Find BC.
Round to the nearest tenth.

Answer:

6

out of the total donuts (90), Ryan ate 12 cream filled donuts. 45 is half of that, therefore he should eat half the cream filled donuts

Answer:

  [tex]\left[\begin{array}{ccc}-3&3&3\\3&6&3\end{array}\right][/tex]

Step-by-step explanation:

Reflection over the line y=x is described by the transformation ...

  (x, y) ⇒ (y, x)

The corresponding transformation matrix is ...

  [tex]\left[\begin{array}{cc}0&1\\1&0\end{array}\right][/tex]

When this left-multiplies the given coordinate matrix, the result is the one shown above.

Answer:

1,4,7 1,74. 4,7,1 ,4,1,7 ,7,4,1

[tex]tan (M) = \frac{side-opposite-angle-M}{side-adjacent-angle-M} =\frac{8\sqrt{2} }{4} =2\sqrt{2}[/tex]

Hope that helps!

ps. I attached a sheet of trigonometry identities

Answer:

[tex] \hookrightarrow \sf \bold{ - \frac{1}{2} }[/tex]

Step-by-step explanation:

⇢ [tex] \bold{5x+5=3x+4} [/tex]

⇢ - 3x + 5x = 4 - 5

⇢ 2x = -1

⇢ 2x/2.= -1/2

⇢ x = -1/2

5x+5=3x+4

5x-3x=4-5

2x=-1

2x/2=-1/2

x=-1/2

Answer:

Answer is 48

Step-by-step explanation:

6x8 = 48

Hope it helps!

Answer:

area=b•h

6 units • 8 units = 48 units²

Answer:

x = -1/7

Step-by-step explanation:

3/5x + 5 = 4/5

3/5x + 5/1 = 4/5

3 + 25x/5x = 4/5

4(5x) = 5(3 + 25x)

20x = 15 + 125x

-15 = 125x - 20x

-15 = 105x

-15/105 = x

-1/7 = x

Part of the value of sin(u) is cut off; I suspect it should be either sin(u) = -5/13 or sin(u) = -12/13, since (5, 12, 13) is a Pythagorean triple. I'll assume -5/13.

Expand the tan expression using the angle sum identities for sin and cos :

tan(u + v) = sin(u + v) / cos(u + v)

tan(u + v) = [sin(u) cos(v) + cos(u) sin(v)] / [cos(u) cos(v) - sin(u) sin(v)]

Since both u and v are in Quadrant III, we know that each of sin(u), cos(u), sin(v), and cos(v) are negative.

Recall that for all x,

cos²(x) + sin²(x) = 1

and it follows that

cos(u) = - √(1 - sin²(u)) = -12/13

sin(v) = - √(1 - cos²(v)) = -3/5

Then putting everything together, we have

tan(u + v)

= [(-5/13) • (-4/5) + (-12/13) • (-3/5)] / [(-12/13) • (-4/5) - (-5/13) • (-3/5)]

= 56/33

(or, if sin(u) = -12/13, then tan(u + v) = -63/16)

The area of the property is the product of its dimensions, and the expression for the area is (x + 10)²

The area of the land is the product of its dimensions.

Let the length and the width of the land be x.

So, the area measured by the appraisal is:

Area = x²

One side of the land is 10 more than the measured length.

So, we have:

Area = (x + 10)²

Substitute 12 for x

Area = (12 + 10)²

Evaluate

Area = 484

Hence, the area of the property is 484

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Answer:

True! We can tell that it is still there through weight becuase weight is a method of evidence/measurement. Hope this helps!

Answer:

Step-by-step explanation:

There's a saying to this kind of equation: Rate + Time = Distance and B best fits the saying, so B must be right (Don't quote me on that, it may be wrong)

the linear equation that can be used to find the distance that Eric travels each day is A. d = rt & the total distance that Eric travels each day is C. 112.5 miles.

Speed is measured as distance moved over time.

here, given that,

He drives at a rate of 75 mph on the interstate for a total of 1.5 hours.

so, the linear equation that can be used to find the distance that Eric travels each day is A. d = rt

i.e. d= 75*1.5

      =112.5

& the total distance that Eric travels each day is C. 112.5 miles.

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Answer:

A

Step-by-step explanation:

If 50 is the diameter that thr radius is 25 and the equation to find the area of a circle is pi(r^2). So you would do pi(25^2) and that is 1963

Answer:

Examples of 2D shapes

2D Shape Properties

Pentagon A shape with five sides and five equal angles.

Kite A quadrilateral with two pairs of sides of the same length.

Rhombus A quadrilateral with both pairs of opposite sides parallel and all sides of the same length. Unlike a square, however, its angles are not all 90˚.

Step-by-step explanation:

Answer:

And great great the owner is 44

Step-by-step explanation:

or 36 because you have to add all sides

Answer:

Area of a triangle is 1/2 x base x height.

area of triangle = 1/2 x 20 x 17 = 170 square feet.

the image shows 4 triangles, total area = 170 x 4 = 680 square feet.

the answer is A. 680 sq. ft.

Hope this helps you!!

Please Mark me as Brainleast!!!!!!!!!!!!!

Answer: the answer is a which is 680 ft²

Step-by-step explanation: we will make 17 Times 220 divided by 2 equals 170 times by 4 equals 680 . Hope it helps you buddy .

The function g(x) = x³ - x² - 4x + 4 has zeros at 1, 2 and -2. The y intercept is at 4.

An equation is an expression that shows the relationship between two or more numbers and variables.

The zeros of the function is at:

g(x) = 0, hence:

x³ - x² - 4x + 4 = 0

(x - 1)(x² - 4) = 0

(x - 1)(x + 2)(x - 2) = 0

x = 1, x = -2 and x = 2

The y intercept is at x = 0, hence:

g(0) = 0³ - 0² - 4(0) + 4 = 4

The function g(x) = x³ - x² - 4x + 4 has zeros at 1, 2 and -2. The y intercept is at 4.

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The calculation that represents the cost of 2 dozen iris bulbs is ($5 * 6) + ($4 * 6) + ($3 * 12)

An equation is an expression that shows the relationship between two or more variables and numbers.

The cost of 2 dozens of iris bulbs is given by the equation:

Cost = ($5 * 6) + ($4 * 6) + ($3 * 12)

The calculation that represents the cost of 2 dozen iris bulbs is ($5 * 6) + ($4 * 6) + ($3 * 12)

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Answer:

Price before Taxes: $ 25.00

Sales Tax (8.5%): $ 2.13

Total Price with Tax: $ 27.1

Step-by-step explanation:

The probability that a flight departed on time given that it arrives is 0.92

The conditional probability of event B occurring giving that event A has occurred is expressed as

P(B|A) = P(A and B)/P(A)

Given the following parameters

P(A and B) = The probability that a flight departs and arrives on time = 0.84

P(A) = The probability that an airplane flight departs on time = 0.91

P(B | A) = 0.84/0.91
P(B | A) = 0.92

Hence the probability that a flight departed on time given that it arrives is 0.92

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5.25 g

Step-by-step explanation:

The half-life of a radioactive substance is the amount of time it takes for half the mass of the substance to decay.

In this question no calculations are required to get half-life. This is because it is given that it took 3 years for the 14g to halve to 7g.

To find amount of the substance after a further 4 years, we’ll use the formula;

Final amount = initial amount / 2ⁿ

Where n = elapse time / half-life

We begin by finding n;

n = 4 years / 3 years

= 4/3

Final amount;

=  initial amount / 2ⁿ

= 7  / 2 ^ (4/3)

= 5.25 g

Learn More:

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Answer:

6/7

Step-by-step explanation:

you juts switch the top and bottom

Brainleist please

Answer:

c:) 150 in²

Step-by-step explanation:

It's basically and SAS triangle

SAS is Side, Angle, Side

side 15 in angle 90° and 20 in

a = 20 in

b = 25 in

c = 15 in

Angles:

A = 53.1301 °

B = 90 °

C = 36.8699 °

Other:

P = 60 in

s = 30 in

K = 150 in2

r = 5 in

R = 12.5 in

Agenda:

A = angle A

B = angle B

C = angle C

a = side a

b = side b

c = side c

P = perimeter

s = semi-perimeter

K = area

r = radius of inscribed circle

R = radius of circumscribed circle

Answer:f θ =2sin θ + square root of 3.

Step-by-step explanation: I think this is right

[tex] \frac{ab}{de} = \frac{bc}{ef} = \frac{ac}{df} [/tex]=k

[tex] \frac{6}{18} = \frac{12}{ef} [/tex]

[tex]ef = 36[/tex]

[tex] \frac{12}{36} = \frac{ac}{15} [/tex]

[tex]ac = 5[/tex]

[tex] \frac{6}{18} = \frac{12}{36} = \frac{5}{15} = \frac{1}{3} [/tex]

I hope it helps

Check the picture below.

[tex]\stackrel{\textit{\Large Areas}}{\stackrel{rectangle}{(160)(20)}~~ + ~~\stackrel{triangle}{\cfrac{1}{2}(90)(120)}}\implies 3200~~ + ~~5400\implies 8600[/tex]

Step-by-step explanation:

if width = 3 length = 5 hight = 10

Volume of rectangular prism = 3×5×10

= 150

Answer:

5 faces

Step-by-step explanation:

A traingular prism has 5 faces. The square on the bottom and the four traingles that make up the sides.

hope this helps :)

Answer:

5

8

5

step by step

Love your pfp

The rule for the height of the tree during the nth month will be an = 83 + 1.5(n – 1). The correct option is A.

The mathematical expression combines numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.

Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.

Given that in the third month of the study, a sugar maple tree is 86 inches tall. In the seventh month, the tree is 92 inches tall.

For option A satisfy the equation for n = 3 and n = 7,

an = 83 + 1.5(n – 1)

a₃ = 83 + 1.5(3 – 1)

a₃ = 83 + 3

a₃ =86

a₇ = 83 + 1.5(7– 1)

a₃ = 83 + ( 1.5 x 6 )

a₃ = 83 + 9

a₃ = 92

Therefore, the rule for the height of the tree during the nth month will be an = 83 + 1.5(n – 1). The correct option is A.

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Answer:

Question 3

Find the range of the function for the domain 2 < x < 3

[tex]f(2)=(2)^2-1=3[/tex]

[tex]f(3)=(3)^2-1=8[/tex]

Therefore, the range of [tex]f(x)=x^2-1[/tex] is [tex]3 < f(x) < 8[/tex] with domain 2 < x < 3

This means that for the function to be continuous, when the domain is x=3, f(x) = 8

[tex]f(3)=2a(3)=6a[/tex]

[tex]\implies 6a=8\implies a=\dfrac43[/tex]

Similarly, when the domain is x > 3, f(x) > 8

[tex]f(3)=b(3)-4=3b-4[/tex]

[tex]\implies 3b-4 > 8 \implies b = 4[/tex]

Therefore, [tex]a=\dfrac43[/tex] and b = 4

Question 5

[tex]\textsf{let}\:u=\ln (x)[/tex]

[tex]\implies \dfrac{du}{dx}=\dfrac{1}{x}\implies dx=x\:du[/tex]

[tex]x=1\implies u=0[/tex]

[tex]x=3 \implies u=\ln 3[/tex]

[tex]\implies \displaystyle \int\limits_{1}^{3} \dfrac{\ln x \sin (\ln x)}{x} \,\:dx=\displaystyle \int\limits_{0}^{\ln 3} \dfrac{u \sin u}{x} \, \cdot x\:du=\displaystyle \int\limits_{0}^{\ln 3} (u \sin u) \, \:du[/tex]

Use integration by parts:

[tex]\displaystyle \int u\dfrac{dv}{dx} \, dx=uv- \displaystyle \int v \dfrac{du}{dx} \, dx[/tex]

[tex]\textsf{where}\:u=u\:\textsf{and}\:\dfrac{dv}{dx}=\sin u[/tex]

[tex]\implies \dfrac{du}{dx}=1\:\textsf{and}\:v=\int \sin u=-\cos u[/tex]

[tex]\implies \displaystyle \int\limits_{0}^{\ln 3} (u \sin u) \, \:du=-u \cos u- \int\limits_{0}^{\ln 3}-\cos u \,\:du[/tex]

[tex]\begin{aligned}\implies \displaystyle \int\limits_{0}^{\ln 3} (u \sin u) \, \:du & =\left[-u \cos u+ \sin u\right]_{0}^{\ln 3}\\ & =[- (\ln 3) \cos (\ln 3)+ \sin (\ln 3)]-[-0 \cos (0)+ \sin (0)]\\\\ & =[- (\ln 3) \cos (\ln 3)+ \sin (\ln 3)]-0\\\\ & = 0.3908925527...\end{aligned}[/tex]