Find the LCM by first finding the prime factor.

Answer:

Min is 51 and max is 75 and the the mediem is 63 and the q1 is 54 and q2 is 55 and 57 and q3 is 65 and 69

Step-by-step explanation:

the least is 51 and the most is 75 and the mean is 63 if u list them in order and than u find the quartiles that are between the median and 51 and q3 is between the median and the max.

Answer:

140 degrees

Step-by-step explanation:

The formula of the hint is the sum of the angles in a nonagon (9 sided polygon). If we divide the sum of the angles in a nonagon by nine we should be able to get the angle of each nonagon.

(9-2) * 180 = 7 * 180 = 1260

1260/9 = 140 degrees

Answer:

15

Step-by-step explanation:

Trust me it 15.

Too long to explain...

Answer:

$201.6

Step-by-step explanation:

5.60 multiplied by 36 is 201.6

Answer:

$201.60

Step-by-step explanation:

5.6 times 36 = 201.6

Answer:

x = 9

Step-by-step explanation:

(7x + 2)

7x can't be added with 2 because 2 has no x

therefor ,

we take x out

X ( 7 + 2 )

so

X = 9

warning :

sory if the answer is wrong

[tex]\left(\sqrt x - \sqrt{3y} \right) \left(\sqrt x + \sqrt{3y} \right)\\\\=\left(\sqrt x\right)^2 - \left(\sqrt{3y} \right)^2\\\\=x -3y[/tex]

x - 3y

Solving Stepwise:

[tex]\hookrightarrow \sf \left(\sqrt{x}-\sqrt{3y}\right)\left(\sqrt{x}+\sqrt{3y}\right)[/tex]

[tex]\hookrightarrow \sf \left(\sqrt{x}\right)^2-\left(\sqrt{3y}\right)^2[/tex]

[tex]\hookrightarrow \sf x-3y[/tex]

[tex]\dfrac 1{x+y} + \dfrac{3}{x-y} + \dfrac{2}{x^2-y^2} \\\\\\=\dfrac 1{x+y} + \dfrac{3}{x-y} + \dfrac{2}{(x+y)(x-y)}\\ \\\\=\dfrac{x-y+3(x+y)+2}{(x+y)(x-y)}\\\\\\=\dfrac{x-y+3x+3y+2}{(x+y)(x-y)}\\\\\\=\dfrac{4x+2y+2}{(x+y)(x-y)}\\\\\\=\dfrac{2(2x+y+1)}{(x+y)(x-y)}[/tex]

Answer:

16

Step-by-step explanation:

400 miles / 1 gallon every 25 miles = 16 gallons total  

Answer:

4:24 pm

Step-by-step explanation: I first drew it out on a time line and both buses came back together at 4:24 pm. I also looked at the common denominator was for both numbers, 6 and 8: 24.

To check my answer, I substituted other numbers and found that they came back together again at the LCD. Hope this helps.

Answer:

54.96

Step-by-step explanation:

Using the formulas

AL=πrl

l=r2+h2

Solving for AL

AL=πrh2+r2=π·3·52+32≈54.95543

Answer:

9 + x + x + 2 = 29

Step-by-step explanation:

all of the sides added together is 29

so

9 + x + x + 2 = 29

that is your equation

Answer: 254.5

Step-by-step explanation:

Well, at first consider the given equation, then will be solving for Part A) and B),

[tex]{:\implies \quad \sf 5+x-14=x-7}[/tex]

Subtracting x from both sides will yield ;

[tex]{:\implies \quad \sf 5-14=-7}[/tex]

[tex]{:\implies \quad \sf -9=-7}[/tex]

But, -9 ≠ -7, so their is no solution for values of x, as -9 can't be equal to -7 , so from definition of algebra, we can say that, their are no solutions for x, as there are no solutions for x, so nothing can be concluded from Part A and Part B

Answer:

Part A: -9 ≠ -7

no solution

Part B: below for the answers

Step-by-step explanation:

Part A: 5 + x - 14 = x - 7

subtract x on both sides

x - 5 + x - 14 = x - 7 - x

then, we take away the x's

5 - 14 = -7

-9 ≠ -7

there is no solution

Part B: 5 + -2 - 14 = -2 - 7

-11 ≠ -9

5 + 0 - 14 = 0 - 7

-9 ≠ -7

5 + 3 - 14 = 3 - 7

-6 ≠ -4

Answer: 4 1/12

Step-by-step explanation:

Answer:

2 option hope it helps

Hence, option D is correct.

[tex]\dashrightarrow \sf \sqrt{\sqrt[3]{2}}[/tex]

apply radical rule

[tex]\dashrightarrow \sf \left(2^{\dfrac{1}{3}}\right)^{\dfrac{1}{2}}[/tex]

apply exponent rule

[tex]\dashrightarrow \ \sf 2^{\dfrac{1}{6}}[/tex]

[tex]\cfrac{(21x^5y^8)^2}{3x^2}\implies \cfrac{((3)(7)x^5y^8)^2}{3x^2}\implies \cfrac{3^2\cdot 7^2x^{5\cdot 2}y^{8\cdot 2}}{3x^2}\implies \cfrac{3^2}{3}\cdot \cfrac{7^2 x^{10} y^{16}}{x^2} \\\\\\ 3\cdot 7^2 x^{10}\cdot x^{-2} y^{16}\implies 3\cdot 49x^{10-2}y^{16}\implies 147x^8y^{16}[/tex]

Answer:

11

Step-by-step explanation:

Cancel out 22 and 22.

\frac{\mathrm{d}}{\mathrm{d}x}(x)

dx

d

(x)

The derivative of ax^{n}ax

n

is nax^{n-1}nax

n−1

.

x^{1-1}x

1−1Subtract 11 from 11For any term tt except 00, t^{0}=1t

0

=1.

Answer:

u didnt give out the choses but it might be a chance to be dilation

Step-by-step explanation:

"the action or condition of becoming or being made wider, larger, or more open."

since she enlarge it without altering the center of it

Answer:

  ST = 6

Step-by-step explanation:

The segment sum is ...

  QR +RS +ST = QT

  QR +2 +ST = 10 . . . . use given values

Since R is the midpoint of QS, we know QR = RS = 2. Now, we have ...

  ST = 10 -2 -QR = 10 -2 -2 = 6

The length of ST is 6.

Answer: ...

Ok done. Thank to me :3

Answer:

1) 1, 1, [tex]\sqrt{2}[/tex]

2) 45°, 45°, 90°

Step-by-step explanation:

side lengths need to be proportional like 1, 1, [tex]\sqrt{2}[/tex], which is proportional for isoscele triangle.

isosceles is the one that has 90° angle and 2 equal angles so two 45° angles.

Answer:

A

Step-by-step explanation:

tan theta will equal zero if theta = n × pi where n is an integer

Answer:

80

Step-by-step explanation:

-50+x=30

x=80

Answer:

im pretty sure its 80

Step-by-step explanation:

Answer:

[tex]y = 3x +1[/tex]

Step-by-step explanation:

We can verify it by substituting the [tex]x[/tex] with the numbers in the [tex]x[/tex] column to get the same [tex]y[/tex] in the [tex]y[/tex] column.

Check:

[tex]y = 3(-2) +1\\y = -6 +1\\y= 5[/tex]

It matches; therefore, the answer is [tex]y = 3x +1[/tex]. You can try with the other equations given and take the same steps, but it will not match.

Answer:

  D) the point where the graph crosses the y-axis

Step-by-step explanation:

The "initial" value of a function is generally taken to mean the function value when the independent variable is zero.

On a graph of the profit function, that will be the y-intercept: the point where the graph crosses the y-axis.

__

The highest point on the graph will be the maximum profit.

The points where the graph crosses the x-axis will be where profit is zero, referred to as "break-even" points.

The lowest point on the graph will be where the profit is a minimum. That point may actually indicate a loss (negative profit).

[tex]\cot^4 A - \cot^2 A = 1\\\\\cot^4 A = 1 + \cot^2 A\\\\\frac{\cos^4 A}{\sin^4 A} = 1 + \frac{\cos^2 A}{\sin^2 A}\\\\\frac{\cos^4 A}{\sin^4 A} = \frac{\sin^2 A}{\sin^2 A}+\frac{\cos^2 A}{\sin^2 A}\\\\\frac{\cos^4 A}{\sin^4 A} = \frac{\sin^2 A+\cos^2 A}{\sin^2 A}\\\\\frac{\cos^4 A}{\sin^4 A} = \frac{1}{\sin^2 A}\\\\\cos^4 A = \frac{\sin^4 A}{\sin^2 A}\\\\\cos^4 A = \sin^2 A\\\\[/tex]

This then means,

[tex]\cos^4 A + \cos^2 A = 1\\\\\sin^2 A + \cos^2 A = 1\\\\[/tex]

which is the pythagorean trig identity. This concludes the proof.

Therefore, if [tex]\cot^4 A - \cot^2 A = 1[/tex], then [tex]\cos^4 A + \cos^2 A = 1[/tex]

Answer: 16.666666 feet

Explanation: 25/9=x/6 (25*2)/3 =50/3 I hoped this helped you solve your problem. Have a good day love!

The tangent or tanθ in a right angle triangle is the ratio of its perpendicular to its base. The Height of the fence is 8 feet.

The tangent or tanθ in a right angle triangle is the ratio of its perpendicular to its base. it is given as,

tan(θ) = Perpendicular/Base

where,

θ is the angle,

Perpendicular is the side of the triangle opposite to the angle θ,

Base is the adjacent smaller side of the angle θ.

Given that a 25-foot tree casts a 6 1/4-foot shadow. Also, At the same time, a fence casts a 2-foot shadow.

Length of the shadow = 6 1/4 feet = 6 + 1/4 = 6.25 feet

Now, since the sun is at the same angle, therefore, the angle between the top of the object and the top of the its shadow will be the same for all the objects. Therefore,

tan(θ) = Height of the tree/Shadow of the tree = Height of the fence/Shadow of the fence

tan(θ) = 25 feet / 6.25 feet =  Height of the fence / 2 feet

Height of the fence = (2feet × 25 feet) / 6.25 feet

Height of the fence = 8 feet

Hence, the Height of the fence is 8 feet.

Learn more about Tangent (Tanθ) here:

https://brainly.com/question/10623976

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Answer:

1094.4

Step-by-step explanation:

assuming you want volume

[tex]\begin{bmatrix}\frac{1}{6} & \frac{1}{2} & \frac{1}{3} \\ \\ \frac{3}{6}& \frac{2}{6} & \frac{1}{6} \\ \\ \frac{1}{3} & \frac{4}{24} & \frac{1}{2} \\ \end{bmatrix} [/tex]

Explanation:

The magic square is a n×n square which contains different number and sum of all the number of any row or column gives same value.

in any magic square the sum values of all row or column is three time of the number in centre of the square.

in above magic square the middle number is 2/6

so we can calculate the final value by multiplying with 3,

[tex] \frac{2}{6} \times 3 = \frac{2}{ \cancel6}_2 \times \cancel3 = \cancel{\frac{2}{2}} = 1[/tex]

The magic number or sum of any row or column is 1,

using this we can find the missing,

in column first,

1/6 and 1/3 are given and middle term is missing

let the middle term be x now,

[tex]x + \frac{1}{6} + \frac{1}{3} = 1 \\ x = 1 - \frac{1}{6} - \frac{1}{3} \\ x = 1 - ( \frac{3 + 6}{18}) \\ x = 1 - \frac{9}{18} \\ x = \frac{18 - 9}{18} \\ x = \cancel \frac{9}{18} = \frac{1}{2} [/tex]

similarly we can solve for the 3rd fraction of second column,

let the third number be y,

[tex] \frac{3}{ 6} + \frac{2}{6} + y = 1 \\ y = 1 - \frac{3}{ 6} - \frac{2}{6} \\ y = 1 - \frac{5}{6} = \frac{1}{6} [/tex]

Now in first and third row, the third number is missing which can be calculated in same way.

The rough work and final calculation is attached!

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