't have ions that are needed to pass the electricity so in order to increase the no of ions we poor acid into the water. Just increasing the no ions will increase the electricity flow faster

Answer:

[tex]\boxed {\boxed {\sf 3.3 \ liters}}}[/tex]

Explanation:

Molarity is a measure of concentration in moles per liter.

[tex]molarity=\frac{moles \ of \ solute}{liters \ of \ solution}}[/tex]

The solution has a molarity of 1.2 M or 1.2 moles per liter. There are 4.0 moles of NaCl, the solute. We don't know the liters of solution, so we can use x.

Substitute the values into the formula.

[tex]1.2 \ mol/L = \frac{4.0 \ mol}{x}[/tex]

Since we are solving for x, we must isolate the variable. Begin by cross multiply (multiply the 1st numerator and 2nd denominator, then the 1st denominator and 2nd numerator.

[tex]\frac {1.2 \ mol/L}{1}=\frac{ 4.0 \ mol}{x}[/tex]

[tex]4.0 \ mol *1=1.2 \ mol/L *x[/tex]

[tex]4.0 \ mol = 1.2 \ mol/L *x[/tex]

x is being multiplied by 1.2 moles per liter. The inverse of multiplication is division, so divide both sides by 1.2 mol/L

[tex]\frac{4.0 \ mol}{1.2 \ mol/L} = \frac{1.2 \ mol/L *x}{1.2 \ mol/L}[/tex]

[tex]\frac{4.0 \ mol}{1.2 \ mol/L}=x[/tex]

The units of moles (mol) will cancel.

[tex]\frac{4.0 }{1.2 } \ L =x[/tex]

[tex]3.33333333 \ L=x[/tex]

The original measurements both have 2 significant figures, so our answer must have the same. For the number we found, this is the tenths place.

The 3 in the hundredth place tells us to leave the 3 in the tenths place.

[tex]3.3 \ L\approx x[/tex]

Approximately  3.3 liters of solution are needed to make a 1.2 M solution with 4.0 moles of sodium chloride.

Answer:

the correct answer is 6...

Answer:

The answer is 2

Answer:

Explanation:

Given pinene has a (temperature, vapor pressure) relation (K, torr) = {(373, 135), (429, 760)}, you want the heat of vaporization in kJ/mol and the vapor pressure at room temperature (23 °C).

The Clausius–Clapeyron equation can be used to find the heat of vaporization:

  [tex]\ln{P}=-\dfrac{\Delta H_{\text{vap}}}{R}\left(\dfrac{1}{T}\right)+C[/tex]

Solving for ∆H, we find ...

  [tex]\Delta H_{\text{vap}}=-\dfrac{R\cdot\ln{\dfrac{P_1}{P_2}}}{\dfrac{1}{T_1}-\dfrac{1}{T_2}}\\\\\\\Delta H_{\text{vap}}=-\dfrac{8.314\cdot\ln{\dfrac{760}{135}}}{\dfrac{1}{429}-\dfrac{1}{373}}\approx 41052.8[/tex]

The heat of vaporization of pinene is about 41 kJ/mol.

Rearranging the above equation to give P1, we have ...

  [tex]\ln{\dfrac{P_1}{P_2}}=-\dfrac{\Delta H_\text{vap}}{R}\left(\dfrac{1}{T_1}-\dfrac{1}{T_2}\right) \\\\\\P_1=P_2\cdot e^{-\frac{\Delta H_\text{vap}}{R}\left(T_1^{-1}-T_2^{-1})}[/tex]

Using the same P2 and T2 as above, we find the vapor pressure at room temperature (296.15 K) to be ...

  P1 ≈ 4.349 . . . . . torr

The vapor pressure of pinene at room temperature is about 4 torr.

There is no other feasible arrangement of “tetramethylbutane” it is redundant in this circumstance.

Tetramethylbutane, often known as hexamethylethane, is a hydrocarbon with the chemical formula C8H18 or (H3C-)3C-C(-CH3)3. It is the most branching and compact of the several octane isomers, as well as the only one having a butane (C4) backbone.

It has a highly symmetrical structure, a high melting point, and a narrow liquid range; in fact, it is the smallest saturated acyclic hydrocarbon that emerges as a solid at 25 °C. (Cubane, C8H8, is much smaller and solid at room temperature among cyclic hydrocarbons.) It is also the most stable C8H18 isomer, with a lower heat of formation of 4.18 kcal/mol (17.5 kJ/mol) than n-octane, which has been related to dispersive interactions (electron correlation) between the methyl groups (protobranching).

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Answer:

beryllium (Be), magnesium (Mg), calcium (Ca), strontium (Sr), barium (Ba), and radium (Ra).

Alkaline earth metals are those that have two valence electrons in their outermost shell.

Barium (Ba), Radium (Ra), Strontium (Sr), Magnesium (Mg), Calcium (Ca), and Beryllium (Be) are the six alkaline earth metals.

By donating their outermost electrons, they take on the noble gas electron configuration, which increases their stability. When electrons are transferred to an atom with an electronegative charge, the alkaline earth metals get a positive charge.

The second column of the periodic table contains alkaline earth metals, which are very reactive metals. These metals are the building blocks of the entire world. These metals are typically found as sulfates in nature.

A few examples of minerals are gypsum, calcium sulfate, epsomite, magnesium sulfate, barite, and barium sulfate.

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Answer:

false

because you can't change a subscript ,

but you can change the coefficient.

Answer:

d. C6H14 > C6H12 > C6H6

Explanation:

Standard molar entropy has to do with the number of atoms that are present in each of the species. The greater the number of atoms possessed by the species, the higher the value of the standard molar entropy due to a greater number of vibration modes.

Hexane (C6H14) has the highest number of atoms followed by cyclohexane (C6H12) and lastly benzene (C6H6).

Thus the order of decreasing molar entropy is;  C6H14 > C6H12 > C6H6.

Option C. Sodium metal is soft and malleable is an example of a physical property.

A physical property can be defined as any feature of a substance that can be really observed and also measured without changing its chemical composition such as for example, the color, density of a metal, boiling point, conductivity, etc.

Therefore, with this data, we can see that physical properties have a significant impact on the performance and use of a given chemical product and they are associated with intrinsic features of the chemical material that forms molecules.

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Answer:

N atom ( bounded to two Nitrogen atoms ) has a +  formal charge while the N atom bounded to only one (1) Nitrogen atom has a - formal charge .

Explanation:

Diagram Lewis structure of methyl azide ( attached below )

Generally CH3N3 has two(2) resonance structures

What is found in both structures is that the N atom ( bounded to two Nitrogen atoms ) has a +  formal charge while the N atom bounded to only one (1) Nitrogen atom has a - formal charge .

Attached below are the two resonance structures

Answer:

acid base

Explanation:

plz mark me brainliest

Answer:

Possible reasons why EA, or electronegativity, is a positive quantity for oxygen atom include:

Explanation:

Answer: The new pressure is 280 kPa.

Explanation:

Given: [tex]V_{1}[/tex] = 400.0 mL,      [tex]T_{1} = 20^{o}C[/tex] ,       [tex]P_{1}[/tex] = 70.0 kPa

[tex]V_{2}[/tex] = 200.0 mL,        [tex]T_{2} = 40.0^{o}C[/tex],        [tex]P_{2}[/tex] = ?

Now, combined gas law is used to calculate the new pressure as follows.

[tex]\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}[/tex]

Substitute the values into above formula as follows.

[tex]\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{70.0 kPa \times 400.0 mL}{20^{o}C} = \frac{P_{2} \times 200.0 mL}{40.0^{o}C}\\P_{2} = 280 kPa[/tex]

Thus, we can conclude that the new pressure is 280 kPa.

Answer:

(1) 4- ethyl -6 methyl -2 octyne

Answer:

[tex]d=6.34g/cm^3[/tex]

Explanation:

Hello there!

In this case, since the calculation of density is performed by dividing the mass over volume:

[tex]d=\frac{m}{V}[/tex]

Which gives us a better understanding of the degree of compactness of the object; we can find the required density in grams per cubic centimeter by applying the following dimensional analysis in the aforementioned equation:

[tex]d=\frac{0.0124kg}{1893mm^3} *(\frac{10mm}{1cm} )^3*\frac{1000g}{1kg}\\\\d=6.34g/cm^3[/tex]

Regards!

Answer:

liquid

Explanation:

Adjusting pH in Water

Pure or distilled water has a pH level of 7, which means it is neutral. If you want to increase the pH of water, you must add an alkaline substance, such as baking powder, to it. If you want to decrease the pH of water, you add an acidic substance, such as lemon juice, to it

A buffer can be added to a solution to control the pH. The correct option is c.

PH is potential hydrogen. It is the value of how acidic or alkaline, the solution is.

The pH scale is consisting of 1 to 14 measure numbers, a pH less than 7 is acidic and a pH more than 7 is basic.

A buffer is a solution that maintains the pH of any solution.

Thus, the correct option is C, a buffer.

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Answer:

0.355 moldm^-3

Explanation:

Answer: by boiling it

Explanation:

By boiling the sap to remove water, also to concentrate the sugar that makes maple syrup.

When the conductivity is at a minimum, the true thing about the amount of Ba(OH)₂ is that the amount of the two reactants are the same when conductivity is low.

The ability of an aqueous solution to carry an electric current is measured by its conductivity. Ionic strength is measured by conductivity monitors. In automated chromatography systems, conductivity is the main input control parameter used to enable the generation of salt gradients or to control buffer dilution or in-line buffer preparation.

Conductivity monitors can be used to automate and monitor cleaning and equilibration procedures. It's important to remember that temperature affects measurements of conductivity and pH.

When conductivity is low, the amounts of the two reactants are equal. Between the reactants, there are no excesses. The aqueous solution cannot dissolve the precipitate BaSO₄. Since there are no ions, the conductivity is at its lowest.

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Complete question

The Ba(OH)₂ dissociates as Ba+2 + 2 OH-. H₂SO₄ dissociates as 2 H+ + SO₄-2. When the conductivity is at a minimum, what must be true about the amount of Ba(OH)₂ compared to H₂SO₄

Explanation:

38.44 g CO2 = 0.873 mol CO2

0.873 mol CO2 × (1 mol C6H12O6 / 6 mol CO2)

= 0.146 mol C6H12O6 x (180.56 g C6H12O6/ 1 mol C6H12O6)

= 26.303 gm