EARTH AND SPACE SCIENCE! PLEASE HELP! Question: You do several trials of measuring the time it takes to swing a bobber around your head for 10 times. You first use a string that is 15 cm in length. You repeat these trials with a 20 cm string. All of the following are True EXCEPT:
a.) The average revolutions per second increases as you increase the length of the string
b.)The relationship between revolutions per second AND average time should be an inverse relationship: (as one increases the other decreases)

Answers

Answer 1

B) The relationship between revolutions per second AND average time should be an inverse relationship: (as one increases the other decreases) is incorrect.

This is incorrect because, as the length of the string increases, the average time for 10 revolutions should increase as well. This is because the bobber has to travel farther as the string gets longer, and so it takes longer to finish 10 revolutions. Therefore, the relationship between revolutions per second and average time is not inverse; instead, it is a direct relationship. As the length of the string increases, the average revolutions per second should increase, and the average time should decrease. This means that the relationship between the two is actually a direct relationship  as one increases, the other increases as well.

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Related Questions

You are standing on the surface of a spherical asteroid 10 km
in diameter, of density 3000 kg/m3
.
Part A
Calculate the escape velocity from the asteroid in km/s
.

Answers

The required escape velocity from the asteroid in km/s and mph is 2.0 km/s and 4478 mph, respectively.

How frequently do asteroid 10 km hit the Earth?

According to analyses of orbital statistics, asteroids of 10 km in size can strike the planet every 100 My or so, which is consistent with the theory that we were struck by an object of this size 65 My ago.

Part A: Escape velocity is the bare minimum speed at which an object can break out of an astronomical body's gravitational influence. The following provides the escape velocity formula:

v = √((2GM)/r)

Where, G = gravitational constant M = mass of the astronomical body r = radius of the astronomical body

Now, let's substitute the given values to find the escape velocity from the asteroid.

Given, Diameter of the asteroid, d = 10 km

So, radius of the asteroid, r = d/2 = 5 km = 5 × 10³ m

Density of the asteroid, ρ = 3000 kg/m³

Mass of the asteroid, M = ρ × volume of the asteroid= ρ × (4/3)πr³= 3000 × (4/3) × π × (5 × 10³)³= 6.54 × 10¹¹ kg

Gravitational constant, G = 6.67 × 10⁻¹¹ Nm²/kg²

Putting all these values in the escape velocity formula, v = √((2GM)/r)= √((2 × 6.67 × 10⁻¹¹ × 6.54 × 10¹¹)/5 × 10³)= 2.0 km/s

Therefore, the escape velocity from the asteroid is 2.0 km/s.

Part B : Now, let's convert the escape velocity from km/s to mph.1 km = 0.621371192 milesSo, v in mph = 2.0 km/s × (0.621371192 miles/km) × (3600 s/hour)= 4478 mph

Therefore, the escape velocity from the asteroid is 4478 mph (rounded to three significant figures).

Hence, the required escape velocity from the asteroid in km/s and mph is 2.0 km/s and 4478 mph, respectively.

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Question:

You are standing on the surface of a spherical asteroid 10 km in diameter, of density 3000 kg/m3.

Part A

Calculate the escape velocity from the asteroid in km/s.

Express your answer in kilometers per second using two significant figures.

Calculate the escape velocity from the asteroid in mph.

Express your answer in miles per hour using three significant figures

10/a = 15/24 a=?

please help

Answers

Answer is 16

Haha we have the same name

Dump Tower is 90 stories tall. A small, 1.5-kg object is dropped over the side of the roof of the tower and accelerates toward the ground. You will track the object for its entire fall. Each story of this tower is 3.85 meters tall.

What is the acceleration due to gravity of the planet and what is the impact speed of the object you dropped?
Time of fall 8.50sec.


30pts.
Thanks!

Answers

The distance the object falls is equal to the height of the building, which is 90 x 3.85 = 346.5 meters.

The acceleration due to gravity can be found using the equation:

d = 1/2 * g * t^2

where d is the distance the object falls, t is the time of fall, and g is the acceleration due to gravity.

Substituting the known values:

346.5 meters = 1/2 * g * (8.50 seconds)^2

Solving for g:

g = 2 * 346.5 meters / (8.50 seconds)^2

g = 9.74 m/s^2

So the acceleration due to gravity on the planet is 9.74 m/s^2.

The impact speed of the object can be found using the equation:

v = g * t

where v is the impact speed and t is the time of fall.

Substituting the known values:

v = 9.74 m/s^2 * 8.50 seconds

v = 82.8 m/s

So, the impact speed of the object is 82.8 m/s.

(a)
Calculate the force (in N) needed to bring a 900 kg car to rest from a speed of 85.0 km/h in a distance of 110 m (a fairly typical distance for a non-panic stop).


(b)
Suppose instead the car hits a concrete abutment at full speed and is brought to a stop in 2.00 m. Calculate the force exerted on the car and compare it with the force found in part (a).

Answers

(a) To calculate the force needed to bring the car to rest, we can use the equation:

f = (m * v^2) / (2 * d)

where:
m = 900 kg (mass of the car)
v = 85.0 km/h = 23.6 m/s (initial velocity of the car)
d = 110 m (stopping distance)

Plugging in the values, we get:

f = (900 kg * (23.6 m/s)^2) / (2 * 110 m)
f = 23095.91 N or 2.31 x 10^4 N

Therefore, the force needed to bring the car to rest from a speed of 85.0 km/h in a distance of 110 m is approximately 23,095.91 N or 23.1 kN.

(b) If the car hits a concrete abutment at full speed and is brought to a stop in 2.00 m, we can calculate the force exerted on the car using the formula:

f = m * a

where:
m = 900 kg (mass of the car)
a = -v^2 / (2 * d) = -(23.6 m/s)^2 / (2 * 2.00 m) = -2793.2 m/s^2 (acceleration of the car)

The negative sign indicates that the acceleration is in the opposite direction to the initial velocity of the car.

Plugging in the values, we get:

f = 900 kg * (-2793.2 m/s^2)
f = -2.51 x 10^6 N or -2.51 MN

Therefore, the force exerted on the car when it hits a concrete abutment at full speed and is brought to a stop in 2.00 m is approximately 2.51 MN (or 2510 kN), which is much greater than the force found in part (a). This is because the stopping distance is much shorter, so the deceleration (and therefore the force) must be much greater to bring the car to a stop in the same amount of time.

In the following equations, the distance x is in meters, the time t is in seconds, and the velocity v is in meters per second. What are the SI units of the constants 1 and 2 ? (a) =1+2, (b) =1212, (c) 2=21, (d) =1cos (2), (e) 2=21−(2)2

Answers

Since [1 + 2] = [1] + [2], the Velocity of the constant 1 and 2 must be the same. Therefore, both constants have the same SI units.

What is the relationship between speed and the SI unit?

V is the velocity, d is the distance, and t is the duration in the equation V = d/t. Calculate the object's acceleration by dividing its mass by its force, then multiplying the result by the acceleration's duration.

(b) The units of the constants 1 and 2 must be the same because [12 / 12] = 1. As a result, the SI units for both variables are the same.

(c) The units of the constant 2 must be the same as the units of the constant 1 squared because [2] = [2] / [1]. As a result, the SI units for the constants 1 and 2 differ.

(d) The constant 2 must have radians as its units because the cosine function's input must be dimensionless. It is necessary for the constant 1 to have units that enable the cosine function's units to cancel out. This can be done by assigning the constant 1 units that are reciprocal radians, or radians to the power of -1. As a result, the SI units for the constants 1 and 2 are rad-1 and radians, respectively.

Due to the fact that [(2 / 1) - (2)2] equals [(2 / 1)], The units of the constant 2 must match those of the constant 1 cubed, or [22]. As a result, the SI units for the constants 1 and 2 differ.

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One end of a spring with a spring constant of 109 N/m is held firmly in place, and the other end is attached to a block with a mass of 2.13kg. The block undergoes SHO (simple harmonic motion) with no friction. At time t = 0.6763s, the position and velocity of the block are:

x(0.6763s) = -0.1031m

y(0.6763s) = 0.5303m/s


A. What was the position, in meters, at t = 0.00s?

B. What was the velocity, in meters per second, at t = 0.00s?

Answers

At time zero, the location is -0.1031m, and the speed is 0 m/s.

How can you determine a block's top speed?

How fast can the block go at its most. When the spring reaches its equilibrium length, all of the stored energy in the spring is transferred to kinetic energy, and the block accelerates to its maximum speed. Since the item is at rest, Ki = 0. As there is no friction, Wnc = 0.

A = x(0.6763s) = -0.1031m

v(0.6763s) = -Aω sin(ω*0.6763s) = 0.5303 m/s

ω = sqrt(k/m) = sqrt(109 N/m / 2.13 kg) = 5.148 rad/s

Now we can use these values to find the position and velocity at t = 0:

A cos(ωt) = A cos(0) = A = -0.1031m

-v(0) = Aω sin(ωt) = -Aω sin(0) = 0

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If x=450 mm, determine the mass of the counterweight s required to balance a 90-kg load

Answers

The mass of the counterweight required to balance the 90-kg load is also 90 kg.

To balance the 90-kg load, the moment created by the counterweight s must equal the moment created by the load. The moment created by a force is equal to the force multiplied by the perpendicular distance from the force to the point of rotation. In this case, the point of rotation is the fulcrum and the perpendicular distance is the distance between the fulcrum and the force.

Let's assume that the distance between the fulcrum and the load is d, and the distance between the fulcrum and the counterweight is x. We can then write the equation:

mass of counterweight x distance to fulcrum = mass of load x distance to fulcrum

m_s x x = 90 kg x d

We are given that x = 450 mm (0.45 m). Solving for m_s, we get:

m_s = (90 kg x d) / x

We need to determine the value of d in order to calculate the mass of the counterweight. Since the system is in balance, we know that the sum of the moments created by the load and the counterweight must be zero. That is:

mass of load x distance to fulcrum = mass of counterweight x distance to fulcrum

90 kg x d = m_s x (x + d)

Substituting the expression we derived earlier for m_s, we get:

90 kg x d = [(90 kg x d) / x] x (x + d)

Simplifying this expression by cancelling out the factor of d on both sides, we get:

90 kg = (90 kg / x) x (x + d)

Multiplying both sides by x, we get:

90 kg x = 90 kg x (x + d)

Cancelling out the factor of 90 kg, we get:

x = x + d

Solving for d, we get:

d = x = 450 mm = 0.45 m

Now we can use the equation we derived earlier for m_s to calculate the mass of the counterweight:

m_s = (90 kg x 0.45 m) / 0.45 m = 90 kg.

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What is the launch speed of a projectile that rises vertically above the Earth to an altitude equal to 11 REarth before coming to rest momentarily?

Answers

the launch speed of the projectile is approximately 12.3 km/s that rises vertically above the Earth to an altitude equal to 11 REarth before coming to rest momentarily

We can use the conservation of energy principle to solve this problem. At the highest point, the projectile has zero kinetic energy and a certain potential energy, given by:

PE = mgh

where m is the mass of the projectile, g is the acceleration due to gravity, and h is the altitude above the Earth's surface. The potential energy can also be expressed in terms of the gravitational potential energy per unit mass, which is given by:

U = GM/r

where M is the mass of the Earth, r is the distance from the center of the Earth to the projectile, and G is the gravitational constant. At the highest point, the projectile has a distance of 12 REarth from the center of the Earth (11 REarth above the surface plus the radius of the Earth).

Setting these two expressions for potential energy equal to each other, we have:

mgh = GMm/r

where we can cancel the mass m from both sides to obtain:

gh = GM/r

Solving for the speed v at the launch point, we have:

v = sqrt(2gh)

where we can substitute:

h = 11 REarth

r = 12 REarth

g = GM/(12 REarth)2

Substituting these values and using the fact that REarth = 6.37×106 m, we get:

v = sqrt(2×(11+1)REarth×GM/(12REarth)) = 12.3 km/s

where we used the fact that the total distance traveled by the projectile is 2 REarth, so the factor of (11+1) appears in the expression for h.

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Sabrina takes a self-report, objective personality rest that asks her to agree or disagree with over 300 statements such as, "I forgive people easily" and "I often got into trouble when I younger". Sabrina is probably taking the

Answers

Sabrina is probably taking the Big Five Personality Test.

What are the three impartial personality assessments?

The Beck Depression Inventory, Millon Clinical Multiaxial Inventory-III, Minnesota Multiphasic Personality Assessment, and Child Behavior Checklist are some of the frequently used objective personality tests.

What are a few illustrations of impartial personality tests?

Examples of objective personality assessments include the Big Five Personality Inventory, the Millon Clinical Multiaxial Inventory (MCMI), and the Minnesota Multiphasic Personality Inventory (MMPI).

What is a psychological assessment that is objective and measures mental disorders?

The Minnesota Multi-Phasic Personality Inventory (MMPI), which rates people on personality, psychological, and emotional factors, is arguably the most popular of the objective personality tests.

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Being over stressed can make you feel

1. Excited

2. Happy

3. Irritable

4. Relaxed

Answers

Answer: The answer would be 4.

Explanation:

Being stressed is not a good feeling. Since None of the other answers suit the description of "overstressed", it would be 4.

irritable

Explanation:

irrtable meaning Easily annoyed or easily made mad

a sound wave takes 6 seconds to complete one cycle. what is the frequency of this wave

Answers

Therefore, the frequency of the sound wave is 0.1667 Hz.

How lengthy is a wave at 20 Hz?

Since we can fit 20 cycles into a distance of 340 meters, the wavelength for 20 Hz is equal to 340 metres divided by 20, or 17 metres. The wavelength is described as the length of this pattern for one cycle.

The quantity of cycles per second is used to describe a wave's frequency. The sound wave in this instance goes through one rotation in 6 seconds.

So the frequency of the wave can be calculated as:

Frequency = 1 / Time period

where Time period is the time taken to complete one cycle.

Therefore, the frequency of the sound wave can be calculated as:

Frequency = 1 / 6 seconds = 0.1667 Hz

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Need help with this

Answers

(9) None of the options listed in the question are correct as a risk assessment approach to environmental hazards.

(10) House debt is not a direct effect of housing on health (option D)

What is risk assessment?

A risk assessment approach to environmental hazards aims to take into account all of the following factors, including the health outcome, inherent danger, quantity of exposure, and route of exposure. Therefore, none of the options listed in the question are correct as all of them should be considered in a risk assessment approach to environmental hazards.

10. While housing affordability and financial stress related to housing can indirectly affect health, they are not a direct effect of housing itself on health.

The other options are direct effects of housing on health:

A. Proximity to services and facilities, such as healthcare, education, and transportation, can affect health outcomes.

B. Materials effects of housing, such as ventilation, insulation, and building materials, can directly affect indoor air quality and physical health.

C. Insecure housing, such as homelessness or living in overcrowded or unsafe conditions, can lead to physical and mental health problems.

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your hand feels cold when you hold an ice cube because A. the ice radiates cold to your hand B. the ice conducts cold to your hand C. your hand cools down by convection. D.Your hand transfers thermal energy to the ice​

Answers

your hand feels cold when you hold an ice cube because D.Your hand transfers thermal energy to the ice

Is there a flow of cold from the ice to your hand?

The ice does not transfer cold to your hand. Heat is transferred from your hand to the ice. When you are transmitting heat to the metal, it feels chilly to the touch.

Heat energy constantly flows from high temperature to low temperature. The temperature of the fingers is higher than that of ice. As a result, energy will be transferred from the finger to the ice.

This is due to the larger quantity of heat from our body moving to the ice through our skin (through thermal conduction) in order to achieve thermal equilibrium between the ice and the body.

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An ocean wave travels at approximately 1.97 m/s. This is 4 miles per hour. The frequency of the waves is roughly 0.07 hz (or roughly 4 waves per minute). What is the Wavelength?

Answers

Therefore, the wavelength of the ocean wave is approximately 28.14 meters.

What is the equation for a wave's frequency?

The equation f=v f = v, where  is the wavelength in metres and v is the wave speed in m/s, can be used to determine the frequency of a wave if the radius and speed of the wave are known. This also provides the wave's frequency in Hertz.

The wave speed calculation can be used to calculate the ocean wave's wavelength:

v = λf

where the wavelength is, the frequency is f, and v is the wave speed.

The wave frequency is given as 0.07 Hz and the wave speed is provided as 1.97 m/s. We can use the following conversion ratio to change 4 miles per hour to metres per second:

1 mile/hour = 0.44704 m/s

So, 4 miles/hour = 1.78816 m/s

Now we can substitute the values into the wave speed equation and solve for λ:

λ = v/f = 1.97 m/s / 0.07 Hz = 28.14 m

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I need help answering the following question. Thank you!

Answers

a. The graph does not appear to be symmetrical.

b. The graph appears to be bimodal, as there are two distinct peaks.

c. The data appear to be positively skewed, as the tail of the graph extends further to the right than to the left.

d. There appear to be outliers for values less than 3.5 and greater than 6.75, as these values are relatively far away from the rest of the data and do not fit the overall pattern of the graph.

What is a graph?

A graph is described as a structure amounting to a set of objects in which some pairs of the objects are in some sense "related.

Graphs are a popular tool for graphically illuminating data relationships.

In conclusion,  A graph serves the purpose of presenting data that are either too numerous or complex to be properly described in the text while taking up less room.

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In the most common form of colorblindness, a cone system malfunctions, rendering the color
indistinguishable from other color combinations.

Answers

The most common form of color blindness is called red-green color blindness.

This type of color blindness is caused by a malfunction of the red and green cone systems in the eye, which are responsible for detecting different wavelengths of light. This malfunction causes individuals to have difficulty distinguishing between certain combinations of red and blue, as they appear to be the same color or shade to the affected person. The exact cause of this malfunction is still unknown, but is believed to be caused by genetic factors, environmental influences, or a combination of both.This color blindness affects up to 8% of men and 0.5% of women, and is caused by a mutation in the gene that codes for the red-sensitive cone cells in the eye.

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complete question:in the most common form of color blindness, the ___ cone system malfunctions rendering ____ indistinguishable from certain combinations of blue and red

A ball thrown with an initial velocity of u(10i+15j)m/s when it reaches the top of it trajectly neglucating air resistance what is avelocity & acceleration ?

Answers

At the apex of the trajectory, the ball's velocity and acceleration are u (10i+15j) m/s and zero

The initial velocity of the ball is u (10i+15j) m/s.

Velocity at the top of the trajectory: Since the ball is thrown with an initial velocity, it will reach the top of its trajectory with the same velocity, since there is no air resistance. Therefore, the velocity of the ball at the top of the trajectory is u (10i+15j) m/s.

Acceleration: The acceleration of the ball at the top of the trajectory is zero, since the ball is not accelerating (there is no acceleration due to air resistance).

Therefore, the velocity and acceleration of the ball at the top of the trajectory are u (10i+15j) m/s and zero, respectively.

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As a beam of light enters a swimming pool, it will because light waves when they pass from one medium to a different medium.

Answers

Light waves will be refracted, or bent, as they move from air to the denser medium of water.

The refraction can cause the light to spread out and become distorted, resulting in a blurry and distorted image.

When a beam of light enters a swimming pool, it will cause light waves to bend and refract when they pass from the less dense medium of air to the denser medium of water.

This is due to the different densities of the two mediums, which causes the light waves to bend as they move from one to the other. As a result, the light waves become distorted and spread out, causing a blurry and distorted image.

This phenomenon is known as refraction, and it happens when light passes through any medium that is denser than the one it is coming from. It's why we can see objects underwater, as the light waves get bent and refracted as they pass through the water. Refraction is an important part of many optical phenomena, such as lenses and prisms, which use it to bend and shape light.

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1.datemine the mechanical energy of mass 200g of bird fling at 12m/s at height of some use (g=12m/s²)
2. calculate the GPF of the following
A. A 20kg lifed 2m into air
B. sixty 6kg boxes lifted into shelf 2m high
3. calculate the kinetic energy of
A. 3g of bullest travelling at 40m/s
B. A car of mass 1200kg that travelling 60m in 3 seconds ​

Answers

The mechanical energy of the bird is 26.4 J.

Mechanical energy calculation.

To determine the mechanical energy of the bird, we need to calculate its kinetic energy and potential energy.

Kinetic energy = 1/2 * mass * velocity^2

Potential energy = mass * gravity * height

Given:

Mass = 0.2 kg

Velocity = 12 m/s

Height = unknown

Gravity = 12 m/s^2

Kinetic energy = 1/2 * 0.2 * 12^2 = 14.4 J

To find the potential energy, we need to know the height. Let's assume it is 5 meters.

Potential energy = 0.2 * 12 * 5 = 12 J

Mechanical energy = kinetic energy + potential energy

Mechanical energy = 14.4 + 12 = 26.4 J

Therefore, the mechanical energy of the bird is 26.4 J.

A.

Gravitational potential energy = mass * gravity * height

GPE = 20 * 9.81 * 2 = 392.4 J

The work done to lift the object is equal to its gravitational potential energy, so the GPF (Gravitational Potential Force) is 392.4 N.

B.

Total mass of boxes = 60 * 6 = 360 kg

Gravitational potential energy = mass * gravity * height

GPE = 360 * 9.81 * 2 = 7069.2 J

The work done to lift the boxes is equal to their gravitational potential energy, so the GPF is 7069.2 N.

Therefore, the GPF for the 20 kg lift is 392.4 N and the GPF for the 60 boxes is 7069.2 N.

A.

Kinetic energy = 1/2 * mass * velocity^2

KE = 1/2 * 0.003 * 40^2 = 2.4 J

Therefore, the kinetic energy of the 3 g bullet travelling at 40 m/s is 2.4 J.

B.

We can calculate the average velocity of the car using the formula:

Average velocity = distance / time

Average velocity = 60 / 3 = 20 m/s

Kinetic energy = 1/2 * mass * velocity^2

KE = 1/2 * 1200 * 20^2 = 240,000 J

Therefore, the kinetic energy of the car is 240,000 J.

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Why is it dangerous for an archer to walk around with an arrow nocked and bowstring pulled to tension

Answers

It is important for archers to follow proper safety protocols and always keep their bows and arrows pointed in a safe direction and not to nock an arrow until they are ready to shoot.

It is dangerous for an archer to walk around with an arrow nocked and bowstring pulled to tension because it creates a situation where the bow is essentially loaded and ready to fire. Any accidental bump or movement could cause the arrow to be released, potentially causing injury to the archer or anyone nearby. This can be especially dangerous if the bow is pointed towards people or valuable objects.

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How many waves are on this string? ​

Answers

A standing wave is composed of two waves with the same frequency and amplitude traveling in opposite directions and interfering with each other.  Thus we have to waves here.

Is a standing wave composed of two waves?

These waves are known as the incident wave and the reflected wave. When the incident wave and the reflected wave interfere constructively, they create points of maximum displacement known as antinodes.

When they interfere destructively, they create points of minimum displacement known as nodes. The pattern of antinodes and nodes remains fixed in space, giving rise to a standing wave.

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EARTH AND SPACE SCIENCE!
Scientist that concluded that the universe was "Earth Centered" after failing to observe any shifting of background stars "stellar parallax" at different times of the year.

a.) Nicolaus Copernicus
b.) Sir Isaac Newton
c.) Tycho Brahe
d.) Johannes Kepler

Answers

Tycho Brahe was the scientist who came to the conclusion that the cosmos was "Earth Centered" after failing to notice any seasonal variations in the background star "stellar parallax."

WHO came to the conclusion that the Earth was the universe's centre?

An Earth-centered perspective of the cosmos. Claudius Ptolemy believed that the Earth was at the centre of the universe. Before the controversial findings of Copernicus, Galileo, and Newton, this belief persisted for 1400 years.

Who made the Earth the centre of universe?

Around 380 B.C., a scientist by the name of Eudoxus developed the first geocentric universe model. The stars, the sun, and the moon are all incorporated into the sequence of cosmic spheres that make up Eudoxus' universe model.

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A 40kg child on a 50kg bike is riding with a velocity of 10 m/s to the northern.

Answers

Answer:

Explanation:

The vertex of an absolute function is the minimum or the maximum point of the graph

The graph that could be  is (a) an absolute value graph has a vertex at (2, 1)

The function is given as:

And the coordinates of the vertex (h,k) are said to be positive.

From the list of given options, only the first option has both coordinates of the vertex to be positive i.e. (2,1)

Hence, the graph that could be  is (a)

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Need help on this question!!!

True or False. Animals can be at the top of more than one food chain.

Answers

Answer:

false

Explanation:

Can animals be at the top of more than one food chain? There cannot be too many links in a single food chain because the animals at the end of the chain would not get enough food (and hence, energy) to stay alive.

A sample of an unknown material appears to weigh 300N in air and 200N when immersed in alcohol of density 700kg/m^3 . What is the volume and density of the material

Answers

Answer:

the volume of the material is 0.0145 m^3 and its density is 20690.3 kg/m^3.

Explanation:

To solve the problem, we can use Archimedes' principle, which states that the buoyant force acting on an object submerged in a fluid is equal to the weight of the fluid displaced by the object.

Let's first find the weight of the unknown material in air:

W_air = 300 N

Next, let's find the weight of the unknown material in alcohol:

W_alcohol = 200 N

We can find the buoyant force acting on the material by subtracting the weight in alcohol from the weight in air:

F_buoyant = W_air - W_alcohol = 300 N - 200 N = 100 N

According to Archimedes' principle, this buoyant force is equal to the weight of the alcohol displaced by the material:

F_buoyant = ρ_alcohol * V * g

where ρ_alcohol is the density of the alcohol, V is the volume of the material, and g is the acceleration due to gravity.

Substituting the values we know:

100 N = 700 kg/m^3 * V * 9.81 m/s^2

Solving for V:

V = 0.0145 m^3

Finally, we can find the density of the material by dividing its weight in air by its volume:

ρ_material = W_air / V = 300 N / 0.0145 m^3 = 20690.3 kg/m^3

Therefore, the volume of the material is 0.0145 m^3 and its density is 20690.3 kg/m^3.

Starting at t = 0, a horizontal net force F⃗ =(0.290N/s)ti^+(−0.445N/s2)t2j^
is applied to a box that has an initial momentum p⃗ =(−3.10kg⋅m/s)i^+(4.10kg⋅m/s))j^
.
a) What is the x-component of the momentum of the box at t = 2.00 s ?
b) What is the y-component of the momentum of the box at t= 2.00 s ?

Answers

a) The x-component of momentum is given by pₓ = m * vₓ, where m is the mass of the box and vₓ is the x-component of velocity. Since the force is only acting in the x-direction, there is no net force in the y-direction, and the y-component of momentum is conserved.

Therefore, we can use the initial y-component of momentum to find the y-component of momentum at any time.

At t = 2.00 s, the x-velocity can be found by integrating the x-component of the force:

Fₓ = (0.290 N/s)t

vₓ = ∫Fₓ dt = (0.145 N/s)t² + C

Using the initial condition that vₓ(0) = pₓ(0)/m = (-3.10 kg⋅m/s) / (m), we can solve for C:

C = -3.10 m/s

Therefore, vₓ = (0.145 N/s)t² - 3.10 m/s

And the x-component of momentum at t = 2.00 s is:

pₓ = m * vₓ = m * [(0.145 N/s) (2.00 s)² - 3.10 m/s]

pₓ = (550 kg) * [-1.54 m/s] ≈ -847 kg⋅m/s

b) As mentioned above, the y-component of momentum is conserved since there is no net force in the y-direction. Therefore, the y-component of momentum at t = 2.00 s is the same as the initial y-component of momentum, which is:

pᵧ = m * vᵧ = m * [(4.10 kg⋅m/s) / (m)] = 4.10 kg⋅m/s

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Match the model of the atom to its description.

Question 3 options:

Now considered inaccurate because it does not include the nucleus


Most accurate and newest model, but often too complicated for use in the classroom


Electrons are orbiting the nucleus in this model. This model is useful and used often, but not fully accurate

1.
"Plum pudding" or "raisin bread" model of the atom

2.
Bohr's planetary model of the atom

3.
The quantum or cloud model of the atom

Answers

"Plum pudding" or "raisin bread" model of the atom

Bohr's planetary model of the atom

The quantum or cloud model of the atom

What is Plum Pudding Model?

The "Plum pudding" or "raisin bread" model of the atom is a model where electrons are distributed throughout the atom and the positive charge is spread out to create a sort of "pudding" with "raisins" of negative charge. This model was proposed by J.J. Thomson in the early 1900s and is now considered inaccurate because it does not include the nucleus.

Bohr's planetary model of the atom is a model where electrons orbit the nucleus in specific energy levels or "shells". This model was proposed by Niels Bohr in 1913 and was an improvement over the "Plum pudding" model. It is useful and used often in introductory chemistry, but it has limitations in accurately describing more complex atoms.

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For a pith ball experiment set up on Earth, which image below correctly depicts the result if you gave the left-hand pith ball a charge of +7.0 × 10-^6C and the right-hand pith ball a charge of +11.0 × 10^-6 C? Assume the pith balls have equal mass.

Answers

The two pith balls with like charge will repel each other and move away from each other until the electric force between them is balanced by the tension force of the string holding them up. Hence, the correct option is (A).

The left-hand pith ball has a charge of +7.0 × 10⁻⁶C and the right-hand pith ball has a charge of +11.0 × 10⁻⁶ C, they will both repel each other due to their like charges. The magnitude of the force between them will depend on the distance between them and the amount of charge on each ball, according to Coulomb's law. The pith balls will move away from each other until the electric force between them is balanced by the tension force of the string holding them up. The resulting position of the pith balls will depend on the angle of the string relative to the vertical direction. The greater the difference in charge between the two balls, the greater the angle will be.

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If two people disagree on metaethics, they will definitely disagree on the best
outcome of a particular ethical issue such as abortion.

Answers

False. Because metaethics is concerned with the nature of ethics and moral reasoning.

What is metaethics?

Metaethics is concerned with the nature of ethics and moral reasoning, while normative ethics is concerned with specific ethical principles and the best course of action in particular ethical issues.

Disagreement on metaethics does not necessarily mean that two people will disagree on the best outcome of a particular ethical issue such as abortion. It is possible for two people with different metaethical views to agree on the best course of action in a particular ethical issue, as long as they share similar normative ethical principles or have similar views on the relevant facts of the situation.

However, differences in metaethics may lead to differences in how one arrives at their normative ethical principles, which may in turn affect their view on the best outcome of a particular ethical issue.

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An object A has a mass of 6kg and a heat capacity of 2 310j/°C. Another object B has a mass of 4.6kg and a heat capacity of 1771j/°C. Determine if the two objects A and B are made from the same substance.​

Answers

We can infer that item A is not composed of the same material as object B since its specific heat capacity is higher than object B's. As the specific heat capacities differ, we cannot assume that they are the same.

Determine if the two objects A and B are made from the same substance.​

The amount of heat needed to increase the warmth of one unit of mass of a substance by one degrees Celsius must be compared between two things in order to ascertain if they are made of the same material. The compounds are probably the same if the heat capacity capacities are the same. The following equation can be used to determine how much heat energy is needed to raise an object's temperature:

Q = mcΔT

Where Q is the heat received or released, m is the object's mass, c is the material's specific heat capacity, and T is the temperature change.

Let's figure out how much heat energy is needed to raise item A's temperature by one degree Celsius:

Q A = mcΔT

Q A equals 6 kg x 2,310 J/(kg°C) x 1°C.

Q A = 13,860 J/°C

Let's now determine how much heat energy is needed to raise item B's temperature by 1 degree Centigrade:

Q B = mcΔT

Q B is equal to 4.6 kg, 1,771 J/(kg°C), and 1°C.

Q B = 8,146.6 J/°C

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