e ABC be similar to RST. Find both missing sides t and s.
B
A
5
4
3
R
S
S
9
T

Answer:

Step-by-step explanation:

Setting A=45, we see that it is not true. However, you might find the following revealing:

sin2(45+A)=(sin45cosA+cos45sinA)2=12(1+2cosAsinA)

sin2(45−A)=(sin45cosA−cos45sinA)2=12(1−2cosAsinA)

Now, stare.

The person can get 3 fives, 2 sixes, and 1 two in 336 ways.

To find the number of ways to roll 3 fives, 2 sixes, and 1 two in 6 rolls of a standard six-sided die, we can use the formula for combinations with repetition:

[tex]C(n + k - 1, k) = C(6 + 3 - 1, 3) * C(3 + 2 - 1, 2) * C(1 + 1 - 1, 1)[/tex]

where n is the number of possible outcomes (in this case, 6), k is the number of choices to make (in this case, 3 for fives, 2 for sixes, and 1 for twos), and C(n + k - 1, k) represents the number of combinations with repetition.

Using this formula, we can calculate:

[tex]C(8, 3) * C(4, 2) * C(1, 1) = 56 * 6 * 1 = 336[/tex]

Therefore, there are 336 ways to roll 3 fives, 2 sixes, and 1 two in 6 rolls of a standard six-sided die.

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The best estimate for the pike population is 9860, rounded to the nearest whole number.

The best estimate for the pike population can be calculated using the mark and recapture method, also known as the Lincoln-Petersen index. According to this method, the population estimate is given by:

N = (M * C) / R

Where:

N = Population estimate

M = Number of individuals in the first sample

C = Number of individuals in the second sample

R = Number of individuals in the second sample that were tagged in the first sample

Substituting the given values, we get:

N = (770 * 270) / 21

N = 9860

The method used to estimate the pike population is the mark and recapture method, also known as the Lincoln-Petersen index. This method is commonly used in ecology and wildlife management to estimate the size of a population of animals based on samples taken from the population.

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There is only one middle number because the collection has an odd number of numbers. Since six is the midpoint, six represents the median.

When a dataset is sorted from lowest to highest, the median, a measure of central tendency, reflects the midpoint value of the dataset. The values are first presented from lowest to greatest in order to get the median of a set of data. The median is the middle value when there are an odd number of values. Use the following data set as an example: 5, 7, 24, 3, 6, 4, 4, 30, 19. We first organise the data in order before calculating the median: 3, 4, 4, 5, 6, 7, 19, 24, 30

The dataset contains 9 values, which is strange. The middle value, which is six, is therefore the median.

given

We must first arrange the numbers in ascending order in order to determine the median of the group:

3, 4, 4, 5, 6, 7, 19, 24, 30

The median will be the middle number as there are nine numbers in this collection.

There is only one middle number because the collection has an odd number of numbers. Since six is the midpoint, six represents the median.

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The exponential function for the Greenville's population so that the yearly growth rate is visible is given as follows:

G(t) = 24000(1.00124)^t.

An increasing exponential function is modeled according to the rule presented as follows:

y = a(1 + r)^t.

In which:

The function for Greenville's population is given as follows:

G(t) = 24000(1.00496)^4t.

Which means that the population grows at a rate of 0.00496 = 0.496% every four years, hence the yearly growth rate is given as follows:

r = 0.00496/4

r = 0.00124.

Then the function is given as follows:

G(t) = 24000(1.00124)^t.

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The probability that at least 5 have eliminated jobs during the last year is  0.002965.

Calculating the likelihood of experiments happening is one of the branches of mathematics known as probability. We can determine everything from the likelihood of receiving heads or tails when tossing a coin to the likelihood of making a research blunder, for instance, using a probability.

n = 9

p = probability of businesses have eliminated jobs = 0.13

X = Number of  businesses have eliminated jobs ~

Binomial( n= 9 , p = 0.13)

[tex]P(X \geq 5)[/tex]

[tex]P(X \geq 5) = 1-P( X < 5)[/tex]

[tex]P(X \geq 5) = 1-P( X \leq 4)[/tex]

Use following Excel command:

=1-BINOM.DIST(x, n, p, cumulative)

=1-BINOM.DIST(4,9,0.13,TRUE)

=0.0029649

=0.002965

Thus

[tex]\mathbf{{P(X \geq 5) =0.002965}}[/tex].

Therefore, probability that at least 5 have eliminated jobs during the last year is  0.002965.

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Complete question';

Job Elimination in the past year, 13% of businesses have eliminated jobs. If 9 businesses are selected at random, find the probability that at least 5 have eliminated jobs during the last year. Round the answer to at least four decimal places P(at least 5 have eliminated jobs during the last year) X

Answer:

B. 15

Step-by-step explanation:

its right on edge

If lisa is on her way home in her car, she has driven 24 miles so far, which is three-fourths of the way home, Lisa's total drive is 32 miles.

Let's represent the total length of Lisa's drive as x. We know that she has driven 24 miles so far, which is three-fourths of the total length. We can write this information as:

24 = (3/4) x

To find x, we need to isolate it on one side of the equation. We can start by multiplying both sides by 4/3 to get rid of the fraction:

24 * (4/3) = x

Simplifying, we get:

32 = x

We can say that Lisa has already driven 24 miles, which is three-fourths of the total distance. To find the total distance, we use the equation 24 = (3/4) x, where x represents the total distance.

To solve for x, we multiply both sides of the equation by 4/3 to cancel out the fraction, giving us 32 = x. Therefore, Lisa's total drive is 32 miles.

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Brad needs to score between 72 and 79 on the fourth test in order to get a C for the semester.

To explain why this is so, we need to first understand how the grade for the semester is calculated.Since the final course grade depends entirely on the average of four equally weighted 100-point tests, this means that each test will count for 25% of Brad’s final grade. Therefore, Brad needs to get an average score of 70-79 (inclusive) on the four tests combined in order to get a C for the semester.

In order to calculate what range of scores Brad needs to get on the fourth test in order to get a C for the semester, we need to look at the scores he has already obtained on the first three tests. Brad has scored 87, 89 and 78 on the first three tests. This gives him a total score of 254 (87+89+78=254). This means that Brad needs to get a score of between 70 and 79 on the fourth test in order to reach a total score of between 280-309 (inclusive), which will result in an average score of between 70-79 (inclusive), and give Brad a C for the semester.

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Isabella's net worth is $2,725.

We know that the net worth is nothing but a measure of an individual's financial standing at a given point in time.

Here, to calculate the net worth, we need to add up all of the assets and subtract all of her liabilities:

We can see that,

Assets

Car worth: $16,700

Savings account: $4,950

So, the total assets worth:

$16,700 + $4,950 = $21,650

Now liabilities:

Credit card balance: $925

And the rent for the remainder of the lease:

$1,500 x 12 = $18,000 for year

So, the total liabilities would be:

$925 + $18,000 = $18,925

Hence her net worth would be:

21,650 - 18,925 = 2,725 dollars

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The area beyond the z-score in the tail for a z-score of .63 is 0.2643. This means that there is a 26.43% chance that a sample is at least as extreme as the z-score of .63.

To understand this concept, it is important to first have a basic understanding of the z-score and the normal distribution. A z-score is the number of standard deviations away from the mean of a normal distribution. It is also referred to as a standard score. It is a measure of how far a sample is from the mean. For a given sample, the higher the z-score, the farther away it is from the mean.

When looking at the normal distribution, the area of the tail is the area beyond the z-score. This means that the area of the tail is the area of the distribution that is beyond the z-score of the given sample. In other words, it is the area of the distribution that is farther away from the mean than the z-score. For example, for a z-score of .63, the area of the tail is the area of the distribution that is farther away from the mean that .63 standard deviations.

When finding the area beyond the z-score, it is important to understand that it is divided into two parts, the area in the left tail and the area in the right tail. The area in the left tail is the area beyond the z-score in the direction of the negative standard deviations. This means that it is the area of the distribution that is farther away from the mean than the negative z-score. The area in the right tail is the area beyond the z-score in the direction of the positive standard deviations. This means that it is the area of the distribution that is farther away from the mean than the positive z-score.

For the given z-score of .63, the area beyond the z-score in the tail is 0.2643. This means that there is a 26.43% chance that a sample is at least as extreme as the z-score of .63. This area is divided into the areas in the left tail of -.2643 and the area in the right tail of 0.2357.

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Answer:

Step-by-step explanation:

Option A) 2+x+ 5x²-x³ + 2x4 is not in standard form because the terms are not arranged in descending order of exponents.

Option B) x + 5x³ + 6x² + x - 2 also, is not in standard form because like terms are not combined and the terms are not arranged in descending order of exponents.

Option C) 2x + 3x² - 4x³ + 3x² + 2 can be simplified to get: -4x³ + 6x² + 2x + 2. This is not in standard form because the terms are not arranged in descending order of exponents.

Option D) 4x³ + 5x² + 6x6 +7x4-2 can be simplified to get: 6x6 +7x4 + 4x³ + 5x² - 2. This is in standard form because the terms are arranged in descending order of exponents.

Therefore, the polynomial in standard form is option D) 6x6 +7x4 + 4x³ + 5x² - 2.

The pieces are reassembled into a triangulation of the original polygon.

In a proof by strong induction, the inductive hypothesis is a statement that assumes the desired property is true for all cases up to some fixed size, and then uses that assumption to prove that the property is also true for the next case.

For the proof that every simple polygon with at least three sides can be triangulated, the inductive hypothesis would be something like,

"Assume that every simple polygon with up to k sides can be triangulated for some fixed k >= 3."

In other words, we are assuming that the property is true for all polygons with up to k sides, where k is some fixed number greater than or equal to 3.

The proof then proceeds by showing that if the property is true for all polygons with up to k sides, then it must also be true for polygons with k+1 sides. This usually involves breaking the (k+1)-sided polygon into smaller pieces (using a diagonal), each of which has fewer sides and can therefore be triangulated by the inductive hypothesis. Finally, the pieces are reassembled into a triangulation of the original polygon.

By completing this proof, we have shown that the property is true for all simple polygons with at least three sides.

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The number line :0-------------4-------------10 represents the solution to the equation.

What Is an integer?

An integer is a whole number that can be positive, negative, or zero. In other words, integers are numbers that can be written without fractions or decimals.

Examples of integers are: -3, -2, -1, 0, 1, 2, 3, and so on.

The equation 4p = 16 represents the number of baseball cards owned by Phillip, where p is the number of baseball cards owned by him.

To solve for p, we can divide both sides of the equation by 4:

4p/4 = 16/4

p = 4

Therefore, Phillip owns 4 baseball cards.

Now we need to represent this solution on a number line. We can draw a number line with 0 on the left and 10 on the right, marking every integer in between. Then we can place a dot at the point corresponding to the number 4, which represents the number of baseball cards owned by Phillip.

Therefore the number line :

0-------------4-------------10

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Answer:

[tex]\huge\boxed{\sf 160 \ km}[/tex]

Step-by-step explanation:

Given that,

50 liters = 400 km

Using unitary method.

50/50 liter = 400/50 km

1 liter = 8 km

1 × 20 liter = 8 × 20 km

[tex]\rule[225]{225}{2}[/tex]

By function, The fact that this number is 1/2 indicates the half-life of the substance is 1 year.

How would you define a function in plain English?

A function is described as a relationship between a set of inputs and one output for every one of them. Simply described, a function is an association of inputs where each input is coupled to a single, distinct output.

                             Every function has an associated domain, codomain, or range. A mathematical function is a rule that, given the values of one or more independent variables and the dependent variable, determines the value of the dependent variable.

300 represents the initial amount of the substance, the amount present at t=0.

0.5 is the fraction of substance remaining at the end of each year. The fact that this number is 1/2 indicates the half-life of the substance is 1 year.

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Answer:49 = 7×7; 64 = 8×8; Difference Square is the answer. where a =7u; b = 8v. Hope that you carry out the rest Bianca,.. Jung Tran

Step-by-step explanation:

The equation of the line of reflection that reflects shape P into shape Q is y = −2x + 12.

To find the equation of the line of reflection that reflects shape P into shape Q, we need to follow some steps:

Step 1: Draw the mirror line. To reflect a point or shape, we must have a mirror line. The mirror line is the line that passes through the reflection and is perpendicular to the reflecting surface. It serves as a reference for reflecting points or shapes.

Step 2: Find the midpoint of PQ. The midpoint of PQ is the point that lies exactly halfway between P and Q.

Step 3: Find the slope of PQ. The slope of PQ is the rise over run or the difference of the y-coordinates over the difference of the x-coordinates.

The slope formula is given by m = (y2 − y1) / (x2 − x1).

Step 4: Find the perpendicular slope of PQ. The perpendicular slope of PQ is the negative reciprocal of the slope of PQ. It is given by m⊥ = −1/m.

Step 5: Write the equation of the line of reflection. The equation of the line of reflection is given by y − y1 = m⊥(x − x1) or y = m⊥x + b, where m⊥ is the perpendicular slope of PQ and b is the y-intercept of the line. To find b, we substitute the coordinates of the midpoint of PQ into the equation and solve for b. Then we substitute m⊥ and b into the equation to get the final answer.

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The rectangular prism is 3 inches by 4.75 inches by 20.5 inches, has a total surface area of 346.25 in².

We need to find the surface area of an object, the surface area of a solid three-dimensional object is the area of the boundary surface of the object and its surroundings, therefore:

The dimensions of the rectangular prism will be as follows:

Let the length of the rectangular prism = 3 inches

Let the width of the prism = 4.75 inches

Let the height of the prism = 20.5 inches

Therefore, the surface area, A, of a rectangular prism can be found using the formula:

A = 2 × Length × Width + 2 × Length × Height + 2 × Height × Width

Therefore, the surface area of the rectangular prism in the question is found as follows:

Area, A = 2 × 3 × 4.75 + 2 × 3 × 20.5 + 2 × 20.5 × 4.75 = 346.25

The total surface area of the rectangular prism is 346.25 in².

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Answer:

346.25

Step-by-step explanation:

took the test :)

The critical value of z for each hypothesis  test is 2.326

In this question, we are asked to use Excel to find the critical value of z for each hypothesis test. We are given a 2 percent level of significance for a two-tailed test. To find the critical value, we can use the NORM.S.INV function in Excel. The syntax for this function is =NORM.S.INV(probability).

We can enter the probability as 1 - (alpha / 2) for a two-tailed test, where alpha is the level of significance. We can then round the result to three decimal places.

To find the critical value for a 2 percent level of significance, two-tailed test, we can follow these steps:

Step 1: Calculate the value of alpha

Alpha = 2% = 0.02

Step 2: Calculate

1 - (alpha / 2)1 - (alpha / 2)

= 1 - (0.02 / 2)

= 0.99

Step 3: Use the NORM.S.INV function in Excel=NORM.S.INV(0.99)

This gives us a critical value of z = 2.326.

Therefore, the critical value of z for the hypothesis test with a 2 percent level of significance and a two-tailed test is 2.326.

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Answer:

Step-by-step explanation:

I would say A is the answer! :) It's the only problem that matches up.

The probability that at least 3 out of 5 businesses have eliminated jobs in the past year is 0.0556.

To find the probability that at least 3 out of 5 businesses have eliminated jobs, we can use the binomial probability formula:

P(X >= 3) = P(X = 3) + P(X = 4) + P(X = 5)

where X is the number of businesses out of 5 that have eliminated jobs, and P(X = k) is the probability of exactly k businesses out of 5 eliminating jobs.

Using the binomial probability formula, we can calculate the probabilities for each possible value of X:

P(X = 3) = (5 choose 3) x (0.13)³ x (0.87)² = 0.0519

P(X = 4) = (5 choose 4) x (0.13)⁴ x (0.87)¹ = 0.0036

P(X = 5) = (5 choose 5) x (0.13)⁵ x (0.87)⁰ = 0.0001

where (n choose k) represents the number of ways to choose k items from a set of n items, and can be calculated using the formula:

(n choose k) = n! / (k! * (n - k)!)

where n! represents the factorial of n.

Now we can add up these probabilities to get the probability of at least 3 out of 5 businesses having eliminated jobs:

P(X >= 3) = 0.0519 + 0.0036 + 0.0001 = 0.0556

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[tex]E = 2 + \dfrac{1}{4} \ \text{n}[/tex]

[tex]n = 40[/tex]

[tex]E = 2 + \dfrac{1}{4} (40)[/tex]

[tex]E= 2 + 10[/tex]

[tex]E = 12[/tex]

Elena scored 12 points

0.4

The probability that an undergraduate business major intends to attend classes full-time in pursuit of an MBA degree depends on the individual student's preferences and situation. Generally speaking, studies have shown that about 40% of undergraduate business majors choose to pursue an MBA degree full-time after graduating. Therefore, the probability of an undergraduate business major pursuing an MBA degree full-time can be estimated at 0.4.

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Answer:

1.6.1) Inversely proportional

1.6.2) 0.6h

1.6.3) 120km

Step-by-step explanation:

1.6.1)

Inversely proportional relationships are in the form of [tex]y=k/x[/tex]

[tex]y=time=t[/tex]

[tex]x=speed=v[/tex]

If we the relationship is inversely proportional, [tex]k[/tex] must be constant for all values.

[tex]yx=k[/tex]

So we just have to check the value of [tex]yx[/tex] in all cases.

[tex]20*3=60\\50*1.2=60\\80*0.75=60[/tex]

Hence relation is inversely proportional.

1.6.2)

[tex]k=60, x=100, y=k/x\\[/tex]

∴[tex]y=60/100[/tex] ⇒[tex]y=0.6[/tex]

1.6.3)

Distance formula:

[tex]v=s/t\\v*t=s\\s=(20*3) + (50*1.2)\\s=60 + 60\\s=120[/tex]

Answer: The coordinates of the reflected point are (0.5, -4)

Step-by-step explanation: When a point is reflected across the y-axis, the x-coordinate changes sign while the y-coordinate remains the same. So the point (-0.5, 4) reflected across the y-axis will be (0.5, 4).When a point is reflected across the x-axis, the y-coordinate changes sign while the x-coordinate remains the same. So the point (0.5, 4) reflected across the x-axis will be (0.5, -4).

Answer:

(5,-4) because if the quadrant one is positive positive quadrant two is negative positive quadrant three is negative negative Quadrant four is positive negative

Step-by-step explanation: Hope this helps!! Mark me brainliest! :))

The identity used to simplify from step 4 to step 5 is the definition of the cosecant function cosecant x = 1/sine x.

What is a mathematical expression?

A mathematical expression is a phrase that includes at least two numbers or variables, at least one arithmetic operation, and the expression itself. This mathematical operation may be addition, subtraction, multiplication, or division. An expression's structure is as follows: Expression is (Number/Variable, Arithmetic Operator, Number/Variable).

                                For instance, the expression x + y is an expression where x and y are terms with an addition operator between them. Mathematical expressions can be divided into two categories: algebraic expressions, which include both numbers and variables, and numerical expressions, which solely contain numbers.

 =  the expression 1/sine x

 = 1/sine x + cosine x/sine x

 =  cosecant x + cosine x/sine x

  = cosecant x + cotangent x.

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The probability of an out-of-control signal occurring on the first sample following the shift is approximately 0.0026 or 0.26%.

To determine the probability of an out-of-control signal occurring on the first sample following the shift, we need to calculate the probability of observing a sample mean or range value that falls outside the control limits.

For the X-bar chart:

New process mean (after the shift) = 702.00

Standard deviation (constant) = 1.738

Sample size (n) = 6

We can calculate the standard error (SE) for the X-bar chart using the formula:

SE = Standard deviation / √(sample size)

SE = 1.738 / √(6) ≈ 0.709

Next, we calculate the control limits for the X-bar chart based on the new process mean:

New UCL = New process mean + 3 × SE

= 702.00 + 3 × 0.709

= 704.127

New LCL = New process mean - 3 × SE

= 702.00 - 3 × 0.709

= 699.873

Now, we need to determine the probability of observing a sample mean outside the control limits, given that the process mean has shifted to 702.00. We can assume a normal distribution for the sample means.

To calculate the probability, we need to determine the z-scores for the new UCL and LCL using the formula:

z = (X - μ) / SE

where X is the value of interest (UCL or LCL), μ is the process mean, and SE is the standard error.

For the UCL:

z = (New UCL - μ) / SE

= (704.127 - 702.00) / 0.709

= 2.999

For the LCL:

z = (New LCL - μ) / SE

= (699.873 - 702.00) / 0.709

= -2.999

We can use a standard normal distribution table or a statistical calculator to find the probabilities associated with these z-scores.

Using a standard normal distribution table, the probability of observing a sample mean greater than the new UCL (2.999 z-score) is approximately 0.0013 (or 0.13%), and the probability of observing a sample mean lower than the new LCL (-2.999 z-score) is also approximately 0.0013 (or 0.13%). Since we are interested in either of these cases (an out-of-control signal), we add the probabilities:

Probability of an out-of-control signal = 0.0013 + 0.0013 ≈ 0.0026 (or 0.26%)

Therefore, the probability of an out-of-control signal occurring on the first sample following the shift is approximately 0.0026 or 0.26%.

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Complete question =

Control charts for x-bar and s have been maintained on a proces and have exhibited statistical control. The sample size is n=6. The control chart parameters are as follows:

X-bar: UCL = 708.20, Center line = 706.00, LCL = 703.80

R chart: UCL = 3.420, Center line = 1.738, LCL = 0.052

natural tolerance limits for the process are ±5.214.

the estimated standard deviation is 1.738.

d) Suppose the process mean shifts to 702.00 while the standard deviation remains constant. What is the probability of an out-of-control signal occuring on the first sample following the shift?

Answer: C - 105

Step-by-step explanation:

75+75=150

360-150=210

210/2=105